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  • Type or namespace could not be found

    - by Jason Shultz
    I'm using LINQ to SQL to connect my database to my home page. I created my datacontext (named businessModel.dbml) In it I have two tables named Category and Business. In home controller I reference the model and attempt to return to the view the table: var dataContext = new businessModelDataContext(); var business = from b in dataContext.Businesses select b; ViewData["WelcomeMessage"] = "Welcome to Jerome, Arizona!"; ViewData["MottoMessage"] = "Largest Ghost Town in America!"; return View(business); and in the view I have this: <%@ Import Namespace="WelcomeToJerome.Models" %> and <% foreach (business b in (IEnumerable)ViewData.Model) { %> <li><%= b.Title %></li> <% } %> Yet, in the view business is cursed with the red underline and say's that The type or namespace name 'business' could not be found (are you missing a using directive or an assembly reference?) What am I doing wrong? This has had me stumped all afternoon. link to all the code in pastebin: http://pastebin.com/es4RnS2q

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  • How should I organize my mvc templates?

    - by CatZ
    Hi, In the new version of MVC we have been given display and editor templates. I was wondering how to make the best possible use of these. I was at first thinking in the line of creating one for a collection and one for an item in the case I want to display either as a list or single but it does not really make sense to me. I'll show you what I mean and please comment if this is wrong. I have trouble figuring it out myself. <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<IEnumerable<DisplayPhoneModel>>" %> <% foreach (var item in Model){%> <%= Html.DisplayFor(x => item) %> <%}%> So in my tiny reality that would for every item in the model search for a display template for DisplayPhoneModel. That display template could then simply look like. <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl<DisplayPhoneModel>" %> <%= Html.LabelFor(x => x.PhoneType) %>&nbsp;<%= Html.LabelFor(x => x.PhoneNumber) %> So, question is if there is a better way to handle this? Am I at all on the right path?

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  • Why is my django bulk database population so slow and frequently failing?

    - by bryn
    I decided I'd like to use django's model system rather than coding raw SQL to interface with my database, but I am having a problem that surely is avoidable. My models.py contains: class Student(models.Model): student_id = models.IntegerField(unique = True) form = models.CharField(max_length = 10) preferred = models.CharField(max_length = 70) surname = models.CharField(max_length = 70) and I'm populating it by looping through a list as follows: from models import Student for id, frm, pref, sname in large_list_of_data: s = Student(student_id = id, form = frm, preferred = pref, surname = sname) s.save() I don't really want to be saving this to the database each time but I don't know another way to get django to not forget about it (I'd rather add all the rows and then do a single commit). There are two problems with the code as it stands. It's slow -- about 20 students get updated each second. It doesn't even make it through large_list_of_data, instead throwing a DatabaseError saying "unable to open database file". (Possibly because I'm using sqlite3.) My question is: How can I stop these two things from happening? I'm guessing that the root of both problems is that I've got the s.save() but I don't see a way of easily batching the students up and then saving them in one commit to the database.

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  • How do you test a command object in a grails controller integration test?

    - by egervari
    I'm new to grails. How do I test a form command object to make sure that it's working? Here's some setup code in a test. When I try to do it, I get the following exceptions: Error occurred creating command object. org.codehaus.groovy.grails.web.servlet.mvc.exceptions.ControllerExecutionException: Error occurred creating command object. at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) .... Caused by: groovy.lang.MissingPropertyException: No such property: password for class: project.user.RegistrationForm Possible solutions: password Here is my test case. As you can see, I set "password" on the params map... void testSaveWhenDataIsCorrect() { controller.params.emailAddress = "[email protected]" controller.params.password = "secret" controller.params.confirmPassword = "secret" controller.save() assertEquals "success", redirectArgs.view ... } Here's the controller action, that adds the command object as a closure parameter: def save = { RegistrationForm form -> if(form.hasErrors()) { render view: "create", model: [form: form] } else { def user = new User(form.properties) user.password = form.encryptedPassword if(user.save()) { redirect(action: "success") } else { render view: "create", model: [form: form] } } } Here's the command object itself... and note that it DOES have a "password" field... class RegistrationForm { def springSecurityService String emailAddress String password String confirmPassword String getEncryptedPassword() { springSecurityService.encodePassword(password) } static constraints = { emailAddress(blank: false, email: true) password(blank: false, size:4..10) confirmPassword(blank: false, validator: { password != confirmPassword }) } } I'm totally lost in the non-intuitive way to do controllers... Please help.

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  • [PHP] Kohana-v3 ORM parent relationship

    - by VDVLeon
    Hi all, I just started with the version 3 of the Kohana Framework. I have worked a little with the $_has_many etc. Now I have the table pages. The primary key is pageID. The table has a column called parentPageID. Now I want to make a ORM model who, when accesed like this $page->parent->find() returns the page identified by parentPageID. I have the following already: // Settings protected $_table_name = 'pages'; protected $_primary_key = 'pageID'; protected $_has_one = array( 'parent' => array( 'model' => 'page', 'foreign_key' => 'parentPageID', ), ); But that does not work, it simply returns the first page from the table. Last query says this: SELECT `pages`.* FROM `pages` ORDER BY `pages`.`pageID` ASC LIMIT 1 Does somebody know how to solve this? I know this can: $parent = $page->parent->find($page->parentPageID); but it must be and can be cleaner (I think).

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  • Linq causes collection to disappear when trying to use OrderByDescending

    - by Jeremy B.
    For background, I am using MongoDB and Rob Conery's linq driver. The code I am attempting is thus: using (var session = new Session<ContentItem>()) { var contentCollection = session.QueryCollection.Where(x => x.CreatedOn < DateTime.Now).OrderByDescending(y => y.CreatedOn).ToList(); ViewData.Model = contentCollection; } this will work on one machine, but on another machine I get back no results. To get results i have to do using (var session = new Session<ContentItem>()) { var contentCollection = session.QueryCollection.Where(x => x.CreatedOn < DateTime.Now).ToList(); ViewData.Model = contentCollection.OrderByDescending(y => y.CreatedOn).ToList(); } I have to do ToList() on both lines, or no results. If I try to chain anything it breaks. This is the same project, all dll's are locally loaded. Both machines have the same framework, versions of Visual studio and addons. the only difference is one has VisualSVN the other AnkhSVN. I can't see those causing the problem. Also, while debugging, on the machine that does not work you can see the items in the collection, and if you remove ordering all together it will work. This has got me completely stumped.

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  • How to get to the key name of a referenced entity property from an entity instance without a datastore read in google app engine?

    - by Sumeet Pareek
    Consider I have the following models - class Team(db.Model): # say I have just 5 teams name = db.StringProperty() class Player(db.Model): # say I have thousands of players name = db.StringProperty() team = db.ReferenceProperty(Team, collection_name="player_set") Key name for each Team entity = 'team_' , and for each Player entity = 'player_' By some prior arrangement I have a Team entity's (key_name, name) mapping available to me. For example (team_01, United States Of America), (team_02, Russia) etc I have to show all the players and their teams on a page. One way of doing this would be - players = Player.all().fetch(1000) # This is 1 DB read for player in players: # This will iterate 1000 times self.response.out.write(player.name) # This is obviously not a DB read self.response.out.write(player.team.name) #This is a total of 1x1000 = 1000 DB reads That is a 1001 DB reads for a silly thing. The interesting part is that when I do a db.to_dict() on players, it shows that for every player in that list there is 'name' of the player and there is the 'key_name' of the team available too. So how can I do the below ?? players = Player.all().fetch(1000) # This is 1 DB read for player in players: # This will iterate 1000 times self.response.out.write(player.name) # This is obviously not a DB read self.response.out.write(team_list[player.<SOME WAY OF GETTING TEAM KEY NAME>]) # Here 'team_list' already has (key_name, name) for all 5 teams I have been struggling with this for a long time. Have read every available documentation. I could just hug the person that can help me here :-) Disclaimer: The above problem description is not a real scenario. It is a simplified arrangement that represents my problem exactly. I have run into it in a rater complex and big GAE appication.

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  • How to populate a listview in ASP.NET 3.5 through a dataset?

    - by EasyDot
    Is it possible to populate a listview with a dataset? I have a function that returns a dataset. Why im asking this is because my SQL is quite complicated and i can't convert it to a SQLDataSource... Public Function getMessages() As DataSet Dim dSet As DataSet = New DataSet Dim da As SqlDataAdapter Dim cmd As SqlCommand Dim SQL As StringBuilder Dim connStr As StringBuilder = New StringBuilder("") connStr.AppendFormat("server={0};", ConfigurationSettings.AppSettings("USERserver").ToString()) connStr.AppendFormat("database={0};", ConfigurationSettings.AppSettings("USERdb").ToString()) connStr.AppendFormat("uid={0};", ConfigurationSettings.AppSettings("USERuid").ToString()) connStr.AppendFormat("pwd={0};", ConfigurationSettings.AppSettings("USERpwd").ToString()) Dim conn As SqlConnection = New SqlConnection(connStr.ToString()) Try SQL = New StringBuilder cmd = New SqlCommand SQL.Append("SELECT m.MESSAGE_ID, m.SYSTEM_ID, m.DATE_CREATED, m.EXPIRE_DATE, ISNULL(s.SYSTEM_DESC,'ALL SYSTEMS') AS SYSTEM_DESC, m.MESSAGE ") SQL.Append("FROM MESSAGE m ") SQL.Append("LEFT OUTER JOIN [SYSTEM] s ") SQL.Append("ON m.SYSTEM_ID = s.SYSTEM_ID ") SQL.AppendFormat("WHERE m.SYSTEM_ID IN ({0}) ", sSystems) SQL.Append("OR m.SYSTEM_ID is NULL ") SQL.Append("ORDER BY m.DATE_CREATED DESC; ") SQL.Append("SELECT mm.MESSAGE_ID, mm.MODEL_ID, m.MODEL_DESC ") SQL.Append("FROM MESSAGE_MODEL mm ") SQL.Append("JOIN MODEL m ") SQL.Append(" ON m.MODEL_ID = mm.MODEL_ID ") cmd.CommandText = SQL.ToString cmd.Connection = conn da = New SqlDataAdapter(cmd) da.Fill(dSet) dSet.Tables(0).TableName = "BASE" dSet.Tables(1).TableName = "MODEL" Return dSet Catch ev As Exception cLog.EventLog.logError(ev, cmd) Finally 'conn.Close() End Try End Function

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  • Resharper 5: How do I set the default formatting style for inline code blocks?

    - by nukefusion
    I've got a problem with the formatting of inline code blocks within the VS2010 text editor and wonder if anyone else has had similar problems and found the 'magic' setting I'm looking for. I'm working my way through tutorials in an MVC book. Whenever I add some inline code blocks to a view I want them formatted like so: <% foreach (var link in Model) { %> <a href="<%=Url.RouteUrl(link.RouteValues)%>"> <%=link.Text%> </a> <% } %> What I'm actually getting is this (auto-formatted by the IDE when I finish writing the code): <% foreach (var link in Model) { %> <a href="<%=Url.RouteUrl(link.RouteValues)%>"> <%=link.Text%> </a> <% } %> It's pretty irritating. Any ideas on how I can instruct the IDE to leave my <% % tags alone? I've been fiddling with options under "Tools - Options - Text Editor" for ages but alas am getting nowhere... Edit: I've just noticed that this is down to Resharper 5 (when I disable it the problem disappears), however I still don't know how to stop it. Any ideas?

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  • Skip HTML escape in custom label_tag helper in Rail 3

    - by tricote
    Hi, I have this nice class ErrorFormBuilder that allows me to add the error description near the corresponding field in the form view : class ErrorFormBuilder < ActionView::Helpers::FormBuilder #Adds error message directly inline to a form label #Accepts all the options normall passed to form.label as well as: # :hide_errors - true if you don't want errors displayed on this label # :additional_text - Will add additional text after the error message or after the label if no errors def label(method, text = nil, options = {}) #Check to see if text for this label has been supplied and humanize the field name if not. text = text || method.to_s.humanize #Get a reference to the model object object = @template.instance_variable_get("@#{@object_name}") #Make sure we have an object and we're not told to hide errors for this label unless object.nil? || options[:hide_errors] #Check if there are any errors for this field in the model errors = object.errors.on(method.to_sym) if errors #Generate the label using the text as well as the error message wrapped in a span with error class text += " <br/><span class=\"error\">#{errors.is_a?(Array) ? errors.first : errors}</span>" end end #Add any additional text that might be needed on the label text += " #{options[:additional_text]}" if options[:additional_text] #Finally hand off to super to deal with the display of the label super(method, text, options) end end But the HTML : text += " <br/><span class=\"error\">#{errors.is_a?(Array) ? errors.first : errors}</span>" is escaped by default in the view... I tried to add the {:escape = false} option : super(method, text, options.merge({:escape => false})) without success Is there any way to bypass this behavior ? Thanks

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  • Entity Framework 4 and SQL Compact 4: How to generate database?

    - by David Veeneman
    I am developing an app with Entity Framework 4 and SQL Compact 4, using a Model First approach. I have created my EDM, and now I want to generate a SQL Compact 4.0 database to act as a data store for the model. I bring up the Generate Database Wizard and click the New Connection button to create a connection for the generated file. The Choose Data Source dialog appears, but SQL Compact 4.0 is not listed in the list of available data sources: I am running VS 2010 SP1 (beta) and I have installed the VS 2010 Tools for SQL Compact 4.0. I can create a SQL Compact 4.0 data connection from the Server Explorer. It is only in the Generate Database Wizard that the 4.0 option doesn't appear. BTW, my SQL Compact 4.0 installation does include System.Data.SqlServerCe.Entity.dll. So I should have the SQL Compact components I need. Am I doing something incorrectly, or is this a bug? Does anyone have a fix or a workaround? Thanks for your help.

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  • Silverlight Data Binding for Collection in Stack Panel

    - by Blake Blackwell
    I'm new to Silverlight, so I don't have a complete grasp of all the controls at my disposal. What I would like to do is use databinding and a view model to maintain a collection of items. Here is some mock code for what I'd like to do: Model public class MyItem { public string DisplayText { get; set; } public bool Enabled { get; set; } } ViewModel public class MyViewModel : INotifyPropertyChanged { private ObservableCollection<MyItem> _myItems = new ObservableCollection<MyItem>(); public ObservableCollection<MyItem> MyItems { get { return _myItems; } set { _myItems = value NotifyPropertyChanged(this, "MyItems"); } } } View <Grid x:Name="LayoutRoot" Background="White"> <StackPanel ItemsSource="{Binding MyItems}"> <StackPanel Orientation="Horizontal"> <CheckBox "{Binding Enabled, Mode=TwoWay}"></CheckBox> <TextBlock Text="{Binding DisplayText, Mode=TwoWay}" /> </StackPanel> </StackPanel> </Grid> So my end goal would be that every time I add another MyItem to the MyItems collection it would create a new StackPanel with checkbox and textblock. I don't have to use a stack panel but just thought I'd use that for this sample.

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  • Comparison operators not supported for type IList when Paging data in Linq to Sql

    - by Dan
    I can understand what the error is saying - it can't compare a list. Not a problem, other than the fact that I don't know how to not have it compare a list when I want to page through a model with a list as a property. My Model: Event : IEvent int Id string Title // Other stuff.. LazyList<EventDate> Dates // The "problem" property Method which pages the data (truncated): public JsonResult JsonEventList(int skip, int take) { var query = _eventService.GetEvents(); // Do some filtering, then page data.. query = query.Skip(skip).Take(take); return Json(query.ToArray()); } As I said, the above is truncated quite a bit, leaving only the main point of the function: filter, page and return JSON'd data. The exception occurs when I enumerate (.ToArray()). The Event object is really only used to list the common objects of all the event types (Meetings, Birthdays, etc - for example). It still implements IEvent like the other types, so I can't just remove the LazyList<EventDate> Dates' property unless I no longer implementIEvent` Anyway, is there a way to avoid this? I don't really want to compare a LazyList when I page, but I do not know how to resolve this issue. Thank you in advance! :)

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  • Keeping dates in order when using date_select and discarding year in Rails?

    - by MikeH
    My app has users who have seasonal products. When a user selects a product, we allow him to also select the product's season. We accomplish this by letting him select a start date and an end date for each product. We're using date_select to generate two sets of drop-downs: one for the start date and one for the end date. Including years doesn't make sense for our model. So we're using the option: discard_year => true To explain our problem, consider that our products are apples. Vendor X carries apples every year from September to January. Years are irrelevant here, and that's why we're using discard_year => true. However, while the specific years are irrelevant, the relative point in time from the start date to the end date is relevant. This is where our problem arises. When you use discard_year => true, Rails does set a year in the database, it just doesn't appear in the views. Rails sets all the years to 0001 in our app. Going back to our apple example, this means that the database now thinks the user has selected September 0001 to January 0001. This is a problem for us for a number of reasons. To solve this, the logic that I need to implement is the following: - If season_start month/date is before season_end month/date, then standard Rails approach is fine. - But, if season_start month/date is AFTER season_end month/date, then I need to dynamically update the database field such that the year for season_end is equal to the year for season_start + 1. My best guess is that I would create a custom method that runs as an after_save or after_update in my products model. But I'm not really sure how to do this. Ideas? Anybody ever had this issue? Thanks!

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  • Custom Django Field is deciding to work as ForiegnKey for no reason

    - by Joe Simpson
    Hi, i'm making a custom field in Django. There's a problem while trying to save it, it's supposed to save values like this 'user 5' and 'status 9' but instead in the database these fields show up as just the number. Here is the code for the field: def find_key(dic, val): return [k for k, v in dic.items() if v == val][0] class ConnectionField(models.TextField): __metaclass__ = models.SubfieldBase serialize = False description = 'Provides a connection for an object like User, Page, Group etc.' def to_python(self, value): if type(value) != unicode: return value value = value.split(" ") if value[0] == "user": return User.objects.get(pk=value[1]) else: from social.models import connections return get_object_or_404(connections[value[0]], pk=value[1]) def get_prep_value(self, value): from social.models import connections print value, "prep" if type(value) == User: return "user %s" % str(value.pk) elif type(value) in connections.values(): o= "%s %s" % (find_key(connections, type(value)), str(value.pk)) print o, "return" return o else: print "CONNECTION ERROR!" raise TypeError("Value is not connectable!") Connection is just a dictionary with the "status" text linked up to the model for a StatusUpdate. I'm saving a model like this which is causing the issue: Relationship.objects.get_or_create(type="feedback",from_user=request.user,to_user=item) Please can someone help, Many Thanks Joe *_*

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  • How to highlight the new created file in JTree

    - by newbie123
    I want to make it like when I click a button, it will create a new file. Then the jTree will highlight the new file. Below are my code. Currently I create new file, i will show the new file but no highlight the file. class FileTreeModel implements TreeModel { private FileNode root; public FileTreeModel(String directory) { root = new FileNode(directory); } public Object getRoot() { return root; } public Object getChild(Object parent, int index) { FileNode parentNode = (FileNode) parent; return new FileNode(parentNode, parentNode.listFiles()[index].getName()); } public int getChildCount(Object parent) { FileNode parentNode = (FileNode) parent; if (parent == null || !parentNode.isDirectory() || parentNode.listFiles() == null) { return 0; } return parentNode.listFiles().length; } public boolean isLeaf(Object node) { return (getChildCount(node) == 0); } public int getIndexOfChild(Object parent, Object child) { FileNode parentNode = (FileNode) parent; FileNode childNode = (FileNode) child; return Arrays.asList(parentNode.list()).indexOf(childNode.getName()); } public void valueForPathChanged(TreePath path, Object newValue) { } public void addTreeModelListener(TreeModelListener l) { } public void removeTreeModelListener(TreeModelListener l) { } } class FileNode extends java.io.File { public FileNode(String directory) { super(directory); } public FileNode(FileNode parent, String child) { super(parent, child); } @Override public String toString() { return getName(); } } jTree = new JTree(); jTree.setBounds(new Rectangle(164, 66, 180, 421)); jTree.setBackground(SystemColor.inactiveCaptionBorder); jTree.setBorder(BorderFactory.createTitledBorder(null, "", TitledBorder.LEADING, TitledBorder.TOP, new Font("Arial", Font.BOLD, 12), new Color(0, 0, 0))); FileTreeModel model = new FileTreeModel(root); jTree.setRootVisible(false); jTree.setModel(model); expandAll(jTree); public void expandAll(JTree tree) { int row = 0; while (row < tree.getRowCount()) { tree.expandRow(row); row++; } }

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  • reshaping a data frame into long format in R

    - by user1773115
    I'm struggling with a reshape in R. I have 2 types of error (err and rel_err) that have been calculated for 3 different models. This gives me a total of 6 error variables (i.e. err_1, err_2, err_3, rel_err_1, rel_err_2, and rel_err_3). For each of these types of error I have 3 different types of predivtive validity tests (ie random holdouts, backcast, forecast). I would like to make my data set long so I keep the 4 types of test long while also making the two error measurements long. So in the end I will have one variable called err and one called rel_err as well as an id variable for what model the error corresponds to (1,2,or 3) Here is my data right now: iter err_1 rel_err_1 err_2 rel_err_2 err_3 rel_err_3 test_type 1 -0.09385732 -0.2235443 -0.1216982 -0.2898543 -0.1058366 -0.2520759 random 1 0.16141630 0.8575728 0.1418732 0.7537442 0.1584816 0.8419816 back 1 0.16376930 0.8700738 0.1431505 0.7605302 0.1596502 0.8481901 front 1 0.14345986 0.6765194 0.1213689 0.5723444 0.1374676 0.6482615 random 1 0.15890059 0.7435382 0.1589823 0.7439204 0.1608709 0.7527580 back 1 0.14412360 0.6743928 0.1442039 0.6747684 0.1463520 0.6848202 front and here is what I would like it to look like: iter model err rel_err test_type 1 1 -0.09385732 (#'s) random 1 2 -0.1216982 (#'s) random 1 3 -0.1216982 (#'s) random and on... I've tried playing around with the syntax but can't quite figure out what to put for the time.varying argument Thanks very much for any help you can offer.

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  • Django 1.1 template question

    - by Bovril
    Hi All, I'm a little stuck trying to get my head around a django template. I have 2 objects, a cluster and a node I would like a simple page that lists... [Cluster 1] [associated node 1] [associated node 2] [associated node 3] [Cluster 2] [associated node 4] [associated node 5] [associated node 6] I've been using Django for about 2 days so if i've missed the point, please be gentle :) Models - class Node(models.Model): name = models.CharField(max_length=30) description = models.TextField() cluster = models.ForeignKey(Cluster) def __unicode__(self): return self.name class Cluster(models.Model): name = models.CharField(max_length=30) description = models.TextField() def __unicode__(self): return self.name Views - def DSAList(request): clusterlist = Cluster.objects.all() nodelist = Node.objects.all() t = loader.get_template('dsalist.html') v = Context({ 'CLUSTERLIST' : clusterlist, 'NODELIST' : nodelist, }) return HttpResponse(t.render(v)) Template - <body> <TABLE> {% for cluster in CLUSTERLIST %} <tr> <TD>{{ cluster.name }}</TD> {% for node in NODELIST %} {% if node.cluster.id == cluster.id %} <tr> <TD>{{ node.name }}</TD> </tr> {% endif %} {% endfor %} </tr> {% endfor %} </TABLE> </body> Any ideas ?

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  • Easiest way to specify the selected option to a dropdown list in ASP.NET MVC

    - by sdr
    I have a list of options (IEnumerable< SelectListItem ) in my model that I want to use in multiple dropdowns in my view. But each of these dropdowns could have a different selected option. Is there an easy way to simply specfiy which should be selected if using the Html.DropDownList helper? At this point, the only way I can see is to generate the html myself and loop through the list of options like so: <% for(int i=0; i<10; i++) { %> <select name="myDropDown<%= i %>"> <% foreach(var option in Model.Options) { %> <option value="<%= Html.Encode(option.optValue) %>" <%if(ShouldBeSelected(i)) {%> selected="selected"<% } %>><%= Html.Encode(option.optText) %></option> <% } %> </select> <% } %>

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  • How to generate a monotone MART ROC in R?

    - by user1521587
    I am using R and applying MART (Alg. for multiple additive regression trees) on a training set to build prediction models. When I look at the ROC curve, it is not monotone. I would be grateful if someone can help me with how I should fix this. I am guessing the issue is that initially, MART generates n trees and if these trees are not the same for all the models I am building, the results will not be comparable. Here are the steps I take: 1) Fix the false-negative cost, c_fn. Let cost = c(0, 1, c_fn, 0). 2) use the following line to build the mart model: mart(x, y, lx, martmode='class', niter=2000, cost.mtx=cost) where x is the matrix of training set variables, y is the observation matrix, lx is the matrix which specifies which of the variables in x is numerical, which one categorical. 3) I predict the test set observations using the mart model found in step 2 using this line: y_pred = martpred(x_test, probs=T) 4) I compute the false-positive and false-negative errors as follows: t = 1/(1+c_fn) %threshold based on Bayes optimal rule where c_fp=1 and c_fn. p_0 = length(which(y_test==1))/dim(y_test)[1] p_01 = sum(1*(y_pred[,2]t & y_test==0))/dim(y_test)[1] p_11 = sum(1*(y_pred[,2]t & y_test==1))/dim(y_test)[1] p_fp = p_01/(1-p_0) p_tp = p_11/p_0 5) repeat step 1-4 for a new false-negative cost.

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  • Rails runner command not saving to cache

    - by mark
    Hi I'm having a bit of a problem with a cron task generated by rails whenever plugin that should store remote data in the rails cache for display. What I have is this: schedule.rb set :path, '/var/www/apps/tuexplore/current' every 1.hour do runner "Weather.cache_remote", :environment => :production end calls this model class Weather def self.cache_remote Rails.cache.write('weather_data', Net::HTTP.get_response(URI.parse(WEATHER_URL)).body) end end Calling whenever returns this PATH=/usr/local/sbin:/usr/local/bin:/usr/sbin:/usr/bin:/sbin:/bin:/usr/games:/home/deploy/.gem/ruby/1.8/bin 0 * * * * /var/www/apps/tuexplore/current/script/runner -e production "Weather.cache_remote" This doesn't work. Calling the weather model method from a controller works fine, but I need to schedule it hourly. The cron task causes a "Cache write: weather_data" entry to appear in the production log but data isn't stored nor output into the page. Additional information, I can log into production console and run Weather.cache_remote, then read the data from the rails cache. I'd be really appreciative if someone could point out the error of my ways. If further explanation is needed please ask. Thanks in advance for any pointers.

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  • How can I perform this query between related tables without using UNION?

    - by jeremy
    Suppose I have two separate tables that I watch to query. Both of these tables has a relation with a third table. How can I query both tables with a single, non UNION based query? I want the result of the search to rank the results by comparing a field on each table. Here's a theoretical example. I have a User table. That User can have both CDs and books. I want to find all of that user's books and CDs with a single query matching a string ("awesome" in this example). A UNION based query might look like this: SELECT "book" AS model, name, ranking FROM book WHERE name LIKE 'Awesome%' UNION SELECT "cd" AS model, name, ranking FROM cd WHERE name LIKE 'Awesome%' ORDER BY ranking DESC How can I perform a query like this without the UNION? If I do a simple left join from User to Books and CDs, we end up with a total number of results equal to the number of matching cds timse the number of matching books. Is there a GROUP BY or some other way of writing the query to fix this?

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  • Extracting function declarations from a PHP file

    - by byronh
    I'm looking to create an on-site API reference for my framework and application. Basically, say I have a class file model.class.php: class Model extends Object { ... code here ... // Separates results into pages. // Returns Paginator object. final public function paginate($perpage = 10) { ... more code here ... } } and I want to be able to generate a reference that my developers can refer to quickly in order to know which functions are available to be called. They only need to see the comments directly above each function and the declaration line. Something like this (similar to a C++ header file): // Separates results into pages. // Returns Paginator object. final public function paginate($perpage = 10); I've done some research and this answer looked pretty good (using Reflection classes), however, I'm not sure how I can keep the comments in. Any ideas? EDIT: Sorry, but I want to keep the current comment formatting. Myself and the people who are working on the code hate the verbosity associated with PHPDocumentor. Not to mention a comment-rewrite of the entire project would take years, so I want to preserve just the // comments in plaintext.

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  • Rails: creating a custom data type, to use with generator classes and a bunch of questions related t

    - by Shyam
    Hi, After being productive with Rails for some weeks, I learned some tricks and got some experience with the framework. About 10 days ago, I figured out it is possible to build a custom data type for migrations by adding some code in the Table definition. Also, after learning a bit about floating points (and how evil they are) vs integers, the money gem and other possible solutions, I decided I didn't WANT to use the money gem, but instead try to learn more about programming and finding a solution myself. Some suggestions said that I should be using integers, one for the whole numbers and one for the cents. When playing in script/console, I discovered how easy it is to work with calculations and arrays. But, I am talking to much (and the reason I am, is to give some sufficient background). Right now, while playing with the scaffold generator (yes, I use it, because I like they way I can quickly set up a prototype while I am still researching my objectives), I like to use a DRY method. In my opinion, I should build a custom "object", that can hold two variables (Fixnum), one for the whole, one for the cents. In my big dream, I would be able to do the following: script/generate scaffold Cake name:string description:text cost:mycustom Where mycustom should create two integer columns (one for wholes, one for cents). Right now I could do this by doing: script/generate scaffold Cake name:string description:text cost_w:integer cost_c:integer I had also had an idea that would be creating a "cost model", which would hold two columns of integers and create a cost_id column to my scaffold. But wouldn't that be an extra table that would cause some kind of performance penalty? And wouldn't that be defy the purpose of the Cake model in the first place, because the costs are an attribute of individual Cake entries? The reason why I would want to have such a functionality because I am thinking of having multiple "costs" inside my rails application. Thank you for your feedback, comments and answers! I hope my message got through as understandable, my apologies for incorrect grammar or weird sentences as English is not my native language.

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  • Using django and django-voting app, how can I order a queryset according to the votes of each item?

    - by snz3
    (I'm new to python and django so please bear with me for a second. I apologise if this has been answered elsewhere and couldn't find it) Let's say I have a Link model and through the django-voting application users can vote on link instances. How can I order those link instances according to their score, eg. display those with the higher score first. I assume I could use the get_top manager of django-voting, but that would only give me the top scoring link instances and wouldn't take into consideration other parameters I would like to add (for example, those links that belong to a specific user or paging or whatever). My guess would be to write a custom manager for my Link model where by I can filter a queryset according to each item's score. If I understand correctly that will require me to loop through each item, check its score, and then place it a list (or dictionary) which will then be sorted according to the score of each item. That wouldn't return a queryset but a dictionary with each item. Am I missing something here?

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