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  • Java long task - Did it stop writing to file?

    - by rockit
    I am writing a lot of data to a file, and while keeping my eye on the file it eventually stopped growing in size. Essentially my task is getting information from a database, and printing out all non-unique values in column A. Since there are many rows to the database table, and the database table is across my network, this is taking days to complete. Thus I'm concerned that since the file isn't growing, that it isn't actually writing to the file anymore. Which is odd, I have no "catch"'s in my code, so if there was a problem writing to file, wouldn't it have thrown an error?! Should I let the task complete (estimate 2-3 days from today), or is there something else that I don't know going on here making my application not write to the file?! my algorithm goes something like this Declare file Create new file Open file for writing get database connection get resultset from database for each row in the resultset - write column "A" to file - if row# % 100000 then write to screen "completed " + row# + " rows" when no more rows exist close file write to screen - "completed"

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  • show activity indicator while loading ViewController

    - by Crystal
    I have a ViewController that takes time to load its views. When I run Instruments, I see from the home screen, if I tap on the icon that pushes that view controller onto the stack, it's half laying out the views, and half getting the data for the views. I tried adding an activity indicator to display on the home screen over the button when the button is pressed to push the LongRunningViewController onto the stack. So I basically do this: - (IBAction)puzzleView:(id)sender { dispatch_async(dispatch_get_main_queue(), ^{ [self.activityIndicator startAnimating]; }); PuzzleViewController *detailViewController = [[[PuzzleViewController alloc] init] autorelease]; [self.navigationController pushViewController:detailViewController animated:YES]; [self.activityIndicator stopAnimating]; }

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  • How to close a form in UserControl

    - by FJPoort
    I created a UserControl with the buttons Save, Close and Cancel. I want to close the form without saving on the Cancel button, prompt a message to save on the Close button and Save without closing on the Save button. Normally, I would have used this.Close() on the Cancel button, but the UserControl doesn't have such an option. So I guess I have to set a property for that. Scrolling down the "Questions that may already have your answer" section, I came across this question: How to close a ChildWindow from an UserControl button loaded inside it? I used the following C# code: private void btnCancel_Click(object sender, EventArgs e) { ProjectInfo infoScreen = (ProjectInfo)this.Parent; infoScreen.Close(); } This does the job for one screen, but I wonder if I have to apply this code for all the screen I have? I think there should be a more efficient way. So my question is: Do I need to apply this code for every form I have, or is there another (more efficient) way?

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  • Detecting touch area on Android

    - by HappyAppDeveloper
    Is it possible to detect every pixel being touched? More specifically, when the user touches the screen, is it possible to track all the x-y coordinates of the cluster of points touched by the user? How can I tell the difference between when users are drawing with their thumb and when they are drawing with the tip of a finger? I would like to reflect the brush difference depending on how users touch the screen, and would also like to track x-y coordinates of all the pixels being touched over time. Thanks so much in advance for any help.

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  • jquery grab and move toggle element

    - by tony noriega
    i have a div that is displayed via: $('a#biz-blue-lnk').click(function() { $('#business-blue').show(); return false; }); what i want to figure out is when this DIV is displayed, can i enable the user to grab it and move it around the screen? potentially if they click another DIV they could have two elements on screen... and would like them to be able to move them around to see each one... possible?

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  • ncurses - expect: sleep executes at wrong time

    - by rahul
    I have some ncurses apps that I need to automate to test repeatedly. I am placing the "sleep" command between "send" commands. However, what i see is that all the sleep's are executed in the beginning before the screen loads. expect concatenates the sends (I see that at the screen bottom during sleep) then issues them together. I have tried sending all keys with "send -s" or "send -h". That marginally helps. I've replaced "-f" on line 1 with "-b" - again a tiny difference. Why isn't "sleep" pausing at the right time. Incidentally, my programs have a getc() loop, so i can't use "expect" command. I tried that too. #!/usr/bin/expect -f spawn ruby testsplit.rb #expect set send_human {3 3 5 5 7} set send_slow {10 1} exp_send -s -- "--" exec sleep 3 send -s "+" send -s "=" sleep 1 send -h -- "-" send -h -- "-" sleep 1 send -h -- "v" interact

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  • [Android] Weird black line on top of list view

    - by CaseyB
    I am creating a layout with a ListView and at the very top of the list there is this weird black line that I can't seem to figure out how to get rid of! It's part of the ListView because it moves up and down as I size the ListView. Has anyone ran into this before? I couldn't get DDMS to take a screen capture for some reason so I took a picture of the screen with my G1, so please forgive the quality! As you can see the line is there at the top of the fade out in the list.

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  • How i solve memory leak problem?

    - by RRB
    Hi, I developing an simple application in which design or make code in which i creating and instance object of UIImage. When i swip on Ipad screen it make up an image of the sreen and that image i render into UIImage object after that this image i set into UIImageView object and UIimage object is released. Every time i swipe on the screen and above process is does again and again. But it give me leak in renderImage = [[UIImage alloc] init];. Code, _renderImage = [[UIImage alloc] init]; _textImageV = [[UIImageView alloc] init]; [self renderIntoImage]; -(void)renderIntoImage { UIGraphicsBeginImageContext(bgTableView.bounds.size); [self.view.layer renderInContext:UIGraphicsGetCurrentContext()]; _renderImage = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); } _textImageV.image = _renderImage; [_renderImage release]; after completing the process of swipe i also releasing _textImageV. How i solve the memory leak problem in UIImage *_renderImage?

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  • how to check the first time user of my App in android?

    - by androidbase Praveen
    hi all, In my App, first it shows a splash screen. after that another activity, then my main activity must be show. this is my design plan. the second activity(i.e before main activity) must be show for the first time user of the app. if he/she closes the app.splash screen will redirect to main activity automatically. how to do this ? Any Idea? i am developing my app for android phones.

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  • How to create horizontal menu in android ?

    - by sohilv
    Hello Friends, I am working on horizontal menu that will open on top of the screen. Layout is something like following, || < || Menu Item1 || Menu Item2 || Menu Item3 || || I want to put this on top of the screen. It can have more than 3 menu item and it can traverse through previous and next arrow. I started with like this, RelativeLayout ( width - fill_parent) Gallery View ( Here i appended adapter ) There is two problem, - Gallery view contains the space before and after - While scrolling its item gets selected Though its not ideal solution for this. How can i build custom component like this ? Any help appreciated. Thanks

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  • ActionScript display zero value

    - by bwong
    It seems the number Datatype handles zeros and nulls the same. I need to display a zero value on the screen, but AS displays nothing. When it's saved, the value is saved as a zero, and therefore shows up zero on the screen. Is there a way to display the zero value using a new object? public class myObject{ private var numVar:Number } My AS file: var temp:MyObject temp.numVar = 0; When I debug, temp.numVar contains a value of 0, but does not show anything on the UI. If this object is then saved to the DB, and then displayed to the UI, it shows a 0. My question is - how do I get temp.numVar to display 0 before persistenting it to the DB?

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  • WPF Manipulation and Touch events not firing, but mouse events do?

    - by Smetad Anarkist
    I have a Samsung LD220Z multi touch monitor, and when I'm experimenting with some WPF and touch features the touch events arent firing. The mouse down event seems to be firing however. Does this mean that I have to take into account that not all touch screen behave the same, and how do I get the touch inputs on my screen? I've tried the Windows 7 Touch pack that microsoft released. And the multi touch features seems to work there. Any suggestion on how to proceed with this?

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  • Java error - not a statement, what does this mean?

    - by user2898828
    I am trying to get my code to create the new constructor objects which I require to create a mobile phone object. I have tried naming the constuctor fields to create the object. when I compile my code on this line this.Mobile samsungPhone = new Mobile("Samsung", 1, 2, "verizon", 3 "GPS"); I get this error: not a statement, what does this mean?? UPDATED CODE! my code: /** * to write a simple java class Mobile that models a mobile phone. * * @author (Lewis Burte-Clarke) * @version (14/10/13) */ public class Mobile { // type of phone private String phonetype; // size of screen in inches private int screensize; // menory card capacity private int memorycardcapacity; // name of present service provider private String serviceprovider; // type of contract with service provider private int typeofcontract; // camera resolution in megapixels private int cameraresolution; // the percentage of charge left on the phone private int checkcharge; // wether the phone has GPS or not private String GPS; // instance variables - replace the example below with your own private int x; // The constructor method public Mobile(String mobilephonetype, int mobilescreensize, int mobilememorycardcapacity,int mobilecameraresolution,String mobileGPS, String newserviceprovider) { this.phonetype = mobilephonetype; this.screensize = mobilescreensize; this.memorycardcapacity = mobilememorycardcapacity; this.cameraresolution = mobilecameraresolution; this.GPS = mobileGPS; this.serviceprovider = newserviceprovider; this.typeofcontract = 12; this.checkcharge = checkcharge; // you do not use this ones during instantiation,you can remove them if you do not need or assign them some default values Mobile samsungPhone = new Mobile("Samsung", 1, 2, "verizon", 3, "GPS"); 1024 = screen size; 2 = memory card capacity; 3=resolution; GPS = gps; "verizon"=service provider; typeofcontract = 12; checkcharge = checkcharge; } } // A method to display the state of the object to the screen public void displayMobileDetails() { System.out.println("phonetype: " + phonetype); System.out.println("screensize: " + screensize); System.out.println("memorycardcapacity: " + memorycardcapacity); System.out.println("cameraresolution: " + cameraresolution); System.out.println("GPS: " + GPS); System.out.println("serviceprovider: " + serviceprovider); System.out.println("typeofcontract: " + typeofcontract); } } class mymobile { public static void) { Mobile Samsung = new Mobile("Samsung", 1, 2, "verizon", 3, "GPS"); Mobile Blackberry = new Mobile("Blackberry", "3.", "4","8", "GPS"); Samsung.displayMobileDetails(); Blackberry.displayMobileDetails(); } } any answers and replies would be greatly appreciated!

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  • Create an Edit view similar to Contacts App

    - by Daniel Granger
    I have an edit view in my app which is a instance of UITableViewController and contains one cell with a textfield in a grouped table. At the moment this cell is at the top of the screen and is firstResponder so they keyboard is visible as well. But in all the Apples apps like the Contacts App when you edit a piece of information like an Email it buts both of its rows in the middle between the Nav Bar and the Keyboard not at the top of the screen. How do I achieve this effect? Many Thanks

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  • Re-opening closed dialog puts it in the start position after moving it

    - by semmelbroesel
    I'm using multiple instances of the JQuery-UI dialog along with draggable and resizable. Whenever I drag or resize one of the dialog boxes, the position and dimensions of the current box are saved to a database and then loaded the next time the page opens. This is working well. However, when I close a dialog box and re-open it using a button, jQuery sets the position of the box back to its original location in the center of the screen. Furthermore, I use a show effect to slide the box off to the left on closing and in from the left on re-opening. I found two ways to update its position when the slide in animation is done, however, it still slides into the center of the screen, and I have yet to find a way to get it to slide in towards the location it is supposed to have. Here are the parts of the code that play a part in this: $('.box').dialog({ closeOnEscape: false, hide: { effect: "drop", direction: 'left' }, beforeClose: function (evt, ui){ var $this = $(this); SavePos($this); // saves the dimensions to db }, dragStop: function() { var $this = $(this); SavePos($this); }, resizeStop: function() { var $this = $(this); SavePos($this); }, open: function() { var $this = $(this); $this.dialog('option', { show: { effect: "drop", direction: 'left'} } ); if (init) // meaning only load this code when the page has finished initializing { // tried it both ways - set the position before and after the effect - no success UpdatePos($this.attr('id')); // I tried this section with promise() and effect / complete - I found no difference $this.parent().promise().done(function() { UpdatePos($this.attr('id')); }); } } }); function UpdatePos(key) { // boxpos is an object holding the position for each box by the box's id var $this = $('#' + key); //console.log('updating pos for box ' + boxid); if ($this && $this.hasClass('ui-dialog-content')) { //console.log($this.dialog('widget').css('left')); $this.dialog('option', { width: boxpos[key].width, height: boxpos[key].height }); $this.dialog('widget').css({ left: boxpos[key].left + 'px', top: boxpos[key].top + 'px' }); //console.log('finished updating pos'); //console.log($this.dialog('widget').css('left')); } } The button that re-opens the box has this code on it to make that happen: var $box = $('#boxid'); if ($box) { if ($box.dialog('isOpen')) { $box.dialog('moveToTop'); } else { $box.dialog("open") } } I don't know what jQuery-UI does to the box as it hides it (other than display:none) or to make it slide in, so maybe there's something I'm missing here that might help... Basically, I need JQuery to remember the box' position and put the box back into that location when it is re-opened. It took me days to make it this far, but this is one obstacle I have yet to overcome. Maybe there's a different way I can re-open the box? Thanks! EDIT: Forgot - this issue ONLY happens when I use my UpdatePos function to set the location of a box (i.e. on page load). When I drag a box with my mouse, close it, and re-open it, everything works. So I'm guessing there's one more storage location for the box' position that I'm missing here... EDIT2: After more messing with it, my code for debugging now looks like this: open: function() { var $this = $(this); console.log('box open'); console.log($this.dialog('widget').position()); // { top=0, left=-78.5} console.log($this.dialog('widget').css('left')); $this.dialog('option', { show: { effect: "drop", direction: 'left'} } ); if (init) { UpdatePos($this.attr('id')); $this.parent().promise().done(function() { console.log($this.dialog('widget').position()); // { top=313, left=641.5} console.log($this.dialog('widget').css('left')); UpdatePos($this.attr('id')); console.log($this.dialog('widget').position()); // { top=121, left=107} console.log($this.dialog('widget').css('left')); }); } The results I'm getting are: box open Object { top=0, left=-78.5} -78.5px Object { top=313, left=641.5} 641.5px Object { top=121, left=107} 107px So looks to me as if the widget is being moved off screen (left=-78.5) and then moved for the animation, and then my code moves it into the location that it should be in (121/107). The position() results for $box.position() or $box.dialog().position() do not change during this debugging section. Maybe this will help someone here - I'm still out of ideas here... ... and I just discovered that when I drag the item around myself, then close and re-open it, it is very unpredictable. Sometimes, it will end up in the correct location horizontally, but not vertically. Sometimes, it will end up back in the center of the screen...

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  • Basic iPhone app help

    - by LaSha
    I'm new to iphone development and have about 5 days of experience with xcode, so I need some help developing the following app. I'm not sure where to start. The app is very simple, it's like a simplified version of the address book that came with the iphone a screen shows a list of all items in a list view list can be filtered through search list can also be favorites or unfavorites selecting an item will take the user to another screen with more detailed information (a pic, location,) the data should be stored in an xml file. Can you guys point me to the right path? or know any code samples that does this? Been stuck on this for days now. Thanks!!!

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  • Slide div content from left to right

    - by Inuka Rathnayake
    I'm beginner in to jquery and i wonder always how do developers do like this. Can someone give me a simple example..? http://static.livedemo00.template-help.com/wt_37928/#!/home What i need is there is a menubar and when you click a link from it that link's content should come to center of the screen by left and when you click another link that visible content should go to right and recently clicked link's content come to the screen as i mentioned. Can anyone help me out...? It will be a great relieve to me. Thank you.

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  • How do I prevent Window resizing when the Workstation is Locked then Unlocked?

    - by Terry
    We have an application that is run in multi-monitor environments. Users normally have the application dialog spread out to span multiple mointors. If the user locks the workstation, and then unlocks it, our application is told to resize. Our users find this behavior frustrating, as they then spend some time restoring the previous layout. We're not yet sure whether it is the graphics driver requesting the resize or Windows. Hopefully through this question, it will become clearer which component is responsible, Popular applications like (File) Explorer and Firefox behave the same way in this setup. To replicate just: open Explorer (Win+E) drag the Explorer window to being horizontally larger than 1 screen lock workstation (Win+L), unlock the application should now resize to being solely on 1 screen How do I prevent Window resizing when the Workstation is Locked then Unlocked? Will we need to code in checks for (un)locking? Is there another mechanism we're not aware of?

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  • Android RealViewSwitcher : How to start on second page?

    - by DarcCode
    i'm using RealViewSwitcher I got from this site. It works perfectly on my code, but I don't have any idea how to set the initial current screen to second or third screen. the method setCurrentScreen(int) doesn't affect anything and if I change the for loop inside the onLayout() method from for (int i = 0; i < count; i++) {...} into for (int i = 1; i < count; i++){...} It does starts in page two, but you can't go to page one. Any idea how to start on page two?

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  • how to animate a menu item into a large div (window) using jquery's animate?

    - by ijjo
    i'm pretty sure this can be done pretty easily with jquery's animate api, but i'm not good enough to figure it out. what i want to do is this: i have a menu item at the top of the viewport that the user will click on. when the user clicks on it, you'll see something that looks like the div "popping" out of the menu and float to a particular location on the screen. when i say popping i don't mean anything fancy - i just mean it appears to be originating from the menu item and settling somewhere on the screen that i specify. but the important part is that this animation happens really fast. fast enough where you don't have to actually wait for the window to appear, but slow enough so the eye sees the animation start from the menu item and end up at a new location where the window will actually appear, and appear with a specify height and width. hope that all made sense?

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  • How do I place an image centered in a DIV and text to the right? Overflow problems

    - by user2218041
    I have a div container where I want to put in a centered image and a small description to the right. The specifications are: The image should have a bottom margin of 35px. The image should always show fully on the screen, so it resizes when the screen does. It should have the biggest size possible, but never be cropped and never use scrollbars. The image should be centered with respect to the container, with the text showing on the right margin. The text should be left-aligned horizontally, center-aligned vertically and have a 30px separation from the image. I've tried using a table in the container and using divs, but I can't find a clean solution. I can show you the non-working code I've tried on request.

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  • C++ - Creating folder method

    - by Matthew
    I have the following method in C++: void create_folder(LPCWSTR full_folder) //Method to create folder in case it does not exist { if(!CreateDirectory(full_folder,attr)) //Checking whether the folder already exists { switch (GetLastError()) { case ERROR_ALREADY_EXISTS: printf("The folder already exists!\n\n"); break; case NULL: printf("The folder does not exist!\n\n"); printf("The folder was created successfully!\n\n"); break; } } } In case the folder already exists, the correct message is displayed on the screen. However, if the folder does NOT exist, nothing is displayed on the screen, that is, the part identified by case NULL is not executed. How can I solve this problem? In other words, how can I get the code after the case NULL to run if the folder does not exist?

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