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• Problem with mysql query in paging

  - by jasmine

  I have a very simple paging and mysql query. Im not sure that my query is right: $perPage =4; $page= (isset($GET['page']) && is_numeric($GET['page'])) ? $_GET['page'] : 1; $start = ($page * $perPage ) - $perPage ; if (is_numeric($_GET['cID'])){$cid = $_GET['cID'];} $totalCount = sprintf("SELECT COUNT(*) as 'Total' FROM content WHERE catID = %d", $cid ) ; $count = mysql_query($totalCount); $rowCount = mysql_fetch_array($count); $sql = sprintf("SELECT id, title, abstract, content_image FROM content WHERE catID = %d ORDER BY id DESC LIMIT %d, %d", $cid, $start, $perPage ); $query = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_array($query)){ echo $row['id'].' : '. $row['title'] .'<br>'; } with /categories.php?cID=1&page=2 and /categories.php?cID=1&page=1 The output is: 95 : titlev 94 : titlex 93 : titlec 92 : titleb and not changed. What is wrong in my query? Thanks in advance

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• Want to convert whole PHP script in RUBY ON RAILS

  - by user303058

  // set image quality (from 0 to 100, not applicable to gif) $imgquality = 100; // get data from $_POST or $_GET ? $data = &$_POST; // get image dimensions $width = (int) $data['width']; $height = (int) $data['height']; // create image object $img = imagecreatetruecolor($width, $height); // populate image with pixels for ($y = 0; $y < $height; $y++) { // innitialize $x = 0; // get row data $row = explode(',', $data['r'.$y]); // place row pixels $cnt = sizeof($row); for ($r = 0; $r < $cnt; $r++) { // get pixel(s) data $pixel = explode(':', $row[$r]); // get color $pixel[0] = str_pad($pixel[0], 6, '0', STR_PAD_LEFT); $cr = hexdec(substr($pixel[0], 0, 2)); $cg = hexdec(substr($pixel[0], 2, 2)); $cb = hexdec(substr($pixel[0], 4, 2)); // allocate color $color = imagecolorallocate($img, $cr, $cg, $cb); // place repeating pixels $repeat = isset($pixel[1]) ? (int) $pixel[1] : 1; for ($c = 0; $c < $repeat; $c++) { // place pixel imagesetpixel($img, $x, $y, $color); // iterate column $x++; } } } // set proper content type header('Content-type: image/'.$imgtype); header('Content-Disposition: attachment; filename="chart.'.$imgtype.'"'); // stream image $function = 'image'.$imgtype; if ($imgtype == 'gif') { $function($img); } else { $function($img, null, $imgquality); } // destroy imagedestroy($img); ?

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• Is fetching data from database a get-method thing?

  - by theva

  I have a small class that I call Viewer. This class is supposed to view the proper layout of each page or something like that... I have a method called getFirstPage, when called the user of this method will get a setting value for which page is currently set as the first page. I have some code here, I think it works but I am not really shure that I have done it the right way: class Viewer { private $db; private $user; private $firstPage; function __construct($db, $user) { $this->db = $db; if(isset($user)) { $this->user = $user; } else { $this->user = 'default'; } } function getFistPage() { $std = $db->prepare("SELECT firstPage FROM settings WHERE user = ':user'"); $std->execute(array(':user' => $user)); $result = $std->fetch(); $this->firstPage = $result['firstPage']; return $this->firstPage; } } My get method is fetching the setting from databse (so far so good?). The problem is that then I have to use this get method to set the private variable firstPage. It seems like I should have a set method to do this, but I cannot really have a set method that just fetch some setting from database, right? Because the user of this object should be able to assume that there already is a setting defined in the object... How should I do that?

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• Php Syntax Error

  - by Jeff Cameron

  I'm trying to update a table in php and I keep getting syntax errors. Here's what I've got: if (isset($_POST['inspect'])) { // get gis_id from pole table to update fm_poles $sql = "select gis_id from poles where pole_number = '".$_GET['polenumber']."'"; $rs = pg_query($sql) or die('Query failed: ' . pg_last_error()); $gisid = $row['gis_id']; pg_free_result($rs); // update fm_poles $sql = "update fm_poles set inspect ='".$_POST['inspect']."',co_date = '".$_POST['co_date']."',size = '".$_POST['size']."',date = ".$_POST['date'].",brand ='".$_POST['brand']."',backspan = ".$_POST['backspan']." WHERE gis_id = ".$gisid.""; print $sql."<BR>\n"; $rs = pg_query($sql) or die('Query failed: ' . pg_last_error()); pg_free_result($rs); } This is the error it gives me: update fm_poles set inspect ='20120208',co_date = '20030710',size = '30-5',date = 0,brand ='test',backspan = 300 WHERE gis_id = The error message: Query failed: ERROR: syntax error at end of input at character 129

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• PHP Array to CSV

  - by JohnnyFaldo

  I'm trying to convert an array of products into a CSV file, but it doesn't seem to be going to plan. The CSV file is one long line, here is my code: for($i=0;$i<count($prods);$i++) { $sql = "SELECT * FROM products WHERE id = '".$prods[$i]."'"; $result = $mysqli->query($sql); $info = $result->fetch_array(); } $header = ''; for($i=0;$i<count($info);$i++) { $row = $info[$i]; $line = ''; for($b=0;$b<count($row);$b++) { $value = $row[$b]; if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$data"; Also, the header doesn't force a download. I've been copy and pasting the output and saving as .csv

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• Session in php are not enough clear to me

  - by Lulzim

  I find sessions in php kind of confusing, can anybody of you explain those to me. I have an example which is not working in my case: I register sessions this way, would you please tell me is this the right way of registering sessions //this is the page from where i register myusername in sessions if($count==1){ session_start(); $_SESSION['myusername'] = $_POST['myusername']; include("enterpincover.php"); } else { echo "Wrong Pin"; } here i check first whether the username is registered in sessions in oder to open his account , otherwise open again login. It works, if user is not loged in, it will show login page which is right, if user is loged it shows welcome message but not the Welcome the name of the user as I want. for ex: Welcome David <?php session_start(); if(isset($_SESSION['myusername'])) { echo 'Welcome '.$_SESSION['myusername']; } else { include("leftmodules.php"); include("rightmodules.php"); include("login.php"); } ?>

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• A problem of a repeated parameter in the pagination links?

  - by myaccount

  The problem is that when I load page 2 for example the URL becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2 And that's fine but when I get to page 3 it becomes: http://domain.com/index.php?restaurant-id=45&currentpage=2&currentpage=3 And so on, it adds one more currentpage parameter everytime a new page is loaded from the pagination links! I wonder how this problem can be fixed? Here's some of the pagination function's code /****** build the pagination links ******/ // Getting current page URL with its parameters $current_page_url = ($_SERVER["PHP_SELF"].(isset($_SERVER["QUERY_STRING"])?"?".htmlentities($_SERVER["QUERY_STRING"]):"")); // Determine which sign to use (? or &) before the (currentpage=xx) parameter $sign = preg_match('/\?/', $current_page_url) ? '&' : '?'; $pagination_links = ''; // if not on page 1, don't show back links if ($currentpage > 1) { // show << link to go back to page 1 $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=1'>First page</a> "; // get previous page num $prevpage = $currentpage - 1; // show < link to go back 1 page $pagination_links .= " <a href='{$current_page_url}{$sign}currentpage=$prevpage'>previous</a> "; } else { $pagination_links .= "? ?"; }// end if

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• PHP SDK Requires two logins...doesn't recognize first

  - by Jay Konieczny

  I am using the following code to authenticate whether users are logged in or not. While users can log in, they have to click the login button twice. Additionally, sometimes even after they click the log-in button twice, my "user info" part of the page (earlier in the page than the content) shows them as logged out while the actual page shows them as logged in. Here is the code. Could someone suggest a better way of handling log-ins? function isLoggedIn($facebook) { if (isset($facebook) and $facebook->getUser() != 0) { // UserID exists, but user may still not be logged in. Let's check: try { $facebook->api('/me', 'GET'); // If this succeeds, then they are logged in. return true; } catch(FacebookApiException $e) { // Some kind of error, so not logged in. if(session_id() === '') session_destroy(); return false; } } else { if(session_id() === '') session_destroy(); return false; } } Thanks!

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• Could this be considered a well-written class (am I using OOP correctly)?

  - by Ben Dauphinee

  I have been learning OOP principals on my own for a while, and taken a few cracks at writing classes. What I really need to know now is if I am actually using what I have learned correctly, or if I could improve as far as OOP is concerned. I have chopped a massive portion of code out of a class that I have been working on for a while now, and pasted it here. To all you skilled and knowledgeable programmers here I ask: Am I doing it wrong? class acl extends genericAPI{ // -- Copied from genericAPI class protected final function sanityCheck($what, $check, $vars){ switch($check){ case 'set': if(isset($vars[$what])){return(1);}else{return(0);} break; } } // --------------------------------- protected $db = null; protected $dataQuery = null; public function __construct(Zend_Db_Adapter_Abstract $db, $config = array()){ $this->db = $db; if(!empty($config)){$this->config = $config;} } protected function _buildQuery($selectType = null, $vars = array()){ // Removed switches for simplicity sake $this->dataQuery = $this->db->select( )->from( $this->config['table_users'], array('tf' => '(CASE WHEN count(*) > 0 THEN 1 ELSE 0 END)') )->where( $this->config['uidcol'] . ' = ?', $vars['uid'] ); } protected function _sanityRun_acl($sanitycheck, &$vars){ switch($sanitycheck){ case 'uid_set': if(!$this->sanityCheck('uid', 'set', $vars)){ throw new Exception(ERR_ACL_NOUID); } $vars['uid'] = settype($vars['uid'], 'integer'); break; } } private function user($action = null, $vars = array()){ switch($action){ case 'exists': $this->_sanityRun_acl('uid_set', $vars); $this->_buildQuery('user_exists_idcheck', $vars); return($this->db->fetchOne($this->dataQuery->__toString())); break; } } public function user_exists($uid){ return($this->user('exists', array('uid' => $uid))); } } $return = $acl_test->user_exists(1);

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• How to pass values from array into mysql with php

  - by moustafa

  my original code is this <tr> <th> <label for="user_level"> User Level: * <?php echo isset($valid_user_level) ? $valid_user_level : NULL; ?> </label> </th> </tr> <td> <select name="user_level" id="user_level" class="sel"> <option value="">Select one…</option> <option value="1">User</option> <option value="5">Admin</option> </select> </td> this give me the option to select one of choice from the drop down menu i.e. user and when user is selected and the submit button is pressed this will insert the value 1 into the database which will when the user logs in tell the system that they are are normal user. I want to change the code to the following <tr> <td> <select name="user_level" id="user_level" class="sel"> <option value="">Select one…</option> <?php if(!empty($level)) { foreach($level as $value) { echo "<option value='{$value}'"; echo getSticky(2,'user_level',$value); echo ">{$value}</option>"; } } ?> </select> </td> </tr> With this being my array query $level = array('User','Admin'); How can I pass the values of 1 for user level and 5 for admin in this code so when the user is selected it inouts 1 into the database?

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• Variable wont echo

  - by jonnnnnnnnnie

  I have the following code, where the var $username doesn't echo, when you type in a value. //TODO: SET AUTH TOKEN as random hash, save in session $auth_token = rand(); if (isset($_POST['action']) && $_POST['action'] == 'Login') { $errors = array(); //USED TO BUILD UP ARRAY OF ERRORS WHICH ARE THEN ECHOED $username = $_POST['username']; if ($username = '') { $errors['username'] = 'Username is required'; } echo $username; // var_dump($username) returns string 0 } require_once 'login_form.html.php'; ?> login_form is this: <form method="POST" action=""> <input type="hidden" name="auth_token" value="<?php echo $auth_token ?>"> Username: <input type="text" name="username"> Password: <input type="password" name="password1"> <input type="submit" name="action" value="Login"> </form> The auth token part isn't important, it just when I type in a value in username textbox and press the login button, the username wont echo, var_dump returns string (0) and print_r is just blank.

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• PHP & HTML Purifier Error: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given

  - by TaG

  I'm trying to Integrate HTML Purifier http://htmlpurifier.org/ to filter my user submitted data but I get the following error below. And I was wondering how can I fix this problem? I get the following error. on line 22: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given line 22 is. if (mysqli_num_rows($dbc) == 0) { Here is the php code. if (isset($_POST['submitted'])) { // Handle the form. require_once '../../htmlpurifier/library/HTMLPurifier.auto.php'; $config = HTMLPurifier_Config::createDefault(); $config->set('Core.Encoding', 'UTF-8'); // replace with your encoding $config->set('HTML.Doctype', 'XHTML 1.0 Strict'); // replace with your doctype $purifier = new HTMLPurifier($config); $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.*, profile.* FROM users INNER JOIN contact_info ON contact_info.user_id = users.user_id WHERE users.user_id=3"); $about_me = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['about_me'])); $interests = mysqli_real_escape_string($mysqli, $purifier->purify($_POST['interests'])); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO profile (user_id, about_me, interests) VALUES ('$user_id', '$about_me', '$interests')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE profile SET about_me = '$about_me', interests = '$interests' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); return; } }

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• MySQL/PHP Search Efficiency

  - by iMaster

  Hi! I'm trying to create a small search for my site. I've tried using full-text index search, but I could never get it to work. Here is what I've come up with: if(isset($_GET['search'])) { $search = str_replace('-', ' ', $_GET['search']); $result = array(); $titles = mysql_query("SELECT title FROM Entries WHERE title LIKE '%$search%'"); while($row = mysql_fetch_assoc($titles)) { $result[] = $row['title']; } $tags = mysql_query("SELECT title FROM Entries WHERE tags LIKE '%$search%'"); while($row = mysql_fetch_assoc($tags)) { $result[] = $row['title']; } $text = mysql_query("SELECT title FROM Entries WHERE entry LIKE '%$search%'"); while($row = mysql_fetch_assoc($text)) { $result[] = $row['title']; } $result = array_unique($result); } So basically, it searches through all the titles, body-text, and tags of all the entries in the DB. This works decently well, but I'm just wondering how efficient would it be? This would only be for a small blog, too. Either way I'm just wondering if this could be made any more efficient.

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• Search for values in nested array

  - by dardub

  I have an array as follows array(2) { ["operator"] => array(2) { ["qty"] => int(2) ["id"] => int(251) } ["accessory209"] => array(2) { ["qty"] => int(1) ["id"] => int(209) } ["accessory211"] => array(2) { ["qty"] => int(1) ["id"] => int(211) } } I'm trying to find a way to verify an id value exists within the array and return bool. I'm trying to figure out a quick way that doesn't require creating a loop. Using the in_array function did not work, and I also read that it is quite slow. In the php manual someone recommended using flip_array() and then isset(), but I can't get it to work for a 2-d array. doing something like if($array['accessory']['id'] == 211) would also work for me, but I need to match all keys containing accessory -- not sure how to do that Anyways, I'm spinning in circles, and could use some help. This seems like it should be easy. Thanks.

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• Display error message at top of form

  - by moustafa

  Hello, I'm trying to get the following error to show when some once presses the submit button and has not filled in the required field/s. My PHP code is. <?php require_once("includes/database.php"); require_once("includes/functions.php"); if(isset($_POST['full_name'])) { $required = array('full_name','user_name','email','pwd','pwd2'); $missing = array(); $validation = array( 'full_name' => 'Please provide your full name', 'user_name' => 'Please provide your username', 'email' => 'Please provide your valid email address', 'pwd' => 'Please provide your password', 'pwd2' => 'Please confirm your password', 'userdup' => 'Username already registered', 'emaildup' => 'Email address already registered', 'mismatch' => 'Passwords do not match' ); //Sanitise and clean function $full_name = escape($_POST['full_name']); $user_name = escape($_POST['user_name']); $email = escape($_POST['email']); $pwd = escape($_POST['pwd']); $pwd2 = escape($_POST['pwd2']); foreach($_POST as $key => $value) { $value = trim($value); if(empty($value) && in_array($key,$required)) { array_push($missing,$key); } else { ${$key} = escape($value); } }

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• How to check Isavailablity in ajax?

  - by udaya

  Hi This is what i have in my view page <td width=""><input type="text" name="txtUserName" id="txtUserName" /></td> <td><input type="button" name="CheckUsername" id="CheckUsername" value="Check Availablity" onclick="Check_User_Name();"/></td> Onclick of the button the Check_User_Name function in my ajax.js loads This is the Check_User_Name function function Check_User_Name(source) { var UserName = document.getElementById('txtUserName').value; if(window.ActiveXObject) User_Name = new ActiveXObject("Microsoft.XMLHTTP"); else if(window.XMLHttpRequest) User_Name = new XMLHttpRequest(); var URL = newURL+"ssit/system/application/views/ssitAjax.php"; URL = URL +"?CheckUsername="+UserName; User_Name.onreadystatechange = User_Name_Fun; User_Name.open("GET",URL,true); User_Name.send(null); } function User_Name_Fun() { document.getElementById('User_div').innerHTML=User_Name.responseText; } Then I can have the value in echo username then the $result has all the user name Hows can i checkIsavailablity of username from here if(($_GET['CheckUsername']!="") || (isset($_GET['CheckUsername']))) { echo $UserName = $_GET['CheckUsername'];//echo username $_SESSION['state'] = $State; $queryres = "SELECT dUser_name FROM tbl_login WHERE dIsDelete='0'"; $result = mysql_query($queryres,$cn) or die("Selection Query Failed !!!");

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• codeigniter avoiding html div's

  - by rabidmachine9

  Hello there!Is there a proper syntax to avoid div's in codeigniter? I don't really like opening and closing tags all the time... <div class="theForm"> <?php echo form_open('edit/links');//this form uploads echo "Enter the Name: ". form_input('name','name'); echo "Enter the Link: ". form_input('url','url'); echo " ".form_submit('submit', 'Submit'); echo form_close(); if (isset($linksQuery) && count($linksQuery)){ foreach($linksQuery as $link){ echo anchor($link['link'], $link['name'].".", array("class" => "links")); echo form_open('edit/links',array('class' => 'deleteForm')); echo form_hidden('name',$link['name']); echo " ".form_submit('delete','Delete'); echo form_close(); echo br(2); } } ?> </div>

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• Why can I not echo out the value from an input text?

  - by user3684783

  I am using Wordpress to do an auction website. Here is what the code looks like <form method="post" action="<?php echo ProjectTheme_post_new_with_pid_stuff_thg($pid, '1');?>"> <?php do_action('ProjectTheme_step1_before_title'); ?> <!--////////// Project Title /////////////--> <li> <h2><?php echo __('Your Project Title', 'ProjectTheme'); ?>: <img src="../../images/help-icon.png" width="16" height="16" id="showhelp1"/></h2> <div id="help1">Your Project Title should be informative and brief.</div> <p><input type="text" style="width:90%;" class="do_input" name="project_title" value="Enter an informative & brief title..." onfocus="this.value = this.value=='Enter an informative & brief title...'?'':this.value;" onblur="this.value = this.value==''?'Enter an informative & brief title...':this.value;" /></p> <input type="submit" class="post-button" name="project_submit1" value="<?php _e("Next Step", 'ProjectTheme'); ?> &raquo;" /> </form> I am using a step by step form for users to fill in and I wanted to do a preview page, however I tried to use: if(isset($_POST['project_submit1'])){ $Name = $_POST['project_title']; echo "$Name"; } It shows up nothing.

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• Should I change $_REQUEST to $_POST

  - by Scarface

  Hey guys quick question, I have a checkbox system where a list of items can be checked and deleted on the click of a button. I currently use request and it does the job but I was wondering if $_REQUEST was some sort of security risk or improper. If anyone has any advice I would appreciate it. Should I change to $_POST? If so, what is the best way to go about it? foreach ($_REQUEST as $key=>$value) { if (substr($key,0,3)==="img") { $id = substr($key,3); if(isset($_REQUEST['Delete'])) { $sql = 'SELECT file_name,username FROM images WHERE id=?'; $stmt = $conn->prepare($sql); $result=$stmt->execute(array($id)); while ($row = $stmt->fetch(PDO::FETCH_ASSOC)) { $image=$row['file_name']; $user=$row['username']; $myFile = "$user/images/$image"; unlink($myFile); } <input id=\"img".$id."\" name=\"img".$id."\" type=\"checkbox\">

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• Warning: Trim expects

  - by user1257518

  I'm getting this warning Warning: trim() expects parameter 1 to be string, array given in .. which is my trim line. The full code is functioned to send an error when fields are empty. However, this error appears saying every field is empty, but only the 'native' field is meant to be required so thats my 2nd problem. Thanks for any help! session_start(); $err = array(); $user_id = intval($_SESSION['user_id']); // otherwise if (isset($_POST['doLanguage'])) { $link = mysql_connect(DB_HOST, DB_USER, DB_PASS) or die("Couldn't make connection."); // check if current user is banned $the_query = sprintf("SELECT COUNT(*) FROM users WHERE `banned` = '0' AND `id` = '%d'", $user_id); $result = mysql_query($the_query, $link); $user_check = mysql_num_rows($result); // user is ok if ($user_check > 0) { // check for empty fields foreach ($_POST as $key => $val) { $value = trim($val); if (empty($value)) { $err[] = "ERROR - $key is required"; } } // no errors if(empty($err)) { for($i = 0; $i < count($_POST["other"]); $i++) $native = mysql_real_escape_string($_POST['native'][$i]); $other = mysql_real_escape_string($_POST['other'][$i]); $other_list = mysql_real_escape_string($_POST['other_list'][$i]); $other_read = mysql_real_escape_string($_POST['other_read'][$i]); $other_spokint = mysql_real_escape_string($_POST['other_spokint'][$i]); $other_spokprod = mysql_real_escape_string($_POST['other_spokprod'][$i]); $other_writ = mysql_real_escape_string($_POST['other_writ'][$i]); // insert into the database $the_query = sprintf("INSERT INTO `language` (`user_id`,`native`,`other`,`other_list`,`other_read`, `other_spokint` ,`other_spokprod`,`other_writ` ) VALUES ('%d','%s','%s','%s','%s','%s','%s','%s')", $user_id,$native,$other,$other_list,$other_read, $other_spokint,$other_spokprod,$other_writ); // query is ok? if (mysql_query($the_query, $link) ){ // redirect to user profile header('Location: myaccount.php?id=' . $user_id); } } } }

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• Textbox auto generate by php and html

  - by user2892997

  i have few field of data such as product , amount and barcode.The system just show 1 row of data insert form that contain the 3 field.when i completed insert the first row, then second row of textbox will auto generate, i can do it by microsoft access, can i do so for php ? <?php $i=0; ?> <form method="post" action=""> <input type="text" name="<?php echo $i; ?>" /> </form> <?php if(isset($_POST[$i])){ $i++; ?> <form method="post" action=""> <input type="text" name="<?php echo $i; ?>" /> </form> <?php }?> it work for the first and second textbox, but how can i continue to create more textbox accordingly?

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• Sort the $_POST variables

  - by Jerry

  Hello guys Might be an easy for you guys. I am trying to sort the $_POST variables that were sent by a form and update the sorted result in mysql. I am not sure how to do it and appreciate it anyone can help me about it. My main.php //I have a loop here. (omitted) //$k will be increased by 1 every time the loop starts, so I will know the total times of the loops //the form will be submitted to update.php echo "<input type='hidden' name='pickTotal' value='".$k."' />"; echo "<input type='hidden' id='point' name='earnedPoint".$k."' value='".$point."' />"; echo "<input type='hidden' id='users' name='userName".$k."' value='".$userPick['user']."' />"; //loop ends My update.php if(isset($_POST['submit'])){ $pickTotal=$_POST['pickTotal']; //get the total loop for ($p=0;$p<=$pickTotal;$p++){ $userToBeUpdated=$_POST['userName'.$p]; $userPoint=$_POST['earnedPoint'.$p]; //sort the $userPoint here. //I need to find out who got the most points //and list user's place. 1st, 2nd, 3rd...etc. //update my mysql } Thanks for any helps.

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• Why does this sql statement keep saying it is a boolean and not a parameter? (php/Mysql)

  - by ggfan

  In this statement, I am trying to see if there if the latest posting in the database that has the exact same title, price, city, state, detail. If there is, then it would say to the user that the exact post has been already made; if not then insert the posting into the dbc. (This is one type of check so that users can't accidentally post twice. This may not be the best check, but this statement error is annoying me, so I want it to work :)) Why won't this sql work? I think it's not letting the title=$title and not getting the value in the $title... ERROR: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in postad.php on line 365 //there is a form that users fill out that has title, price, city, etc <form> blah blah </form> //if users click submit, then does all the checks and if all okay, insert to dbc if (isset($_POST['submit'])) { // Grab the pposting data from the POST and gets rid of any funny stuff $title = mysqli_real_escape_string($dbc, trim($_POST['title'])); $price = mysqli_real_escape_string($dbc, trim($_POST['price'])); $city = mysqli_real_escape_string($dbc, trim($_POST['city'])); $state = mysqli_real_escape_string($dbc, trim($_POST['state'])); $detail = mysqli_real_escape_string($dbc, trim($_POST['detail'])); if (!is_numeric($price) && !empty($price)) { echo "<p class='error'>The price can only be numbers. No special characters, etc</p>"; } //Error problem...won't let me set title=$title, detail=$detail, etc. //this statement after all the checks so that none of the variables are empty $query="Select * FROM posting WHERE user_id={$_SESSION['user_id']} AND title=$title AND price=$price AND city=$city AND state=$state AND detail=$detail"; $data = mysqli_query($dbc, $query); if(mysqli_num_rows($data)==1) { echo "You already posted this ad. Most likely caused by refreshing too many times."; } }

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• detect click on submit button in PHP

  - by Remus Rigo

  hi all I have a php file that contains a form (witch contains 2 input boxes and a submit button) for updating a contact. I managed to fill the fields with the contact's data, but I can't detect if the submit button is clicked form looks like this echo "<form action=Contact.php><table>". "<tr><td>First Name</td><td><input type=text size=75% name=FirstName value='".$row['FirstName']."'></td></tr>". "<tr><td>Last Name</td><td><input type=text size=75% name=LastName value='".$row['LastName']."'></td></tr>". "<tr><td colspan=2><input type=submit name=UpdateContact value=Update></td></tr>". "</table></form>"; this code should output a "clicked" message if the button is clicked if (isset($_POST['UpdateContact'])) { echo "<p>clicked"; } else { echo "<p>not clicked"; } can anyone help me out or tell me what i've done wrong (I want from the same php file to fill the contact's data in a from and to update the database)

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• Help to Understand PHP Code into C#

  - by user342944

  Hi Gurus, I am a C# guy and got this logic into php from a website. Need to implement the same in C#. $items = array(); while($row = mysql_fetch_assoc($query)) { //parent id $pkey = $row['parent_id']; //child id $ckey = $row['category_id']; //store this $items[$pkey]['children'][$ckey] = $row['categoryname']; } //create our list $first = true; //create our list createList($items, $first); function createList($array, $first) { //we need access to the original array global $items; //first is a flag on whether or not this is the first item in the array //we use this flag so that you don't need to initially call the function using createList($array[0]['children']) if($first){ $array = $array[0]['children']; } echo "<ol>\n"; foreach($array as $key => $value){ echo "<li>{$value}"; //if this item does have children, display them if(isset($items[$key]['children'])){ echo "\n"; createList($items[$key]['children'], false); //set $first to false! } echo "</li>\n"; } echo "</ol>\n"; } In the above last line is it a 3 dimensional array or hashtable? it looks like its a hashtable cause [$pkey]['children'][$ckey] is bugging me.. Can anyone convert the above code in C#? I would really appreciate.

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