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Unordered list appears higher than div

- by LordArmadillo

I am trying to create a simple page, which I normally can without any trouble. However, the unordered list appears higher up the page than the div. I do know a solution for this, however I cannot remember it. The page goes like this: <style> ul.menu { list-style-type: none; margin:150; margin-bottom:30px; padding:0; display: block; width: 708px; margin-left: auto; margin-right: auto; } li.menu { float:left; display: block; width: 118px; } a.menu:link,a.menu:visited { color:black; display:block; border:1px solid black; background-color:#FFFF00; width:118px; text-align:center; text-decoration:none; font-family:"Courier New", Courier, monospace } a.menu:hover { background-color:#FFBB11; } </style> <div id="head"> My images here & such</div> <ul class="menu"> <li class="menu"> <a class="menu">Main</a> </li> </ul> Normally I welcome suggestions to change my code, but I have a deadline today! So, quick & simple help would be appreciated! Thanks! LordArmadillo

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More than one JPanel in a Frame / having a brackground Image and another Layer with Components on the top

- by user1905203

I've got a JFrame with a JPanel in which there is a JLabel with an ImageIcon(). Everything's working perfectly, problem is i now want to add another JPanel with all the other stuff like buttons and so on to the JFrame. But it still shows the background Image on top and nothing with the second JPanel. Can someone help me? Here is an extract of my code: JFrame window = new JFrame("Http Download"); /* * Background Section */ JPanel panel1 = new JPanel(); JLabel lbl1 = new JLabel(); /* * Component Section */ JPanel panel2 = new JPanel(); JLabel lbl2 = new JLabel(); /* * Dimension Section */ Dimension windowSize = new Dimension(800, 600); Dimension screen = Toolkit.getDefaultToolkit().getScreenSize(); public HTTPDownloadGUI() { window.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); panel1.setLayout(null); panel1.setSize(windowSize); panel1.setOpaque(false); panel2.setLayout(null); panel2.setSize(windowSize); panel2.setOpaque(false); lbl1.setSize(windowSize); lbl1.setLocation(0, 0); lbl1.setIcon(new ImageIcon(getClass().getResource("bg1.png"))); panel1.add(lbl1); lbl2.setBounds(0, 0, 100, 100); //lbl2.setIcon(new ImageIcon(getClass().getResource("bg2.png"))); lbl2.setBackground(Color.GREEN); panel2.add(lbl2); panel1.add(panel2); window.add(panel1); int X = (screen.width / 2) - (windowSize.width / 2); int Y = (screen.height / 2) - (windowSize.height / 2); window.setBounds(X,Y , windowSize.width, windowSize.height); window.setVisible(true); }

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Calling a method from another view in objective-c. (iphone sdk).

- by MarcZero

Hello. I am currently creating a multi-view game on the iPhone platform. I have my main view start to play some background music upon loading. I then go to another view and start the game. I am trying to get the background music from the original view to stop once I start the game. I am having trouble getting the stop playing music message to my original view. Here is the relevant info: The main view where the sound is played from is just a subView of the programViewController class called *viewController. The heading is in the programAppDelegate class. The sound is done using the AVAudioPlayer class and plays fine when the program starts up and when I navigate to other subviews that are added on by going through the menu system. In the view that I want to start the game, I attempt to call the instance of the class to turn of the player but anytime I use this format of code: [viewController #######]; It gives a build error of "viewController undeclared" no matter what I put after the "viewController" in the message.I have attempted to import the programAppDelegate.h file but it still gives the same error. I realize this might be a simple misunderstanding of the objective-c language but I cannot find any info on this issue. I am a recent convert from Java so I am trying to wrap my head around everything. Thank you for your time!

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Why should I install Python packages into `~/.local`?

- by Matthew Rankin

Background I don't develop using OS X's system provided Python versions (on OS X 10.6 that's Python 2.5.4 and 2.6.1). I don't install anything in the site-packages directory for the OS provided versions of Python. (The only exception is Mercurial installed from a binary package, which installs two packages in the Python 2.6.1 site-packages directory.) I installed three versions of Python, all using the Mac OS X installer disk image: Python 2.6.6 Python 2.7 Python 3.1.2 I don't like polluting the site-packages directory for my Python installations. So I only install the following five base packages in the site-packages directory. For the actual method/commands used to install these, see SO Question 4324558. setuptools/ez_setup distribute pip virtualenv virtualenvwrapper All other packages are installed in virtualenvs. I am the only user of this MacBook. Questions Given the above background, why should I install the five base packages in ~/.local? Since I'm installing these base packages into the site-packages directories of Python distributions that I've installed, I'm isolated from the OS X's Python distributions. Using this method, should I be concerned about Glyph's comment that other things could potentially break (see his comment below)? Again, I'm only interested in where to install those five base packages. Related Questions/Info I'm asking because of Glyph's comment to my answer to SO question 4314376, which stated: NO. NEVER EVER do sudo python setup.py install whatever. Write a ~/.pydistutils.cfg that puts your pip installation into ~/.local or something. Especially files named ez_setup.py tend to suck down newer versions of things like setuptools and easy_install, which can potentially break other things on your operating system. Previously, I asked What's the proper way to install pip, virtualenv, and distribute for Python?. However, no one answered the "why" of using ~/.local.

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Fake location for the device (custom)

- by AtomRiot

I know there are a few apps out there to fake a devices location but specifically what i want to do is use a location grabbed from a url. What direction should I look for setting the location on the device. The scenario i have is a jailbroken Wi-Fi iPad tethered to a nexus one. The nexus one would host a background service that when a request is recieved, it would respond with gps data of its current location. The jailbroken ipad would have a background service that either updated the location on a time interval, or on a per request basis (depending on how i have to implement it) by submitting a request to the tethered nexus one service. That data would then be set on the ipad and an application requesting location would get the service data. The goal is to recreate the location faker app's functionality with the exception of the spoofed location comes from the nexus ones gps via the service but i have not yet found out how to set the location data for the device. I can ofcourse implement this in a per app basis but it would be awesome to have any app be able to use it.

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Padding between images doesn't pad

- by ripper234

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <style type="text/css"> #action-icons { float:right; } #action-icons.img { position:relative; top:-30px; padding-right:200px; } </style> </head> <body> <h1 class="edit">Some nifty title <span id="action-icons"> <img src="foo.png" width="64" height="64" alt="" id="newsticky"/> <img src="bar.png" width="60" height="60" alt="" id="trash"/> </span> </h1> </body> </html>

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CSS 3 columns, why is the third column taking over the other 2?

- by Matt Dawdy

Here is the smallest amount of code that clearly illustrates my problem: <html> <body> <div style="float: left; width: 200px;">One</div> <div style="float: left; width: 200px;">Two</div> <div style="background-color: #f0f;">Three</div> </body> </html> The first 2 divs are supposed to be 2 left columns. The 3rd should take up the rest of the page. Eventually, I'm going to add options to hide and show the 2 columns on the left. But, why is the color purple extending all the way to the browser's left edge? I am trying to get it to start at the word "Three".

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jQuery variable and object caching

- by niksy

This is something that has been bugging me some time and every time I found myself using different solution for this. So, I have link in my document which on click creates new element with some ID. <a href="#" id="test-link">Link</a> For the purpose of easier reusing, I would like to store that new elements ID in a variable which is jQuery object var test = $('#test'); On click I append that new element on body, new element is DIV $('body').append('<div id="test"/>'); And here goes the main "problem" - if I test this new elements length with test.length it first returns 0 and later 1. But, when I test it with $('#test').length it returns 1 from the start. I suppose it is some caching mechanism and I was wondering is there better, all-around solution which will allow to store elements in variables in the start for later repurpose and in the same time work with dynamically created elements. Live, delegate, something else? What I do sometimes is create string and add it to jQuery object but I think this is just avoiding the real issue. Also, using .find() inside another jQuery object. Thanks in advance.

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Javascript dynamic table memory usage

- by Dan

I use a dynamic table: <html> <body> <button id="button">Build table</button> <div id="container"> <script type="text/javascript"> window.onload=function(){ var table = null; var row = "<tr><td>111111111111111111111111111111111111111111111111111111</td>" + "<td>222222222222222222222222222222222222222222222222222222</td>" + "<td>333333333333333333333333333333333333333333333333333333</td></tr>"; var data = null; for (var i = 0; i < 2000; i++){ data += row; } var obj = document.getElementById("button"); obj.onclick=function buildTable(){ document.getElementById("container").innerHTML = "<div><table><tbody>" + data + "</tbody></table></div>"; }; }; </script> </body> </html> Using chromes task manager, each time new data is loaded the memory usage increases considerably and doesn't go down, so after some time the app consumes a lot of memory and requires the browser to be closed. Is there any change in the code I can use to solve this or is it a browser side problem?

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Picture lead-in to Youtube video

- by cf_PhillipSenn

I have the following, which displays an image and when the user clicks on the image, it takes them to the Youtube video: <html> <head> <script src="http://www.google.com/jsapi"></script> <script type="text/javascript"> google.load("jquery", "1", {uncompressed: true}); </script> <script> jQuery(function($){ $('a').click(function() { $(this).html('<object width="425" height="344"><param name="movie" value="http://www.youtube.com/v/Msef24JErmU&hl=en_US&fs=1&rel=0&color1=0x2b405b&color2=0x6b8ab6"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/Msef24JErmU&hl=en_US&fs=1&rel=0&color1=0x2b405b&color2=0x6b8ab6" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="425" height="344"></embed></object>'); return false; }); }); </script> </head> <body> <a href="javascript:void();"><img src="http://www.clipov.net/pic/paul_oakenfold+%5Bstarry_eyed_surprise%5D+_+3-07+mtv_dance_beats+clear.jpg"></a> </body> </html> Q: How do I autoplay the video to keep the user from having to click on it (a second time)?

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Why can't I overwrite the prototype of `Array` (`Array.prototype`)?

- by user828896

I set the prototype of Array as an instance of my, I think book.aa will display "aa", but it displays "undefined", why? Thanks! <html> <head> <title>Array Properties</title> <h2>Array Properties</h2> <script type="text/javascript"> function my() { this.aa = 'aa'; } Array.prototype = new my(); Array.prototype.bb = "bb"; var book = new Array(); book[0] = "War and Peace"; </script> </head> <body bgcolor="lightblue"> <script type="text/javascript"> document.write(book.aa+book.bb); </script> </body> </html>

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on click submit button move itsplace

- by Mayur

Hi All, I m Using submit button for my form its work fine in all browser except ie7 when an user click on it it moved please suggest me what to do .confirm-button-submit { width : 79px; font : bold 12px sans-serif;; color : #000; background : url("../images/confirm-btn.png") 0 -33px no-repeat; text-decoration : none; margin-top :0px; text-align:center; border:0px; cursor : pointer; height:32px; padding : 8px 0px 12px 0px; } .confirm-button-submit:hover { width : 79px; font : bold 12px sans-serif;; color : #fff; background : url("../images/confirm-btn.png") 0 0 no-repeat; text-decoration : none; margin-top :0px; text-align:center; border:0px; cursor : pointer; height:32px; padding : 8px 0px 12px 0px; } i used this css please tell me what to do code: <input type="button" value="Show" name="commit" onclick="range_validation(this)" class="confirm-button-submit"/>`

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JQuery Cross-slide

- by Foxticity

I'm trying to cycle through 3 images with JQuery Cross-slide, but the images doesn't want to display, here is the basic code below. All 3 images are in 650 - 100 size, and they are in the correct location, but the images just don't want to display. What am i doing wrong?? <html> <body> <script src="jquery.js" type="text/javascript"></script> <script src="jquery.cross-slide.js" type="text/javascript"></script> <div id="crossslide" style="width:650px; height:100px;"></div> <script type="text/javascript"> // </script> </body> </html>

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form.has_errors tag not working

- by John

Hello, Im using Django 1.2.3. I have login functionality in my site using django.contrib.auth.views.login. The user is able to login after entering correct username and password. But, form.has_errors is not working i.e. if the login credentials entered are incorrect i dont see the error message. My login.html in templates/registration is as follows : <html> <head> <title>Login</title> </head> <body> <h1>User Login</h1> {% if form.has_errors %} <p>Your username and password didn't match. Please try again.</p> {% endif %} <form method="post" action="."> {% csrf_token %} <p><label for="id_username">Username:</label> {{ form.username }}</p> <p><label for="id_password">Password:</label> {{ form.password }}</p> <input type="hidden" name="next" value="/" /> <input type="submit" value="login" /> </form> </body> </html> Any way to fix this problem? Please Help Thank You.

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Javascript mouseover image failure

- by CaptainTeancum

This is what I have so far, I have been watching a ton of Javascript videos and I feel I mimicked them solid but this is still not functioning as I want. Than being, it changes from logo1 to logo2 on mousover. This is homework. However homework that is important to me so any help or guidance would be appreciated. </head> <body> <p> <div> <script type="text/javascript"> // Pre load images for rollover function imgOver(id) { document.getElementById(id).src="logo1.jpg"; } function imgOut(id) { document.getElementById(id).src="logo2.jpg"; } </script> <a href="#" onmouseover="imgOver('logo1');" onmouseout="imgOut('logo2')"> <img alt="logo" height="150" src="images/Logo1.jpeg" width="110" /> </a> </div> </body> </html>

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jquery to toggle a label

- by Juan Almonte

How can I get the label to toggle show/hide? Below is my code and currently it is also displaying show. I would like it to toggle from show to hide and from hide back to show. when show is displayed the div will be hidden but when show is clicked the label will switch to hide and the div will be displayed and when hide is clicked the label will go back to show and the div will be hidden <html> <head> <title>jQuery test page</title> <script type="text/javascript" src="../scripts/jquery-1.4.2.js"></script> <script type="text/javascript"> $(document).ready(function() { $("#clickMe").click(function() { $("#textBox").toggle(); }); }); </script> </head> <body> <label id="clickMe">Show</label> <br /> <div id="textBox" style="display: none">This text will be toggled</div> </body> </html>

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php mysql_fetch_array() error

- by user1877823

I am getting this error while i am trying to delete a record the query is working but this line remains on the page. i want to echo "Deleted" written in the while should show up but the while loop is not working, i have tried and searched alot nothing helps! mysql_fetch_array() expects parameter 1 to be resource, boolean given in delete.php on line 27 delete.php <html> <body> <form method="post"> Id : <input type="text" name="id"> Name : <input type="text" name="name"> Description : <input type="text" name="des"> <input type="submit" value="delete" name="delete"> </form> <?php include("connect.php"); $id = $_POST['id']; $name = $_POST['name']; $des = $_POST['des']; $result = mysql_query("DELETE FROM fact WHERE id='$id'") or die(mysql_error()); while($row = mysql_fetch_array($result)) { echo "Deleted"; } mysql_close($con); ?> </body> </html> connect.php <?php $con = mysql_connect("localhost","root",""); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("Dataentry", $con); ?> How should i make the while loop work..

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(JQuery) How to call a custom function before following link

- by morpheous

I want to achieve the following behavior in a page link. When the link is clicked, I want to: First, send (POST) some data back to the server Second, allow the browser to navigate to the url that the link was pointing to. I am relatively new to JQuery, and here is my first attempt below. I will be grateful to any jQuery gurus in here to fillin the blanks (and maybe point out how the snippet below may be improved). <html> <head>test page</head> <body> <div><a id="hotlink" href="http://www.example.com">Clik and see</a></div> </body> <script type="text/javascript"> $(document).ready(function(){ $('hotlink').click(function(){ //AJAX Post data here ... //follow the link url (i.e. navigate/browse to the link) ... }); }); </script> </html>

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How to break an object into chunks based on some property?

- by CurlyFro

public class InvestorMailing { public string To { get; set; } public IEnumerable<string> Attachments { get; set; } public int AttachmentCount { get; set; } public long AttachmentSize { get; set; } } i have an IList<InvestorMailing> mailingList. if the attachment size is greater than x, then i need to split my object into chunks. is there an easy linq-y way to do this? Edited: this is how i'm generating my mailings: var groupedMailings = mailingList.GroupBy(g => g.GroupBy); var investorMailings = groupedMailings.Select( g => new DistinctInvestorMailing { Id = g.Select(x => x.Id).FirstOrDefault(), To = g.Key.Trim(), From = g.Select(x => x.From).FirstOrDefault(), FromName = g.Select(x => x.FromName).FirstOrDefault(), Bcc = g.Select(x => x.Bcc).FirstOrDefault(), DeliveryCode = g.Select(x => x.DeliveryCode).FirstOrDefault(), Subject = g.Select(x => x.Subject).FirstOrDefault(), Body = g.Select(x => x.Body).FirstOrDefault(), CommentsOnStatus = g.Select(x => x.CommentsOnStatus).FirstOrDefault(), Attachments = g.Select(x => x.AttachmentPath), AttachmentCount = g.Select(x => x.AttachmentPath).Count(), AttachmentSize = g.Sum(x => x.AttachmentSize), MailType = g.Select(x => x.MessageType).FirstOrDefault() } ).ToList();

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Issue in alternate Row color using each() method of JQuery

- by user1323981

I have a table as under <table > <tr> <th scope="col">EmpId</th><th scope="col">EmpName</th> </tr> <tr> <td>1</td><td>ABC</td> </tr> <tr> <td>2</td><td>DEF</td> </tr> </table> I want to set the alternate row color of only the "td" elements of the table and not "th" by using only each() function. I have tried with <style type="text/css"> tr.even { background-color: green; } tr.odd { background-color: yellow; } </style> $(document).ready(function () { $('table > tbody').each(function () { $('tr:odd', this).addClass('odd').removeClass('even'); $('tr:even', this).addClass('even').removeClass('odd'); }); }); Though this works but it accepts also "th" element. How to avoid that? Please help Thanks

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Getting a Script Error Every Time I Click a Link

- by Flip4Life

I have everything working perfectly on my site, but for some reason, I get an error message in console whenever I click a link anywhere on my site. The error has to do with this line of coding here: jQuery(function($){ $('.navbar a, .scroll a, .smoothscroll a').bind('click',function(event){ var $anchor = $(this); $('html, body').stop().animate({ scrollTop: $($anchor.attr('href')).offset().top }, 850,'easeInOutExpo'); event.preventDefault(); }); }); And the error I am getting is this: "SCRIPT5007: Unable to get value of the property 'top': object is null or undefined custom.min.js, line 6 character 197" The exact code it is highlighting is this part of the above code: $('html, body').stop().animate({ scrollTop: $($anchor.attr('href')).offset().top }, 850,'easeInOutExpo') All I know is that when I remove the above code, my scroll-to links stop working on pages such as these: http://www.northtownsremodeling.com/things-to-know.php You can see the popup error happen and stay in the console easily by going to a page with a filter like this: http://www.northtownsremodeling.com/bathroom/ And clicking one of the filter buttons. Ultimately, I am trying to make it so my scroll-to setting still works, but not have that error come up anymore. I made this script a long time ago, and I'm really confused as to what could be causing this error when everything is functioning perfectly otherwise? Thanks!

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null reference problems with c#

- by alex

Hi: In one of my window form, I created an instance of a class to do some works in the background. I wanted to capture the debug messages in that class and displayed in the textbox in the window form. Here is what I did: class A //window form class { public void startBackGroundTask() { B backGroundTask = new B(this); } public void updateTextBox(string data) { if (data != null) { if (this.Textbox.InvokeRequired) { appendUIDelegate updateDelegate = new appendUIDelegate(updateUI); try { this.Invoke(updateDelegate, data); } catch (Exception e) { Console.WriteLine(e.Message); } } else { updateUI(data); } } } private void updateUI(string data) { if (this.Textbox.InvokeRequired) { this.Textbox.Invoke(new appendUIDelegate(this.updateUI), data); } else { //update the text box this.Textbox.AppendText(data); this.Textbox.AppendText(Environment.NewLine); } } private delegate void appendUIDelegate(string data); } class B // background task { A curUI; public b( A UI) { curUI = UI; } private void test() { //do some works here then log the debug message to UI. curUI.updateTextBox("message); } } I keep getting a null reference exception after this.Invoke(updateDelegate, data); is called. I know passing "this" as a parameter is strange. But I want to send the debug message to my window form. Please help. Thanks

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Calling child constructor by casting (ChildClass)parentObject; to track revisions

- by FreshCode

To track revisions of a Page class, I have a PageRevision class which inherits from Page and adds a revision ID (Guid RevisionID;). If possible, how should I cast an existing Page object to a PageRevision and ensure that the PageRevision constructor is called to create a new revision ID? I could could have a PageRevision(Page page) constructor which generates the Guid and copies all the Page attributes, but I want to automate it, especially if a Page class has many attributes (and I later add one, and forget to modify the copy constructor). Desired use Page page = new Page(123, "Page Title", "Page Body"); // where 123 is page ID PageRevision revision = (PageRevision)page; // now revision.RevisionID should be a new Guid. Page, PageRevision classes: public class Page { public int ID { get; set; } public string Title { get; set; } public string Body { get; set; } } public class PageRevision : Page { public Guid RevisionID { get; set; } public PageRevision() { this.RevisionID = Guid.NewGuid(); } }

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Dropdown menu not showing when using position: absolute;

- by Xiy

I've just turned my website into a responsive layout and along the way I've somehow managed to make my dropdown menus not work. When hovering over 'Drop-downs' they don't display unless I'm using position: relative. They worked before using position: absolute - but it seems they only work with position relative now. When using relative it uses the width which messes up the navigation bar. Using relative: http://d.pr/i/tp5R Using absolute: http://d.pr/i/j7r1 CSS for my sub-menu div.left_first_header ul.sub-menu { width: 125px; top: 14px; z-index: 2; height: 100%; position: absolute; -webkit-border-radius: 0px 0px 4px 4px; -moz-border-radius: 0px 0px 4px 4px; background: url(images/drop_down_bg.jpg); padding-left: 15px; padding-right: 15px; background-repeat: repeat; } jQuery for the drop down functionality jQuery(document).ready(function ($) { jQuery("ul.dropdown li").hover(function() { $('ul:first',this).css('visibility', 'visible'); }, function() { jQuery(this).removeClass("hover"); jQuery('ul:first',this).css('visibility', 'hidden'); }); }); My website http://wpvault.com/kahlam/ Considering it's 4am I've probably made a really stupid simple mistake. I apologise if I've missed anything.

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CSS Style Firefox/Safari/Chrome

- by patrick

hi, i have a problem with css differences between browsers. i have a simple input textfield an a submit button. the should be arranged. with webkit (safari/webkit) everything looks fine but firefox doesnt do it. does anyone have an idea whats wrong? i have written a little test html page: <html> <head> <style type="text/css"> #input { background: none repeat scroll 0 0 white; border-color: #DCDCDC; border-style: solid; border-width: 1px 0 1px 1px; font: 13px "Lucida Grande",Arial,Sans-serif; margin: 0; padding: 5px 5px 5px 15px; width: 220px; outline-width: 0; height: 30px; } #submit { background: none repeat scroll 0 0 white; border: 1px solid #DCDCDC; font: 13px "Lucida Grande",Arial,Sans-serif; margin: 0; outline-width: 0; height: 30px; padding: 5px 10px; } </style> </head> <body> <input id="input" type="text" value="" /><input id="submit" type="button" value="Add" /> </body> </html>

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