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  • Performing a MYSQL query based off of $_GET results

    - by Michael N
    When a user clicks an item on my items page, it takes them to blank page template using $_GET to pass the item brand and model through. I'd like to perform another MYSQL query when that user clicks through to populate the blank page with the product details from my database. I'd like to retrieve the single row using the model number (unique ID) to populate the page with the information. I've tried a couple of things but am having a little difficulty. On my blank item page, I have $brand = $_GET['Brand']; $modelnumber = $_GET['ModelNumber']; $query = mysql_query("SELECT * FROM items WHERE `Model Number` = '$modelnumber'"); $results = mysql_fetch_row($query); echo $results; I think having ''s around Model Number is causing troubles, but without them, I get a Warning: mysql_fetch_row() expects parameter 1 to be resource, boolean given error. My database columns looks like Brand | Model Number | Price | Description | Image A few other things I have tried include $query = mysql_query("SELECT * FROM item WHERE Model Number = $_GET['ModelNumber']"); Which gave me a syntax error. I've also tried concatenating the $_GET which gives me a mysql_fetch_row() expects parameter 1 to be resource, boolean given error Which leads me to believe that I'm also going about displaying the results incorrectly. I'm not sure if I need to put it in a where loop like I have with my previous page which displays all items in the database because this is just displaying one.

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  • How can I secure my $_GETs in PHP?

    - by ggfan
    My profile.php displays all the user's postings,comments,pictures. If the user wants to delete, it sends the posting's id to the remove.php so it's like remove.php?action=removeposting&posting_id=2. If they want to remove a picture, it's remove.php?action=removepicture&picture_id=1. Using the get data, I do a query to the database to display the info they want to delete and if they want to delete it, they click "yes". So the data is deleted via $POST NOT $GET to prevent cross-site request forgery. My question is how do I make sure the GETs are not some javascript code, sql injection that will mess me up. here is my remove.php //how do I make $action safe? //should I use mysqli_real_escape_string? //use strip_tags()? $action=trim($_GET['action']); if (($action != 'removeposting') && ($action != 'removefriend') && ($action != 'removecomment')) { echo "please don't change the action. go back and refresh"; header("Location: index.php"); exit(); } if ($action == 'removeposting') { //get the info and display it in a form. if user clicks "yes", deletes } if ($action =='removepicture') { //remove pic } I know I can't be 100% safe, but what are some common defenses I can use. EDIT Do this to prevent xss $action=trim($_GET['action']); htmlspecialchars(strip_tags($action)); Then when I am 'recalling' the data back via POST, I would use $posting_id = mysqli_real_escape_string($dbc, trim($_POST['posting_id']));

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  • [Zend Framework] Forms and success output

    - by rasouza
    Well, It's a beginer's question but I really don't know what is the best way. I have a basic CRUD (Create, Retrieve, Update and Delete) in my project and I'd like to output some message if succeded or not in a div inside the same page. So, basically, I have a form which action is setted to the same page and I have a div #statusDiv below this same form which I'd like to output something like Register included with success. What is the best way for doing this? Set a flag in the controller $this->view->flagStatus = 'message' then call it in the view? Just to make it more clear. It's my code: //IndexController.php indexAction() ... //Check if there's submitted data if ($this->getRequest()->isPost()) { ... $registries->insert($data); $this->view->flagStatus = 'message'; $this->_redirect('/'); } Then my view: .... <?php if ($this->flagStatus) { ?> <div id="divStatus" class="success span-5" style="display: none;"> <?php echo $this->flagStatus; ?> </div> <?php } ?> ....

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  • How to separate date in php

    - by user225269
    I want to be able to separate the birthday from the mysql data into day, year and month. Using the 3 textbox in html. How do I separate it? I'm trying to think of what can I do with the code below to show the result that I want: Here's the html form with the php code: $idnum = mysql_real_escape_string($_POST['idnum']); mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO='$idnum'"); $month = mysql_real_escape_string($_POST['mm']); ?> <?php while ( $row = mysql_fetch_array($result) ) { ?> <tr> <td width="30" height="35"><font size="2">Month:</td> <td width="30"><input name="mo" type="text" id="mo" onkeypress="return handleEnter(this, event)" value="<?php echo $month = explode("-",$row['BIRTHDAY']);?>"> As you can see the column is the mysql database is called BIRTHDAY. With this format: YYYY-MM-DD How do I do it. So that the data from the single column will be divided into three parts? Please help thanks,

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  • How to first get different related values from diferent SQL tables (PHP)

    - by Ole Jak
    I am triig to fill options list. I have 2 tables USERS and STREAMS I vant to get all streams and get names of users assigned to that streams. Users consists of username and id Streams consists of id, userID, streamID I try such code: <?php global $connection; $query = "SELECT * FROM streams "; $streams_set = mysql_query($query, $connection); confirm_query($streams_set); $streams_count = mysql_num_rows($streams_set); while ($row = mysql_fetch_array($streams_set)){ $userid = $row['userID']; global $connection; $query2 = "SELECT email, username "; $query2 .= "FROM users "; $query2 .= "WHERE id = '{$userid}' "; $qs = mysql_query($query2, $connection); confirm_query($qs); $found_user = mysql_fetch_array($qs); echo ' <option value="'.$row['streamID'].'">'.$row['userID'].$found_user.'</option> '; } ?> But it does not return USER names from DB=( So what shall I do to this code to see usernames as "options" text?

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  • How to remove background of a image and copy into another?

    - by Gustavo Pinent
    I'm researching about captchas. In this idea, the task is: create a image from a JPEG and remove the white background, than create another image from another JPEG, than create the final image by adding the second as a background, and copying the first one over this background preserving the transparent area created, of course. Here is the code: header("Content-Type: image/jpeg"); $nFundo = rand(0,4); $Dirs = array(rand(0,7), rand(0,7), rand(0,7), rand(0,7)); // Will be four times all $_SESSION["form_captcha"] = $Dirs; $image = ImageCreatetruecolor(320, 80); ImageAlphaBlending($image, FALSE); ImageSaveAlpha($image, TRUE); $image_seta = ImageCreateFromJPEG("_captcha-seta.jpg"); // Image do copy over $image_fundo = ImageCreateFromJPEG("_captcha-fundo-".$nFundo.".jpg"); // Image to make the background for($i=0; $i<4; $i++){ ImageCopy($image, $image_fundo, $i*80, 0, 0, 0, 80, 80); } // So far so good, a background with a pattern repeated four times $color_white = ImageColorAllocate($image_seta, 255, 255, 255); ImageColorTransparent($image_seta, $color_white); ImageSaveAlpha($image_seta, TRUE); for($i=0; $i<4; $i++){ $image_seta_rot = imageRotate($image_seta, $Dirs[$i]*45, $color_white); ImageCopyResampled($image, $image_seta_rot, $i*80, 0, 0, 0, 80, 80, 80, 80); // Try } echo(imagejpeg($image)); imagedestroy($image); I tried to replace $image_seta_rot by $image_seta ("Try" line) to see if the rotation is the problem, but even without rotation, the white wasn't removed and the image just "erase" the background created before. So the copy is failing or the white were never removed... I may create a PNG with transparent background, but will be interesting to learn how to make it dynamically, don't you think? Any ideas?

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  • Adding up row number and displaying total using COUNT (PHP MySQL)

    - by Yvonne
    I'm attempting to run a query that adds up the total number of subjects in a class. A class has many subjects. There is a 'teachersclasses' table between teachers (the user table) and classes. The principles sounds pretty simple but I'm having some trouble in getting my page to display the number of subjects for each class (directly associated with the teacher) This is what I have so far, trying to make use of the COUNT with a nested SELECT: SELECT (SELECT count(*) FROM subjects WHERE subjects.classid = class.classid) AS total_subjects, class.classname, class.classid FROM class Then I am calling up 'num_subjects' to present the total within a while loop: <?php echo $row['total_subjects']?> From the above, I am receiving the total subjects for a class, but within the same table row (for one class) and my other while loop doesnt run anymore, which returns all of the classes associated with a teacher :( ... Bit of a mess now! I know to return the classes for a particular teacher, I can do an additional WHERE clause on the session of 'teacherid' but I think my query is getting too complicated for me that errors are popping up everywhere. Anyone have a quick fix for this! Thanks very much

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  • All possibilities in 2d array

    - by valli-R
    I have this array: $array = array ( array('1', '2', '3'), array('!', '@'), array('a', 'b', 'c', 'd'), ); And I want to know all character combination of sub arrays.. for example : 1!a 1!b 1!c 1!d 1@a 1@b 1@c 1@d 2!a 2!b 2!c 2!d 2@a 2@b ... Currently I am having this code : for($i = 0; $i < count($array[0]); $i++) { for($j = 0; $j < count($array[1]); $j++) { for($k = 0; $k < count($array[2]); $k++) { echo $array[0][$i].$array[1][$j].$array[2][$k].'<br/>'; } } } It works, but I think it is ugly, and when I am adding more arrays, I have to add more for. I am pretty sure there is a way to do this recursively, but I don't know how to start/how to do it. A little help could be nice! Thanks you!

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  • An issue on object orientation in php

    - by rabidmachine9
    Hello people, I have come up to issues while I'm trying to write some classes, here is an example: I have this class called TwitterGrub and I cant call it like that: $c = new TwitterGrub(); $c->twitterDisplay(); here is the class itself: <?php class TwitterGrub{ function twitterCapture($user = 'username',$password = 'pass') { $ch = curl_init("https://twitter.com/statuses/user_timeline.xml"); curl_setopt($ch, CURLOPT_HEADER, 1); curl_setopt($ch,CURLOPT_TIMEOUT, 30); curl_setopt($ch,CURLOPT_USERPWD,$user . ":" . $password); curl_setopt($ch,CURLOPT_RETURNTRANSFER,1); curl_setopt ($ch, CURLOPT_SSL_VERIFYPEER, 0); curl_setopt ($ch, CURLOPT_SSL_VERIFYHOST, 0); $result=curl_exec ($ch); $data = strstr($result, '<?'); $xml = new SimpleXMLElement($data); return $xml; } function twitterDisplay($twitNum = 2){ $xml = $this::twitterCapture(); for($i= 0; $i<$twitNum; $i++){ echo "<div class= 'curvebox'>".$xml->status[$i]->text."</div>"; } } } ?> The problem is that everytime I want to change the username or password I have to jump back to class definition and that makes things not modular... and in many ways it feels wrong. So the question is what would be the proper way to chance my username and password through the objects interface and then call twitterDisplay() method with the new data?Hope that makes sense. Thanks in advance

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  • custom function is not getting called

    - by nectar
    here my code - $child1 = create_childid()."01"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child1', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); echo $newid; update_level(); $child2 = create_childid()."02"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child2', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child3 = create_childid()."03"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child3', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child4 = create_childid()."04"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child4', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); $child5 = create_childid()."05"; $sqltree = "INSERT INTO tbltree (`userId`, `level`, `superId`, `rootId`, `childcount`) VALUES ('$child5', '1', '$newid', '$myroot', '0');"; mysql_query($sqltree); update_level(); ERROR : update_level(); is executing only once why??

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  • How to write this loop prettier?

    - by Tom
    I've just read this topic http://stackoverflow.com/questions/2930533/highlight-search-keywords-on-hover and actually I use pretty the same structure, but it looks awful. So can you give me an advice, how to write this loop prettier in one php file, I mean php and html at the same time? <table class="result"> <?php while ($row= mysql_fetch_array($result, MYSQL_ASSOC)) { $cQuote = highlightWords(htmlspecialchars($row['cQuotes']), $search_result); ?> <tr> <td style="text-align:right; font-size:15px;"><?php h($row['cArabic']); ?></td> <td style="font-size:16px;"><?php echo $cQuote; ?></td> <td style="font-size:12px;"><?php h($row['vAuthor']); ?></td> <td style="font-size:12px; font-style:italic; text-align:right;"><?php h($row['vReference']); ?></td> </tr> <?php } ?>

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  • Location of DB models in Zend Framework - want them centralized

    - by jeffkolez
    Maybe I've been staring at the problem too long and it's much simpler than I think, but I'm stuck right now. I have three websites that are going to share database models. I've structured my applications so that I have an application directory for each site and a public directory for each site. The DB models live in a directory in the library along with Zend Framework and my third party libraries. I use the Autoloader class and when I try to instantiate one of my DB classes, it fails. The library directory is in my include path, but for whatever reason it refuses to instantiate my classes. It will work if I have my models in my application directory, but that's not the point. They're supposed to be shared classes in a Library. $model = new Model_Login(); $model->hello_world(); This fails when its in the library. The class is just a test: class Model_Login { public function hello_world() { echo "hello world"; } } Everything works until I try to instantiate one of my models. I've even tried renaming the class to something else (Db_Login), but that doesn't work either. Any ideas? Thanks in advance.

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  • ajax form handling an array

    - by moata_u
    am trying to handle an array comes from php file after submitting the form data , the value of data after submitting the form is = ARRAY but i cant use this array in any way , any idea how can i handle this array !!!! Javascript : $('#file').live('change',function(){ $('#preview').html(''); $('#preview').html('<img src="loader.gif" />'); $('#data').ajaxForm(function(data){ $(data['toshow']).insertBefore('.pic_content').hide().fadeIn(1000); }).submit(); }); PHP : .... ....etc echo json_encode(array('toshow'=>somedata,'data'=>somedata)); data come from php file {"toshow":"\r\n\t\t\t\t\r\n\t\t<table class=\"out\">\r\n\t\t\t<tr ><td class=\"img\"><a title=\"2012-06-02 01-22-09\" rel=\"prettyPhoto\" href=\"img\/2012-06-02 01-22-09.284.jpg\"><img src=\"img\/thumb\/2012-06-02 01-22-09.284.jpg\"\/><\/a><\/td><\/tr>\r\n\t\t\t\r\n\t\t\t<td>\r\n\t\t\t\t<table cellSpacing=\"1\" cellPadding=\"0\">\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">2012-06-02 01-22-09<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><span class=\"click\">Download<\/span><\/td><\/tr>\r\n\t\t\t\t\t<tr><td class=\"data\"><a href=\"img\/2012-06-02 01-22-09.284.jpg\"><span class=\"click\">View<\/span><\/a><\/td><\/tr>\r\n\t\t\t\t<\/table>\r\n\t\t\t<\/td>\r\n\t\t\t<\/tr>\r\n\t\t<\/table>","span":"<span class='text'><img src='greencheck.png'\/>2012-06-02 01-22-09 Uploaded ,File Size =152Kb <\/span>"}

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  • Access property of a class from within a class instantiated in the original class.

    - by Iain
    I'm not certain how to explain this with the correct terms so maybe an example is the best method... $master = new MasterClass(); $master-doStuff(); class MasterClass { var $a; var $b; var $c; var $eventProccer; function MasterClass() { $this->a = 1; $this->eventProccer = new EventProcess(); } function printCurrent() { echo '<br>'.$this->a.'<br>'; } function doStuff() { $this->printCurrent(); $this->eventProccer->DoSomething(); $this->printCurrent(); } } class EventProcess { function EventProcess() {} function DoSomething() { // trying to access and change the parent class' a,b,c properties } } My problem is i'm not certain how to access the properties of the MasterClass from within the EventProcess-DoSomething() method? I would need to access, perform operations on and update the properties. The a,b,c properties will be quite large arrays and the DoSomething() method would be called many times during the execuction of the script. Any help or pointers would be much appreciated :)

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  • problem by displaying images stored in a MySQL database?

    - by user1400
    i have images in my blob field in database i use blow colde for displaying image but it does not show any pic , someone could tell me where is my wrong? this is my model: public function getListUser() { $select = $this->select() ->order('lastname DESC'); $adapter = new Zend_Paginator_Adapter_DbTableSelect ($select); return $adapter; } this my controller: $userModel = new Admin_Model_User(); $adapter = $userModel->getListUser(); $paginator = new Zend_Paginator ($adapter); $paginator->setItemCountPerPage(1); $page = $this->_request->getParam('page', 1); $paginator->setCurrentPageNumber($page); $this->view->paginator = $paginator; this my view code: <td style="width: 20%;"> <?php echo $this->lastname ?> </td> <td style="width: 20%;"><?php header("Content-type: image/gif"); print $this->image; ?></td>

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  • Zend Framework How can I print a logged in user name from a Zend_Session_Namespace

    - by IrishStudent76
    Hi all I have created the following login controller for my site and it works fine in relation to logging users in a logging them out. The thing I want to do is echo the logged in users name into the FlashMessenger for the success page how ever as my code stands I only get the following message when redirected to the success page, "you have been successfully logged in as Array". Can I also ask the following does the line $session-user =$adaptergetResultArray('Password'); create an array of user information less the password value from the database. Many Thanks in advance, IrishStudent76 <?php class LoginController extends Zend_Controller_Action { public function init(){ $this->view->doctype('XHTML1_STRICT'); } // login action public function loginAction() { $form = new PetManager_Form_Login; $this->view->form = $form; /* check for valid input from the form and authenticate using adapter Add user record to session and redirect to the original request URL if present */ if ($this->getRequest()->isPost()) { if ($form->isValid($this->getRequest()->getPost())) { $values = $form->getValues(); $adapter = new PetManager_Auth_Adapter_Doctrine( $values['username'], $values['password'] ); $auth = Zend_Auth::getInstance(); $result = $auth->authenticate($adapter); if ($result->isValid()) { $session = new Zend_Session_Namespace('petmanager.auth'); $session->user = $adapter->getResultArray('Password'); if (isset($session->requestURL)) { $url = $session->requestURL; unset($session->requestURL); $this->_redirect($url); } else { $this->_helper->getHelper('FlashMessenger') ->addMessage('You have been successfully logged in as '.$session- >user); $this->_redirect('/login/success'); } } else { $this->view->message = 'You could not be logged in. Please try again.'; } } } } public function successAction() { if ($this->_helper->getHelper('FlashMessenger')->getMessages()) { $this->view->messages = $this->_helper ->getHelper('FlashMessenger') ->getMessages(); } else { $this->_redirect('/login'); } } public function logoutAction() { Zend_Auth::getInstance()->clearIdentity(); Zend_Session::destroy(); $this->_redirect('/'); } }

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  • Processing JSON data with jQuery - strange results needing alert()

    - by James
    I have this code below. I randomly ran across that it will work if I have that alert message exactly where it is. If I take it out or move it to any other spot the tabs will not appear. What exactly is that alert doing that allows the code to work and how can I make it work without the alert? If I move the each loop into the success section it does not work even with the alert. $.ajax({ type: "GET", url: "../ajax.php", data: "action=tabs", dataType: "json", success: function(data){ Projects = data; } }); alert("yes"); $.each(Projects, function(i){ /* Sequentially creating the tabs and assigning a color from the array: */ var tmp = $('<li><a href="#" class="tab green">'+Projects[i].name+'<span class="left" /><span class="right" /></a></li>'); /* Setting the page data for each hyperlink: */ tmp.find('a').data('page','../ajax.php?action=lists&projectID='+Projects[i].project_id); /* Adding the tab to the UL container: */ $('ul.tabContainer').append(tmp); }); The ajax code is retuning json with this code $query = mysql_query("SELECT * FROM `projects` ORDER BY `position` ASC"); $projects = array(); // Filling the $projects array with new project objects: while($row = mysql_fetch_assoc($query)){ $projects[] = $row; } echo json_encode($projects); The returning data is very small and very fast so I don't think that is the problem.

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  • text in div not going to next line

    - by Kia Dull
    for some reason the text in my div doesn't go to the next line, i've tried several different css elements which don't seem to work.... word-wrap:break word, just jumbles the letters... what i want is for one there is an extra word it goes down to the next line like it's supposed to here is my code this is the div it's in #top7 { width: 150px; height:auto; margin: 5px; display: block; float: left; word-wrap:break-word; } text that it's in #p6 { font-family: Myriad Pro; margin: 1px; font-size: 22px; background-color:#540f45; padding: 5px 5px 3px 4px; margin:4px; } a { text-decoration: none; color: white; text-align: right; font-family: Myriad Pro; } here is the php function that retrieves the data from the database <p id='p6'><?php echo "<a href='' "</a>"; ?></p> this is all wrapped in these two id's body { background:#603e4f; display: block; } #foursquare { background-color:#603e4f; width: 290px; display: block; position: absolute; }

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  • Convert html with image to ms.word

    - by user1629258
    I have the html code as below: file.html <body> <h1>TEST</h1> <p>this is test</p> <table> <tr> <td>1</td> <td>2</td> </tr> <tr> <td>3</td> <td>4</td> </tr> <tr> <td>5</td> <td><img src="../../../wamp/www/html2doc/SGEPP.jpg"></td> </tr> </table> html2doc.php <?php $handle = fopen("doc2html.html","r"); $contents = ''; while (!feof($handle)) { $contents .= fread($handle, 8192); } header("Content-type: application/vnd.ms-word"); header("Content-Disposition: attachment;Filename=html2word.doc"); echo $contents; ?> The problems: when I convert it,I get html2word.doc but I can get only all texts from html file.For the images in html file I can not get it, it is missing images.So I want to get all data from html and images also.How do I fix this?Anyone help me please,Thanks.

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  • Show image on hover with PHP

    - by Sorosh
    I have a small problem with my PHP code and It would be very nice if someone could help me. I want to display an image when hovering over a link. This is the link with the PHP code that I have now: <a href="<?php the_permalink(); ?>"><?php if ( has_post_thumbnail() ) {the_post_thumbnail();} else if ( has_post_video() ) {the_post_video_image();}?></a> This code shows a image, but I want to execute this code when hovering over the link with the image: <?php echo print_image_function(); ?> The code also shows a image that belongs to a category. I don't want the initial image to disappear I simply want to show the second image on top off the first image when hovering over the first image. I don't know if it is helpful but I use Wordpress and I am not a PHP expert. I even don't know if this is going to work. Thats why I am asking if somebody can help me with this. Thanks in advance

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  • How to make a multi vector in C++

    - by Bob Dealio
    I was wondering why can't I have a multi vectors in C ++ /please take a look at this example, it's not working though. there are only two parts to the code, foo function to manipulate the vector and the main function to echo them. typedef vector< vector<double> > MyVec; MyVec foo() { MyVec v; for (int index=0; index < 2; index ++) { for (int j=0; j<5; j++) { v[index][j]; } } return v; } int main () { MyVec z = foo(); for (int i = 0; i < z.size(); i++) { cout << z[i][1]; } return 0; }

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  • Scan HTML for values with a special character before them.

    - by DogPooOnYourShoe
    Say I have values on my page, like #100 #246, What I want to do is scan the page for values with a # before them and then alter them to put a hyperlink on it $MooringNumbers = '#!' . $MooringNumbers . ' | ' . '#!' . $row1["Number"]; } $viewedResult = '<tr><td>' .$Surname.'</td><td>'.$Title.'</td><td>'.$MooringNumbers . '</td><td>'.$Telephone.'</td><td>' . '<a href="rlayCustomerUpdtForm.php?id='.$id.'">[EDIT]</a></td>'.'<td>'. '<a href="deleteCustomer.php?id='.$id.'">[x]</a></td>'. '</tr>'; preg_replace('/#!(\d\d\d)/', '<a href="update.php?id=${1}">${1}</a>', $viewedResult); echo $viewedResult; This is the broken code which doesnt work.

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  • Left Join only returning one row

    - by Adam
    I am trying to join two tables. I would like all the columns from the product_category table (there are a total of 6 now) and count the number of products, CatCount, that are in each category from the products_has_product_category table. My query result is 1 row with the first category and a total count of 68, when I am looking for 6 rows with each individual category's count. <?php $result = mysql_query(" SELECT a.*, COUNT(b.category_id) AS CatCount FROM `product_category` a LEFT JOIN `products_has_product_category` b ON a.product_category_id = b.category_id "); while($row = mysql_fetch_array($result)) { echo ' <li class="ui-shadow" data-count-theme="d"> <a href="' . $row['product_category_ref_page'] . '.php" data-icon="arrow-r" data-iconpos="right">' . $row['product_category_name'] . '</a><span class="ui-li-count">' . $row['CatCount'] . '</span></li>'; } ?> I have been working on this for a couple of hours and would really appreciate any help on what I am doing wrong.

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  • How can I add dynamic text from a different table where primary key is a foreign key to adynamic table being shown?

    - by Jethro Tamares Doble
    I have here a dynamic table named tb_user with column region_id and institute_id and both ids are primary key of another table tb_region (with column region_name and region_id) and tb_institute (column institute_id and institute_name). I wanted to see region_name and institute_name instead of the ids. I've used this php script <?php echo $row_institute['institution_name']; ?> and query to collect data for tb_institute mysql_select_db($database_connection_ched, $connection_ched); $query_institution = "SELECT institute_id, institute_name FROM tb_institute"; $institution = mysql_query($query_institution, $connection_ched) or die(mysql_error()); $row_institution = mysql_fetch_assoc($institution); $totalRows_institution = mysql_num_rows($institution); but it seems not to display the correct name of id. query i used to collect data: mysql_select_db($database_connection_ched, $connection_ched); $query_notification = sprintf("SELECT * FROM tb_user WHERE status = 'inactive' ORDER BY date_register ASC", GetSQLValueString($colname_notification, "text")); $query_limit_notification = sprintf("%s LIMIT %d, %d", $query_notification, $startRow_notification, $maxRows_notification); $notification = mysql_query($query_limit_notification, $connection_ched) or die(mysql_error()); $row_notification = mysql_fetch_assoc($notification); if (isset($_GET['totalRows_notification'])) { $totalRows_notification = $_GET['totalRows_notification']; } else { $all_notification = mysql_query($query_notification); $totalRows_notification = mysql_num_rows($all_notification); } $totalPages_notification = ceil($totalRows_notification/$maxRows_notification)-1;

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  • Access php multidimensional array key based on a variable string

    - by ggirtsou
    I have stored the XML path to items in a string like this: response->items->item. What I need to do is to access an array called $xml_array like this: $xml_array['response']['items']['item'] When I write it in the code it works. The thing is that I want it to be done on the fly. I use this to convert response->items->item to ['response']['items']['item']: $xml_path = 'response->items->item'; $explode_path = explode('->', $xml_path); $correct_string = false; foreach($explode_path as $path) { $correct_string .= '[\''.$path.'\']'; } the problem is that I can't access $xml_array by doing this: $xml_array[$correct_string] So I end up with this: $xml_tag = 'title'; $xml_path = 'response->items->item'; $correct_string = '$items = $xml2array'; $explode_path = explode('->', $xml_path); foreach($explode_path as $path) { $correct_string .= '[\''.$path.'\']'; } $correct_string .= ';'; eval($correct_string); foreach($items as $item) { echo $item[$xml_tag].'<br />'; } and access the $xml_array array through $items array. Is there any way I can do this and avoid using eval()? Thanks in advance!

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