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  • Symfony on virtual host (document root problem)

    - by Martin Sikora
    Hello, I'm developing an application in Symfony and on localhost (XAMPP) I want to simulate the same conditions as on the webserver. The web server is configured as follows: /www => mydomain.com /foo => foo.mydomain.com /bar => bar.mydomain.com ... I'm going to put my Symfony application into /www direcotry so there'll be: /www /www/apps /www/apps/frontend /www/apps/frontend/... /www/apps/backend /www/apps/backend/... /www/cache /www/config ... and so on... /www/web The thing is that the document root is still set to the /www directory but Symfony expects it in the /www/web. Of course it will work if I call http://mydomain.com/web but I guess you understand this is quiet stupid solution. So my question is: Is there any way how can I change/bypass the default document root setting using .htaccess or whatever?

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  • Setting the size of a silverlight window at runtime automatically?

    - by dilbert789
    I need to be able to change the size of my Silverlight object at run time because I have content that changes in size dramatically between pages, and I'd rather not show a Silverlight scroll bar inside the browser scroll bar. I was able to do the following to get it to work: In the aspx page hosting the silverlight control: - Set your Div to the starting size you need it to be - Set the Silverlight Obejct to width=”100%” height=”100%” In your Main page add this: public static void ChangeSize(string height) { var myDiv = HtmlPage.Plugin.Parent; while (myDiv.TagName != "div") myDiv = myDiv.Parent; myDiv.SetStyleAttribute("height", height); } Anywhere you want to now change the size of the page do this: string newHeight = (App.Current.Host.Content.ActualHeight + 75).ToString(); MainPage.ChangeSize(newHeight + "px"); //App.Current.Host.Content.ActualHeight will get the current actual height of the object Is there a way that I can set this to re-size automatically so that I do not have to specify the amount to change? Currently using SL 2, interested in if there is another way in a different version though.

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  • Selecting dictionary items by key efficiently in Python

    - by user248237
    suppose I have a dictionary whose keys are strings. How can I efficiently make a new dictionary from that which contains only the keys present in some list? for example: # a dictionary mapping strings to stuff mydict = {'quux': ..., 'bar': ..., 'foo': ...} # list of keys to be selected from mydict keys_to_select = ['foo', 'bar', ...] The way I came up with is: filtered_mydict = [mydict[k] for k in mydict.keys() \ if k in keys_to_select] but I think this is highly inefficient because: (1) it requires enumerating the keys with keys(), (2) it requires looking up k in keys_to_select each time. at least one of these can be avoided, I would think. any ideas? I can use scipy/numpy too if needed.

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  • Question about r-value in C++0x

    - by Goofy
    Rvalues IMHO are great improvement in C++, but at the beginning the're seems quite. Please look at code below: #include <string> std::string && foo (void) { std::string message ("Hello!"); return std::move (message); } void bar (const std::string &message2) { if (message == "Bye Bye!") return; } int main () { bar (foo ()); } Reference message2 is last owner of original message object returned by foo(), right?

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  • An array of structures in C...

    - by 00010000
    For the life of me I can't figure out the proper syntax for creating an array of structures in C. I tried this: struct foo { int x; int y; } foo[][] = { { { 1, 2 }, { 4, 5 }, { -1, -1 } }, { { 55, 44 } { 100, 200 }, } }; So for example foo[1][0].x == 100, foo[0][1].y == 5, etc. But GCC spits out a lot of errors. If anyone could provide the proper syntax that'd be great. EDIT: Okay, I tried this: struct foo { const char *x; int y; }; struct foo bar[2][] = { { { "A", 1 }, { "B", 2 }, { NULL, -1 }, }, { { "AA", 11 }, { "BB", 22 }, { NULL, -1 }, }, { { "ZZ", 11 }, { "YY", 22 }, { NULL, -1 }, }, { { "XX", 11 }, { "UU", 22 }, { NULL, -1 }, }, }; But GCC gives me "elements of array bar have incomplete type" and "excess elements in array initializer".

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  • How place a link below a picture that is displayed using fancybox (jquery)?

    - by janoChen
    In the first picture of my website (the two persons), shows an URL address when you click on it. I used the "title" thing. Is there a simple way of doing the same but placing a link instead? code: <div class="pusher"> <h3><?php echo l('showcase1_h3'); ?></h3> <p><?php echo l('showcase1_p'); ?></p> <div class="pic"> <a id="showcase1" title="studyatbest.com" href="images/showcase1.png"><img src="images/showcase1t.png"/></a> </div> </div> http://alexchen.co.nr/

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  • Problem in to navigate on UITableView on the UIButtonClick which is present in UITabBarController sc

    - by Rajendra Bhole
    Hi, I develop an application in which i want to on UIButton Click the application navigate on UITableViewcontroller class.The UIButton is already on UITabBarController during the navigation the tab bar should be visible.The calling method in first tab bar controller class is, [appDelegate.nvcHome pushViewController:itemMenuTable animated:YES]; [itemMenuTable release]; itemMenuTable = nil; But it given me the following problem in GDB, Application tried to push a nil view controller on target . Also i want to display the icon and title of UITabBarController in programmatically, the code is, homeViewControllerLink = [[homeViewController alloc]initWithNibName:@"homeViewController" bundle:nil]; nvcHome = [[UINavigationController alloc]initWithRootViewController:homeViewControllerLink]; nvcHome.navigationBar.barStyle = UIStatusBarStyleBlackOpaque; UIImage *imgHomeTab = [UIImage imageNamed:@"home"]; [nvcHome.tabBarItem initWithTitle:@"Home" image:imgHomeTab tag:101]; [homeViewControllerLink release]; But it does not display when i running my app on iphone simulator.

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  • MySQL: How to separate a name field in one table into firstname / lastname in two separate tables?

    - by Eileen
    I have a drupal database where the node table is full of profiles. The field node.title is "Firstname Lastname". I want to separate the names so that node.title = "Firstname", and over in another table entirely, content_type_profile.field_lastname_value = "Lastname". The entries in the two tables can be joined on the field nid. I'd love to run a SQL command to do this, and I am fine with taking the naive approach that the first word is the first name, and everything else in the field is last name -- it will mean a few manual corrections down the line, but that's much better than doing it all by hand in the first place. (I read this question and surely the answer lies in there but I am not that SQL-savvy and am not sure how to make it work for my database.) Thanks!

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  • Printing Script Codes.

    - by Spelljack
    I wanna print out script's codes after the output. The script goes on different ways on the way it calls. So i wanna see it when script runs. is there any function that prints all script codes as the way it writed. Example: $foo = "bar"; $foo .= " is my bar"; function foobar() { // do some stuff here } i wanna see the codes just like this. is there a way to do this? without file_get_contents(), file(), readfile() functions?

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  • rootview controller in Interface builder?

    - by senthilmuthu
    hi, i have done in didapplicationfinishing function tabBarController = [[UITabBarController alloc] init] ; tabBarController.navigationItem.title = @"News"; SimpleTableViewController *rtbfViewController = [[SimpleTableViewController alloc] init]; //initWithStyle:UITableViewStyleGrouped]; rtbfViewController.tabBarItem.title = @"News1"; rtbfViewController.tabBarItem.image = [UIImage imageNamed:@"home.png"];; UINavigationController *table2NavController = [[[UINavigationController alloc] initWithRootViewController:rtbfViewController] autorelease]; [rtbfViewController release]; it works fine .suppose if i have Navigation controller in Interface Builder,how can i set initWithRootViewController in Interface builder?

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  • using jquery $.post() for returning multiple values

    - by Aninemity
    Hi all I am trying to use a $.post() in the following way: $.post("file.php", { file_id: $(this).val()}, function(data){...} The file.php then does a database query and returns an array with a title, description and image reference. What I want to do then is be able to update the .val() for form fields for each. I understand how to do this on a single variable, it would just be the following: $.post("file.php", { file_id: $(this).val()}, function(data){ $('#title').val(data); } But, how do I get the data returned to be recognizable in jquery as either separate variables or as an array? Thanks in advance

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  • how to create a logo and graphical images [closed]

    - by priya
    hi Can you tell me how to create code for this? Insert a new logo of the company Use layout manager to place the components on the applet Insert graphical images The details of the music CDs should be stored category-wise in seperate text files. For example, classic.txt file stores the music titles of classic tracks, western.txt file stores the music title of western tracks. Display the list of the title available with the music store depending upon the category selected. The images should also change according to the selection.

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  • MS Access Can't move to a different record?

    - by user986706
    Ok, I'm really baffled. Here's the rundown: I've created a form with a subform. The main form is called FacilityInfo, and the subform is called BillingInfo. The forms are linked via 3 fields, AffiliateID, ClientID, and FacilityID. the subform shows one record at a time, set to show Continuous Forms, and AllowAdditions = No I can see that there are 4 records in the nav bar. But Access won't let me move off the first record. I've tried setting to Single Form. I've tried AllowAdditions = Yes. I do have a Vertical Scroll bar on the subform. It will allow me to scroll through the records, but I can only see them. I cannot move to one of the controls. Any ideas? I'm freakin' out! Thanks in advance!

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  • Currency Conversion and display fetched from Server

    - by user198725878
    I am fetching the in app purchase items for my app from my web server.the web-server gives the product title, description and price... Currently i am displaying the each product using the product title,description and price.Currently i am showing the currency in $. Now i am having the doubt that , can i display the prices as such?when i referred some URL, it seems that prices needs to be localized. So do i need to display the prices localized which is fetched from my-server? please let me know how should i proceed? Thanks a lot for stopping by..

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  • collapse row by row with (jQuery)

    - by Mini
    I want to hide/show a lot of contents by id Here is an example: <a href="#" class="click"> title here </a> <p class="content" id="1"> text here ... </p> <a href="#" class="click" id="2"> another title here </a> <p class="content"> another text here ... </p> I can add an ID into my HTML code. How Can I get it by jQuery? The jQuery lines: <script type="text/javascript"> $(document).ready(function(){ $('.content').hide(); $('.click').click(function() { $('.content').slideToggle(500); return false; });

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  • many-to-many relationship in CI (not using ORM)

    - by Ross
    I'm implementing a categories system in my CI app and trying to work out the best way of working with many to many relationships. I'm not using an ORM at this stage, but could use say Doctrine if necessary. Each entry may have multiple categories. I have three tables (simplified) Entries: entryID, entryName Categories: categoryID, categoryname Entry_Category: entryID, categoryID my CI code returns a record set like this: entryID, entryName, categoryID, categoryName but, as expected with Many-to-Many relationships, each "entry" is repeated for each "category". What would the best way to "group" the categories so that when I output the results, I am left with something like: Entry Name Appears in Category: Foo, Bar rather than: Entry Name Appears in Category: Foo Entry Name Appears in Category: Bar I believe the option is to track if the post ID matches a previous entry, and if so, store the respective category, and output it as one, rather than several, but am unsure of how to do this in CI. thanks for any pointers (I appreciate this is may be a vague/complex question without a better knowledge of the system).

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  • JQuery or Javascript solution for selecting default value in drop down

    - by user1446843
    I have a calender list in a webpart page, this webpart page has a version number in it's title e.g. "WebPart 1.62". What I need to do is when a New item is created in the calender list on a webpart page, the New Item form has a dropdown menu 'SystemID' which gets it's values from the title column of a 'Systems' list, which is pre-populated with all versions of webpart forms. This dropdown menu 'SystemID' should select the version of the webpart page it is in as the default value. I need a JQuery solution for this, or even Javascript. I am finding it difficult as I am new to both JQuery and Sharepoint. I am using SP2007. I'll appreciate any guidance in solving this. At the moment the Create New Item form of the Calender list has the 'SystemID' drop down list pre-populated with the versions from the Systems list. If anyhthing is unclear pls let me know and I'll explain in more detail.

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  • How do I select the most recent entry in mysql?

    - by ggfan
    i want to select the most recent entry from a table and see if that entry is exactly the same as the one the user is trying to enter. How do I do a query to "select * from the most recent entry of 'posting'"? $query="Select * FROM //confused here (SELECT * FROM posting ORDER BY date_added DESC) WHERE user_id='{$_SESSION['user_id']}' AND title='$title' AND price='$price' AND city='$city' AND state='$state' AND detail='$detail' "; $data = mysqli_query($dbc, $query); $row = mysqli_fetch_array($data); if(mysqli_num_rows($data)>0) { echo "You already posted this ad. Most likely caused by refreshing too many times."; echo "<br>"; $linkposting_id=$row['posting_id']; echo "See the <a href='ad.php?posting_id=$linkposting_id'>Ad</a>"; } else { ...insert into the dbc }

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  • Reorganized JSON

    - by couatl
    Need to be reorganized JSON into a new structure. Python. for example { 'a' : 1, 'b' : 1, 'd' : {'d1' : '1', 'd2' : 2}, 'm' : [ {'x' : 6, 'y' : 5, 'z' : {'foo' : 'foo1', 'bar : 'bar1'} }, {'x' : 8, 'y' : 8, 'z' : {'foo' : 'foo2', 'bar : 'bar2'} } ... ] } to { 'new_a' : 1, 'new_d' : {'new_d1' : '1', 'new_d2' : 2}, 'new_m' : [ {'new_x' : 6, 'new_z' : {'new_foo' : 'foo1', new_'bar : 'bar1'} }, {'new_x' : 8, 'new_z' : {'new_foo' : 'foo2', 'new_bar : 'bar2'} } ... ] } There is the idea of ??a new form of an old JSON Is there a more elegant way of that? import json new_data = {} new_data['new_a'] = old_data['a'] new_data['new_d'] = {} new_data['new_d']['new_d1'] = old_data['d']['d1'] new_data['new_d']['new_d2'] = old_data['d']['d2'] new_data['new_m'] = {} new_m = [] for m in old_data: new_m.append({'new_x' : m['x'], 'new_z' : {'new_foo' ....

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  • Omit attribute name from validation error message (at start of it)?

    - by mrbrdo
    I write code in English but I'm currently doing a site which is fully translated to another language (validation error messages included). However, I have a problem because validation error messages always seem to include the name of the attribute the error is on at the start of the error, e.g.: Title Prosimo izpolnite naziv fakultete. I want to get rid of the Title at the start, like so: Prosimo izpolnite naziv fakultete. Any help is appreciated. I would rather see if this can be solved without installing any 3rd party plugins. If it's possible to provide translations for attribute names, that would be a cool solution too, but I would still like to know how it can be done both ways (omit or translate).

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  • prettyPhoto not working in my wordpress theme

    - by codemanic
    So friends I am trying to use prettyPhoto in my wordpress theme but its not working at all. Both of its files - prettyPhoto.css and jquery.prettyPhoto.js are correctly linked in header.php file. This is the linking of the files in my header.php file - <link rel="stylesheet" href="<?php bloginfo('stylesheet_directory'); ?>/js/prettyPhoto/css/prettyPhoto.css" type="text/css" media="screen" title="prettyPhoto main stylesheet" charset="utf-8" /> <script src="<?php bloginfo('stylesheet_directory'); ?>/js/prettyPhoto/js/jquery.prettyPhoto.js" type="text/javascript"></script> Please let me know if this problem is due to not using wp_enqueue_script(). And this is how I link the image to be used with prettyPhoto - <a title="test image" href="images/new-image.png" rel="prettyPhoto[]"><img src="images/new-image.png" alt="Some Alternate Text" /></a> When I click on image, it doesn't open in prettyPhoto.

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