How add loading image using jquery?
- by user244394
I'm working on a form,
<form id="myform" class="form">
</form>
that gets submitted to the server using jquery ajax.
How can I refresh the form on success to show the updated form information and add a spinner until the form loads?
here is my html and jquery snippet
<div class="container">
<div class="page-header">
<div class="span2">
<!--Sidebar content-->
<img src="img/emc_logo.png" title="EMC" >
</div>
<div class="span6">
<h2 class="form-wizard-heading">Configuration</h2>
</div>
</div>
<form id="myform" class="form">
</form>
</div> <!-- /container -->
<!-- Modal -->
<div id="myModal" class="modal hide fade" tabindex="-1" role="dialog" aria-labelledby="myModalLabel" aria-hidden="true">
<div class="modal-header">
<button type="button" class="close" data-dismiss="modal" aria-hidden="true">×</button>
<h3 id="myModalLabel">Configuration Changes</h3>
<p><span class="label label-important">Please review your changes before submitting. Submitting the changes will result in rebooting the cluster</span></p>
</div>
<div class="modal-body">
<table class="table table-condensed table-striped" id="display"></table>
</div>
<div class="modal-footer">
<button id="cancel" class="btn" data-dismiss="modal" aria-hidden="true">Close</button>
<button id="save" class="btn btn-primary">Save changes</button>
</div>
</div>
//Jquery part
$(document).ready(function () {
$('input').hover(function () {
$(this).popover('show')
});
// On mouseout destroy popout
$('input').mouseout(function () {
$(this).popover('destroy')
});
$('#myform').on('submit', function (ev) {
ev.preventDefault();
var data = $(this).serializeObject();
json_data = JSON.stringify(data);
$('#myModal').modal('show');
$.each(data, function (key, val) {
var tablefeed = $('<tr><td>' + key + '</td><td id="' + key + '">' + val + '</td><tr>').appendTo('#display');
});
$(".modal-body").html(tablefeed);
});
$("#cancel").click(function () {
$("#display").empty();
});
$(function () {
$("#save").click(function () {
// validate and process form here
alert("button submitted" + json_data);
$.ajax({
type: "POST",
url: "somefile.json.",
data: json_data,
contentType: 'application/json',
success: function (data, textStatus, xhr) {
console.log(arguments);
console.log(xhr.status);
alert("Your form has been submitted: " + textStatus + xhr.status);
},
error: function (jqXHR, textStatus, errorThrown) {
alert(jqXHR.responseText + " - " + errorThrown + " : " + jqXHR.status);
}
});
});
});
});
