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• Trying to compile x264 and ffmpeg for iPhone - "missing required architecture arm in file"

  - by jtrim

  I'm trying to compile x264 for use in an iPhone application. I see there are instructions on how to compile ffmpeg for use on the platform here: http://lists.mplayerhq.hu/pipermail/ffmpeg-devel/2009-October/076618.html , but I can't seem to find anything this complete for compiling x264 on the iPhone. I've found this source tree: http://gitorious.org/x264-arm that seems to have support for the ARM platform. Here is my config line: ./configure --cross-prefix=/usr/bin/ --host=arm-apple-darwin10 --extra-cflags="-B /Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS3.2.sdk/usr/lib/ -I /Developer/Platforms/iPhoneOS.platform/Developer/SDKs/iPhoneOS3.2.sdk/usr/lib/" ...and inside configure I'm using the gas-preprocessor script (first link above) as my assembler: gas-preprocessor.pl gcc When I start compiling, it chunks away for a little while, then it spits out these warnings and a huge list of undefined symbols: ld: warning: option -s is obsolete and being ignored ld: warning: -force_cpusubtype_ALL will become unsupported for ARM architectures ld: warning: in /usr/lib/crt1.o, missing required architecture arm in file ld: warning: in /usr/X11R6/lib/libX11.dylib, missing required architecture arm in file ld: warning: in /usr/lib/libm.dylib, missing required architecture arm in file ld: warning: in /usr/lib/libpthread.dylib, missing required architecture arm in file ld: warning: in /usr/lib/libgcc_s.1.dylib, missing required architecture arm in file ld: warning: in /usr/lib/libSystem.dylib, missing required architecture arm in file Undefined symbols: My guess would be that the problem has to do with the "missing required architecture arm in file" warning...any ideas?

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• Building a python module and linking it against a MacOSX framework

  - by madflo

  I'm trying to build a Python extension on MacOSX 10.6 and to link it against several frameworks (i386 only). I made a setup.py file, using distutils and the Extension object. I order to link against my frameworks, my LDFLAGS env var should look like : LDFLAGS = -lc -arch i386 -framework fwk1 -framework fwk2 As I did not find any 'framework' keyword in the Extension module documentation, I used the extra_link_args keyword instead. Extension('test', define_macros = [('MAJOR_VERSION', '1'), ,('MINOR_VERSION', '0')], include_dirs = ['/usr/local/include', 'include/', 'include/vitale'], extra_link_args = ['-arch i386', '-framework fwk1', '-framework fwk2'], sources = "testmodule.cpp", language = 'c++' ) Everything is compiling and linking fine. If I remove the -framework line from the extra_link_args, my linker fails, as expected. Here is the last two lines produced by a python setup.py build : /usr/bin/g++-4.2 -arch x86_64 -arch i386 -isysroot / -L/opt/local/lib -arch x86_64 -arch i386 -bundle -undefined dynamic_lookup build/temp.macosx-10.6-intel-2.6/testmodule.o -o build/lib.macosx-10.6-intel-2.6/test.so -arch i386 -framework sgdosx -framework srtosx -framework ssvosx -framework stsosx Unfortunately, the .so that I just produced is unable to find several symbols provided by this framework. I tried to check the linked framework with otool. None of them is appearing. $ otool -L test.so test.so: /usr/lib/libstdc++.6.dylib (compatibility version 7.0.0, current version 7.9.0) /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.1) There is the output of otool run on a test binary, made with g++ and ldd using the LDFLAGS described at the top of my post. On this example, the -framework did work. $ otool -L vitaosx vitaosx: /Library/Frameworks/sgdosx.framework/Versions/A/sgdosx (compatibility version 1.0.0, current version 1.0.0) /Library/Frameworks/ssvosx.framework/Versions/A/ssvosx (compatibility version 1.0.0, current version 1.0.0) /usr/lib/libstdc++.6.dylib (compatibility version 7.0.0, current version 7.9.0) /usr/lib/libSystem.B.dylib (compatibility version 1.0.0, current version 125.0.1) May this issue be linked to the "-undefined dynamic_lookup" flag on the linking step ? I'm a little bit confused by the few lines of documentation that I'm finding on Google. Cheers,

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• perl dynamic path given to 'use lib'

  - by Ed Hyer

  So, my code (Perl scripts and Perl modules) sits in a tree like this: trunk/ util/ process/ scripts/ The 'util' directory has, well, utilities, that things in the 'process/' dir need. They get access like this: use FindBin; use lib "$FindBin::Bin/../util"; use UtilityModule qw(all); That construct doesn't care where you start, as long as you're at the same level in the tree as "util/". But I decided that 'scripts/' was getting too crowded, so I created scripts/scripts1 scripts/scripts2 Now I see that this doesn't work. If I run a script 'trunk/scripts/scripts1/call_script.pl', and it calls '/trunk/process/process_script.pl', then 'process_script.pl' will fail trying to get the routines from UtilityModule(), because the path that FindBin returns is the path of the top-level calling script. The first ten ways I thought of to solve this all involved something like: use lib $path_that_came_from_elsewhere; but that seems to be something Perl doesn't like to do, except via that FindBin trick. I tried some things involving BEGIN{} blocks, but i don't really know what I'm doing there, and will likely just end up refactoring. But if someone has some clever insight into this type of problem, this would be a good chance to earn some points!

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• Build failed question - maven - jre or jdk problem

  - by Gandalf StormCrow

  Hi all, I have my JAVA_HOME set to C:\Program Files (x86)\Java\jdk1.6.0_18 After I run maven install I get this message from eclipse: Reason: Unable to locate the Javac Compiler in: C:\Program Files (x86)\Java\jre6\..\lib\tools.jar Please ensure you are using JDK 1.4 or above and not a JRE (the com.sun.tools.javac.Main class is required). In most cases you can change the location of your Java installation by setting the JAVA_HOME environment variable. I'm certain that this is the tricky part Please ensure you are using JDK 1.4 or above and not a JRE When I run configuration its set to JRE6, how do I change it to JDK 1.6 which I have already installed EDIT I even tried to modify the plugin : <plugin> <groupId>org.apache.maven.plugins</groupId> <artifactId>maven-compiler-plugin</artifactId> <version>2.0.2</version> <configuration> <source>1.6</source> <target>1.6</target> <executable>C:\Program Files (x86)\Java\jdk1.6.0_18\bin</executable> </configuration> </plugin> Still I get the same error Maybe I forgot to say I use eclipse maven plugin .. how can I change from JRE to JDK in eclipse ?

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• Help with Perl persistent data storage using Data::Dumper

  - by stephenmm

  I have been trying to figure this out for way to long tonight. I have googled it to death and none of the examples or my hacks of the examples are getting it done. It seems like this should be pretty easy but I just cannot get it. Here is the code: #!/usr/bin/perl -w use strict; use Data::Dumper; my $complex_variable = {}; my $MEMORY = "$ENV{HOME}/data/memory-file"; $complex_variable->{ 'key' } = 'value'; $complex_variable->{ 'key1' } = 'value1'; $complex_variable->{ 'key2' } = 'value2'; $complex_variable->{ 'key3' } = 'value3'; print Dumper($complex_variable)."TEST001\n"; open M, ">$MEMORY" or die; print M Data::Dumper->Dump([$complex_variable], ['$complex_variable']); close M; $complex_variable = {}; print Dumper($complex_variable)."TEST002\n"; # Then later to restore the value, it's simply: do $MEMORY; #eval $MEMORY; print Dumper($complex_variable)."TEST003\n"; And here is my output: $VAR1 = { 'key2' => 'value2', 'key1' => 'value1', 'key3' => 'value3', 'key' => 'value' }; TEST001 $VAR1 = {}; TEST002 $VAR1 = {}; TEST003 Everything that I read says that the TEST003 output should look identical to the TEST001 output which is exactly what I am trying to achieve. What am I missing here? Should I be "do"ing differently or should I be "eval"ing instead and if so how? Thanks for any help...

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• How to Display a Bmp in a RTF control in VB.net

  - by Gerolkae

  I Started with this C# Question I'm trying to Display a bmp image inside a rtf Box for a Bot program I'm making. This function is supposed to convert a bitmap to rtf code whis is inserted to another rtf formatter srtring with additional text. Kind of like Smilies being used in a chat program. For some reason the output of this function gets rejected by the RTF Box and Vanishes completly. I'm not sure if it the way I'm converting the bmp to a Binary string or if its tied in with the header tags 'returns the RTF string representation of our picture Public Shared Function PictureToRTF(ByVal Bmp As Bitmap) As String Dim stream As New MemoryStream() Bmp.Save(stream, System.Drawing.Imaging.ImageFormat.Bmp) Dim bytes As Byte() = stream.ToArray() Dim str As String = BitConverter.ToString(bytes, 0).Replace("-", String.Empty) 'header to string we want to insert Using g As Graphics = Main.CreateGraphics() xDpi = g.DpiX yDpi = g.DpiY End Using Dim _rtf As New StringBuilder() ' Calculate the current width of the image in (0.01)mm Dim picw As Integer = CInt(Math.Round((Bmp.Width / xDpi) * HMM_PER_INCH)) ' Calculate the current height of the image in (0.01)mm Dim pich As Integer = CInt(Math.Round((Bmp.Height / yDpi) * HMM_PER_INCH)) ' Calculate the target width of the image in twips Dim picwgoal As Integer = CInt(Math.Round((Bmp.Width / xDpi) * TWIPS_PER_INCH)) ' Calculate the target height of the image in twips Dim pichgoal As Integer = CInt(Math.Round((Bmp.Height / yDpi) * TWIPS_PER_INCH)) ' Append values to RTF string _rtf.Append("{\pict\wbitmap0") _rtf.Append("\picw") _rtf.Append(Bmp.Width.ToString) ' _rtf.Append(picw.ToString) _rtf.Append("\pich") _rtf.Append(Bmp.Height.ToString) ' _rtf.Append(pich.ToString) _rtf.Append("\wbmbitspixel24\wbmplanes1") _rtf.Append("\wbmwidthbytes40") _rtf.Append("\picwgoal") _rtf.Append(picwgoal.ToString) _rtf.Append("\pichgoal") _rtf.Append(pichgoal.ToString) _rtf.Append("\bin ") _rtf.Append(str.ToLower & "}") Return _rtf.ToString End Function

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• vtk glyphs 3D, indenpently color and rotation

  - by user3684219

  I try to display thanks to vtk (python wrapper) several glyphs in a scene with each their own colour and rotation. Unfortunately, just the rotation (using vtkTensorGlyph) is taken in consideration by vtk. Reversely, just color is taken in consideration when I use a vtkGlyph3D. Here is a ready to use piece of code with a vtkTensorGlyph. Each cube should have a random color but there all will be in the same color. I read and read again the doc of vtk but I found no solution. Thanks in advance for any idea #!/usr/bin/env python # -*- coding: utf-8 -*- import vtk import scipy.linalg as sc import random as ra import numpy as np import itertools points = vtk.vtk.vtkPoints() # where to locate each glyph in the scene tensors = vtk.vtkDoubleArray() # rotation for each glyph tensors.SetNumberOfComponents(9) colors = vtk.vtkUnsignedCharArray() # should be the color for each glyph colors.SetNumberOfComponents(3) # let's make 10 cubes in the scene for i in range(0, 50, 5): points.InsertNextPoint(i, i, i) # position of a glyph colors.InsertNextTuple3(ra.randint(0, 255), ra.randint(0, 255), ra.randint(0, 255) ) # pick random color rot = list(itertools.chain(*np.reshape(sc.orth(np.random.rand(3, 3)).transpose(), (1, 9)).tolist())) # random rotation matrix (row major) tensors.InsertNextTuple9(*rot) polydata = vtk.vtkPolyData() # create the polydatas polydata.SetPoints(points) polydata.GetPointData().SetTensors(tensors) polydata.GetPointData().SetScalars(colors) cubeSource = vtk.vtkCubeSource() cubeSource.Update() glyphTensor = vtk.vtkTensorGlyph() glyphTensor.SetColorModeToScalars() # is it really work ? try: glyphTensor.SetInput(polydata) except AttributeError: glyphTensor.SetInputData(polydata) glyphTensor.SetSourceConnection(cubeSource.GetOutputPort()) glyphTensor.ColorGlyphsOn() # should not color all cubes independently ? glyphTensor.ThreeGlyphsOff() glyphTensor.ExtractEigenvaluesOff() glyphTensor.Update() # next is usual vtk code mapper = vtk.vtkPolyDataMapper() mapper.SetInputConnection(glyphTensor.GetOutputPort()) actor = vtk.vtkActor() actor.SetMapper(mapper) ren = vtk.vtkRenderer() ren.SetBackground(0.2, 0.5, 0.3) ren.AddActor(actor) renwin = vtk.vtkRenderWindow() renwin.AddRenderer(ren) iren = vtk.vtkRenderWindowInteractor() iren.SetInteractorStyle(vtk.vtkInteractorStyleTrackballCamera()) iren.SetRenderWindow(renwin) renwin.Render() iren.Initialize() renwin.Render() iren.Start()

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• Turning off hibernate logging console output

  - by Jared

  I'm using hibernate 3 and want to stop it from dumping all the startup messages to the console. I tried commenting out the stdout lines in log4j.properties but no luck. I've pasted my log file below. Also I'm using eclipse with the standard project structure and have a copy of log4j.properties in both the root of the project folder and the bin folder. ### direct log messages to stdout ### #log4j.appender.stdout=org.apache.log4j.ConsoleAppender #log4j.appender.stdout.Target=System.out #log4j.appender.stdout.layout=org.apache.log4j.PatternLayout #log4j.appender.stdout.layout.ConversionPattern=%d{ABSOLUTE} %5p %c{1}:%L - %m%n ### direct messages to file hibernate.log ### log4j.appender.file=org.apache.log4j.FileAppender log4j.appender.file.File=hibernate.log log4j.appender.file.layout=org.apache.log4j.PatternLayout log4j.appender.file.layout.ConversionPattern=%d{ABSOLUTE} %5p %c{1}:%L - %m%n ### set log levels - for more verbose logging change 'info' to 'debug' ### log4j.rootLogger=warn, stdout #log4j.logger.org.hibernate=info log4j.logger.org.hibernate=debug ### log HQL query parser activity #log4j.logger.org.hibernate.hql.ast.AST=debug ### log just the SQL #log4j.logger.org.hibernate.SQL=debug ### log JDBC bind parameters ### log4j.logger.org.hibernate.type=info #log4j.logger.org.hibernate.type=debug ### log schema export/update ### log4j.logger.org.hibernate.tool.hbm2ddl=debug ### log HQL parse trees #log4j.logger.org.hibernate.hql=debug ### log cache activity ### #log4j.logger.org.hibernate.cache=debug ### log transaction activity #log4j.logger.org.hibernate.transaction=debug ### log JDBC resource acquisition #log4j.logger.org.hibernate.jdbc=debug ### enable the following line if you want to track down connection ### ### leakages when using DriverManagerConnectionProvider ### #log4j.logger.org.hibernate.connection.DriverManagerConnectionProvider=trac5

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• Watir issue. cant move forward in irb

  - by user1033392

  Hello i'am using windows 7 and i wish to use watir-webdriver with ruby 1.9.2. Please tell me why i get this: C:\>irb irb(main):001:0> require "watir-webdriver" => true irb(main):002:0> browser = Watir::Browser.new :ff Errno::EADDRNOTAVAIL: ??dany adres jest nieprawid?owy w tym kontek?cie. - bind(2 ) from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/firefox/socket_lock.rb:45:in `initialize' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/firefox/socket_lock.rb:45:in `new' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/firefox/socket_lock.rb:45:in `can_lock?' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/firefox/socket_lock.rb:31:in `lock' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/firefox/socket_lock.rb:17:in `locked' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/firefox/launcher.rb:32:in `launch' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/firefox/bridge.rb:19:in `initialize' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/common/driver.rb:31:in `new' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver/common/driver.rb:31:in `for' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/selenium-webdriver-2.22.0/lib/s elenium/webdriver.rb:65:in `for' from C:/Ruby193/lib/ruby/gems/1.9.1/gems/watir-webdriver-0.6.1/lib/watir -webdriver/browser.rb:35:in `initialize' from (irb):2:in `new' from (irb):2 from C:/Ruby193/bin/irb:12:in `<main>' irb(main):003:0> Thanks a lot for help!

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• rails server fails to start with mysql2 using rvm & ruby 1.9.2-p0 on OSX 10.6.5

  - by Scott

  I'm getting the following error when I start rails server: $ rails server /Users/ssmith/.rvm/gems/ruby-1.9.2-p0/gems/mysql2-0.2.6/lib/mysql2.rb:7:in `require': dlopen(/Users/ssmith/.rvm/gems/ruby-1.9.2-p0/gems/mysql2-0.2.6/lib/mysql2/mysql2.bundle, 9): Library not loaded: libmysqlclient.16.dylib (LoadError) Referenced from: /Users/ssmith/.rvm/gems/ruby-1.9.2-p0/gems/mysql2- 0.2.6/lib/mysql2/mysql2.bundle Reason: image not found - /Users/ssmith/.rvm/gems/ruby-1.9.2-p0/gems/mysql2- 0.2.6/lib/mysql2/mysql2.bundle I've installed mysql2 with the following command after the rvm use ruby-1.9.2-p0 command: $ gem install mysql2 -- --with-mysql-dir=/usr/local/mysql --with-mysql-config=/usr/local/mysql/bin/mysql_config Building native extensions. This could take a while... Successfully installed mysql2-0.2.6 1 gem installed Installing ri documentation for mysql2-0.2.6... Enclosing class/module 'mMysql2' for class Client not known Installing RDoc documentation for mysql2-0.2.6... Enclosing class/module 'mMysql2' for class Client not known I have mysql2 in my Gemfile as well as in the database.yml file and bundle install completes fine $ bundle show mysql2 /Users/ssmith/.rvm/gems/ruby-1.9.2-p0/gems/mysql2-0.2.6 I understand the rails server error is due to it not knowing the mysql_config location on OSX, however on gem install I specified the correct location. Yet RVM's gem is not respecting that mysql_config location it seems. Anyone have a solution to this? Thanks in advance. Scott

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• Simple perl program failing to execute

  - by yves Baumes

  Here is a sample that fails: #!/usr/bin/perl -w # client.pl #---------------- use strict; use Socket; # initialize host and port my $host = shift || 'localhost'; my $port = shift || 55555; my $server = "10.126.142.22"; # create the socket, connect to the port socket(SOCKET,PF_INET,SOCK_STREAM,(getprotobyname('tcp'))[2]) or die "Can't create a socket $!\n"; connect( SOCKET, pack( 'Sn4x8', AF_INET, $port, $server )) or die "Can't connect to port $port! \n"; my $line; while ($line = <SOCKET>) { print "$line\n"; } close SOCKET or die "close: $!"; with the error: Argument "10.126.142.22" isn't numeric in pack at D:\send.pl line 16. Can't connect to port 55555! I am using this version of Perl: This is perl, v5.10.1 built for MSWin32-x86-multi-thread (with 2 registered patches, see perl -V for more detail) Copyright 1987-2009, Larry Wall Binary build 1006 [291086] provided by ActiveState http://www.ActiveState.com Built Aug 24 2009 13:48:26 Perl may be copied only under the terms of either the Artistic License or the GNU General Public License, which may be found in the Perl 5 source kit. Complete documentation for Perl, including FAQ lists, should be found on this system using "man perl" or "perldoc perl". If you have access to the Internet, point your browser at http://www.perl.org/, the Perl Home Page. While I am running the netcat command on the server side. Telnet does work.

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• Activate a python virtual environment using activate_this.py in a fabfile on Windows

  - by Rudy Lattae

  I have a Fabric task that needs to access the settings of my Django project. On Windows, I'm unable to install Fabric into the project's virtualenv (issues with Paramiko + pycrypto deps). However, I am able to install Fabric in my system-wide site-packages, no problem. I have installed Django into the project's virtualenv and I am able to use all the " python manage.py" commands easily when I activate the virtualenv with the "VIRTUALENV\Scripts\activate.bat" script. I have a fabric tasks file (fabfile.py) in my project that provides tasks for setup, test, deploy, etc. Some of the tasks in my fabfile need to access the settings of my django project through "from django.conf import settings". Since the only usable Fabric install I have is in my system-wide site-packages, I need to activate the virtualenv within my fabfile so django becomes available. To do this, I use the "activate_this" module of the project's virtualenv in order to have access to the project settings and such. Using "print sys.path" before and after I execute activate_this.py, I can tell the python path changes to point to the virtualenv for the project. However, I still cannot import django.conf.settings. I have been able to successfully do this on *nix (Ubuntu and CentOS) and in Cygwin. Do you use this setup/workflow on Windows? If so Can you help me figure out why this wont work on Windows or provide any tips and tricks to get around this issue? Thanks and Cheers. REF: http://virtualenv.openplans.org/#id9 | Using Virtualenv without bin/python Local development environment: Python 2.5.4 Virtualenv 1.4.6 Fabric 0.9.0 Pip 0.6.1 Django 1.1.1 Windows XP (SP3)

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• Retrieve Flash file post in ASP.NET

  - by Quandary

  Question: In ASP.NET, I retrieve a JPEG-file as Flash post data like this Sub ProcessRequest(ByVal context As HttpContext) Implements IHttpHandler.ProcessRequest context.Response.ContentType = "text/plain" ' Retrieve a bytearray from the post buffer Dim myBuffer As Byte() = context.Request.BinaryRead(Convert.ToInt32(context.Request.InputStream.Length)) System.IO.File.WriteAllBytes("c:\temp\test.jpg", myBuffer) End Sub In Flash, I send it to an asp.net handler like this var jpgSource:BitmapData = cPrint.TakeSnapshot(MovieClip(cGlobals.ccPlanZoomView)); var bmpThisBitmap:Bitmap = new Bitmap(jpgSource); var nQuality:Number = 100; var jpgEncoder:JPGEncoder = new JPGEncoder(nQuality); var jpgStream:ByteArray = jpgEncoder.encode(jpgSource); var header:URLRequestHeader = new URLRequestHeader ("Content-type", "application/octet-stream"); // Make sure to use the correct path to jpg_encoder_download.php var strFileName:String="test.jpg"; var jpgURLRequest:URLRequest = new URLRequest("http://localhost/raumplaner_new/raumplaner_new/cgi-bin/SavePDF.ashx"); //var scriptVars:URLVariables = new URLVariables(); //scriptVars.fn = strFileName; //var myarr:Array= new Array(); //myarr.push(jpgStream); //scriptVars.Files = myarr; jpgURLRequest.requestHeaders.push(header); jpgURLRequest.method = URLRequestMethod.POST; //jpgURLRequest.data = scriptVars; jpgURLRequest.data = jpgStream; var loader:URLLoader = new URLLoader(); loader.dataFormat = URLLoaderDataFormat.BINARY; loader.load(jpgURLRequest); It works but I want to send a few additional variables along, via scriptVars (commented out here). How do I retrieve the JPEG file in that case ? Because if I use parameters, there is no more BinaryRead... Aspecially, how would I read an array of jpeg files (several files) ?

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• Perl: Exporting variables in a subclass

  - by Jonathan

  I have a base class like this: package MyClass; use vars qw/$ME list of vars/; use Exporter; @ISA = qw/Exporter/; @EXPORT_OK = qw/ many variables & functions/; %EXPORT_TAGS = (all => \@EXPORT_OK ); sub my_method { } sub other_methods etc { } --- more code--- I want to subclass MyClass, but only for one method. package MySubclass; use MyClass; use vars qw/@ISA/; @ISA = 'MyClass'; sub my_method { --- new method } And I want to call this MySubclass like I would the original MyClass, and still have access to all of the variables and functions from exporter. However I am having problems getting the Exporter variables from the original class, MyClass, to export correctly. Do I need to run exporter again inside the subclass? That seems redundant and unclear. Example file: #!/usr/bin/perl use MySubclass /$ME/; -- rest of code But I get compile errors when I try to import the $ME variable. Any suggestions?

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• Bash Shell Script: Nested Select Statements

  - by CCG121

  I have A Script that has a Select statement to go to multiple sub select statements however once there I can not seem to figure out how to get it to go back to the main script. also if possible i would like it to re-list the options #!/bin/bash PS3='Option = ' MAINOPTIONS="Apache Postfix Dovecot All Quit" APACHEOPTIONS="Restart Start Stop Status" POSTFIXOPTIONS="Restart Start Stop Status" DOVECOTOPTIONS="Restart Start Stop Status" select opt in $MAINOPTIONS; do if [ "$opt" = "Quit" ]; then echo Now Exiting exit elif [ "$opt" = "Apache" ]; then select opt in $APACHEOPTIONS; do if [ "$opt" = "Restart" ]; then sudo /etc/init.d/apache2 restart elif [ "$opt" = "Start" ]; then sudo /etc/init.d/apache2 start elif [ "$opt" = "Stop" ]; then sudo /etc/init.d/apache2 stop elif [ "$opt" = "Status" ]; then sudo /etc/init.d/apache2 status fi done elif [ "$opt" = "Postfix" ]; then select opt in $POSTFIXOPTIONS; do if [ "$opt" = "Restart" ]; then sudo /etc/init.d/postfix restart elif [ "$opt" = "Start" ]; then sudo /etc/init.d/postfix start elif [ "$opt" = "Stop" ]; then sudo /etc/init.d/postfix stop elif [ "$opt" = "Status" ]; then sudo /etc/init.d/postfix status fi done elif [ "$opt" = "Dovecot" ]; then select opt in $DOVECOTOPTIONS; do if [ "$opt" = "Restart" ]; then sudo /etc/init.d/dovecot restart elif [ "$opt" = "Start" ]; then sudo /etc/init.d/dovecot start elif [ "$opt" = "Stop" ]; then sudo /etc/init.d/dovecot stop elif [ "$opt" = "Status" ]; then sudo /etc/init.d/dovecot status fi done elif [ "$opt" = "All" ]; then sudo /etc/init.d/apache2 restart sudo /etc/init.d/postfix restart sudo /etc/init.d/dovecot restart fi done

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• Executing bat file and returning the prompt

  - by Lieven Cardoen

  I have a problem with cruisecontrol where an ant scripts executes a bat file that doesn't give me the prompt back. As a result, the project in cruisecontrol keeps on bulding forever until I restart cruisecontrol. How can I resolve this? It's a startup.bat from wowza (Streaming Server) that I'm executing: @echo off call setenv.bat if not %WMSENVOK% == "true" goto end set _WINDOWNAME="Wowza Media Server 2" set _EXESERVER= if "%1"=="newwindow" ( set _EXESERVER=start %_WINDOWNAME% shift ) set CLASSPATH="%WMSAPP_HOME%\bin\wms-bootstrap.jar" rem cacls jmxremote.password /P username:R rem cacls jmxremote.access /P username:R rem NOTE: Here you can configure the JVM's built in JMX interface. rem See the "Server Management Console and Monitoring" chapter rem of the "User's Guide" for more information on how to configure the rem remote JMX interface in the [install-dir]/conf/Server.xml file. set JMXOPTIONS=-Dcom.sun.management.jmxremote=true rem set JMXOPTIONS=%JMXOPTIONS% -Djava.rmi.server.hostname=192.168.1.7 rem set JMXOPTIONS=%JMXOPTIONS% -Dcom.sun.management.jmxremote.port=1099 rem set JMXOPTIONS=%JMXOPTIONS% -Dcom.sun.management.jmxremote.authenticate=false rem set JMXOPTIONS=%JMXOPTIONS% -Dcom.sun.management.jmxremote.ssl=false rem set JMXOPTIONS=%JMXOPTIONS% -Dcom.sun.management.jmxremote.password.file= "%WMSCONFIG_HOME%/conf/jmxremote.password" rem set JMXOPTIONS=%JMXOPTIONS% -Dcom.sun.management.jmxremote.access.file= "%WMSCONFIG_HOME%/conf/jmxremote.access" rem log interceptor com.wowza.wms.logging.LogNotify - see Javadocs for ILogNotify %_EXESERVER% "%_EXECJAVA%" %JAVA_OPTS% %JMXOPTIONS% -Dcom.wowza.wms.AppHome="%WMSAPP_HOME%" -Dcom.wowza.wms.ConfigURL="%WMSCONFIG_URL%" -Dcom.wowza.wms.ConfigHome="%WMSCONFIG_HOME%" -cp %CLASSPATH% com.wowza.wms.bootstrap.Bootstrap start :end

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• paypal address1 HTML name doensnt work?

  - by ajsie

  i use this code to send the customer to the paypals payment page: <form action="https://www.paypal.com/cgi-bin/webscr" method="post"> <input type='hidden' name='cmd' value='_cart' /> <input type='hidden' name='upload' value='1' /> <input type="hidden" name="business" value="[email protected]"> <input type="hidden" name="currency_code" value="SEK"> <input type="hidden" name="return" value="http://freelanceswitch.com/payment-complete/"> <input type="hidden" name="item_number_1" value="01 - General Payment"> <input type="hidden" name="item_name_1" size="45"> <input type="hidden" name="amount_1" size="45"> <input type="hidden" name="item_number_2" value="01 - Bonus Payment"> <input type="hidden" name="item_name_2" size="45"> <input type="hidden" name="amount_2" size="45"> <!-- PREPOPULATING FIELDS --> <input type='hidden' name='address1' value='Open Bridge street 19' /> <input type='hidden' name='address2' value='Easter heaven garden 12' /> <input type='hidden' name='first_name' value='Peter' /> <input type='hidden' name='last_name' value='Hansen' /> <input type="submit" name="Submit" value="Submit"> </form> everything works except the address1 and address2 in PREPOPULATING FIELDS. the fields for the Billing Address Line 1 and Billing Address Line 2 are empty. anyone knows why?

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• Programmatically talking to a Serial Port in OS X or Linux

  - by deadprogrammer

  I have a Prolite LED sign that I like to set up to show scrolling search queries from a apache logs and other fun statistics. The problem is, my G5 does not have a serial port, so I have to use a usb to serial dongle. It shows up as /dev/cu.usbserial and /dev/tty.usbserial . When i do this everything seems to be hunky-dory: stty -f /dev/cu.usbserial speed 9600 baud; lflags: -icanon -isig -iexten -echo iflags: -icrnl -ixon -ixany -imaxbel -brkint oflags: -opost -onlcr -oxtabs cflags: cs8 -parenb Everything also works when I use the serial port tool to talk to it. If I run this piece of code while the above mentioned serial port tool, everthing also works. But as soon as I disconnect the tool the connection gets lost. #!/usr/bin/python import serial ser = serial.Serial('/dev/cu.usbserial', 9600, timeout=10) ser.write("<ID01><PA> \r\n") read_chars = ser.read(20) print read_chars ser.close() So the question is, what magicks do I need to perform to start talking to the serial port without the serial port tool? Is that a permissions problem? Also, what's the difference between /dev/cu.usbserial and /dev/tty.usbserial?

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• VERY simple C program won't compile with VC 64

  - by Paperflyer

  Here is a very simple C program: #include <stdio.h> int main (int argc, char *argv[]) { printf("sizeof(short) = %d\n",(int)sizeof(short)); printf("sizeof(int) = %d\n",(int)sizeof(int)); printf("sizeof(long) = %d\n",(int)sizeof(long)); printf("sizeof(long long) = %d\n",(int)sizeof(long long)); printf("sizeof(float) = %d\n",(int)sizeof(float)); printf("sizeof(double) = %d\n",(int)sizeof(double)); return 0; } While it compiles fine on Win32 (command line: cl main.c), it does not using the Win64 compiler ("c:\Program Files(x86)\Microsoft Visual Studio 9.0\VC\bin\amd64\cl.exe" main.c). Specifically, it sais "error LNK2019: unresolved external symbol printf referenced in function main". As far as I understand this, it can not link to printf, right? Obviously, I have Microsoft Visual C++ Compiler 2008 (Standard enu) x86 and x64 installed and am using the 64-bit flavor of Windows (7). What is the problem here?

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• Installing Gtk2 on portable strawberry

  - by XoR

  I downloaded "strawberry-perl-5.12.2.0-portable" and "gtk+-bundle_2.22.1-20101227_win32". I extracted strawberry-perl in some directory and there I put gtk folder with gtk stuff. In portableshell.bat I changed Path env and added: "%drivep%\gtk\bin;%drivep%\gtk\lib;". Don't ask me why I added lib directory, I saw that some guy added it in some website. When I run in portableshell command: "pkg-config --libs --cflags gtk+-2.0" I get: c:\test>pkg-config --libs --cflags gtk+-2.0 -mms-bitfields -Ic:/test/gtk/include/gtk-2.0 -Ic:/test/gtk/lib/gtk-2.0/include - Ic:/test/gtk/include/atk-1.0 -Ic:/test/gtk/include/cairo -Ic:/test/gtk/include/g dk-pixbuf-2.0 -Ic:/test/gtk/include/pango-1.0 -Ic:/test/gtk/include/glib-2.0 -Ic :/test/gtk/lib/glib-2.0/include -Ic:/test/gtk/include -Ic:/test/gtk/include/free type2 -Ic:/test/gtk/include/libpng14 -Lc:/test/gtk/lib -lgtk-win32-2.0 -lgdk-wi n32-2.0 -latk-1.0 -lgio-2.0 -lpangowin32-1.0 -lgdi32 -lpangocairo-1.0 -lgdk_pixb uf-2.0 -lpango-1.0 -lcairo -lgobject-2.0 -lgmodule-2.0 -lgthread-2.0 -lglib-2.0 -lintl All folders looks fine, I also have complete log of compiling glib here. It looks like it doesn't compile because pkg-config gives bad data, or something. Does anyone have some idea how to make this thing work?

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• Bash script to log in over SSH

  - by user1042928

  Sorry if this seems like a dumb question but I am just learning bash scripting. For a school project we need to code an RTX that runs in Unix. It runs as a process in terminal and takes in user input and then prints it to the screen. I want to write a bash script to test that it can respond to lots of quick user input without overflowing or failing. My main problem is that once the RTX starts the bash script will stop on that line until the RTX terminates and only then print the loop to the terminal (instead of printing it to the RTX prompt as I intend it to). I have tried running the RTX in the background but that didn't work. I need to find a way to redirect input to the RTX while it is still running with a bash script. Google searches didn't come up with examples that I understood/could adapt. Any help is appreciated. #!/bin/bash # declare STRING variable STRING="RTX Worked =D" #Start the rtx in a new process, stuck on this line until rtx terminates. ./main #Somehow redirect io to the rtx. for i in `seq 1 100`; do echo $i echo " \n" done echo $STRING

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• Bash Templating: How to build configuration files from templates with Bash?

  - by FractalizeR

  Hello. I'm writting a script to automate creating configuration files for Apache and PHP for my own webserver. I don't want to use any GUIs like CPanel or ISPConfig. I have some templates of Apache and PHP configuration files. Bash script needs to read templates, make variable substitution and output parsed templates into some folder. What is the best way to do that? I can think of several ways. Which one is the best or may be there are some better ways to do that? I want to do that in pure Bash (it's easy in PHP for example) 1)http://stackoverflow.com/questions/415677/how-to-repace-variables-in-a-nix-text-file template.txt: the number is ${i} the word is ${word} script.sh: #!/bin/sh #set variables i=1 word="dog" #read in template one line at the time, and replace variables #(more natural (and efficient) way, thanks to Jonathan Leffler) while read line do eval echo "$line" done < "./template.txt" BTW, how do I redirect output to external file here? Do I need to escape something if variables contain, say, quotes? 2) Using cat & sed for replacing each variable with it's value: Given template.txt: The number is ${i} The word is ${word} Command: cat template.txt | sed -e "s/\${i}/1/" | sed -e "s/\${word}/dog/" Seems bad to me because of the need to escape many different symbols and with many variables the line will be tooooo long. Can you think of some other elegant and safe solution?

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• Better viewing of postfix mail queue files than postcat?

  - by Geekman

  So I got a call early this morning about a client needing to see what email they have waiting to be delivered sitting in our secondary mail server. Their link for the main server had (still is) been down for two days and they needed to see their email. So I wrote up a quick perl script to use mailq in combination with postcat to dump each email for their address into separate files, tar'd it up and sent it off. Horrible code, I know, but it was urgent. My solution works OK in that it at least gives a raw view, but I thought tonight it would be nice if I had a solution where I could provide their email attachments and maybe remove some "garbage" header text as well. Most of the important emails seem to have a PDF or similar attached. I've been looking around but the only method of viewing queue files I can see is the postcat command, and I really don't want to write my own parser - so I was wondering if any of you have already done so, or know of a better command to use? Here's the code for my current solution: #!/usr/bin/perl $qCmd="mailq | grep -B 2 \"someemailaddress@isp\" | cut -d \" \" -f 1"; @data = split(/\n/, `$qCmd`); $i = 0; foreach $line (@data) { $i++; $remainder = $i % 2; if ($remainder == 0) { next; } if ($line =~ /\(/ || $line =~ /\n/ || $line eq "") { next; } print "Processing: " . $line . "\n"; `postcat -q $line > $line.email.txt`; $subject=`cat $line.email.txt | grep "Subject:"`; #print "SUB" . $subject; #`cat $line.email.txt > \"$subject.$line.email.txt\"`; } Any advice appreciated.

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• Problem Linking Boost Filesystem Library in Microsoft Visual C++

  - by Scott

  Hello. I am having trouble getting my project to link to the Boost (version 1.37.0) Filesystem lib file in Microsoft Visual C++ 2008 Express Edition. The Filesystem library is not a header-only library. I have been following the Getting Started on Windows guide posted on the official boost web page. Here are the steps I have taken: I used bjam to build the complete set of lib files using: bjam --build-dir="C:\Program Files\boost\build-boost" --toolset=msvc --build-type=complete I copied the /libs directory (located in C:\Program Files\boost\build-boost\boost\bin.v2) to C:\Program Files\boost\boost_1_37_0\libs. In Visual C++, under Project Properties Additional Library Directories I added these paths: C:\Program Files\boost\boost_1_37_0\libs C:\Program Files\boost\boost_1_37_0\libs\filesystem\build\msvc-9.0express\debug\link-static\threading-multi I added the second one out of desperation. It is the exact directory where libboost_system-vc90-mt-gd-1_37.lib resides. In Configuration Properties C/C++ General Additional Include Directories I added the following path: C:\Program Files\boost\boost_1_37_0 Then, to put the icing on the cake, under Tools Options VC++ Directories Library files, I added the same directories mentioned in step 3. Despite all this, when I build my project I get the following error: fatal error LNK1104: cannot open file 'libboost_system-vc90-mt-gd-1_37.lib' Additionally, here is the code that I am attempting to compile as well as a screen shot of the aformentioned directory where the (assumedly correct) lib file resides: #include "boost/filesystem.hpp" // includes all needed Boost.Filesystem declarations #include <iostream> // for std::cout using boost::filesystem; // for ease of tutorial presentation; // a namespace alias is preferred practice in real code using namespace std; int main() { cout << "Hello, world!" << endl; return 0; } Can anyone help me out? Let me know if you need to know anything else. As always, thanks in advance.

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• Paypal sandbox account in dotnet: "IPN Response invalid"

  - by Sam

  I am integrating Paypal with my website. I use a sandbox account, one buyer account and one seller account. I downloaded the code below from Paypal: string strSandbox = "https://www.sandbox.paypal.com/cgi-bin/webscr"; HttpWebRequest req = (HttpWebRequest)WebRequest.Create(strSandbox); //Set values for the request back req.Method = "POST"; req.ContentType = "application/x-www-form-urlencoded"; byte[] param = Request.BinaryRead(HttpContext.Current.Request.ContentLength); string strRequest = Encoding.ASCII.GetString(param); strRequest += "&cmd=_notify-validate"; req.ContentLength = strRequest.Length; //for proxy //WebProxy proxy = new WebProxy(new Uri("http://url:port#")); //req.Proxy = proxy; //Send the request to PayPal and get the response StreamWriter streamOut = new StreamWriter(req.GetRequestStream(), System.Text.Encoding.ASCII); streamOut.Write(strRequest); streamOut.Close(); StreamReader streamIn = new StreamReader(req.GetResponse().GetResponseStream()); string strResponse = streamIn.ReadToEnd(); streamIn.Close(); if (strResponse == "VERIFIED") { //check the payment_status is Completed //check that txn_id has not been previously processed //check that receiver_email is your Primary PayPal email //check that payment_amount/payment_currency are correct //process payment } else if (strResponse == "INVALID") { //log for manual investigation } else { //log response/ipn data for manual investigation } When I add this snippet in my pageload event of my success page, I show the IPN response as INVALID, but amount is paid successfully. Why is this? Paypal's docs are not clear.

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