Python opening a file and putting list of names on separate lines
- by Jeremy Borton
I am trying to write a python program using Python 3
I have to open a text file and read a list of names, print the list, sort the list in alphabetical order and then finally re-print the list.
There's a little more to it than that BUT the problem I am having is that I'm supposed to print the list of names with each name on a separate line
Instead of printing each name on a separate line, it prints the list all on one line.
How can I fix this?
def main():
#create control loop
keep_going = 'y'
#Open name file
name_file = open('names.txt', 'r')
names = name_file.readlines()
name_file.close()
#Open outfile
outfile = open('sorted_names.txt', 'w')
index = 0
while index < len(names):
names[index] = names[index].rstrip('\n')
index += 1
#sort names
print('original order:', names)
names.sort()
print('sorted order:', names)
#write names to outfile
for item in names:
outfile.write(item + '\n')
#close outfile
outfile.close()
#search names
while keep_going == 'y' or keep_going == 'Y':
search = input('Enter a name to search: ')
if search in names:
print(search, 'was found in the list.')
keep_going = input('Would you like to do another search Y for yes: ')
else:
print(search, 'was not found.')
keep_going = input('Would you like to do another search Y for yes: ')
main()
