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  • Chroot into a 32 bit version of ubuntu from a 64 bit host

    - by Leif Andersen
    I have a piece of software that only runs on 32 bit linux (Xilinx webPack 10.1, apperently it 'has' to be the old version because that's the latest one compatible with their boards), anyway, this version is only compatible with 32 bit linux. So, I head off to this page to see what I can do: https://help.ubuntu.com/community/32bit_and_64bit Of the 4 options (listed at the bottom): I already installed ia32-libs, and it's still not working I could do that one if needed (which I ended up doing). No, I don't want to be working from a vm all of next semester, that would be painful and I'd rather just reinstall my whole computer to a 32 bit os (which I don't want to do). It didn't sound like it was the best option based on what I've seen. So I went off to do #2, and set up a chroot for 32 bit ubuntu. It linked to this tutorial: https://help.ubuntu.com/community/DebootstrapChroot As I'm running ubuntu 10.10 I made the lucid and newer version changes. Which is to say I wrote: [hardy-i386] description=Ubuntu 8.04 Hardy for i386 directory=/srv/chroot/hardy-i386 personality=linux32 root-users=leif type=directory users=leif to /etc/schroot/chroot.d/hardy-i386 (Note though that I did save it once before I had the file properly formatted, I saved the correct version moments later though). I then ran: $ sudo mkdir -p /srv/chroot/hardy_i386 $ sudo debootstrap --variant=buildd --arch i386 hardy /srv/chroot/hardy_i386 http://archive.ubuntu.com/ubuntu/ Then I ran: $ schroot -l And it showed the proper chroot, but then when I ran: $ schroot -c hardy-i386 -u root I got the following error: E: 10mount: error: Directory '/srv/chroot/hardy-i386' does not exist E: 10mount: warning: Mount location /var/lib/schroot/mount/hardy-i386-80359697-2164-4b10-a05a-89b0f497c4f1 no longer exists; skipping unmount E: hardy-i386-80359697-2164-4b10-a05a-89b0f497c4f1: Chroot setup failed: stage=setup-start Can anyone help me figure out what the problem is? Oh, by the way: /srv/chroot/hardy-i386 most certainly exists. I've also tried it replacing all references with hardy to lucid, to no avail. Oh, one more thing, I did set up the chrome os environment a month back or so: http://www.chromium.org/chromium-os/developer-guide and it had me use something with chmod. So, can anyone figure out what the problem is? Thank you.

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  • Using Find/Replace with regular expressions inside a SSIS package

    - by jamiet
    Another one of those might-be-useful-again-one-day-so-I’ll-share-it-in-a-blog-post blog posts I am currently working on a SQL Server Integration Services (SSIS) 2012 implementation where each package contains a parameter called ETLIfcHist_ID: During normal execution this will get altered when the package is executed from the Execute Package Task however we want to make sure that at deployment-time they all have a default value of –1. Of course, they tend to get changed during development so I wanted a way of easily changing them all back to the default value. Opening up each package in turn and editing them was an option but given that we have over 40 packages and we might want to carry out this reset fairly frequently I needed a more automated method so I turned to Visual Studio’s Find/Replace… feature Of course, we don’t know what value will be in that parameter so I can’t simply search for a particular value; hence I opted to use a regular expression to identify the value to be change. In the rest of this blog post I’ll explain how to do that. For demonstration purposes I have taken the contents of a .dtsx file and stripped out everything except the element containing the parameters (<DTS:PackageParameters>), if you want to play along at home you can copy-paste the XML document below into a new XML file and open it up in Visual Studio: <?xml version="1.0"?> <DTS:Executable xmlns:DTS="www.microsoft.com/SqlServer/Dts">   <DTS:PackageParameters>     <DTS:PackageParameter       DTS:CreationName=""       DTS:DataType="3"       DTS:Description="InterfaceHistory_ID: used for Lineage"       DTS:DTSID="{635616DB-EEEE-45C8-89AA-713E25846C7E}"       DTS:ObjectName="ETLIfcHist_ID">       <DTS:Property         DTS:DataType="3"         DTS:Name="ParameterValue">VALUE_TO_BE_CHANGED</DTS:Property>     </DTS:PackageParameter>     <DTS:PackageParameter       DTS:CreationName=""       DTS:DataType="3"       DTS:Description="Some other description"       DTS:DTSID="{635616DB-EEEE-45C8-89AA-713E25845C7E}"       DTS:ObjectName="SomeOtherObjectName">       <DTS:Property         DTS:DataType="3"         DTS:Name="ParameterValue">SomeOtherValue</DTS:Property>     </DTS:PackageParameter>   </DTS:PackageParameters> </DTS:Executable> We are trying to identify the value of the parameter whose name is ETLIfcHist_ID – notice that in the XML document above that value is VALUE_TO_BE_CHANGED. The following regular expression will find the appropriate portion of the XML document: {\<DTS\:PackageParameter[\n ]*DTS\:CreationName="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:DataType="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:Description="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:DTSID="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:ObjectName="ETLIfcHist_ID"\>[\n ]*\<DTS\:Property[\n ]*DTS\:DataType="[A-Za-z0-9\:_\{\}- ]*"[\n ]*DTS\:Name="ParameterValue"\>}[A-Za-z0-9\:_\{\}- ]*{\<\/DTS\:Property\>} I have highlighted the name of the parameter that we’re looking for. I have also highlighted two portions identified by pairs of curly braces “{…}”; these are important because they pick out the two portions either side of the value I want to replace, in other words the portions highlighted here: <DTS:PackageParameters>     <DTS:PackageParameter       DTS:CreationName=""       DTS:DataType="3"       DTS:Description="InterfaceHistory_ID: used for Lineage"       DTS:DTSID="{635616DB-EEEE-45C8-89AA-713E25846C7E}"       DTS:ObjectName="ETLIfcHist_ID">       <DTS:Property         DTS:DataType="3"         DTS:Name="ParameterValue">VALUE_TO_BE_CHANGED</DTS:Property>     </DTS:PackageParameter> Those sections in the curly braces are termed tag expressions and can be identified in the replace expression using a backslash and a number identifying which tag expression you’re referring to according to its ordinal position. Hence, our replace expression is simply: \1-1\2 We’re saying the portion of our file identified by the regular expression should be replaced by the first curly brace section, then the literal –1, then the second curly brace section. Make sense? Give it a go yourself by plugging those two expressions into Visual Studio’s Find and Replace dialog. If you set it to look in “All Open Documents” then you can open up the code-behind of all your packages and change all of them at once. The Find and Replace dialog will look like this: That’s it! I realise that not everyone will be looking to change the value of a parameter but hopefully I have shown you a technique that you can modify to work for your own scenario. Given that this blog post is, y’know, on the web I have no doubt that someone is going to find a fault with my find regex expression and if that person is you….that’s OK. Let me know about it in the comments below and perhaps we can work together to come up with something better! Note that some parameters may have a different set of properties (for example some, but not all, of my parameters have a DTS:Required attribute) so your find regular expression may have to change accordingly. When researching this I found the following article to be invaluable: Visual Studio Find/Replace Regular Expression Usage @Jamiet

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  • Grub2 -- Dualboot Ubuntu LTS 12.04 and Windows 7 -- Detects two Windows 7 (loader) entries

    - by DarkIron112
    this is the first question I have ever asked the Ubuntu Community. :D I'm fairly new to Ubuntu, but I understand the basics and know how to navigate the Terminal. I also know how to ask for/research my problems before asking for/ help. I have scoured the internet high and low and learned much of how Grub2 works. But nothing has helped me to solve my problem. My problem is this: I have a computer that has three hard drives. It previously had Windows XP, but I upgraded to Windows 7. I also installed Ubuntu 12.04 LTS (Precise Pangolin). During my installation of Windows 7, there was a failure and I had to restart the installation. Afterwards, I installed Ubuntu. After some trouble removing all traces of the XP OS (Ubuntu auto-detected it, but not Windows 7) I got the two OSes working flawlessly. Or, almost. When booting up, Grub2 used to display Ubuntu, Ubuntu Recovery Mode, Other Versions of Linux, memtest, followed by "Windows 7 (loader) on /dev/sda1" and "Windows 7 (loader) on /dev/sdb1". I eventually removed Recovery Mode, Other Versions, and Memtest. Now, when I run: sudo update-grub I get this print-out: Generating grub.cfg ... Found linux image: /boot/vmlinuz-3.2.0-26-generic Found initrd image: /boot/initrd.img-3.2.0-26-generic Found Windows 7 (loader) on /dev/sda1 Found Windows 7 (loader) on /dev/sdb1 I would like to remove "Windows 7 (loader) on /dev/sda1", as it is a broken entry that shouldn't exist, and must have been installed during my first Windows 7 attempt. I cannot find a Windows 7 entry in /etc/grub.d... And I don't know where to look. Here is a layout of my hard drives: /dev/sda1/ (1.82 TiB), NTFS ("Media") /dev/sdb1/ (100 Mib), NTFS ("System Reserved") /dev/sdb2/ (149 GiB), NTFS ("Windows 7") /dev/sdb3/ (149 GiB), Extended (" ") /dev/sdb4/ (145 GiB), ext4 (" ") /dev/sdb5/ (4 GiB), linux-swap (" ") /dev/sdc1/ (488.28 GiB), NTFS ("Downloads") /dev/sdc2/ (488.28 GiB), NTFS ("AltMedia") /dev/sdc3/ (886.45 GiB), NTFS ("Personal") unallocated (2.09 MiB), unallocated What I think has happened: Windows 7 installed first and badly. I installed it again. First, there was Windows XP to guide where the bootloader went to so it was put on /dev/sdb1/. But, the second time no such guide existed so the machine put another bootloader on /dev/sda1/. sda1, by the way, is the only partition on a 2TB drive. No boot record partition appears to exist according to gedit. I'm not sure where Grub2 is getting this information from. But, there it is. Is there anything somebody can do to help me? Or, is there any more information I should add? Thank you, community!

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  • SQL SERVER – Shard No More – An Innovative Look at Distributed Peer-to-peer SQL Database

    - by pinaldave
    There is no doubt that SQL databases play an important role in modern applications. In an ideal world, a single database can handle hundreds of incoming connections from multiple clients and scale to accommodate the related transactions. However the world is not ideal and databases are often a cause of major headaches when applications need to scale to accommodate more connections, transactions, or both. In order to overcome scaling issues, application developers often resort to administrative acrobatics, also known as database sharding. Sharding helps to improve application performance and throughput by splitting the database into two or more shards. Unfortunately, this practice also requires application developers to code transactional consistency into their applications. Getting transactional consistency across multiple SQL database shards can prove to be very difficult. Sharding requires developers to think about things like rollbacks, constraints, and referential integrity across tables within their applications when these types of concerns are best handled by the database. It also makes other common operations such as joins, searches, and memory management very difficult. In short, the very solution implemented to overcome throughput issues becomes a bottleneck in and of itself. What if database sharding was no longer required to scale your application? Let me explain. For the past several months I have been following and writing about NuoDB, a hot new SQL database technology out of Cambridge, MA. NuoDB is officially out of beta and they have recently released their first release candidate so I decided to dig into the database in a little more detail. Their architecture is very interesting and exciting because it completely eliminates the need to shard a database to achieve higher throughput. Each NuoDB database consists of at least three or more processes that enable a single database to run across multiple hosts. These processes include a Broker, a Transaction Engine and a Storage Manager.  Brokers are responsible for connecting client applications to Transaction Engines and maintain a global view of the network to keep track of the multiple Transaction Engines available at any time. Transaction Engines are in-memory processes that client applications connect to for processing SQL transactions. Storage Managers are responsible for persisting data to disk and serving up records to the Transaction Managers if they don’t exist in memory. The secret to NuoDB’s approach to solving the sharding problem is that it is a truly distributed, peer-to-peer, SQL database. Each of its processes can be deployed across multiple hosts. When client applications need to connect to a Transaction Engine, the Broker will automatically route the request to the most available process. Since multiple Transaction Engines and Storage Managers running across multiple host machines represent a single logical database, you never have to resort to sharding to get the throughput your application requires. NuoDB is a new pioneer in the SQL database world. They are making database scalability simple by eliminating the need for acrobatics such as sharding, and they are also making general administration of the database simpler as well.  Their distributed database appears to you as a user like a single SQL Server database.  With their RC1 release they have also provided a web based administrative console that they call NuoConsole. This tool makes it extremely easy to deploy and manage NuoDB processes across one or multiple hosts with the click of a mouse button. See for yourself by downloading NuoDB here. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: CodeProject, PostADay, SQL, SQL Authority, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology Tagged: NuoDB

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  • SQL SERVER – Puzzle #1 – Querying Pattern Ranges and Wild Cards

    - by Pinal Dave
    Note: Read at the end of the blog post how you can get five Joes 2 Pros Book #1 and a surprise gift. I have been blogging for almost 7 years and every other day I receive questions about Querying Pattern Ranges. The most common way to solve the problem is to use Wild Cards. However, not everyone knows how to use wild card properly. SQL Queries 2012 Joes 2 Pros Volume 1 – The SQL Queries 2012 Hands-On Tutorial for Beginners Book On Amazon | Book On Flipkart Learn SQL Server get all the five parts combo kit Kit on Amazon | Kit on Flipkart Many people know wildcards are great for finding patterns in character data. There are also some special sequences with wildcards that can give you even more power. This series from SQL Queries 2012 Joes 2 Pros® Volume 1 will show you some of these cool tricks. All supporting files are available with a free download from the www.Joes2Pros.com web site. This example is from the SQL 2012 series Volume 1 in the file SQLQueries2012Vol1Chapter2.2Setup.sql. If you need help setting up then look in the “Free Videos” section on Joes2Pros under “Getting Started” called “How to install your labs” Querying Pattern Ranges The % wildcard character represents any number of characters of any length. Let’s find all first names that end in the letter ‘A’. By using the percentage ‘%’ sign with the letter ‘A’, we achieve this goal using the code sample below: SELECT * FROM Employee WHERE FirstName LIKE '%A' To find all FirstName values beginning with the letters ‘A’ or ‘B’ we can use two predicates in our WHERE clause, by separating them with the OR statement. Finding names beginning with an ‘A’ or ‘B’ is easy and this works fine until we want a larger range of letters as in the example below for ‘A’ thru ‘K’: SELECT * FROM Employee WHERE FirstName LIKE 'A%' OR FirstName LIKE 'B%' OR FirstName LIKE 'C%' OR FirstName LIKE 'D%' OR FirstName LIKE 'E%' OR FirstName LIKE 'F%' OR FirstName LIKE 'G%' OR FirstName LIKE 'H%' OR FirstName LIKE 'I%' OR FirstName LIKE 'J%' OR FirstName LIKE 'K%' The previous query does find FirstName values beginning with the letters ‘A’ thru ‘K’. However, when a query requires a large range of letters, the LIKE operator has an even better option. Since the first letter of the FirstName field can be ‘A’, ‘B’, ‘C’, ‘D’, ‘E’, ‘F’, ‘G’, ‘H’, ‘I’, ‘J’ or ‘K’, simply list all these choices inside a set of square brackets followed by the ‘%’ wildcard, as in the example below: SELECT * FROM Employee WHERE FirstName LIKE '[ABCDEFGHIJK]%' A more elegant example of this technique recognizes that all these letters are in a continuous range, so we really only need to list the first and last letter of the range inside the square brackets, followed by the ‘%’ wildcard allowing for any number of characters after the first letter in the range. Note: A predicate that uses a range will not work with the ‘=’ operator (equals sign). It will neither raise an error, nor produce a result set. --Bad query (will not error or return any records) SELECT * FROM Employee WHERE FirstName = '[A-K]%' Question: You want to find all first names that start with the letters A-M in your Customer table and end with the letter Z. Which SQL code would you use? a. SELECT * FROM Customer WHERE FirstName LIKE 'm%z' b. SELECT * FROM Customer WHERE FirstName LIKE 'a-m%z' c. SELECT * FROM Customer WHERE FirstName LIKE 'a-m%z' d. SELECT * FROM Customer WHERE FirstName LIKE '[a-m]%z' e. SELECT * FROM Customer WHERE FirstName LIKE '[a-m]z%' f. SELECT * FROM Customer WHERE FirstName LIKE '[a-m]%z' g. SELECT * FROM Customer WHERE FirstName LIKE '[a-m]z%' Contest Leave a valid answer before June 18, 2013 in the comment section. 5 winners will be selected from all the valid answers and will receive Joes 2 Pros Book #1. 1 Lucky person will get a surprise gift from Joes 2 Pros. The contest is open for all the countries where Amazon ships the book (USA, UK, Canada, India and many others). Special Note: Read all the options before you provide valid answer as there is a small trick hidden in answers. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Joes 2 Pros, PostADay, SQL, SQL Authority, SQL Puzzle, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • It's like I'm in recovery mode after update, but I'm not

    - by mawburn
    I used the Ubuntu software updater and updated to the most recent packages. After the last update today, it's like I have gone into recovery mode, but I haven't. I am running UbuntuGNOME First, everything looks like this: Switching to dark mode does nothing. Also, default applications do not work. Such as Startup and the default screenshot application. Everything was working fine before the latest software update. System Info Ubuntu 14.04 LTS Gnome-Shell 3.10.4 Kernel 3.13.0-29 I can't figure out how to get an update history, but this is almost a fresh install. It's about a week old install and this is the 3rd time I've used the Ubuntu Software Update. I am running AMD ATI HD6700 with the proprietary Catalyst drivers. I tried to provide all information that I thought would be useful, if you need any more please let me know. Edit - I believe something went wrong within these updates: Update Log: Start-Date: 2014-06-09 19:07:07 Commandline: aptdaemon role='role-commit-packages' sender=':1.68' Install: libgnome-desktop-3-10:amd64 (3.12.0-0~eugenesan~trusty2) Upgrade: gnome-session-common:amd64 (3.9.90-0ubuntu12, 3.12.0-0~eugenesan~trusty10), gnome-session-bin:amd64 (3.9.90-0ubuntu12, 3.12.0-0~eugenesan~trusty10), gir1.2-gnomedesktop-3.0:amd64 (3.8.4-0ubuntu3, 3.12.0-0~eugenesan~trusty2), gnome-session:amd64 (3.9.90-0ubuntu12, 3.12.0-0~eugenesan~trusty10), python-libxml2:amd64 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), libspice-server1:amd64 (0.12.4-0nocelt2, 0.12.4-0nocelt2.02~eugenesan~trusty1), gir1.2-mutter-3.0:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1), xserver-xorg-video-qxl:amd64 (0.1.1-0ubuntu3, 0.1.1-0ubuntu3.01), libxml2:amd64 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), libxml2:i386 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), gnome-desktop3-data:amd64 (3.8.4-0ubuntu3, 3.12.0-0~eugenesan~trusty2), mutter:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1), mutter-common:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1), libxml2-utils:amd64 (2.9.1+dfsg1-3ubuntu4.1, 2.9.1+dfsg1-3ubuntu4.2), libmutter0c:amd64 (3.10.4-0ubuntu2, 3.10.4-0ubuntu2.1) End-Date: 2014-06-09 19:07:12 I also installed Citrix Receiver today, following the tutorial here: Citrix Receiver 12.1 on Ubuntu 14.04 64-bit Log Start-Date: 2014-06-09 18:59:06 Commandline: apt-get install libmotif4:i386 nspluginwrapper lib32z1 libc6-i386 libxp6:i386 libxpm4:i386 libasound2:i386 Install: libmotif-common:amd64 (2.3.4-5, automatic), libatk1.0-0:i386 (2.10.0-2ubuntu2, automatic), libxft2:i386 (2.3.1-2, automatic), libgraphite2-3:i386 (1.2.4-1ubuntu1, automatic), nspluginviewer:i386 (1.4.4-0ubuntu5, automatic), libpango-1.0-0:i386 (1.36.3-1ubuntu1, automatic), libxcursor1:i386 (1.1.14-1, automatic), libmotif4:i386 (2.3.4-5), libxm4:amd64 (2.3.4-5, automatic), libxm4:i386 (2.3.4-5, automatic), libxp6:i386 (1.0.2-1ubuntu1), libpangocairo-1.0-0:i386 (1.36.3-1ubuntu1, automatic), libxcb-render0:i386 (1.10-2ubuntu1, automatic), libthai0:i386 (0.1.20-3, automatic), libharfbuzz0b:i386 (0.9.27-1, automatic), libpixman-1-0:i386 (0.30.2-2ubuntu1, automatic), libpangoft2-1.0-0:i386 (1.36.3-1ubuntu1, automatic), libcairo2:i386 (1.13.0~20140204-0ubuntu1, automatic), lib32z1:amd64 (1.2.8.dfsg-1ubuntu1), libjasper1:i386 (1.900.1-14ubuntu3, automatic), libgtk2.0-0:i386 (2.24.23-0ubuntu1.1, automatic), nspluginwrapper:amd64 (1.4.4-0ubuntu5), libuil4:amd64 (2.3.4-5, automatic), libuil4:i386 (2.3.4-5, automatic), libxcb-shm0:i386 (1.10-2ubuntu1, automatic), libxmu6:i386 (1.1.1-1, automatic), libc6-i386:amd64 (2.19-0ubuntu6), libxinerama1:i386 (1.1.3-1, automatic), libgdk-pixbuf2.0-0:i386 (2.30.7-0ubuntu1, automatic), libxcomposite1:i386 (0.4.4-1, automatic), libmrm4:amd64 (2.3.4-5, automatic), libmrm4:i386 (2.3.4-5, automatic), libdatrie1:i386 (0.2.8-1, automatic), libxrandr2:i386 (1.4.2-1, automatic), libxpm4:i386 (3.5.10-1) End-Date: 2014-06-09 18:59:11

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  • Live-Ubuntu 12.04 ran fine, now stopped booting!

    - by user89743
    I've seen similar problems to this several times in the forum, but mine is a bit different, so the other posts I saw were no help to me. When I boot Ubuntu 12.04 64-bit from live-SD-card (3GB persistence) I suddenly get this error: (initramfs) mount: mounting /dev/loop0 on //filesystem.squashfs failed: Invalid argument Can not mount /dev/loop/0 (/cdrom/casper/filesystem.squashfs) on //filesystem.squashfs (it says I can type "help" for commands, but I don't know anything about how to go from there, totally new to linux) The reason I say my case is different is because my Ubuntu worked fine for over a week, even pretty fast, and now this problem happened. Before that I used to run my live ubuntu from USB sticks but that was slower (especially when booting which took 15 minutes from USB stick!). Also I kept getting the same above problem after a while when booting and had to re-create a live USB linux several times. Installing on harddrive is not an option because my harddrive has physical damage and getting a replacement will take a while, therefore I can only use live-USB or live-SD-card Ubuntu. As I said I used Ubuntu without problems for more than a week, before that as well for several weeks on USB sticks, but the above problem occured sooner or later. This time I paid attention to when it happened: I was rebooting my computer (HP 620 laptop, 4 GB RAM, 64 bit system) from SD flash card and when I was booting I selected F6 and then the first option "no acpi" or something like that...I had used it before and noticed it slowed down the time it took Linux to use. This time it caused this error. Now even when I boot normally/default I get this error. Now I'm accessing Ubuntu from my USB stick without persistence file, when I check my SD card, all the files mentioned in the error message are there and the filesystem.squashfs is 691.2 MB so nothing seems to have been deleted by accident. (I have already made many changes/downloaded programs to my SD card persistent Ubuntu and would hope to loose them, since downloading is expensive for me, and since the problem seems to re-occur...) Can anyone help me, preferably without having to create another startup disk on my SD card? I'm totally new to this. Sorry for the long posts, just didn't know what info is relevant and what isnt! Kon

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  • Dual booting windows 8/ubuntu 12.04. Grub doesn't appear and machine never boot in ubuntu

    - by black sensei
    i got a new ACER predator AG3620-UR308 which came with windows 8, so i wanted to run ubuntu 12.04.2 on it as a dual booting. To be honest, i've been doing dual booting for a while now so, i did the right thing. the box came with 2TB HDD. so i made 4 partitions with a raw partition just after the windows installation partition I always do manual installation so even if ubuntu didn't detect windows 8, it was ok for me. So i created swap area and finished the installation etc....Grub was install on the only drive there which is sda. After reboot, grub doesn't even come up.So it always boot in windows 8. I did repeat the installation process twice and yield same result. which is weird because this method always works for me so far.Even the laptop am using to write this post is a dual booting windows 7/ mint nadia installed the same way. Is there anything new in windows 8 that i didn't make provision for? Before starting the installation, all i read about was that , windows 8 should be installed first and ubuntu after. I went ahead and disable secure boot from the BIOS and enabled CSM (don't even know what it means) according to Acer custhelp site . I boot from USB and did fdisk -l bellow is the result: ubuntu@ubuntu:~$ sudo fdisk -l WARNING: GPT (GUID Partition Table) detected on '/dev/sda'! The util fdisk doesn't support GPT. Use GNU Parted. Disk /dev/sda: 2000.4 GB, 2000398934016 bytes 255 heads, 63 sectors/track, 243201 cylinders, total 3907029168 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 4096 bytes I/O size (minimum/optimal): 4096 bytes / 4096 bytes Disk identifier: 0x8c361cb5 Device Boot Start End Blocks Id System /dev/sda1 1 3907029167 1953514583+ ee GPT Partition 1 does not start on physical sector boundary. Disk /dev/sdb: 8178 MB, 8178892800 bytes 255 heads, 63 sectors/track, 994 cylinders, total 15974400 sectors Units = sectors of 1 * 512 = 512 bytes Sector size (logical/physical): 512 bytes / 512 bytes I/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x0006a87e Device Boot Start End Blocks Id System /dev/sdb1 * 2048 15972351 7985152 b W95 FAT32 ubuntu@ubuntu:~$ Can anybody shed some light? thank you in advance

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  • WiFi on Ubuntu 12.04 custom: downloading unbearably slow

    - by Mark
    iwconfig reports 11 Mbps, yet I've seen as low as <1 KBps. This is the latest in my laundry list of Ubuntu problems in a dual-boot machine (cyberpowerpc custom, intel i7-3820, nvidia gtx 570). I received it two days ago, Windows 7 running fine, still having problems with Ubuntu. The browsing is intermittent but unacceptable. e.g. I could get to this site last night but I couldn't post this question. The downloading is unbearably slow, I can't download anything or install any packages because the speed is so slow. e.g. I am trying to install vim which is inexplicably missing from my 12.04 install (add another one to the problems list) and my download speed reported in the terminal was 241 B/s. Yes, bytes. iwconfig reports 11 Mbps, which further adds to the confusion. User@ubuntu:~$ iwconfig lo no wireless extensions. wlan0 IEEE 802.11bgn ESSID:"linksys" Mode:Managed Frequency:2.437 GHz Access Point: 00:18:39:76:2C:A1 Bit Rate=11 Mb/s Tx-Power=20 dBm Retry long limit:7 RTS thr:off Fragment thr:off Power Management:off Link Quality=36/70 Signal level=-74 dBm Rx invalid nwid:0 Rx invalid crypt:0 Rx invalid frag:0 Tx excessive retries:54 Invalid misc:18 Missed beacon:0 eth0 no wireless extensions. Any ideas? I see this is a problem a lot of people, but none of the on line solutions have worked for me so far. e.g. one site recommends editing the ath9k.conf file in /etc/modprobe.d, yet this file isn't even in the folder: User@ubuntu:/$ cd etc/modprobe.d User@ubuntu:/etc/modprobe.d$ ls alsa-base.conf blacklist-oss.conf blacklist-ath_pci.conf blacklist-rare-network.conf blacklist.conf blacklist-watchdog.conf blacklist-firewire.conf dkms.conf blacklist-framebuffer.conf nvidia-current_hybrid.conf blacklist-modem.conf nvidia-graphics-drivers.conf I think the nvidia gpu might be mucking things up. I had the "blinking cursor" problem when installing in the first place, and then I had the monitor out of range problem as well. I have my faithful Asus laptop, which is running Ubuntu 12.04 just fine. The only difference is executing host -t SOA local in the terminal gives User@ubuntu:~$ host -t SOA local local has SOA record local. nobody.localhost. 42 86400 43200 604800 10800 in my new machine, and the command reports Host local. not found in the laptop. Help would be most welcome, as I am in danger of reverting back to Windows. I'm seriously considering it. Sorry for the length, trying to show my effort in resolving the issue and include terminal snippets that might be helpful.

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  • How to connect to MySQL server in LAN

    - by waelbk
    Ok, Here is the technical description. My laptop's config: Ip Adress:192.168.2.5 Mysqlserver 5.0 on port : 3306 Operating system: Ubuntu the database is in this machine My friend's laptop config: Ip Adress:192.168.2.4 Mysqlserver 5.0 on port : 3306 Operating system: Windows XP Both are on a wireless LAN connected through a belkin router (192.168.2.1) I put this but its not working: url = "jdbc:mysql://192.168.2.5:3306/Database" so how configure to connect to this database?

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  • Cannot install Nvidia driver X server

    - by Negoti Leboti
    I downloaded NVIDIA-Linux-x86-295.59.run from the official Nvidia website, I used in the terminal sudo sh NVIDIA-Linux-x86-295.59.run the installation started and everything, but I got this ERROR: You appear to be running an X server; please exit X before installing. For further details, please see the section INSTALLING THE NVIDIA DRIVER in the README available on the Linux driver download page at www.nvidia.com. I'm a newbie to ubuntu, and I don't know so much codes, can you please tell me step by step?

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  • SQL SERVER – 2008 – Introduction to Snapshot Database – Restore From Snapshot

    - by pinaldave
    Snapshot database is one of the most interesting concepts that I have used at some places recently. Here is a quick definition of the subject from Book On Line: A Database Snapshot is a read-only, static view of a database (the source database). Multiple snapshots can exist on a source database and can always reside on the same server instance as the database. Each database snapshot is consistent, in terms of transactions, with the source database as of the moment of the snapshot’s creation. A snapshot persists until it is explicitly dropped by the database owner. If you do not know how Snapshot database work, here is a quick note on the subject. However, please refer to the official description on Book-on-Line for accuracy. Snapshot database is a read-only database created from an original database called the “source database”. This database operates at page level. When Snapshot database is created, it is produced on sparse files; in fact, it does not occupy any space (or occupies very little space) in the Operating System. When any data page is modified in the source database, that data page is copied to Snapshot database, making the sparse file size increases. When an unmodified data page is read in the Snapshot database, it actually reads the pages of the original database. In other words, the changes that happen in the source database are reflected in the Snapshot database. Let us see a simple example of Snapshot. In the following exercise, we will do a few operations. Please note that this script is for demo purposes only- there are a few considerations of CPU, DISK I/O and memory, which will be discussed in the future posts. Create Snapshot Delete Data from Original DB Restore Data from Snapshot First, let us create the first Snapshot database and observe the sparse file details. USE master GO -- Create Regular Database CREATE DATABASE RegularDB GO USE RegularDB GO -- Populate Regular Database with Sample Table CREATE TABLE FirstTable (ID INT, Value VARCHAR(10)) INSERT INTO FirstTable VALUES(1, 'First'); INSERT INTO FirstTable VALUES(2, 'Second'); INSERT INTO FirstTable VALUES(3, 'Third'); GO -- Create Snapshot Database CREATE DATABASE SnapshotDB ON (Name ='RegularDB', FileName='c:\SSDB.ss1') AS SNAPSHOT OF RegularDB; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO Now let us see the resultset for the same. Now let us do delete something from the Original DB and check the same details we checked before. -- Delete from Regular Database DELETE FROM RegularDB.dbo.FirstTable; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO When we check the details of sparse file created by Snapshot database, we will find some interesting details. The details of Regular DB remain the same. It clearly shows that when we delete data from Regular/Source DB, it copies the data pages to Snapshot database. This is the reason why the size of the snapshot DB is increased. Now let us take this small exercise to  the next level and restore our deleted data from Snapshot DB to Original Source DB. -- Restore Data from Snapshot Database USE master GO RESTORE DATABASE RegularDB FROM DATABASE_SNAPSHOT = 'SnapshotDB'; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Clean up DROP DATABASE [SnapshotDB]; DROP DATABASE [RegularDB]; GO Now let us check the details of the select statement and we can see that we are successful able to restore the database from Snapshot Database. We can clearly see that this is a very useful feature in case you would encounter a good business that needs it. I would like to request the readers to suggest more details if they are using this feature in their business. Also, let me know if you think it can be potentially used to achieve any tasks. Complete Script of the afore- mentioned operation for easy reference is as follows: USE master GO -- Create Regular Database CREATE DATABASE RegularDB GO USE RegularDB GO -- Populate Regular Database with Sample Table CREATE TABLE FirstTable (ID INT, Value VARCHAR(10)) INSERT INTO FirstTable VALUES(1, 'First'); INSERT INTO FirstTable VALUES(2, 'Second'); INSERT INTO FirstTable VALUES(3, 'Third'); GO -- Create Snapshot Database CREATE DATABASE SnapshotDB ON (Name ='RegularDB', FileName='c:\SSDB.ss1') AS SNAPSHOT OF RegularDB; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Delete from Regular Database DELETE FROM RegularDB.dbo.FirstTable; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Restore Data from Snapshot Database USE master GO RESTORE DATABASE RegularDB FROM DATABASE_SNAPSHOT = 'SnapshotDB'; GO -- Select from Regular and Snapshot Database SELECT * FROM RegularDB.dbo.FirstTable; SELECT * FROM SnapshotDB.dbo.FirstTable; GO -- Clean up DROP DATABASE [SnapshotDB]; DROP DATABASE [RegularDB]; GO Reference : Pinal Dave (http://blog.SQLAuthority.com) Filed under: SQL, SQL Authority, SQL Backup and Restore, SQL Data Storage, SQL Query, SQL Server, SQL Tips and Tricks, SQLServer, T SQL, Technology

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  • How To Delete Top 100 Rows From SQL Server Tables

    - by Gopinath
    If you want to delete top 100/n records from an SQL Server table, it is very easy with the following query: DELETE FROM MyTable WHERE PK_Column IN(     SELECT TOP 100 PK_Column     FROM MyTable     ORDER BY creation    ) Why Would You Require To Delete Top 100 Records? I often delete a top n records of a table when number of rows in the are too huge. Lets say if I’ve 1000000000 records in a table, deleting 10000 rows at a time in a loop is faster than trying to delete all the 1000000000  at a time. What ever may be reason, if you ever come across a requirement of deleting a bunch of rows at a time, this query will be helpful to you. Join us on Facebook to read all our stories right inside your Facebook news feed.

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  • Updating Windows DNS records from a remote windows DNS server

    - by Luckyboy
    Does anyone know if it is possible for a windows 2003 DNS server to update the records for a domain so that it contains all the records of a domain of of a remotely based DNS server? Im almost certain that doesn't quite explain the problem so I shall illustrate with an example: We have two offices, both are based about 100 miles apart. One deals with IT (Intranet development etc.) while the other is a call centre that uses the Intranet systems. Currently each office has its own DNS server, with the IT office's and call centre's DNS servers containing entries for intranet site. The difference is that the IT DNS server records point to the various servers that host the Intranet sites (e.g. intranetsite1 - 192.168.1.10, intranetsite2 - 192.168.1.11) while all of the entries in the call centre's DNS point to the IT office's DNS server (intranetsite1 - [it office ip address], intranetsite2 - [it office ip address]). Is there any way that the call centre's DNS server could automatically add all DNS records hosted by the IT office's DNS, translating the IP addresses to the IP address of the IT office?

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  • SQL SERVER – FIX : ERROR : 4214 BACKUP LOG cannot be performed because there is no current database

    - by pinaldave
    I recently got following email from one of the reader. Hi Pinal, Even thought my database is in full recovery mode when I try to take log backup I am getting following error. BACKUP LOG cannot be performed because there is no current database backup. (Microsoft.SqlServer.Smo) How to fix it? Thanks, [name and email removed as requested] Solution / Fix: This error can happen when you have never taken full backup of your database and you try to attempt to take backup of the log only. Take full backup once and attempt to take log back up. If the name of your database is MyTestDB follow procedure as following. BACKUP DATABASE [MyTestDB] TO DISK = N'C:\MyTestDB.bak' GO BACKUP LOG [MyTestDB] TO DISK = N'C:\MyTestDB.bak' GO Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Backup and Restore, SQL Error Messages, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SQL Log

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  • SQL SERVER – Get Latest SQL Query for Sessions – DMV

    - by pinaldave
    In recent SQL Training I was asked, how can one figure out what was the last SQL Statement executed in sessions. The query for this is very simple. It uses two DMVs and created following quick script for the same. SELECT session_id, TEXT FROM sys.dm_exec_connections CROSS APPLY sys.dm_exec_sql_text(most_recent_sql_handle) AS ST While working with DMVs if you ever find any DMV has column with name sql_handle you can right away join that DMV with another DMV sys.dm_exec_sql_text and can get the text of the SQL statement. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: DMV, SQL DMV

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  • SQL SERVER – Check the Isolation Level with DBCC useroptions

    - by pinaldave
    In recent consultancy project coordinator asked me – “can you tell me what is the isolation level for this database?” I have worked with different isolation levels but have not ever queried database for the same. I quickly looked up bookonline and found out the DBCC command which can give me the same details. You can run the DBCC UserOptions command on any database to get few details about dateformat, datefirst as well isolation level. DBCC useroptions Set Option                  Value --------------------------- -------------- textsize                    2147483647 language                    us_english dateformat                  mdy datefirst                   7 lock_timeout                -1 quoted_identifier           SET arithabort                  SET ansi_null_dflt_on           SET ansi_warnings               SET ansi_padding                SET ansi_nulls                  SET concat_null_yields_null     SET isolation level             read committed I thought this was very handy script, which I have not used earlier. Thanks Gary for asking right question. Reference: Pinal Dave (http://blog.sqlauthority.com) Filed under: Pinal Dave, SQL, SQL Authority, SQL Query, SQL Scripts, SQL Server, SQL System Table, SQL Tips and Tricks, T SQL, Technology Tagged: Transaction Isolation

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  • SQL SERVER – Difference Between GETDATE and SYSDATETIME

    - by pinaldave
    Sometime something so simple skips our mind. I never knew the difference between GETDATE and SYSDATETIME. I just ran simple query as following and realized the difference. SELECT GETDATE() fn_GetDate, SYSDATETIME() fn_SysDateTime In case of GETDATE the precision is till miliseconds and in case of SYSDATETIME the precision is till nanoseconds. Now the questions is to you – did you know this? Be honest and please share your views. I already accepted that I did not know this in very first line. Reference: Pinal Dave (http://www.SQLAuthority.com), Filed under: Pinal Dave, SQL, SQL Authority, SQL DateTime, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – Convert IN to EXISTS – Performance Talk

    - by pinaldave
    In recent training one of the attendee asked if I can show simple method to convert IN clause to EXISTS clause. Here is the simple example. USE AdventureWorks GO -- use of = SELECT * FROM HumanResources.Employee E WHERE E.EmployeeID = ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA WHERE EA.EmployeeID = E.EmployeeID) GO -- use of exists SELECT * FROM HumanResources.Employee E WHERE EXISTS ( SELECT EA.EmployeeID FROM HumanResources.EmployeeAddress EA WHERE EA.EmployeeID = E.EmployeeID) GO It is NOT necessary that every time when IN is replaced by EXISTS it gives better performance. However, in our case listed above it does for sure give better performance. Click on below image to see the execution plan. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: SQL, SQL Authority, SQL Optimization, SQL Performance, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL Server - MVP 2010

    - by JustinL
    I was very happy to receive an email last week to confirm I would receive the MVP Award for SQL Server for 2010 - very exciting news ! I missed the first FedEx delivery, however this weekend they were able to successfully deliver the package from Microsoft and it began to feel very real as I opened the box to find the MVP glass-ware! Since leaving Microsoft, the past couple of years have been incredibly challenging, exciting and satisfying.  The MVP Award is really special, the SQL community has a fantastic, international base with many successful events, leaders and contributors providing an impressive network both online and in-person. I'm really excited about the year ahead - starting this week with SQL Bits in London, followed by PASS EMEA in Germany next week and at the London PASS user group meeting on Monday 26th April. Regards,   Justin Langford - Coeo Ltd

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  • SQL SERVER – List of Article on Expressor Data Integration Platform

    - by pinaldave
    The ability to transform data into meaningful and actionable information is the most important information in current business world. In this fast growing and changing business needs effective data integration is single most important thing in making proper decision making. I have been following expressor software since November 2010, when I met expressor team in Seattle. Here are my posts on their innovative data integration platform and expressor Studio, a free desktop ETL tool: 4 Tips for ETL Software IDE Developers Introduction to Adaptive ETL Tool – How adaptive is your ETL? Sharing your ETL Resources Across Applications with Ease expressor Studio Includes Powerful Scripting Capabilities expressor 3.2 Release Review 5 Tips for Improving Your Data with expressor Studio As I had mentioned in some of my blog posts on them, I encourage you to download and test-drive their Studio product – it’s free. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: PostADay, SQL, SQL Authority, SQL Documentation, SQL Download, SQL Query, SQL Server, SQL Tips and Tricks, T SQL, Technology Tagged: SSIS

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  • We're Hiring! - Server and Desktop Virtualization Product Management

    - by adam.hawley
    There is a lot of exciting stuff going on here at Oracle in general but the server and desktop virtualization group in particular is deeply involved in executing on Oracle's strategy for delivering complete hardware-software solutions across the company, so we're expanding our team with several open positions. If you're interested and qualified, then please send us your resume. The three positions in Virtualization Product Management can be found by going here or going to the Employment Opportunities Job Search page, clicking on 'Advanced Search' and typing the job opening numbers (include 'IRC'... see below) in the 'Keywords' field. Click Search. Current openings are... IRC1457623: Oracle VM Product Management IRC1457626: Desktop Virtualization Application Solutions Product Management IRC1473577: Oracle VM Best Practices Implementation Engineer (Product Management) I look forward to hearing from you!

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  • Can't access IIS 7 server URL from the same IIS 7 server.

    - by Kevin Raffay
    We have an intranet site ie, xxx.yyyy.com, that users access by entering "http"://xxx.yyy.com. Our problems started when we migrated to IIS 7 running on a new 2003 server. We got rid of our single-sign on code and implemented a security model where we capture a user's domain credentials which we then authenticate against a DB. In order to get the domain credentials passed to our ASP.NET app, we have the following settings: Anonymous Authentication:Disabled ASP.NET Impersonation: Enabled Basic/Digest/Forms Authentication: Disabled Windows Authentication: Enabled We allow "*" and deny "?" in the web.config. Browsing "http"://xxx.yyy.com from any client PC results in a domain login prompt, and if your enter a proper user/pwd, you can get in. However, browsing "http"://xxx.yyy.com while remoting into the server results in 3 domain login prompts and eventually a 401 error - unauthorized. We have traced this behavior to problems with our web site where we have pages doing "screen scraping" using the HttpRequest calling a url on the same server. When doing a HttpRequest from any other client, using a test harness that passes authorized credentials, all is good. So internal HttpRequest calls on the server fail, just like attempts to browse that server's url from within a remote session. Why would a to "http"://xxx.yyy.com on server xxx.yyy.com fail authentication?

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