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  • How to track folder permission event?

    - by Sushant
    Hi, This is about folder level permissions. We have a document library with break inheritance. While adding folders, sub folders through code, again we coded for break inheritance. Now the requirement is, when a user/group is added to subfolder permission list, we need to track this event. Which sharepoint event do we use and on what level. Please help.

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  • Jquery Works in FF but not IE at all

    - by Shawn
    I set up the SimpleModal plugin to work from our Ad server(Real 24/7). Essentially, attempting to make an interstitial ad. I serve a popupAd.js file from the Ad Server to our homepage(index.php), Here is the code for popupAd.js: $(document).ready(function() { $.modal('<iframe src="/welcomeAd.htm" height="525" width="562" style="border:0;" scrolling="no"/>', { closeHTML: "<a href='#' title='Close' align='right' style='color:#666>(X) Continue to website</a>", containerCss: { backgroundColor: '#fff', borderColor: "#0063dc", height: 525, padding: 0, width: 562, }, overlayCss:{ backgroundColor:"#fff", }, opacity:100, overlayClose: true }); }); This opens a modal window on the homepage which then loads welcomeAd.htm which contain nothing other than the ad call to the creative. Here is the code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/1999/REC-html401-19991224/loose.dtd"> <html> <head> <title>Company Name</title> <!------ AD SERVER SETUP begin ------> <!------ OAS SERVER SETUP end ------> </head> <body style="margin: 0; padding: 0; width: 100%; height: 100%"> <script type="text/javascript" language="JavaScript"> <!-- AD SERVER CALL; //--> </script> </body> </html> This all works in FF but does nothing in IE, of which I am running IE7. Also, the closeHTML doesn't show up in Safari, though, the ad does.

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  • scope equivalent in rails 2.3.x?

    - by Jacob Relkin
    Is there a way to generate a group of routes under an admin scope without having to create a new physical directory (like namespace requires you to). I know that in Rails 3 there is a scope method on the route mapper, and this appears to do what I want, but apparently it doesn't exist in Rails 2.3.x My goal is to have a route like this: "/admin/products" map to "app/controllers/products_controller, not "app/controllers/admin/products_controller". Is there any way to accomplish this in Rails 2.3.x?

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  • T-SQL Subquery Question

    - by Nick
    Hi, i have two queries. For each tuple of query1 i want to run query2. i dont want to use cursors. i tried several approaches using subqueries. query1: select distinct category, Count(category) as CategoryCount from mytable group by category query2: select top 3 Text, Title, Category from mytable where Category = '1' Category = '1' is a sample. the value should come from query1

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  • Figuring out QuadCurveTo's parameters

    - by Fev
    Could you guys help me figuring out QuadCurveTo's 4 parameters , I tried to find information on http://docs.oracle.com/javafx/2/api/javafx/scene/shape/QuadCurveTo.html, but it's hard for me to understand without picture , I search on google about 'Quadratic Bezier' but it shows me more than 2 coordinates, I'm confused and blind now. I know those 4 parameters draw 2 lines to control the path , but how we know/count exactly which coordinates the object will throught by only knowing those 2 path-controller. Are there some formulas? import javafx.animation.PathTransition; import javafx.animation.PathTransition.OrientationType; import javafx.application.Application; import static javafx.application.Application.launch; import javafx.scene.Group; import javafx.scene.Scene; import javafx.scene.paint.Color; import javafx.scene.shape.MoveTo; import javafx.scene.shape.Path; import javafx.scene.shape.QuadCurveTo; import javafx.scene.shape.Rectangle; import javafx.stage.Stage; import javafx.util.Duration; public class _6 extends Application { public Rectangle r; @Override public void start(final Stage stage) { r = new Rectangle(50, 80, 80, 90); r.setFill(javafx.scene.paint.Color.ORANGE); r.setStrokeWidth(5); r.setStroke(Color.ANTIQUEWHITE); Path path = new Path(); path.getElements().add(new MoveTo(100.0f, 400.0f)); path.getElements().add(new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f)); PathTransition pt = new PathTransition(Duration.millis(1000), path); pt.setDuration(Duration.millis(10000)); pt.setNode(r); pt.setPath(path); pt.setOrientation(OrientationType.ORTHOGONAL_TO_TANGENT); pt.setCycleCount(4000); pt.setAutoReverse(true); pt.play(); stage.setScene(new Scene(new Group(r), 500, 700)); stage.show(); } public static void main(String[] args) { launch(args); } } You can find those coordinates on this new QuadCurveTo(150.0f, 60.0f, 100.0f, 20.0f) line, and below is the picture of Quadratic Bezier

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  • Can get Sum() working in Northwind example

    - by Vince
    Hi, The following code is generating a runtime error and I have no idea why. from o in Orders group o by o.Employee into employeeOrders select new { employeeOrders.Key.EmployeeID, employeeOrders.Key.FirstName, Orders = from eord in employeeOrders orderby eord.OrderID select new { eord.OrderID, eord.OrderDate, OrderTotal=eord.OrderDetails.Sum (od => od.UnitPrice) } } The error is Member access 'System.Decimal UnitPrice' of 'LINQPad.User.OrderDetails' not legal on type 'LINQPad.User.Orders Thanks in advance

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  • Magento - How to select mysql rows by max value?

    - by Damodar Bashyal
    mysql> SELECT * FROM `log_customer` WHERE `customer_id` = 224 LIMIT 0, 30; +--------+------------+-------------+---------------------+-----------+----------+ | log_id | visitor_id | customer_id | login_at | logout_at | store_id | +--------+------------+-------------+---------------------+-----------+----------+ | 817 | 50139 | 224 | 2011-03-21 23:56:56 | NULL | 1 | | 830 | 52317 | 224 | 2011-03-27 23:43:54 | NULL | 1 | | 1371 | 136549 | 224 | 2011-11-16 04:33:51 | NULL | 1 | | 1495 | 164024 | 224 | 2012-02-08 01:05:48 | NULL | 1 | | 2130 | 281854 | 224 | 2012-11-13 23:44:13 | NULL | 1 | +--------+------------+-------------+---------------------+-----------+----------+ 5 rows in set (0.00 sec) mysql> SELECT * FROM `customer_entity` WHERE `entity_id` = 224; +-----------+----------------+---------------------------+----------+---------------------+---------------------+ | entity_id | entity_type_id | email | group_id | created_at | updated_at | +-----------+----------------+---------------------------+----------+---------------------+---------------------+ | 224 | 1 | [email protected] | 3 | 2011-03-21 04:59:17 | 2012-11-13 23:46:23 | +-----------+----------------+---------------------------+----------+--------------+----------+-----------------+ 1 row in set (0.00 sec) How can i search for customers who hasn't logged in for last 10 months and their account has not been updated for last 10 months. I tried below but failed. $collection = Mage::getModel('customer/customer')->getCollection(); $collection->getSelect()->joinRight(array('l'=>'log_customer'), "customer_id=entity_id AND MAX(l.login_at) <= '" . date('Y-m-d H:i:s', strtotime('10 months ago')) . "'")->group('e.entity_id'); $collection->addAttributeToSelect('*'); $collection->addFieldToFilter('updated_at', array( 'lt' => date('Y-m-d H:i:s', strtotime('10 months ago')), 'datetime'=>true, )); $collection->addAttributeToFilter('group_id', array( 'neq' => 5, )); Above tables have one customer for reference. I have no idea how to use MAX() on joins. Thanks UPDATE: This seems returning correct data, but I would like to do magento way using resource collection, so i don't need to do load customer again on for loop. $read = Mage::getSingleton('core/resource')->getConnection('core_read'); $sql = "select * from ( select e.*,l.login_at from customer_entity as e left join log_customer as l on l.customer_id=e.entity_id group by e.entity_id order by l.login_at desc ) as l where ( l.login_at <= '".date('Y-m-d H:i:s', strtotime('10 months ago'))."' or ( l.created_at <= '".date('Y-m-d H:i:s', strtotime('10 months ago'))."' and l.login_at is NULL ) ) and group_id != 5"; $result = $read->fetchAll($sql); I have loaded full shell script to github https://github.com/dbashyal/Magento-ecommerce-Shell-Scripts/blob/master/shell/suspendCustomers.php

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  • Equivalent of Oracle’s RowID in MySQL

    - by echo
    is there an equivalent of oracle's rowid in mysql? delete from my_table where rowid not in (select max(rowid) from my_table group by field1,field2) I want to make a mysql equivalent of this query!!! What i'm trying to do is, : The my_table has no primary key.. i'm trying to delete the duplicate values and impose a primary key (composite of field1, field2)..!!

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  • mysql :ordering table with day names

    - by Meko
    Hi.I am trying to get day of names with and correct order like Monday ,Tuesday.. But in my table I have records that after Monday comes Friday or I have Thursday between two Tuesday .I want to order them like Monday ,Monday ,Tuesday ,Tuesday, Wednesday so on .But I don`t want to group them. I used this query but it does not make order select Day_Name from mydb.schedule where Room_NO=(510) And Week_NO =(1) it outputs Monday Monday Tuesday Wednesday Wednesday Tuesday Thursday Thursday Thursday how can I correct it?

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  • Mysql select most frequent and sort alphabetically

    - by user2605793
    I am trying to select the most common 100 names from a table then display the list showing the names and count. I want the user to be able to re-sort the list alphabetically rather than based on count. I thought the following code would do it. It works for the default sort by count but fails on the sort alphabetically. The line "$count = mysql_num_rows($table);" gives an error: mysql_num_rows() expects parameter 1 to be resource, boolean given. Any help would be greatly appreciated. // Get most popular surnames echo '<h2>Most Common Surnames</h2>'; if ($sort == "") { // default sort by count echo '<a href="http://mysite/names.php?id='.$id.'&sort=name">Sort by name</a><br>'; $query = "SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100"; } else { // sort alphabetically echo '<a href="http://mysite/names.php?id='.$id.'">Sort by count</a><br>'; $query = "SELECT * FROM ( SELECT family_name, COUNT(*) as count FROM namefile WHERE record_key = $id GROUP BY family_name ORDER BY count DESC LIMIT 100) AS alpha ORDER BY family_name"; } $table = mysql_query($query); $count = mysql_num_rows($table); $tot = 0; $i = 0; echo '<table><tr>'; while ($tot < $count2) { $rec2 = mysql_fetch_array($table2); echo '<td>'.$rec2[0].'</td><td>'.$rec2[1].'</td><td width="40">&nbsp;</td><td>'; if ($i++ == 6) { echo '</tr><tr>'; $i = 0; } $tot++; } echo '</tr></table><br>'; UPDATE: I needed to add "AS alpha" to give the outer select a unique name. (alpha is just a random name I made up.) It now works perfectly. Code updated for the benefit of any others who need something similar.

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  • Leading a Developer Meeting?

    - by hypoxide
    I've recently inherited responsibility for organizing and running the hour long monthly developer meetings at my office. I've only been out of college for 2 years so I'm kind of intimidated by holding the reins for this type of thing. The group is composed of about 20 developers, more than half of which are significantly more senior than I am. I need some tips on how to make this meeting valuable for everybody, as well as any possible advice/consolation/condolences you can give me.

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  • Doubt in stored procedure in asp.net

    - by Surya sasidhar
    hi, i am writing a sotreprocedure displaying month and year it is working but it is not coming in a order descending order can u help me my procedure like below... ALTER procedure [dbo].[audioblog_getarchivedates] as begin select DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) as ArchiveDate from audio_blog a group by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) order by DateName(Month,a.createddate) + ' ' + DateName(Year,a.createddate) desc end result will come like this March 2010 January 2010 February 2010 but it is not in a order (desc) can u help me

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  • How to enumerate returned rows in SQL?

    - by SilentGhost
    I was wondering if it would be possible to enumerate returned rows. Not according to any column content but just yielding a sequential integer index. E.g. select ?, count(*) as usercount from users group by age would return something along the lines: 1 12 2 78 3 4 4 42

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  • checkboxes jquery

    - by mazhar
    <% foreach (var i in (IEnumerable)ViewData["Group"]) { % " / <%= i.vcr_GroupName % <% foreach (var ik in (IEnumerable)ViewData["Feature"]) { % " / <%= ik.vcr_FeaturesName % <% } % <% } % I have created this now the thing is that when I click on any parent with parentid=0 .all its child should automatically be clicked with parentid 0 but not viceversa.How would I do it in jquery? (Like i CLICK ON SOME FEATURE Manage User its child Add user ,edit and delete user should be clicked automatically ) but if i click on add user nothing should happened

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  • check all values match using prototype

    - by snaken
    Using prototype, is there a simple method of checking that a group of values match, for example - can this code be refined to a single line or something otherwise more elegant? var val = ''; var fail = false; $('form').select('.class').each(function(e){ if(!val){ val = $F(e); }else{ if(val != $F(e)) fail = true; } });

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  • Dealing with whitespace in SVN?

    - by Eric the Red
    All of the SVN shops I've worked in have a strict rule - replace all tabs with spaces, to avoid whitespace conflicts and variations of tabs in different editors. Is this a very common standard? Does it really make a huge difference, and is it worth the trouble to push this standard to a group of developers new to SVN?

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  • Assign query results to MySQL variable

    - by 5un5
    I'm querying a big mysql database with only read privileges, and I'd like to set some slow query results to a variable, 'foo', so I can use them again in other queries. I get, ERROR 1193 (HY000): Unknown system variable '$foo' when I enter: set $foo := (select * from table1 join table2 where bar = 0 group by id); Is there a way to do this with variables, since I don't have privileges to create temporary tables?

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  • Senior programming 'guru' who can't program - should I find a different career?

    - by confess
    Background: According to my resume I'm supposed to be pretty good at programming. I've worked on a ton of big projects at big companies over many years. When I go for an interview and someone looks at my resume they immediately assume I really know what I'm talking about. I generally communicate well, present myself well, know the 'jargon' and know a lot about technology at a high level, which makes matters worse because after talking to me for a while an interviewer really believes that what my resume says is probably true. The Problem: The problem arises when someone asks me to code something. I choke. As a programmer I have almost no capacity to come up with creative solutions of my own. I can't think through solutions to a programming problem the way good programmers are usually able to. I read questions on StackOverflow and the answer is obvious to me after I read other people's answers but if I am the first person to look at a question with no hints from anyone else I usually don't know where to start. At work it's the same thing. I'm fine if I'm correcting other people's code. I can identify the source of a bug quicker than anyone I work with. But if you ask me to sit down and code up a new application from scratch I will spend ten times longer than programmers who are much more junior than me. Question: Now that I am looking for work this is raising its ugly head in interview situations and making me feel desperately that I'm in the wrong career. I don't know if this problem is incompetence, laziness or some combination of these. Does anyone have any ideas about what I might be dealing with - are there books or exercises that could help me with this basic problem?

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  • What is the result of this SQL query?

    - by Martin
    I'm working on a mock exam paper at the moment, however I have no set of correct answers and I'm not sure what the correct answer of this SQL query is. Given a table: foo, bar a , 1 b , 3 a , 2 c , 1 and the query: SELECT foo, sum(bar) FROM table GROUP BY foo The two ways I can see this going are either: a 3 a 3 b 3 c 1 or a 3 b 3 c 1 Thanks.

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  • Selecting from a Large Table SQL 2005

    - by Eugene
    I have a SQL table it has more than 1000000 rows, and I need to select with the query as you can see below: SELECT DISTINCT TOP (200) COUNT(1) AS COUNT, KEYWORD FROM QUERIES WITH(NOLOCK) WHERE KEYWORD LIKE '%Something%' GROUP BY KEYWORD ORDER BY 'COUNT' DESC Could you please tell me how can I optimize it to speed up the execution process? Thank you for useful answers.

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  • WPF separator between grid buttons

    - by Bob
    I have a grid with 4 buttons...1 row, 4 columns. I am looking for a way to visually group the two buttons on the left from the two on the right. I was looking for a way to do this with a separator but it doesnt seem to be playing nice with Grid, preferring StackPanel. Is this the right control? If so, how does one make the thing separate the columns (populated with buttons in this case)? Thanks.

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