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  • How do I redirect a user using Apache Rewrite, to the fully qualified domain name?

    - by Mark
    Hi Guys, I'm really new to apache mod_rewrite module. I have a page called http://abc in my company intranet. I want users to be redirected to http://abc.somecompanyname.com whenever they type http://abc to the URL bar. Could someone please provide and example or point me in the right direction. I figure this should be quite an easy question to answer. Thanks everyone for you inputs. -Mark

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  • how to delete findDependentRowset result in Zend Framework

    - by Behrang
    I have place model & entry model that entry is parent everything is fine but how can I delete the result row $categoryPlacements in place model: $entryModel = new Model_EntryModel(); $entryRow = $entryModel-find ( $entryId )-current (); $categoryPlacements = $entryRow-findDependentRowset($this); in this case i want to delete the $categoryPlacements result in place model I can use categoryPlacements-toarray() and then delete but is another easy way?

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  • Cannot call action method 'System.Web.Mvc.PartialViewResult Foo[T](T)' on controller 'Controller' be

    - by MedicineMan
    Cannot call action method 'System.Web.Mvc.PartialViewResult FooT' on controller 'Controller' because the action method is a generic method <% Html.RenderAction("Foo", model = Model}); %> Is there a workaround for this limitation on ASP MVC 2? I would really prefer to use a generic. The workaround that I have come up with is to change the model type to be an object. It works, but is not preferred: public PartialViewResult Foo<T>(T model) where T : class { // do stuff }

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  • Correct model for a database with a table for each user.

    - by BAH
    Kinda stuck here... I have an application with lets say 5000 rows of data per user and was wondering if it was right or wrong to do it this way: On user account creation a new table is created (UserData_[UserID]) or should I just have 1 table for userdata and have everything in there with a column for userid? The reason I am stuck at the moment is that it seems NHibernate isn't able to be mapped to dynamic table names without creating another ISessionFactory which has alot of overhead AFAIK. Any help would be greatly appreciated. Thanks.

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  • sql "Group By" and "Having"

    - by Hans Rudel
    im trying to work through some questions and im not sure how to do the following Q:Find the hard drive sizes that are equal among two or more PCs. its q15 on this site http://www.sql-ex.ru/learn_exercises.php#answer_ref The database scheme consists of four tables: Product(maker, model, type) PC(code, model, speed, ram, hd, cd, price) Laptop(code, model, speed, ram, hd, screen, price) Printer(code, model, color, type, price) any pointers would be appreciated.

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  • Rails 3: How to validate that A < B where A and B are both model attributes ?

    - by Misha Moroshko
    I would like to validate that customer_price >= my_price. I tried the following: class Product < ActiveRecord::Base attr_accessor :my_price validates_numericality_of :customer_price, :greater_than_or_equal_to => my_price ... end (customer_price is a column in the Products table in the database, while my_price isn't.) Here is the result: NameError in ProductsController#index undefined local variable or method `my_price' for #<Class:0x313b648> What is the right way to do this in Rails 3 ?

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  • php session not working (as with cookies disabled), but cookies are enabled for the domain. What oth

    - by SWilk
    Hi, I have a problem with a client, who cannot log in to our system. We have PHP-based B2B system, which uses cookies to store session-id. The client cannot log in and is redirected to the login page, without any error message. He claims he have cookies enabled in his Firefox. Also, if he had cookies disabled, my javascript would detect this and would show him an red, very descriptive error info. He does not seen anything like this. What else could have same effect on sessions like disabled cookies in browser? Are there any proxies which filters cookies? Any AV software, etc? What to look for? Our login form works for any other user without problems.

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  • Django: get count of ForeignKey item in template?

    - by AP257
    Straightforward question - apologies if it is a duplicate, but I can't find the answer if so. I have a User model and a Submission model, like this: class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) How can I show the number of Submissions made by each user in the template? I've tried {{ user.submission.count }}, like this: for user in users: {{ user.name }} ({{ user.submission.count }} submissions) but no luck...

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  • How do I set up for sharing code (ASP.NET) across multiple domain names?

    - by Scott J.
    I have built a website and now the customer wants to split it between three different domains. What is the best way to do this? This is what I have so far. c:/website1/ points to www.website1.com c:/website1/vd1/ points to www.website2.com c:/website1/vd2/ points to www.website3.com The webhost I'm working with has done it the following way, but now I'm getting a bunch of errors that seems like it's not seeing the App_code folder. Do I need to make a lot of changes? How does this affect the location references?

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  • How to page multiple data sets in ASP.NET MVC

    - by REA_ANDREW
    On a single view I will have three sets of paged data. Which means for each model I will have The Objects The Page Index The Page Size My initial thought was for example: public class PagedModel<T> where T:class { public IList<T> Objects { get; set; } public int ModelPageIndex { get; set; } public int ModelPageSize { get; set; } } Then having a model which is to be supplied to the action as for example: public class TypesViewModel { public PagedModel<ObjectA> Types1 { get; set; } public PagedModel<ObjectB> Typed2 { get; set; } public PagedModel<ObjectC> Types3 { get; set; } } So if I then for example have the Index view inherit from the type: System.Web.Mvc.ViewPage<uk.co.andrewrea.forum.Web.Models.TypesViewModel> Now my initial aciton method for the index is simply: public ActionResult Index() { var forDisplayPurposes = new TypesViewModel(); return View(forDisplayPurposes); } If I then want to page, it is here where I am struggling to decide which action to take. Lets say that I select the next page of the Types2 PageModel. What should the action look like for this in order to return the new view showing the second page of the Types2 PageModel I was thinking possibly to duplicate the action but use it with POST [AcceptVerbs(HttpVerbs.Post)] public ActionResult Index(TypesViewModel model) { return View(model); } Is this a good way to approach it. I understand there is always Session, but I was just wondering how such a thing is achieved currently out there. If any best methods have been mutually accepted and things. So simply, one page with multiple paged models. How to persist the data for each using a wrapper model. Which way should you pass in the model and which way should you page the data, i.e. Form Post Lastly, I have seen the routes take this into account i.e. {controller}/{action}/{id}/{pageindex}/{pagesize} but this only accounts for one model and I do not really wwant to repeat the pagesize and pageindex values for the number of models I have inside the wrapper model. Thanks for your time!! Andrew

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  • can I add properties to a typo3 extbase domain model object?

    - by The Newbie Qs
    I want to store a username in a coupon object, each coupon object already has the uid of the user who created it. I can loop over the coupon objects and read the associated usernames from fe_users but how then will I save those usernames into the coupons so when they are passed to the template the usernames can be read like so coupon.username, or in some other easy way so each username will appear on the page with the right coupon as they are all printed out in a table? If I was doing basic php instead of typo3 i would just define a query but what is the typo3 v4.5 way? My code so far - which dies on the line where I try to assign the new property --creatorname -- to the $coup object. public function listAction() { $coupons = $this->couponRepository->findAll(); // @var Tx_Extbase_Domain_Repository_FrontendUserRepository $userRepository */ $userRepository = $this->objectManager->get("Tx_Extbase_Domain_Repository_FrontendUserRepository"); foreach ($coupons as $coup) { echo '<br />test '.$coup->getCreator(); echo '<br />count = '.$userRepository->countAll().'<br />'; $newObject = $userRepository->findByUid( intval($coup->getCreator())); //var_dump($newObject); var_dump($coup); echo '<br />getUsername '.$newObject->getUsername() ; $coup['creatorname'] = $newObject->getUsername(); echo '<br />creatorname '.$coup['creatorname'] ; } $this->view->assign('coupons', $coupons); }

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  • When saving a model with has_one or has_many associations, which side of the association is saved fi

    - by SeeBees
    I have three simplified models: class Team < ActiveRecord::Base has_many :players has_one :coach end class Player < ActiveRecord::Base belongs_to :team validates_presence_of :team_id end class Coach < ActiveRecord::Base belongs_to :team validates_presence_of :team_id end I use the following code to test these models: t = Team.new team.coach = Coach.new team.save! team.save! returns true. But in another test: t = Team.new team.players << Player.new team.save! team.save! gives the following error: > ActiveRecord::RecordInvalid: > Validation failed: Players is invalid > from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/validations.rb:1090:in > `save_without_dirty!' from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/dirty.rb:87:in `save_without_transactions!' from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/transactions.rb:200:in > `save!' from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/connection_adapters/abstract/database_statements.rb:136:in > `transaction' from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/transactions.rb:182:in > `transaction' from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/transactions.rb:200:in > `save!' from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/transactions.rb:208:in > `rollback_active_record_state!' from > /usr/lib/ruby/gems/1.8/gems/activerecord-2.3.4/lib/active_record/transactions.rb:200:in > `save!' from (irb):14 I figured out that when team.save! is called, it first calls player.save!. player needs to validate the presence of the id of the associated team. But at the time player.save! is called, team hasn't been saved yet, and therefore, team_id doesn't yet exist for player. This fails the player's validation, so the error occurs. But on the other hand, team is saved before coach.save!, otherwise the first example will get the same error as the second one. So I've concluded that when a has_many bs, a.save! will save bs prior to a. When a has_one b, a.save! will save a prior to b. If I am right, why is this the case? It doesn't seem logical to me. Why do has_one and has_many association have different order in saving? Any ideas? And is there any way I can change the order? Say I want to have the same saving order for both has_one and has_many. Thanks.

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  • Problem: connecting to drupal on hostgator without pointed domain.

    - by Kirk
    I need to connect to drupal on a website that I'm programming on a hostgator account. The website that I'm working on currently receives a lot of traffic, and I would like to make sure that it is fully functional before I launch the new website. The old website was programmed with .asp which hostgator doesn't support, and the old webhost doesn't support drupal or .php which are integral to the new web design. Drupal 6 has been freshly installed on my website, but when I try to login, it redirects me to http://gator83.hostgator.com/?q=node&destination=node instead of the drupal control panel. Is it possible to work around this? Thank you in advance.

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  • Django left join m2m field.

    - by duder
    Here's my Model: class User(models.Model): pass class Item(models.Model): pass class ItemVote(models.Model): user = models.ForeignKey(User) item = models.ForeignKey(Item) vote = models.BooleanField() I want to retrieve a list of Items, and I want to know if the current user has voted for each Item. How do I alter my query object so that it will generate sql similar to: SELECT ... FROM items LEFT OUTER JOIN item_votes ON (item_votes.user_id = ? AND item_votes.item_id = items.id)

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  • email sending issue in Outlook 2007

    - by rookie
    Hi I am unable to send emails to recipients who are outside our domain from outlook 2007. I am able to send email to the same domain. The error i am getting is Your message did not reach some or all of the intended recipients. Subject: test subject Sent: 2/19/2010 7:44 PM The following recipient(s) cannot be reached: test, user on 2/19/2010 7:44 PM 553 sorry, that domain isn't in my list of allowed rcpthosts (#5.7.1) PN: I am able to send the emails to any domain from webmail.

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  • MySQL: check whether two fields on a model are always the same?

    - by AP257
    Sorry if this is a duplicate question, I'm a total database newbie and I'm probably using the wrong terminology to search for answers. I have a MySQL table as follows: +------------+---------------+------+-----+---------+-------+ | Field | Type | Null | Key | Default | Extra | +------------+---------------+------+-----+---------+-------+ | placeid | int(11) | NO | PRI | NULL | | | grid | varchar(120) | YES | | NULL | | | vill | varchar(300) | YES | | NULL | | +------------+---------------+------+-----+---------+-------+ I'd like to find out whether 'grid' and 'vill' always occur in the same combinations or not. Maybe it'd be clearer with an example: placeid, grid, vill 1, TM1, Suffolk 2, TM1, Suffolk 3, WA8, Newcastle 4, WA8, Newcastle 5, WA8, York I'd like to construct a query that returns 'WA8' but not 'TM1', because 'WA8' occurs in combination with more than one vill. I would be SO grateful for any help!

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  • SVN repository browser issue

    - by williang
    Hi, I use TortoiseSVN on WindowsXP and ran into an issue inside repository browser today. Basically, I can browser/checkout fine at application level "https://domain/svn/app1". However, When I try to browse at the root level of the repository "https://domain/svn/", the following error msg displays: OPTIONS of 'https://domain/svn': 200 OK I try to access https://domain/svn in a web browser, I can see all the applications there. Thanks

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  • How to get the domain name from an url with PHP?

    - by ilhan
    For example http://www.google.com/ -> google.com http://www.ma219.metu.edu.tr -> metu.edu.tr https://www.nic.tr/ -> nic.tr http://www.plasticsurgery.a.bg/ -> plasticsurgery.a.bg www.abv.bg -> abv.bg abv.bg -> abv.bg The output should not have subdomain. Edit: It would be great if we were able to read http://mxr.mozilla.org/mozilla/source/netwerk/dns/src/effective_tld_names.dat?raw=1

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  • How do I go about link web content in a database with a nested set model?

    - by wb
    My nested set table is as follows. create table depts ( id int identity(0, 1) primary key , lft int , rgt int , name nvarchar(60) , abbrv nvarchar(20) ); Test departments. insert into depts (lft, rgt, name, abbrv) values (1, 14, 'root', 'r'); insert into depts (lft, rgt, name, abbrv) values (2, 3, 'department 1', 'd1'); insert into depts (lft, rgt, name, abbrv) values (4, 5, 'department 2', 'd2'); insert into depts (lft, rgt, name, abbrv) values (6, 13, 'department 3', 'd3'); insert into depts (lft, rgt, name, abbrv) values (7, 8, 'sub department 3.1', 'd3.1'); insert into depts (lft, rgt, name, abbrv) values (9, 12, 'sub department 3.2', 'd3.2'); insert into depts (lft, rgt, name, abbrv) values (10, 11, 'sub sub department 3.2.1', 'd3.2.1'); My web content table is as follows. create table content ( id int identity(0, 1) , dept_id int , page_name nvarchar(60) , content ntext ); Test content. insert into content (dept_id, page_name, content) values (3, 'index', '<h2>welcome to department 3!</h2>'); insert into content (dept_id, page_name, content) values (4, 'index', '<h2>welcome to department 3.1!</h2>'); insert into content (dept_id, page_name, content) values (6, 'index', '<h2>welcome to department 3.2.1!</h2>'); insert into content (dept_id, page_name, content) values (2, 'what-doing', '<h2>what is department 2 doing?/h2>'); I'm trying to query the correct page content (from the content table) based on the url given. I can easily accomplish this task with a root department. However, querying a department with multiple depths is proving to be a little harder. For example: http://localhost/departments.asp?d3/ (Should return <h2>welcome to department 3!</h2>) http://localhost/departments.asp?d2/what-doing (Should return <h2>what is department 2 doing?</h2>) I'm not sure if this can be create in one query or if there will need to be a recursive function of some sort. Also, if there is nothing after the last / then assume we want the index page. How can this be accomplished? Thank you.

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  • Jsf validation error (shown by h:message) while updating Model, why?

    - by Ignacio
    List.xhtml: <h:selectOneMenu value="#{produtosController.selected.codigo}"> <f:selectItems value="#{produtosController.itemsAvailableSelectOne}"/> </h:selectOneMenu> <h:commandButton action="#{produtosController.createByCodigos}" value="Buscar" /> Controller Class method: public String createByCodigos(){ items = new ListDataModel(ejbFacade.findByCodigos(current.getCodigo())); updateCurrentItem(); return "List"; } Facade Class method: public List<Produtos> findByCodigos(Integer codigo){ Query q = em.createNamedQuery("Produtos.findByCodigo"); q.setParameter("codigo", codigo); return q.getResultList(); } Bean Class query: @NamedQuery(name = "Produtos.findByCodigo", query = "SELECT p FROM Produtos p WHERE p.codigo = :codigo") @Column(name = "codigo") private Integer codigo;

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  • Model of hql query firing at back end by hql engine?

    - by Maddy.Shik
    I want to understand how hibernate execute hql query internally or in other models how hql query engine works. Please suggest some good links for same? One of reason for reading is following problem. Class Branch { //lazy loaded @joincolumn(name="company_id") Company company; } Since company is heavy object so it is lazy loaded. now i have hql query "from Branch as branch where branch.Company.id=:companyId" my concern is that if for firing above query, hql engine has to retrieve company object then its a performance hit and i would prefer to add one more property in Branch class i.e. companyId. So in this case hql query would be "from Branch as branch where branch.companyId=:companyId" If hql engine first generate sql from hql followed by firing of sql query itself, then there should be no performance issue. Please let me know if problem is not understandable.

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