Search Results

Search found 12223 results on 489 pages for 'password generator'.

Page 291/489 | < Previous Page | 287 288 289 290 291 292 293 294 295 296 297 298  | Next Page >

  • mysql_connect() causes page to not display (WAMP)

    - by VOIDHand
    I currently have a website running MySQL and PHP in which this is all working. I've tried installing WAMPServer to be able to work on the site on my own computer, but I have been having issues trying to get the site to work correctly. HTML and PHP files work correctly (by going to http://localhost/index.php, etc.). But some of the pages display "This Webpage is not available" (in Chrome) or "Internet Explorer cannot display this webpage", which leads me to think there is an error is the server, as when the page doesn't exist, it typically dispays "Oops! This link appears to be broken" or IE's standard 404 page. Each page in my site has an include() call to set up an instance of a class to handle all database transactions. This class opens the connection to the database in its constructor. I have found commenting out the contents of the constructor will allow the page to load, although this understandably causes errors later in the page. This is the contents of the included file: class dbAccess { private $db; function __construct() { $this->db = mysql_connect("externalURL","user","password") or die ("Connection for database not found."); mysql_select_db("dbName", $this->db) or die ("Database not selected"); } ... } As a note for what's happening here. I'm attempting to use the database on my site, rather than the local machine. The actual values of externalURL, dbName, user, and password work when I plug them into my database software and the file fine of the site, so I don't think the issue is with those values themselves, but rather some setting with Apache or Wamp. The issue persists if I try a local database as well. This is an excerpt of my Apache error log for one attempt at logging into the site: [Wed Apr 14 15:32:54 2010] [notice] Parent: child process exited with status 255 -- Restarting. [Wed Apr 14 15:32:54 2010] [notice] Apache/2.2.11 (Win32) PHP/5.3.0 configured -- resuming normal operations [Wed Apr 14 15:32:54 2010] [notice] Server built: Dec 10 2008 00:10:06 [Wed Apr 14 15:32:54 2010] [notice] Parent: Created child process 1756 [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Child process is running [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Acquired the start mutex. [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Starting 64 worker threads. [Wed Apr 14 15:32:55 2010] [notice] Child 1756: Starting thread to listen on port 80. For the first line, isLoggedIn (from the first line) is a method of the class above. Assuming that the connection works, this error should disappear. I've tried searching for solutions online, but haven't been able to find anything to help. If you need any further information to help solve this issue, feel free to ask for it. (One more note, I don't even have Skype on this computer, so I can't see it being an issue, as this conflict seems to be the default response for any Wamp issue.) [Edit: Removed entry from the error log as it was solved as an unrelated issue]

    Read the article

  • KVM error with device pass through

    - by javano
    I am running the following command booting a Debian live CD passing a host PCI device to the guest as a test and KVM errors out; kvm -m 512 -boot c -net none -hda /media/AA502592502565F3/debian.iso -device pci-assign,host=07:00.0 PCI region 1 at address 0xf7920000 has size 0x80, which is not a multiple of 4K. You might experience some performance hit due to that. No IOMMU found. Unable to assign device "(null)" kvm: -device pci-assign,host=07:00.0: Device 'pci-assign' could not be initialized lspci | grep 07 07:00.0 Ethernet controller: 3Com Corporation 3c905C-TX/TX-M [Tornado] (rev 74) I shoved an old spare NIC into my motherboard to test PCI pass through. I have searched the Internet with Goolge and found that errors relating to "No IOMMU found" often mean the PCI device is not supported by KVM. Does KVM have to support the device being "passed-through"? I though the point was to pass the device through and let the guest worry about it? Ultimately I want to pass-through a PCI random number generator, is this not going to be possible with KVM? Thank you.

    Read the article

  • Disable everything in windows except program c#

    - by rubentjeuh
    Hello, I've got the following question: Is it possible te disable everything in windows except the program it's running? I need to program an application on a touchscreen (fullscreen), where people can fill in a survey. The only thing they should use is this program. (for protection of the survey anwsers and other secret stuff :p ) And the program should be closed when entering the right password. So how can I disable everything else but the program I'm running? Thanks

    Read the article

  • [WCF] Simple login

    - by Tr?n Qu?c Bình
    Hi everybody, I have a WCF service like this: [ServiceContract( SessionMode=SessionMode.Required)] public interface IService { [OperationContract(IsInitiating = true, IsTerminating = false)] void login(string id); [OperationContract(IsInitiating = false, IsTerminating = false)] string getdata(); } public class Service : IService { public void login(string hashedid) { if (username != "someusername" || password != "somepassword") { // can not get data } else { // can get data } } public string getdata() { return "these are data"; } } How can I write the method login and create the client application? Thanks you.

    Read the article

  • how to set the user credentials for accessing an webservice

    - by prince23
    hi, i have an webservive written where any user hit the url can acces the webservice.now i need to set username and password for the webservice so that before accessing the webservice they need to provide the user credentials only valid user would be allowed to access the webservice how can i achive this functionality. is there any setting tat i need to do any help would be great thank you

    Read the article

  • If I can ping my DB server, is my SQL Server connection guaranteed to work?

    - by Matt
    If I can ping my DB server, is my SQL Server connection guaranteed to work? I am using a default connection string in my code. My program runs fine locally but overseas sites are having issues and I am wondering if SQL might be using a TCP or UDP port that is still blocked. Here is the connection string "Data Source=xxxx.xxxx.com; Initial Catalog = xxxxx; User ID=xxxxx;password=xxxxx"

    Read the article

  • Forgot the user name

    - by prithviraj
    Hello all I have fedora installed in my system. I know the password but i forgot the user name. I can access through terminal but i don't no how to login through gui. Please help me. Thanks in advance.

    Read the article

  • Fabfile with support for sqlalchemy-migrate deployments?

    - by Chris Reid
    I have database migrations (with sqlalchemy-migrate) working well in my dev environment. However, I'm a little stumped about how to integrate this into my deployment process. I'm using fabric for deployment but having some trouble scripting the migrations part. The path to the to migrations directory in site-packages is dynamic (due to changing egg version number) and I'd rather not hard code my db password into the fabfile. Does anyone have a fabfile that plays nicely with sqlalchemy-migrate?

    Read the article

  • Is this class is a POJO

    - by Narendra
    Hi All, I have a doubt regarding POJO. Take below example public class **user** { String user=""; String password=""; String firstName=""; String lastName=""; ChallengeQuestions challengeQuestions; //Getter and setters for thses prooperties } public class **ChallengeQuestions** { String question=""; String answer=""; //getter and setters for these properties } Here My question is **User** class is POJO or not. Thanks, Narendra

    Read the article

  • How do I authenticate to a Proxy Server from clj-apache-http?

    - by erikcw
    I'm trying to get up an running using http://github.com/rnewman/clj-apache-http (http/get (java.net.URI. url) :headers {"User-Agent" user-agent} :parameters (http/map->params {:default-proxy (http/http-host :host "localhost" :port 8888)}) :as :string) Problem is, my proxy (squid) requires authentication. How do I "feed" my username/password into this library? Thanks!

    Read the article

  • xslt test if a variable value is contained in a node set

    - by Aamir
    I have the following two files: <?xml version="1.0" encoding="utf-8" ?> <!-- D E F A U L T H O S P I T A L P O L I C Y --> <xas DefaultPolicy="open" DefaultSubjectsFile="subjects.xss"> <rule id="R1" access="deny" object="record" subject="roles/*[name()!='Staff']"/> <rule id="R2" access="deny" object="diagnosis" subject="roles//Nurse"/> <rule id="R3" access="grant" object="record[@id=$user]" subject="roles/member[@id=$user]"/> </xas> and the other xml file called subjects.xss is: <?xml version="1.0" encoding="utf-8" ?> <subjects> <users> <member id="dupont" password="4A-4E-E9-17-5D-CE-2C-DD-43-43-1D-F1-3F-5D-94-71"> <name>Pierre Dupont</name> </member> <member id="durand" password="3A-B6-1B-E8-C0-1F-CD-34-DF-C4-5E-BA-02-3C-04-61"> <name>Jacqueline Durand</name> </member> </users> <roles> <Staff> <Doctor> <member idref="dupont"/> </Doctor> <Nurse> <member idref="durand"/> </Nurse> </Staff> </roles> </subjects> I am writing an xsl sheet which will read the subject value for each rule in policy.xas and if the currently logged in user (accessible as variable "user" in the stylesheet) is contained in that subject value (say roles//Nurse), then do something. I am not being able to test whether the currently logged in user ($user which is equal to say "durand") is contained in roles//Nurse in the subjects file (which is a different xml file). Hope that clarifies my question. Any ideas? Thanks in advance.

    Read the article

  • Which SHA-256 is correct? The Java SHA-256 digest or the Linux commandline tool

    - by Peter Tillemans
    When I calculate in Java an SHA-256 of a string with the following method I get : 5e884898da2847151d0e56f8dc6292773603dd6aabbdd62a11ef721d1542d8 on the commandline I do : echo "password" | sha256sum and get 5e884898da28047151d0e56f8dc6292773603d0d6aabbdd62a11ef721d1542d8 if we compare these more closely I find 2 subtle differences 5e884898da2847151d0e56f8dc6292773603dd6aabbdd62a11ef721d1542d8 5e884898da28047151d0e56f8dc6292773603d0d6aabbdd62a11ef721d1542d8 or : 5e884898da28 47151d0e56f8dc6292773603d d6aabbdd62a11ef721d1542d8 5e884898da28 0 47151d0e56f8dc6292773603d 0 d6aabbdd62a11ef721d1542d8 Which of the 2 is correct here?

    Read the article

  • How to connect an existing strongly-typed data set to a different server at run time?

    - by Kiril
    I am coding a simple space empire management game in Visual C# 2008, which relies on connecting to a remote SQL server database to get/store data. I would like the user to be able to connect to a user-specified SQL server from the login screen(he specifies IP address, port, database name, ID, password and presses "connect" button). However, I found out that the Dataset connection string property is read only and cannot be changed. Is there any way to guide the wizard-generated DataSet to a user-specified server at run time?

    Read the article

  • Error code while trying to use private variables in a function

    - by Cortopasta
    I get an error that says Parse error: syntax error, unexpected T_PRIVATE in E:\PortableApps\xampp\htdocs\SN\AC\ACclass.php on line 6 while trying to run my script. I'm new to classes in PHP and was wondering if someone could point out my error. Here's the code for that part. <?php class ac { public function authentication() { private $plain_username = $_POST['username']; private $md5_password = md5($_POST['password']); $ac = new ac();

    Read the article

  • How can give validation on custom registration form in drupal?

    - by Nitz
    Hey Friends, I have created custom registration form in drupal 6. i have used changed the behavior of the drupal registration page by adding this code in themes. template file function earthen_theme($existing, $type, $theme, $path) { return array( // tell Drupal what template to use for the user register form 'user_register' => array( 'arguments' => array('form' => NULL), 'template' => 'user_register', // this is the name of the template ), ); } and my user_register.tpl.php file is looking like this... //php tag starts from here $forms['access'] = array( '#type' = 'fieldset', '#title' = t('Access log settings'), ); $form['my_text_field']=array( '#type' = 'textfield', '#default_value' = $node-title, '#size' = 30, '#maxlength' = 50, '#required' = TRUE ); <div id="registration_form"><br> <div class="field"> <?php print drupal_render($form['my_text_field']); // prints the username field ?> </div> <div class="field"> <?php print drupal_render($form['account']['name']); // prints the username field ?> </div> <div class="field"> <?php print drupal_render($form['account']['pass']); // print the password field ?> </div> <div class="field"> <?php print drupal_render($form['account']['email']); // print the password field ?> </div> <div class="field"> <?php print drupal_render($form['submit']); // print the submit button ?> </div> </div> How to make validation on "my_text_field" which is custmized. and exactly i want that as soon as user click on my_text_field then datetime picker should be open and whichever date user select, that date should be value in my_text_field. so guys help. Thanks in advance, nitish Panchjanya Corporation

    Read the article

  • Maze not generating properly. Out of bounds exception. need quick fix

    - by Dan Joseph Porcioncula
    My maze generator seems to have a problem. I am trying to generate something like the maze from http://mazeworks.com/mazegen/mazetut/index.htm . My program displays this http://a1.sphotos.ak.fbcdn.net/hphotos-ak-snc7/s320x320/374060_426350204045347_100000111130260_1880768_1572427285_n.jpg and the error Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: -1 at Grid.genRand(Grid.java:73) at Grid.main(Grid.java:35) How do I fix my generator program? import java.awt.*; import java.awt.Color; import java.awt.Component; import java.awt.Graphics; import javax.swing.*; import java.util.ArrayList; public class Grid extends Canvas { Cell[][] maze; int size; int pathSize; double width, height; ArrayList<int[]> coordinates = new ArrayList<int[]>(); public Grid(int size, int h, int w) { this.size = size; maze = new Cell[size][size]; for(int i = 0; i<size; i++){ for(int a =0; a<size; a++){ maze[i][a] = new Cell(); } } setPreferredSize(new Dimension(h, w)); } public static void main(String[] args) { JFrame y = new JFrame(); y.setLayout(new BorderLayout()); Grid f = new Grid(25, 400, 400); y.add(f, BorderLayout.CENTER); y.setSize(450, 450); y.setVisible(true); y.setDefaultCloseOperation(y.EXIT_ON_CLOSE); f.genRand(); f.repaint(); } public void push(int[] xy) { coordinates.add(xy); int i = coordinates.size(); coordinates.ensureCapacity(i++); } public int[] pop() { int[] x = coordinates.get((coordinates.size())-1); coordinates.remove((coordinates.size())-1); return x; } public int[] top() { return coordinates.get((coordinates.size())-1); } public void genRand(){ // create a CellStack (LIFO) to hold a list of cell locations [x] // set TotalCells = number of cells in grid int TotalCells = size*size; // choose a cell at random and call it CurrentCell int m = randomInt(size); int n = randomInt(size); Cell curCel = maze[m][n]; // set VisitedCells = 1 int visCel = 1,d=0; int[] q; int h,o = 0,p = 0; // while VisitedCells < TotalCells while( visCel < TotalCells){ // find all neighbors of CurrentCell with all walls intact if(maze[m-1][n].countWalls() == 4){d++;} if(maze[m+1][n].countWalls() == 4){d++;} if(maze[m][n-1].countWalls() == 4){d++;} if(maze[m][n+1].countWalls() == 4){d++;} // if one or more found if(d!=0){ Point[] ls = new Point[4]; ls[0] = new Point(m-1,n); ls[1] = new Point(m+1,n); ls[2] = new Point(m,n-1); ls[3] = new Point(m,n+1); // knock down the wall between it and CurrentCell h = randomInt(3); switch(h){ case 0: o = (int)(ls[0].getX()); p = (int)(ls[0].getY()); curCel.destroyWall(2); maze[o][p].destroyWall(1); break; case 1: o = (int)(ls[1].getX()); p = (int)(ls[1].getY()); curCel.destroyWall(1); maze[o][p].destroyWall(2); break; case 2: o = (int)(ls[2].getX()); p = (int)(ls[2].getY()); curCel.destroyWall(3); maze[o][p].destroyWall(0); break; case 3: o = (int)(ls[3].getX()); p = (int)(ls[3].getY()); curCel.destroyWall(0); maze[o][p].destroyWall(3); break; } // push CurrentCell location on the CellStack push(new int[] {m,n}); // make the new cell CurrentCell m = o; n = p; curCel = maze[m][n]; // add 1 to VisitedCells visCel++; } // else else{ // pop the most recent cell entry off the CellStack q = pop(); m = q[0]; n = q[1]; curCel = maze[m][n]; // make it CurrentCell // endIf } // endWhile } } public int randomInt(int s) { return (int)(s* Math.random());} public void paint(Graphics g) { int k, j; width = getSize().width; height = getSize().height; double htOfRow = height / (size); double wdOfRow = width / (size); //checks verticals - destroys east border of cell for (k = 0; k < size; k++) { for (j = 0; j < size; j++) { if(maze[k][j].checkWall(2)){ g.drawLine((int) (k * wdOfRow), (int) (j * htOfRow), (int) (k * wdOfRow), (int) ((j+1) * htOfRow)); }} } //checks horizontal - destroys north border of cell for (k = 0; k < size; k++) { for (j = 0; j < size; j++) { if(maze[k][j].checkWall(3)){ g.drawLine((int) (k * wdOfRow), (int) (j * htOfRow), (int) ((k+1) * wdOfRow), (int) (j * htOfRow)); }} } } } class Cell { private final static int NORTH = 0; private final static int EAST = 1; private final static int WEST = 2; private final static int SOUTH = 3; private final static int NO = 4; private final static int START = 1; private final static int END = 2; boolean[] wall = new boolean[4]; boolean[] border = new boolean[4]; boolean[] backtrack = new boolean[4]; boolean[] solution = new boolean[4]; private boolean isVisited = false; private int Key = 0; public Cell(){ for(int i=0;i<4;i++){wall[i] = true;} } public int countWalls(){ int i, k =0; for(i=0; i<4; i++) { if (wall[i] == true) {k++;} } return k;} public boolean checkWall(int x){ switch(x){ case 0: return wall[0]; case 1: return wall[1]; case 2: return wall[2]; case 3: return wall[3]; } return true; } public void destroyWall(int x){ switch(x){ case 0: wall[0] = false; break; case 1: wall[1] = false; break; case 2: wall[2] = false; break; case 3: wall[3] = false; break; } } public void setStart(int i){Key = i;} public int getKey(){return Key;} public boolean checkVisit(){return isVisited;} public void visitCell(){isVisited = true;} }

    Read the article

  • How do I mount a drive when user clicks on a button of MFC application

    - by Subhen
    Now I have a MFC application which accepts the user name and password and on click of connect it should mount the drive. The drivers team has already created and installed the driver which has function to mount the drive. Now the problem is when I click the login button on my MFC app then the mount function in drive should be called. But how do I post the message to the driver? Is there any other way arround ?

    Read the article

  • Error: java.lang.ClassCastException

    - by theJava
    Updating the entire post. public Login authenticate(Login login) { String query = "SELECT email, id FROM Login WHERE email=? AND password=?"; Object[] parameters = { login.getEmail(), login.getPassword() }; List resultsList = getHibernateTemplate().find(query,parameters); if ( resultsList.size() == 1 ) { results = (Login)resultsList.get(0); System.out.println(results); } else { System.out.println("Error dude.... "); // error no entity or mutiple entities } return results; } I now return Login Objects. private void checkLogin() { form.commit(); Login newUser = new Login(); newUser = ilogin.authenticate(loginbean); System.out.println("Its Null Value" + newUser); if (newUser == null) { getWindow().showNotification("Login failed", LOGIN_ERROR_MSG, Notification.TYPE_WARNING_MESSAGE); } else { System.out.println(newUser); getApplication().setUser(newUser); } } When there is no matching email, i get there is no such user and also this statement does get printed out. System.out.println("Its Null Value" + newUser); But when there is a email and password matching. I get weird error. Caused by: java.lang.ClassCastException: [Ljava.lang.Object; cannot be cast to com.intermedix.domain.Login at com.intermedix.services.LoginService.authenticate(LoginService.java:30) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.springframework.aop.support.AopUtils.invokeJoinpointUsingReflection(AopUtils.java:301) at org.springframework.aop.framework.ReflectiveMethodInvocation.invokeJoinpoint(ReflectiveMethodInvocation.java:182) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:149) at org.springframework.transaction.interceptor.TransactionInterceptor.invoke(TransactionInterceptor.java:106) at org.springframework.aop.framework.ReflectiveMethodInvocation.proceed(ReflectiveMethodInvocation.java:171) at org.springframework.aop.framework.JdkDynamicAopProxy.invoke(JdkDynamicAopProxy.java:204) at $Proxy32.authenticate(Unknown Source) at com.intermedix.ui.LoginDailog.checkLogin(LoginDailog.java:106) at com.intermedix.ui.LoginDailog.access$0(LoginDailog.java:102) at com.intermedix.ui.LoginDailog$1.buttonClick(LoginDailog.java:52) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at com.vaadin.event.ListenerMethod.receiveEvent(ListenerMethod.java:487) ... 26 more

    Read the article

  • using mod_auth_mysql and mod_auth together

    - by sirrobin
    is it possible to use a database and a flatfile to authenticate a user for a directory. for example, if the requested user is not found in the database, apache should check the flatfile via mod_auth for the user. this is my current .htaccess files AuthMYSQLEnable On AuthName "Restricted" AuthType Basic AuthGroupFile /dev/null AuthMySQLHost localhost AuthMySQLDB members AuthMySQLUser admin AuthMySQLPassword admin123 AuthMySQLUserTable members AuthMySQLNameField username AuthMySQLPasswordField password AuthMySQLPwEncryption md5 require valid-user

    Read the article

  • IsAuthenticated is false! weird behaviour + review question

    - by Naor
    This is the login function (after I validate user name and password, I load user data into "user" variable and call Login function: public static void Login(IUser user) { HttpResponse Response = HttpContext.Current.Response; HttpRequest Request = HttpContext.Current.Request; FormsAuthenticationTicket ticket = new FormsAuthenticationTicket(1, user.UserId.ToString(), DateTime.Now, DateTime.Now.AddHours(12), false, UserResolver.Serialize(user)); HttpCookie cookie = new HttpCookie(FormsAuthentication.FormsCookieName, FormsAuthentication.Encrypt(ticket)); cookie.Path = FormsAuthentication.FormsCookiePath; Response.Cookies.Add(cookie); string redirectUrl = user.HomePage; Response.Redirect(redirectUrl, true); } UserResolver is the following class: public class UserResolver { public static IUser Current { get { IUser user = null; if (HttpContext.Current.User.Identity.IsAuthenticated) { FormsIdentity id = (FormsIdentity)HttpContext.Current.User.Identity; FormsAuthenticationTicket ticket = id.Ticket; user = Desrialize(ticket.UserData); } return user; } } public static string Serialize(IUser user) { StringBuilder data = new StringBuilder(); StringWriter w = new StringWriter(data); string type = user.GetType().ToString(); //w.Write(type.Length); w.WriteLine(user.GetType().ToString()); StringBuilder userData = new StringBuilder(); XmlSerializer serializer = new XmlSerializer(user.GetType()); serializer.Serialize(new StringWriter(userData), user); w.Write(userData.ToString()); w.Close(); return data.ToString(); } public static IUser Desrialize(string data) { StringReader r = new StringReader(data); string typeStr = r.ReadLine(); Type type=Type.GetType(typeStr); string userData = r.ReadToEnd(); XmlSerializer serializer = new XmlSerializer(type); return (IUser)serializer.Deserialize(new StringReader(userData)); } } And the global.asax implements the following: void Application_PostAuthenticateRequest(Object sender, EventArgs e) { IPrincipal p = HttpContext.Current.User; if (p.Identity.IsAuthenticated) { IUser user = UserResolver.Current; Role[] roles = user.GetUserRoles(); HttpContext.Current.User = Thread.CurrentPrincipal = new GenericPrincipal(p.Identity, Role.ToString(roles)); } } First question: Am I do it right? Second question - weird thing! The user variable I pass to Login has 4 members: UserName, Password, Name, Id. When UserResolver.Current executed, I got the user instance. I descided to change the user structure - I add an array of Warehouse object. Since that time, when UserResolver.Current executed (after Login), HttpContext.Current.User.Identity.IsAuthenticated was false and I couldn't get the user data. When I removed the Warehouse[] from user structure, it starts to be ok again and HttpContext.Current.User.Identity.IsAuthenticated become true after I Login. What is the reason to this weird behaviour?

    Read the article

< Previous Page | 287 288 289 290 291 292 293 294 295 296 297 298  | Next Page >