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• how to get latest entry from a table for an item and do arithmatic operation on it?

  - by I Like PHP

  i have below tables tbl_rcv_items st_id | item_id |stock_opening_qnty |stock_received_qnty |stock_rcvd_date 14 1 0 70 2010-05-18 15 16 0 100 2010-05-06 16 10 0 59 2010-05-20 17 14 0 34 2010-05-20 20 1 70 5 2010-05-12 tbl_issu_items issue_id refer_issue_id item_id item_qntt item_updated 51 1 1 5 2010-05-18 19:34:29 52 1 16 6 2010-05-18 19:34:29 53 1 10 7 2010-05-18 19:34:29 54 1 14 8 2010-05-18 19:34:29 75 7 1 12 2010-05-18 19:40:52 76 7 16 1 2010-05-18 19:40:52 77 7 10 1 2010-05-18 19:40:52 78 7 14 1 2010-05-18 19:40:52 79 8 1 3 2010-05-19 11:28:50 80 8 16 5 2010-05-19 11:28:50 81 8 10 6 2010-05-19 11:28:50 82 8 14 7 2010-05-19 11:28:51 87 10 1 2 2010-05-19 12:51:03 88 10 16 0 2010-05-19 12:51:03 89 10 10 0 2010-05-19 12:51:03 90 10 14 0 2010-05-19 12:51:03 91 14 1 1 2010-05-19 18:43:58 92 14 14 3 2010-05-19 18:43:58 tbl_item_detail item_id item_name 1 shirt 2 belt 10 ball pen 14 vim powder 16 pant NOW if i want total available quantity for each item till today using both table total available quantity for an item =stock_opening_qnty+stock_received_qnty(LATEST ENTRY FROM (tbl_rcv_item) for that item id according to stock_rcvd_date) - SUM(item_qntt) for eg: if i want to know the available quantity for item_id=1 till today(25-05-2010) then it shoud be 70+5(latest entry for item_id till 25/5/2010)-23( issued till 25/5/2010)=52 i write below query , SELECT tri.item_id, tid.item_name, (tri.stock_opening_qnty + tri.stock_received_qnty) AS totalRcvQntt, SUM( tii.item_qntt ) AS totalIsudQntt FROM tbl_rcv_items tri JOIN tbl_issu_items tii ON tii.item_id = tri.item_id JOIN tbl_item_detail tid ON tid.item_id=tri.item_id WHERE tri.stock_rcvd_date <= CURDATE() GROUP BY (tri.item_id) which results Array ( [0] => Array ( [item_id] => 1 [item_name] => shirt [totalRcvQntt] => 70 [totalIsudQntt] => 46 ) [1] => Array ( [item_id] => 10 [item_name] => ball pen [totalRcvQntt] => 59 [totalIsudQntt] => 16 ) [2] => Array ( [item_id] => 14 [item_name] => vim powder [totalRcvQntt] => 34 [totalIsudQntt] => 20 ) [3] => Array ( [item_id] => 16 [item_name] => pant [totalRcvQntt] => 100 [totalIsudQntt] => 17 ) ) in above result total isuse quantity for shirt(item_id=1) shoube be 23 whereas results reflects 46 bcoz there are two row regrading item_id=1 in tbl_rcv_items, i only need the latest one(means which stock_rcvd_date is less than tommorow) please tell me where i doing mistake?? or rewrite the best query. thanks a lot!

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• Windows repair console, impossible?

  - by Daniel

  I found an old Windows XP SP2 in my -trash- cd can and tried it on a 30 GB FAT32 partition. Installation went fine till the copying operation was completed and XP asked for reboot. After that either it starts over again or throws invalid disk. Starting over is an infinite loop the only way I see is to choose the "Repair console" but I'm not used to a DOS box. Can anyone help me through this harmful installation?

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• Datagridview error

  - by Simon

  I have two datagridviews. So for the second one, i just copy-pasted the code from the first and changed where the difference was. But i get an error at the secod data grid when i want to view the result of my sql code. Translated in english the error show something like that there was no value given to at least one required parameter. Please help! private void button1_Click(object sender, EventArgs e) { string connectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=save.mdb"; try { database = new OleDbConnection(connectionString); database.Open(); date = DateTime.Now.ToShortDateString(); string queryString = "SELECT zivila.naziv,(obroki_save.skupaj_kalorij/zivila.kalorij)*100 as Kolicina_v_gramih " + "FROM (users LEFT JOIN obroki_save ON obroki_save.ID_uporabnika=users.ID)" + " LEFT JOIN zivila ON zivila.ID=obroki_save.ID_zivila " + " WHERE users.ID= " + a.ToString(); loadDataGrid(queryString); } catch (Exception ex) { MessageBox.Show(ex.Message); return; } } public void loadDataGrid(string sqlQueryString) { OleDbCommand SQLQuery = new OleDbCommand(); DataTable data = null; dataGridView1.DataSource = null; SQLQuery.Connection = null; OleDbDataAdapter dataAdapter = null; dataGridView1.Columns.Clear(); // <-- clear columns SQLQuery.CommandText = sqlQueryString; SQLQuery.Connection = database; data = new DataTable(); dataAdapter = new OleDbDataAdapter(SQLQuery); dataAdapter.Fill(data); dataGridView1.DataSource = data; dataGridView1.AllowUserToAddRows = false; dataGridView1.ReadOnly = true; dataGridView1.Columns[0].Visible = true; } private void Form8_Load(object sender, EventArgs e) { } private void button2_Click(object sender, EventArgs e) { string connectionString = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=save.mdb"; try { database = new OleDbConnection(connectionString); database.Open(); date = DateTime.Now.ToShortDateString(); string queryString = "SELECT skupaj_kalorij " + "FROM obroki_save " + " WHERE users.ID= " + a.ToString(); loadDataGrid2(queryString); } catch (Exception ex) { MessageBox.Show(ex.Message); return; } } public void loadDataGrid2(string sqlQueryString) { OleDbCommand SQLQuery = new OleDbCommand(); DataTable data = null; dataGridView2.DataSource = null; SQLQuery.Connection = null; OleDbDataAdapter dataAdapter = null; dataGridView2.Columns.Clear(); // <-- clear columns SQLQuery.CommandText = sqlQueryString; SQLQuery.Connection = database; data = new DataTable(); dataAdapter = new OleDbDataAdapter(SQLQuery); dataAdapter.Fill(data); dataGridView2.DataSource = data; dataGridView2.AllowUserToAddRows = false; dataGridView2.ReadOnly = true; dataGridView2.Columns[0].Visible = true; }

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• Mysql Joins - How to know which row is retrieved from which table...?

  - by SpikETidE

  Hi everyone... Consider i am using join on three tables to get a desired result-set... Now in that result set, is there anyway that i can find out which row comes from which table...?

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• Python Script to backup a directory

  - by rgolwalkar

  Filename:backup_ver1 import os import time 1 Using list to specify the files and directory to be backed up source = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\Dr Py\Final_Py' 2 define backup directory destination = r'C:\Documents and Settings\rgolwalkar\Desktop\Desktop\PyDevResourse' 3 Setting the backup name targetBackup = destination + time.strftime('%Y%m%d%H%M%S') + '.rar' rar_command = "rar.exe a -ag '%s' %s" % (targetBackup, ''.join(source)) i am sure i am doing something wrong here - rar command please let me know if os.system(rar_command) == 0: print 'Successful backup to', targetBackup else: print 'Backup FAILED' O/P:- Backup FAILED winrar is added to Path and CLASSPATH under Environment variables as well - anyone else with a suggestion for backing up the directory is most welcome

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• Memory efficient int-int dict in Python

  - by Bolo

  Hi, I need a memory efficient int-int dict in Python that would support the following operations in O(log n) time: d[k] = v # replace if present v = d[k] # None or a negative number if not present I need to hold ~250M pairs, so it really has to be tight. Do you happen to know a suitable implementation (Python 2.7)? EDIT Removed impossible requirement and other nonsense. Thanks, Craig and Kylotan! To rephrase. Here's a trivial int-int dictionary with 1M pairs: >>> import random, sys >>> from guppy import hpy >>> h = hpy() >>> h.setrelheap() >>> d = {} >>> for _ in xrange(1000000): ... d[random.randint(0, sys.maxint)] = random.randint(0, sys.maxint) ... >>> h.heap() Partition of a set of 1999530 objects. Total size = 49161112 bytes. Index Count % Size % Cumulative % Kind (class / dict of class) 0 1 0 25165960 51 25165960 51 dict (no owner) 1 1999521 100 23994252 49 49160212 100 int On average, a pair of integers uses 49 bytes. Here's an array of 2M integers: >>> import array, random, sys >>> from guppy import hpy >>> h = hpy() >>> h.setrelheap() >>> a = array.array('i') >>> for _ in xrange(2000000): ... a.append(random.randint(0, sys.maxint)) ... >>> h.heap() Partition of a set of 14 objects. Total size = 8001108 bytes. Index Count % Size % Cumulative % Kind (class / dict of class) 0 1 7 8000028 100 8000028 100 array.array On average, a pair of integers uses 8 bytes. I accept that 8 bytes/pair in a dictionary is rather hard to achieve in general. Rephrased question: is there a memory-efficient implementation of int-int dictionary that uses considerably less than 49 bytes/pair?

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• app engine jpa N-way joins ?

  - by cometta

  may i know is the latest version of jgae support N-way joins? or still limit to 2-way join? reference: http://gae-java-persistence.blogspot.com/2010/03/executing-simple-joins-across-owned.html?showComment=1276491851890_AIe9_BEqp-CCn0bibiOUY8JUbbSFwFE02aF9d68baX0squIcfBnve8K3iIT3IEhPhpJxEBSZQLlz8tH-NMq1XGzOV0fAA8othN4f3zhR2B6xN0WzsTRpyEZJl2vPDonhVY38iUhJGe8Ot9URs3IjYk4HoH9LG41az7l0blTBNNnpJuyI-xl5CDJGoPLGk5jw4tLvtvsCYhq3n7XuiZwJIaBMWjHSDdy7-fB1NYszI0G4f9JRjZ5UdDM4at3o3tAhd-CYK2Af1dnG#c3679507832415682306

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• bundler/capistrano is not installing gems with correct ruby version

  - by Douglas

  I'm trying to deploy my first app on a server with Capistrano, and I'm a bit lost with managing gemsets and ruby version. These are my (server and workstation) versions : Rails 3.2.8 RVM 1.16.17 Gem 1.8.24 Bundler 1.2.1 pg gem 0.14.1 My gemset are : Gemsets for ruby-1.9.3-p194 (found in /usr/local/rvm/gems/ruby-1.9.3-p194) (default) global = rail3dev20120606 I set the default gemset with : rvm use 1.9.3-p194@rail3dev20120606 --default --passenger When I run a : cap bundle:install The task end with success, but when I do a : gem list There are many missing gems though they are present in my Gemfile. When I go to check my gems in /var/www/opf/shared/bundle/ruby/ I find a folder called 1.9.1 and in /var/www/opf/shared/bundle/ruby/1.9.1/gems/ I can fond all of my needed gems (specified in Gemfile). I'm sure there is a problem with ruby version, but how do I solve this ? At the moment, if I do any rake command, I got a ruby crash [Bug] Segmentation fault, as it try to access the db and using postgresql_adapter. I think as many gems are missing there must have some gem dependencies not verified, and maybe a gem is using an incompatible ruby version 1.9.1 though it expect a 1.9.3. I think the issue is around managing ruby versions and gems. I'm certainly doing some mix with gemset and my capistrano deployement. I'm missing experience and info. Could anybody advise me how to handle this on the server ? What are the best practices ? How am I suppose to update my ruby version ? with Capistrano deploy.rb ? manually ? with/without rvm ? I saw a new version of ruby 1.9.3-p327 has just released. Should I use gemset or not ? What about the :rvm_ruby_string in my deploy.rb. Is it correctly spelled or should I remove the p194 part ? Should I Remove the :rvm_ruby_string ? Keep it ? Use a .rvmrc file ??? I'm really lost and some kind help would be welcome. This is my config/deploy.rb in any case : require 'bundler/capistrano' require File.join(File.dirname(__FILE__), 'deploy') + '/capistrano_database' set :rvm_type, :system set :rvm_ruby_string, 'ruby-1.9.3-p194@rail3dev20120606' require 'rvm/capistrano' set :application, 'opf' set :deploy_to, '/var/www/opf' set :rails_env, 'production' set :user, 'the_user' set :use_sudo, false set :group_writable, false set :scm, :git set :repository, '[email protected]:user/opf.git' set :branch, 'master' default_run_options[:pty] = true set :deploy_via, :remote_cache server '192.168.5.200', :web, :app, :db, :primary => true # If you are using Passenger mod_rails uncomment this: namespace :deploy do task :start do ; end task :stop do ; end task :restart, :roles => :app, :except => { :no_release => true } do run "#{try_sudo} touch #{File.join(current_path,'tmp','restart.txt')}" end end Thanks for any help

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• Can't concatenate 2 arrays in PHP

  - by alex

  I've recently learned how to join 2 arrays using the + operator in PHP. But consider this code... $array = array('Item 1'); $array += array('Item 2'); var_dump($array); Output is array(1) { [0]= string(6) "Item 1" } Why does this not work? Skipping the shorthand and using $array = $array + array('Item 2') does not work either. Does it have something to do with the keys?

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• How do you encrypt parts of a file separately using pgp?

  - by Collin Anderson

  I would like to encrypt credit card numbers on a web server as they come in using PGP. I would then like to be able to export all of the credit card numbers and other information in one file that can be easily decrypted using standard PGP software. Is it possible to take the encrypted credit card numbers and join them with other encrypted data and be able to decrypt the entire file? Basically is this true? D(E(x) + E(y)) = x + y Where '+' means string concatenation.

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• linq multiple condition on "on" clause

  - by swapna

  I have a query which have multiple conditions on on clause select * FROM CATALOGITEM with (nolock) INNER JOIN CATALOG with (nolock) ON CATALOGITEM.catalog_id = CATALOG.catalog_id and not(catalog.catalog_id = 21) and not(catalog.catalog_id = 20) WHERE ( CATALOGITEM.publish_code = 'upd' OR CATALOG_ITEM.publish_code = 'ins' OR PRODUCT.publish_code = 'upd' OR PRODUCT.publish_code = 'ins' ) How to write this in linq. Please advice.

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• Is derived table executed once or three times?

  - by AspOnMyNet

  Every time you make use of a derived table, that query is going to be executed. When using a CTE, that result set is pulled back once and only once within a single query. Does the quote suggest that the following query will cause derived table to be executed three times ( once for each aggregate function’s call ): SELECT AVG(OrdersPlaced),MAX(OrdersPlaced),MIN(OrdersPlaced) FROM ( SELECT v.VendorID, v.[Name] AS VendorName, COUNT(*) AS OrdersPlaced FROM Purchasing.PurchaseOrderHeader AS poh INNER JOIN Purchasing.Vendor AS v ON poh.VendorID = v.VendorID GROUP BY v.VendorID, v.[Name] ) AS x thanx

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• return 0 with sql query instead of nothing

  - by user1202606

  How do I return a 0 with as Responses with the PossibleAnswerText if count is 0? Right now it won't return anything. select COUNT(sr.Id) AS 'Responses', qpa.PossibleAnswerText from CaresPlusParticipantSurvey.QuestionPossibleAnswer as qpa join CaresPlusParticipantSurvey.SurveyResponse as sr on sr.QuestionPossibleAnswerId = qpa.Id where sr.QuestionPossibleAnswerId = 116 GROUP BY qpa.PossibleAnswerText

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• SQL Code Smells

  - by Lijo

  Hi Team, Could you please list some of the bad practices in SQL, that novice people do? I have found the use of "WHILE loop" in scenarios which could be resolved using set operations. Another example is inserting data only if it does not exist. This can be achieved using LEFT OUTER JOIN. Some people go for "IF" Any other thoughts? Thanks Lijo

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• does BeautifulSoup strips inline CSS and javascript content

  - by goh

  hey guys does beautifulSoup strips css and javascript content? after using content3 = ''.join(BeautifulSoup(content).findAll(text=True)) i still have them lingering around.

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• How ton put give alias name inside a Query string.?

  - by Vibin Jith

  Please look that alias name. I hope to set the value into a string var. How to put single coats inside a string which is in single coats. SET @SQLString = N'SELECT purDetQty as 'detQty',stkBatchCode as 'batchCode',purDetProductId as 'productId' INTO #ProductTable FROM PurchaseDetail INNER JOIN Stock on stkId=purDetStockId WHERE purDetID=@detId'

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• Running resize2fs on /

  - by Paul Steckler

  I'm trying to resize an ext4 filesystem on a Fedora 11 box. Using fsdisk and lvm, I was able to grow the partition and logical volume containing the filesystem. When I try to run resize2fs on the device containing the filesystem (/dev/sda2 in this case), I get: "Device or resource busy while trying to open /dev/sda2, Couldn't find valid filesystem superblock" I've tried this from a rescue disk that doesn't have the filesystem mounted, no joy. Maybe resize2fs doesn't know about ext4?

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• What are the DB smells?

  - by Jonas Byström

  We all know 'code smells', but what are the fundamental 'database smells'? I'm a DB n00b, but I'll give an example of something that I find fishy. It seems to me like when I have to join 6-8 tables together to optimize our loading that we have a DB smell? Or would that be a pretty 'normal' database layout? (Sure, early optimization is the root of all evil, but this seems to me like early pessimisation, not to mention the cumbersomeness?)

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• How do i program a simple IRC bot in python?

  - by Jake

  Hi every one. I need help writing a basic IRC bot that just connects to a channel.. is anyone able to explain me this? I have managed to get it to connect to the IRC server but i am unable to join a channel and log on. The code i have thus far is: import sockethost = 'irc.freenode.org' port = 6667 join_sock = socket.socket() join_sock.connect((host, port)) <code here> Any help would be greatly appreciated.

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• Rewrite SQL Fulltext Function to return Table only

  - by Alex

  I have a MS SQL Fulltext Function like this: (...) RETURNS TABLE AS RETURN SELECT * FROM fishes INNER JOIN CONTAINSTABLE(fishes, *, @keywords, @limit) AS KEY_TBL ON fishes.id = KEY_TBL.[KEY] When I use this function in LINQ, it generates a special return type which includes all fields of my "fishes" table, plus Key and Rank. How could I rewrite above query, or change something in LINQ, to omit Key and Rank and just return my "fishes" results (and to have the fulltext search result objects be of type Fish, which is what I really care about, so I don't have to cast)?

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• Whats for to use GO

  - by Incognito

  I am interested in new language from Google, GO. I have checked the materials in the golang.com. And now want to use GO in practice. Please share any ideas whats for you are using GO. Or are there any open source GO projects that it would be possible to join?

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• MySQL - Order results by relevancy, LEFT JOINS and more

  - by XaviEsteve

  Hi guys, I am trying to get some results ordered by total votes (where client votes count 2 points and other people votes are 1 point). tab_names: +-----------+ | Name | id | +------+----+ | John | 1 | | Paul | 2 | +------+----+ tab_votes: +--------+-----------+ | idname | ip | +--------+-----------+ | 2 | 127.0.0.1 | | 2 | 127.0.0.1 | | 2 | 82.23.5.1 | | 1 | 127.0.0.1 | +--------+-----------+ This is the MySQL query I've got but doesn't work: SELECT * COUNT(v.idname) AS totalvotes, (SELECT COUNT(v.ip) FROM tab_votes WHERE v.ip LIKE '$ip') AS uservotes FROM tab_names n LEFT JOIN tab_votes v ON n.id = v.idname GROUP BY n.name ORDER BY uservotes DESC, totalvotes DESC LIMIT 40

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• Retrieving multipel rows in MS SQL but distinct filteringen only on one

  - by Nicklas

  I have this: SELECT Product.ProductID, Product.Name, Product.GroupID, Product.GradeID, AVG(tblReview.Grade) AS Grade FROM Product left Join tblReview ON Product.GroupID = tblReview.GroupID WHERE (Product.CategoryID = @CategoryID) GROUP BY Product.ProductID, Product.Name, Product.GroupID, Product.GradeID I would like to return only the rows where Product.Name is unique. If I make a SELECT DISTINCT the ProductID is diffrent on every row so all the rows are unique. Thanks in andvance

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• jQuery: Setting 'style' attribute of element with object

  - by JamesBrownIsDead

  I saw this in our codebase the other day: link.attr('style', map({ color: '#9a4d9e', cursor: 'default' })); map is defined as: function map(map) { var cssValue = []; for (var o in map) { cssValue.push(o + ':' + map[o] + ';') } return cssValue.join(';'); } Is map necessarily? Is there a shorter way to do this? It's important to note that the "style" attribute overrides any styles set by a class added/defined in the "class" attribute.

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• MYSQL get the name from another table that is associated with the first table

  - by Juan Gonzales

  I can't figure out why this statement is not working SELECT myChurches.id AS id, myChurches.church_name AS church_name FROM myChurches INNER JOIN church_staff ON church_staff.church_id=myChurches.id WHERE church_staff.mem_id='$logOptions_id' ORDER BY myChurches.church_name ASC Basically I need to find the person's that are staff members of a church from one table and want to get the 'name' of that church FROM the 'myChurches' table. Hopefully that makes sense. Thanks in advance

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