Search Results

Search found 37666 results on 1507 pages for 'matthew page'.

Page 243/1507 | < Previous Page | 239 240 241 242 243 244 245 246 247 248 249 250  | Next Page >

  • Which of these methods provides for the fastest page loading?

    - by chromedude
    I am building a database in MySQL that will be accessed by PHP scripts. I have a table that is the activity stream. This includes everything that goes on on the website (following of many different things, liking, upvoting etc.). From this activity stream I am going to run an algorithm for each user depending on their activity and display relevant activity. Should I create another table that stores the activity for each user once the algorithm has been run on the activity or should I run the algorithm on the activity table every time the user accesses the site? UPDATE:(this is what is above except rephrased hopefully in an easier to understand way) I have a database table called activity. This table creates a new row every time an action is performed by a user on the website. Every time a user logs in I am going to run an algorithm on the new rows (since the users last login) in the table (activity) that apply to them. For example if the user is following a user who upvoted a post in the activity stream that post will be displayed when the user logs in. I want the ability for the user to be able to access previous content applying to them. Would it be easiest to create another table that saved the rows that have already been run over with the algorithm except attached to individual users names? (a row can apply to multiple different users)

    Read the article

  • How do you display a PHPmyadmin table onto a web browser/web page?

    - by user1390754
    Just a simple question, i've been searching around and for some reason i cannot find an answer to this. after creating a database/table in Phpmyadmin using xampp, what command do i need to put into my webpage (PHP) to show the table I made? I know the first step involves connecting to the database and i think i've done that properly. This is the code i found from somewhere about connecting (w3 tutorials I believe) $con = mysql_connect("localhost","xxxxxx,""); if (!$con) { die('Could not connect: ' . mysql_error()); }

    Read the article

  • How do I get developers to look at our bug tracking page regularly?

    - by abeger
    We've recently started using Trac and are still trying to figure out the best way to use it in our environment. It's great, but it will only be effective if developers look at it once in a while and I'm trying to figure out how to instill that habit in them. I've contemplated several solutions, such as: forcing them to use Trac as their homepage (too draconian) handing out bookmarks to the RSS feeds (same problem--no one will look at them) automatic email notifications (won't drive them to the site and might just annoy them more than anything else) What are some other solutions? What have you tried that worked?

    Read the article

  • If-statement: how to pull 2nd GET variable

    - by arsoneffect
    How do I get this to pull my 2nd variable? (I already have a switch setup) <body id="<?php if (! isset($_GET['page'])) { echo "home"; } else { $_GET['page']; echo $page; } ?>"> I have a switch statement that pulls the pages from index.php?page=##### and I have just added this part to my switch: index.php?page=####&section=##### Right now, if I am on page=photos, my code ends up being: <body id="photos"> I need to make it so that if any link has the "sections" variable on it like this page=photos&section=cars it uses the same ID: <body id="photos">

    Read the article

  • @Intertceptors does not work for web bean for JSF page.

    - by Drevlyanin
    @Named @ConversationScoped @Interceptors(MyInterceptor.class) public class BeanWeb implements Serializable { public String methodThrowException throws Exception() { throws new Exception(); } } public class MyInterceptor { @AroundInvoke public Object intercept(InvocationContext ic) throws Exception { try { return ic.proceed(); } catch (Exception e) { return null; } } } For @Stateless beans interceptor works, but for the BeanWeb interceptor does not work. And we have never entered into "intercept" method. Why is this happening? How could intercept method calls in BeanWeb? P.S.: All this spin under Glassfish 3.x.

    Read the article

  • Mechanize form submit not going to the correct response page, no errors as to why. Something I'm doing?

    - by Zack Shapiro
    I threw this all in one controller for testing purposes. My code fills out the form correctly for adding a new address to your Amazon account. There are two buttons that submit this form, one takes you to add a new address which is what I don't want, and the other is just a Save & Continue input/image. When I submit the form via that button, as I do below, the form is still on the page, filled out as I have with my code. Inspecting the page titles, they're the same. There are no discernible errors that Mechanize or Amazon spit back. Any ideas? class AmazonCrawler def initialize @agent = Mechanize.new do |agent| agent.user_agent_alias = 'Mac Safari' agent.follow_meta_refresh = true agent.redirect_ok = true end end def login # login_url = "https://www.amazon.com/ap/signin?_encoding=UTF8&openid.assoc_handle=usflex&openid.claimed_id=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.identity=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0%2Fidentifier_select&openid.mode=checkid_setup&openid.ns=http%3A%2F%2Fspecs.openid.net%2Fauth%2F2.0&openid.ns.pape=http%3A%2F%2Fspecs.openid.net%2Fextensions%2Fpape%2F1.0&openid.pape.max_auth_age=0&openid.return_to=https%3A%2F%2Fwww.amazon.com%2Fgp%2Fcss%2Fhomepage.html%3Fie%3DUTF8%26ref_%3Dgno_yam_ya" login_url = "https://www.amazon.com/gp/css/account/address/view.html?ie=UTF8&ref_=ya_add_address&viewID=newAddress" @agent.get(login_url) form = @agent.page.forms.first form.email = "[email protected]" form.radiobuttons.first.value = "0" form.radiobuttons.last.check form.password = "my_password" dashboard = @agent.submit(form) end end class UsersController < ApplicationController def index response = AmazonCrawler.new.login form = response.forms[1] # fill out form form.enterAddressFullName == "Your Name" form.enterAddressAddressLine1 = "123 Main Street" form.enterAddressAddressLine2 = "Apartment 34" form.enterAddressCity = "San Francisco" form.enterAddressStateOrRegion = "CA" form.enterAddressPostalCode = "94101" form.enterAddressPhoneNumber = "415-555-1212" form.AddressType = "RES" new_response = form.submit( form.button_with(value: /Save.*Continue/) ) end end

    Read the article

  • How to load the whole content of a page into another window?

    - by Cristian Castiblanco
    I'm building a Dashboard and for some stupid reasons my boss wants to load it in a frame on the homepage (yes a frame, he still lives in the 1990s). Anyway, sometimes the dashboard needs some room so that it can show all charts correctly, so I want to add a feature to load the content of the dashboard into a new window. The problem is that, if the user has had some interaction with the dashboard, it will contain modal dialogs, new images, etc... so I want to load all the dashboard content into a new window without reloading its content. Of course, the user should be able to continue browsing the dashboard without problems. How can I do that? I'm using jQuery as my JavaScript framework.

    Read the article

  • Online webcam chat on web page. Free server and easy-to-implement client?

    - by Oskar Kjellin
    I have a client requesting that his users can use their webcams to talk to each other on his web site. From what I've understood the main thing to use for this is Flash. However as I have not written flash I would like to have something really easy to implement. Of course preferrably free (or trial). The idea of this is that everything but the chat alone is in .net. So the users will not use flash until they are actaully going to talk to each other. So there is no use for rooms here. I've been looking into silverlight some as well. But it seems like silverlight does not offer streaming between users..? I know this question has been asked many times here. But I could not find a suitable answer which is why I post a new question.

    Read the article

  • problem in jquery with showing pop message on submit form

    - by user1400
    hi guys in my application on php i use of 'jQuery Notify Bar' plugin for display messages, i'd like to show message when my form submit(in edit page) ,the other page(index page) is opened and notify bar be open until the other page(index page) is completely load and even some second more but the problem is that notify bar show for short Moment and when the index page begin to load , notify bar is closed, and the delay property is not effect to that $('#myForm').submit(function(){ $.notifyBar({ html: "Thank you, your settings were updated!", **delay: 20000,** animationSpeed: "normal" }); how to show notify bar in the other page too? thanks

    Read the article

  • How do you automatically refresh part of a page automatically using AJAX?

    - by Ryan
    $messages = $db->query("SELECT * FROM chatmessages ORDER BY datetime DESC, displayorderid DESC LIMIT 0,10"); while($message = $db->fetch_array($messages)) { $oldmessages[] = $message['message']; } $oldmessages = array_reverse($oldmessages); ?> <div id="chat"> <?php for ($count = 0; $count < 9; $count++) { echo $oldmessages[$count]; } ?> <script language="javascript" type="text/javascript"> <!-- setInterval( "document.getElementById('chat').innerHTML='<NEW CONTENT OF #CHAT>'", 1000 ); --> </script> </div> I'm trying to create a PHP chatroom script but I'm having a lot of trouble getting it to AutoRefresh The content should automatically update to , how do you make it do that? I've been searching for almost an hour

    Read the article

  • How to use substring in vbscript within a xsl page.

    - by dipesh
    I am trying to replace the double quotes in a string with a single quote, got the following code but get error message saying "Object Required strLocation" Sub UpdateAdvancedDecisions(strLocation) Dim d Dim strLLength strLLength = Len(strLocation) - 1 For d = 0 To strLLength alert strLocation strValue = strLocation.Substring(2,3) If strLocation.substring(d,d+1)=" " " Then strLLength = strLLength.substring(0, d) + "'" + strLLength.substring(d + 1,strLLength.length) Next End Sub

    Read the article

  • How would I go about writing a conditional statement to check if visitor is coming from a particular

    - by Matthew
    Hello guys, What I have in mind is this... We are going to have people come from a particular site during a acquisition campaign and was wondering how I could conditionalize a certain section of my site to display a thank you message instead of the sign up form as they would have had the opportunity to fill this out before coming to my landing page. I have seen solutions like: $referal = mysql_real_escape_string($_SERVER['HTTP_REFERER']); I would like to know if this is the best way to get this to work??? - okay this is what i think might work. The third party website that is referring people to our landing page once the form on that site has been filled out can push into the record a hidden input value of "www.sample.com" or whatever... then I can have something check the for that particular value and fire off the conidtional. Does that even sound right?

    Read the article

  • An html5 canvas element in the background of my page?

    - by fx42
    Is it possible to have a full screen canvas element in the background of a webpage and "normal" markup elements like a table in front of it? like the following snippet (if it wouldn't be used as alternative content): <canvas id=&#34;imageView&#34; width=100%; height=100%;> <table>...</table> </canvas>

    Read the article

  • How to tell my asp.net page to use .net 3.5?

    - by kralco626
    My company recently upgraded from IE 6 to IE 8. My site does not render properly. I wanted to make sure my .net version was fixed before I started to try to fix a problem. I think my web.config file says i'm using 3.5, but if I get an error when running the app I get this: Version Information: Microsoft .NET Framework Version:2.0.50727.3603; ASP.NET Version:2.0.50727.3082 Why does it say 2.0? rather than 3.5? How do i change this? (using visual studio 2008, running the site locally) Thanks in advance!

    Read the article

< Previous Page | 239 240 241 242 243 244 245 246 247 248 249 250  | Next Page >