Search Results

Search found 14310 results on 573 pages for 'mysql sock'.

Page 241/573 | < Previous Page | 237 238 239 240 241 242 243 244 245 246 247 248  | Next Page >

  • Can someone recommend a good tutorial on MySQL indexes, specifically when used in an order by clause

    - by Philip Brocoum
    I could try to post and explain the exact query I'm trying to run, but I'm going by the old adage of, "give a man a fish and he'll eat for a day, teach a man to fish and he'll eat for the rest of his life." SQL optimization seems to be very query-specific, and even if you could solve this one particular query for me, I'm going to have to write many more queries in the future, and I'd like to be educated on how indexes work in general. Still, here's a quick description of my current problem. I have a query that joins three tables and runs in 0.2 seconds flat. Awesome. I add an "order by" clause and it runs in 4 minutes and 30 seconds. Sucky. I denormalize one table so there is one fewer join, add indexes everywhere, and now the query runs in... 20 minutes. What the hell? Finally, I don't use a join at all, but rather a subquery with "where id in (...) order by" and now it runs in 1.5 seconds. Pretty decent. What in God's name is going on? I feel like if I actually understood what indexes were doing I could write some really good SQL. Anybody know some good tutorials? Thanks!

    Read the article

  • MySQL - What is wrong with this query or my database? Terrible performance.

    - by Moss
    SELECT * from `employees` a LEFT JOIN (SELECT phone1 p1, count(*) c, FROM `employees` GROUP BY phone1) b ON a.phone1 = b.p1; I'm not sure if it is this query in particular that has the problem. I have been getting terrible performance in general with this database. The table in question has 120,000 rows. I have tried this particular query remotely and locally with the MyISAM and InnoDB engines, with different types of joins, and with and without an index on phone1. I can get this to complete in about 4 minutes on a 10,000 row table successfully but performance drops exponentially with larger tables. Remotely it will lose connection to the server and locally it brings my system to its knees and seems to go on forever. This query is only a smaller step I was trying to do when a larger query couldn't complete. Maybe I should explain the whole scenario. I have one big flat ugly table that lists a bunch of people and their contact info and the info of the companies they work for. I'm trying to normalize the database and intelligently determine which phone numbers apply to individual people and which apply to an office location. My reasoning is that if a phone number occurs multiple times and the number of occurrence equals the number of times that the street address it is attached to occurs then it must be an office number. So the first step is to count each phone number grouping by phone number. Normally if you just use COUNT()...GROUP BY it will only list the first record it finds in that group so I figured I have to join the full table to the count table where the phone number matches. This does work but as I said I can't successfully complete it on any table much larger than 10,000 rows. This seems pathetic and this doesn't seem like a crazy query to do. Is there a better way to achieve what I want or do I have to break my large table into 12 pieces or is there something wrong with the table or db?

    Read the article

  • Can I use a MySQL PREPARE statement in a function to create a query with a variable table name

    - by aHunter
    I want to create a function that has a select query inside that can be used against multiple database tables but I can not use a variable as the table name. Can I get around this using a PREPARE statement in the function? An Example: FUNCTION `TESTFUNC`(dbTable VARCHAR(25)) RETURNS bigint(20) BEGIN DECLARE datereg DATETIME; DECLARE stmt VARCHAR(255); SET stmt := concat( 'SELECT dateT FROM', dbTable, 'ORDER BY dateT DESC LIMIT 1'); PREPARE stmt FROM @stmt; EXECUTE stmt; RETURN dateT; END $$ Thanks in advance for any input.

    Read the article

  • How to create conditions in mysql (use of 'if')?

    - by Audel
    This code works fine to find an available room within certain date, but it does not work to show a room that has been booked and canceled The "hotel" has 4 rooms and 1 of them has been booked an canceled So even if I make a cancelation, the select method keeps giving me 3 results. Maybe because the second AND is still running. So basically what I need is check if the room is booked in the selected dates if it has been booked, check if its canceled if it has been canceled, or not booked display it. Otherwise not   SELECT RoomNo, NightCost FROM room, room_types, booking WHERE typeid = fk1_typeid and double_bed=1 and single_bed=0 AND canceled = '1' in (SELECT canceled from booking, room_booking where bookingid = fk2_bookingid) AND RoomNo not in (SELECT fk1_RoomNo FROM room_booking WHERE '2010-04-02' between Check_in and Check_Out or '2010-04-03' between Check_in and Check_Out) ; I tried to be as clear as possible, i will be around to give more details if needed

    Read the article

  • Moving from MySQL to MySQLi? I have the code here but I don't get it

    - by MuqMan
    I have posted the code there, please help me out as I am a newbie, I don't know much in terms of deprecation and stuff. <?php session_start(); include('settings.php'); $issub = $_POST['issub']; if($issub == "yes") { require('settings.php'); $dbcon = mysql_connect($dbhost, $dbuser, $dbpword); if(!dbcon) { die('Could not connect'.mysql_error()); } $selectdb = mysql_select_db($db, $dbcon); $formset = 'yes'; $val = 0; $user = trim($_POST['username'], ' '); $luser = mysql_real_escape_string($user); $password = $_POST['password']; $lpassword = mysql_real_escape_string($password); $selectdb; $userq = mysql_query("SELECT user FROM users WHERE user='".$luser."'"); $userresult = @mysql_result($userq, 0); //echo $userresult; if($userresult == $user) { $val = $val + 1; $usercorrect = 'yes'; } else { $usercorrect = 'no'; } $dbselect; $passwordq = mysql_query("SELECT password FROM users where user='".$luser."'"); $passresult = @mysql_result($passwordq, 0); if($passresult == sha1($password)) { $val = $val + 1; $passcorrect = 'yes'; } else { $passcorrect = 'no'; } if ($val == 2) { $_SESSION['loggedin'] = 'yes'; $_SESSION['uloggedin'] = $user; header('location: logged.php'); } }?> <?php ini_set('display_errors', 1); require('testinclude.php'); ?> <body> <div id="loginform"> <form action="/login.php" method="post" > <input type="hidden" name="issub" value="yes" /> <?php if($usercorrect == 'no') { echo '<span class="required"><i><small>The email address or password you entered is incorrect, please try again.</a></small></i></span>'; } ?> <br /> email: <?php if ($issub == 'yes') { if($user == null){ echo '<br /><span class="required"><i><small>Please enter your email address</a></small></i></span>'; } } ?> <br /><input type="text" name="username" id="usename" /> <br /> password: <br /><input type="password" name="password" id="password" /> <br /> <input type="submit" value="login" /> </form> <div> </body>

    Read the article

  • How to store MySQL query results in another Table?

    - by Taz
    How to store results from following query into another table. Considering there is an appropriate table already created. SELECT labels.label,shortabstracts.ShortAbstract,images.LinkToImage,types.Type FROM ner.images,ner.labels,ner.shortabstracts,ner.types WHERE labels.Resource=images.Resource AND labels.Resource=shortabstracts.Resource AND labels.Resource=types.Resource;

    Read the article

  • Searching a keyword in a long string in mysql?

    - by user187580
    Hello keyword = house SELECT * FROM products WHERE description LIKE '%house%' This query also returns records having keyword, for example, courthouse, but I want to look for house only. How do I search anywhere in the description for "house" only? Thanks. UPDATE just for more clarification .. actually house, can be at - the start of the description .. "House for sale..", - can be quoted -- "house", 'house' - can have exclamation .. house!!!, house! - others - house? etc .. this is why I used %house%

    Read the article

  • Multiple Scripts With the Same MySQL Query Running At Once => Will There Be Interference?

    - by walden
    I want to have multiple scripts running from cron at the same time. They will all update, say, 500 rows with a unique status ID for that particular script to use. If each script grabs the same type of rows to update, and the scripts run at once, will there be interference between the queries run at the same time? For example, using this query: UPDATE table SET status = <unique script ID> WHERE status = 0 LIMIT 500 Will I get the same rows updating more than once? I'm trying to get each script to get unique rows. I was thinking of using sleep() to make the queries run at different times, but I'm not sure if that's necessary. Thanks.

    Read the article

  • How do you encode an apostrophe so that it's searchable in mysql?

    - by Yegor
    I don't think that was the most clear question, but an example should make it a little clearer. I have a table filled with movie names, some of which contain apostrophes. I have a search box which is used to find movies. If I perform searches via mov_title = '$search_keywords' it all works, but this method will not yield any results for partial searches, so I have to use this mov_title LIKE '%$search_keywords%' This method works fine for titles that are A-Za-z0-9, but if a title has an apostrophe, it's not able to find the movie, even if I do an exact match. Before the titles are stored in the DB, I put them through this: $search_keywords = htmlspecialchars(mysql_escape_string($_GET["search_keywords"])); So in the DB, there is a forward slash before every single apostrophe. The only way to match a movie title with an apostrophe is to physically put a forward slash in front of the apostrophe, in the search box. This seems so trivial, and I'm sure the solution is painfully obvious, but I'm just not seeing it.

    Read the article

  • How do I write this SQL statement to get the ad and posting? (PHP/MySQL)

    - by ggfan
    I am a little confused on the logic of how to write this SQL statement. When a user clicks on a tag, say HTML, it would display all the posts with HTML as its tag. (a post can have multiple tags) I have three tables: Posting--posting_id, title, detail, etc tags--tagID, tagname postingtag--posting_id, tagID I want to display all the title of the post and the date added. global $dbc; $tagID=$_GET['tagID']; //the GET is set by URL //part I need help with. I need another WHERE statment to get to the posting table $query = "SELECT p.title,p.date_added, t.tagname FROM posting as p, postingtag as pt, tags as t WHERE t.tagID=$tagID"; $data = mysqli_query($dbc, $query); echo '<table>'; echo '<tr><td><b>Title</b></td><td><b>Date Posted</b></td></tr>'; while ($row = mysqli_fetch_array($data)) { echo '<tr><td>'.$row['title'].'</td>'; echo '<td>'.$row['date_added'].'</td></tr>'; } echo '</table>'; }

    Read the article

  • Faster way to know the tolal number of rows in Mysql Database?

    - by Starx
    If I need to know the total number of rows in a table of database I do something like $query = "SELECT * FROM tablename WHERE link='1';"; $result = mysql_query($query); $rows = mysql_fetch_array($result); $count = count($rows); So you see the total number of data is recovered scanning through entire database Is there a better way

    Read the article

  • How can you access two identically-named columns in a MySQL LEFT JOIN query?

    - by George Edison
    I have two tables. table_x: id INT(11) tag INT(11) table_tags: id INT(11) name VARCHAR(255) Then I use PHP to perform the following query: SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id The only problem is: how do I access table_x.id and table_tags.id in the results? Here is the PHP code: $query = "SELECT * FROM table_x LEFT JOIN table_tags ON table_x.tag = table_tags.id"; $results = mysql_query($query); while($row = mysql_fetch_array($results)) { // how do I now access table_x.id and table_tags.id ??? }

    Read the article

  • MySQL: selecting totals as three fields from same table as one query?

    - by coderama
    I have a table with various orders in it: ID | Date | etc... 1 | 2013-01-01 | etc 2 | 2013-02-01 | etc 3 | 2013-03-01 | etc 4 | 2013-04-01 | etc 5 | 2013-05-01 | etc 6 | 2013-06-01 | etc 7 | 2013-06-01 | etc 8 | 2013-03-01 | etc 9 | 2013-04-01 | etc 10 | 2013-05-01 | etc I want a query that ends wit the result: overallTotal | totalThisMonth | totalLastMonth 10 | 2 | 1 But I want to do this in one query! I am trying to find a way to use subqueries to do this. SO far I have: SELECT * from ( SELECT count(*) as overallTotal from ORDERS ) How can I combine this with other subqueries so I can get the totals in one query?

    Read the article

  • Implementing Tagging System with PHP and mySQL. Caching help!!!

    - by Hamid Sarfraz
    With reference to this post: http://stackoverflow.com/questions/2122546/how-to-implement-tag-counting I have implemented the suggested 3 table tagging system completely. To count the number of Articles per tag, i am using another column named tagArticleCount in the tag definition table. (other columns are tagId, tagText, tagUrl, tagArticleCount). If i implement realtime editing of this table, so that whenever user adds another tag to article or deletes an existing tag, the tag_definition_table is updated to update the counter of the added/removed tag. This will cost an extra query each time any modification is made. (at the same time, related link entry for tag and article is deleted from tagLinkTable). An alternative to this is not allowing any real time editing to the counter, instead use CRONs to update counter of each tag after a specified time period. Here comes the problem that i want to discuss. This can be seen as caching the article count in database. Can you please help me find a way to present the articles in a list when a tag is explored and when the article counter for that tag is not up to date. For example: 1. Counter shows 50 articles, but there are infact 55 entries in the tag link table (that links tags and articles). 2. Counter shows 50 articles, but there are infact 45 extries in the tag link table. How to handle these 2 scenerios given in example. I am going to use APC to keep cache of these counters. Consider it too in your solution. Also discuss performance in the realtime / CRONNED counter updates.

    Read the article

  • MySQL not using index on DATE when used with '<' or '>' operators?

    - by Haroldo
    I'm using explain to test these queries. The col type is DATE this uses index: explain SELECT events.* FROM events WHERE events.date = '2010-06-11' this doesnt explain SELECT events.* FROM events WHERE events.date >= '2010-06-11' index as follows (phpmyadmin) Action Keyname Type Unique Packed Field Cardinality Collation Null Comment Edit Drop PRIMARY BTREE Yes No event_id 18 A Edit Drop date BTREE No No date 0 A i notice cardinality is 0, though there are some rows with the same date..

    Read the article

  • MySQL : select/join on strings as fieldnames - is this possible?

    - by Dylan
    I can retrieve all column names from table 'categories' with : SELECT col.column_name FROM information_schema.columns AS col WHERE col.table_schema= database() and col.table_name = "categories" This produces a resultset like this : column_name ----------------- categoryID name description I can retrieve all values for a specific category with : SELECT * FROM categories AS c WHERE c.categoryID=12345 this results in a resultset like this: categoryID | name | description ------------------------------------------------ 12345 | test | this is a test Now I would like to get some kind of join of above selects to get a resultset that looks something like this : fieldname | value ---------------------------------------- categoryID | 12345 name | test description | this is a test Does anyone know if this is possible ? Can you do a join on strings that come from another select ?? The reason for this is that I'm writing a universal stored procedure that outputs all fields + their values from a table, without knowing what fields there are in the table. (The tablename is given in a parameter)

    Read the article

  • Having trouble comparing a range of dates entered in a form with records in a mySQL database

    - by Andrew Fox
    I have a table called schedule and a column called Date where the column type is date. In that column I have a range of dates, which is currently from 2012-11-01 to 2012-11-30. I have a small form where the user can enter a range of dates (input names from and to) and I want to be able to compare the range of dates with the dates currently in the database. This is what I have: //////////////////////////////////////////////////////// //////First set the date range that we want to use////// //////////////////////////////////////////////////////// if(isset($_POST['from']) && ($_POST['from'] != NULL)) { $startDate = $_POST['from']; } else { //Default date is Today $startDate = date("Y-m-d"); } if(isset($_POST['to']) && ($_POST['to'] != NULL)) { $endDate = $_POST['to']; } else { //Default day is one month from today $endDate = date("Y-m-d", strtotime("+1 month")); } ////////////////////////////////////////////////////////////////////////////////////// //////Next calculate the total amount of days selected above to use as a limiter////// ////////////////////////////////////////////////////////////////////////////////////// $dayStart = strtotime($startDate); $dayEnd = strtotime($endDate); $total_days = abs($dayEnd - $dayStart) / 86400 +1; echo "Start Date: " . $startDate . "<br>End Date: " . $endDate . "<br>"; echo "Day Start: " . $dayStart . "<br>Day End: " . $dayEnd . "<br>"; echo "Total Days: " . $total_days . "<br>"; //////////////////////////////////////////////////////////////////////////////////// //////Then we're going to see if the dates selected are in the schedule table////// //////////////////////////////////////////////////////////////////////////////////// //Select all of the dates currently in the schedule table between the range selected. $sql = ("SELECT Date FROM schedule WHERE Date BETWEEN '$startDate' AND '$endDate' LIMIT $total_days"); //Run a check on the query to make sure it worked. If it failed then print the error. if(!$result_date_query = $mysqli->query($sql)) { die('There was an error getting the dates from the schedule table [' . $mysqli->error . ']'); } //Set the dates to an array for future use. // $current_dates = $result_date_query->fetch_assoc(); //Loop through the results while a result is being returned. while($row = $result_date_query->fetch_assoc()) { echo "Row: " . $row['Date'] . "<br>"; echo "Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Set this loop to add 1 day to the Start Date until it reaches the End Date for($i = $dayStart; $i <= $dayEnd; $i = strtotime('+1 day', $i)) { $date = date('Y-m-d',$i); echo "Loop Start day: " . date('Y-m-d', $dayStart) . "<br>"; //Run a check to see if any of the dates selected are in the schedule table. if($row['Date'] != $date) { echo "Current Date: " . $row['Date'] . "<br>"; echo "Date: " . $date . "<br>"; echo "It appears as though you've selected some dates that are not in the schedule database.<br>Please correct the issue and try again."; return; } } } //Free the result so something else can use it. $result_date_query->free(); As you can see I've added in some echo statements so I can see what is being produced. From what I can see it looks like my $row['Date'] is not incrementing and staying at the same date. I originally had it set to a variable (currently commented out) but I thought that could be causing problems. I have created the table with dates ranging from 2012-11-01 to 2012-11-15 for testing and entered all of this php code onto phpfiddle.org but I can't get the username provided to connect. Here is the link: PHP Fiddle I'll be reading through the documentation to try and figure out the user connection problem in the meantime, I would really appreciate any direction or advice you can give me.

    Read the article

  • There has to be an easier way.. pulling data from mysql

    - by Daniel Hunter
    I need to pull 3 values from a table and assign each one to a variable each value is based on to columns, a type and an id $ht_live_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='L'"); $ht_live_result = mysql_fetch_array($ht_live_query); $htCODE_Live = $ht_live_result['htcode']; You can see that I am assigning the desired value to the variable $htL $ht_General_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='G'"); $ht_General_result = mysql_fetch_array($ht_General_query); $htCODE_General = $ht_General_result['htcode']; $ht_Reward_query = mysql_query("SELECT htcode FROM coupon WHERE pid='$pid' AND type='R'"); $ht_Reward_result = mysql_fetch_array($ht_Reward_query); $htCODE_Reward = $ht_Reward_result ['htcode']; I know I am doing this the hard way but can not figure out how to do the foreach or while loop to attain the desired results.

    Read the article

< Previous Page | 237 238 239 240 241 242 243 244 245 246 247 248  | Next Page >