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  • Django | passing form values

    - by MMRUser
    I want to create a user sign up process that requires two different forms with the same data one (1st form) is for filling out the data and other one (2nd form) is for displaying the filled data as a summery (before actually saving the data) so then user can view what he/she has filled up... my problem is that how do I pass 1st form's data in to the 2nd one .. I have used the basic Django form manipulation mechanism and passed the form field values to the next form using Django template tags.. if request.method == 'POST': form = Users(request.POST) if form.is_valid(): cd = form.cleaned_data try: name = cd['fullName'] email = cd['emailAdd'] password1 = cd['password'] password2 = cd['password2'] phoneNumber = cd['phoneNumber'] return render_to_response('signup2.html', {'name': name, 'email': email, 'password1': password1, 'password2': password2, 'phone': phone, 'pt': phoneType}) except Exception, ex: return HttpResponse("Error %s" % str(ex)) and from the second from I just displayed those field values using tags and also used hidden fields in order to submit the form with values, like this: <label for="">Email:</label> {{ email }} <input type="hidden" id="" name="email" class="width250" value="{{ email }}" readonly /> It works nicely from the out look, but the real problem is that if someone view the source of the html he can simply get the password even hackers can get through this easily. So how do I avoid this issue.. and I don't want to use Django session since this is just a simple sign up process and no other interactions involved. Thanks.

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  • When is it safe to use a broken hash function?

    - by The Rook
    It is trivial to use a secure hash function like SHA256 and continuing to use md5 is reckless behavior. However, there are some complexities to hash function vulnerabilities that I would like to better understand. Collisions have been generated for md4 and md5. According to NIST md5() is not a secure hash function. It only takes 2^39th operations to generate a collision and should never be used for passwords. However SHA1 is vulnerable to a similar collision attack in which a collision can be found in 2^69 operations, where as brute force is 2^80th. No one has generated a sha1 collision and NIST still lists sha1 as a secure message digest function. So when is it safe to use a broken hash function? Even though a function is broken it can still be "big enough". According to Schneier a hash function vulnerable to a collsion attack can still be used as an HMAC. I believe this is because the security of an HMAC is Dependant on its secret key and a collision cannot be found until this key is obtained. Once you have the key used in a HMAC its already broken, so its a moot point. What hash function vulnerabilities would undermine the security of an HMAC? Lets take this property a bit further. Does it then become safe to use a very weak message digest like md4 for passwords if a salt is perpended to the password? Keep in mind the md4 and md5 attacks are prefixing attacks, and if a salt is perpended then an attacker cannot control the prefix of the message. If the salt is truly a secret, and isn't known to the attacker, then does it matter if its a appended to the end of the password? Is it safe to assume that an attacker cannot generate a collision until the entire message has been obtained? Do you know of other cases where a broken hash function can be used in a security context without introducing a vulnerability? (Please post supporting evidence because it is awesome!)

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  • how run Access 2007 module in Vb6?

    - by Mahmoud
    I have created a module in access 2007 that will update linked tables, but I wanted to run this module from vb6. I have tried this code from Microsoft, but it didnt work. Sub AccessTest1() Dim A As Object Set A = CreateObject("Access.Application") A.Visible = False A.OpenCurrentDatabase (App.Path & "/DataBase/acc.accdb") A.DoCmd.RunMacro "RefreshLinks" End Sub What I am aiming to do, is to allow my program to update all linked tables to new links, in case the program has been used on other computer In case you want to take a look at the module program, here it is: Sub CreateLinkedJetTable() Dim cat As ADOX.Catalog Dim tbl As ADOX.Table Set cat = New ADOX.Catalog ' Open the catalog. cat.ActiveConnection = CurrentProject.Connection Set tbl = New ADOX.Table ' Create the new table. tbl.Name = "Companies" Set tbl.ParentCatalog = cat ' Set the properties to create the link. tbl.Properties("Jet OLEDB:Link Datasource") = CurrentProject.Path & "/db3.mdb" tbl.Properties("Jet OLEDB:Remote Table Name") = "Companies" tbl.Properties("Jet OLEDB:Create Link") = True ' To link a table with a database password set the Link Provider String ' tbl.Properties("Jet OLEDB:Link Provider String") = "MS Access;PWD=Admin;" ' Append the table to the tables collection. cat.Tables.Append tbl Set cat = Nothing End Sub Sub RefreshLinks() Dim cat As ADOX.Catalog Dim tbl As ADOX.Table Set cat = New ADOX.Catalog ' Open the catalog. cat.ActiveConnection = CurrentProject.Connection Set tbl = New ADOX.Table For Each tbl In cat.Tables ' Verify that the table is a linked table. If tbl.Type = "LINK" Then tbl.Properties("Jet OLEDB:Link Datasource") = CurrentProject.Path & "/db3.mdb" ' To refresh a linked table with a database password set the Link Provider String 'tbl.Properties("Jet OLEDB:Link Provider String") = "MS Access;PWD=Admin;" End If Next End Sub

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  • Usage Rails 3.0 beta 3 without ActiveRecoord ORM

    - by Anton
    Hi everybody! Just installed Rails 3.0 beta 3 in Windows 7. And started playing with some easy examples class SignupController < ApplicationController def index @user = User.new(params[:user]) if method.post? and @user.save redirect_to :root end end end class User def initialize(params = {}) @email = params[:email] @passw = params[:passw] end def save end end <div align="center"> <% form_for :user do |form| %> <%= form.label :email %> <%= form.text_field :email %><br /> <%= form.label :password %> <%= form.text_field :password %><br /> <%= form.submit :Register! %> <% end %> </div> When I go to /signup I'm getting this error NoMethodError in SignupController#index You have a nil object when you didn't expect it! You might have expected an instance of Array. The error occurred while evaluating nil.[] Is there a problem with constructor or what's wrong?Please, need your help!

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  • Shell script for generating HTML out put

    - by user1638016
    The following script is generating the desired out put but not redirecting the result to /home/myuser/slavedelay.html #!/bin/bash host=<ip> echo $host user=usr1 password=mypass threshold=300 statusok=OK statuscritical=CRITICAL for i in ert7 ert9 do echo "<html>" > /home/myuser/slavedelay.html if [ "$i" == "ert7" ]; then slvdelay=`mysql -u$user -p$password -h<ip> -S /backup/mysql/mysql.sock -e 'show slave status\G' | grep Seconds_Behind_Master | sed -e 's/ *Seconds_Behind_Master: //'` if [ $slvdelay -ge $threshold ]; then echo "<tr><td>$i</td><td>CRITICAL</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>CRITICAL</td>" else echo "<tr><td>$i</td><td>OK</td>" >> /home/myuser/slavedelay.html echo "<tr><td>$i</td><td>OK</td>" fi fi done echo "</html>" >> /home/myuser/slavedelay.html If I cat the output file /home/myuser/slavedelay.html it gives. <html> </html> Execution result : sh slave_delay.sh <tr><td>sdb7</td><td>OK</td>

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  • Deal with update location for click-once.

    - by Assimilater
    I'm not sure how many people here are experts with visual studios, but I'd imagine a handful (not to raise expectations but to appeal to your egos :P). I'm working primarily in visual basic for now (though I hope to switch to c# in the near future and maybe a java or web app). Basically I'm trying to create an update feature that will work similarly to how common programs such as firefox or itunes update automatically. There is supposed to be provided functionality for this in what is called click once. I carry out the following procedures and get the following errors when trying to change the update url of my program to a password-protected ftp location. Go to project properties Go to publish click updates click browse click FTP Site Under Server put: web###.opentransfer.com Under Port: 21 Under Directory put: CMSOFT Passive mode is selected (which is what filezilla tells me the server is accessed with) Anonymous User is unselected and a username and password are typed in Push Ok Under Update location it shows: ftp://web###.opentransfer.com/CMSOFT I push Ok I see a message box titled Microsoft Visual Basic 2010 Express with an x icon Publish.UpdateUrl: The string must be a fully qualified URL or UNC path, for example "http://www.microsoft.com/myapplication" or "\server\myapplication". I've tried changing the directory to "CMSOFT/PQCM.exe" and the results are the same...hope this was descriptive enough.

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  • Replacing mysql user authentication with openid

    - by David
    So, I'm working with a really old system which uses a person's mysql database credentials to authenticate to a web site (the database was originally only accessed from the command line, but is now accessed from a php frontend). Because of some internal reasons (and to preserve the user's history), I have to leave the old authentication intact. I've been charged with adding openid authentication to this system. Somehow I need to be able to retrieve a users mysql username and password upon logging into the site through openid (using the Zend framework, by the way). I've thought of simply requiring registration at the first login, where the user must provide their mysql credentials, but I'd rather not store the password plain text. I've also considered blanking everyone's mysql passwords, and just setting the user's mysql username manually (rather than having the user provide this, since they could provide any username). This is turning into a security nightmare. Does anyone have any suggestions for alternatives? This is running on a Linux server, by the way. Also, I can't use mysql pluggable authentication because the mysql version is 5.0 (pluggable authentication requires mysql 5.5), and no, I can't update it.

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  • New user register, script auto create problems!

    - by SKY
    Hi, im currently trying to create a php script that when a new user register, a script (eg:wordpress,blog etc..) will install for them. I'm currently got the code below for just single setup, but how can i setup a form for multi user? which only allowing them to input the username (subdomain) and password. <?php class scriptname_Config { public static $title = 'new_script_title'; // Domain name and path where new script will installed in public static $domain = 'username.domain.com'; public static $absolutePath = '/new_register_username/'; // Settings for general mysql database public static $db = array( 'host' => 'localhost', 'database' => 'scriptname', 'user' => 'root', 'password' => '', 'prefix' => 'scriptname_' ); } define( 'scriptname_BASE_URL', 'http://'.scriptname_Config::$domain.scriptname_Config::$absolutePath ); ?> Or any tutorial that will help is appreciate! Thanks!

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  • Windows "forms" authentication - <deny users="?"> redirecting to foreign page!

    - by Erik5388
    Like the title states - I have a web.config file that looks like, <?xml version="1.0" encoding="UTF-8"?> <configuration> <system.web> <compilation debug="true" targetFramework="4.0" /> <authentication mode="Forms"> <forms name="login" protection="All" timeout="30" loginUrl="login" defaultUrl="~/"> <credentials passwordFormat="Clear"> <user name="admin" password="password" /> </credentials> </forms> </authentication> <authorization> <deny users="?" /> </authorization> </system.web> </configuration> I want to do exactly what it says it should do... I want to deny all users who try to enter the site. It works however, it redirects to a "Account/Login?ReturnUrl=%2flogin" url I have never heard of... Is there a place I can change this?

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  • Windows Service Start-Up Error 1069

    - by Gavin
    Hello, I am installing a new windows service coded in C# on a server. I installed the service fine on the server, but once i manually start up the service on a server, with the same login credentials that our other services use, i get the fatal error message notification: "Could not start the %service name% on Local Computer. Error 1069: The Service did not start due to a logon failure." I looked in the event log and i got a 7038 and 7000 event id error in that order. 7038 event id message: "The %service name% service was unable to log on as %login% with the currently configured password due to the following error: Logon failure: unknown user name or bad password. To ensure that the service is configured properly, use the Services snap-in in Microsoft Management Console (MMC)." 7000 event id message: "The %service name% service failed to start due to the following error: The service did not start due to a logon failure. " I have other services that are using the same exact login account and they work fine. Is there something simple I could be missing? Thanks

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  • Error after redirection using CakePHP

    - by Praveen kalal
    I have created some code called LoginController. Whenever Admin gets successfully logged in I redirect the page to index. However, I got an error like "problem on loading page". This is my code: <?php class LoginController extends AdminAppController { var $name = 'Login'; var $uses = array('Admin.Login'); var $sessionkey= ''; /*function beforeFilter() { if($this->Session->read('user')=='Admin' || $this->params['action']=='login') { echo "in"; exit; } else { echo "else"; exit; $this->Session->setFlash('Login first','flash_failure'); $this->redirect(array('action'=>'login')); } }*/ function index() { } function login() { //pr($this->data); exit; if(!empty($this->data)) { $results = $this->Login->findByEmail($this->data['Login']['email']); if(!empty($results) && $results['Login']['password']== md5($this->data['Login']['password'])) { $this->Session->write('user', 'Admin'); $results['Login']['last_login']=date("Y-m-d H:i:s"); $this->Login->save($results); $this->Session->setFlash('Login successfully.', 'flash_success'); $this->redirect(array('controller'=>'login','action' => 'index')); } } } } ?> Can anyone help me? Thanks.

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  • Invoking a SOAP ( Web Services ) from ORACLE DB

    - by Mousarules
    Dears, Kindly note that I’m trying to invoke a SOAP (web services) from ORACLE DB using pl\sql , after I have done some investigations it says that I have to use the UTL_HTTP package but It didn't work with me !!! Kindly to advice me , where should I exactly place the following SOAP in pl\SQL to be invoked .... is it posible ? SOAP 1.1 The following is a sample SOAP 1.1 request and response. The placeholders shown need to be replaced with actual values. POST /gmgwebservice/service.asmx HTTP/1.1 Host: bulk.umniah.com Content-Type: text/xml; charset=utf-8 Content-Length: length SOAPAction: "http://tempuri.org/SendSMS" <SendSMS xmlns="http://tempuri.org/"> <UserName>string</UserName> <Password>string</Password> <MessageBody>string</MessageBody> <Sender>string</Sender> <Destination>string</Destination> </SendSMS> HTTP/1.1 200 OK Content-Type: text/xml; charset=utf-8 Content-Length: length <SendSMSResponse xmlns="http://tempuri.org/"> <SendSMSResult>string</SendSMSResult> </SendSMSResponse> --This web services refers to a web site called Bulk Messaging ; the web site sends SMS to a specific mobile number by filling in some text boxes , I need it to be done from ORACLE forms when a specific action occurs ( JOB ) but I don’t know how to use it inside my pl\sql code . Hope that it’s clear ,is there something else I have to mention ?

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  • using IntentExatras with Alarm Manager

    - by Ashwin
    I want to know if this code will work(I cannot try it out right now. Moreover, I have a few doubts that have to be cleared). Intent intent = new Intent(context, AlarmReceiver.class); intent.putExtra("user",global.getUsername()); intent.puExtra("password",global.getPassword); PendingIntent sender = PendingIntent.getBroadcast(context, 192837, intent, PendingIntent.FLAG_UPDATE_CURRENT); // Get the AlarmManager service Log.v("inside log_run", "new service started"); AlarmManager am = (AlarmManager) getSystemService(ALARM_SERVICE); am.setRepeating(AlarmManager.RTC_WAKEUP, IMMEDIATELY,60000,sender); finish(); As you can see, this code starts an AlarmManager with setRepeating(). If you see the intent(actually the pending intent) passed on to the BroadcastReceiver, there are two extras that are passed on. These are global variables that live as long as the Application is running. But this AlarmManager is meant to be run in the background (that is application will be alive only for the first few calls of the o fthe alrmamanager to the broadcast recevier) My Question Will AlarmManager make a copy of the global variables(the username and password) and maintain this copy to be passed along with the intent? Because, these values will be used in the broadcast receiver.

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  • deployd authentification using jquery ajax

    - by user2507987
    I have installed deployd in my debian 7.0.0 64 bit, I have also succesfully installed mongodb in it, I have create some collection and user collection in deployd dashboard, then using user guide how to connect and query the table in deployd, I choose jquery ajax to log in to deployd from my localhost site and after login success I try to get/post some data, but somehow deployd return access denied. I have create collection name it people, and then at the GET, POST, PUT Event I have write this code : cancelUnless(me, "You are not logged in", 401); then using this ajax code, I try to login and POST new people data: $(document).ready(function(){ /* Create query for username and password for login */ var request = new Object; request.username = 'myusername'; request.password = 'mypassword'; submitaddress = "http://myipaddress:myport/users/login"; $.ajax({ type: "POST", url: submitaddress, data: request, cache: false, success: function(data){ var returndata = eval(data); /* After Login success try to post people data */ if (returndata){ var request2 = new Object; request2.name = 'People Name'; submitaddress2 = "http://myipaddress:myport/people"; $.ajax({ type: "POST", url: submitaddress2, data: request2, cache: false, success: function(){ } }) } } } }); }) The login process success, it's return session id and my user id, but after login success and I try to POST people data it's return "You are not logged in", can anyone help me, what is the correct way to login to deployd using jquery from other website(cross domain)?

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  • JDBC with JSP fails to insert

    - by StrykeR
    I am having some issues right now with JDBC in JSP. I am trying to insert username/pass ext into my MySQL DB. I am not getting any error or exception, however nothing is being inserted into my DB either. Below is my code, any help would be greatly appreciated. <% String uname=request.getParameter("userName"); String pword=request.getParameter("passWord"); String fname=request.getParameter("firstName"); String lname=request.getParameter("lastName"); String email=request.getParameter("emailAddress"); %> <% try{ String dbURL = "jdbc:mysql:localhost:3306/assi1"; String user = "root"; String pwd = "password"; String driver = "com.mysql.jdbc.Driver"; String query = "USE Users"+"INSERT INTO User (UserName, UserPass, FirstName, LastName, EmailAddress) " + "VALUES ('"+uname+"','"+pword+"','"+fname+"','"+lname+"','"+email+"')"; Class.forName(driver); Connection conn = DriverManager.getConnection(dbURL, user, pwd); Statement statement = conn.createStatement(); statement.executeUpdate(query); out.println("Data is successfully inserted!"); } catch(SQLException e){ for (Throwable t : e) t.printStackTrace(); } %> DB script here: CREATE DATABASE Users; use Users; CREATE TABLE User ( UserID INT NOT NULL AUTO_INCREMENT, UserName VARCHAR(20), UserPass VARCHAR(20), FirstName VARCHAR(30), LastName VARCHAR(35), EmailAddress VARCHAR(50), PRIMARY KEY (UserID) );

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  • Create 2nd tables and add data

    - by Tyler Matema
    I have this task from school, and I am confuse and lost on how I got to do this. So basically I have to create 2 tables to the database but I have to created from php. I have created the first table, but not the second one for some reason. And then, I have to populate first and second tables with 10 and 20 sample records respectively, populate, does it mean like adding more fake users? if so is it like the code shown below? *I got error on the populating second part as well Thank you so much for the help. <?php $host = "host"; $user = "me"; $pswd = "password"; $dbnm = "db"; $conn = @mysqli_connect($host, $user, $pswd, $dbnm); if (!$conn) die ("<p>Couldn't connect to the server!<p>"); $selectData = @mysqli_select_db ($conn, $dbnm); if(!$selectData) { die ("<p>Database Not Selected</p>"); } //1st table $sql = "CREATE TABLE IF NOT EXISTS `friends` ( `friend_id` INT NOT NULL auto_increment, `friend_email` VARCHAR(20) NOT NULL, `password` VARCHAR(20) NOT NULL, `profile_name` VARCHAR(30) NOT NULL, `date_started` DATE NOT NULL, `num_of_friends` INT unsigned, PRIMARY KEY (`friend_id`) )"; //2nd table $sqlMyfriends = "CREATE TABLE `myfriends` ( `friend_id1` INT NOT NULL, `friend_id2` INT NOT NULL, )"; $query_result1 = @mysqli_query($conn, $sql); $query_result2 = @mysqli_query($conn, $sqlMyfriends); //populating 1st table $sqlSt3="INSERT INTO friends (friend_id, friend_email, password, profile_name, date_started, num_of_friends) VALUES('NULL','[email protected]','123','abc','2012-10-25', 5)"; $queryResult3 = @mysqli_query($dbConnect,$sqlSt3) //populating 2nd table $sqlSt13="INSERT INTO myfriends VALUES(1,2)"; $queryResult13=@mysqli_query($dbConnect,$sqlSt13); mysqli_close($conn); ?>

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  • java.lang.ClassNotFoundException: com.mysql.jdbc.Driver When run jar file

    - by user1024858
    Hi all, Connection conn = null; String url = "jdbc:mysql://localhost:3306/"; String dbName = "test"; String driver = "com.mysql.jdbc.Driver"; String userName = "root"; String password = "admin"; try { Class.forName(driver).newInstance(); conn = DriverManager.getConnection(url+dbName,userName,password); System.out.println("Connected to the database"); conn.close(); System.out.println("Disconnected from database"); } catch (Exception e) { e.printStackTrace();} I run in eclipse it's ok, but i built to jar file and run on command line java -jar Test.jar i get this error: java.lang.ClassNotFoundException: com.mysql.jdbc.Driver at java.net.URLClassLoader$1.run(Unknown Source) at java.net.URLClassLoader$1.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at sun.misc.Launcher$AppClassLoader.loadClass(Unknown Source) at java.lang.ClassLoader.loadClass(Unknown Source) at java.lang.Class.forName0(Native Method) at java.lang.Class.forName(Unknown Source) Please help me how to fix it. Thanks!!!

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  • Properly handling NSURLConnection errors

    - by Cal S
    Hi, I have a simple form interface set up that send username and password information to a server: (working) NSString *postData = [NSString stringWithFormat:@"user=%@&pass=%@",[self urlEncodeValue:sysUsername],[self urlEncodeValue:password]]; NSLog(@"Post data -> %@", postData); /// NSData* postVariables = [postData dataUsingEncoding:NSASCIIStringEncoding allowLossyConversion:YES]; NSMutableURLRequest* request = [[[NSMutableURLRequest alloc] init] autorelease]; NSString* postLength = [NSString stringWithFormat:@"%d", [postVariables length]]; NSURL* postUrl = [NSURL URLWithString:@"http://localhost/~csmith/cocoa/test.php"]; [request setURL:postUrl]; [request setHTTPMethod:@"POST"]; [request setValue:postLength forHTTPHeaderField:@"Content-Length"]; [request setValue:@"application/x-www-form-urlencoded" forHTTPHeaderField:@"Content-Type"]; [request setHTTPBody: postVariables]; NSData *returnData = [NSURLConnection sendSynchronousRequest:request returningResponse:NULL error:NULL]; NSLog(@"Post data SENT & returned -> %@", returnData); How do I handle connection errors such as no internet connection, firewall, etc. Also, does this method use the system-wide proxy settings? Many of my users are behind a proxy. Thanks a lot!

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  • How does an ASP.NET programmer go from working on/developing existing sites, to creating one from sc

    - by SLC
    I've been an ASP.NET developer for some time, always working on existing ASP.NET pages, modifying functionality, adding features, tweaking things etc. but have never built a site up from scratch. I've read books on ASP.NET, and they generally talk you through the various features of ASP.NET with a mock up site, but it's always very basic and they jump straight in. The time has come however, to write a site from scratch for a client. I've never done this before. There are design considerations, but like a lot of ASP.NET sites, the basic idea is, you have a site, where users can log in, and save some information like their name and password and address. The site has some functionality, but that's the basic design of a majority of (business-related) asp.net websites I would wager. I know how to program in ASP.NET already on an existing site, but I don't know how to design my own properly that meets the criteria above. I guess the main worry is security. I don't know the best way to handle a simple log-in system that stores user information like their name and password. I understand there are a few approaches to this, but the catch with this project is that it has to be absolutely bulletproof. Maximum security. All those good practices for security, it needs to have them all. I'm not asking what they are, but I am asking where to begin. What should be the first steps after I do File New Project ? Where can I look for information about setting up a secure ASP.NET website? I'll figure out the content and page layout later, it's the framework that is the big thing. Any and all advice would be welcome. I really want to get my first from-scratch project right from the beginning. Just to confuse things, it's possible I will be using MVC, I am not sure if this has any impact.

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  • zend_db and join

    - by premtemp
    Hello, I am trying to understand how to use Zend_DB in my program but I have some problem. The class below (DatabaseService) work when I pass it a simple query. However, if I pass it it query with a join clause my page just hangs and not error is return. I cut and paste the qry in a query browesr and it is valid Any help would be great $SQL = "select name from mytable" $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // works ----------------------------------------------------------- $SQL = "select count(*) as cnt from EndPoints join CallID on EndPoints.`CallID` = CallID.CallID where EndPoints.LastRegister >= '2010-04-21 00:00:01' and EndPoints.LastRegister <= '2010-04-21 23:59:59' " $db = new DatabaseService($dbinfo) $db ->fetchall($SQL ) // DOES NO WORK class DatabaseService { function DatabaseService($dbinfo,$dbname="") { try { $dbConfig = array( 'host' => $this->host, 'username' => $this->username, 'password' => $password, 'dbname' => $this->dbname ); $this->db = Zend_Db::factory($this->adapter, $dbConfig); Zend_Db_Table::setDefaultAdapter($this->db); } catch(Zend_Exception $e) { $this->error = $e->getMessage(); Helper::log($this->error); return false; } } public function connnect() { if($this->db !=null) { try { $this->db->getConnection(); return true; } catch (Zend_Exception $e) { $err = "FAILED ::".$e->getMessage()." <br />"; } } return false; } public function fetchall($sql) { $res= $this->db->fetchAll($sql); return $res; } }

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  • Paypal Sandbox 2014 Non US test account Sign Up proper link

    - by Flood Gravemind
    Ok I had a Paypal Sandbox account a year ago. I am developing a new site for a client and when I try to Login it won't recognize my email address. I tried forgot my password forgot password still nothing. So I guessed that maybe due to inactivity for such a long time they may have deleted my account. So then I try to Sign Up for a new one. I entered my details 3 times now and spent 6 hours trying to figure out what is the proper link to do this. Then I went to another Sandbox link which required me to entered a US Zip code and its a dead end. I am not even sure which Paypal account I signed up for those three times. No email nothing at all. I am a Non US developer and the FAQ link for Non US developers just points to their REST API. Can someone please guide me to the proper Paypal Sandbox Setup for Non US developers including the proper sign up links please. And I know Stackoverflow does not like rants but from my experience dealing with Paypal, GTA 6 should make a satirical Paypal company in their next Game with Paypal Developer Rampage mode for the main protagonist who also happens to be a Developer. EDIT: REST API does not include UK :(

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  • Discussion - Allowing / blocking user access to pages / Client Side Validation (Client Side Only!) -

    - by Ozaki
    TLDR Using plain HTML / Javascript (Client Side) I want to prevent viewing of certain pages. The user will have to type a username and password and depending on that they get access to different pages. Answers can NOT include server side whatsoever It does not matter if they can break it easily. There is no sensitive information etc. Also the target audience will not have access to internet OR probably know what a cookie is... At some point the user will have to type username / password.(I can define the cookie here) Currently I thought of using cookies to set a cookie for each page to say "true" / "false" but that would get messy with so many cookies. Or setting an array within a cookie for each page? I have div field "#Content" which as it looks encompasses all of my content on the page so blocking out content will be as simple as replacing it with ("sorry you don't have access") etc. For Example: $.cookie("Access","page1, page2, page3"{ expires: 1 }); I am looking for anyway to do this does not have to be with cookies. Would be nice to get a discussion of different ways this can be done. So the question is: What do YOU think would be a good way to go about doing this with client side validation? Also on another note discussion on how to make client side more secure or ways to do so are acceptable.

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  • Selenium problem locating by DOM

    - by bartonlee
    Hi, I'm trying to use the DOM to locate a form element in Selenium but I can't get it to work. Even if I use the example in the Selenium documentation it still fails, for example with this html... <html> <body> <form id="loginForm"> <input name="username" type="text" /> <input name="password" type="password" /> <input name="continue" type="submit" value="Login" /> <input name="continue" type="button" value="Clear" /> </form> </body> <html> and this command in the Selenium IDE... verifyElementPresent with target... dom=document.forms['loginForm'] I get [error] false in the log. The 'getElementById' example in the documentation does work, but none of the others. Can someone explain what I'm doing wrong here? Thanks.

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  • make java plugin use the browser certificates

    - by Shalom938
    We have a java applet that communicates with a spring application running on tomcat and using spring's http invoker. We want to secure the applet using ssl with client authentication, we have a jsp page for login, after successful login the applet loads. The jsp page is secured with ssl, when the applet loads the http invoker inside the applet is doing a second handshake apparently not related to the browser handshake, OK, I don't mind that, but I want the java plugin to use browser certificates and client certificates but its not, I have to load the client certificate to the java plugin also using the java ControlPanel, and if my server's certificate is self signed then I have to load the server certificate also to the java ControlPanel and to the nrowser. Another thing is when the applet starts loading the java plugin pops a dialog asking for the client keystore password, I would like to avoid that. So to conclude: I would like the java plugin to use the browser's trusted certificates and client certificates, and to avoid the keystore password dialog that pops up. I have googled for it for two days and can't find any clue of how to accomplish that. I will appreciate any help. I'm using jdk 1.6.0 u23 and firefox 3.6.13.

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  • Windows Phone 7.1.1 Ping

    - by Matt
    I am writing an app to connect to a third party application using REST web services. I have a configuration page that asks for an IP, Port, User Name & Password, currently it just blindly assumes you enter the correct details and attempts a connection. I want to create a test routine that goes through and checks off the following steps when setting up the config information Is the IP/Hostname correct (using ping or something) Is the Port correct Is the Username & Password correct then displays the results on screen as it's going so that if it can't connect to the service it's easier to identify where the issue is. To achieve step 1 I would like to use Ping or some equivalent that does not rely on a particular port being open. So I can eliminate dodgy DNS or a typo in the IP/Hostname. I understand from previous questions asked that ping wasn't possible in 7.0 but with Mango the sockets classes have been added in, is it possible now, if so how? If it still isn't possible is there a different way I can achieve step 1?

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