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  • I need help on my C++ assignment using MS Visual C++

    - by krayzwytie
    Ok, so I don't want you to do my homework for me, but I'm a little lost with this final assignment and need all the help I can get. Learning about programming is tough enough, but doing it online is next to impossible for me... Now, to get to the program, I am going to paste what I have so far. This includes mostly //comments and what I have written so far. If you can help me figure out where all the errors are and how to complete the assignment, I will really appreciate it. Like I said, I don't want you to do my homework for me (it's my final), but any constructive criticism is welcome. This is my final assignment for this class and it is due tomorrow (Sunday before midnight, Arizona time). This is the assignment: Examine the following situation: o Your company, Datamax, Inc., is in the process of automating its payroll systems. Your manager has asked you to create a program that calculates overtime pay for all employees. Your program must take into account the employee’s salary, total hours worked, and hours worked more than 40 in a week, and then provide an output that is useful and easily understood by company management. • Compile your program utilizing the following background information and the code outline in Appendix D (included in the code section). • Submit your project as an attachment including the code and the output. Company Background: o Three employees: Mark, John, and Mary o The end user needs to be prompted for three specific pieces of input—name, hours worked, and hourly wage. o Calculate overtime if input is greater than 40 hours per week. o Provide six test plans to verify the logic within the program. o Plan 1 must display the proper information for employee #1 with overtime pay. o Plan 2 must display the proper information for employee #1 with no overtime pay. o Plans 3-6 are duplicates of plan 1 and 2 but for the other employees. Program Requirements: o Define a base class to use for the entire program. o The class holds the function calls and the variables related to the overtime pay calculations. o Define one object per employee. Note there will be three employees. o Your program must take the objects created and implement calculations based on total salaries, total hours, and the total number of overtime hours. See the Employee Summary Data section of the sample output. Logic Steps to Complete Your Program: o Define your base class. o Define your objects from your base class. o Prompt for user input, updating your object classes for all three users. o Implement your overtime pay calculations. o Display overtime or regular time pay calculations. See the sample output below. o Implement object calculations by summarizing your employee objects and display the summary information in the example below. And this is the code: // Final_Project.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <string> #include <iomanip> using namespace std; // //CLASS DECLARATION SECTION // class CEmployee { public: void ImplementCalculations(string EmployeeName, double hours, double wage); void DisplayEmployInformation(void); void Addsomethingup (CEmployee, CEmployee, CEmployee); string EmployeeName ; int hours ; int overtime_hours ; int iTotal_hours ; int iTotal_OvertimeHours ; float wage ; float basepay ; float overtime_pay ; float overtime_extra ; float iTotal_salaries ; float iIndividualSalary ; }; int main() { system("cls"); cout << "Welcome to the Employee Pay Center"; /* Use this section to define your objects. You will have one object per employee. You have only three employees. The format is your class name and your object name. */ std::cout << "Please enter Employee's Name: "; std::cin >> EmployeeName; std::cout << "Please enter Total Hours for (EmployeeName): "; std::cin >> hours; std::cout << "Please enter Base Pay for(EmployeeName): "; std::cin >> basepay; /* Here you will prompt for the first employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Example of Prompts Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the second employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the third employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will implement a function call to implement the employ calcuations for each object defined above. You will do this for each of the three employees or objects. The format for this step is the following: [(object name.function name(objectname.name, objectname.hours, objectname.wage)] ; */ /* This section you will send all three objects to a function that will add up the the following information: - Total Employee Salaries - Total Employee Hours - Total Overtime Hours The format for this function is the following: - Define a new object. - Implement function call [objectname.functionname(object name 1, object name 2, object name 3)] /* } //End of Main Function void CEmployee::ImplementCalculations (string EmployeeName, double hours, double wage){ //Initialize overtime variables overtime_hours=0; overtime_pay=0; overtime_extra=0; if (hours > 40) { /* This section is for the basic calculations for calculating overtime pay. - base pay = 40 hours times the hourly wage - overtime hours = hours worked – 40 - overtime pay = hourly wage * 1.5 - overtime extra pay over 40 = overtime hours * overtime pay - salary = overtime money over 40 hours + your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // if (hours > 40) else { /* Here you are going to calculate the hours less than 40 hours. - Your base pay is = your hours worked times your wage - Salary = your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // End of the else } //End of Primary Function void CEmployee::DisplayEmployInformation(); { // This function displays all the employee output information. /* This is your cout statements to display the employee information: Employee Name ............. = Base Pay .................. = Hours in Overtime ......... = Overtime Pay Amount........ = Total Pay ................. = */ } // END OF Display Employee Information void CEmployee::Addsomethingup (CEmployee Employ1, CEmployee Employ2) { // Adds two objects of class Employee passed as // function arguments and saves them as the calling object's data member values. /* Add the total hours for objects 1, 2, and 3. Add the salaries for each object. Add the total overtime hours. */ /* Then display the information below. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% EMPLOYEE SUMMARY DATA%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% Total Employee Salaries ..... = 576.43 %%%% Total Employee Hours ........ = 108 %%%% Total Overtime Hours......... = 5 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% */ } // End of function

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  • OpenLDAP and SSL

    - by Stormshadow
    I am having trouble trying to connect to a secure OpenLDAP server which I have set up. On running my LDAP client code java -Djavax.net.debug=ssl LDAPConnector I get the following exception trace (java version 1.6.0_17) trigger seeding of SecureRandom done seeding SecureRandom %% No cached client session *** ClientHello, TLSv1 RandomCookie: GMT: 1256110124 bytes = { 224, 19, 193, 148, 45, 205, 108, 37, 101, 247, 112, 24, 157, 39, 111, 177, 43, 53, 206, 224, 68, 165, 55, 185, 54, 203, 43, 91 } Session ID: {} Cipher Suites: [SSL_RSA_WITH_RC4_128_MD5, SSL_RSA_WITH_RC4_128_SHA, TLS_RSA_WITH_AES_128_CBC_SHA, TLS_DHE_RSA_WITH_AES_128_CBC_SHA, TLS_DHE_DSS_WITH_AES_128_CBC_SHA, SSL_RSA_W ITH_3DES_EDE_CBC_SHA, SSL_DHE_RSA_WITH_3DES_EDE_CBC_SHA, SSL_DHE_DSS_WITH_3DES_EDE_CBC_SHA, SSL_RSA_WITH_DES_CBC_SHA, SSL_DHE_RSA_WITH_DES_CBC_SHA, SSL_DHE_DSS_WITH_DES_CBC_SH A, SSL_RSA_EXPORT_WITH_RC4_40_MD5, SSL_RSA_EXPORT_WITH_DES40_CBC_SHA, SSL_DHE_RSA_EXPORT_WITH_DES40_CBC_SHA, SSL_DHE_DSS_EXPORT_WITH_DES40_CBC_SHA] Compression Methods: { 0 } *** Thread-0, WRITE: TLSv1 Handshake, length = 73 Thread-0, WRITE: SSLv2 client hello message, length = 98 Thread-0, received EOFException: error Thread-0, handling exception: javax.net.ssl.SSLHandshakeException: Remote host closed connection during handshake Thread-0, SEND TLSv1 ALERT: fatal, description = handshake_failure Thread-0, WRITE: TLSv1 Alert, length = 2 Thread-0, called closeSocket() main, handling exception: javax.net.ssl.SSLHandshakeException: Remote host closed connection during handshake javax.naming.CommunicationException: simple bind failed: ldap.natraj.com:636 [Root exception is javax.net.ssl.SSLHandshakeException: Remote host closed connection during hands hake] at com.sun.jndi.ldap.LdapClient.authenticate(Unknown Source) at com.sun.jndi.ldap.LdapCtx.connect(Unknown Source) at com.sun.jndi.ldap.LdapCtx.<init>(Unknown Source) at com.sun.jndi.ldap.LdapCtxFactory.getUsingURL(Unknown Source) at com.sun.jndi.ldap.LdapCtxFactory.getUsingURLs(Unknown Source) at com.sun.jndi.ldap.LdapCtxFactory.getLdapCtxInstance(Unknown Source) at com.sun.jndi.ldap.LdapCtxFactory.getInitialContext(Unknown Source) at javax.naming.spi.NamingManager.getInitialContext(Unknown Source) at javax.naming.InitialContext.getDefaultInitCtx(Unknown Source) at javax.naming.InitialContext.init(Unknown Source) at javax.naming.InitialContext.<init>(Unknown Source) at javax.naming.directory.InitialDirContext.<init>(Unknown Source) at LDAPConnector.CallSecureLDAPServer(LDAPConnector.java:43) at LDAPConnector.main(LDAPConnector.java:237) Caused by: javax.net.ssl.SSLHandshakeException: Remote host closed connection during handshake at com.sun.net.ssl.internal.ssl.SSLSocketImpl.readRecord(Unknown Source) at com.sun.net.ssl.internal.ssl.SSLSocketImpl.performInitialHandshake(Unknown Source) at com.sun.net.ssl.internal.ssl.SSLSocketImpl.readDataRecord(Unknown Source) at com.sun.net.ssl.internal.ssl.AppInputStream.read(Unknown Source) at java.io.BufferedInputStream.fill(Unknown Source) at java.io.BufferedInputStream.read1(Unknown Source) at java.io.BufferedInputStream.read(Unknown Source) at com.sun.jndi.ldap.Connection.run(Unknown Source) at java.lang.Thread.run(Unknown Source) Caused by: java.io.EOFException: SSL peer shut down incorrectly at com.sun.net.ssl.internal.ssl.InputRecord.read(Unknown Source) ... 9 more I am able to connect to the same secure LDAP server however if I use another version of java (1.6.0_14) I have created and installed the server certificates in the cacerts of both the JRE's as mentioned in this guide -- OpenLDAP with SSL When I run ldapsearch -x on the server I get # extended LDIF # # LDAPv3 # base <dc=localdomain> (default) with scope subtree # filter: (objectclass=*) # requesting: ALL # # localdomain dn: dc=localdomain objectClass: top objectClass: dcObject objectClass: organization o: localdomain dc: localdomain # admin, localdomain dn: cn=admin,dc=localdomain objectClass: simpleSecurityObject objectClass: organizationalRole cn: admin description: LDAP administrator # search result search: 2 result: 0 Success # numResponses: 3 # numEntries: 2 On running openssl s_client -connect ldap.natraj.com:636 -showcerts , I obtain the self signed certificate. My slapd.conf file is as follows ####################################################################### # Global Directives: # Features to permit #allow bind_v2 # Schema and objectClass definitions include /etc/ldap/schema/core.schema include /etc/ldap/schema/cosine.schema include /etc/ldap/schema/nis.schema include /etc/ldap/schema/inetorgperson.schema # Where the pid file is put. The init.d script # will not stop the server if you change this. pidfile /var/run/slapd/slapd.pid # List of arguments that were passed to the server argsfile /var/run/slapd/slapd.args # Read slapd.conf(5) for possible values loglevel none # Where the dynamically loaded modules are stored modulepath /usr/lib/ldap moduleload back_hdb # The maximum number of entries that is returned for a search operation sizelimit 500 # The tool-threads parameter sets the actual amount of cpu's that is used # for indexing. tool-threads 1 ####################################################################### # Specific Backend Directives for hdb: # Backend specific directives apply to this backend until another # 'backend' directive occurs backend hdb ####################################################################### # Specific Backend Directives for 'other': # Backend specific directives apply to this backend until another # 'backend' directive occurs #backend <other> ####################################################################### # Specific Directives for database #1, of type hdb: # Database specific directives apply to this databasse until another # 'database' directive occurs database hdb # The base of your directory in database #1 suffix "dc=localdomain" # rootdn directive for specifying a superuser on the database. This is needed # for syncrepl. rootdn "cn=admin,dc=localdomain" # Where the database file are physically stored for database #1 directory "/var/lib/ldap" # The dbconfig settings are used to generate a DB_CONFIG file the first # time slapd starts. They do NOT override existing an existing DB_CONFIG # file. You should therefore change these settings in DB_CONFIG directly # or remove DB_CONFIG and restart slapd for changes to take effect. # For the Debian package we use 2MB as default but be sure to update this # value if you have plenty of RAM dbconfig set_cachesize 0 2097152 0 # Sven Hartge reported that he had to set this value incredibly high # to get slapd running at all. See http://bugs.debian.org/303057 for more # information. # Number of objects that can be locked at the same time. dbconfig set_lk_max_objects 1500 # Number of locks (both requested and granted) dbconfig set_lk_max_locks 1500 # Number of lockers dbconfig set_lk_max_lockers 1500 # Indexing options for database #1 index objectClass eq # Save the time that the entry gets modified, for database #1 lastmod on # Checkpoint the BerkeleyDB database periodically in case of system # failure and to speed slapd shutdown. checkpoint 512 30 # Where to store the replica logs for database #1 # replogfile /var/lib/ldap/replog # The userPassword by default can be changed # by the entry owning it if they are authenticated. # Others should not be able to see it, except the # admin entry below # These access lines apply to database #1 only access to attrs=userPassword,shadowLastChange by dn="cn=admin,dc=localdomain" write by anonymous auth by self write by * none # Ensure read access to the base for things like # supportedSASLMechanisms. Without this you may # have problems with SASL not knowing what # mechanisms are available and the like. # Note that this is covered by the 'access to *' # ACL below too but if you change that as people # are wont to do you'll still need this if you # want SASL (and possible other things) to work # happily. access to dn.base="" by * read # The admin dn has full write access, everyone else # can read everything. access to * by dn="cn=admin,dc=localdomain" write by * read # For Netscape Roaming support, each user gets a roaming # profile for which they have write access to #access to dn=".*,ou=Roaming,o=morsnet" # by dn="cn=admin,dc=localdomain" write # by dnattr=owner write ####################################################################### # Specific Directives for database #2, of type 'other' (can be hdb too): # Database specific directives apply to this databasse until another # 'database' directive occurs #database <other> # The base of your directory for database #2 #suffix "dc=debian,dc=org" ####################################################################### # SSL: # Uncomment the following lines to enable SSL and use the default # snakeoil certificates. #TLSCertificateFile /etc/ssl/certs/ssl-cert-snakeoil.pem #TLSCertificateKeyFile /etc/ssl/private/ssl-cert-snakeoil.key TLSCipherSuite TLS_RSA_AES_256_CBC_SHA TLSCACertificateFile /etc/ldap/ssl/server.pem TLSCertificateFile /etc/ldap/ssl/server.pem TLSCertificateKeyFile /etc/ldap/ssl/server.pem My ldap.conf file is # # LDAP Defaults # # See ldap.conf(5) for details # This file should be world readable but not world writable. HOST ldap.natraj.com PORT 636 BASE dc=localdomain URI ldaps://ldap.natraj.com TLS_CACERT /etc/ldap/ssl/server.pem TLS_REQCERT allow #SIZELIMIT 12 #TIMELIMIT 15 #DEREF never

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  • Why does fprintf start printing out of order or not at all?

    - by Steve Melvin
    This code should take an integer, create pipes, spawn two children, wait until they are dead, and start all over again. However, around the third time around the loop I lose my prompt to enter a number and it no longer prints the number I've entered. Any ideas? #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <errno.h> #define WRITE 1 #define READ 0 int main (int argc, const char * argv[]) { //Pipe file-descriptor array unsigned int isChildA = 0; int pipeA[2]; int pipeB[2]; int num = 0; while(1){ fprintf(stderr,"Enter an integer: "); scanf("%i", &num); if(num == 0){ fprintf(stderr,"You entered zero, exiting...\n"); exit(0); } //Open Pipes if(pipe(pipeA) < 0){ fprintf(stderr,"Could not create pipe A.\n"); exit(1); } if(pipe(pipeB) < 0){ fprintf(stderr,"Could not create pipe B.\n"); exit(1); } fprintf(stderr,"Value read: %i \n", num); fprintf(stderr,"Parent PID: %i\n", getpid()); pid_t procID = fork(); switch (procID) { case -1: fprintf(stderr,"Fork error, quitting...\n"); exit(1); break; case 0: isChildA = 1; break; default: procID = fork(); if (procID<0) { fprintf(stderr,"Fork error, quitting...\n"); exit(1); } else if(procID == 0){ isChildA = 0; } else { write(pipeA[WRITE], &num, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); pid_t pid; while (pid = waitpid(-1, NULL, 0)) { if (errno == ECHILD) { break; } } } break; } if (procID == 0) { //We're a child, do kid-stuff. ssize_t bytesRead = 0; int response; while (1) { while (bytesRead == 0) { bytesRead = read((isChildA?pipeA[READ]:pipeB[READ]), &response, sizeof(int)); } if (response < 2) { //Kill other child and self fprintf(stderr, "Terminating PROCID: %i\n", getpid()); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); return 0; } else if(!(response%2)){ //Even response/=2; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } else { //Odd response*=3; response++; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } } } } return 0; } This is the output I am getting... bash-3.00$ ./proj2 Enter an integer: 101 Value read: 101 Parent PID: 9379 PROCID: 9380, VALUE: 304 PROCID: 9381, VALUE: 152 PROCID: 9380, VALUE: 76 PROCID: 9381, VALUE: 38 PROCID: 9380, VALUE: 19 PROCID: 9381, VALUE: 58 PROCID: 9380, VALUE: 29 PROCID: 9381, VALUE: 88 PROCID: 9380, VALUE: 44 PROCID: 9381, VALUE: 22 PROCID: 9380, VALUE: 11 PROCID: 9381, VALUE: 34 PROCID: 9380, VALUE: 17 PROCID: 9381, VALUE: 52 PROCID: 9380, VALUE: 26 PROCID: 9381, VALUE: 13 PROCID: 9380, VALUE: 40 PROCID: 9381, VALUE: 20 PROCID: 9380, VALUE: 10 PROCID: 9381, VALUE: 5 PROCID: 9380, VALUE: 16 PROCID: 9381, VALUE: 8 PROCID: 9380, VALUE: 4 PROCID: 9381, VALUE: 2 PROCID: 9380, VALUE: 1 Terminating PROCID: 9381 Terminating PROCID: 9380 Enter an integer: 102 Value read: 102 Parent PID: 9379 PROCID: 9386, VALUE: 51 PROCID: 9387, VALUE: 154 PROCID: 9386, VALUE: 77 PROCID: 9387, VALUE: 232 PROCID: 9386, VALUE: 116 PROCID: 9387, VALUE: 58 PROCID: 9386, VALUE: 29 PROCID: 9387, VALUE: 88 PROCID: 9386, VALUE: 44 PROCID: 9387, VALUE: 22 PROCID: 9386, VALUE: 11 PROCID: 9387, VALUE: 34 PROCID: 9386, VALUE: 17 PROCID: 9387, VALUE: 52 PROCID: 9386, VALUE: 26 PROCID: 9387, VALUE: 13 PROCID: 9386, VALUE: 40 PROCID: 9387, VALUE: 20 PROCID: 9386, VALUE: 10 PROCID: 9387, VALUE: 5 PROCID: 9386, VALUE: 16 PROCID: 9387, VALUE: 8 PROCID: 9386, VALUE: 4 PROCID: 9387, VALUE: 2 PROCID: 9386, VALUE: 1 Terminating PROCID: 9387 Terminating PROCID: 9386 Enter an integer: 104 Value read: 104 Parent PID: 9379 Enter an integer: PROCID: 9388, VALUE: 52 PROCID: 9389, VALUE: 26 PROCID: 9388, VALUE: 13 PROCID: 9389, VALUE: 40 PROCID: 9388, VALUE: 20 PROCID: 9389, VALUE: 10 PROCID: 9388, VALUE: 5 PROCID: 9389, VALUE: 16 PROCID: 9388, VALUE: 8 PROCID: 9389, VALUE: 4 PROCID: 9388, VALUE: 2 PROCID: 9389, VALUE: 1 Terminating PROCID: 9388 Terminating PROCID: 9389 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9395, VALUE: 316 PROCID: 9396, VALUE: 158 PROCID: 9395, VALUE: 79 PROCID: 9396, VALUE: 238 PROCID: 9395, VALUE: 119 PROCID: 9396, VALUE: 358 PROCID: 9395, VALUE: 179 PROCID: 9396, VALUE: 538 PROCID: 9395, VALUE: 269 PROCID: 9396, VALUE: 808 PROCID: 9395, VALUE: 404 PROCID: 9396, VALUE: 202 PROCID: 9395, VALUE: 101 PROCID: 9396, VALUE: 304 PROCID: 9395, VALUE: 152 PROCID: 9396, VALUE: 76 PROCID: 9395, VALUE: 38 PROCID: 9396, VALUE: 19 PROCID: 9395, VALUE: 58 PROCID: 9396, VALUE: 29 PROCID: 9395, VALUE: 88 PROCID: 9396, VALUE: 44 PROCID: 9395, VALUE: 22 PROCID: 9396, VALUE: 11 PROCID: 9395, VALUE: 34 PROCID: 9396, VALUE: 17 PROCID: 9395, VALUE: 52 PROCID: 9396, VALUE: 26 PROCID: 9395, VALUE: 13 PROCID: 9396, VALUE: 40 PROCID: 9395, VALUE: 20 PROCID: 9396, VALUE: 10 PROCID: 9395, VALUE: 5 PROCID: 9396, VALUE: 16 PROCID: 9395, VALUE: 8 PROCID: 9396, VALUE: 4 PROCID: 9395, VALUE: 2 PROCID: 9396, VALUE: 1 Terminating PROCID: 9395 Terminating PROCID: 9396 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9397, VALUE: 316 PROCID: 9398, VALUE: 158 PROCID: 9397, VALUE: 79 PROCID: 9398, VALUE: 238 PROCID: 9397, VALUE: 119 PROCID: 9398, VALUE: 358 PROCID: 9397, VALUE: 179 PROCID: 9398, VALUE: 538 PROCID: 9397, VALUE: 269 PROCID: 9398, VALUE: 808 PROCID: 9397, VALUE: 404 PROCID: 9398, VALUE: 202 PROCID: 9397, VALUE: 101 PROCID: 9398, VALUE: 304 PROCID: 9397, VALUE: 152 PROCID: 9398, VALUE: 76 PROCID: 9397, VALUE: 38 PROCID: 9398, VALUE: 19 PROCID: 9397, VALUE: 58 PROCID: 9398, VALUE: 29 PROCID: 9397, VALUE: 88 PROCID: 9398, VALUE: 44 PROCID: 9397, VALUE: 22 PROCID: 9398, VALUE: 11 PROCID: 9397, VALUE: 34 PROCID: 9398, VALUE: 17 PROCID: 9397, VALUE: 52 PROCID: 9398, VALUE: 26 PROCID: 9397, VALUE: 13 PROCID: 9398, VALUE: 40 PROCID: 9397, VALUE: 20 PROCID: 9398, VALUE: 10 PROCID: 9397, VALUE: 5 PROCID: 9398, VALUE: 16 PROCID: 9397, VALUE: 8 PROCID: 9398, VALUE: 4 PROCID: 9397, VALUE: 2 PROCID: 9398, VALUE: 1 Terminating PROCID: 9397 Terminating PROCID: 9398 106 Value read: 106 Parent PID: 9379 Enter an integer: PROCID: 9399, VALUE: 53 PROCID: 9400, VALUE: 160 PROCID: 9399, VALUE: 80 PROCID: 9400, VALUE: 40 PROCID: 9399, VALUE: 20 PROCID: 9400, VALUE: 10 PROCID: 9399, VALUE: 5 PROCID: 9400, VALUE: 16 PROCID: 9399, VALUE: 8 PROCID: 9400, VALUE: 4 PROCID: 9399, VALUE: 2 PROCID: 9400, VALUE: 1 Terminating PROCID: 9399 Terminating PROCID: 9400 ^C Another thing that's strange, when ran from within XCode it behaves normally. However, when ran from bash on Solaris or OSX it acts up.

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  • Error with JSF2 and RichFaces

    - by Miguel Ping
    Hi, I'm trying to use RichFaces on a working JSF2 application. I incorporated the RichFaces jars, changed the web.xml but got the following error: 17:49:13,097 SEVERE [javax.enterprise.resource.webcontainer.jsf.application] Error Rendering View[/login.xhtml]: java.lang.NullPointerExcept ion at com.sun.faces.application.ApplicationImpl.createComponent(ApplicationImpl.java:936) at com.sun.faces.facelets.tag.jsf.CompositeComponentTagHandler.createComponent(CompositeComponentTagHandler.java:154) at com.sun.faces.facelets.tag.jsf.ComponentTagHandlerDelegateImpl.createComponent(ComponentTagHandlerDelegateImpl.java:311) at com.sun.faces.facelets.tag.jsf.ComponentTagHandlerDelegateImpl.apply(ComponentTagHandlerDelegateImpl.java:145) at javax.faces.view.facelets.DelegatingMetaTagHandler.apply(DelegatingMetaTagHandler.java:114) at javax.faces.view.facelets.CompositeFaceletHandler.apply(CompositeFaceletHandler.java:91) at javax.faces.view.facelets.DelegatingMetaTagHandler.applyNextHandler(DelegatingMetaTagHandler.java:120) at com.sun.faces.facelets.tag.jsf.ComponentTagHandlerDelegateImpl.apply(ComponentTagHandlerDelegateImpl.java:204) at javax.faces.view.facelets.DelegatingMetaTagHandler.apply(DelegatingMetaTagHandler.java:114) at javax.faces.view.facelets.CompositeFaceletHandler.apply(CompositeFaceletHandler.java:91) at com.sun.faces.facelets.compiler.NamespaceHandler.apply(NamespaceHandler.java:86) at javax.faces.view.facelets.CompositeFaceletHandler.apply(CompositeFaceletHandler.java:91) at com.sun.faces.facelets.compiler.EncodingHandler.apply(EncodingHandler.java:75) at com.sun.faces.facelets.impl.DefaultFacelet.include(DefaultFacelet.java:301) at com.sun.faces.facelets.impl.DefaultFacelet.include(DefaultFacelet.java:360) at com.sun.faces.facelets.impl.DefaultFacelet.include(DefaultFacelet.java:339) at com.sun.faces.facelets.impl.DefaultFaceletContext.includeFacelet(DefaultFaceletContext.java:191) at com.sun.faces.facelets.tag.ui.CompositionHandler.apply(CompositionHandler.java:149) at com.sun.faces.facelets.compiler.NamespaceHandler.apply(NamespaceHandler.java:86) at com.sun.faces.facelets.compiler.EncodingHandler.apply(EncodingHandler.java:75) at com.sun.faces.facelets.impl.DefaultFacelet.apply(DefaultFacelet.java:145) at com.sun.faces.application.view.FaceletViewHandlingStrategy.buildView(FaceletViewHandlingStrategy.java:716) at com.sun.faces.application.view.FaceletViewHandlingStrategy.renderView(FaceletViewHandlingStrategy.java:351) at com.sun.faces.application.view.MultiViewHandler.renderView(MultiViewHandler.java:126) at org.ajax4jsf.application.ViewHandlerWrapper.renderView(ViewHandlerWrapper.java:100) at org.ajax4jsf.application.AjaxViewHandler.renderView(AjaxViewHandler.java:176) at com.sun.faces.lifecycle.RenderResponsePhase.execute(RenderResponsePhase.java:127) at com.sun.faces.lifecycle.Phase.doPhase(Phase.java:101) at com.sun.faces.lifecycle.LifecycleImpl.render(LifecycleImpl.java:139) at javax.faces.webapp.FacesServlet.service(FacesServlet.java:313) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:336) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:242) at org.ajax4jsf.webapp.BaseXMLFilter.doXmlFilter(BaseXMLFilter.java:206) at org.ajax4jsf.webapp.BaseFilter.handleRequest(BaseFilter.java:290) at org.ajax4jsf.webapp.BaseFilter.processUploadsAndHandleRequest(BaseFilter.java:388) at org.ajax4jsf.webapp.BaseFilter.doFilter(BaseFilter.java:515) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:274) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:242) at org.apache.catalina.core.ApplicationDispatcher.invoke(ApplicationDispatcher.java:734) at org.apache.catalina.core.ApplicationDispatcher.processRequest(ApplicationDispatcher.java:541) at org.apache.catalina.core.ApplicationDispatcher.doForward(ApplicationDispatcher.java:479) at org.apache.catalina.core.ApplicationDispatcher.forward(ApplicationDispatcher.java:407) at org.apache.catalina.authenticator.FormAuthenticator.forwardToLoginPage(FormAuthenticator.java:318) at org.apache.catalina.authenticator.FormAuthenticator.authenticate(FormAuthenticator.java:243) at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:559) at org.jboss.web.tomcat.security.JaccContextValve.invoke(JaccContextValve.java:95) at org.jboss.web.tomcat.security.SecurityContextEstablishmentValve.process(SecurityContextEstablishmentValve.java:126) at org.jboss.web.tomcat.security.SecurityContextEstablishmentValve.invoke(SecurityContextEstablishmentValve.java:70) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.jboss.web.tomcat.service.jca.CachedConnectionValve.invoke(CachedConnectionValve.java:158) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:368) at org.apache.coyote.http11.Http11Processor.process(Http11Processor.java:872) at org.apache.coyote.http11.Http11Protocol$Http11ConnectionHandler.process(Http11Protocol.java:653) at org.apache.tomcat.util.net.JIoEndpoint$Worker.run(JIoEndpoint.java:951) at java.lang.Thread.run(Thread.java:619) It seems that some jars are missing, but I cannot seem to find this cause. The above error is the only thing that the log spits out. Here's web.xml: <context-param> <param-name>javax.faces.FACELETS_LIBRARIES</param-name> <param-value>/WEB-INF/faces-validator-tags/general.taglib.xml; /WEB-INF/faces-converter-tags/general.converter.taglib.xml </param-value> </context-param> <!-- Startup Servlet <servlet> <servlet-name>StartUpServlet</servlet-name> <servlet-class>pt.cgd.agile.util.StartupServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> --> <context-param> <param-name>javax.faces.DISABLE_FACELET_JSF_VIEWHANDLER</param-name> <param-value>true</param-value> </context-param> <context-param> <param-name>org.richfaces.SKIN</param-name> <param-value>blueSky</param-value> </context-param> <!-- Making the RichFaces skin spread to standard HTML controls --> <context-param> <param-name>org.richfaces.CONTROL_SKINNING</param-name> <param-value>enable</param-value> </context-param> <context-param> <param-name>javax.faces.STATE_SAVING_METHOD</param-name> <param-value>server</param-value> </context-param> <context-param> <param-name>org.richfaces.SKIN</param-name> <param-value>blueSky</param-value> </context-param> <context-param> <param-name>org.richfaces.CONTROL_SKINNING</param-name> <param-value>enable</param-value> </context-param> <filter> <display-name>RichFaces Filter</display-name> <filter-name>richfaces</filter-name> <filter-class>org.ajax4jsf.Filter</filter-class> </filter> <filter-mapping> <filter-name>richfaces</filter-name> <servlet-name>Faces Servlet</servlet-name> <dispatcher>REQUEST</dispatcher> <dispatcher>FORWARD</dispatcher> <dispatcher>INCLUDE</dispatcher> </filter-mapping> <listener> <listener-class>com.sun.faces.config.ConfigureListener</listener-class> </listener> <!-- Just here so the JSF implementation can initialize, *not* used at runtime --> <servlet> <servlet-name>Faces Servlet</servlet-name> <servlet-class>javax.faces.webapp.FacesServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <!-- Just here so the JSF implementation can initialize --> <servlet-mapping> <servlet-name>Faces Servlet</servlet-name> <url-pattern>*.jsf</url-pattern> </servlet-mapping> <login-config> <auth-method>FORM</auth-method> <form-login-config> <form-login-page>/login.jsf</form-login-page> <form-error-page>/loginError.jsf</form-error-page> </form-login-config> </login-config> <error-page> <exception-type>java.lang.Throwable</exception-type> <location>/errors/error.jsf</location> </error-page>

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  • Handling aces and finding a segfault in a blackjack program

    - by Bill Adams
    Here's what i have so far... I have yet to figure out how i'm going to handle the 11 / 1 situation with an ace, and when the player chooses an option for hit/stand, i get segfault. HELP!!! #include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> #define DECKSIZE 52 #define VALUE 9 #define FACE 4 #define HANDSIZE 26 typedef struct { int value; char* suit; char* name; }Card; typedef struct { int value; char* suit; char* name; }dealerHand; typedef struct { int value; char* suit; char* name; }playerHand; Card cards[DECKSIZE]; dealerHand deal[HANDSIZE]; playerHand dealt[HANDSIZE]; char *faceName[]={"two","three", "four","five","six", "seven","eight","nine", "ten", "jack","queen", "king","ace"}; char *suitName[]={"spades","diamonds","clubs","hearts"}; void printDeck(){ int i; for(i=0;i<DECKSIZE;i++){ printf("%s of %s value = %d\n ",cards[i].name,cards[i].suit,cards[i].value); if((i+1)%13==0 && i!=0) printf("-------------------\n\n"); } } void shuffleDeck(){ srand(time(NULL)); int this; int that; Card temp; int c; for(c=0;c<10000;c++){ //c is the index for number of individual card shuffles should be set to c<10000 or more this=rand()%DECKSIZE; that=rand()%DECKSIZE; temp=cards[this]; cards[this]=cards[that]; cards[that]=temp; } } /*void hitStand(i,y){ // I dumped this because of a segfault i couldn't figure out. int k; printf(" Press 1 to HIT or press 2 to STAND:"); scanf("%d",k); if(k=1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } } */ int main(){ int suitCount=0; int faceCount=0; int i; int x; int y; int d; int p; int k; for(i=0;i<DECKSIZE;i++){ //this for statement builds the deck if(faceCount<9){ cards[i].value=faceCount+2; }else{ //assigns face cards as value 10 cards[i].value=10; } cards[i].suit=suitName[suitCount]; cards[i].name=faceName[faceCount++]; if(faceCount==13){ //this if loop increments suit count once cards[i].value=11; //all faces have been assigned, and also suitCount++; //assigns the ace as 11 faceCount=0; } //end building deck } /*printDeck(); //prints the deck in order shuffleDeck(); //shuffles the deck printDeck(); //prints the deck as shuffled This was used in testing, commented out to keep the deck hidden!*/ shuffleDeck(); x=0; y=0; for(i=0;i<4;i++){ //this for loop deals the first 4 cards, dealt[y].suit=cards[i].suit; //first card to player, second to dealer, dealt[y].name=cards[i].name; //as per standard dealing practice. dealt[y].value=cards[i].value; i++; y++; deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; } printf(" Dealer's hand is: %s of %s and XXXX of XXXX. (Second card is hidden!)\n",deal[0].name,deal[0].suit,deal[1].name,deal[1].suit); printf(" Player's hand is: %s of %s and %s of %s.\n",dealt[0].name,dealt[0].suit,dealt[1].name,dealt[1].suit); printf(" the current value of the index i=%d\n",i); //this line gave me the value of i for testing d=deal[0].value+deal[1].value; p=dealt[0].value+dealt[1].value; if(d==21){ printf(" The Dealer has Blackjack! House win!\n"); }else{ if(d>21){ printf(" The dealer is Bust! You win!\n"); }else{ if(d>17){ printf(" Press 1 to HIT or 2 to STAND"); scanf("%d",k); if(k==1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } }else{ if(d<17){ printf(" Dealer Hits!"); deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; i++; } } } } return 0; }

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  • C++ scoping error

    - by Pat Murray
    I have the following code: #include "Student.h" #include "SortedList.h" using namespace std; int main() { // points to the sorted list object SortedList *list = new SortedList; //This is line 17 // array to hold 100 student objects Student create[100]; int num = 100000; // holds different ID numbers // fills an array with 100 students of various ID numbers for (Student &x : create) { x = new Student(num); num += 100; } // insert all students into the sorted list for (Student &x : create) list->insert(&x); delete list; return 0; } And I keep getting the compile time error: main.cpp: In function ‘int main()’: main.cpp:17: error: ‘SortedList’ was not declared in this scope main.cpp:17: error: ‘list’ was not declared in this scope main.cpp:17: error: expected type-specifier before ‘SortedList’ main.cpp:17: error: expected `;' before ‘SortedList’ main.cpp:20: error: ‘Student’ was not declared in this scope main.cpp:20: error: expected primary-expression before ‘]’ token main.cpp:20: error: expected `;' before ‘create’ main.cpp:25: error: expected `;' before ‘x’ main.cpp:31: error: expected primary-expression before ‘for’ main.cpp:31: error: expected `;' before ‘for’ main.cpp:31: error: expected primary-expression before ‘for’ main.cpp:31: error: expected `)' before ‘for’ main.cpp:31: error: expected `;' before ‘x’ main.cpp:34: error: type ‘<type error>’ argument given to ‘delete’, expected pointer main.cpp:35: error: expected primary-expression before ‘return’ main.cpp:35: error: expected `)' before ‘return’ My Student.cpp and SortedList.cpp files compile just fine. They both also include .h files. I just do not understand why I get an error on that line. It seems to be a small issue though. Any insight would be appreciated. UPDATE1: I originally had .h files included, but i changed it when trying to figure out the cause of the error. The error remains with the .h files included though. UPDATE2: SortedList.h #ifndef SORTEDLIST_H #define SORTEDLIST_H #include "Student.h" /* * SortedList class * * A SortedList is an ordered collection of Students. The Students are ordered * from lowest numbered student ID to highest numbered student ID. */ class SortedList { public: SortedList(); // Constructs an empty list. SortedList(const SortedList & l); // Constructs a copy of the given student object ~SortedList(); // Destructs the sorted list object const SortedList & operator=(const SortedList & l); // Defines the assignment operator between two sorted list objects bool insert(Student *s); // If a student with the same ID is not already in the list, inserts // the given student into the list in the appropriate place and returns // true. If there is already a student in the list with the same ID // then the list is not changed and false is returned. Student *find(int studentID); // Searches the list for a student with the given student ID. If the // student is found, it is returned; if it is not found, NULL is returned. Student *remove(int studentID); // Searches the list for a student with the given student ID. If the // student is found, the student is removed from the list and returned; // if no student is found with the given ID, NULL is returned. // Note that the Student is NOT deleted - it is returned - however, // the removed list node should be deleted. void print() const; // Prints out the list of students to standard output. The students are // printed in order of student ID (from smallest to largest), one per line private: // Since Listnodes will only be used within the SortedList class, // we make it private. struct Listnode { Student *student; Listnode *next; }; Listnode *head; // pointer to first node in the list static void freeList(Listnode *L); // Traverses throught the linked list and deallocates each node static Listnode *copyList(Listnode *L); // Returns a pointer to the first node within a particular list }; #endif #ifndef STUDENT_H #define STUDENT_H Student.h #ifndef STUDENT_H #define STUDENT_H /* * Student class * * A Student object contains a student ID, the number of credits, and an * overall GPA. */ class Student { public: Student(); // Constructs a default student with an ID of 0, 0 credits, and 0.0 GPA. Student(int ID); // Constructs a student with the given ID, 0 credits, and 0.0 GPA. Student(int ID, int cr, double grPtAv); // Constructs a student with the given ID, number of credits, and GPA.\ Student(const Student & s); // Constructs a copy of another student object ~Student(); // Destructs a student object const Student & operator=(const Student & rhs); // Defines the assignment operator between two student objects // Accessors int getID() const; // returns the student ID int getCredits() const; // returns the number of credits double getGPA() const; // returns the GPA // Other methods void update(char grade, int cr); // Updates the total credits and overall GPA to take into account the // additions of the given letter grade in a course with the given number // of credits. The update is done by first converting the letter grade // into a numeric value (A = 4.0, B = 3.0, etc.). The new GPA is // calculated using the formula: // // (oldGPA * old_total_credits) + (numeric_grade * cr) // newGPA = --------------------------------------------------- // old_total_credits + cr // // Finally, the total credits is updated (to old_total_credits + cr) void print() const; // Prints out the student to standard output in the format: // ID,credits,GPA // Note: the end-of-line is NOT printed after the student information private: int studentID; int credits; double GPA; }; #endif

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  • Generic Aggregation of C++ Objects by Attribute When Attribute Name is Unknown at Runtime

    - by stretch
    I'm currently implementing a system with a number of class's representing objects such as client, business, product etc. Standard business logic. As one might expect each class has a number of standard attributes. I have a long list of essentially identical requirements such as: the ability to retrieve all business' whose industry is manufacturing. the ability to retrieve all clients based in London Class business has attribute sector and client has attribute location. Clearly this a relational problem and in pseudo SQL would look something like: SELECT ALL business in business' WHERE sector == manufacturing Unfortunately plugging into a DB is not an option. What I want to do is have a single generic aggregation function whose signature would take the form: vector<generic> genericAggregation(class, attribute, value); Where class is the class of object I want to aggregate, attribute and value being the class attribute and value of interest. In my example I've put vector as return type, but this wouldn't work. Probably better to declare a vector of relevant class type and pass it as an argument. But this isn't the main problem. How can I accept arguments in string form for class, attribute and value and then map these in a generic object aggregation function? Since it's rude not to post code, below is a dummy program which creates a bunch of objects of imaginatively named classes. Included is a specific aggregation function which returns a vector of B objects whose A object is equal to an id specified at the command line e.g. .. $ ./aggregations 5 which returns all B's whose A objects 'i' attribute is equal to 5. See below: #include <iostream> #include <cstring> #include <sstream> #include <vector> using namespace std; //First imaginativly names dummy class class A { private: int i; double d; string s; public: A(){} A(int i, double d, string s) { this->i = i; this->d = d; this->s = s; } ~A(){} int getInt() {return i;} double getDouble() {return d;} string getString() {return s;} }; //second imaginativly named dummy class class B { private: int i; double d; string s; A *a; public: B(int i, double d, string s, A *a) { this->i = i; this->d = d; this->s = s; this->a = a; } ~B(){} int getInt() {return i;} double getDouble() {return d;} string getString() {return s;} A* getA() {return a;} }; //Containers for dummy class objects vector<A> a_vec (10); vector<B> b_vec;//100 //Util function, not important.. string int2string(int number) { stringstream ss; ss << number; return ss.str(); } //Example function that returns a new vector containing on B objects //whose A object i attribute is equal to 'id' vector<B> getBbyA(int id) { vector<B> result; for(int i = 0; i < b_vec.size(); i++) { if(b_vec.at(i).getA()->getInt() == id) { result.push_back(b_vec.at(i)); } } return result; } int main(int argc, char** argv) { //Create some A's and B's, each B has an A... //Each of the 10 A's are associated with 10 B's. for(int i = 0; i < 10; ++i) { A a(i, (double)i, int2string(i)); a_vec.at(i) = a; for(int j = 0; j < 10; j++) { B b((i * 10) + j, (double)j, int2string(i), &a_vec.at(i)); b_vec.push_back(b); } } //Got some objects so lets do some aggregation //Call example aggregation function to return all B objects //whose A object has i attribute equal to argv[1] vector<B> result = getBbyA(atoi(argv[1])); //If some B's were found print them, else don't... if(result.size() != 0) { for(int i = 0; i < result.size(); i++) { cout << result.at(i).getInt() << " " << result.at(i).getA()->getInt() << endl; } } else { cout << "No B's had A's with attribute i equal to " << argv[1] << endl; } return 0; } Compile with: g++ -o aggregations aggregations.cpp If you wish :) Instead of implementing a separate aggregation function (i.e. getBbyA() in the example) I'd like to have a single generic aggregation function which accounts for all possible class attribute pairs such that all aggregation requirements are met.. and in the event additional attributes are added later, or additional aggregation requirements, these will automatically be accounted for. So there's a few issues here but the main one I'm seeking insight into is how to map a runtime argument to a class attribute. I hope I've provided enough detail to adequately describe what I'm trying to do...

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  • Memory not being freed, causing giant memory leak

    - by Delan Azabani
    In my Unicode library for C++, the ustring class has operator= functions set for char* values and other ustring values. When doing the simple memory leak test: #include <cstdio> #include "ucpp" main() { ustring a; for(;;)a="MEMORY"; } the memory used by the program grows uncontrollably (characteristic of a program with a big memory leak) even though I've added free() calls to both of the functions. I am unsure why this is ineffective (am I missing free() calls in other places?) This is the current library code: #include <cstdlib> #include <cstring> class ustring { int * values; long len; public: long length() { return len; } ustring() { len = 0; values = (int *) malloc(0); } ustring(const ustring &input) { len = input.len; values = (int *) malloc(sizeof(int) * len); for (long i = 0; i < len; i++) values[i] = input.values[i]; } ustring operator=(ustring input) { ustring result(input); free(values); len = input.len; values = input.values; return * this; } ustring(const char * input) { values = (int *) malloc(0); long s = 0; // s = number of parsed chars int a, b, c, d, contNeed = 0, cont = 0; for (long i = 0; input[i]; i++) if (input[i] < 0x80) { // ASCII, direct copy (00-7f) values = (int *) realloc(values, sizeof(int) * ++s); values[s - 1] = input[i]; } else if (input[i] < 0xc0) { // this is a continuation (80-bf) if (cont == contNeed) { // no need for continuation, use U+fffd values = (int *) realloc(values, sizeof(int) * ++s); values[s - 1] = 0xfffd; } cont = cont + 1; values[s - 1] = values[s - 1] | ((input[i] & 0x3f) << ((contNeed - cont) * 6)); if (cont == contNeed) cont = contNeed = 0; } else if (input[i] < 0xc2) { // invalid byte, use U+fffd (c0-c1) values = (int *) realloc(values, sizeof(int) * ++s); values[s - 1] = 0xfffd; } else if (input[i] < 0xe0) { // start of 2-byte sequence (c2-df) contNeed = 1; values = (int *) realloc(values, sizeof(int) * ++s); values[s - 1] = (input[i] & 0x1f) << 6; } else if (input[i] < 0xf0) { // start of 3-byte sequence (e0-ef) contNeed = 2; values = (int *) realloc(values, sizeof(int) * ++s); values[s - 1] = (input[i] & 0x0f) << 12; } else if (input[i] < 0xf5) { // start of 4-byte sequence (f0-f4) contNeed = 3; values = (int *) realloc(values, sizeof(int) * ++s); values[s - 1] = (input[i] & 0x07) << 18; } else { // restricted or invalid (f5-ff) values = (int *) realloc(values, sizeof(int) * ++s); values[s - 1] = 0xfffd; } len = s; } ustring operator=(const char * input) { ustring result(input); free(values); len = result.len; values = result.values; return * this; } ustring operator+(ustring input) { ustring result; result.len = len + input.len; result.values = (int *) malloc(sizeof(int) * result.len); for (long i = 0; i < len; i++) result.values[i] = values[i]; for (long i = 0; i < input.len; i++) result.values[i + len] = input.values[i]; return result; } ustring operator[](long index) { ustring result; result.len = 1; result.values = (int *) malloc(sizeof(int)); result.values[0] = values[index]; return result; } operator char * () { return this -> encode(); } char * encode() { char * r = (char *) malloc(0); long s = 0; for (long i = 0; i < len; i++) { if (values[i] < 0x80) r = (char *) realloc(r, s + 1), r[s + 0] = char(values[i]), s += 1; else if (values[i] < 0x800) r = (char *) realloc(r, s + 2), r[s + 0] = char(values[i] >> 6 | 0x60), r[s + 1] = char(values[i] & 0x3f | 0x80), s += 2; else if (values[i] < 0x10000) r = (char *) realloc(r, s + 3), r[s + 0] = char(values[i] >> 12 | 0xe0), r[s + 1] = char(values[i] >> 6 & 0x3f | 0x80), r[s + 2] = char(values[i] & 0x3f | 0x80), s += 3; else r = (char *) realloc(r, s + 4), r[s + 0] = char(values[i] >> 18 | 0xf0), r[s + 1] = char(values[i] >> 12 & 0x3f | 0x80), r[s + 2] = char(values[i] >> 6 & 0x3f | 0x80), r[s + 3] = char(values[i] & 0x3f | 0x80), s += 4; } return r; } };

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  • ANSI C blackjack assignment, linux GCC compiler, i'm stuck...

    - by Bill Adams
    Here's what i have so far... I have yet to figure out how i'm going to handle the 11 / 1 situation with an ace, and when the player chooses an option for hit/stand, i get segfault. HELP!!! #include <stdio.h> #include <string.h> #include <stdlib.h> #include <time.h> #define DECKSIZE 52 #define VALUE 9 #define FACE 4 #define HANDSIZE 26 typedef struct { int value; char* suit; char* name; }Card; typedef struct { int value; char* suit; char* name; }dealerHand; typedef struct { int value; char* suit; char* name; }playerHand; Card cards[DECKSIZE]; dealerHand deal[HANDSIZE]; playerHand dealt[HANDSIZE]; char *faceName[]={"two","three", "four","five","six", "seven","eight","nine", "ten", "jack","queen", "king","ace"}; char *suitName[]={"spades","diamonds","clubs","hearts"}; void printDeck(){ int i; for(i=0;i<DECKSIZE;i++){ printf("%s of %s value = %d\n ",cards[i].name,cards[i].suit,cards[i].value); if((i+1)%13==0 && i!=0) printf("-------------------\n\n"); } } void shuffleDeck(){ srand(time(NULL)); int this; int that; Card temp; int c; for(c=0;c<10000;c++){ //c is the index for number of individual card shuffles should be set to c<10000 or more this=rand()%DECKSIZE; that=rand()%DECKSIZE; temp=cards[this]; cards[this]=cards[that]; cards[that]=temp; } } /*void hitStand(i,y){ // I dumped this because of a segfault i couldn't figure out. int k; printf(" Press 1 to HIT or press 2 to STAND:"); scanf("%d",k); if(k=1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } } */ int main(){ int suitCount=0; int faceCount=0; int i; int x; int y; int d; int p; int k; for(i=0;i<DECKSIZE;i++){ //this for statement builds the deck if(faceCount<9){ cards[i].value=faceCount+2; }else{ //assigns face cards as value 10 cards[i].value=10; } cards[i].suit=suitName[suitCount]; cards[i].name=faceName[faceCount++]; if(faceCount==13){ //this if loop increments suit count once cards[i].value=11; //all faces have been assigned, and also suitCount++; //assigns the ace as 11 faceCount=0; } //end building deck } /*printDeck(); //prints the deck in order shuffleDeck(); //shuffles the deck printDeck(); //prints the deck as shuffled This was used in testing, commented out to keep the deck hidden!*/ shuffleDeck(); x=0; y=0; for(i=0;i<4;i++){ //this for loop deals the first 4 cards, dealt[y].suit=cards[i].suit; //first card to player, second to dealer, dealt[y].name=cards[i].name; //as per standard dealing practice. dealt[y].value=cards[i].value; i++; y++; deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; } printf(" Dealer's hand is: %s of %s and XXXX of XXXX. (Second card is hidden!)\n",deal[0].name,deal[0].suit,deal[1].name,deal[1].suit); printf(" Player's hand is: %s of %s and %s of %s.\n",dealt[0].name,dealt[0].suit,dealt[1].name,dealt[1].suit); printf(" the current value of the index i=%d\n",i); //this line gave me the value of i for testing d=deal[0].value+deal[1].value; p=dealt[0].value+dealt[1].value; if(d==21){ printf(" The Dealer has Blackjack! House win!\n"); }else{ if(d>21){ printf(" The dealer is Bust! You win!\n"); }else{ if(d>17){ printf(" Press 1 to HIT or 2 to STAND"); scanf("%d",k); if(k==1){ dealt[y].suit=cards[i].suit; dealt[y].name=cards[i].name; dealt[y].value=cards[i].value; y++; i++; } }else{ if(d<17){ printf(" Dealer Hits!"); deal[x].suit=cards[i].suit; deal[x].name=cards[i].name; deal[x].value=cards[i].value; x++; i++; } } } } return 0; }

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  • I need help on my C++ assignment using Microsoft Visual C++

    - by krayzwytie
    Ok, so I don't want you to do my homework for me, but I'm a little lost with this final assignment and need all the help I can get. Learning about programming is tough enough, but doing it online is next to impossible for me... Now, to get to the program, I am going to paste what I have so far. This includes mostly //comments and what I have written so far. If you can help me figure out where all the errors are and how to complete the assignment, I will really appreciate it. Like I said, I don't want you to do my homework for me (it's my final), but any constructive criticism is welcome. This is my final assignment for this class and it is due tomorrow (Sunday before midnight, Arizona time). This is the assignment: Examine the following situation: Your company, Datamax, Inc., is in the process of automating its payroll systems. Your manager has asked you to create a program that calculates overtime pay for all employees. Your program must take into account the employee’s salary, total hours worked, and hours worked more than 40 in a week, and then provide an output that is useful and easily understood by company management. Compile your program utilizing the following background information and the code outline in Appendix D (included in the code section). Submit your project as an attachment including the code and the output. Company Background: Three employees: Mark, John, and Mary The end user needs to be prompted for three specific pieces of input—name, hours worked, and hourly wage. Calculate overtime if input is greater than 40 hours per week. Provide six test plans to verify the logic within the program. Plan 1 must display the proper information for employee #1 with overtime pay. Plan 2 must display the proper information for employee #1 with no overtime pay. Plans 3-6 are duplicates of plan 1 and 2 but for the other employees. Program Requirements: Define a base class to use for the entire program. The class holds the function calls and the variables related to the overtime pay calculations. Define one object per employee. Note there will be three employees. Your program must take the objects created and implement calculations based on total salaries, total hours, and the total number of overtime hours. See the Employee Summary Data section of the sample output. Logic Steps to Complete Your Program: Define your base class. Define your objects from your base class. Prompt for user input, updating your object classes for all three users. Implement your overtime pay calculations. Display overtime or regular time pay calculations. See the sample output below. Implement object calculations by summarizing your employee objects and display the summary information in the example below. And this is the code: // Final_Project.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include <iostream> #include <string> #include <iomanip> using namespace std; // //CLASS DECLARATION SECTION // class CEmployee { public: void ImplementCalculations(string EmployeeName, double hours, double wage); void DisplayEmployInformation(void); void Addsomethingup (CEmployee, CEmployee, CEmployee); string EmployeeName ; int hours ; int overtime_hours ; int iTotal_hours ; int iTotal_OvertimeHours ; float wage ; float basepay ; float overtime_pay ; float overtime_extra ; float iTotal_salaries ; float iIndividualSalary ; }; int main() { system("cls"); cout << "Welcome to the Employee Pay Center"; /* Use this section to define your objects. You will have one object per employee. You have only three employees. The format is your class name and your object name. */ std::cout << "Please enter Employee's Name: "; std::cin >> EmployeeName; std::cout << "Please enter Total Hours for (EmployeeName): "; std::cin >> hours; std::cout << "Please enter Base Pay for(EmployeeName): "; std::cin >> basepay; /* Here you will prompt for the first employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Example of Prompts Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the second employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will prompt for the third employee’s information. Prompt the employee name, hours worked, and the hourly wage. For each piece of information, you will update the appropriate class member defined above. Enter the employee name = Enter the hours worked = Enter his or her hourly wage = */ /* Here you will implement a function call to implement the employ calcuations for each object defined above. You will do this for each of the three employees or objects. The format for this step is the following: [(object name.function name(objectname.name, objectname.hours, objectname.wage)] ; */ /* This section you will send all three objects to a function that will add up the the following information: - Total Employee Salaries - Total Employee Hours - Total Overtime Hours The format for this function is the following: - Define a new object. - Implement function call [objectname.functionname(object name 1, object name 2, object name 3)] /* } //End of Main Function void CEmployee::ImplementCalculations (string EmployeeName, double hours, double wage){ //Initialize overtime variables overtime_hours=0; overtime_pay=0; overtime_extra=0; if (hours > 40) { /* This section is for the basic calculations for calculating overtime pay. - base pay = 40 hours times the hourly wage - overtime hours = hours worked – 40 - overtime pay = hourly wage * 1.5 - overtime extra pay over 40 = overtime hours * overtime pay - salary = overtime money over 40 hours + your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // if (hours > 40) else { /* Here you are going to calculate the hours less than 40 hours. - Your base pay is = your hours worked times your wage - Salary = your base pay */ /* Implement function call to output the employee information. Function is defined below. */ } // End of the else } //End of Primary Function void CEmployee::DisplayEmployInformation(); { // This function displays all the employee output information. /* This is your cout statements to display the employee information: Employee Name ............. = Base Pay .................. = Hours in Overtime ......... = Overtime Pay Amount........ = Total Pay ................. = */ } // END OF Display Employee Information void CEmployee::Addsomethingup (CEmployee Employ1, CEmployee Employ2) { // Adds two objects of class Employee passed as // function arguments and saves them as the calling object's data member values. /* Add the total hours for objects 1, 2, and 3. Add the salaries for each object. Add the total overtime hours. */ /* Then display the information below. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% EMPLOYEE SUMMARY DATA%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%% Total Employee Salaries ..... = 576.43 %%%% Total Employee Hours ........ = 108 %%%% Total Overtime Hours......... = 5 %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% */ } // End of function

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  • Why does C qicksort function implementation works much slower (tape comparations, tape swapping) than bobble sort function?

    - by Artur Mustafin
    I'm going to implement a toy tape "mainframe" for a students, showing the quickness of "quicksort" class functions (recursive or not, does not really matters, due to the slow hardware, and well known stack reversal techniques) comparatively to the "bubblesort" function class, so, while I'm clear about the hardware implementation ans controllers, i guessed that quicksort function is much faster that other ones in terms of sequence, order and comparation distance (it is much faster to rewind the tape from the middle than from the very end, because of different speed of rewind). Unfortunately, this is not the true, this simple "bubble" code shows great improvements comparatively to the "quicksort" functions in terms of comparison distances, direction and number of comparisons and writes. So I have 3 questions: Does I have mistaken in my implememtation of quicksort function? Does I have mistaken in my implememtation of bubblesoft function? If not, why the "bubblesort" function is works much faster in (comparison and write operations) than "quicksort" function? I already have a "quicksort" function: void quicksort(float *a, long l, long r, const compare_function& compare) { long i=l, j=r, temp, m=(l+r)/2; if (l == r) return; if (l == r-1) { if (compare(a, l, r)) { swap(a, l, r); } return; } if (l < r-1) { while (1) { i = l; j = r; while (i < m && !compare(a, i, m)) i++; while (m < j && !compare(a, m, j)) j--; if (i >= j) { break; } swap(a, i, j); } if (l < m) quicksort(a, l, m, compare); if (m < r) quicksort(a, m, r, compare); return; } } and the kind of my own implememtation of the "bubblesort" function: void bubblesort(float *a, long l, long r, const compare_function& compare) { long i, j, k; if (l == r) { return; } if (l == r-1) { if (compare(a, l, r)) { swap(a, l, r); } return; } if (l < r-1) { while(l < r) { i = l; j = l; while (i < r) { i++; if (!compare(a, j, i)) { continue; } j = i; } if (l < j) { swap(a, l, j); } l++; i = r; k = r; while(l < i) { i--; if (!compare(a, i, k)) { continue; } k = i; } if (k < r) { swap(a, k, r); } r--; } return; } } I have used this sort functions in a test sample code, like this: #include <stdio.h> #include <stdlib.h> #include <math.h> #include <conio.h> long swap_count; long compare_count; typedef long (*compare_function)(float *, long, long ); typedef void (*sort_function)(float *, long , long , const compare_function& ); void init(float *, long ); void print(float *, long ); void sort(float *, long, const sort_function& ); void swap(float *a, long l, long r); long less(float *a, long l, long r); long greater(float *a, long l, long r); void bubblesort(float *, long , long , const compare_function& ); void quicksort(float *, long , long , const compare_function& ); void main() { int n; printf("n="); scanf("%d",&n); printf("\r\n"); long i; float *a = (float *)malloc(n*n*sizeof(float)); sort(a, n, &bubblesort); print(a, n); sort(a, n, &quicksort); print(a, n); free(a); } long less(float *a, long l, long r) { compare_count++; return *(a+l) < *(a+r) ? 1 : 0; } long greater(float *a, long l, long r) { compare_count++; return *(a+l) > *(a+r) ? 1 : 0; } void swap(float *a, long l, long r) { swap_count++; float temp; temp = *(a+l); *(a+l) = *(a+r); *(a+r) = temp; } float tg(float x) { return tan(x); } float ctg(float x) { return 1.0/tan(x); } void init(float *m,long n) { long i,j; for (i = 0; i < n; i++) { for (j=0; j< n; j++) { m[i + j*n] = tg(0.2*(i+1)) + ctg(0.3*(j+1)); } } } void print(float *m, long n) { long i, j; for(i = 0; i < n; i++) { for(j = 0; j < n; j++) { printf(" %5.1f", m[i + j*n]); } printf("\r\n"); } printf("\r\n"); } void sort(float *a, long n, const sort_function& sort) { long i, sort_compare = 0, sort_swap = 0; init(a,n); for(i = 0; i < n*n; i+=n) { if (fmod (i / n, 2) == 0) { compare_count = 0; swap_count = 0; sort(a, i, i+n-1, &less); if (swap_count == 0) { compare_count = 0; sort(a, i, i+n-1, &greater); } sort_compare += compare_count; sort_swap += swap_count; } } printf("compare=%ld\r\n", sort_compare); printf("swap=%ld\r\n", sort_swap); printf("\r\n"); }

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  • Visual Studio C++ list iterator not decementable

    - by user69514
    I keep getting an error on visual studio that says list iterator not decrementable: line 256 My program works fine on Linux, but visual studio compiler throws this error. Dammit this is why I hate windows. Why can't the world run on Linux? Anyway, do you see what my problem is? #include <iostream> #include <fstream> #include <sstream> #include <list> using namespace std; int main(){ /** create the list **/ list<int> l; /** create input stream to read file **/ ifstream inputstream("numbers.txt"); /** read the numbers and add them to list **/ if( inputstream.is_open() ){ string line; istringstream instream; while( getline(inputstream, line) ){ instream.clear(); instream.str(line); /** get he five int's **/ int one, two, three, four, five; instream >> one >> two >> three >> four >> five; /** add them to the list **/ l.push_back(one); l.push_back(two); l.push_back(three); l.push_back(four); l.push_back(five); }//end while loop }//end if /** close the stream **/ inputstream.close(); /** display the list **/ cout << "List Read:" << endl; list<int>::iterator i; for( i=l.begin(); i != l.end(); ++i){ cout << *i << " "; } cout << endl << endl; /** now sort the list **/ l.sort(); /** display the list **/ cout << "Sorted List (head to tail):" << endl; for( i=l.begin(); i != l.end(); ++i){ cout << *i << " "; } cout << endl; list<int> lReversed; for(i=l.begin(); i != l.end(); ++i){ lReversed.push_front(*i); } cout << "Sorted List (tail to head):" << endl; for(i=lReversed.begin(); i!=lReversed.end(); ++i){ cout << *i << " "; } cout << endl << endl; /** remove first biggest element and display **/ l.pop_back(); cout << "List after removing first biggest element:" << endl; cout << "Sorted List (head to tail):" << endl; for( i=l.begin(); i != l.end(); ++i){ cout << *i << " "; } cout << endl; cout << "Sorted List (tail to head):" << endl; lReversed.pop_front(); for(i=lReversed.begin(); i!=lReversed.end(); ++i){ cout << *i << " "; } cout << endl << endl; /** remove second biggest element and display **/ l.pop_back(); cout << "List after removing second biggest element:" << endl; cout << "Sorted List (head to tail):" << endl; for( i=l.begin(); i != l.end(); ++i){ cout << *i << " "; } cout << endl; lReversed.pop_front(); cout << "Sorted List (tail to head):" << endl; for(i=lReversed.begin(); i!=lReversed.end(); ++i){ cout << *i << " "; } cout << endl << endl; /** remove third biggest element and display **/ l.pop_back(); cout << "List after removing third biggest element:" << endl; cout << "Sorted List (head to tail):" << endl; for( i=l.begin(); i != l.end(); ++i){ cout << *i << " "; } cout << endl; cout << "Sorted List (tail to head):" << endl; lReversed.pop_front(); for(i=lReversed.begin(); i!=lReversed.end(); ++i){ cout << *i << " "; } cout << endl << endl; /** create frequency table **/ const int biggest = 1000; //create array size of biggest element int arr[biggest]; //set everything to zero for(int j=0; j<biggest+1; j++){ arr[j] = 0; } //now update number of occurences for( i=l.begin(); i != l.end(); i++){ arr[*i]++; } //now print the frequency table. only print where occurences greater than zero cout << "Final list frequency table: " << endl; for(int j=0; j<biggest+1; j++){ if( arr[j] > 0 ){ cout << j << ": " << arr[j] << " occurences" << endl; } } return 0; }//end main

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  • Sending email to gmail account using c++ on windows error check

    - by LCD Fire
    I know this has been disscused a lot, but I I'm not asking how to do it, I'm just asking why it doesn't work. What I am doing wrong. It says that the email was sent succesfully but I don't see it in my inbox. I want to send an email to a gmail account, not through it. #include <iostream> #include <windows.h> #include <fstream> #include <conio.h> #pragma comment(lib, "ws2_32.lib") // Insist on at least Winsock v1.1 const int VERSION_MAJOR = 1; const int VERSION_MINOR = 1; #define CRLF "\r\n" // carriage-return/line feed pair using namespace std; // Basic error checking for send() and recv() functions void Check(int iStatus, char *szFunction) { if((iStatus != SOCKET_ERROR) && (iStatus)) return; cerr<< "Error during call to " << szFunction << ": " << iStatus << " - " << GetLastError() << endl; } int main(int argc, char *argv[]) { int iProtocolPort = 25; char szSmtpServerName[64] = ""; char szToAddr[64] = ""; char szFromAddr[64] = ""; char szBuffer[4096] = ""; char szLine[255] = ""; char szMsgLine[255] = ""; SOCKET hServer; WSADATA WSData; LPHOSTENT lpHostEntry; LPSERVENT lpServEntry; SOCKADDR_IN SockAddr; // Check for four command-line args //if(argc != 5) // ShowUsage(); // Load command-line args lstrcpy(szSmtpServerName, "smtp.gmail.com"); lstrcpy(szToAddr, "[email protected]"); lstrcpy(szFromAddr, "[email protected]"); // Create input stream for reading email message file ifstream MsgFile("D:\\d.txt"); // Attempt to intialize WinSock (1.1 or later) if(WSAStartup(MAKEWORD(VERSION_MAJOR, VERSION_MINOR), &WSData)) { cout << "Cannot find Winsock v" << VERSION_MAJOR << "." << VERSION_MINOR << " or later!" << endl; return 1; } // Lookup email server's IP address. lpHostEntry = gethostbyname(szSmtpServerName); if(!lpHostEntry) { cout << "Cannot find SMTP mail server " << szSmtpServerName << endl; return 1; } // Create a TCP/IP socket, no specific protocol hServer = socket(PF_INET, SOCK_STREAM, 0); if(hServer == INVALID_SOCKET) { cout << "Cannot open mail server socket" << endl; return 1; } // Get the mail service port lpServEntry = getservbyname("mail", 0); // Use the SMTP default port if no other port is specified if(!lpServEntry) iProtocolPort = htons(IPPORT_SMTP); else iProtocolPort = lpServEntry->s_port; // Setup a Socket Address structure SockAddr.sin_family = AF_INET; SockAddr.sin_port = iProtocolPort; SockAddr.sin_addr = *((LPIN_ADDR)*lpHostEntry->h_addr_list); // Connect the Socket if(connect(hServer, (PSOCKADDR) &SockAddr, sizeof(SockAddr))) { cout << "Error connecting to Server socket" << endl; return 1; } // Receive initial response from SMTP server Check(recv(hServer, szBuffer, sizeof(szBuffer), 0), "recv() Reply"); // Send HELO server.com sprintf(szMsgLine, "HELO %s%s", szSmtpServerName, CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() HELO"); Check(recv(hServer, szBuffer, sizeof(szBuffer), 0), "recv() HELO"); // Send MAIL FROM: <[email protected]> sprintf(szMsgLine, "MAIL FROM:<%s>%s", szFromAddr, CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() MAIL FROM"); Check(recv(hServer, szBuffer, sizeof(szBuffer), 0), "recv() MAIL FROM"); // Send RCPT TO: <[email protected]> sprintf(szMsgLine, "RCPT TO:<%s>%s", szToAddr, CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() RCPT TO"); Check(recv(hServer, szBuffer, sizeof(szBuffer), 0), "recv() RCPT TO"); // Send DATA sprintf(szMsgLine, "DATA%s", CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() DATA"); Check(recv(hServer, szBuffer, sizeof(szBuffer), 0), "recv() DATA"); //strat writing about the subject, end it with two CRLF chars and after that you can //write data to the body oif the message sprintf(szMsgLine, "Subject: My own subject %s%s", CRLF, CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() DATA"); // Send all lines of message body (using supplied text file) MsgFile.getline(szLine, sizeof(szLine)); // Get first line do // for each line of message text... { sprintf(szMsgLine, "%s%s", szLine, CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() message-line"); MsgFile.getline(szLine, sizeof(szLine)); // get next line. } while(!MsgFile.eof()); // Send blank line and a period sprintf(szMsgLine, "%s.%s", CRLF, CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() end-message"); Check(recv(hServer, szBuffer, sizeof(szBuffer), 0), "recv() end-message"); // Send QUIT sprintf(szMsgLine, "QUIT%s", CRLF); Check(send(hServer, szMsgLine, strlen(szMsgLine), 0), "send() QUIT"); Check(recv(hServer, szBuffer, sizeof(szBuffer), 0), "recv() QUIT"); // Report message has been sent cout<< "Sent " << argv[4] << " as email message to " << szToAddr << endl; // Close server socket and prepare to exit. closesocket(hServer); WSACleanup(); _getch(); return 0; }

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  • Criticize my code, please

    - by Micky
    Hey, I was applying for a position, and they asked me to complete a coding problem for them. I did so and submitted it, but I later found out I was rejected from the position. Anyways, I have an eclectic programming background so I'm not sure if my code is grossly wrong or if I just didn't have the best solution out there. I would like to post my code and get some feedback about it. Before I do, here's a description of a problem: You are given a sorted array of integers, say, {1, 2, 4, 4, 5, 8, 9, 9, 9, 9, 9, 9, 10, 10, 10, 11, 13 }. Now you are supposed to write a program (in C or C++, but I chose C) that prompts the user for an element to search for. The program will then search for the element. If it is found, then it should return the first index the entry was found at and the number of instances of that element. If the element is not found, then it should return "not found" or something similar. Here's a simple run of it (with the array I just put up): Enter a number to search for: 4 4 was found at index 2. There are 2 instances for 4 in the array. Enter a number to search for: -4. -4 is not in the array. They made a comment that my code should scale well with large arrays (so I wrote up a binary search). Anyways, my code basically runs as follows: Prompts user for input. Then it checks if it is within bounds (bigger than a[0] in the array and smaller than the largest element of the array). If so, then I perform a binary search. If the element is found, then I wrote two while loops. One while loop will count to the left of the element found, and the second while loop will count to the right of the element found. The loops terminate when the adjacent elements do not match with the desired value. EX: 4, 4, 4, 4, 4 The bold 4 is the value the binary search landed on. One loop will check to the left of it, and another loop will check to the right of it. Their sum will be the total number of instances of the the number four. Anyways, I don't know if there are any advanced techniques that I am missing or if I just don't have the CS background and made a big error. Any constructive critiques would be appreciated! #include <stdio.h> #include <stdlib.h> #include <string.h> #include <stddef.h> /* function prototype */ int get_num_of_ints( const int* arr, size_t r, int N, size_t* first, size_t* count ); int main() { int N; /* input variable */ int arr[]={1,1,2,3,3,4,4,4,4,5,5,7,7,7,7,8,8,8,9,11,12,12}; /* array of sorted integers */ size_t r = sizeof(arr)/sizeof(arr[0]); /* right bound */ size_t first; /* first match index */ size_t count; /* total number of matches */ /* prompts the user to enter input */ printf( "\nPlease input the integer you would like to find.\n" ); scanf( "%d", &N ); int a = get_num_of_ints( arr, r, N, &first, &count ); /* If the function returns -1 then the value is not found. Else it is returned */ if( a == -1) printf( "%d has not been found.\n", N ); else if(a >= 0){ printf( "The first matching index is %d.\n", first ); printf( "The total number of instances is %d.\n", count ); } return 0; } /* function definition */ int get_num_of_ints( const int* arr, size_t r, int N, size_t* first, size_t* count ) { int lo=0; /* lower bound for search */ int m=0; /* middle value obtained */ int hi=r-1; /* upper bound for search */ int w=r-1; /* used as a fixed upper bound to calculate the number of right instances of a particular value. */ /* binary search to find if a value exists */ /* first check if the element is out of bounds */ if( N < arr[0] || arr[hi] < N ){ m = -1; } else{ /* binary search to find a value, if it exists, within given parameters */ while(lo <= hi){ m = (hi + lo)/2; if(arr[m] < N) lo = m+1; else if(arr[m] > N) hi = m-1; else if(arr[m]==N){ m=m; break; } } if (lo > hi) /* if it doesn't we assign it -1 */ m = -1; } /* If the value is found, then we compute the left and right instances of it */ if( m >= 0 ){ int j = m-1; /* starting with the first term to the left */ int L = 0; /* total number of left instances */ /* while loop computes total number of left instances */ while( j >= 0 && arr[j] == arr[m] ){ L++; j--; } /* There are six possible outcomes of this. Depending on the outcome, we must assign the first index variable accordingly */ if( j > 0 && L > 0 ) *first=j+1; else if( j==0 && L==0) *first=m; else if( j > 0 && L==0 ) *first=m; else if(j < 0 && L==0 ) *first=m; else if( j < 0 && L > 0 ) *first=0; else if( j=0 && L > 0 ) *first=j+1; int h = m + 1; /* starting with the first term to the right */ int R = 0; /* total number of right instances */ /* while loop computes total number of right instances */ /* we fixed w earlier so that it's value does not change */ while( arr[h]==arr[m] && h <= w ){ R++; h++; } *count = (R + L + 1); /* total number of instances stored as value of count */ return *first; /* first instance index stored here */ } /* if value does not exist, then we return a negative value */ else if( m==-1) return -1; }

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  • Is it possible to pass a structure of delegates from managed to native?

    - by Veiva
    I am writing a wrapper for the game programming library "Allegro" and its less stable 4.9 branch. Now, I have done good insofar, except for when it comes to wrapping a structure of function pointers. Basically, I can't change the original code, despite having access to it, because that would require me to fork it in some manner. I need to know how I can somehow pass a structure of delegates from managed to native without causing an AccessViolationException that has occurred so far. Now, for the code. Here is the Allegro definition of the structure: typedef struct ALLEGRO_FILE_INTERFACE { AL_METHOD(ALLEGRO_FILE*, fi_fopen, (const char *path, const char *mode)); AL_METHOD(void, fi_fclose, (ALLEGRO_FILE *handle)); AL_METHOD(size_t, fi_fread, (ALLEGRO_FILE *f, void *ptr, size_t size)); AL_METHOD(size_t, fi_fwrite, (ALLEGRO_FILE *f, const void *ptr, size_t size)); AL_METHOD(bool, fi_fflush, (ALLEGRO_FILE *f)); AL_METHOD(int64_t, fi_ftell, (ALLEGRO_FILE *f)); AL_METHOD(bool, fi_fseek, (ALLEGRO_FILE *f, int64_t offset, int whence)); AL_METHOD(bool, fi_feof, (ALLEGRO_FILE *f)); AL_METHOD(bool, fi_ferror, (ALLEGRO_FILE *f)); AL_METHOD(int, fi_fungetc, (ALLEGRO_FILE *f, int c)); AL_METHOD(off_t, fi_fsize, (ALLEGRO_FILE *f)); } ALLEGRO_FILE_INTERFACE; My simple attempt at wrapping it: public delegate IntPtr AllegroInternalOpenFileDelegate(string path, string mode); public delegate void AllegroInternalCloseFileDelegate(IntPtr file); public delegate int AllegroInternalReadFileDelegate(IntPtr file, IntPtr data, int size); public delegate int AllegroInternalWriteFileDelegate(IntPtr file, IntPtr data, int size); public delegate bool AllegroInternalFlushFileDelegate(IntPtr file); public delegate long AllegroInternalTellFileDelegate(IntPtr file); public delegate bool AllegroInternalSeekFileDelegate(IntPtr file, long offset, int where); public delegate bool AllegroInternalIsEndOfFileDelegate(IntPtr file); public delegate bool AllegroInternalIsErrorFileDelegate(IntPtr file); public delegate int AllegroInternalUngetCharFileDelegate(IntPtr file, int c); public delegate long AllegroInternalFileSizeDelegate(IntPtr file); [StructLayout(LayoutKind.Sequential, Pack = 0)] public struct AllegroInternalFileInterface { [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalOpenFileDelegate fi_fopen; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalCloseFileDelegate fi_fclose; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalReadFileDelegate fi_fread; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalWriteFileDelegate fi_fwrite; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalFlushFileDelegate fi_fflush; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalTellFileDelegate fi_ftell; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalSeekFileDelegate fi_fseek; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalIsEndOfFileDelegate fi_feof; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalIsErrorFileDelegate fi_ferror; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalUngetCharFileDelegate fi_fungetc; [MarshalAs(UnmanagedType.FunctionPtr)] public AllegroInternalFileSizeDelegate fi_fsize; } I have a simple auxiliary wrapper that turns an ALLEGRO_FILE_INTERFACE into an ALLEGRO_FILE, like so: #define ALLEGRO_NO_MAGIC_MAIN #include <allegro5/allegro5.h> #include <stdlib.h> #include <string.h> #include <assert.h> __declspec(dllexport) ALLEGRO_FILE * al_aux_create_file(ALLEGRO_FILE_INTERFACE * fi) { ALLEGRO_FILE * file; assert(fi && "`fi' null"); file = (ALLEGRO_FILE *)malloc(sizeof(ALLEGRO_FILE)); if (!file) return NULL; file->vtable = (ALLEGRO_FILE_INTERFACE *)malloc(sizeof(ALLEGRO_FILE_INTERFACE)); if (!(file->vtable)) { free(file); return NULL; } memcpy(file->vtable, fi, sizeof(ALLEGRO_FILE_INTERFACE)); return file; } __declspec(dllexport) void al_aux_destroy_file(ALLEGRO_FILE * f) { assert(f && "`f' null"); assert(f->vtable && "`f->vtable' null"); free(f->vtable); free(f); } Lastly, I have a class that accepts a Stream and provides the proper methods to interact with the stream. Just to make sure, here it is: /// <summary> /// A semi-opaque data type that allows one to load fonts, etc from a stream. /// </summary> public class AllegroFile : AllegroResource, IDisposable { AllegroInternalFileInterface fileInterface; Stream fileStream; /// <summary> /// Gets the file interface. /// </summary> internal AllegroInternalFileInterface FileInterface { get { return fileInterface; } } /// <summary> /// Constructs an Allegro file from the stream provided. /// </summary> /// <param name="stream">The stream to use.</param> public AllegroFile(Stream stream) { fileStream = stream; fileInterface = new AllegroInternalFileInterface(); fileInterface.fi_fopen = Open; fileInterface.fi_fclose = Close; fileInterface.fi_fread = Read; fileInterface.fi_fwrite = Write; fileInterface.fi_fflush = Flush; fileInterface.fi_ftell = GetPosition; fileInterface.fi_fseek = Seek; fileInterface.fi_feof = GetIsEndOfFile; fileInterface.fi_ferror = GetIsError; fileInterface.fi_fungetc = UngetCharacter; fileInterface.fi_fsize = GetLength; Resource = AllegroFunctions.al_aux_create_file(ref fileInterface); if (!IsValid) throw new AllegroException("Unable to create file"); } /// <summary> /// Disposes of all resources. /// </summary> ~AllegroFile() { Dispose(); } /// <summary> /// Disposes of all resources used. /// </summary> public void Dispose() { if (IsValid) { Resource = IntPtr.Zero; // Should call AllegroFunctions.al_aux_destroy_file fileStream.Dispose(); } } IntPtr Open(string path, string mode) { return IntPtr.Zero; } void Close(IntPtr file) { fileStream.Close(); } int Read(IntPtr file, IntPtr data, int size) { byte[] d = new byte[size]; int read = fileStream.Read(d, 0, size); Marshal.Copy(d, 0, data, size); return read; } int Write(IntPtr file, IntPtr data, int size) { byte[] d = new byte[size]; Marshal.Copy(data, d, 0, size); fileStream.Write(d, 0, size); return size; } bool Flush(IntPtr file) { fileStream.Flush(); return true; } long GetPosition(IntPtr file) { return fileStream.Position; } bool Seek(IntPtr file, long offset, int whence) { SeekOrigin origin = SeekOrigin.Begin; if (whence == 1) origin = SeekOrigin.Current; else if (whence == 2) origin = SeekOrigin.End; fileStream.Seek(offset, origin); return true; } bool GetIsEndOfFile(IntPtr file) { return fileStream.Position == fileStream.Length; } bool GetIsError(IntPtr file) { return false; } int UngetCharacter(IntPtr file, int character) { return -1; } long GetLength(IntPtr file) { return fileStream.Length; } } Now, when I do something like this: AllegroFile file = new AllegroFile(new FileStream("Test.bmp", FileMode.Create, FileAccess.ReadWrite)); bitmap.SaveToFile(file, ".bmp"); ...I get an AccessViolationException. I think I understand why (the garbage collector can relocate structs and classes whenever), but I'd think that the method stub that is created by the framework would take this into consideration and route the calls to the valid classes. However, it seems obviously so that I'm wrong. So basically, is there any way I can successfully wrap that structure? (And I'm sorry for all the code! Hope it's not too much...)

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  • C++/CLI HTTP Proxy problems...

    - by darkantimatter
    Hi, I'm trying(very hard) to make a small HTTP Proxy server which I can use to save all communications to a file. Seeing as I dont really have any experience in the area, I used a class from codeproject.com and some associated code to get started (It was made in the old CLI syntax, so I converted it). I couldn't get it working, so I added lots more code to make it work (threads etc), and now it sort of works. Basically, it recieves something from a client (I just configured Mozilla Firefox to route its connections through this proxy) and then routes it to google.com. After it sends Mozilla's data to google, recieves a responce, and sends that to Mozilla. This works fine, but then the proxy fails to recieve any data from Mozilla. It just loops in the Sleep(50) section. Anyway, heres the code: ProxyTest.cpp: #include "stdafx.h" #include "windows.h" #include "CHTTPProxy.h" public ref class ClientThread { public: System::Net::Sockets::TcpClient ^ pClient; CHttpProxy ^ pProxy; System::Int32 ^ pRecieveBufferSize; System::Threading::Thread ^ Thread; ClientThread(System::Net::Sockets::TcpClient ^ sClient, CHttpProxy ^ sProxy, System::Int32 ^ sRecieveBufferSize) { pClient = sClient; pProxy = sProxy; pRecieveBufferSize = sRecieveBufferSize; }; void StartReading() { Thread = gcnew System::Threading::Thread(gcnew System::Threading::ThreadStart(this,&ClientThread::ThreadEntryPoint)); Thread->Start(); }; void ThreadEntryPoint() { char * bytess; bytess = new char[(int)pRecieveBufferSize]; memset(bytess, 0, (int)pRecieveBufferSize); array<unsigned char> ^ bytes = gcnew array<unsigned char>((int)pRecieveBufferSize); array<unsigned char> ^ sendbytes; do { if (pClient->GetStream()->DataAvailable) { try { do { Sleep(100); //Lets wait for whole packet to get cached (If it even does...) unsigned int k = pClient->GetStream()->Read(bytes, 0, (int)pRecieveBufferSize); //Read it for(unsigned int i=0; i<(int)pRecieveBufferSize; i++) bytess[i] = bytes[i]; Console::WriteLine("Packet Received:\n"+gcnew System::String(bytess)); pProxy->SendToServer(bytes,pClient->GetStream()); //Now send it to google! pClient->GetStream()->Flush(); } while(pClient->GetStream()->DataAvailable); } catch (Exception ^ e) { break; } } else { Sleep(50); //It just loops here because it thinks mozilla isnt sending anything if (!(pClient->Connected)) break; }; } while (pClient->GetStream()->CanRead); delete [] bytess; pClient->Close(); }; }; int main(array<System::String ^> ^args) { System::Collections::Generic::Stack<ClientThread ^> ^ Clients = gcnew System::Collections::Generic::Stack<ClientThread ^>(); System::Net::Sockets::TcpListener ^ pTcpListener = gcnew System::Net::Sockets::TcpListener(8080); pTcpListener->Start(); System::Net::Sockets::TcpClient ^ pTcpClient; while (1) { pTcpClient = pTcpListener->AcceptTcpClient(); //Wait for client ClientThread ^ Client = gcnew ClientThread(pTcpClient, gcnew CHttpProxy("www.google.com.au", 80), pTcpClient->ReceiveBufferSize); //Make a new object for this client Client->StartReading(); //Start the thread Clients->Push(Client); //Add it to the list }; pTcpListener->Stop(); return 0; } CHTTPProxy.h, from http://www.codeproject.com/KB/IP/howtoproxy.aspx with a lot of modifications: //THIS FILE IS FROM http://www.codeproject.com/KB/IP/howtoproxy.aspx. I DID NOT MAKE THIS! BUT I HAVE MADE SEVERAL MODIFICATIONS! #using <mscorlib.dll> #using <SYSTEM.DLL> using namespace System; using System::Net::Sockets::TcpClient; using System::String; using System::Exception; using System::Net::Sockets::NetworkStream; #include <stdio.h> ref class CHttpProxy { public: CHttpProxy(System::String ^ szHost, int port); System::String ^ m_host; int m_port; void SendToServer(array<unsigned char> ^ Packet, System::Net::Sockets::NetworkStream ^ sendstr); }; CHttpProxy::CHttpProxy(System::String ^ szHost, int port) { m_host = gcnew System::String(szHost); m_port = port; } void CHttpProxy::SendToServer(array<unsigned char> ^ Packet, System::Net::Sockets::NetworkStream ^ sendstr) { TcpClient ^ tcpclnt = gcnew TcpClient(); try { tcpclnt->Connect(m_host,m_port); } catch (Exception ^ e ) { Console::WriteLine(e->ToString()); return; } // Send it if ( tcpclnt ) { NetworkStream ^ networkStream; networkStream = tcpclnt->GetStream(); int size = Packet->Length; networkStream->Write(Packet, 0, size); array<unsigned char> ^ bytes = gcnew array<unsigned char>(tcpclnt->ReceiveBufferSize); char * bytess = new char[tcpclnt->ReceiveBufferSize]; Sleep(500); //Wait for responce do { unsigned int k = networkStream->Read(bytes, 0, (int)tcpclnt->ReceiveBufferSize); //Read from google for(unsigned int i=0; i<k; i++) { bytess[i] = bytes[i]; if (bytess[i] == 0) bytess[i] = ' '; //Dont terminate the string if (bytess[i] < 8) bytess[i] = ' '; //Somethings making the computer beep, and its not 7?!?! }; Console::WriteLine("\n\nAbove packet sent to google. Google Packet Received:\n"+gcnew System::String(bytess)); sendstr->Write(bytes,0,k); //Send it to mozilla Console::WriteLine("\n\nAbove packet sent to client..."); //Sleep(1000); } while(networkStream->DataAvailable); delete [] bytess; } return; } Any help would be much appreciated, I've tried for hours.

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  • what "Debug Assertion Failed" mean and how to fix it, c++?

    - by nonon
    hi, why this program gives me a "Debug Assertion Failed" Error Message while running #include "stdafx.h" #include "iostream" #include "fstream" #include "string" using namespace std; int conv_ch(char b) { int f; f=b; b=b+0; switch(b) { case 48: f=0; break; case 49: f=1; break; case 50: f=2; break; case 51: f=3; break; case 52: f=4; break; case 53: f=5; break; case 54: f=6; break; case 55: f=7; break; case 56: f=8; break; case 57: f=9; break; default: f=0; } return f; } class Student { public: string id; size_t id_len; string first_name; size_t first_len; string last_name; size_t last_len; string phone; size_t phone_len; string grade; size_t grade_len; void print(); void clean(); }; void Student::clean() { id.erase (id.begin()+6, id.end()); first_name.erase (first_name.begin()+15, first_name.end()); last_name.erase (last_name.begin()+15, last_name.end()); phone.erase (phone.begin()+10, phone.end()); grade.erase (grade.begin()+2, grade.end()); } void Student::print() { int i; for(i=0;i<6;i++) { cout<<id[i]; } cout<<endl; for(i=0;i<15;i++) { cout<<first_name[i]; } cout<<endl; for(i=0;i<15;i++) { cout<<last_name[i]; } cout<<endl; for(i=0;i<10;i++) { cout<<phone[i]; } cout<<endl; for(i=0;i<2;i++) { cout<<grade[i]; } cout<<endl; } int main() { Student k[80]; char data[1200]; int length,i,recn=0; int rec_length; int counter = 0; fstream myfile; char x1,x2; char y1,y2; char zz; int ad=0; int ser,j; myfile.open ("example.txt",ios::in); int right; int left; int middle; string key; while(!myfile.eof()){ myfile.get(data,1200); char * pch; pch = strtok (data, "#"); printf ("%s\n", pch); j=0; for(i=0;i<6;i++) { k[recn].id[i]=data[j]; j++; } for(i=0;i<15;i++) { k[recn].first_name[i]=data[j]; j++; } for(i=0;i<15;i++) { k[recn].last_name[i]=data[j]; j++; } for(i=0;i<10;i++) { k[recn].phone[i]=data[j]; j++; } for(i=0;i<2;i++) { k[recn].grade[i]=data[j]; j++; } recn++; j=0; } //cout<<recn; string temp1; size_t temp2; int temp3; for(i=0;i<recn-1;i++) { for(j=0;j<recn-1;j++) { if(k[i].id.compare(k[j].id)<0) { temp1 = k[i].first_name; k[i].first_name = k[j].first_name; k[j].first_name = temp1; temp2 = k[i].first_len; k[i].first_len = k[j].first_len; k[j].first_len = temp2; temp1 = k[i].last_name; k[i].last_name = k[j].last_name; k[j].last_name = temp1; temp2 = k[i].last_len; k[i].last_len = k[j].last_len; k[j].last_len = temp2; temp1 = k[i].grade; k[i].grade = k[j].grade; k[j].grade = temp1; temp2 = k[i].grade_len; k[i].grade_len = k[j].grade_len; k[j].grade_len = temp2; temp1 = k[i].id; k[i].id = k[j].id; k[j].id = temp1; temp2 = k[i].id_len; k[i].id_len = k[j].id_len; k[j].id_len = temp2; temp1 = k[i].phone; k[i].phone = k[j].phone; k[j].phone = temp1; temp2 = k[i].phone_len; k[i].phone_len = k[j].phone_len; k[j].phone_len = temp2; } } } for(i=0;i<recn-1;i++) { k[i].clean(); } char z; string id_sear; cout<<"Enter 1 to display , 2 to search , 3 to exit:"; cin>>z; while(1){ switch(z) { case '1': for(i=0;i<recn-1;i++) { k[i].print(); } break; case '2': cin>>key; right=0; left=recn-2; while(right<=left) { middle=((right+left)/2); if(key.compare(k[middle].id)==0){ cout<<"Founded"<<endl; k[middle].print(); break; } else if(key.compare(k[middle].id)<0) { left=middle-1; } else { right=middle+1; } } break; case '3': exit(0); break; } cout<<"Enter 1 to display , 2 to search , 3 to exit:"; cin>>z; } return 0; } the program reads from a file example.txt 313121crewwe matt 0114323111A # 433444cristinaee john 0113344325A+# 324311matte richee 3040554032B # the idea is to read fixed size field structure with a text seprator record strucutre

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  • Simple C++ program on multidimensional arrays - Getting C2143 error among others. Not sure why?

    - by noobzilla
    Here is my simple multidimensional array program. The first error occurs where I declare the function addmatrices and then a second one where it is implemented. I am also getting an undefined variable error for bsize. What am I doing incorrectly? #include <iostream> #include <fstream> #include <string> #include <iomanip> using namespace std; //Function declarations void constmultiply (double matrixA[][4], int asize, double matrixC[][4], int bsize, double multiplier); //Pre: The address of the output file, the matrix to be multiplied by the constant, the matrix in which // the resultant values will be stored and the multiplier are passed in. //Post: The matrix is multiplied by the multiplier and the results are displayed on screen and written to the // output file. int addmatrices (double matrixA[][4], int asize, double matrixB[]4], int bsize, double matrixC[][4], int csize); //Pre: The addresses of three matrices are passed in //Post: The values in each of the two matrices are added together and put into a third matrix //Error Codes int INPUT_FILE_FAIL = 1; int UNEQUAL_MATRIX_SIZE = 2; //Constants const double multiplier = 2.5; const int rsize = 4; const int csize = 4; //Main Driver int main() { //Declare the two matrices double matrix1 [rsize][csize]; double matrix2 [rsize][csize]; double matrix3 [rsize][csize]; //Variables double temp; string filename; //Declare filestream object ifstream infile; //Ask the user for the name of the input file cout << "Please enter the name of the input file: "; cin >> filename; //Open the filestream object infile.open(filename.c_str()); //Verify that the input file opened correctly if (infile.fail()) { cout << "Input file failed to open" <<endl; exit(INPUT_FILE_FAIL); } //Begin reading in data from the first matrix for (int i = 0; i <= 3; i++)//i = row { for (int j = 0; j <= 3; j++)// j = column { infile >> temp; matrix1[i][j] = temp; } } //Begin reading in data from the second matrix for (int k = 0; k <= 3; k++)// k = row { for (int l = 0; l <= 3; l++)// l = column { infile >> temp; matrix2[k][l] = temp; } } //Notify user cout << "Input file open, reading matrices...Done!" << endl << "Read in 2 matrices..."<< endl; //Output the values read in for Matrix 1 for (int i = 0; i <= 3; i++) { for (int j = 0; j <= 3; j ++) { cout << setprecision(1) << matrix1[i][j] << setw(8); } cout << "\n"; } cout << setw(40)<< setfill('-') << "-" << endl ; //Output the values read in for Matrix 2 for (int i = 0; i <= 3; i++) { for (int j = 0; j <= 3; j ++) { cout << setfill(' ') << setprecision(2) << matrix2[i][j] << setw(8); } cout << "\n"; } cout << setw(40)<< setfill('-') << "-" << endl ; //Multiply matrix 1 by the multiplier value constmultiply (matrix1, rsize, matrix3, rsize, multiplier); //Output matrix 3 values to screen for (int i = 0; i <= 3; i++) { for (int j = 0; j <= 3; j ++) { cout << setfill(' ') << setprecision(2) << matrix3[i][j] << setw(8); } cout << "\n"; } cout << setw(40)<< setfill('-') << "-" << endl ; // //Add matrix1 and matrix2 // addmatrices (matrix1, 4, matrix2, 4, matrix3, 4); // //Finished adding. Now output matrix 3 values to screen // for (int i = 0; i <= 3; i++) // { //for (int j = 0; j <= 3; j ++) //{ // cout << setfill(' ') << setprecision(2) << matrix3[i][j] << setw(8); //} //cout << "\n"; // } // cout << setw(40)<< setfill('-') << "-" << endl ; //Close the input file infile.close(); return 0; } //Function implementation void constmultiply (double matrixA[][4], int asize, double matrixC[][4], int bsize, double multiplier) { //Loop through each row and multiply the value at that location with the multiplier for (int i = 0; i < asize; i++) { for (int j = 0; j < 4; j++) { matrixC[i][j] = matrixA[i][j] * multiplier; } } } int addmatrices (double matrixA[][4], int asize, double matrixB[]4], int bsize, double matrixC[][4], int csize) { //Remember that you can only add two matrices that have the same shape - i.e. They need to have an equal //number of rows and columns. Let's add some error checking for that: if(asize != bsize) { cout << "You are attempting to add two matrices that are not equal in shape. Program terminating!" << endl; return exit(UNEQUAL_MATRIX_SIZE); } //Confirmed that the matrices are of equal size, so begin adding elements for (int i = 0; i < asize; i++) { for (int j = 0; j < bsize; j++) { matrixC[i][j] = matrixA[i][j] + matrixB[i][j]; } } }

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  • how to properly transfer user input from index to invoice?

    - by Romel
    I got a dillema, I'm trying to find a solution for my code. How do I make it so that when the user inputs a given quantity in the text box from the index.php it will transfer that input quantity to the invoice.php. I've tried doing the post method but it seems like it's not working :/ As always, any help or suggestions will be greatly appreciated! I hope it's something simple:( Here's my code: index.php <html> <style> body{ background-image: url('URL HERE'); font-family: "Helvetica"; font-size:15px; } h1{ color:black; text-align:center; } p{ font-size:15px; } </style> <h1> STORE TITLE HERE </h1> <body> <form action="login.php" method="post"> <?php //Include products info.inc (Which holds all our product arrays and info) //Credit: Tracy & Mark (THank you!) include 'products_info.inc'; /*The following code centers my table on the page, makes the table background white, makes the table 50% of the browser window, gives it a border of 1 px, gives a padding of 2 px between the cell border and content, and gives 1 px of spacing between cells. */ echo "<table align=center bgcolor='FFFFFF' width=50% border=1 cellpadding=1 cellspacing=2>"; //Credit: Tracy & Mark (THank you!) echo '<th>Product</th> <th>Description</th> <th>Price</th> <th>Quantity</th>'; //The following code loops through the whole table body and then prints each row. for($i=0; $i<count($allfood); $i++) { //Credit: Tracy & Mark (THank you!) echo "<tr align=center>"; echo "<td>{$allfood[$i]['Product']}</td>"; echo "<td>{$allfood[$i]['Description']}</td>"; echo "<td>{$allfood[$i]['Price']}</td>"; echo "<td>{$allfood[$i]['Quantity']}</td>"; echo "</tr>"; } //This code ends the table. echo "</table>"; echo "<br>"; ?> <br><center><input type='submit' name='purchase' value='Purchase'></center> </form> </body> </html> And here's my invoice.php <html> <style> body{ background-image: url('URL HERE'); font-family: "Helvetica"; font-size:15px; } h1{ color:black; text-align:center; } p{ font-size:15px; } </style> <h1> Invoice </h1> </html> <?php //Include products info.inc (Which holds all our product arrays and info) //Credit: Tracy & Mark (Thank you!) include 'products_info.inc'; //Display the invoice & 'WELCOME USER. THANK YOU FOR USING THIS DAMN THING msg' /*The following code centers my invoice table on the page, makes the table background white, makes the table 50% of the browser window, gives it a border of 1 px, gives a padding of 2 px between the cell border and content, and gives 1 px of spacing between cells. */ echo "<table align=center bgcolor='FFFFFF' width=50% border=1 cellpadding=1cellspacing=2>"; echo "<tr>"; echo "<td align=center><b>Product</b></td>"; echo "<td align=center><b>Quantity</b></td>"; echo "<td align=center><b>Price</></td>"; echo "<td align=center><b>Extended Price</b></td>"; echo "</tr>"; for($i=0; $i<count($allfood); $i++) { //Credit: Tracy & Mark (Thank you!) $qty= @$_POST['Quantity']['$i']; // This calculates the price if the user orders more than 1 item. $extendedprice = $qty*$allfood[$i]['Price']; echo "<tr>"; echo "<td align=center>{$allfood[$i]['Product']}</td>"; echo "<td align=center>$extendedprice</td>"; echo "<td align=center>{$allfood[$i]['Price']}</td>"; echo "</tr>"; } // The goal here was to make it so that if the user selected a certain quantity from index.php, it would carry over and display on the invoice.php if ($qty = 0) { echo "please choose 1"; } elseif ($qty > 0) { echo $qty; } /*echo "<tr>"; echo "<td align=center>Subtotal</b></td>"; echo "<td align=center></td>"; echo "<td align=center></td>"; echo "<tr>"; echo "<td align=center>Tax at 5.75%</td>"; echo "<td align=center></td>"; echo "<td align=center></td>"; echo "<tr>"; echo "<td align=center><b>Grand total</b></td>"; echo "<td align=center></td>"; echo "<td align=center></td>"; */ echo "</table>"; ?> <br> <center> <form action="index.php" method="post"> <input type="submit" name="home" value="Back to homepage"> </form> </center>

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  • Remotely Schedule and Stream Recorded TV in Windows 7 Media Center

    - by DigitalGeekery
    Have you ever been away from home and suddenly realized you forgot to record your favorite program? Now Windows 7 Media Center, users can schedule recordings remotely from their phones or mobile devices with Remote Potato. How it Works Remote Potato installs server software on the host computer running Windows 7 Media Center. Once the software is installed, we’ll need to do some port forwarding on the router and setup an optional dynamic DNS address. When setup is completed, we will access the application through a web based interface. Silverlight is required for Streaming recorded TV, but scheduling recordings can be done through an HTML interface. Installing Remote Potato Download and install Remote Potato on the Media Center PC. (See download link below) If you plan to stream any Recorded TV, you’ll also want to install the streaming pack located on the same page. It isn’t required to stream all shows, only shows that require the AC3 audio codec. Click Yes to allow Remote Potato to add rules to the Windows Firewall for remote access. You’ll likely need to accept a few UAC prompts. When notified that the rules were added, click OK. Remote Potato will then prompt you to allow administrator privileges to reserve a URL for it’s web server. Click Yes. Remote Potato server will start. Click on the configuration button at the right to to reveal the settings tabs.   One the General tab, you’ll have the option to run Remote Potato on startup and minimized in the System Tray. If you’re running Media Center on a dedicated HTPC, you’ll probably want to enable both startup options. Forwarding Ports on Your Router You’ll need to forward a couple ports on your router. By default, these will be ports 9080 and 9081. In this example we’re using a Linksys WRT54GL router, however, the steps for port forwarding will vary from router to router. On the Linksys configuration page, click on the Applications & Gaming Tab, and then the Port Range Forward tab. Under Application, type in a name of your choosing. In both the Start and End boxes, type the port number 9080. Enter the local IP address of your Media Center computer in the IP address column. Click the check box under Enable. Repeat the process on the next line, but this time use port 9081. When finished, click the Save Settings button. Note: It’s highly recommended that you configure the home computer running Media Center & Remote Potato with a static IP address.   Find your IP Address You’ll need to find the IP address assigned to your router from your ISP. There are many ways to do this but a quick and easy way is to visit a site like checkip.dyndns.org (link available below) The current external IP address of your router will be displayed in the browser.   Dynamic DNS This is an optional step, but  it’s highly recommended. Many routers, such as the Linksys WRT54GL we are using, support Dynamic DNS (DDNS). What Dynamic DNS allows you to do is affiliate your home router’s external IP address to a domain name. Every time your home router is assigned a a new IP address by your ISP, the domain name is updated to point to your new IP address. Remote Potato’s user interface is accessed over the Internet is by connecting to your router’s IP address followed by a colon and the port number. (Ex: XXX.XXX.XXX.XXX:9080) Instead of constantly having to look up and remember an IP address, you can use DDNS along with a 3rd party provider like DynDNS.com, to sign up for a free domain name and configure it to be updated each time your router is assigned a new IP address. Go to the DynDNS.com website (See link at the end of the article) and sign up for a free Domain name. You’ll need to register and confirm by email.   Once you’ve signed in and selected your domain name click Activate Services. You’ll get a confirmation message that your domain name has been activated.    On the Linksys WRT54GL click on the Setup tab an then DDNS. Select DynDNS.org, or TZO.com if you prefer to use their service, from the drop down list.   With DynDNS, you’ll need to fill in your username and password you signed up with at the DynDNS website and the hostname you chose. Note: You can connect over your local network with the IP Address of the computer running Remote Potato followed by a colon and the port number. Ex: 192.168.1.2:9080 Logging in Remote Potato and Recording a Show Once you connect, you’ll see the start page. To view the TV listings, click on TV Guide. You’ll then see your guide listings. There are a few ways to navigate the listings. At the top left, you can click on any of the preset time buttons to jump to  the listings at that time of the day.  Click on the arrows to the right and left of the day and date at the top center to proceed to the previous or next day. Or, jump to a specific day with the date and date buttons at the top right.   To setup a recording, click on a program.   You can choose to record the individual show or the entire series by clicking on Record Show or Record Series.   Remote Potato on Mobile Devices Perhaps the coolest feature of Remote Potato is the ability to schedule recording from your phone or mobile device. Note: For any devices or computers without Silverlight, you will be prompted to view the HTML page. Select Browse Listings. Select your program to record. In the Program Details, select Record Show to record the single episode or Record Series to record all instances of the series. You will then see a red dot on the program listing to indicate that the show is scheduled for recording.   Streaming Recorded TV Click on Recorded TV from the home screen to access your previously recorded TV programs. Click on the selection you wish to stream. Click on Play. If you receive this error message, you’ll need to install the streaming pack for Remote Potato. This is found on the same download page as installation files. (See link below) The Begin from slider allows you to start playback from the start (by default) or a different time of the program by moving the slider. The Quality (bitrate) setting  allows you to choose the quality of the playback. We found the video quality on the Normal setting to be pretty lousy, and Low was just pointless. High was the best overall viewing experience as it provided smooth quality video playback. We experienced significant stuttering during playback using the Ultra High setting.   Click Start when you are ready to begin. When playback begins you’ll see a slider at the top right.   Move the slider left or right to increase or decrease the size of the video. There’s also a button to switch to full screen.   Media Center users who travel frequently or are always on the go will likely find Remote Potato to be a blessing. Since being released earlier this year, updates for Remote Potato have come fast and furious. The latest beta release includes support for streaming music and photos. If you like those nice network TV logos, check out our article on adding TV channel logos to Windows Media Center. Downloads and Links Download Remote Potato and Streaming Pack Find your IP address Sign Up for a Domain Name at DynDNS.com Similar Articles Productive Geek Tips Schedule Updates for Windows Media CenterUsing Netflix Watchnow in Windows Vista Media Center (Gmedia)Add a Sleep Timer to Windows 7 Media CenterStartup Customizations for Media Center in Windows 7Enable Media Streaming in Windows Home Server to Windows Media Player TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 FoxClocks adds World Times in your Statusbar (Firefox) Have Fun Editing Photo Editing with Citrify Outlook Connector Upgrade Error Gadfly is a cool Twitter/Silverlight app Enable DreamScene in Windows 7 Microsoft’s “How Do I ?” Videos

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  • How to Upgrade Your Netbook to Windows 7 Home Premium

    - by Matthew Guay
    Would you like more features and flash in Windows on your netbook?  Here’s how you can easily upgrade your netbook to Windows 7 Home Premium the easy way. Most new netbooks today ship with Windows 7 Starter, which is the cheapest edition of Windows 7.  It is fine for many computing tasks, and will run all your favorite programs great, but it lacks many customization, multimedia, and business features found in higher editions.  Here we’ll show you how you can quickly upgrade your netbook to more full-featured edition of Windows 7 using Windows Anytime Upgrade.  Also, if you want to upgrade your laptop or desktop to another edition of Windows 7, say Professional, you can follow these same steps to upgrade it, too. Please note: This is only for computers already running Windows 7.  If your netbook is running XP or Vista, you will have to run a traditional upgrade to install Windows 7. Upgrade Advisor First, let’s make sure your netbook can support the extra features, such as Aero Glass, in Windows 7 Home Premium.  Most modern netbooks that ship with Windows 7 Starter can run the advanced features in Windows 7 Home Premium, but let’s check just in case.  Download the Windows 7 Upgrade Advisor (link below), and install as normal. Once it’s installed, run it and click Start Check.   Make sure you’re connected to the internet before you run the check, or otherwise you may see this error message.  If you see it, click Ok and then connect to the internet and start the check again. It will now scan all of your programs and hardware to make sure they’re compatible with Windows 7.  Since you’re already running Windows 7 Starter, it will also tell you if your computer will support the features in other editions of Windows 7. After a few moments, the Upgrade Advisor will show you want it found.  Here we see that our netbook, a Samsung N150, can be upgraded to Windows 7 Home Premium, Professional, or Ultimate. We also see that we had one issue, but this was because a driver we had installed was not recognized.  Click “See all system requirements” to see what your netbook can do with the new edition. This shows you which of the requirements, including support for Windows Aero, your netbook meets.  Here our netbook supports Aero, so we’re ready to go upgrade. For more, check out our article on how to make sure your computer can run Windows 7 with Upgrade Advisor. Upgrade with Anytime Upgrade Now, we’re ready to upgrade our netbook to Windows 7 Home Premium.  Enter “Anytime Upgrade” in the Start menu search,and select Windows Anytime Upgrade. Windows Anytime Upgrade lets you upgrade using product key you already have or one you purchase during the upgrade process.  And, it installs without any downloads or Windows disks, so it works great even for netbooks without DVD drives. Anytime Upgrades are cheaper than a standard upgrade, and for a limited time, select retailers in the US are offering Anytime Upgrades to Windows 7 Home Premium for only $49.99 if purchased with a new netbook.  If you already have a netbook running Windows 7 Starter, you can either purchase an Anytime Upgrade package at a retail store or purchase a key online during the upgrade process for $79.95.  Or, if you have a standard Windows 7 product key (full or upgrade), you can use it in Anytime upgrade.  This is especially nice if you can purchase Windows 7 cheaper through your school, university, or office. Purchase an upgrade online To purchase an upgrade online, click “Go online to choose the edition of Windows 7 that’s best for you”.   Here you can see a comparison of the features of each edition of Windows 7.  Note that you can upgrade to either Home Premium, Professional, or Ultimate.  We chose home Premium because it has most of the features that home users want, including Media Center and Aero Glass effects.  Also note that the price of each upgrade is cheaper than the respective upgrade from Windows XP or Vista.  Click buy under the edition you want.   Enter your billing information, then your payment information.  Once you confirm your purchase, you will directly be taken to the Upgrade screen.  Make sure to save your receipt, as you will need the product key if you ever need to reinstall Windows on your computer. Upgrade with an existing product key If you purchased an Anytime Upgrade kit from a retailer, or already have a Full or Upgrade key for another edition of Windows 7, choose “Enter an upgrade key”. Enter your product key, and click Next.  If you purchased an Anytime Upgrade kit, the product key will be located on the inside of the case on a yellow sticker. The key will be verified as a valid key, and Anytime Upgrade will automatically choose the correct edition of Windows 7 based on your product key.  Click Next when this is finished. Continuing the Upgrade process Whether you entered a key or purchased a key online, the process is the same from here on.  Click “I accept” to accept the license agreement. Now, you’re ready to install your upgrade.  Make sure to save all open files and close any programs, and then click Upgrade. The upgrade only takes about 10 minutes in our experience but your mileage may vary.  Any available Microsoft updates, including ones for Office, Security Essentials, and other products, will be installed before the upgrade takes place. After a couple minutes, your computer will automatically reboot and finish the installation.  It will then reboot once more, and your computer will be ready to use!  Welcome to your new edition of Windows 7! Here’s a before and after shot of our desktop.  When you do an Anytime Upgrade, all of your programs, files, and settings will be just as they were before you upgraded.  The only change we noticed was that our pinned taskbar icons were slightly rearranged to the default order of Internet Explorer, Explorer, and Media Player.  Here’s a shot of our desktop before the upgrade.  Notice that all of our pinned programs and desktop icons are still there, as well as our taskbar customization (we are using small icons on the taskbar instead of the default large icons). Before, with the Windows 7 Starter background and the Aero Basic theme: And after, with Aero Glass and the more colorful default Windows 7 background.   All of the features of Windows 7 Home Premium are now ready to use.  The Aero theme was activate by default, but you can now customize your netbook theme, background, and more with the Personalization pane.  To open it, right-click on your desktop and select Personalize. You can also now use Windows Media Center, and can play-back DVD movies using an external drive. One of our favorite tools, the Snipping Tool, is also now available for easy screenshots and clips. Activating you new edition of Windows 7 You will still need to activate your new edition of Windows 7.  To do this right away, open the start menu, right-click on Computer, and select Properties.   Scroll to the bottom, and click “Activate Windows Now”. Make sure you’re connected to the internet, and then select “Activate Windows online now”. Activation may take a few minutes, depending on your internet connection speed. When it is done, the Activation wizard will let you know that Windows is activated and genuine.  Your upgrade is all finished! Conclusion Windows Anytime Upgrade makes it easy, and somewhat cheaper, to upgrade to another edition of Windows 7.  It’s useful for desktop and laptop owners who want to upgrade to Professional or Ultimate, but many more netbook owners will want to upgrade from Starter to Home Premium or another edition.  Links Download the Windows 7 Upgrade Advisor Windows Team Blog: Anytime Upgrade Special with new PC purchase Similar Articles Productive Geek Tips How To Upgrade from Vista to Windows 7 Home Premium EditionAnother Blog You Should Subscribe ToMysticgeek Blog: Turn Vista Home Premium Into Ultimate (Part 3) – Shadow CopyUpgrade Ubuntu from Breezy to DapperHow to Upgrade the Windows 7 RC to RTM (Final Release) TouchFreeze Alternative in AutoHotkey The Icy Undertow Desktop Windows Home Server – Backup to LAN The Clear & Clean Desktop Use This Bookmarklet to Easily Get Albums Use AutoHotkey to Assign a Hotkey to a Specific Window Latest Software Reviews Tinyhacker Random Tips DVDFab 6 Revo Uninstaller Pro Registry Mechanic 9 for Windows PC Tools Internet Security Suite 2010 Get Your Delicious Bookmarks In Firefox’s Awesome Bar Manage Photos Across Different Social Sites With Dropico Test Drive Windows 7 Online Download Wallpapers From National Geographic Site Spyware Blaster v4.3 Yes, it’s Patch Tuesday

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  • git on HTTP with gitolite and nginx

    - by Arnaud
    I am trying to setup a server where my git repo would be accessible with HTTP(S). I am using gitolite and nginx (and gitlab for web interface but I doubt it makes any difference). I have searched the whole afternoon and I think I'm stuck. I have think I have understood that nginx needs fcgiwrap to work with gitolite, so I tried several configurations, but none of them work. My repositories are at /home/git/repositories. Here's the three nginx configurations I have tried. 1: location ~ /git(/.*) { gzip off; root /usr/lib/git-core; fastcgi_pass unix:/var/run/fcgiwrap.socket; include /etc/nginx/fcgiwrap.conf; fastcgi_param SCRIPT_FILENAME /usr/lib/git-core/git-http-backend; fastcgi_param DOCUMENT_ROOT /usr/lib/git-core/; fastcgi_param SCRIPT_NAME git-http-backend; fastcgi_param GIT_HTTP_EXPORT_ALL ""; fastcgi_param GIT_PROJECT_ROOT /home/git/repositories; fastcgi_param PATH_INFO $1; #fastcgi_param PATH_TRANSLATED $document_root$fastcgi_path_info; } Result: > git clone http://myservername/projectname.git test/ Cloning into test... fatal: http://myservername/projectname.git/info/refs not found: did you run git update-server-info on the server? and > git clone http://myservername/git/projectname.git test/ Cloning into test... error: The requested URL returned error: 502 while accessing http://myservername/git/projectname.git/info/refs fatal: HTTP request failed 2: location ~ /git(/.*) { fastcgi_pass localhost:9001; include /etc/nginx/fcgiwrap.conf; fastcgi_param SCRIPT_FILENAME /usr/lib/git-core/git-http-backend; fastcgi_param GIT_HTTP_EXPORT_ALL ""; fastcgi_param GIT_PROJECT_ROOT /home/git/repositories; fastcgi_param PATH_INFO $1; } Result: > git clone http://myservername/projectname.git test/ Cloning into test... fatal: http://myservername/projectname.git/info/refs not found: did you run git update-server-info on the server? and > git clone http://myservername/git/projectname.git test/ Cloning into test... error: The requested URL returned error: 502 while accessing http://myservername/git/projectname.git/info/refs fatal: HTTP request failed 3: location ~ ^.*\.git/objects/([0-9a-f]+/[0-9a-f]+|pack/pack-[0-9a-f]+.(pack|idx))$ { root /home/git/repositories/; } location ~ ^.*\.git/(HEAD|info/refs|objects/info/.*|git-(upload|receive)-pack)$ { root /home/git/repositories; fastcgi_pass unix:/var/run/fcgiwrap.socket; fastcgi_param SCRIPT_FILENAME /usr/lib/git-core/git-http-backend; fastcgi_param PATH_INFO $uri; fastcgi_param GIT_PROJECT_ROOT /home/git/repositories; include /etc/nginx/fcgiwrap.conf; } Result: > git clone http://myservername/projectname.git test/ Cloning into test... error: The requested URL returned error: 502 while accessing http://myservername/projectname.git/info/refs fatal: HTTP request failed and > git clone http://myservername/git/projectname.git test/ Cloning into test... error: The requested URL returned error: 502 while accessing http://myservername/git/projectname.git/info/refs fatal: HTTP request failed Also note that with any of those configurations, when I try to clone with a project name that actually doesn't exist, I get a 502 error. Does anyone already succeeded in doing this? What am I doing wrong? Thanks. UPDATE: nginx error log file said: 2012/04/05 17:34:50 [crit] 21335#0: *50 connect() to unix:/var/run/fcgiwrap.socket failed (13: Permission denied) while connecting to upstream, client: 192.168.12.201, server: myservername, request: "GET /git/oct_editor.git/info/refs HTTP/1.1", upstream: "fastcgi://unix:/var/run/fcgiwrap.socket:", host: "myservername" So I changed permissions for /var/run/fcgiwrap.socket, and now I have : > git clone http://myservername/git/projectname.git test/ Cloning into test... error: The requested URL returned error: 403 while accessing http://myservername/git/projectname.git/info/refs fatal: HTTP request failed Here is the error.log file I have now: 2012/04/05 17:36:52 [error] 21335#0: *78 FastCGI sent in stderr: "Cannot chdir to script directory (/usr/lib/git-core/git/projectname.git/info)" while reading response header from upstream, client: 192.168.12.201, server: myservername, request: "GET /git/projectname.git/info/refs HTTP/1.1", upstream: "fastcgi://unix:/var/run/fcgiwrap.socket:", host: "myservername" I keep on investigating.

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  • SQLAuthority News – TechEd India – April 12-14, 2010 Bangalore – An Unforgettable Experience – An Op

    - by pinaldave
    TechEd India was one of the largest Technology events in India led by Microsoft. This event was attended by more than 3,000 technology enthusiasts, making it one of the most well-organized events of the year. Though I attempted to attend almost all the technology events here, I have not seen any bigger or better event in Indian subcontinents other than this. There are 21 Technical Tracks at Tech·Ed India 2010 that span more than 745 learning opportunities. I was fortunate enough to be a part of this whole event as a speaker and a delegate, as well. TechEd India Speaker Badge and A Token of Lifetime Hotel Selection I presented three different sessions at TechEd India and was also a part of panel discussion. (The details of the sessions are given at the end of this blog post.) Due to extensive traveling, I stay away from my family occasionally. For this reason, I took my wife – Nupur and daughter Shaivi (8 months old) to the event along with me. We stayed at the same hotel where the event was organized so as to maximize my time bonding with my family and to have more time in networking with technology community, at the same time. The hotel Lalit Ashok is the largest and most luxurious venue one can find in Bangalore, located in the middle of the city. The cost of the hotel was a bit pricey, but looking at all the advantages, I had decided to ask for a booking there. Hotel Lalit Ashok Nupur Dave and Shaivi Dave Arrival Day – DAY 0 – April 11, 2010 I reached the event a day earlier, and that was one wise decision for I was able to relax a bit and go over my presentation for the next day’s course. I am a kind of person who likes to get everything ready ahead of time. I was also able to enjoy a pleasant evening with several Microsoft employees and my family friends. I even checked out the location where I would be doing presentations the next day. I was fortunate enough to meet Bijoy Singhal from Microsoft who helped me out with a few of the logistics issues that occured the day before. I was not aware of the fact that the very next day he was going to be “The Man” of the TechEd 2010 event. Vinod Kumar from Microsoft was really very kind as he talked to me regarding my subsequent session. He gave me some suggestions which were really helpful that I was able to incorporate them during my presentation. Finally, I was able to meet Abhishek Kant from Microsoft; his valuable suggestions and unlimited passion have inspired many people like me to work with the Community. Pradipta from Microsoft was also around, being extremely busy with logistics; however, in those busy times, he did find some good spare time to have a chat with me and the other Community leaders. I also met Harish Ranganathan and Sachin Rathi, both from Microsoft. It was so interesting to listen to both of them talking about SharePoint. I just have no words to express my overwhelmed spirit because of all these passionate young guys - Pradipta,Vinod, Bijoy, Harish, Sachin and Ahishek (of course!). Map of TechEd India 2010 Event Day 1 – April 12, 2010 From morning until night time, today was truly a very busy day for me. I had two presentations and one panel discussion for the day. Needless to say, I had a few meetings to attend as well. The day started with a keynote from S. Somaseger where he announced the launch of Visual Studio 2010. The keynote area was really eye-catching because of the very large, bigger-than- life uniform screen. This was truly one to show. The title music of the keynote was very interesting and it featured Bijoy Singhal as the model. It was interesting to talk to him afterwards, when we laughed at jokes together about his modeling assignment. TechEd India Keynote Opening Featuring Bijoy TechEd India 2010 Keynote – S. Somasegar Time: 11:15pm – 11:45pm Session 1: True Lies of SQL Server – SQL Myth Buster Following the excellent keynote, I had my very first session on the subject of SQL Server Myth Buster. At first, I was a bit nervous as right after the keynote, for this was my very first session and during my presentation I saw lots of Microsoft Product Team members. Well, it really went well and I had a really good discussion with attendees of the session. I felt that a well begin was half-done and my confidence was regained. Right after the session, I met a few of my Community friends and had meaningful discussions with them on many subjects. The abstract of the session is as follows: In this 30-minute demo session, I am going to briefly demonstrate few SQL Server Myths and their resolutions as I back them up with some demo. This demo presentation is a must-attend for all developers and administrators who would come to the event. This is going to be a very quick yet fun session. Pinal Presenting session at TechEd India 2010 Time: 1:00 PM – 2:00 PM Lunch with Somasegar After the session I went to see my daughter, and then I headed right away to the lunch with S. Somasegar – the keynote speaker and senior vice president of the Developer Division at Microsoft. I really thank to Abhishek who made it possible for us. Because of his efforts, all the MVPs had the opportunity to meet such a legendary person and had to talk with them on Microsoft Technology. Though Somasegar is currently holding such a high position in Microsoft, he is very polite and a real gentleman, and how I wish that everybody in industry is like him. Believe me, if you spread love and kindness, then that is what you will receive back. As soon as lunch time was over, I ran to the session hall as my second presentation was about to start. Time: 2:30pm – 3:30pm Session 2: Master Data Services in Microsoft SQL Server 2008 R2 Business Intelligence is a subject which was widely talked about at TechEd. Everybody was interested in this subject, and I did not excuse myself from this great concept as well. I consider myself fortunate as I was presenting on the subject of Master Data Services at TechEd. When I had initially learned this subject, I had a bit of confusion about the usage of this tool. Later on, I decided that I would tackle about how we all developers and DBAs are not able to understand something so simple such as this, and even worst, creating confusion about the technology. During system designing, it is very important to have a reference material or master lookup tables. Well, I talked about the same subject and presented the session keeping that as my center talk. The session went very well and I received lots of interesting questions. I got many compliments for talking about this subject on the real-life scenario. I really thank Rushabh Mehta (CEO, Solid Quality Mentors India) for his supportive suggestions that helped me prepare the slide deck, as well as the subject. Pinal Presenting session at TechEd India 2010 The abstract of the session is as follows: SQL Server Master Data Services will ship with SQL Server 2008 R2 and will improve Microsoft’s platform appeal. This session provides an in-depth demonstration of MDS features and highlights important usage scenarios. Master Data Services enables consistent decision-making process by allowing you to create, manage and propagate changes from a single master view of your business entities. Also, MDS – Master Data-hub which is a vital component, helps ensure the consistency of reporting across systems and deliver faster and more accurate results across the enterprise. We will talk about establishing the basis for a centralized approach to defining, deploying, and managing master data in the enterprise. Pinal Presenting session at TechEd India 2010 The day was still not over for me. I had ran into several friends but we were not able keep our enthusiasm under control about all the rumors saying that SQL Server 2008 R2 was about to be launched tomorrow in the keynote. I then ran to my third and final technical event for the day- a panel discussion with the top technologies of India. Time: 5:00pm – 6:00pm Panel Discussion: Harness the power of Web – SEO and Technical Blogging As I have delivered two technical sessions by this time, I was a bit tired but  not less enthusiastic when I had to talk about Blog and Technology. We discussed many different topics there. I told them that the most important aspect for any blog is its content. We discussed in depth the issues with plagiarism and how to avoid it. Another topic of discussion was how we technology bloggers can create awareness in the Community about what the right kind of blogging is and what morally and technically wrong acts are. A couple of questions were raised about what type of liberty a person can have in terms of writing blogs. Well, it was generically agreed that a blog is mainly a representation of our ideas and thoughts; it should not be governed by external entities. As long as one is writing what they really want to say, but not providing incorrect information or not practicing plagiarism, a blogger should be allowed to express himself. This panel discussion was supposed to be over in an hour, but the interest of the participants was remarkable and so it was extended for 30 minutes more. Finally, we decided to bring to a close the discussion and agreed that we will continue the topic next year. TechEd India Panel Discussion on Web, Technology and SEO Surprisingly, the day was just beginning after doing all of these. By this time, I have almost met all the MVP who arrived at the event, as well as many Microsoft employees. There were lots of Community folks present, too. I decided that I would go to meet several friends from the Community and continue to communicate with me on SQLAuthority.com. I also met Abhishek Baxi and had a good talk with him regarding Win Mobile and Twitter. He also took a very quick video of me wherein I spoke in my mother’s tongue, Gujarati. It was funny that I talked in Gujarati almost all the day, but when I was talking in the interview I could not find the right Gujarati words to speak. I think we all think in English when we think about Technology, so as to address universality. After meeting them, I headed towards the Speakers’ Dinner. Time: 8:00 PM – onwards Speakers Dinner The Speakers’ dinner was indeed a wonderful opportunity for all the speakers to get together and relax. We talked so many different things, from XBOX to Hindi Movies, and from SQL to Samosas. I just could not express how much fun I had. After a long evening, when I returned tmy room and met Shaivi, I just felt instantly relaxed. Kids are really gifts from God. Today was a really long but exciting day. So many things happened in just one day: Visual Studio Lanch, lunch with Somasegar, 2 technical sessions, 1 panel discussion, community leaders meeting, speakers dinner and, last but not leas,t playing with my child! A perfect day! Day 2 – April 13, 2010 Today started with a bang with the excellent keynote by Kamal Hathi who launched SQL Server 2008 R2 in India and demonstrated the power of PowerPivot to all of us. 101 Million Rows in Excel brought lots of applause from the audience. Kamal Hathi Presenting Keynote at TechEd India 2010 The day was a bit easier one for me. I had no sessions today and no events planned. I had a few meetings planned for the second day of the event. I sat in the speaker’s lounge for half a day and met many people there. I attended nearly 9 different meetings today. The subjects of the meetings were very different. Here is a list of the topics of the Community-related meetings: SQL PASS and its involvement in India and subcontinents How to start community blogging Forums and developing aptitude towards technology Ahmedabad/Gandhinagar User Groups and their developments SharePoint and SQL Business Meeting – a client meeting Business Meeting – a potential performance tuning project Business Meeting – Solid Quality Mentors (SolidQ) And family friends Pinal Dave at TechEd India The day passed by so quickly during this meeting. In the evening, I headed to Partners Expo with friends and checked out few of the booths. I really wanted to talk about some of the products, but due to the freebies there was so much crowd that I finally decided to just take the contact details of the partner. I will now start sending them with my queries and, hopefully, I will have my questions answered. Nupur and Shaivi had also one meeting to attend; it was with our family friend Vijay Raj. Vijay is also a person who loves Technology and loves it more than anybody. I see him growing and learning every day, but still remaining as a ‘human’. I believe that if someone acquires as much knowledge as him, that person will become either a computer or cyborg. Here, Vijay is still a kind gentleman and is able to stay as our close family friend. Shaivi was really happy to play with Uncle Vijay. Pinal Dave and Vijay Raj Renuka Prasad, a Microsoft MVP, impressed me with his passion and knowledge of SQL. Every time he gives me credit for his success, I believe that he is very humble. He has way more certifications than me and has worked many more years with SQL compared to me. He is an excellent photographer as well. Most of the photos in this blog post have been taken by him. I told him if ever he wants to do a part time job, he can do the photography very well. Pinal Dave and Renuka Prasad I also met L Srividya from Microsoft, whom I was looking forward to meet. She is a bundle of knowledge that everyone would surely learn a lot from her. I was able to get a few minutes from her and well, I felt confident. She enlightened me with SQL Server BI concepts, domain management and SQL Server security and few other interesting details. I also had a wonderful time talking about SharePoint with fellow Solid Quality Mentor Joy Rathnayake. He is very passionate about SharePoint but when you talk .NET and SQL with him, he is still overwhelmingly knowledgeable. In fact, while talking to him, I figured out that the recent training he delivered was on SQL Server 2008 R2. I told him a joke that it hurts my ego as he is more popular now in SQL training and consulting than me. I am sure all of you agree that working with good people is a gift from God. I am fortunate enough to work with the best of the best Industry experts. It was a great pleasure to hang out with my Community friends – Ahswin Kini, HimaBindu Vejella, Vasudev G, Suprotim Agrawal, Dhananjay, Vikram Pendse, Mahesh Dhola, Mahesh Mitkari,  Manu Zacharia, Shobhan, Hardik Shah, Ashish Mohta, Manan, Subodh Sohani and Sanjay Shetty (of course!) .  (Please let me know if I have met you at the event and forgot your name to list here). Time: 8:00 PM – onwards Community Leaders Dinner After lots of meetings, I headed towards the Community Leaders dinner meeting and met almost all the folks I met in morning. The discussion was almost the same but the real good thing was that we were enjoying it. The food was really good. Nupur was invited in the event, but Shaivi could not come. When Nupur tried to enter the event, she was stopped as Shaivi did not have the pass to enter the dinner. Nupur expressed that Shaivi is only 8 months old and does not eat outside food as well and could not stay by herself at this age, but the door keeper did not agree and asked that without the entry details Shaivi could not go in, but Nupur could. Nupur called me on phone and asked me to help her out. By the time, I was outside; the organizer of the event reached to the door and happily approved Shaivi to join the party. Once in the party, Shaivi had lots of fun meeting so many people. Shaivi Dave and Abhishek Kant Dean Guida (Infragistics President and CEO) and Pinal Dave (SQLAuthority.com) Day 3 – April 14, 2010 Though, it was last day, I was very much excited today as I was about to present my very favorite session. Query Optimization and Performance Tuning is my domain expertise and I make my leaving by consulting and training the same. Today’s session was on the same subject and as an additional twist, another subject about Spatial Database was presented. I was always intrigued with Spatial Database and I have enjoyed learning about it; however, I have never thought about Spatial Indexing before it was decided that I will do this session. I really thank Solid Quality Mentor Dr. Greg Low for his assistance in helping me prepare the slide deck and also review the content. Furthermore, today was really what I call my ‘learning day’ . So far I had not attended any session in TechEd and I felt a bit down for that. Everybody spends their valuable time & money to learn something new and exciting in TechEd and I had not attended a single session at the moment thinking that it was already last day of the event. I did have a plan for the day and I attended two technical sessions before my session of spatial database. I attended 2 sessions of Vinod Kumar. Vinod is a natural storyteller and there was no doubt that his sessions would be jam-packed. People attended his sessions simply because Vinod is syhe speaker. He did not have a single time disappointed audience; he is truly a good speaker. He knows his stuff very well. I personally do not think that in India he can be compared to anyone for SQL. Time: 12:30pm-1:30pm SQL Server Query Optimization, Execution and Debugging Query Performance I really had a fun time attending this session. Vinod made this session very interactive. The entire audience really got into the presentation and started participating in the event. Vinod was presenting a small problem with Query Tuning, which any developer would have encountered and solved with their help in such a fashion that a developer feels he or she have already resolved it. In one question, I was the only one who was ready to answer and Vinod told me in a light tone that I am now allowed to answer it! The audience really found it very amusing. There was a huge crowd around Vinod after the session. Vinod – A master storyteller! Time: 3:45pm-4:45pm Data Recovery / consistency with CheckDB This session was much heavier than the earlier one, and I must say this is my most favorite session I EVER attended in India. In this TechEd I have only attended two sessions, but in my career, I have attended numerous technical sessions not only in India, but all over the world. This session had taken my breath away. One by one, Vinod took the different databases, and started to corrupt them in different ways. Each database has some unique ways to get corrupted. Once that was done, Vinod started to show the DBCC CEHCKDB and demonstrated how it can solve your problem. He finally fixed all the databases with this single tool. I do have a good knowledge of this subject, but let me honestly admit that I have learned a lot from this session. I enjoyed and cheered during this session along with other attendees. I had total satisfaction that, just like everyone, I took advantage of the event and learned something. I am now TECHnically EDucated. Pinal Dave and Vinod Kumar After two very interactive and informative SQL Sessions from Vinod Kumar, the next turn me presenting on Spatial Database and Indexing. I got once again nervous but Vinod told me to stay natural and do my presentation. Well, once I got a huge stage with a total of four projectors and a large crowd, I felt better. Time: 5:00pm-6:00pm Session 3: Developing with SQL Server Spatial and Deep Dive into Spatial Indexing Pinal Presenting session at TechEd India 2010 Pinal Presenting session at TechEd India 2010 I kicked off this session with Michael J Swart‘s beautiful spatial image. This session was the last one for the day but, to my surprise, I had more than 200+ attendees. Slowly, the rain was starting outside and I was worried that the hall would not be full; despite this, there was not a single seat available in the first five minutes of the session. Thanks to all of you for attending my presentation. I had demonstrated the map of world (and India) and quickly explained what  Geographic and Geometry data types in Spatial Database are. This session had interesting story of Indexing and Comparison, as well as how different traditional indexes are from spatial indexing. Pinal Presenting session at TechEd India 2010 Due to the heavy rain during this event, the power went off for about 22 minutes (just an accident – nobodies fault). During these minutes, there were no audio, no video and no light. I continued to address the mass of 200+ people without any audio device and PowerPoint. I must thank the audience because not a single person left from the session. They all stayed in their place, some moved closure to listen to me properly. I noticed that the curiosity and eagerness to learn new things was at the peak even though it was the very last session of the TechEd. Everybody wanted get the maximum knowledge out of this whole event. I was touched by the support from audience. They listened and participated in my session even without any kinds of technology (no ppt, no mike, no AC, nothing). During these 22 minutes, I had completed my theory verbally. Pinal Presenting session at TechEd India 2010 After a while, we got the projector back online and we continued with some exciting demos. Many thanks to Microsoft people who worked energetically in background to get the backup power for project up. I had a very interesting demo wherein I overlaid Bangalore and Hyderabad on the India Map and find their aerial distance between them. After finding the aerial distance, we browsed online and found that SQL Server estimates the exact aerial distance between these two cities, as compared to the factual distance. There was a huge applause from the crowd on the subject that SQL Server takes into the count of the curvature of the earth and finds the precise distances based on details. During the process of finding the distance, I demonstrated a few examples of the indexes where I expressed how one can use those indexes to find these distances and how they can improve the performance of similar query. I also demonstrated few examples wherein we were able to see in which data type the Index is most useful. We finished the demos with a few more internal stuff. Pinal Presenting session at TechEd India 2010 Despite all issues, I was mostly satisfied with my presentation. I think it was the best session I have ever presented at any conference. There was no help from Technology for a while, but I still got lots of appreciation at the end. When we ended the session, the applause from the audience was so loud that for a moment, the rain was not audible. I was truly moved by the dedication of the Technology enthusiasts. Pinal Dave After Presenting session at TechEd India 2010 The abstract of the session is as follows: The Microsoft SQL Server 2008 delivers new spatial data types that enable you to consume, use, and extend location-based data through spatial-enabled applications. Attend this session to learn how to use spatial functionality in next version of SQL Server to build and optimize spatial queries. This session outlines the new geography data type to store geodetic spatial data and perform operations on it, use the new geometry data type to store planar spatial data and perform operations on it, take advantage of new spatial indexes for high performance queries, use the new spatial results tab to quickly and easily view spatial query results directly from within Management Studio, extend spatial data capabilities by building or integrating location-enabled applications through support for spatial standards and specifications and much more. Time: 8:00 PM – onwards Dinner by Sponsors After the lively session during the day, there was another dinner party courtesy of one of the sponsors of TechEd. All the MVPs and several Community leaders were present at the dinner. I would like to express my gratitude to Abhishek Kant for organizing this wonderful event for us. It was a blast and really relaxing in all angles. We all stayed there for a long time and talked about our sweet and unforgettable memories of the event. Pinal Dave and Bijoy Singhal It was really one wonderful event. After writing this much, I say that I have no words to express about how much I enjoyed TechEd. However, it is true that I shared with you only 1% of the total activities I have done at the event. There were so many people I have met, yet were not mentioned here although I wanted to write their names here, too . Anyway, I have learned so many things and up until now, I am not able to get over all the fun I had in this event. Pinal Dave at TechEd India 2010 The Next Days – April 15, 2010 – till today I am still not able to get my mind out of the whole experience I had at TechEd India 2010. It was like a whole Microsoft Family working together to celebrate a happy occasion. TechEd India – Truly An Unforgettable Experience! Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: About Me, MVP, Pinal Dave, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, SQLAuthority Author Visit, SQLAuthority News, SQLServer, T SQL, Technology Tagged: TechEd, TechEdIn

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  • Mapping UrlEncoded POST Values in ASP.NET Web API

    - by Rick Strahl
    If there's one thing that's a bit unexpected in ASP.NET Web API, it's the limited support for mapping url encoded POST data values to simple parameters of ApiController methods. When I first looked at this I thought I was doing something wrong, because it seems mighty odd that you can bind query string values to parameters by name, but can't bind POST values to parameters in the same way. To demonstrate here's a simple example. If you have a Web API method like this:[HttpGet] public HttpResponseMessage Authenticate(string username, string password) { …} and then hit with a URL like this: http://localhost:88/samples/authenticate?Username=ricks&Password=sekrit it works just fine. The query string values are mapped to the username and password parameters of our API method. But if you now change the method to work with [HttpPost] instead like this:[HttpPost] public HttpResponseMessage Authenticate(string username, string password) { …} and hit it with a POST HTTP Request like this: POST http://localhost:88/samples/authenticate HTTP/1.1 Host: localhost:88 Accept: text/html,application/xhtml+xml,application/xml;q=0.9,*/*;q=0.8 Content-type: application/x-www-form-urlencoded Content-Length: 30 Username=ricks&Password=sekrit you'll find that while the request works, it doesn't actually receive the two string parameters. The username and password parameters are null and so the method is definitely going to fail. When I mentioned this over Twitter a few days ago I got a lot of responses back of why I'd want to do this in the first place - after all HTML Form submissions are the domain of MVC and not WebAPI which is a valid point. However, the more common use case is using POST Variables with AJAX calls. The following is quite common for passing simple values:$.post(url,{ Username: "Rick", Password: "sekrit" },function(result) {…}); but alas that doesn't work. How ASP.NET Web API handles Content Bodies Web API supports parsing content data in a variety of ways, but it does not deal with multiple posted content values. In effect you can only post a single content value to a Web API Action method. That one parameter can be very complex and you can bind it in a variety of ways, but ultimately you're tied to a single POST content value in your parameter definition. While it's possible to support multiple parameters on a POST/PUT operation, only one parameter can be mapped to the actual content - the rest have to be mapped to route values or the query string. Web API treats the whole request body as one big chunk of data that is sent to a Media Type Formatter that's responsible for de-serializing the content into whatever value the method requires. The restriction comes from async nature of Web API where the request data is read only once inside of the formatter that retrieves and deserializes it. Because it's read once, checking for content (like individual POST variables) first is not possible. However, Web API does provide a couple of ways to access the form POST data: Model Binding - object property mapping to bind POST values FormDataCollection - collection of POST keys/values ModelBinding POST Values - Binding POST data to Object Properties The recommended way to handle POST values in Web API is to use Model Binding, which maps individual urlencoded POST values to properties of a model object provided as the parameter. Model binding requires a single object as input to be bound to the POST data, with each POST key that matches a property name (including nested properties like Address.Street) being mapped and updated including automatic type conversion of simple types. This is a very nice feature - and a familiar one from MVC - that makes it very easy to have model objects mapped directly from inbound data. The obvious drawback with Model Binding is that you need a model for it to work: You have to provide a strongly typed object that can receive the data and this object has to map the inbound data. To rewrite the example above to use ModelBinding I have to create a class maps the properties that I need as parameters:public class LoginData { public string Username { get; set; } public string Password { get; set; } } and then accept the data like this in the API method:[HttpPost] public HttpResponseMessage Authenticate(LoginData login) { string username = login.Username; string password = login.Password; … } This works fine mapping the POST values to the properties of the login object. As a side benefit of this method definition, the method now also allows posting of JSON or XML to the same endpoint. If I change my request to send JSON like this: POST http://localhost:88/samples/authenticate HTTP/1.1 Host: localhost:88 Accept: application/jsonContent-type: application/json Content-Length: 40 {"Username":"ricks","Password":"sekrit"} it works as well and transparently, courtesy of the nice Content Negotiation features of Web API. There's nothing wrong with using Model binding and in fact it's a common practice to use (view) model object for inputs coming back from the client and mapping them into these models. But it can be  kind of a hassle if you have AJAX applications with a ton of backend hits, especially if many methods are very atomic and focused and don't effectively require a model or view. Not always do you have to pass structured data, but sometimes there are just a couple of simple response values that need to be sent back. If all you need is to pass a couple operational parameters, creating a view model object just for parameter purposes seems like overkill. Maybe you can use the query string instead (if that makes sense), but if you can't then you can often end up with a plethora of 'message objects' that serve no further  purpose than to make Model Binding work. Note that you can accept multiple parameters with ModelBinding so the following would still work:[HttpPost] public HttpResponseMessage Authenticate(LoginData login, string loginDomain) but only the object will be bound to POST data. As long as loginDomain comes from the querystring or route data this will work. Collecting POST values with FormDataCollection Another more dynamic approach to handle POST values is to collect POST data into a FormDataCollection. FormDataCollection is a very basic key/value collection (like FormCollection in MVC and Request.Form in ASP.NET in general) and then read the values out individually by querying each. [HttpPost] public HttpResponseMessage Authenticate(FormDataCollection form) { var username = form.Get("Username"); var password = form.Get("Password"); …} The downside to this approach is that it's not strongly typed, you have to handle type conversions on non-string parameters, and it gets a bit more complicated to test such as setup as you have to seed a FormDataCollection with data. On the other hand it's flexible and easy to use and especially with string parameters is easy to deal with. It's also dynamic, so if the client sends you a variety of combinations of values on which you make operating decisions, this is much easier to work with than a strongly typed object that would have to account for all possible values up front. The downside is that the code looks old school and isn't as self-documenting as a parameter list or object parameter would be. Nevertheless it's totally functionality and a viable choice for collecting POST values. What about [FromBody]? Web API also has a [FromBody] attribute that can be assigned to parameters. If you have multiple parameters on a Web API method signature you can use [FromBody] to specify which one will be parsed from the POST content. Unfortunately it's not terribly useful as it only returns content in raw format and requires a totally non-standard format ("=content") to specify your content. For more info in how FromBody works and several related issues to how POST data is mapped, you can check out Mike Stalls post: How WebAPI does Parameter Binding Not really sure where the Web API team thought [FromBody] would really be a good fit other than a down and dirty way to send a full string buffer. Extending Web API to make multiple POST Vars work? Don't think so Clearly there's no native support for multiple POST variables being mapped to parameters, which is a bit of a bummer. I know in my own work on one project my customer actually found this to be a real sticking point in their AJAX backend work, and we ended up not using Web API and using MVC JSON features instead. That's kind of sad because Web API is supposed to be the proper solution for AJAX backends. With all of ASP.NET Web API's extensibility you'd think there would be some way to build this functionality on our own, but after spending a bit of time digging and asking some of the experts from the team and Web API community I didn't hear anything that even suggests that this is possible. From what I could find I'd say it's not possible primarily because Web API's Routing engine does not account for the POST variable mapping. This means [HttpPost] methods with url encoded POST buffers are not mapped to the parameters of the endpoint, and so the routes would never even trigger a request that could be intercepted. Once the routing doesn't work there's not much that can be done. If somebody has an idea how this could be accomplished I would love to hear about it. Do we really need multi-value POST mapping? I think that that POST value mapping is a feature that one would expect of any API tool to have. If you look at common APIs out there like Flicker and Google Maps etc. they all work with POST data. POST data is very prominent much more so than JSON inputs and so supporting as many options that enable would seem to be crucial. All that aside, Web API does provide very nice features with Model Binding that allows you to capture many POST variables easily enough, and logistically this will let you build whatever you need with POST data of all shapes as long as you map objects. But having to have an object for every operation that receives a data input is going to take its toll in heavy AJAX applications, with a lot of types created that do nothing more than act as parameter containers. I also think that POST variable mapping is an expected behavior and Web APIs non-support will likely result in many, many questions like this one: How do I bind a simple POST value in ASP.NET WebAPI RC? with no clear answer to this question. I hope for V.next of WebAPI Microsoft will consider this a feature that's worth adding. Related Articles Passing multiple POST parameters to Web API Controller Methods Mike Stall's post: How Web API does Parameter Binding Where does ASP.NET Web API Fit?© Rick Strahl, West Wind Technologies, 2005-2012Posted in Web Api   Tweet !function(d,s,id){var js,fjs=d.getElementsByTagName(s)[0];if(!d.getElementById(id)){js=d.createElement(s);js.id=id;js.src="//platform.twitter.com/widgets.js";fjs.parentNode.insertBefore(js,fjs);}}(document,"script","twitter-wjs"); (function() { var po = document.createElement('script'); po.type = 'text/javascript'; po.async = true; po.src = 'https://apis.google.com/js/plusone.js'; var s = document.getElementsByTagName('script')[0]; s.parentNode.insertBefore(po, s); })();

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  • Complete Guide to Symbolic Links (symlinks) on Windows or Linux

    - by Matthew Guay
    Want to easily access folders and files from different folders without maintaining duplicate copies?  Here’s how you can use Symbolic Links to link anything in Windows 7, Vista, XP, and Ubuntu. So What Are Symbolic Links Anyway? Symbolic links, otherwise known as symlinks, are basically advanced shortcuts. You can create symbolic links to individual files or folders, and then these will appear like they are stored in the folder with the symbolic link even though the symbolic link only points to their real location. There are two types of symbolic links: hard and soft. Soft symbolic links work essentially the same as a standard shortcut.  When you open a soft link, you will be redirected to the folder where the files are stored.  However, a hard link makes it appear as though the file or folder actually exists at the location of the symbolic link, and your applications won’t know any different. Thus, hard links are of the most interest in this article. Why should I use Symbolic Links? There are many things we use symbolic links for, so here’s some of the top uses we can think of: Sync any folder with Dropbox – say, sync your Pidgin Profile Across Computers Move the settings folder for any program from its original location Store your Music/Pictures/Videos on a second hard drive, but make them show up in your standard Music/Pictures/Videos folders so they’ll be detected my your media programs (Windows 7 Libraries can also be good for this) Keep important files accessible from multiple locations And more! If you want to move files to a different drive or folder and then symbolically link them, follow these steps: Close any programs that may be accessing that file or folder Move the file or folder to the new desired location Follow the correct instructions below for your operating system to create the symbolic link. Caution: Make sure to never create a symbolic link inside of a symbolic link. For instance, don’t create a symbolic link to a file that’s contained in a symbolic linked folder. This can create a loop, which can cause millions of problems you don’t want to deal with. Seriously. Create Symlinks in Any Edition of Windows in Explorer Creating symlinks is usually difficult, but thanks to the free Link Shell Extension, you can create symbolic links in all modern version of Windows pain-free.  You need to download both Visual Studio 2005 redistributable, which contains the necessary prerequisites, and Link Shell Extension itself (links below).  Download the correct version (32 bit or 64 bit) for your computer. Run and install the Visual Studio 2005 Redistributable installer first. Then install the Link Shell Extension on your computer. Your taskbar will temporally disappear during the install, but will quickly come back. Now you’re ready to start creating symbolic links.  Browse to the folder or file you want to create a symbolic link from.  Right-click the folder or file and select Pick Link Source. To create your symlink, right-click in the folder you wish to save the symbolic link, select “Drop as…”, and then choose the type of link you want.  You can choose from several different options here; we chose the Hardlink Clone.  This will create a hard link to the file or folder we selected.  The Symbolic link option creates a soft link, while the smart copy will fully copy a folder containing symbolic links without breaking them.  These options can be useful as well.   Here’s our hard-linked folder on our desktop.  Notice that the folder looks like its contents are stored in Desktop\Downloads, when they are actually stored in C:\Users\Matthew\Desktop\Downloads.  Also, when links are created with the Link Shell Extension, they have a red arrow on them so you can still differentiate them. And, this works the same way in XP as well. Symlinks via Command Prompt Or, for geeks who prefer working via command line, here’s how you can create symlinks in Command Prompt in Windows 7/Vista and XP. In Windows 7/Vista In Windows Vista and 7, we’ll use the mklink command to create symbolic links.  To use it, we have to open an administrator Command Prompt.  Enter “command” in your start menu search, right-click on Command Prompt, and select “Run as administrator”. To create a symbolic link, we need to enter the following in command prompt: mklink /prefix link_path file/folder_path First, choose the correct prefix.  Mklink can create several types of links, including the following: /D – creates a soft symbolic link, which is similar to a standard folder or file shortcut in Windows.  This is the default option, and mklink will use it if you do not enter a prefix. /H – creates a hard link to a file /J – creates a hard link to a directory or folder So, once you’ve chosen the correct prefix, you need to enter the path you want for the symbolic link, and the path to the original file or folder.  For example, if I wanted a folder in my Dropbox folder to appear like it was also stored in my desktop, I would enter the following: mklink /J C:\Users\Matthew\Desktop\Dropbox C:\Users\Matthew\Documents\Dropbox Note that the first path was to the symbolic folder I wanted to create, while the second path was to the real folder. Here, in this command prompt screenshot, you can see that I created a symbolic link of my Music folder to my desktop.   And here’s how it looks in Explorer.  Note that all of my music is “really” stored in C:\Users\Matthew\Music, but here it looks like it is stored in C:\Users\Matthew\Desktop\Music. If your path has any spaces in it, you need to place quotes around it.  Note also that the link can have a different name than the file it links to.  For example, here I’m going to create a symbolic link to a document on my desktop: mklink /H “C:\Users\Matthew\Desktop\ebook.pdf”  “C:\Users\Matthew\Downloads\Before You Call Tech Support.pdf” Don’t forget the syntax: mklink /prefix link_path Target_file/folder_path In Windows XP Windows XP doesn’t include built-in command prompt support for symbolic links, but we can use the free Junction tool instead.  Download Junction (link below), and unzip the folder.  Now open Command Prompt (click Start, select All Programs, then Accessories, and select Command Prompt), and enter cd followed by the path of the folder where you saved Junction. Junction only creates hard symbolic links, since you can use shortcuts for soft ones.  To create a hard symlink, we need to enter the following in command prompt: junction –s link_path file/folder_path As with mklink in Windows 7 or Vista, if your file/folder path has spaces in it make sure to put quotes around your paths.  Also, as usual, your symlink can have a different name that the file/folder it points to. Here, we’re going to create a symbolic link to our My Music folder on the desktop.  We entered: junction -s “C:\Documents and Settings\Administrator\Desktop\Music” “C:\Documents and Settings\Administrator\My Documents\My Music” And here’s the contents of our symlink.  Note that the path looks like these files are stored in a Music folder directly on the Desktop, when they are actually stored in My Documents\My Music.  Once again, this works with both folders and individual files. Please Note: Junction would work the same in Windows 7 or Vista, but since they include a built-in symbolic link tool we found it better to use it on those versions of Windows. Symlinks in Ubuntu Unix-based operating systems have supported symbolic links since their inception, so it is straightforward to create symbolic links in Linux distros such as Ubuntu.  There’s no graphical way to create them like the Link Shell Extension for Windows, so we’ll just do it in Terminal. Open terminal (open the Applications menu, select Accessories, and then click Terminal), and enter the following: ln –s file/folder_path link_path Note that this is opposite of the Windows commands; you put the source for the link first, and then the path second. For example, let’s create a symbolic link of our Pictures folder in our Desktop.  To do this, we entered: ln -s /home/maguay/Pictures /home/maguay/Desktop   Once again, here is the contents of our symlink folder.  The pictures look as if they’re stored directly in a Pictures folder on the Desktop, but they are actually stored in maguay\Pictures. Delete Symlinks Removing symbolic links is very simple – just delete the link!  Most of the command line utilities offer a way to delete a symbolic link via command prompt, but you don’t need to go to the trouble.   Conclusion Symbolic links can be very handy, and we use them constantly to help us stay organized and keep our hard drives from overflowing.  Let us know how you use symbolic links on your computers! 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