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  • GTK implementation of MessageBox

    - by Bernard
    I have been trying to implement Win32's MessageBox using GTK. The app using SDL/OpenGL, so this isn't a GTK app. I handle the initialisation (gtk_init) sort of stuff inside the MessageBox function as follows: int MessageBox(HWND hwnd, const char* text, const char* caption, UINT type){ GtkWidget *window = NULL; GtkWidget *dialog = NULL; gtk_init(&gtkArgc, &gtkArgv); window = gtk_window_new(GTK_WINDOW_TOPLEVEL); g_signal_connect(G_OBJECT(window), "delete_event", G_CALLBACK(delete_event), NULL); g_signal_connect(G_OBJECT(window), "destroy", G_CALLBACK(destroy), NULL); // gcallback calls gtk_main_quit() gtk_init_add((GtkFunction)gcallback, NULL); if (type & MB_YESNO) { dialog = gtk_message_dialog_new(GTK_WINDOW(window), GTK_DIALOG_DESTROY_WITH_PARENT, GTK_MESSAGE_QUESTION, GTK_BUTTONS_YES_NO, text); } else { dialog = gtk_message_dialog_new(GTK_WINDOW(window), GTK_DIALOG_DESTROY_WITH_PARENT, GTK_MESSAGE_INFO, GTK_BUTTONS_OK, text); } gtk_window_set_title(GTK_WINDOW(dialog), caption); gint result = gtk_dialog_run(GTK_DIALOG(dialog)); gtk_main(); gtk_widget_destroy(dialog); if (type & MB_YESNO) { switch (result) { default: case GTK_RESPONSE_DELETE_EVENT: case GTK_RESPONSE_NO: return IDNO; break; case GTK_RESPONSE_YES: return IDYES; break; } } return IDOK;} Now, I am by no means an experienced GTK programmer, and I realise that I'm probably doing something(s) horribly wrong. However, my problem is that the last dialog popped up with this function stays around until the process exits. Any ideas?

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  • NullPointerException when installing the Android SDK on Mac OS X

    - by Feanor
    I'm installing the Android SDK on Mac OS X. Following the instructions on the Android Development site, I've downloaded the SDK and modified my .bash_profile to include the path. The next step is to use the Android SDK and AVD Manager to actually download the platforms. However, when I use the Manager to install the platforms, I get the following error in the Terminal. I've looked around for similar problems in the Eclipse and Android forums and haven't found anything yet. Is something else damaged in the environment and needs to be repaired? Any recommendations on where I should look? java.lang.NullPointerException at org.eclipse.swt.graphics.Device.getFontList(Unknown Source) at org.eclipse.jface.resource.FontRegistry.filterData(FontRegistry.java:456) at org.eclipse.jface.resource.FontRegistry.createFont(FontRegistry.java:490) at org.eclipse.jface.resource.FontRegistry.defaultFontRecord(FontRegistry.java:551) at org.eclipse.jface.resource.FontRegistry.defaultFontData(FontRegistry.java:563) at org.eclipse.jface.resource.FontRegistry.getFontData(FontRegistry.java:579) at org.eclipse.jface.dialogs.Dialog.dialogFontIsDefault(Dialog.java:1077) at org.eclipse.jface.dialogs.Dialog.applyDialogFont(Dialog.java:998) at org.eclipse.jface.dialogs.Dialog.createContents(Dialog.java:756) at org.eclipse.jface.window.Window.create(Window.java:431) at org.eclipse.jface.dialogs.Dialog.create(Dialog.java:1089) at com.android.sdkuilib.internal.repository.UpdateChooserDialog.create(UpdateChooserDialog.java:280) at org.eclipse.jface.window.Window.open(Window.java:790) at com.android.sdkuilib.internal.repository.UpdaterData.updateOrInstallAll(UpdaterData.java:502) at com.android.sdkuilib.internal.repository.RemotePackagesPage.onInstallSelectedArchives(RemotePackagesPage.java:323) at com.android.sdkuilib.internal.repository.RemotePackagesPage.access$600(RemotePackagesPage.java:54) at com.android.sdkuilib.internal.repository.RemotePackagesPage$7.widgetSelected(RemotePackagesPage.java:168) at org.eclipse.swt.widgets.TypedListener.handleEvent(Unknown Source) at org.eclipse.swt.widgets.EventTable.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Display.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.sendEvent(Unknown Source) at org.eclipse.swt.widgets.Widget.notifyListeners(Unknown Source) at org.eclipse.swt.widgets.Display.runDeferredEvents(Unknown Source) at org.eclipse.swt.widgets.Display.readAndDispatch(Unknown Source) at com.android.sdkuilib.internal.repository.UpdaterWindowImpl.open(UpdaterWindowImpl.java:104) at com.android.sdkuilib.repository.UpdaterWindow.open(UpdaterWindow.java:110) at com.android.sdkmanager.Main.showMainWindow(Main.java:281) at com.android.sdkmanager.Main.doAction(Main.java:247) at com.android.sdkmanager.Main.run(Main.java:92) at com.android.sdkmanager.Main.main(Main.java:81) logout

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  • WPF Textbox & Borders - curious resizing behavior

    - by CitizenParker
    The following XAML produces a window with strange behavior around the textbox: <Window x:Class="WpfSandbox.CuriousExample" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="CuriousExample" Height="300" Width="300"> <DockPanel Margin="15"> <TextBox BorderThickness="1" BorderBrush="#FF000000"></TextBox> </DockPanel> </Window> What happens, at least during my limited testing, is that the textbox renders with an inset border pattern (top/left is black, right/bottom is grey). However, when you resize to any position except the original, the entire textbox border goes to black. Whenever you return the window to the exact number of on-screen pixels the form had when it first loaded, it's inset again. I'm guessing it isn't pixel snapping as I can easily correct the problem with this code: <Window x:Class="WpfSandbox.CuriousExample" xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml" Title="CuriousExample" Height="300" Width="300"> <DockPanel Margin="15"> <Border BorderThickness="1" BorderBrush="#FF000000"> <TextBox BorderThickness="0" ></TextBox> </Border> </DockPanel> </Window> Anyone care to venture an explanation as to what I'm seeing? Or is it all in my head? Like I said, the above workaround can resolve this problem - just trying to understand what is happening here. Thanks, -Scott

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  • Controling virtualbox internet access?

    - by HandyGandy
    I am finally going through the process of moving my XP into a vbox (host linux). The thing is that I am migrating a virtually clean install. So aside from the occasional antivirus scan, I want to make sure that my XP is not sending malware data (keystoke.logs, spam etc. ) out silently ( and thus having picked up some virus ). To that end I want to limit XP to contacting my LAN and a few internet sites. ( mainly sites that require proprietary windows only software to access, AV sites and Windows update ). I want XP to only access preapproved addresses. If it is trying to contact a nonapproved address, I want it somehow logged and access restricted until I allow access. I also don't want to have to decide whether to allow access to a site at my leisure. To keeps things clear let me give an example: I start my vbox/XP ( which I call MYXP) running on my linux box ( called MYLINUX connecting to the net through a linksys wrt54g ) and connects via samba to my LAN ( since my LAN seems to be possessed of every evil thing, it's address is 192.168.666. ). At the moment my configuration is set so that I allow MYXP to access 192.168.666 and www.MYANTIVIRUS_UPDATES.com and www.MS_UPDATES.com. Then on the VM I start a program which tries to make a connection to www.playmygame.com . www.playmygame.com is on my preapproved list so the connection goes through. Later I check attempted accesses and discover that it also tried to connect to www.mygame_high_scores.com I figure this is OK so I add www.mygame_high_scores.com to my approved list. Later, I again check address and discover that my VM/XP tried to access www.mygame_steals_your_identity.com. I do some checking and discover the address is registered to someone in Kiev, Nigeria. Since this doesn't sound kosher to me, I replace the MYXP VM with one that was backed up before I installed mygame. I remove www.playmygame.com and www.mygame_high_scores.com from my access list for MYXP. It should acomplish this with little overheard. When I am not running the VM ideally it should not have any overhead. Suggestions?

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  • making java SingleFrameApplication to appear second

    - by Karel Bílek
    Sorry if this question will sound too chaotic, feel free to edit it. I have an application made entirely in netbeans, which uses SingleFrameApplication and auto-generated the GUI code, named "MyApp", and FrameView, named "MyView". Now, the MyApp somehow has the main() function, but the MyView has all the graphic elements.. I don't entirely understand how that happens, so used it as black box (it somehow created the window, I didn't have to care why). But now, I need the window to be only a window, opened by another JFrame. I don't know, how to accomplish that. MyApp, which is extending SingleFrameApplication, have these methods: public class MyApp extends SingleFrameApplication { @Override protected void startup() { show(new MyView(this)); } @Override protected void configureWindow(java.awt.Window root) { } public static MyApp getApplication() { return Application.getInstance(MyApp.class); } public static void main(String[] args) { launch(MyApp.class, args); } } MyView has these methods: public class MyView extends FrameView { public MyView(SingleFrameApplication app) { super(app); initComponents(); } private void initComponents() { //all the GUI stuff is somehow defined here } } Now, I have no clue how the two classes work, I just want this window, defined in MyView, to appear after another window, "ordinary" JFrame. How can I call this MyApp/MyView?

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  • How to bind a table in a dataset to a WPF datagrid in C# and XAML

    - by Jim Thomas
    I have been searching to hours for something very simple: bind a WPF datagrid to a datatable in order to see the columns at design-time. I can’t get any of the examples to work for me. Here is the C# code to populate the datatable InfoWork inside the dataset info: info = new Info(); InfoTableAdapters.InfoWorkTableAdapter adapter = new InfoTableAdapters.InfoWorkTableAdapter(); adapter.Fill(info.InfoWork); The problem is no matter how I declare ‘info’ or ‘infoWork’ Visual Studio/XAML can’t find it. I have tried: <Window.Resources> <ObjectDataProvider x:Key="infoWork" ObjectType="{x:Type local:info}" /> </Window.Resources> I have also tried this example from wpf.codeplex, but XAML doesn’t even like the “local:” keyword! <Window.Resources> <local:info x:Key="infoWork"/> </Window.Resources> There are really two main questions here: 1) How do I declare the table InfoWork in C# so that XAML can see it? I tried declaring it Public in the window class that XAML exists in with no success. 2) How do I declare the windows resource in XAML, specifcally the datatable inside the dataset? Out of curiosity, is there a reason that ItemsSource just doesn't show up as a property that be set in the properties design window?

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  • Xlib mouse events and ButtonPressMask

    - by Trilly Campanelino
    I have written a simple program which will report key press and release events for a particular window. In my case, it is mostly the terminal since I invoke the program from the terminal. I am able to get the key press and release events taking place in the terminal window (I have used XSelectInput() with KeyPressMask and KeyReleaseMask on the terminal) but the same is not working with ButtonPress and ButtonRelease. Not just these, but any events related to the mouse are not being reported. Any idea why this is happening? #include #include #include #include #include #include int main() { Display *display = XOpenDisplay(NULL); KeySym k; int revert_to; Window window; XEvent event; XGetInputFocus(display, &window, &revert_to); XSelectInput(display, window, KeyPressMask | KeyReleaseMask | ButtonPressMask | ButtonReleaseMask); while(1) { XNextEvent(display,&event); switch (event.type) { case KeyPress : printf("Key Pressed\n"); break; case KeyRelease : printf("Key Released\n"); break; case ButtonPress : printf("Button Pressed\n"); break; case ButtonRelease : printf("Button Released\n"); break; case EnterNotify : printf("Enter\n"); break; } } XCloseDisplay(display); return 0; }

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  • Prompt User before browser close?

    - by JM4
    We have an administrative portal that our teachers constantly forget to download their latest PDF instructions before logging out and/or closing the browser window. I have looked around but can't find what I'm looking for. I want to accomplish the following goals: Goal 1 Before a user can close the browser window, they are prompted "Did you remember to download your form?" with two options, yes/no. If yes, close, if no, return to page. Goal 2 Before a user can click the 'logout' button, they are prompted with the same as above. My first pass at the very basic code (which does not work for browser close) is: <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> <script type="text/javascript"> function init() { if(window.addEventListener) { window.addEventListener("beforeunload", unloadMess, false); } else if(window.onbeforeunload) { window.onbeforeunload = unloadMess; }; } function unloadMess() { var User_Message = "[Your user message here]" return User_Message; } </script> </head> <body onload="init();"> hello this is my site </body> </html> anybody ever come across a good solution?

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  • Using a Javascript Variable & Sending to JSON

    - by D Franks
    Hello all! I'm trying to take a URL's hash value, send it through a function, turn that value into an object, but ultimately send the value to JSON. I have the following setup: function content(cur){ var mycur = $H(cur); var pars = "p="+mycur.toJSON(); new Ajax.Updater('my_box', 'test.php', { parameters: pars }); } function update(){ if(window.location.hash.length > 0){ content(window.location.hash.substr(1)); // Everything after the '#' } } var curHashVal = window.location.hash; window.onload = function(){ setInterval(function(){ if(curHashVal != window.location.hash){ update(); curHashVal = window.location.hash; } },1); } But for some reason, I can't seem to get the right JSON output. It will either return as a very large object (1:"{",2:"k") or not return at all. I doubt that it is impossible to accomplish, but I've exhausted most of the ways I can think of. Other ways I've tried were "{" + cur + "}" as well as cur.toObject(), however, none seemed to get the job done. Thanks for the help!

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  • How does the overall view hierarchy change when using UIKit view manipulations?

    - by executor21
    I've been trying to figure out what happens in the view hierarchy when methods like pushViewController:animated, presentModalViewController:animated, and tab switches in UITabBarViewController are used, as well as UIAlertView and UIActionSheet. (Side note: I'm doing this because I need to know whether a specific UIView of my creation is visible on screen when I do not know anything about how it or its superview may have been added to the view hierarchy. If someone knows a good way to determine this, I'd welcome the knowledge.) To figure it out, I've been logging out the hierarchy of [[UIApplication sharedApplication] keyWindow] subviews in different circumstances. Is the following correct: When a new viewController is pushed onto the stack of a UINavigationController, the old viewController's view is no longer in the view hierarchy. That is, only the top view controller's view is a subview of UINavigationController's view (according to logs, it's actually several private classes such as UILayoutContainerView). Are the views of view controllers below the top controller of the stack actually removed from the window? A very similar thing happens when a new viewController is presented via presentModalViewController:animated. The new viewController's view is the only subview of the kew window. Is this correct? The easiest thing to understand: a UIAlertView creates its own window and makes it key. The strangest thing I encountered: a UIActionSheet is shown via showInView: method, the actionSheet isn't in the view hierarchy at all. It's not a subview of the view passed as an argument to showInView:, it isn't added as a subview of the key window, and it doesn't create its own window. How does it appear, then? I haven't tried this yet, so I'd like to know what happens in the keyWindow hierarchy when tabs in a UITabBarController are switched. Is the view of the selected UIViewController moved to the top, or does it work like with pushViewController:animated and presentModalViewController:animated, where only the displayed view is in the window hierarchy?

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  • Layering Cocoa WebView - Drawing on top?

    - by Josh
    http://stackoverflow.com/questions/1618498/webview-in-core-animation-layer The only other thread I can find is the above which doesn't necessarily fit my needs. Is there a reliable way to simply draw a view on top of a webview? I've tried to layer a regular NSView on top of WebView, and it draws right at first, but any movement in the webview (scrolling the page etc) appears to invalidate the view and produces visual artifacts. I've tried: [[[NSApp mainWindow] contentView] addSubview:view positioned:NSWindowAbove relativeTo:webView]; No luck there, same problems -- z-ordering doesn't seem to work unless I'm missing something. Is this just a limitation of webviews? I also tried implementing the view above as a window, which worked much better (just controlled the location of the window programmatically). However, the desired behavior is for the user to enter some text into this window, but for it not to steal "focus" -- ie the main window goes inactive (the x - + go gray) when the user clicks on the text field in the new window. Any way to avoid that? I've tried subclassing NSWindow and overriding canBecomeKey (return YES) and canBecomeMain (return NO) but the window still steals focus. Josh

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  • Wordpress + VMware CSS path problem

    - by Stephen Meehan
    I posted a similar question earlier today but this question is clearer. I want to locally develop my Wordpress websites (on my Mac) and test them in Internet Explorer (6,7,8) on Windows XP. I can get the MAMP welcome screen to show in Windows XP, so I know VMWare is doing it's thing. The local URL for my site (on my Mac) is: URL (http://d3creative:8888/) But the local URL under VMware/Internet Explorer is: URL (http://192.168.2.1:8888/d3creative/) This is the only way I can get it to show up, problem is all the CSS styles are referencing the local Mac URL (http://d3creative:8888/) So understandably the CSS isn't showing up. Is there a way to tell Windows that "http://192.168.2.1:8888/d3creative/" should equal "http://d3creative:8888/" I've tried editing the "hosts" file within in Windows XP and I've rebooted after making any changes, but nothing is working. My software: MAMP Pro (v1.8.2) Wordpress (v2.8.6) Windows XP (SP3) Internet Explorer (6, 7, 8) Any help would be much appreciated. Stephen Meehan

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  • JS: capture a static snapshot of an object at a point in time with a method

    - by Barney
    I have a JS object I use to store DOM info for easy reference in an elaborate GUI. It starts like this: var dom = { m:{ old:{}, page:{x:0,y:0}, view:{x:0,y:0}, update:function(){ this.old = this; this.page.x = $(window).width(); this.page.y = $(window).height(); this.view.x = $(document).width(); this.view.y = window.innerHeight || $(window).height(); } I call the function on window resize: $(window).resize(function(){dom.m.update()}); The problem is with dom.m.old. I would have thought that by calling it in the dom.m.update() method before the new values for the other properties are assigned, at any point in time dom.m.old would contain a snapshot of the dom.m object as of the last update – but instead, it's always identical to dom.m. I've just got a pointless recursion method. Why isn't this working? How can I get a static snapshot of the object that won't update without being specifically told to? Comments explaining how I shouldn't even want to be doing anything remotely like this in the first place are very welcome :)

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  • Why does my iOS app crash when trying presentModalViewController?

    - by user555807
    I've been banging my head against this all day, it seems like something simple but I can't figure it out. I've got an iOS app that I created using the "View-based Application" template in XCode. Here is essentially the code I have: AppDelegate.h: #import <UIKit/UIKit.h> @interface AppDelegate : NSObject <UIApplicationDelegate> { UIWindow *window; MainViewController *viewController; } @property (nonatomic, retain) IBOutlet UIWindow *window; @property (nonatomic, retain) IBOutlet MainViewController *viewController; @end AppDelegate.m: #import "AppDelegate.h" #import "MainViewController.h" @implementation AppDelegate @synthesize window, viewController; - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { [self.window addSubview:viewController.view]; [self.window makeKeyAndVisible]; return YES; } - (void)dealloc { [viewController release]; [window release]; [super dealloc]; } @end MainViewController.h: #import <UIKit/UIKit.h> @interface MainViewController : UIViewController { } -(IBAction) button:(id)sender; @end MainViewController.m: #import "MainViewController.h" #import "ModalViewController.h" @implementation MainViewController ... -(IBAction) button:(id)sender { ModalViewController *mvc = [[[ModalViewController alloc] initWithNibName:NSStringFromClass([ModalViewController class]) bundle:nil] autorelease]; [self presentModalViewController:mvc animated:YES]; } @end There's nothing of interest in the ModalViewController. So the modal view should display when the button is pressed. When I press the button, it hangs for a second then crashes back to the home screen with no error message. I am stumped, please show me what I'm doing wrong!

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  • How to repeatedly show a Dialog with PyGTK / Gtkbuilder?

    - by Julian
    I have created a PyGTK application that shows a Dialog when the user presses a button. The dialog is loaded in my __init__ method with: builder = gtk.Builder() builder.add_from_file("filename") builder.connect_signals(self) self.myDialog = builder.get_object("dialog_name") In the event handler, the dialog is shown with the command self.myDialog.run(), but this only works once, because after run() the dialog is automatically destroyed. If I click the button a second time, the application crashes. I read that there is a way to use show() instead of run() where the dialog is not destroyed, but I feel like this is not the right way for me because I would like the dialog to behave modally and to return control to the code only after the user has closed it. Is there a simple way to repeatedly show a dialog using the run() method using gtkbuilder? I tried reloading the whole dialog using the gtkbuilder, but that did not really seem to work, the dialog was missing all child elements (and I would prefer to have to use the builder only once, at the beginning of the program). [SOLUTION] As pointed out by the answer below, using hide() does the trick. But one has to take care that the dialog is in fact destroyed if one does not catch its "delete-event". A simple example that works is: import pygtk import gtk class DialogTest: def rundialog(self, widget, data=None): self.dia.show_all() result = self.dia.run() def destroy(self, widget, data=None): gtk.main_quit() def closedialog(self, widget, data=None): self.dia.hide() return True def __init__(self): self.window = gtk.Window(gtk.WINDOW_TOPLEVEL) self.window.connect("destroy", self.destroy) self.dia = gtk.Dialog('TEST DIALOG', self.window, gtk.DIALOG_MODAL | gtk.DIALOG_DESTROY_WITH_PARENT) self.dia.vbox.pack_start(gtk.Label('This is just a Test')) self.dia.connect("delete-event", self.closedialog) self.button = gtk.Button("Run Dialog") self.button.connect("clicked", self.rundialog, None) self.window.add(self.button) self.button.show() self.window.show() if __name__ == "__main__": testApp = DialogTest() gtk.main()

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  • UINaviagtionBar not displaying?

    - by Rajendra Bhole
    Hi, I developing an application in which initially choose UINavigationController based application. In rooViewController xib i added two more UIView, the code is written as follows. @implementation RootViewController @synthesize introductionView, WheelView; (void)viewDidLoad { [super viewDidLoad]; [self.navigationController setNavigationBarHidden:YES]; } pragma mark pragma mark strart up screen: -(void)startIntroductionScreen{ if(window == nil) { window = [[UIWindow alloc] initWithFrame:CGRectMake(0, 0, 320, 480)]; } [window addSubview: introductionView]; [window makeKeyAndVisible]; } -(void)WheelScreen{ [window addSubview:carnivalWheelView]; [window makeKeyAndVisible]; self.navigationController.navigationBar.hidden = NO; [self.navigationItem setLeftBarButtonItem:[[UIBarButtonItem alloc] initWithTitle:@"Setting" style:UIBarButtonItemStylePlain target:nil action:nil] animated:YES]; } pragma mark pragma mark IBAction: -(IBAction)breakGlass:(id)sender{ [self startIntroductionScreen]; } -(IBAction)anotherView:(id)sender{ [self WheelScreen]; } In above code, when the -(void)WheelScreen method on the IBAction anotherView of invoke the UINaviagtionBar is not displaying. Thank's in advance.

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  • how do I zoom to normal text size in vs2008?

    - by gerryLowry
    I can not find any help on this issue in vs2008 help, Google, or SO. Scenario: I'm looking at a source file in vs2008 SP1; Windows 2003 Server SP2 Standard Edition, 1280x1024. The irrelevant name of this file is index.aspx. What is relevant is that the file has only 65 lines of code. The print is unreadably small--less than 4 point. It uses less than a third of the vs2008 text window vertically and less that a quarter of the vs2008 text window horizontally. It's not just index.aspx; e.g. another file with 142 lines only fills about 3/4 of the vs2008 text window vertically and less that a quarter of the vs2008 text window horizontally. Possible cause: Probably, but not certainly, I found the equivalent of zoom in/zoom out such as one finds in products like Microsoft Word. However, I've explored many vs2008 toolbars and other customization options and unfortunately I can not find out how to get myself out of this mess. Window, Reset Window Layout has no effect on the text size; my tiny text size did not change. QUESTION: how do I zoom vs2008 text size in and out and back to normal size? Thank you. Regards ~~ Gerry (Lowry)

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  • How do I switch out Views in a Cocoa application?

    - by David Garcia
    So I'm beginning to learn how to use Cocoa. I think I've pretty much got it but I'm hung up on creating and switching views. I'm rewriting a game I made a little bit ago for practice. All I want is one window (preferably not resizable) and I want to be able to switch out views for different screens in the game. First, I have the main menu (Start Game, High Scores, Exit). Then I need a window for each screen (Gameplay screen, Highscore screen). What I'm getting confused with is how to design this. I looked up NSViewController thinking it manages views but it doesn't. It only manages one view by loading it really. I don't understand why I'd need to use NSViewController then. Couldn't I just have a window class that contains multiple subclasses of NSView and load them like that? I'm not sure I understand the purpose of the ViewController. Does my Window Class really need to subclass NSWindowController? I was trying to follow the example of Apple's ViewController example and it has a window controller class that's a subclass of NSWindowController. I don't see what the purpose was of subclassing that. All NSWindowController seems to add is - initWithPath:(NSString *)newPath but I fail to see the use in that either when I can just edit the plist file to open the window on start up. Apple's example also has an NSView variable and an NSViewController variable. Don't you only need one variable to store the current view? Thanks in advance guys, I'm really confused as to how this works.

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  • WPF ResourceDictionary and DynamicResource

    - by lanicor
    i am new to WPF so maybe this will be "noob" question but i can't find answer to it (and it seems so easy)... well i am programing WPF app and i want to use smth similar to css for webpages, so i found ResourceDictionary and tried to use it... I have main window in which i create Frame and on click some UserControl is loaded to that same Frame.I include my ResourceDictionary (root/style/Styles.xaml) to my main window like this: <Window.Resources> <ResourceDictionary x:Key="styles" Source="style/Styles.xaml" /> </Window.Resources> in which i have: <ResourceDictionary xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation" xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"> <Style x:Key="ProductsRequired" TargetType="{x:Type Label}"> <Setter Property="Height" Value="28" /> ... I don't use it on my main window but want to use it on my UserControls, which are loaded to that main window and i try to use it like this: <Label Name="product1" Style="{DynamicResource ProductsRequired}" /> Warning i am getting all the time is: The resource "ProductsRequired" could not be resolved. I even tried including Styles to my UserControl <UserControl.Resources> <ResourceDictionary x:Key="styles" Source="../style/Styles.xaml" /> </UserControl.Resources> and nothing happens... Well my question is long but i wanted to be clear... :) P.S. all that logic works in C# code btw private ResourceDictionary myStyles = new ResourceDictionary(); Style ProductsRequired = myStyles["ProductsRequired"] as Style; product1.Style = ProductsRequired;

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  • Autoupgradeenable property of openfiledialog.

    - by Harikrishna
    I had need of showing open file dialog in winform application. And one property of the file dialog, autoupgradeenabled which I set as a true, which is for updating the open file dialog according to operating system, like if application is running on xp then dialog is displayed different as in wista or window 7. So when I used that property as a true, and once in the machine where there was xp with 2.0 .net framework that open file dialog could not be opened. So I tried by doing it false then also it could not be opened in the machine with the xp and 2.0 framework. Then I tried by commenting that whole line means I removed that property from the code, then I tried and it was fine in xp machine with 2.0 framework. So problem is I cannot understand that why that property is not working by setting it false or true. Because by setting that property is should work in all os with all framework and dialog should be changed according to os. If not,then what is the meaning of that property ?

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  • Can't add to NSMutableArray from SecondaryView

    - by Antonio
    Hi guys, I've searched and read and still haven't found a concrete answer. Brief: I have an application where I declare an NSMutableArray in my AppDelegate to synthesize when the application loads. (code below). I have a SecondaryViewController call this function, and I have it output a string to let me know what the array size is. Every time I run it, it executes but it does not add any objects to the array. How do I fix this? AppDelegate.h file #import <UIKit/UIKit.h> @class arrayTestViewController; @interface arrayTestAppDelegate : NSObject <UIApplicationDelegate> { UIWindow *window; arrayTestViewController *viewController; NSMutableArray *myArray3; } @property (nonatomic, retain) NSMutableArray *myArray3; @property (nonatomic, retain) IBOutlet UIWindow *window; @property (nonatomic, retain) IBOutlet arrayTestViewController *viewController; -(void)addToArray3; @end AppDelegate.m file #import "arrayTestAppDelegate.h" #import "arrayTestViewController.h" @implementation arrayTestAppDelegate @synthesize window; @synthesize viewController; @synthesize myArray3; #pragma mark - #pragma mark Application lifecycle - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { myArray3 = [[NSMutableArray alloc] init]; // Override point for customization after application launch. // Add the view controller's view to the window and display. [window addSubview:viewController.view]; [window makeKeyAndVisible]; return YES; } -(void)addToArray3{ NSLog(@"Array Count: %d", [myArray3 count]); [myArray3 addObject:@"Test"]; NSLog(@"Array triggered from SecondViewController"); NSLog(@"Array Count: %d", [myArray3 count]); } SecondViewController.m file #import "SecondViewController.h" #import "arrayTestAppDelegate.h" @implementation SecondViewController -(IBAction)addToArray{ arrayTestAppDelegate *object = [[arrayTestAppDelegate alloc] init]; [object addToArray3]; }

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  • Javascript and jQuery (Fancybox) question

    - by songdogtech
    Javascript and jQuery (Fancybox) question I'm using the Javascript function below for Twitter sharing (as well as other services; the function code is simplified to just Twitter for this question) that grabs the to-be-shared page URL and title and it is invoked in the link with onclick. That results in the Twitter share page loading in a pop up browser window, i.e.<img src="/images/twitter_16.png" onclick="share.tw()" /> In order to be consistent with other design aspects of the site, what I'd like to be able to do is have the Twitter share page open not in a standard browser window but in a Fancybox (jQuery) window. Fancybox can load an external page in an iFrame when the img or href link contains a class (in this case class="iframe" ) in the link and in the document ready function in the header. Right now, of course, when I give the iframe class to the link that also has the onclick share.tw(), I get two popups: one browser window popup with the correct Twitter share page loaded, and a Fancybox jQuery popup that shows a site 404. How can I change the function to use Fancybox to present the Twitter share page? Is that a correct way to approach it? Or is there a better way, such as implementing the share function in jQuery, too? Thanks... Javascript share function: var share = { tw:function(title,url) { this.share('http://twitter.com/home?status=##URL##+##TITLE##',title,url); }, share:function(tpl,title,url) { if(!url) url = encodeURIComponent(window.location); if(!title) title = encodeURIComponent(document.title); tpl = tpl.replace("##URL##",url); tpl = tpl.replace("##TITLE##",title); window.open(tpl,"sharewindow"+tpl.substr(6,15),"width=640,height=480"); } }; It is invoked, i.e.: <img src="/images/twitter_16.png" onclick="share.tw()" /> Fancybox function, invoked by adding class="iframe" in the img or href link $(".iframe").fancybox({ 'width' : '100%', 'height' : '100%', 'autoScale' : false, 'transitionIn' : 'none', 'transitionOut' : 'none', 'type' : 'iframe' });

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  • How is an AppDelegate instanciated?

    - by pwny
    I have an iOS application for which I want to create a ViewController programmatically. I started an empty XCode project and modified the main method so it looks like this int main(int argc, char *argv[]) { NSAutoreleasePool *pool = [[NSAutoreleasePool alloc] init]; int retVal = UIApplicationMain(argc, argv, nil, @"MyAppDelegate_iPad"); [pool release]; return retVal; } The app is a Universal Application, MyAppDelegate_iPad is a subclass of MyAppDelegate, which is a subclass of NSObject <UIApplicationDelegate>. My problem is that the applicationDidFinishLoading method I've overridden in MyAppDelegate_iPad is never called (break point on the first line never hits). The method looks like this -(void) applicationDidFinishLaunching:(UIApplication *)application { window = [[UIWindow alloc] initWithFrame:[[UIScreen mainScreen] bounds]]; if(!window) { [self release]; return; } window.backgroundColor = [UIColor whiteColor]; rootController = [[MyViewController alloc] init]; [window addSubview:rootController.view]; [window makeKeyAndVisible]; [window layoutSubviews]; } I removed the line to link to a nib file from my plist file (I used to get the default "My Universal app on iPad" white screen) and now all that is displayed is a black screen. applicationDidFinishLoading is still not being called. Am I doing something wrong? How should I properly create my AppDelegate instance?

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  • JSP getParameter problem

    - by user236501
    I have a form, if the timer reach the form will auto redirect to the Servlet to update database. My problem now is if javascript redirect the window to servlet my request.getParameter is null. function verify(f,whichCase){ if(whichCase == "Submit"){ msg = "Are you sure that you want to submit this test?"; var i = confirm(msg) if(i){ parent.window.location = "sindex.jsp" } return i; } } I doing this because i got a iframe in my jsp. Timer update problem have to use iframe. So, when time up or user click submit parent.window.location can let me refresh parent window <form method="POST" action="${pageContext.request.contextPath}/TestServlet" onSubmit="return verify(this,whichPressed)"> My form when user click submit button within the timing, it will trigger the verify function to let user confirm submit. So inside my TestServlet i got this, because using javascript redirect request.getParameter("answer") this keep return me null. protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (request.getParameter("Submit") != null) { String ans = request.getParameter("answer"); Answer a = new Answer(ans, no); aa.CreateAnswer(an,t.getTestCode(),username); RequestDispatcher rd = request.getRequestDispatcher("/sindex.jsp"); rd.forward(request, response); } } Below are my timer when time up redirect to TestServlet trigger the doGet method if((mins == 0) && (secs == 0)) { window.alert("Time is up. Press OK to submit the test."); // change timeout message as required var sUrl = "TestServlet"; parent.window.location = sUrl // redirects to specified page once timer ends and ok button is pressed } else { cd = setTimeout("redo()",1000); }

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