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  • php - get content from second pair of quotes in string

    - by Aaron Turecki
    I'm trying to get the contents of the second quotes and only the second quotes from a string. Right now I'm able to get the contents of all three quotes. What am I doing wrong? Is it possible to just print the second value in the output array? Text 2014-06-02 11:48:41.519 -0700 Information 94 NICOLE Client "[WebDirect] (207.230.229.204) [207.230.229.204]" opening database "FMServer_Sample" as "Admin". PHP if (preg_match_all('~(["\'])([^"\']+)\1~', $line, $matches)) $database_names = $matches[2]; print_r($database); Output [WebDirect] (207.230.229.204) [207.230.229.204], FMServer_Sample, Admin

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  • SQL Query: Using Cursors

    - by user2953138
    I need some directions for SQL Server & Cursors: I have a table named Order: OrderID Item Amount 1 A 10 1 B 1 2 A 5 2 C 4 2 D 21 3 B 11 I have a second table named Storage: Item Amount A 40 B 44 C 20 D 1 For every OrderID, I want to check if enough items are available. If not, I want to return an error message. How can this be done with Cursors at all? Are nested cursors the solution to this? My main issue is to understand how I can fetch the OrderID as actual "Group" of ID=1, 2, 3 etc. instead of line by line

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  • How to output an array's content in columns in BASH.

    - by Arko
    I wanted to display a long list of strings from an array. Right now, my script run through a for loop echoing each value to the standard output: for value in ${values[@]} do echo $value done Yeah, that's pretty ugly! And the one column listing is pretty long too... I was wondering if i can find a command or builtin helping me to display all those values in columns, like the ls command does by default when listing a directory (ls -C). [Update] Losing my brain with column not displaying properly formatted columns, here's more info: The values: $ values=( 01----7 02----7 03-----8 04----7 05-----8 06-----8 07-----8 08-----8 09---6 10----7 11----7 12----7 13----7 14-----8 15-----8 16----7 17----7 18---6 19-----8 20-----8 21-----8) (Notice the first two digits as an index and the last one indicating the string length for readability) The command: echo " ${values[@]/%/$'\n'}" | column The result: Something is going wrong...

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  • How to format a string as a telephone number in C#

    - by Brian G
    I have a string "1112224444' it is a telephone number. I want to format as 111-222-4444 before I store it in a file. It is on a datarecord and I would prefer to be able to do this without assigning a new variable. I was thinking: String.Format("{0:###-###-####}", i["MyPhone"].ToString() ); but that does not seem to do the trick. ** UPDATE ** Ok. I went with this solution Convert.ToInt64(i["Customer Phone"]).ToString("###-###-#### ####") Now its gets messed up when the extension is less than 4 digits. It will fill in the numbers from the right. so 1112224444 333 becomes 11-221-244 3334 Any ideas?

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  • What is the meanning of 'idx_categories_desc_categories_name' in osCommerce

    - by Sumant
    while working on osCommerce-3 i got the table structure for category & categories_description as CREATE TABLE IF NOT EXISTS `osc_categories` ( `categories_id` int(10) unsigned NOT NULL AUTO_INCREMENT, `categories_image` varchar(255) DEFAULT NULL, `parent_id` int(10) unsigned DEFAULT NULL, `sort_order` int(11) DEFAULT NULL, `date_added` datetime DEFAULT NULL, `last_modified` datetime DEFAULT NULL, PRIMARY KEY (`categories_id`), KEY `idx_categories_parent_id` (`parent_id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=5 ; CREATE TABLE IF NOT EXISTS `osc_categories_description` ( `categories_id` int(10) unsigned NOT NULL, `language_id` int(10) unsigned NOT NULL, `categories_name` varchar(255) NOT NULL, PRIMARY KEY (`categories_id`,`language_id`), KEY `idx_categories_desc_categories_id` (`categories_id`), KEY `idx_categories_desc_language_id` (`language_id`), KEY `idx_categories_desc_categories_name` (`categories_name`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8; here i am not getting the meanning of indexing "idx_categories_desc_categories_id", "idx_categories_desc_language_id", "idx_categories_desc_categories_name" What is the use of this indexing.What does it mean?

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  • getting java.lang.OutOfMemoryError exception while running a Midlet (using netbeans)

    - by Jeeka
    I am writing a Midlet(using Netbeans) which reads a file containing exactly 2400 lines (each line being 32 characters long) and (extract a part of each line) puts them in an array. I am doing the same for 11 such files( all files have exactly 2400 lines).The Midlet runs fine for reading 6 files and putting them in 6 arrays. However, the Midlet stops while doing it for the 7th file throwing the following exception: TRACE: , startApp threw an Exception java.lang.OutOfMemoryError (stack trace incomplete) java.lang.OutOfMemoryError (stack trace incomplete) I have tried the modifying the netbeans.conf file to increase the heap memory ( as suggested by many forums and blogs) but nothing works for me. Here are the parameters that i had modified in the netbeans.conf file: -J-Xss2m -J-Xms1024m -J-Xmx1024m -J-XX:PermSize=1024m -J-XX:MaxPermSize=1536m -J-XX:+UseConcMarkSweepGC -J-XX:+CMSClassUnloadingEnabled -J-XX:+CMSPermGenSweepingEnabled Can anyone please help me to get me out of this ! I badly need this to be sorted out ASAP ! Thanks in advance !

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  • Interning strings in Java

    - by Tiny
    The following segment of code interns a string. String str1="my"; String str2="string"; String concat1=str1+str2; concat1.intern(); System.out.println(concat1=="mystring"); The expression concat1=="mystring" returns true because concat1 has been interned. If the given string mystring is changed to string as shown in the following snippet. String str11="str"; String str12="ing"; String concat11=str11+str12; concat11.intern(); System.out.println(concat11=="string"); The comparison expression concat11=="string" returns false. The string held by concat11 doesn't seem to be interned. What am I overlooking here? I have tested on Java 7, update 11.

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  • Oracle/c#: How do i use bind variables with select statements to return multiple records?

    - by twiga
    I have a question regarding Oracle bind variables and select statements. What I would like to achieve is do a select on a number different values for the primary key. I would like to pass these values via an array using bind values. select * from tb_customers where cust_id = :1 int[] cust_id = { 11, 23, 31, 44 , 51 }; I then bind a DataReader to get the values into a table. The problem is that the resulting table only contains a single record (for cust_id=51). Thus it seems that each statement is executed independently (as it should), but I would like the results to be available as a collective (single table). A workaround is to create a temporary table, insert all the values of cust_id and then do a join against tb_customers. The problem with this approach is that I would require temporary tables for every different type of primary key, as I would like to use this against a number of tables (some even have combined primary keys). Is there anything I am missing?

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  • rails g migration error

    - by user1506183
    I don't know what to do. Try to use command $ rails g migration vacancy but this command give me error: invoke active_record /home/proger/.rvm/rubies/ruby-1.9.3-p194/lib/ruby/1.9.1/psych.rb:203:in `parse': (<unknown>): mapping values are not allowed in this context at line 21 column 11 (Psych::SyntaxError) from /home/proger/.rvm/rubies/ruby-1.9.3-p194/lib/ruby/1.9.1/psych.rb:203:in `parse_stream' from /home/proger/.rvm/rubies/ruby-1.9.3-p194/lib/ruby/1.9.1/psych.rb:151:in `parse' ... There are many rows in error code I don't know how to fix that Thanks

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  • how to modify a json array with jQuery

    - by Emin
    I have the following json array of objects in my code var groups = [ { "gid": 28, "name": "Group 1", "ishidden": false, "isprivate": false }, { "gid": 16, "name": "Group 2", "ishidden": true, "isprivate": false }, { "gid": 31, "name": "Group 3", "ishidden": true, "isprivate": false }, { "gid": 11, "name": "Group 4", "ishidden": false, "isprivate": false }, { "gid": 23, "name": "Group 5", "ishidden": false, "isprivate": false } ]; I can access or iterate through this with no problm using jQuery. However a situation arose where I need to change a value of one of the items (e.g. change the ishidden property to true for gid: 28) and then run some other jQuery function against it. Is this possible? or do I have to re-build the whole object ? If possible, how can I achieve this? any help would be appreciated!

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  • Obtaining photo 'stars' rating using PHP

    - by DarwinIcesurfer
    I am trying to extract the photo 'stars' rating from .jpg files using php code. My intent is to show the highest rated images as part of a slideshow. I found that using the PHP_JPEG_Metadata_Toolkit_1.11 I am able to get the rating of the file if the rating is set from within Vista (Right click - Properties - Details - Set rating by clicking on stars) by reading the array returned by the Metadata_Toolkit $exif = get_EXIF_JPEG( $photodir . "/" . $filename ); $rating = $exif[0][18246]['Data'][0]; However if I set the rating using Adobe Bridge, I can see the 'stars' in Vista, but the $exif[0][18246]['Data'][0] returns a null value. Is PHP code available to read the ratings applied by both Windows Vista AND Adobe Bridge?

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  • Top x rows and group by (again)

    - by Tibor Szasz
    Hello, I know it's a frequent question but I just can't figure it out and the examples I found didn't helped. What I learned, the best strategy is to try to find the top and bottom values of the top range and then select the rest, but implementing is a bit tricky. Example table: id | title | group_id | votes I'd like to get the top 3 voted rows from the table, for each group. I'm expecting this result: 91 | hello1 | 1 | 10 28 | hello2 | 1 | 9 73 | hello3 | 1 | 8 84 | hello4 | 2 | 456 58 | hello5 | 2 | 11 56 | hello6 | 2 | 0 17 | hello7 | 3 | 50 78 | hello8 | 3 | 9 99 | hello9 | 3 | 1 I've fond complex queries and examples, but they didn't really helped.

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  • Which data structure for List of objects + datagrid wiev

    - by Martin
    Hi, I have to develop a code which will store a list of objects, as example below 101, value 11, value 12, value 13 ...etc 102, value 21, value 22, value 23 ...etc 103, value 31, value 32, value 33 ...etc 104, value 41, value 42, value 43 ...etc Now, the difficulty is, that first column is an identifier, and whole table should always be sorted by it. Easy access to each element is required. Additionally, list should be easily updated, and extended by adding element at the end as well as in front and still keep being sorted by first column. Finally, I would like to be able to display values of the above in datagridview. What is most important is a performance of the implementation, as rows will be updated many times per second, and datagridview should be able to display all changes immediately. I was thinking about creating class for the values, and then a Dictionary but encountered a problem with displaying values in gridview. What would be the most optimal way of implementing the code? Thanks in advance Martin

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  • Distance between numpy arrays, columnwise

    - by Jaapsneep
    I have 2 arrays in 2D, where the column vectors are feature vectors. One array is of size F x A, the other of F x B, where A << B. As an example, for A = 2 and F = 3 (B can be anything): arr1 = np.array( [[1, 4], [2, 5], [3, 6]] ) arr2 = np.array( [[1, 4, 7, 10, ..], [2, 5, 8, 11, ..], [3, 6, 9, 12, ..]] ) I want to calculate the distance between arr1 and a fragment of arr2 that is of equal size (in this case, 3x2), for each possible fragment of arr2. The column vectors are independent of each other, so I believe I should calculate the distance between each column vector in arr1 and a collection of column vectors ranging from i to i + A from arr2 and take the sum of these distances (not sure though). Does numpy offer an efficient way of doing this, or will I have to take slices from the second array and, using another loop, calculate the distance between each column vector in arr1 and the corresponding column vector in the slice?

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  • Invalid SQL Query

    - by svovaf
    I have the next query that in my opinion is a valid one, but I keep getting error telling me that there is a proble on "WHERE em.p4 = ue.p3" - Unknown column 'ue.p3' in 'where clause'. This is the query: SELECT DISTINCT ue.p3 FROM table1 AS ue INNER JOIN table2 AS e ON ue.p3 = e.p3 WHERE EXISTS( SELECT 1 FROM ( SELECT (COUNT(*) >= 1) AS MinMutual FROM table4 AS smm WHERE smm.p1 IN ( SELECT sem.p3 FROM table3 AS sem INNER JOIN table2 AS em ON sem.p3 = em.p3 WHERE em.p4 = ue.p3 AND sem.type = 'friends' AND em.p2 = 'normal' ) AND smm.p5 IN ( 15000,15151 ) ) AS Mutual WHERE Mutual.MinMutual = TRUE) LIMIT 11 If I execute the sub-query which is inside the EXISTS function, everything is O.K. PLEASE HELP!

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  • Reverse Bredth First Search in C#

    - by Ngu Soon Hui
    Anyone has a ready implementation of the Reverse Bredth First Search algorithm in C#? By Reverse Bredth First Search, I mean instead of searching a tree starting from a common node, I want to search the tree from the bottom and gradually converged to a common node. Let's see the below figure, this is the output of a Bredth First Search: In my reverse bredth first search, 9,10,11 and 12 will be the first few nodes found ( the order of them are not important as they are all first order). 5, 6, 7 and 8 are the second few nodes found, and so on. 1 would be the last node found. Any ideas or pointers?

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  • Using Linq to select a range of members in a list

    - by clintp
    Given a list of elements like so: int[] ia = new int[] { -4, 10, 11, 12, 13, -1, 9, 8, 7, 6, 5, 4, -2, 6, 15, 32, -5, 6, 19, 22 }; Is there an easy way in Linq to do something along the lines of "Select the elements from the -1 up to the next negative number (or the list exhausts)"? A successful result for -1 would be (-1, 9, 8, 7, 6, 5, 4). Using -2 would give the result (-2, 6, 15, 32). Not a homework problem. I'm just looking at an implementation using a bool, a for loop, and an if wondering if there's a cleaner way to do it.

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  • ModX: Selecting and outputting specific menu items using Wayfinder

    - by Staffan Estberg
    tI've been trying to output specific menu items, also wanting to change the names of some, without satisfying results. The problem is that I have three different menu setups throughout the site - the header split into two sections and the footer divided into a couple of columns. This is what I've tried so far - [[Wayfinder? &startId=0 &level=1 &limit=5 &excludeDocs=49,61,55]] While it works excluding all the other links isn's the most optimal solution as there are 11 in total plus I want to be able to 1. rearrange the order and 2. change the names of two of them. Is this possible at all using the Wayfinder or do I have to create a snippet? Thanks in advance.

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  • Get variable value from XML to JavaScript. Pure way.

    - by kalininew
    I have XML: <point> ... <longitude>34.123123</longitude> </point> <point> ... <longitude>11.12534534</longitude> </point> <point> ... <longitude>32.567653</longitude> </point> <point> ... <longitude>33.345345</longitude> </point> ... Task: get values of <longitude> in javascript (in variable). Which is purest way? It is possible to do it without XSLT (without making dummy elements)?

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  • C++ Constructor Initializer List - using member functions of initialized members

    - by Andy
    I've run into the following a few times with initializer lists and I've never been able to explain it well. Can anyone explain why exactly the following fails (I don't have a compiler to catch typos, so bear with me): class Foo { public: Foo( int i ) : m_i( i ) {} //works with no problem int getInt() {return m_i;} ~Foo {} private: int m_i; }; class Bar { public: Bar() : m_foo( 5 ), //this is ok m_myInt( m_foo.getInt() ) //runtime error, seg 11 {} ~Bar() {} private: Foo m_foo; int m_myInt; }; When trying to call member functions of members initialized higher up the initializer list, I get seg faults. I seem to recall this is a known problem (or perhaps somehow by design) but I've never seen it well described. The attached example is contrived with plain old data types, but substitute the Bar::m_myInt with another object lacking a default (empty) constructor and the issue is more real. Can anyone enlighten me? Thanks!

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  • Mysql table data problem?

    - by DaTeNtImE
    I'm new to mysql and was wondering how can I add the users birthdate in the following HTML format to the MYSQL table data listed below? How would the structure look like for example email VARCHAR(80) NOT NULL,? Here is the HTML code below. <li><label>Date of Birth: </label> <label for="month">Month: </label> <select name="month" id="month"> <option value="January">January</option> <option value="February">February</option> <option value="March">March</option> <option value="April">April</option> <option value="May">May</option> <option value="June">June</option> <option value="July">July</option> <option value="August">August</option> <option value="September">September</option> <option value="October">October</option> <option value="November">November</option> <option value="December">December</option> </select> <label for="day">Day: </label> <select id="day" name="day"> <option value="0" selected="selected">Day</option> <option value="1">1</option> <option value="2">2</option> <option value="3">3</option> <option value="4">4</option> <option value="5">5</option> <option value="6">6</option> <option value="7">7</option> <option value="8">8</option> <option value="9">9</option> <option value="10">10</option> <option value="11">11</option> <option value="12">12</option> <option value="13">13</option> <option value="14">14</option> <option value="15">15</option> <option value="16">16</option> <option value="17">17</option> <option value="18">18</option> <option value="19">19</option> <option value="20">20</option> <option value="21">21</option> <option value="22">22</option> <option value="23">23</option> <option value="24">24</option> <option value="25">25</option> <option value="26">26</option> <option value="27">27</option> <option value="28">28</option> <option value="29">29</option> <option value="30">30</option> <option value="31">31</option> </select> <label for="year">Year: </label><input type="text" name="year" id="year" /></li> Here is the MySQL table data. CREATE TABLE users ( user_id INT UNSIGNED NOT NULL AUTO_INCREMENT, first_name VARCHAR(20) NOT NULL, last_name VARCHAR(40) NOT NULL, email VARCHAR(80) NOT NULL, pass CHAR(40) NOT NULL, user_level TINYINT(1) UNSIGNED NOT NULL DEFAULT 0, active CHAR(32), registration_date DATETIME NOT NULL, PRIMARY KEY (user_id), UNIQUE KEY (email), INDEX login (email, pass) );

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  • CoreDumpDirectory isn't working on ubuntu; getting segmentation fault with php

    - by siran
    I'm trying to solve a segmentation fault. This message appears in my apache-error.log: [notice] child pid 3979 exit signal Segmentation fault (11) I've tried disabling some apache and php modules but I'm still getting the same error. I've also tried putting this in apache2.conf: CoreDumpDirectory /tmp/apache2-gdb-dump and then chmod 777, chown www-data... so that the server can write. I can see no core-dump files to give me a hint on the error. Does anybody have an idea why CoreDumpDirectory isn't working on Ubuntu?

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  • Running Ruby app on Apache

    - by TandemAdam
    I have been learning Ruby lately, and I want to upload a test web application to my server. But I can't figure out how to get it to run on my shared hosting. My Hosting Details Shared Hosting with JustHost (see here for list of features) OS: Linux Apache: 2.2.11 cPanel: 11.25.0-STABLE No SSH access. Can install Ruby Gems. Can't install Apache modules. Can "Manage Ruby on Rails Applications" through cPanel. Mongrel gem is installed. I built the following simple HelloWorld Ruby Rack app using Sinatra: #!/usr/bin/ruby ruby require 'rubygems' require 'sinatra' get '/hi' do "Hello World!" end I just can can't figure out how to "start" the application. Do I need to tell Mongrel (or maybe Apache) that the application exists somehow? How do I start this app running? I am happy to provide more info if needed.

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  • Parse a json(?) string using php

    - by passatgt
    I have a string, more specifically, this one: a:16:{s:9:"pseudonym";O:16:"SimpleXMLElement":0:{}s:14:"parallel_title";O:16:"SimpleXMLElement":0:{}s:9:"title_var";O:16:"SimpleXMLElement":0:{}s:6:"series";O:16:"SimpleXMLElement":0:{}s:9:"vol_title";O:16:"SimpleXMLElement":0:{}s:9:"reference";O:16:"SimpleXMLElement":0:{}s:10:"bound_with";O:16:"SimpleXMLElement":0:{}s:15:"general_remarks";O:16:"SimpleXMLElement":0:{}s:6:"copies";O:16:"SimpleXMLElement":1:{i:0;s:1:"1";}s:11:"remarks_BPH";O:16:"SimpleXMLElement":0:{}s:3:"ICN";O:16:"SimpleXMLElement":1:{i:0;s:4:"neen";}s:10:"provenance";O:16:"SimpleXMLElement":0:{}s:7:"binding";O:16:"SimpleXMLElement":0:{}s:10:"size_hxwxd";O:16:"SimpleXMLElement":0:{}s:6:"BookID";O:16:"SimpleXMLElement":1:{i:0;s:4:"6271";}s:5:"repro";O:16:"SimpleXMLElement":0:{}} Is it possible to parse this string somehow? I need to display the keys and values in a list. I tried to use json_decode but it not returns anything, even with the second true parameter(json_decode($string,true))

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  • MySQL: filling empty fields with zeroes when using GROUP BY

    - by SaltLake
    I've got MySQL table CREATE TABLE cms_webstat ( ID int NOT NULL auto_increment PRIMARY KEY, TIMESTAMP_X timestamp DEFAULT CURRENT_TIMESTAMP, # ... some other fields ... ) which contains statistics about site visitors. For getting visits per hour I use SELECT hour(TIMESTAMP_X) as HOUR , count(*) AS HOUR_STAT FROM cms_webstat GROUP BY HOUR ORDER BY HOUR DESC which gives me | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 20 | 3 | | 18 | 2 | | 15 | 1 | | 12 | 3 | | 9 | 1 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | And I'd like to get following: | HOUR | HOUR_STAT | | 24 | 15 | | 23 | 12 | | 22 | 9 | | 21 | 0 | | 20 | 3 | | 19 | 0 | | 18 | 2 | | 17 | 0 | | 16 | 0 | | 15 | 1 | | 14 | 0 | | 13 | 0 | | 12 | 3 | | 11 | 0 | | 10 | 0 | | 9 | 1 | | 8 | 0 | | 7 | 0 | | 6 | 0 | | 5 | 0 | | 4 | 0 | | 3 | 5 | | 2 | 7 | | 1 | 9 | | 0 | 12 | How should I modify the query to get such result? Thanks.

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