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  • OpenGL Pixel Format Attributes (NSOpenGLPixelFormatAttibutes) explanation?

    - by nacho4d
    Hi, I am not new to OpenGL, but not an expert. Many tutorials teach how to draw, 3D, 2D, projections, orthogonal, etc, but How about setting a the view? (NSOpenGLView in Cocoa, Macs). For example I have this: - (id) initWithFrame: (NSRect) frame { GLuint attribs[] = { //PF: PixelAttibutes NSOpenGLPFANoRecovery, NSOpenGLPFAWindow, NSOpenGLPFAAccelerated, NSOpenGLPFADoubleBuffer, NSOpenGLPFAColorSize, 24, NSOpenGLPFAAlphaSize, 8, NSOpenGLPFADepthSize, 24, NSOpenGLPFAStencilSize, 8, NSOpenGLPFAAccumSize, 0, 0 }; NSOpenGLPixelFormat* fmt = [[NSOpenGLPixelFormat alloc] initWithAttributes: (NSOpenGLPixelFormatAttribute*) attribs]; return self = [super initWithFrame:frame pixelFormat: [fmt autorelease]]; } And I don't understand very well their usage, specially when combining them. For example: If I want my view to be capable of full screen should I write NSOpenGLPFAFullScreen only ? or both? (by capable I mean not always in full screen) Regarding Double Buffer, what is this exactly? (Below: Apple's definition) If present, this attribute indicates that only double-buffered pixel formats are considered. Otherwise, only single-buffered pixel formats are considered Regarding Color: if NSOpenGLPFAColorSize is 24 and NSOpenGLPFAColorSize is 8 then it means that alpha and RGB components are treated differently? what happen if I set the former to 32 and the later to 0? Etc, etc,In general how do I learn to set my view from scratch? Thanks in advance. Ignacio.

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  • java setting resolution and print size for an Image

    - by Ingrid
    I wrote a program that generates a BufferedImage to be displayed on the screen and then printed. Part of the image includes grid lines that are 1 pixel wide. That is, the line is 1 pixel, with about 10 pixels between lines. Because of screen resolution, the image is displayed much bigger than that, with several pixels for each line. I'd like to draw it smaller, but when I scale the image (either by using Image.getScaledInstance or Graphics2D.scale), I lose significant amounts of detail. I'd like to print the image as well, and am dealing with the same problem. In that case, I am using this code to set the resolution: HashPrintRequestAttributeSet set = new HashPrintRequestAttributeSet(); PrinterResolution pr = new PrinterResolution(250, 250, ResolutionSyntax.DPI); set.add(pr); job.print(set); which works to make the image smaller without losing detail. But the problem is that the image is cut off at the same boundary as if I hadn't set the resolution. I'm also confused because I expected a larger number of DPI to make a smaller image, but it's working the other way. I'm using java 1.6 on Windows 7 with eclipse.

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  • Stil facing the problem in Orientation in iphone

    - by aman-gupta
    Hi, In my application I have 15 screens in that i m using UIViewController for all screens and in all screens i m using the below way to call other screen :- AppDelegate *appRefre = (AppDelegate *)[[UIApplication sharedApplication]delegate]; [self.navigationController pushViewController:appRefre.frmReferencesLink animated:YES]; And the below code is activated in all screen for orientation to control the user to switch from one orientation to other mode (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { if (interfaceOrientation == UIInterfaceOrientationPortrait) { return YES; } else { return NO; } } But when i run my application in iPhone device my application gets terminated when i physically rotate my iphone device from UIInterfaceOrientationPortrait to UIInterfaceOrientationPortraitUpsideDown or UIInterfaceOrientationLandscapeLeft,UIInterfaceOrientationLandscapeRight. And One more things is that when my application lauch i used following code for launching my appliaction :- 1) I made a pointer in mydelegate.h file: UINavigationController *navigationController; Then synthesize its property @property(nonatomic,retain)UINavigationController *navigationController 2) In mydelegat.m I Wrote @synthesize navigationController; (void)applicationDidFinishLaunching:(UIApplication *)application { navigationController = [[UINavigationController alloc] initWithRootViewController:DefaultViewLink]; [window addSubview:navigationController.view]; [window makeKeyAndVisible]; } 3) In above point DefaultView is launch first and gets remove from view and then actual my appliaction come into picture. So exactly what i want i want my appliaction to be in portrait mode for all screens i dont want my appliaction will switch to other mode.It remains the same as in portrait mode after rotation to any other mode. Please help me out its very urgent. Thanks in Advance and humble request to help me out

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  • Active State Image Display

    - by fmz
    I have some images that need to change, based not only on hover, but also on active state. If you look at the page here: http://site427.mysite4now.net/tazthedog/site1/ There are some tabs with Screen Printing Quick Links, etc. The tab image is associated with the link and displays properly. The icon in tabs defaults to the gray and turns blue on mouse over, however, I also need it to be blue on the "active" state. Here is the css: .quick-links em:hover { background: transparent url(../images/quick-links.png) 10px 9px no-repeat ; display: block ; float: left; } Here is the html: <ul class="tabs"> <li class="quick-links"> <a href="#quickLinks" id=""> <em> <span>Screen Printing Quick Links</span> </em> </a> </li> <li class="distributor-ql"> <a href="#distributorQL" id=""> <em> <span>Dealer &amp; Distributor Quick Links</span> </em> </a> </li> </ul> I tried adding a .quick-links em:active... but that doesn't maintain it. I know there is a way to keep the icon blue while in the active state, I just need a little help to understand what that is. Thanks!

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  • Changing direction of rotation Pygame

    - by czl
    How would you change the direction of a rotating image/rect in Pygame? Applying positive and negative degree values works but it seems to only be able to rotate one direction throughout my window. Is there a way to ensure a change in direction of rotation? Perhaps change up rotation of a spinning image every 5 seconds, or if able to change the direction of the spin when hitting a X or Y axis. I've added some code below. It seems like switching movement directions is easy with rect.move_ip as long as I specify a speed and have location clause, it does what I want. Unfortunately rotation is't like that. Here I'l adding angles to make sure it spins, but no matter what I try, I'm unable to negate the rotation. def rotate_image(self): #rotate image orig_rect = self.image.get_rect() rot_image = pygame.transform.rotate(self.image, self.angle) rot_rect = orig_rect.copy() rot_rect.center = rot_image.get_rect().center rot_image = rot_image.subsurface(rot_rect).copy() return rot_image def render(self): self.screen.fill(self.bg_color) self.rect.move_ip(0,5) #Y axis movement at 5 px per frame self.angle += 5 #add 5 anglewhen the rect has not hit one of the window self.angle %= 360 if self.rect.left < 0 or self.rect.right > self.width: self.speed[0] = -self.speed[0] self.angle = -self.angle #tried to invert the angle self.angle -= 5 #trying to negate the angle rotation self.angle %= 360 self.screen.blit(self.rotate_image(),self.rect) pygame.display.flip() I would really like to know how to invert rotation of a image. You may provide your own examples.

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  • Web page for IPhone - Large fonts instead of scrolling?

    - by chris_l
    I'm planning the layout of my web page, which should also be usable on the IPhone. I don't really have much experience with the IPhone yet - I just installed the IPhone Simulator on my Mac. The page's contents are flexible, so I think it would be better to use this flexibility to avoid that the user has to scroll around the entire page. Especially I have A header and a sidebar that will be used all the time to perform several actions. A main content area with a number of elements (e.g. images). The UI would stay usable pretty well, if the number of elements shown at one time is reduced for a small screen (e.g. by JavaScript). It would also be okay to make the main content area scrollable (as opposed to the entire page). The problem: If I simply display the page on the IPhone, it uses an extremely small font size, so that users must zoom in first, and then scroll around - so that they can't see the header and sidebar all the time. What's the best way to deal with this situation? Just leave it this way (very small fonts), because users expect that behaviour on the IPhone? Increase the font size (by specifying it in em or px or with xx-large, or what would be the best way?), if I detect - somehow - that it's being displayed on the IPhone. Or is there some way to restrict the viewport size to the screen size, and make it zoom in automatically? I think that would be the easiest solution in my case. Or ...?

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  • Drawing animation

    - by HHHH
    I'm creating a simple app where when the user presses a button, a series of lines will be drawn on the screen and the user will be able to see these lines drawn in real time (almost like an animation). My code looks something like this (has been simplified): UIGraphicsBeginImageContext(CGSizeMake(300,300)); CGContextRef context = UIGraphicsGetCurrentContext(); for (int i = 0; i < 100; i++ ) { CGContextMoveToPoint(context, i, i); CGContextAddLineToPoint(context, i+20, i+20); CGContextSetStrokeColorWithColor(context, [[UIColor blackColor] CGColor]); CGContextStrokePath(context); } UIImage *newImage = UIGraphicsGetImageFromCurrentImageContext(); UIGraphicsEndImageContext(); My problem is that: 1) As soon as the user presses the button, the UIThread blocks until the drawing is done. 2) I can't get the lines to be drawn on the screen one at a time - I've tried setting the UIImage directly inside the loop and also tried setting a layer content inside the loop. How do I get around these problems?

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  • Typical Search, Result and Detail Workflow Staying Within an Android Tab

    - by Justin
    So, I've been banging my head looking for a good solution for a few days and am stuck. I have a search screen (Activity) in a tab, and after the user enters a value and clicks "search" I would like the results to come back in that same tab, and then if an item from the results is selected, to show more detailed results, in that same tab. I have it all working now in separate activities, and even the first step working in a tab, but as soon as I call the activity to process he search results... i.e. startActivity(i); for the results Activity, the results displayed are not in the tab! I am having a very difficult time getting this flow to work all under a tab. Any thoughts on how to make this happen? I keep hearing that Android views should be used instead of activities, but am I then to assume that all the logic I have right now for 3 activity needs to go inside 1 activity and then I need to handle setting the content and state for each of these cases? Plus, won't the history stack not work as pressing the back button will take the user out of the application, instead of taking them from say the search result to the search screen, or the details to the search results, etc. This seems like a mess. Can anyone show a more complex example of tabs or how one might have a simple search, result and detail workflow staying in a tab? I have seen a few questions on this concept of keeping activities "within a tab", but no good resolution. Please help.

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  • Doing some downloading without blocking you app

    - by Code
    Hi guys, I'm working on my first app that's doing a few different web connections at once. My first screen is my Menu. And at the bottom of viewDidLoad of MenuViewController i call a method that gets and parses a .xml file that is located on my webserver. Also at the bottom of viewDidLoad i do FootballScores = [[FootBallScores alloc] init]; and FootballScores makes a connection to a html page which it loads into a string and then parses out data. Now since both of these are getting called at the bottom of viewDidLoad of the class thats is responsible for the main menu(first screen in the app) it means the app is kinda slow to load. What is the right way to do the above? Should i remove the 2 pieces of code from my viewDidLoad and replace with maybe dataGetterOne = [NSTimer scheduledTimerWithTimeInterval:1.000 target:self selector:@selector(xmlParser) userInfo:nil repeats:NO]; dataGetterTwo = [NSTimer scheduledTimerWithTimeInterval:2.000 target:self selector:@selector(htmlParser) userInfo:nil repeats:NO]; This would mean that the methods get called later on and the viewDidLoad gets to finish before the i try get the data from the web servers. Making 2 connections to we bservers a second apart to quick? Can the iphone handle having 2 connections open at once? I'm really unsure of anything bad/dangerous I am doing in regards to connections. Many Thanks -Code

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  • How to make buttons in python/pygame?

    - by user1334014
    I'm making a game in pygame and on the first screen I want there to be buttons that you can press to (i) start the game, (ii) load a new screen with instructions, and (iii) exit the program. I've found this code online for button making, but I don't really understand it (I'm not that good at object oriented programming). If I could get some explanation as to what it's doing that would be great. Also, when I use it and try to open a file on my computer using the file path, I get the error sh: filepath :Permission denied, which I don't know how to solve. #load_image is used in most pygame programs for loading images def load_image(name, colorkey=None): fullname = os.path.join('data', name) try: image = pygame.image.load(fullname) except pygame.error, message: print 'Cannot load image:', fullname raise SystemExit, message image = image.convert() if colorkey is not None: if colorkey is -1: colorkey = image.get_at((0,0)) image.set_colorkey(colorkey, RLEACCEL) return image, image.get_rect() class Button(pygame.sprite.Sprite): """Class used to create a button, use setCords to set position of topleft corner. Method pressed() returns a boolean and should be called inside the input loop.""" def __init__(self): pygame.sprite.Sprite.__init__(self) self.image, self.rect = load_image('button.png', -1) def setCords(self,x,y): self.rect.topleft = x,y def pressed(self,mouse): if mouse[0] > self.rect.topleft[0]: if mouse[1] > self.rect.topleft[1]: if mouse[0] < self.rect.bottomright[0]: if mouse[1] < self.rect.bottomright[1]: return True else: return False else: return False else: return False else: return False def main(): button = Button() #Button class is created button.setCords(200,200) #Button is displayed at 200,200 while 1: for event in pygame.event.get(): if event.type == MOUSEBUTTONDOWN: mouse = pygame.mouse.get_pos() if button.pressed(mouse): #Button's pressed method is called print ('button hit') if __name__ == '__main__': main() Thank you to anyone who can help me.

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  • How to detect iPhone movement in space using accelerometer ?

    - by super_tomtom
    Hi ! I am trying to make an application that would detect what kind of shape you made with your iPhone using accelerometer. As an example, if you draw a circle with your hand holding the iPhone, the app would be able to redraw it on the screen. This could also work with squares, or even more complicated shapes. The only example of application I've seen doing such a thing is AirPaint (http://vimeo.com/2276713), but it doesn't seems to be able to do it in real time. My first try is to apply a low-pass filter on the X and Y parameters from the accelerometer, and to make a pointer move toward these values, proportionally to the size of the screen. But this is clearly not enought, I have a very low accuracy, and if I shake the device it also makes the pointer move... Any ideas about that ? Do you think accelerometer data is enought to do it ? Or should I consider using other data, such as the compass ? Thanks in advance !

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  • Output error in comparing characters from two strings

    - by Andrew Martin
    I'm stuck with my a piece of code I'm creating. My IDE is Eclipse and when I use its debugging feature, to trace what's happening on each line, it outputs perfectly. However, when I click the "run" project, it just outputs a blank screen: public static void compareInterests(Client[] clientDetails) { int interests = 0; for (int p = 0; p < numberOfClients; p++) { for (int q = 0; q < numberOfClients; q++) { String a = clientDetails[p].getClientInterests(); String b = clientDetails[q].getClientInterests(); int count = 0; while (count < a.length()) { if (a.charAt(count) == b.charAt(count)) interests++; count++; } if ((interests >= 3) && (clientDetails[p].getClientName() != clientDetails[q].getClientName())) System.out.print (clientDetails[p].getClientName() + " is compatible with " + clientDetails[q].getClientName()); interests = 0; } } } The code is designed to import an object array which contains information on a client's name and a client's interests. The client's interests are stored in the format "01010", where each 1 means they are interested in that activity, each 0 means they are not. My code compares each character of every client's string with every other client's string and outputs the results for all client's that don't have the same name and have three or more interests in common. When I run this code through Java's debugger, it outputs fine - but when I click run project or compile, I just get a blank screen. Any ideas?

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  • Why would dynamically changing the stroke type of a GestureOverlayView cause unusual behaviour?

    - by Rob Kent
    I recently introduced multi-stroke gestures into my application. This is a preference so I set the StrokeType dynamically in Activity.OnCreate. What I have discovered is that if you change the StrokeType so that it is different to the setting in the layout file, it changes the behaviour of the GestureOverlayView in the following way. The normal behaviour is that you draw a gesture and it stays on the screen after it is drawn. When you change the stroke type dynamically however, any gesture drawn on the screen disappears immediately after the OnGestureEnded event has fired. I reloaded the sample GesturesBuilder application and confirmed it has the same problem if you add the second line shown here: GestureOverlayView overlay = (GestureOverlayView) findViewById(R.id.gestures_overlay); overlay.setGestureStrokeType(GestureOverlayView.GESTURE_STROKE_TYPE_SINGLE); overlay.addOnGestureListener(new GesturesProcessor()); } The default in the layout is MULTIPLE but changing it to single changes the behaviour. If you keep the above line but set it to what it already is, the behaviour is not affected. Is this a bug in the Android gestures library and does anyone know a workaround? Note that this is on an HTC Magic so it could also be a handset issue.

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  • Android getSelectedItem, how to use?

    - by user1881184
    Im trying use the spinner control result in order to point it to another screen that would be on the app. For example in the spinner control if the user chose chevy it would then take you to another screen which is coded in chevy.xml and Chevy.class. This is what i have thus far and need some help, as our book only used getSelectedItem and the example was only for an output statement. Please help. import android.app.Activity; import android.content.Intent; import android.os.Bundle; import android.view.View; import android.widget.AdapterView; import android.widget.AdapterView.OnItemSelectedListener; import android.widget.Spinner; public class Mainpage extends Activity implements OnItemSelectedListener { String carChoice, chevy, ford, dodge, toyota; public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.activity_main); /* carChoice = group.getSelectedItem().toString(); } if (carChoice.compareTo(chevy)==0) { startActivity(new Intent(Mainpage.this, Chevy.class)); */ } public void onItemSelected(AdapterView<?> arg0, View arg1, int arg2, long arg3) { final Spinner group = (Spinner) findViewById(R.id.carGroup); group.setOnItemSelectedListener(this); // TODO Auto-generated method stub String selected = group.getItemAtPosition(1).toString(); } public void onNothingSelected(AdapterView<?> arg0) { // TODO Auto-generated method stub } }

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  • Draggable cards (touch enumeration) issue

    - by glitch
    I'm trying to let a player tap, drag and release a card from a fanned stack on the screen to a 4x4 field on the board. My cards are instantiated from a custom class that inherits from the UIImageView class. I started with the Touches sample app, and I modified the event handlers for touches to iterate over my player's card hand instead of the 3 squares the sample app allows you to move on screen. Everything works, until that is, I move the card I'm dragging near another card. I'm really drawing a blank here for the logic to get the cards to behave properly. Here's my code: - (void)touchesBegan:(NSSet *)touches withEvent:(UIEvent *)event { NSUInteger numTaps = [[touches anyObject] tapCount]; if(numTaps = 1) { for (UITouch *touch in touches) { [self dispatchFirstTouchAtPoint:[touch locationInView: self.boardCardView] forEvent:nil]; } } } -(void) dispatchFirstTouchAtPoint:(CGPoint)touchPoint forEvent:(UIEvent *)event { for (int i = 0; i<5; i++) { UIImageView *touchedCard = boardBuffer[i]; if (CGRectContainsPoint([touchedCard frame], touchPoint)) { [self animateFirstTouchAtPoint:touchPoint forView:touchedCard]; } } } - (void)touchesMoved:(NSSet *)touches withEvent:(UIEvent *)event { NSUInteger touchCount = 0; for (UITouch *touch in touches){ [self dispatchTouchEvent:[touch view] toPosition:[touch locationInView:self.boardCardView]]; touchCount++; } } My questions are: How do I get the touch logic to disallow other cards from being picked up by a dragging finger? Is there anyway I can only enumerate the objects that are directly below a player's finger and explicitly disable other objects from responding? Thanks!

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  • Collision between 2 objects of the same class

    - by user1826033
    Okay, so I have an enemy class(With rotation, position, texture and so on). I spawn a few enemies on the screen, they move around, but they overlap each other. So I tried to do a collision check between two enemies of the same class. But no matter what method I try, it isn't quite working. The best thing I tried was: foreach (Enemy enemy1 in enemies) { enemy1Pos = new Vector2(enemy1.position.X, enemy1.position.Y) foreach (Enemy enemy2 in enemies) { enemy2Pos = new Vector2(enemy2.position.X, enemy2.position.Y) if (Vector2.Distance(enemy2Pos, enemy1Pos) < 200) { enemy1Pos += new Vector2((float)(enemy1.Speed * Math.Cos(enemy1.Rotation)), (float)(enemy1.Speed * Math.Sin(enemy1.Rotation))); } } } This is not to exact code, so it might have some mistakes in it. Anyway when i implemented this solution, the enemies were not overlapping so everything was fine on that part. But, they were always moving to the right side of the screen. I've also looked up flocking etc, but I would like to know, how can I detect collision between 2 objects of the same class?

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  • Detect that the onscreen keyboard has been displayed on Windows Phone 7

    - by David_001
    Simple question: How do I detect that the onscreen keyboard has been displayed on windows mobile 7? Is there an event I can add a listener to? It takes up about half the screen and I want to scroll the view up when it gets displayed... EDIT: A comment below indicates more clearly what I'm trying to do: I have a textbox input, and as the user types into it an autocomplete dropdown appears below it (like google suggest). By default, the active control (the textbox) scrolls into view when focussed, and the onscreen keyboard is directly below it. The onscreen keyboard appears in front of my autocomplete dropdown - what I want to do is make the screen scroll a little further up, so there's some room for my dropdown to be shown. The windows phone UI design guidelines say: "When the keyboard is deployed, the application should scroll to ensure the active edit control and the caret are in view". This happens fine, it's just the non-active dropdown gets hidden behind the onscreen keyboard. The guidelines also say that an application can choose to show the onscreen keyboard, and can also choose to close it. At the moment i'm stuck, and I don't think (based on my research and the replies to this question) that it's possible to detect that the onscreen keyboard has been displayed. I'm moving my investigation to see if it's possible to determine the "visible area" of the page (width & height in pixels for example), and combine this with an onfocus for the textbox... not sure if this will prove fruitful though.

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  • Setting Android webview initialScale prevents proper zooming

    - by Ryan
    Need: I want a webview to automatically be sized to fit the width of that particular page. I have Googled this and found several different suggestions. Most of them work. But then each of them effects zooming in / zooming out. What I'm looking for is a solution that accomplishes both. The webview is initially set to fill the screen, but then it allows the user to zoom in (with pinching) and zoom out. What I've Tried: mainView.getSettings().setLoadWithOverviewMode(true); mainView.getSettings().setUseWideViewPort(false); mainView.setScrollBarStyle(WebView.SCROLLBARS_OUTSIDE_OVERLAY); mainView.getSettings().setBuiltInZoomControls(true); mainView.getSettings().setSupportZoom(true); I have also tried setting mainView.setInitialScale(various percentages) Again, I have tried these in different orders, including some, not including others. Currently, if I use the above code and setInitialScale(65), it loads initially fine but then once you zoom in, you cannot zoom all the way back out. Does anyone know of the best practice to set initial scale to fit screen but fully allow zooming out and in? Why I Need It: I'm using a ViewFlipper in my Android app to load several webviews simultaneously. I have a touch sensor that allows sliding from left to right to switch between different webviews. The practical purpose of this is to show a grocery store's ads and allow the user to slide from page to page. The problem is that the API feed I'm using basically only allows me to load a URL for each page. So I have to use webviews.

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  • php mysql error beginner

    - by Marcelo
    Hi, I'm trying to print some values on the screen from a table but I having a problem, I don't know much about string, vector and array but I think that my problem is related to them. I'm getting this on the screen Fatal error: Cannot use [] for reading ... My code $sql="SELECT * FROM $tbl_name"; $result=mysql_query($sql) or trigger_error(mysql_error().$sql); while($row = mysql_fetch_array($result)){ $DATA = $row[]; } //line with probelm mysql_close(); //html part <table> <? foreach($DATA as $row): ?> <tr> <td><?=$row['id']?></td> //more stuff </tr> <? endforeach ?> </table> What I'm trying to do is print somevalues form a database. But I'm getting this error. I'm sorry for any mistake in English, and thanks in advance for any help.

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  • issue with tab bar view displaying a compound view

    - by ambertch
    I created a tab bar application, and I make the first tab a table. So I create a tableView controller, and go about setting the class identity of the view controller for the first tab to my tableView controller. This works fine, and I see the contents of the table filling up the whole screen. However, this is not what I actually want in the end goal - I would like a compound window having multiple views: - the aforementioned table - a custom view with data in it So what I do is create a nib for this content (call it contentNib), change the tab's class from the tableView controller to a generic UIViewController, and set the nib of that tab to this new contentNib. In this new contentNib I drag on a tableView and set File's Owner to the TableViewController. I then link the dataSource and delegate to file's owner (which is TableViewController). Surprisingly this does not work and I receive the error: **Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[UIViewController tableView:numberOfRowsInSection:]: unrecognized selector sent to instance 0x3b0f910'** This is bewildering to me since the file's owner is the TableViewController, which has been assigned to be both the dataSource and delegate. Does someone have either insight into my confusions, or a link to an example of how to have a compound view include a tableView? *update* I see this in the Apple TableView programming guide: "Note: You should use a UIViewController subclass rather than a subclass of UITableViewController to manage a table view if the view to be managed is composed of multiple subviews, one of which is a table view. The default behavior of the UITableViewController class is to make the table view fill the screen between the navigation bar and the tab bar (if either are present)." <----- I don't really get what this is telling me to do though... if someone can explain or point me to an example I'd be much appreciated!

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  • Changing style sheets depending on useragent

    - by John Vasiliou
    <script language="Javascript"> var deviceIphone = "iPhone"; var deviceIpod = "iPod"; //Initialize our user agent string to lower case. var uagent = navigator.userAgent.toLowerCase(); //************************** // Detects if the current device is an iPhone. function DetectiPhone() { if (uagent.search(deviceIphone) > -1) {document.write('<link rel="stylesheet" type="text/css" href="ui/mobile/css/site.css">'); } etc... Above is the start of my code. I am trying to change the CSS file depending on what platform the user is using. I currently use media="screen ... " but it doesn't work with the amount of platforms I'm trying to use. I need something a lot more detailed/complex that is why I'm turning to useragents. Any ideas why the css file doesn't change on my iPhone using the above code? Better yet, any ideas on another way to change style sheets depending on the users platform/screen resolution?

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  • How to convert a string to variable name

    - by p1xelarchitect
    I'm loading several external JSON files and want to check if they have been successfully cached before the the next screen is displayed. My strategy is to check the name of the array to see if it an object. My code works perfectly when I check only a single array and hard code the array name into my function. My question is: how can i make this dynamic? not dynamic: (this works) $("document").ready(){ checkJSON("nav_items"); } function checkJSON(){ if(typeof nav_items == "object"){ // success... } } dynamic: (this doesn't work) $("document").ready(){ checkJSON("nav_items"); checkJSON("foo_items"); checkJSON("bar_items"); } function checkJSON(item){ if(typeof item == "object"){ // success... } } here is the a larger context of my code: var loadAttempts = 0; var reloadTimer = false; $("document").ready(){ checkJSON("nav_items"); } function checkJSON(item){ loadAttempts++; //if nav_items exists if(typeof nav_items == "object"){ //if a timer is running, kill it if(reloadTimer != false){ clearInterval(reloadTimer); reloadTimer = false; } console.log("found!!"); console.log(nav_items[1]); loadAttempts = 0; //reset // load next screen.... } //if nav_items does not yet exist, try 5 times, then give up! else { //set a timer if(reloadTimer == false){ reloadTimer = setInterval(function(){checkJSON(nav_items)},300); console.log(item + " not found. Attempts: " + loadAttempts ); } else { if(loadAttempts <= 5){ console.log(item + " not found. Attempts: " + loadAttempts ); } else { clearInterval(reloadTimer); reloadTimer = false; console.log("Giving up on " + item + "!!"); } } } }

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  • how do i call methods from another class in android?

    - by Phani Gargey
    I have two classes in question. Both extend Activity. Class A public void displayinfo() { setContentView(R.layout.dynamicinfo); //Add some buttons dynamically here //do some processing // move on to Class B } In Class B: I want to go back to Class A state in UI if BACK button is pressed. Class B //Register a listener for this button Backbutton.setOnClickListener(new OnClickListener() { public void onClick(View arg0) { Log.i("setOnClickListener", "Pressed Back Button "); Toast.makeText(mycontext, "Pressed Back Button", Toast.LENGTH_SHORT).show(); //HERE I want to go back class's function in UI as well as restoring the sttae for that screen. } how do I do that? I looked around some questions. they did not answer clearly what I am looking for.hence the posting. thanks.I think I was adding my own Back button on the Layout I created in the Class B's UI Screen --not using the regular "Back" button on the key board. May be that was the problem.

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  • I can not navigate to the next page in windows phone 7

    - by Vijay
    I am trying to navigate form one page to another page depends upon the login. If already user logged in, Welcome page should open. Else Log in Page should open. I am trying like this. The Splash Page is the start up page. This is a Splash Screen Xaml.cs: namespace NewExample.Views { public partial class SplashPage : PhoneApplicationPage { public SplashPage() { InitializeComponent(); this.DataContext = new SplashPageViewModel(); } } } This is Splash Screen View Model: Here I am check the user already logged in or not. namespace NewExample.ViewModel { public class SplashPageViewModel { public static bool isLogin = false; public SplashPageViewModel() { var rootFrame = (App.Current as App).RootFrame; if (isLogin) rootFrame.Navigate(new Uri("/Views/WelcomePage.xaml", UriKind.Relative)); else rootFrame.Navigate(new Uri("/Views/LoginPage.xaml", UriKind.Relative)); } } } But it is not working. The Splash Page only showing. This is not navigating to another page. Please help me to resolve this problem.

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  • initialize jquery slider with hidden input value from database.

    - by ludwigs3rd
    I'm using a slider as user input for a screen. Basically it's a bulk update screen where there is a table with multiple rows, thus multiple sliders. I created it so that the hidden value is what gets posted in the form. <td> <input class="percentageProvidedHidden" type="hidden" name='<%= "Values[" + i + "].Percentage" %>' value='<%=item.Percentage %>' /> <div class="percentageProvidedSlider"></div> </td> I have the update working just fine (move slider changes hidden input value, submit, values are updated in db), however, I can't get the damn thing to initialize with the value of the hidden input (note the "value: " parameter below). In this case I think $(this) isn't actually $('percentageProvidedSlider') but the page itself. Can someone help me get the slider value to initialize with the hidden input field? I'm using ASP .Net MVC 2 so if there are any methods I should try with that I welcome them as well. $('.percentageProvidedSlider').slider( { min: 0, max: 100, step: 25, value: $(this).parents('tr').find('input.percentageProvidedHidden').val(), slide: function(e, ui) { var mypos = ui.value; $(this).find('.ui-slider-handle').text(ui.value); }, change: function(event, ui) { var myVal = $(this).slider("option", "value"); $(this).parents('tr').find('input.percentageProvidedHidden').val(myVal); var myDropDown = $(this).parents('tr').find('select.verified'); } });

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