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  • Styling a comment box to appear below dynamically-generated comments

    - by John
    Hello, For the code below, how could I make the form always appear 30 pixels below the bottom of the HTML table styled with "commentecho"? Thanks in advance, John $sqlStr = "SELECT comment.comment, comment.datecommented, login.username FROM comment LEFT JOIN login ON comment.loginid=login.loginid WHERE submissionid=$submissionid ORDER BY comment.datecommented DESC LIMIT 100"; $result = mysql_query($sqlStr); $arr = array(); echo "<table class=\"commentecho\">"; while ($row = mysql_fetch_array($result)) { echo '<tr>'; echo '<td class="commentname1">'.$row["comment"].'</td>'; echo '</tr>'; echo '<tr>'; echo '<td class="commentname2"><a href="http://www...com/sandbox/members/index.php?profile='.$row["username"].'">'.$row["username"].'</a>'.date('l, F j, Y &\nb\sp &\nb\sp g:i a &\nb\sp &\nb\sp \N\E\W &\nb\sp \Y\O\R\K &\nb\sp \T\I\M\E', strtotime($row["datecommented"])).'</td>'; echo '</tr>'; } echo "</table>"; echo '<form action="http://www...com/sandbox/comments/comments2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <input type="hidden" value="'.$submissionid.'" name="submissionid"> <input type="hidden" value="'.$submission.'" name="submission"> <label class="addacomment" for="title">Add a comment:</label> <input class="commentsubfield" name="comment" type="comment" id="comment" maxlength="1000"> <div class="commentsubbutton"><input name="submit" type="submit" value="Submit"></div> </form> ';

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  • Permission denied (maybe missing INTERNET permission) when calling web service

    - by Maxim
    I'm trying to use .net SOAP web service with ksoap2 lib. Example from http://www.vimeo.com/9633556 shows how to do it correct. Below the code from that example. everything shoud work ok, but when I try to do a call inself (httpTransport.call) I get "Permission denied (maybe missing INTERNET permission)" exception. Moreover, I don't see in the Application info window among permissions the internet permission alert. Tried this on emulator and Google phone. Will be very appreciated if somebody could help with it. Thanks. public void CelsiusToFahrenheit() { String SOAP_ACTION = "http://tempuri.org/CelsiusToFahrenheit"; String METHOD_NAME = "CelsiusToFahrenheit"; String NAMESPACE = "http://tempuri.org/"; String URL = "http://www.w3schools.com/webservices/tempconvert.asmx"; SoapObject Request = new SoapObject(NAMESPACE, METHOD_NAME); Request.addProperty("Celsius", "32"); SoapSerializationEnvelope soapEnvelope = new SoapSerializationEnvelope(SoapEnvelope.VER11); soapEnvelope.dotNet = true; soapEnvelope.setOutputSoapObject(Request); AndroidHttpTransport httpTransport = new AndroidHttpTransport(URL); try { httpTransport.call(SOAP_ACTION, soapEnvelope); SoapPrimitive resultString = (SoapPrimitive)soapEnvelope.getResponse(); res = resultString.toString(); } catch (Exception e) { e.printStackTrace(); } } AndroidManifest.xml <?xml version="1.0" encoding="utf-8"?> <manifest> <application> <intent-filter> <action android:name="android.intent.action.MAIN" /> <category android:name="android.intent.category.LAUNCHER" /> </intent-filter> </activity> </application> <user-permission android:name="android.permission.INTERNET"></user-permission> <uses-sdk android:minSdkVersion="4" />

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  • Posting XML form data to a RESTful Server with Javascript or PHP

    - by pjs-worker
    Hi folks, I've been given the task of posting to a RESTful server. I'm new to the official "REST" but I've played with the concept before. However, this time I have an XML Payload example file that I am supposed to post. I'm struggling to figure out how the two relate. Can you help? Right now I can post to a specific site, say www.pcpost.com/schema/Application I can generate the URL for the inital, ie: postApplication?userid=4&... Being relatively new to web programming, I find that don't know how to take the following and interface it with the server. I'm at least familiar with Javascript and PHP. If this is impossible with those two types, I can learn whatever would be best. Thanks for your help on this. C <?xml version=\"1.0\" ?> <Application xmlns="http://www.pcpost.com/schema/Application" SchemaVersion="1.0" ProgramId="8" ApplicationDate="2009-08-29"> <Vendors> <Vendor Role="Applicant" Company="Test Company" Contact="Smith, John"/> <Vendor Role="Seller" Company="Test Company" Contact="Doe, Jane"/> <Vendor Role="Installer" Company="Test Company" Contact="Funk, Carl"/> </Vendors> <Participants> <Participant TaxStatus="Individual" Sector="Commercial"> <Roles> <Role>Host Customer</Role> </Roles> </Participants> </Application>

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  • UnicodeDecodeError on attempt to save file through django default filebased backend

    - by Ivan Kuznetsov
    When i attempt to add a file with russian symbols in name to the model instance through default instance.file_field.save method, i get an UnicodeDecodeError (ascii decoding error, not in range (128) from the storage backend (stacktrace ended on os.exist). If i write this file through default python file open/write all goes right. All filenames in utf-8. I get this error only on testing Gentoo, on my Ubuntu workstation all works fine. class Article(models.Model): file = models.FileField(null=True, blank=True, max_length = 300, upload_to='articles_files/%Y/%m/%d/') Traceback: File "/usr/lib/python2.6/site-packages/django/core/handlers/base.py" in get_response 100. response = callback(request, *callback_args, **callback_kwargs) File "/usr/lib/python2.6/site-packages/django/contrib/auth/decorators.py" in _wrapped_view 24. return view_func(request, *args, **kwargs) File "/var/www/localhost/help/wiki/views.py" in edit_article 338. new_article.file.save(fp, fi, save=True) File "/usr/lib/python2.6/site-packages/django/db/models/fields/files.py" in save 92. self.name = self.storage.save(name, content) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in save 47. name = self.get_available_name(name) File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in get_available_name 73. while self.exists(name): File "/usr/lib/python2.6/site-packages/django/core/files/storage.py" in exists 196. return os.path.exists(self.path(name)) File "/usr/lib/python2.6/genericpath.py" in exists 18. st = os.stat(path) Exception Type: UnicodeEncodeError at /edit/ Exception Value: ('ascii', u'/var/www/localhost/help/i/articles_files/2010/03/17/\u041f\u0440\u0438\u0432\u0435\u0442', 52, 58, 'ordinal not in range(128)')

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  • Frameset isn't working in IE

    - by Cameroon
    First of all, why use a frame set in the first place you ask? answer: Because my boss told me. That been said, I have 2 files. Index.html and Head.html. Contents of index.html: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Frameset//EN" "http://www.w3.org/TR/1999/REC-html401-19991224/frameset.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1" /> <title>Site Title</title> </head> <frameset rows="122,*" FRAMEBORDER=NO FRAMESPACING=2 BORDER=0> <frame name="t" src="head.html" scrolling="no" marginheight="0" marginwidth="0"> <frame name="b" src="http://www.website.com"> </frameset> <noframes> <p>You have frames turned off on your browser, please turn it on and reload this page.</p> </noframes> </html> Contents of head.html: <div style="border-bottom:2px solid #000;height:120px"> <center>This is the frame head.</center> </div> The code works fine in all browsers except Internet Explorer 7 and 8 (I don't care about 6). Is there anything I am doing wrong, and if not then can the same effect be achieved without frames and if so how?

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  • Kohana 3, themes outside application.

    - by Marek
    Hi all I read http://forum.kohanaframework.org/comments.php?DiscussionID=5744&page=1#Item_0 and I want to use similar solution, but with db. In my site controller after(): $theme = $page->get_theme_name(); //Orange Kohana::set_module_path('themes', Kohana::get_module_path('themes').'/'.$theme); $this->template = View::factory('layout') I checked with firebug: fire::log(Kohana::get_module_path('themes')); // D:\tools\xampp\htdocs\kohana\themes/Orange I am sure that path exists. I have directly in 'Orange' folder 'views' folder with layout.php file. But I am getting: The requested view layout could not be found Extended Kohana_Core is just: public static function get_module_path($module_key) { return self::$_modules[$module_key]; } public static function set_module_path($module_key, $path) { self::$_modules[$module_key] = $path; } Could anybody help me with solving that issue? Maybe it is a .htaccess problem: # Turn on URL rewriting RewriteEngine On # Put your installation directory here: # If your URL is www.example.com/kohana/, use /kohana/ # If your URL is www.example.com/, use / RewriteBase /kohana/ # Protect application and system files from being viewed RewriteCond $1 ^(application|system|modules) # Rewrite to index.php/access_denied/URL RewriteRule ^(.*)$ / [PT,L] RewriteRule ^(media) - [PT,L] RewriteRule ^(themes) - [PT,L] # Allow these directories and files to be displayed directly: # - index.php (DO NOT FORGET THIS!) # - robots.txt # - favicon.ico # - Any file inside of the images/, js/, or css/ directories RewriteCond $1 ^(index\.php|robots\.txt|favicon\.ico|static) # No rewriting RewriteRule ^(.*)$ - [PT,L] # Rewrite all other URLs to index.php/URL RewriteRule ^(.*)$ index.php/$1 [PT,L] Could somebody help? What I am doing wrong? Regards

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  • Why is my logic not working correctly for SPOJ TOPOSORT?

    - by Kavish Dwivedi
    The given problem is http://www.spoj.com/problems/TOPOSORT/ The output format is particularly important as : Print "Sandro fails." if Sandro cannot complete all his duties on the list. If there is a solution print the correct ordering, the jobs to be done separated by a whitespace. If there are multiple solutions print the one, whose first number is smallest, if there are still multiple solutions, print the one whose second number is smallest, and so on. What I am doing is simply doing dfs by reversing the edges i.e if job A finishes before job B, there is a directed edge from B to A . I am maintaining the order by sorting the adjacency list I created and storing the nodes which don't have any constraints separately so as to print them later in correct order . There are two flag arrays used , one for marking discovered node and one for marking the node whose all neighbors have been explored. Now my solution is http://www.ideone.com/QCUmKY (the important function is the visit funtion ) and its giving WA after running correct for 10 cases so its really hard to figure out where am I doing it wrong since it runs for all of the test cases which I have done by hand.

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  • Javascript break breaks Firefox

    - by Maxime
    Hi, I'm working on this Javascript script that works nice in Safari and Chome but for some reason it doesn't work at all in Firefox. I identified the line that caused this: it's "break;". How do I fix this? playListConfig( index ); $("#jquery_jplayer").jPlayer("play"); song_num = myPlayList[index].song_id; if(!o[song_num]) { o[song_num] = 1;} $.get("http://www.ratemysong.net/includes/getnote.php?song_id="+song_num+"&s"+Math.random(), function(data){ if(data == "") { $('#rating ul li a').each(function() { $(this).attr('href', '#'); $(this).css("color","#FFF"); }); $('#rating ul li a').click(function(e) { ++o[song_num]; if(o[song_num]==2) { $(this).css({color:'#59B'}); var url = "http://www.ratemysong.net/boxes/voted.php?note="; url = url + $(this).attr('id'); $.get(url, function(data){ $('#basic-modal-content').html(data); $("#basic-modal-content").modal(); }); rating[song_num] = $(this).attr('id'); } else { $("#already_voted").modal(); } break; }); } else { $('#rating ul li a').each(function() { $(this).removeAttr('href'); $(this).css("color","#000"); var id_value = $(this).attr("id"); $(this).css("color","#FFF"); if(id_value == data) { $(this).css("color","#59B"); } }); } }); }

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  • Invalid iPhone Application Binary

    - by Kristopher Johnson
    I'm trying to upload an application to the iPhone App Store, but I get this error message from iTunes Connect: The binary you uploaded was invalid. The signature was invalid, or it was not signed with an Apple submission certificate. My guess is that it is not properly signed. I have downloaded my App Store distribution certficate, but I can't figure out how to "sign" my application with it. The SDK's documentation about code signing is not very helpful. (FWIW, I can install the app on my iPhone just fine using the development provisioning profile.) However, it is possible that I screwed things up on a more basic level. Here's what I did to try to prepare it for upload: In Xcode, select the Device|Release target Select the target and click the Info button. Change "Code Signing Identity" to "iPhone Distribution", and change "Code Signing Provisioning Profile" to my App Store distribution profile. Build Go to the directory where the built MyApp.app bundle is, control-click and choose "Compress" to create MyApp.zip Upload MyApp.zip to the App Store via iTunes Connect (which resulted in the above error message). Can anybody give me any hints? Edit: Found someone with the same problem. Unfortunately, he won't tell us how he fixed it. http://www.rhonabwy.com/wp/2008/07/18/seattlebus-diary-ongoing-update-saga/#comments http://www.rhonabwy.com/wp/2008/07/22/seattlebus-diary-update-is-pending-review/ (Note: For general information on submitting iPhone applications to the App Store, see Steps to upload an iPhone application to the AppStore.)

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  • With Apache/mod_wsgi how can I redirect to ssl and require Auth?

    - by justin
    I have a Media Temple DV server hosting dev.example.com with django mounted at /. There is a legacy directory in my httpdocs I need to continue to serve at /legacy. But for this directory I need to redirect anyone coming over http over to https, then prompt for http basic auth. In the virtual host conf, I'm pointing the root to a django application: WSGIScriptAlias / /var/django-projects/myproject/apache/django.wsgi <Directory /var/django-projects/myproject/apache> Order allow,deny Allow from all </Directory> Then I alias the legacy directory. Alias /legacy/ /var/www/vhosts/example.com/subdomains/dev/httpdocs/legacy/ <Directory /var/www/vhosts/example.com/subdomains/dev/httpdocs> Order deny,allow Allow from all RewriteEngine On RewriteCond %{SERVER_PORT} 80 RewriteRule ^(.*)$ https://dev.example.com/$1 [R,L] </Directory> This works. It isn't served by django, and the url redirects to https. However, it serves httpdocs/legacy instead of httpsdocs/legacy (where I have an .htaccess that prompts for auth.) Any idea of how I can manage this?

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  • Loading user controls programatically into a placeholder (asp.net(vb))

    - by Phil
    In my .aspx page I have; <%@ Page Language="VB" AutoEventWireup="false" CodeFile="Default.aspx.vb" Inherits="_Default" AspCompat="True" %> <%@ Register src="Modules/Content.ascx" tagname="Content" tagprefix="uc1" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <title></title> </head> <body> <form id="form1" runat="server"> <div> <asp:PlaceHolder ID="Modulecontainer" runat="server"></asp:PlaceHolder> </div> </form> </body> </html> In my aspx.vb I have; Try Dim loadmodule As Control loadmodule = Me.LoadControl("~/modules/content.ascx") Modulecontainer.Controls.Add(loadmodule) Catch ex As Exception Response.Write(ex.ToString & "<br />") End Try The result is an empty placeholder and no errors. Thanks a lot for any assistance

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  • How do I cancel the link action?

    - by Tobbe
    I though returning false would be enough to cancel the link action, but apparently it isn't. When I click the link in the code below I do get the 'click' message, which is expected. But I also end up at google.com, which is unexpected. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <html> <head> <title>Link test</title> <script> window.addEventListener('load', function () { document.getElementsByTagName('a')[0].addEventListener('click', function () { alert('click'); return false; }, false); }, false); </script> </head> <body> <a href="http://www.google.com">google</a> </body> </html> How can I make the url NOT change when clicking the link? Pure JavaScript solutions only please, no additional libraries (like jQuery). It only has to work in FireFox 3+ and Chrome.

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  • Link to RSS/Atom feed, relative, doesn't work in Firefox

    - by Adrian Smith
    I have a weird problem. I generate a HTML page, hosted let's say at http://www.x.com/stuff which contains <head> <link type="application/atom+xml" rel="alternate" href="/stuff/feed"/> .. </head> The result is: In IE7 all works well - you can click on the feed icon in the browser and the feed is displayed In Firefox, view source, click on the linked /stuff/feed and you see the source of the feed, so that works as expected In Firefox, view the page (not source), then click on the feed icon in the address bar, I get an error that it can't retrieve the URL feed://http//www.x.com/stuff/feed So the problem is, that it's appending feed:// to the front of the URL and then taking out the colon : after the http. I understand that feed: is HTTP anyway so perhaps the adding of that isn't a big problem. But anyway, the fact is, that URL Firefox generates out of my <link> tag doesn't work. I have considered making the URL absolute, but I haven't found any evidence that those URLs have to be absolute, nor can I understand why that would be the case. And for various reasons it would be inconvenient in my code to generate an absolute URL. I can do it if necessary but I would prefer to see proof (e.g. specification, or Mozilla bug report) that it's necessary before making my code messy What do you think? Does anyone know of any evidence that the URL should be absolute? Or am I doing something else wrong? It seems such a simple/obvious tag, where nothing could go wrong, but I can't get it to work.

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  • C# .net Deserialization I get an exception.

    - by starz26
    namespace N1 { public class InputEntry { //FieldName is a class tht is generated from an XSD which has complex type Name and value private FieldName[] name; public FieldName[] Name { get { return this.Name; } set { this.Name = value; } } } public class B { public void Method1() { InputEntry inputEntry = new InputEntry(); inputEntry.Name = "abc"; } private void Method2(InputEntry inputEntry) { System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(InputEntry)); System.IO.StringWriter inputStr = new System.IO.StringWriter(CultureInfo.InvariantCulture); serializer.Serialize(inputStr, inputEntry); string ipEntry = inputStr.ToString(); Method3(ipEntry); } private void Method3(string ipEntry) { System.Xml.Serialization.XmlSerializer serializer = new System.Xml.Serialization.XmlSerializer(typeof(InputEntry)); System.IO.StringReader inputStr = new System.IO.StringReader(ipEntry); InputEntry inputEntry = (InputEntry)serializer.Deserialize(inputStr); } } } I get an exception when deserialising the follwing data(when a client configues data as <FieldName>PRINTLINE00</FieldName> <FieldValue>DENIAL STATE</FieldValue> ) Exception is: Message: There is an error in XML document (6, 22). String: <?xml version="1.0" encoding="utf-16"?> <InputEntry xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"xmlns:xsd="http://www.w3.org/2001/XMLSchema"> <Fields> <Field> <FieldName>PRINTLINE00</FieldName> <FieldValue>&#x1B;DENIAL STATE 217</FieldValue> </Field> </InputEntry>

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  • cfchart ignores my scalefrom value

    - by Monte Chan
    Hi all, I have the following codes in my page. The style variable holds the custom style. <cfchart chartheight="450" chartwidth="550" gridlines="9" yaxistitle="Score" scalefrom="20" scaleto="100" style="#style#" format="png" > <cfchartseries query="variables.chart_query" type="scatter" seriescolor="##000000" itemcolumn="MyItem" valuecolumn="MyScore"/> </cfchart> Before I begin, please go to http://www.monteandjanicechan.com/chart_good.jpg. This is how I want my report to come up. On the x-axis, there will always be three items as long as at least one of them has values. If an item does not have any values (i.e. 2010), there would not be a marker in the chart. The problem occurs only when only one item has value. Please see http://www.monteandjanicechan.com/chart_bad.jpg. As you can see, 2008 and 2010 do not have any values; y-axis is now scaled from 0 to 100. I have tried setting one of the items (ex. 2008) a value of 0 or something off the chart; it would scale according to this off-the-chart value and the 2009 value. In short, I have to have at least two items with values between 20 and 100 in order for cfchart to scale from 20 to 100. My question is, how can I correct the issue so that cfchart would ALWAYS scale from 20 to 100? I am running CF9. Thanks in advance, Monte

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  • chrome frame causes postback to wrong url and a Server Error in '/' Application error

    - by Johnny S
    I have a simple asp page with no code behind defined as: <%@ Page Language="C#" AutoEventWireup="true" CodeFile="Default.aspx.cs" Inherits="_Default" %> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head runat="server"> <meta http-equiv="X-UA-Compatible" content="chrome=1" /> <title>test login</title> </head> <body> <form id="form1" runat="server"> <div> <asp:Button runat="server" CommandName="test" Text="test" /> </div> </form> </body> </html> This is being hosted on an IIS server that ships with XP (looks like 5.1). If I have machine with native IE6 running chrome frame click the TEST button, I receive: Server Error in '/' Application. The resource cannot be found. Description: HTTP 404. The resource you are looking for (or one of its dependencies) could have been removed, had its name changed, or is temporarily unavailable. Please review the following URL and make sure that it is spelled correctly. Requested URL: /Default.aspx I have tried this test on an IIS 7 host and several other IE6 machines with the same result. What I have noticed is that it is trying to postback to the wrong URL. I have checked with fiddler and have seen it will start at hostname/test/default.aspx but when I click the button it is trying to post to hostname/default.aspx Any help is greatly appreciated.

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  • Internet Explorer Warning when embedding Youtube on HTTPS site?

    - by pellepim
    Our application is run over HTTPS which rarely presents any problems for us. When it comes to youtube however, the fact that they do not present any content over SSL connections is giving us some head ache when trying to embed clips. Mostly because of Internet Explorers famous little warning message: "Do you want to view only the webpage content that was delivered securely? This page contains content that will not be delivered using a secure HTTPS ... etc" I've tried to solve this in several ways. The most promising one was to use the ProxyPass functionality in Apache to map to YouTube. Like this: ProxyPass: /youtube/ http://www.youtube.com ProxyPassReverse: /youtube/ http://www.youtube.com This gets rid of the annoying warning. However, the youtube SWF fails to start streaming The SWF i manage to load into the browser simply states : "An error occurred, please try again later". Potential solutions are perhaps: Download youtube FLV:s and serve them out of own domain (gah) Use custom FLV-player and stream only FLV:s from youtube over a https proxy? Update 10 March: I've tried to use Googles Youtube API for ActionScript to load a player. It looked promising at first and I was able to load a player through my https:// proxy. However, the SWF that is loaded contains loads of explicit calls to different non-ssl urls to create authentication links for the FLV-stream and for loading different crossdomain policies. It really seems like we're not supposed to access flv-streams directly. This makes it very hard to bypass the Internet Explorer warning, short of ripping out the FLV:s from youtube and serving them out of your own domain. There are solutions out there for downloading youtubes FLV:s. But that is not compliant with the Youtube terms of use and is really not an option for us.

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  • jQuery.load doesn't execute javascript with document.write

    - by Garfield
    I am trying to use jQuery.Load to load an ad call that has a document.write, and for some reason its not able to, or in firefox atleast, reloads the page with the entire ad. Here is the simplified version of the code. DynamicLoad.html <html> <head> <script src="http://www.prweekus.com/js/scripts.js?3729212881" type="text/javascript"></script> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>jQuery Load of Script</title> <script type="text/javascript" src="http://www.google.com/jsapi"></script> <script type="text/javascript"> google.load("jquery", "1.3.2"); </script> <script type="text/javascript"> $(document).ready(function(){ $("#myButton").click(function() { $("#myDiv").load("source.html"); }); }); </script> </head> <body> <button id="myButton">Click Me</button> <div id="myDiv"></div> <div id="slideAdUnit"></div> </body> </html> Source.html <script language="javascript" type="text/javascript"> document.write('<script language="javascript" type="text/javascript"><\/script>'); </script> test Once you click the button in FF the browser just waits for something to load. Any thoughts ? Eventually I would be passing a src element in the document.write which points to our ad server. Thanks for your help.

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  • Specify which xml file to load when link is clicked

    - by Jason
    Good morning, I would like it so when a link is clicked on the homepage it would load a particular xml file into the next page (the page is called category-list.apsx). This category list page uses the Repeater Control method to display the xml details on the page. I used the example shown here: http://www.w3schools.com/aspnet/aspnet_repeater.asp So at the moment the repeater script looks like: <script runat="server"> sub Page_Load if Not Page.IsPostBack then dim mycategories=New DataSet mycategories.ReadXml(MapPath("categories.xml")) categories.DataSource=mycategories categories.DataBind() end if end sub </script> After doing some research I did find someone with the same problem and the solution was to insert #tags as part of the link on the homepage (i.e. category-list.apsx#company1results) and then some script on the list page to pick up the correct xml file: <script type="text/javascript"> var old_onload = window.onload; // Play it safe by respecting onload handlers set by other scripts. window.onload=function() { var categories = document.location.href.substring(document.location.href.indexOf("#")+1); loadXMLDoc('XML/'+categories+'.xml'); old_onload(); } </script> This was from the following link: http://www.hotscripts.com/forums/javascript/45641-solved-specify-xml-file-load-when-click-link.html How can I get these two scripts to connect with each other? Thank you for your time

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  • Extract enumeration data from .XSD file

    - by Ram
    Hi, I am trying to read enum from a XSD file. The schema is as follows <xs:schema id="ShipReports-v1.xsd" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata" attributeFormDefault="unqualified" elementFormDefault="qualified" msdata:IsDataSet="true"> <xs:simpleType name="Type"> <xs:restriction base="xs:string"> <xs:enumeration value="Op1" /> <xs:enumeration value="Op2" /> <xs:enumeration value="Op3" /> </xs:restriction> </xs:simpleType> </xs:schema> I also tried using this but I am getting list item count as Zero. Following is the code I am using DataSet _sR = new DataSet(); _sR.ReadXmlSchema(assembly.GetManifestResourceStream("v1.xsd")); XmlDocument xDoc = new XmlDocument(); xDoc.LoadXml(_sR.GetXml()); XmlNamespaceManager xMan = new XmlNamespaceManager(xDoc.NameTable); xMan.AddNamespace("xs", "http://www.w3.org/2001/XMLSchema"); XmlNodeList xNodeList = xDoc.SelectNodes( "//xs:schema/xs:simpleType[@name='Type']/xs:enumeration", xMan); string[] enumVal = new string[xNodeList.Count]; int ctr = 0; foreach (XmlNode xNode in xNodeList) { enumVal[ctr] = xNode.Attributes["value"].Value; ctr++; }

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  • [SOLVED]: Delegate OpenID to Google (NOT Google Apps)

    - by Rio
    OK, I searched this question on SO but no good answer. After spent some time I figured out how to do it. I'm going to answer this myself as a way to share it. Not sure if this is the correct way to use SO, but here it goes: Now it is possible delegate OpenID to your Google account (not Google Apps). No, this is not using the demo OpenID provider using App Engine. This is your REAL Google account! First you need to enable your Google Profiles. Try to view your profile and edit it, there should be an option to set your Profile URL. You have two choices there: either use your Gmail account name (without the @gmail.com part) as your profile id, or a random number assigned to you. It's up to you to decide which one to use. Either way, that id is your profile id below. Now add the following HTML code to your delegating page: <link rel="openid2.provider" href="https://www.google.com/accounts/o8/ud?source=profiles" > <link rel="openid2.local_id" href="http://www.google.com/profiles/[YOUR PROFILE ID]" > And it's done. Now try login SO with your custom url!

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  • asynchronous pages

    - by lockedscope
    I have just read the multi-threading and custom threading in asp.net articles. http://www.williablog.net/williablog/post/2008/12/16/Custom-Threading-in-ASPNET.aspx http://www.williablog.net/williablog/post/2008/12/16/Multi-Threading-in-ASPNET.aspx I have couple of questions. What does he mean by returning a thread to the pool? Is that thread completely removed from memory or put in to a state that it does not scheduled to CPU(is it in sleep state or whatever)? If that thread is removed from memory how could it survive after async point? How this mechanism works? Are every objects(pages class, request,response etc.) are copied to somewhere else before they are disposed? (Or, is it just waiting in a sleep state and then its waked when async call ends?) He is saying that; "Having said that, making pages asynchronous is not really about improving performance, it is about improving scalability" then he is saying; "I'm sorry to say that it will do nothing for scalability or performance." So which one is true? or for which case(s) are they true?

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  • MySQL Connection Error in PHP

    - by user309381
    I have set the password for root and grant all privileges for root. Why does it say it is denied? ****mysql_query() [function.mysql-query]: Access denied for user 'SYSTEM'@'localhost' (using password: NO) in C:\wamp\www\photo_gallery\includes\database.php on line 56 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\wamp\www\photo_gallery\includes\database.php on line 56 The Query has problemAccess denied for user 'SYSTEM'@'localhost' (using password: NO) Code as follows: <?php include("DB_Info.php"); class MySQLDatabase { public $connection; function _construct() { $this->open_connection(); } public function open_connection() { /* $DB_SERVER = "localhost"; $DB_USER = "root"; $DB_PASS = ""; $DB_NAME = "photo_gallery";*/ $this->connection = mysql_connect($DBSERVER,$DBUSER,$DBPASS); if(!$this->connection) { die("Database Connection Failed" . mysql_error()); } else { $db_select = mysql_select_db($DBNAME,$this->connection); if(!$db_select) { die("Database Selection Failed" . mysql_error()); } } } function mysql_prep($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } // Quote if not a number if (!is_numeric($value)) { $value = "'" . mysql_real_escape_string($value) . "'"; } return $value; } public function close_connection() { if(isset($this->connection)) { mysql_close($this->connection); unset($this->connection); } } public function query($sql) { //$sql = "SELECT*FROM users where id = 1"; $result = mysql_query($sql); $this->confirm_query($result); //$found_user = mysql_fetch_assoc($result); //echo $found_user; return $found_user; } private function confirm_query($result) { if(!$result) { die("The Query has problem" . mysql_error()); } } } $database = new MySQLDatabase(); ?>

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  • Weird Issues with WPMU I Can't Figure Out

    - by HollerTrain
    I know I should post this on the WPMU forum, but no one writes me back and I'm just trying to find a larger audience hoping you have run into this issue as well. I have built a WPMU site for a client, and I am able to upload media into the Media Library and within a Post or Page perfectly. I thought my job was finished, yet the client can't upload any media at all. I'm located in Kentucky, they are located in New England (if that even matters). I had the client record their process of uploading as I thought they were simply not following my instructions for uploading, yet they are doing everything correctly. When uploading a file it goes through the process of allowing them to select a file and it says it uploads it, yet when it is finished uploading nothing is in the Media Library or in the Post. Video of the client trying to upload in Media Manager (http://www.screencast.com/users/CatherineWeber/folders/Jing/media/945d33fa-a752-45fd-9bc1-f76fc5a1814a) Video of the client trying to upload within a Post (http://www.screencast.com/users/CatherineWeber/folders/Jing/media/b5c60e25-f0b5-40c0-a820-c2fc9eb00906) Asking the client to disable Flash Uploader didn't work :( Yet, I can login to the WPMU site, access their blog's backend and can easily upload a ton of files. I am so lost at to what the issue is here. I am running version 2.8.4a, and will try to upgrade to latest release hoping this will fix things.

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  • jquery change image on mouse rollover

    - by Craig Rinde
    I have been having problems with this. I think this should be pretty simple but I cannot seem to get it to work. I want a new image to appear when rolling over my facebook button. Thanks for your help! <p align="right"> <a href="http://www.facebook.com/AerialistPress" ><img height="30px" id="facebook" class="changePad" alt="Aerialist Press Facebook Page" src="/sites/aerialist.localhost/files/images/facebook300.jpg" /></a> <a href="http://twitter.com/#!/AerialistPress" > <img height="30px" class="changePad" alt="Aerialist Press Twitter Page" src="/sites/aerialist.localhost/files/images/twitter300.jpg" /></a> <a href="http://www.pinterest.com/aerialistpress" ><img height="30px" class="changePad" alt="Aerialist Press Pinterest Page" src="/sites/aerialist.localhost/files/images/pinterest300.jpg" /></a> </p> <script> jQuery(document).ready(function(){ jQuery('#facebook').mouseover(function() { jQuery('#facebook').attr('src').replace('/sites/aerialist.localhost/files/images/facebook-roll.jpg'); }) }); </script>

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