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  • Deceptive MySQL Query

    - by jerebear
    So I don't consider myself a novice at MySQL but this one has me stumped: I have a message board and I want to pull a list of all the most recent posts grouped by the Thread ID. Here's the table: MB_Posts -ID -Thread_ID -Created_On (timestamp) -Creator_User (user_id) -Subject -Contents -Edited (timestamp) -Reported I've tried many different things to keep it simple but I would like help from the community on this one. Just to kick this out there...this one does not work as expected: SELECT * FROM MB_Posts GROUP BY Thread_ID ORDER BY ID DESC

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  • Datatype Conversion

    - by user87
    I am trying to execute the following Query select distinct pincode as Pincode,CAST(Date_val as DATE) as Date, SUM(cast(megh_38 as int)) as 'Postage Realized in Cash', SUM(cast(megh_39 as int)) as 'MO Commission', from dbo.arrow_dtp_upg group by pincode,Date_Val but I am getting an error "Conversion failed when converting the nvarchar value '82.25' to data type int." Am I using a wrong data type?

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  • dotted stroke in <canvas>

    - by Sam
    I guess it is not possible to set stroke property such as CSS which is quite easy. With CSS we have dashed, dotted, solid but on canvas when drawing lines/or strokes this doesn't seem to be an option. How have you implemented this? I've seen some examples but they are really long for such a silly function. For example: http://groups.google.com/group/javascript-information-visualization-toolkit/browse_thread/thread/22000c0d0a1c54f9?pli=1

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  • How do I design this link table?

    - by Soo
    Ok SO, I have a user table and want to define groups of users together. The best solution I have for this is to create three database tables as follows: UserTable user_id user_name UserGroupLink group_id member_id GroupInfo group_id group_name This method keeps the member and group information separate. This is just my way of thinking. Is there a better way to do this? Also, what is a good naming convention for tables that link two other tables?

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  • Why is distributed source control considered harder?

    - by Will Robertson
    It seems rather common (around here, at least) for people to recommend SVN to newcomers to source control because it's "easier" than one of the distributed options. As a very casual user of SVN before switching to Git for many of my projects, I found this to be not the case at all. It is conceptually easier to set up a DCVS repository with git init (or whichever), without the problem of having to set up an external repository in the case of SVN. And the base functionality between SVN, Git, Mercurial, Bazaar all use essentially identical commands to commit, view diffs, and so on. Which is all a newcomer is really going to be doing. The small difference in the way Git requires changes to be explicitly added before they're committed, as opposed to SVN's "commit everything" policy, is conceptually simple and, unless I'm mistaken, not even an issue when using Mercurial or Bazaar. So why is SVN considered easier? I would argue that this is simply not true.

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  • MySQL Sub-query.. Doesn't provide proper information after 3 entries into table.

    - by Chris Keefer
    After I get 3 rows in my forum_threads table this no longer does it's job; to organize a list of active forum threads and put the most recently responded-to thread at the top of the list, followed by second most recent posted-to thread, followed by third, fourth, etc. Like I said, the query works wonders up until there is a fourth row added to forum_threads. SELECT forum_threads.*, forum_posts.thread_id FROM forum_threads INNER JOIN (SELECT MAX(id) AS id, thread_id as thread_id FROM forum_posts group by thread_id order by id DESC) forum_posts ON forum_threads.id = forum_posts.thread_id

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  • MySQL SUM Query daily values of a week problem

    - by davykiash
    Am trying to return the sum of each day of a week in mysql but it returns nothing despite having values for the 3rd Week of March 2010 SELECT SUM(expense_details_amount) AS total FROM expense_details WHERE YEAR(expense_details_date) = '2010' AND MONTH(expense_details_date) = '03' AND WEEK(expense_details_date) = '3' GROUP BY DAY(expense_details_date) How do I go about this?

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  • CSS Footer Not on same Line

    - by streetparade
    Im trying to write a footer like this one Did i said that im very bad at Css? My css looks like this #footer-navi { margin-bottom:1.5em; padding-bottom:1.5em; } clearfix { display:block; } #footer-group { margin:0 auto; } How can i implement somethin like the footer above? Thanks very much.

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  • How to get unique values when using a UNION mysql query

    - by Roland
    I have 2 sql queries that return results, both contain a contract number, now I want to get the unique values of contract numbers HEre's the query (SELECT contractno, dsignoff FROM campaigns WHERE clientid = 20010490 AND contractno != '' GROUP BY contractno,dsignoff) UNION (SELECT id AS contractno,signoffdate AS dsignoff FROM contract_details WHERE clientid = 20010490) So for example, if the first query before the union returns two results with contract no 10, and the sql query after the union also returns 10, then we have 3 rows in total, however because contractno of all three rows is 10, I need to have only one row returned, Is this possible?

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  • Security review of an authenticated Diffie Hellman variant

    - by mtraut
    EDIT I'm still hoping for some advice on this, i tried to clarify my intentions... When i came upon device pairing in my mobile communication framework i studied a lot of papers on this topic and and also got some input from previous questions here. But, i didn't find a ready to implement protocol solution - so i invented a derivate and as i'm no crypto geek i'm not sure about the security caveats of the final solution: The main questions are Is SHA256 sufficient as a commit function? Is the addition of the shared secret as an authentication info in the commit string safe? What is the overall security of the 1024 bit group DH I assume at most 2^-24 bit probability of succesful MITM attack (because of 24 bit challenge). Is this plausible? What may be the most promising attack (besides ripping the device out off my numb, cold hands) This is the algorithm sketch For first time pairing, a solution proposed in "Key agreement in peer-to-peer wireless networks" (DH-SC) is implemented. I based it on a commitment derived from: A fix "UUID" for the communicating entity/role (128 bit, sent at protocol start, before commitment) The public DH key (192 bit private key, based on the 1024 bit Oakley group) A 24 bit random challenge Commit is computed using SHA256 c = sha256( UUID || DH pub || Chall) Both parties exchange this commitment, open and transfer the plain content of the above values. The 24 bit random is displayed to the user for manual authentication DH session key (128 bytes, see above) is computed When the user opts for persistent pairing, the session key is stored with the remote UUID as a shared secret Next time devices connect, commit is computed by additionally hashing the previous DH session key before the random challenge. For sure it is not transfered when opening. c = sha256( UUID || DH pub || DH sess || Chall) Now the user is not bothered authenticating when the local party can derive the same commitment using his own, stored previous DH session key. After succesful connection the new DH session key becomes the new shared secret. As this does not exactly fit the protocols i found so far (and as such their security proofs), i'd be very interested to get an opinion from some more crypto enabled guys here. BTW. i did read about the "EKE" protocol, but i'm not sure what the extra security level is.

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  • Handling inheritance with overriding efficiently

    - by Fyodor Soikin
    I have the following two data structures. First, a list of properties applied to object triples: Object1 Object2 Object3 Property Value O1 O2 O3 P1 "abc" O1 O2 O3 P2 "xyz" O1 O3 O4 P1 "123" O2 O4 O5 P1 "098" Second, an inheritance tree: O1 O2 O4 O3 O5 Or viewed as a relation: Object Parent O2 O1 O4 O2 O3 O1 O5 O3 O1 null The semantics of this being that O2 inherits properties from O1; O4 - from O2 and O1; O3 - from O1; and O5 - from O3 and O1, in that order of precedence. NOTE 1: I have an efficient way to select all children or all parents of a given object. This is currently implemented with left and right indexes, but hierarchyid could also work. This does not seem important right now. NOTE 2: I have tiggers in place that make sure that the "Object" column always contains all possible objects, even when they do not really have to be there (i.e. have no parent or children defined). This makes it possible to use inner joins rather than severely less effiecient outer joins. The objective is: Given a pair of (Property, Value), return all object triples that have that property with that value either defined explicitly or inherited from a parent. NOTE 1: An object triple (X,Y,Z) is considered a "parent" of triple (A,B,C) when it is true that either X = A or X is a parent of A, and the same is true for (Y,B) and (Z,C). NOTE 2: A property defined on a closer parent "overrides" the same property defined on a more distant parent. NOTE 3: When (A,B,C) has two parents - (X1,Y1,Z1) and (X2,Y2,Z2), then (X1,Y1,Z1) is considered a "closer" parent when: (a) X2 is a parent of X1, or (b) X2 = X1 and Y2 is a parent of Y1, or (c) X2 = X1 and Y2 = Y1 and Z2 is a parent of Z1 In other words, the "closeness" in ancestry for triples is defined based on the first components of the triples first, then on the second components, then on the third components. This rule establishes an unambigous partial order for triples in terms of ancestry. For example, given the pair of (P1, "abc"), the result set of triples will be: O1, O2, O3 -- Defined explicitly O1, O2, O5 -- Because O5 inherits from O3 O1, O4, O3 -- Because O4 inherits from O2 O1, O4, O5 -- Because O4 inherits from O2 and O5 inherits from O3 O2, O2, O3 -- Because O2 inherits from O1 O2, O2, O5 -- Because O2 inherits from O1 and O5 inherits from O3 O2, O4, O3 -- Because O2 inherits from O1 and O4 inherits from O2 O3, O2, O3 -- Because O3 inherits from O1 O3, O2, O5 -- Because O3 inherits from O1 and O5 inherits from O3 O3, O4, O3 -- Because O3 inherits from O1 and O4 inherits from O2 O3, O4, O5 -- Because O3 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 O4, O2, O3 -- Because O4 inherits from O1 O4, O2, O5 -- Because O4 inherits from O1 and O5 inherits from O3 O4, O4, O3 -- Because O4 inherits from O1 and O4 inherits from O2 O5, O2, O3 -- Because O5 inherits from O1 O5, O2, O5 -- Because O5 inherits from O1 and O5 inherits from O3 O5, O4, O3 -- Because O5 inherits from O1 and O4 inherits from O2 O5, O4, O5 -- Because O5 inherits from O1 and O4 inherits from O2 and O5 inherits from O3 Note that the triple (O2, O4, O5) is absent from this list. This is because property P1 is defined explicitly for the triple (O2, O4, O5) and this prevents that triple from inheriting that property from (O1, O2, O3). Also note that the triple (O4, O4, O5) is also absent. This is because that triple inherits its value of P1="098" from (O2, O4, O5), because it is a closer parent than (O1, O2, O3). The straightforward way to do it is the following. First, for every triple that a property is defined on, select all possible child triples: select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value from TriplesAndProperties tp -- Select corresponding objects of the triple inner join Objects as Objects1 on Objects1.Id = tp.O1 inner join Objects as Objects2 on Objects2.Id = tp.O2 inner join Objects as Objects3 on Objects3.Id = tp.O3 -- Then add all possible children of all those objects inner join Objects as Children1 on Objects1.Id [isparentof] Children1.Id inner join Objects as Children2 on Objects2.Id [isparentof] Children2.Id inner join Objects as Children3 on Objects3.Id [isparentof] Children3.Id But this is not the whole story: if some triple inherits the same property from several parents, this query will yield conflicting results. Therefore, second step is to select just one of those conflicting results: select * from ( select Children1.Id as O1, Children2.Id as O2, Children3.Id as O3, tp.Property, tp.Value, row_number() over( partition by Children1.Id, Children2.Id, Children3.Id, tp.Property order by Objects1.[depthInTheTree] descending, Objects2.[depthInTheTree] descending, Objects3.[depthInTheTree] descending ) as InheritancePriority from ... (see above) ) where InheritancePriority = 1 The window function row_number() over( ... ) does the following: for every unique combination of objects triple and property, it sorts all values by the ancestral distance from the triple to the parents that the value is inherited from, and then I only select the very first of the resulting list of values. A similar effect can be achieved with a GROUP BY and ORDER BY statements, but I just find the window function semantically cleaner (the execution plans they yield are identical). The point is, I need to select the closest of contributing ancestors, and for that I need to group and then sort within the group. And finally, now I can simply filter the result set by Property and Value. This scheme works. Very reliably and predictably. It has proven to be very powerful for the business task it implements. The only trouble is, it is awfuly slow. One might point out the join of seven tables might be slowing things down, but that is actually not the bottleneck. According to the actual execution plan I'm getting from the SQL Management Studio (as well as SQL Profiler), the bottleneck is the sorting. The problem is, in order to satisfy my window function, the server has to sort by Children1.Id, Children2.Id, Children3.Id, tp.Property, Parents1.[depthInTheTree] descending, Parents2.[depthInTheTree] descending, Parents3.[depthInTheTree] descending, and there can be no indexes it can use, because the values come from a cross join of several tables. EDIT: Per Michael Buen's suggestion (thank you, Michael), I have posted the whole puzzle to sqlfiddle here. One can see in the execution plan that the Sort operation accounts for 32% of the whole query, and that is going to grow with the number of total rows, because all the other operations use indexes. Usually in such cases I would use an indexed view, but not in this case, because indexed views cannot contain self-joins, of which there are six. The only way that I can think of so far is to create six copies of the Objects table and then use them for the joins, thus enabling an indexed view. Did the time come that I shall be reduced to that kind of hacks? The despair sets in.

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  • Change password in Task Scheduler in script

    - by titanium
    I'm changing password every month for all scheduled tasks I created in Task Scheduler. This is because our security policy expires our password every month. Due to increasing number of scheduled tasks I'm creating, it eats up a lot of time in just changing password within Task Scheduler. My question is: Is there a way in script to change password in one run specifying the tasks, DOMAIN\username, and password? I know there's a security risk in putting the password in script. The password in script will be removed after the running it.

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  • Is it a Good Practice to Add two Conditions when using a JOIN keyword?

    - by Raúl Roa
    I'd like to know if having to conditionals when using a JOIN keyword is a good practice. I'm trying to filter this resultset by date but I'm unable to get all the branches listed even if there's no expense or income for a date using a WHERE clause. Is there a better way of doing this, if so how? SELECT Branches.Name ,SUM(Expenses.Amount) AS Expenses ,SUM(Incomes.Amount) AS Incomes FROM Branches LEFT JOIN Expenses ON Branches.Id = Expenses.BranchId AND Expenses.Date = '3/11/2010' LEFT JOIN Incomes ON Branches.Id = Incomes.BranchId AND Incomes.Date = '3/11/2010' GROUP BY Branches.Name

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  • SQL Error with Order By in Subquery

    - by cagin
    Hi all. i m working sql server 2005. My query is: SELECT ( SELECT COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4 GROUP BY refKlinik_id ORDER BY refKlinik_id) as dorduncuay And the error: The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP or FOR XML is also specified. How can i use order by in a sub query?

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  • Error using iif in ms access query

    - by naveen
    I am trying to fire this query in MS Access SELECT file_number, IIF(invoice_type='Spent on Coding',SUM(CINT(invoice_amount)), 0) as CodingExpense FROM invoice GROUP BY file_number I am getting this error Error in list of function arguments: '=' not recognized. Unable to parse query text. I tried replacing IIF with SWITCH to no avail. What's wrong with my query and how to correct this?

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  • Optimize "not in" query

    - by Vasu
    Please help optimize this query: SELECT ts.SiteId, COUNT(ts.SiteId) AS Count FROM ts WHERE ts.SiteId not in (SELECT ts.SiteId FROM ts WHERE ts.uniqueid = 'xxx') GROUP BY ts.SiteId ORDER BY Count DESC

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  • Table clusters in SQLServer

    - by Bruno Martinez
    In Oracle, a table cluster is a group of tables that share common columns and store related data in the same blocks. When tables are clustered, a single data block can contain rows from multiple tables. For example, a block can store rows from both the employees and departments tables rather than from only a single table: http://download.oracle.com/docs/cd/E11882_01/server.112/e10713/tablecls.htm#i25478 Can this be done in SQLServer?

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  • Jquery hover function doesn't work for a table...

    - by chandru_cp
    I dynamically added rows to a table but it doesn't seem to take hover effects given in jquery... Here is my code, <table id="chkbox" cellpadding="0" cellspacing="2" width="100%" class="table_Style_Border"> <tr> <td style="width:150px" class="grid_header" align="center">RackName</td> <td style="width:150px" class="grid_header" align="center">LibraryName</td> <td style="width:200px" class="grid_header" align="center">LibrarianName</td> <td style="width:200px" class="grid_header" align="center">Location</td> <td style="width:1%" class="grid_header"></td> </tr> <? if(isset($comment)) { echo '<tr><td class=table_label colspan=5>'.$comment.'</td></tr>'; } ?> <?php foreach($rackData as $key => $row) { ?> <?php printf('<tr class="%s">', ($key % 2) ? 'rowcolor' : 'alternaterowcolor'); ?> <td align="left" class="table_label"> <?=$row['rack_name']?> </td> <td align="left" class="table_label"> <?=$row['library_name']?> </td> <td align="center" class="table_label"> <?=$row['librarian']?> </td> <td align="center" class="table_label"> <?=$row['location']?> </td> <td align="center"> <input type="checkbox" name="group" id="group" value="<?=$row['rack_id']?>" onclick="display(this);" > </td> </tr> <? } ?> </table><div align="right" class="pagination"> <?php /*?><?php echo $links;?><?php */?></div> <script type="text/javascript"> $("#chkbox").hover(function() { $(this).addClass("resultshover"); }, function() { $(this).removeClass("resultshover"); }); </script>

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  • SMS/Text message sending via PHP

    - by Onion
    I'm interested in knowing if it would be at all feasible to be able to send text messages via PHP. The main purpose of which would be to send a single message to a group of people - 10+ - with updates regarding news and such. Preferably the solution should be free, though it is not a necessity in any way. Thanks to all in advance.

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  • problem in mysql query with join and limit the time

    - by moustafa
    i have this SELECT COUNT(1) cnt, a.auther_id FROM `posts` a LEFT JOIN users u ON a.auther_id = u.id GROUP BY a.auther_id ORDER BY cnt DESC LIMIT 20 its work fine bu now i want select from posts which added from 1 day tried to use WHERE from_unixtime(post_time) >= SUBDATE(NOW(),1) but its didnot worked any one have idea

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