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  • SQL to return the rownum of a specific row? (using Oracle db)

    - by jedierikb
    In Oracle 10g, I have this SQL: select dog.id as dogId from CANINES dog order by dog.codename asc which returns: id -- 204 203 206 923 I want to extend this query to determine the oracle rownum of a dog.id in this resultset. I have tried select rownum from (select dog.id as dogId from CANINES dog order by dog.codename asc) where dog.id=206 But this does not work out very well (it returns 1 no matter which dog.id I match on). I was expecting to get back 3. Thanks for your help! Notes http://www.oracle.com/technology/oramag/oracle/06-sep/o56asktom.html I am pretty sure I do not need to use rowid

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  • DB Interface Design Optimization: Is it better to optimise for Fewer requests of smaller data size?

    - by Overflow
    The prevailing wisdom in webservices/web requests in general is to design your api such that you use as few requests as possible, and that each request returns therefore as much data as is needed In database design, the accepted wisdom is to design your queries to minimise size over the network, as opposed to minimizing the number of queries. They are both remote calls, so what gives?

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  • How to duplicate all data in a table except for a single column that should be changed.

    - by twiga
    I have a question regarding a unified insert query against tables with different data structures (Oracle). Let me elaborate with an example: tb_customers ( id NUMBER(3), name VARCHAR2(40), archive_id NUMBER(3) ) tb_suppliers ( id NUMBER(3), name VARCHAR2(40), contact VARCHAR2(40), xxx, xxx, archive_id NUMBER(3) ) The only column that is present in all tables is [archive_id]. The plan is to create a new archive of the dataset by copying (duplicating) all records to a different database partition and incrementing the archive_id for those records accordingly. [archive_id] is always part of the primary key. My problem is with select statements to do the actual duplication of the data. Because the columns are variable, I am struggling to come up with a unified select statement that will copy the data and update the archive_id. One solution (that works), is to iterate over all the tables in a stored procedure and do a: CREATE TABLE temp as (SELECT * from ORIGINAL_TABLE); UPDATE temp SET archive_id=something; INSERT INTO temp (select * from temp); DROP TABLE temp; I do not like this solution very much as the DDL commands muck up all restore points. Does anyone else have any solution?

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  • how to decrease queries in php/mysql array selection loop

    - by Mac Taylor
    hey guys i need to show stories details and tags' names in my php/mysql project . for every story row, there is a filed named : tags that save tags id as an array Table name: stories table filed : tags example of tags filed : 1 5 6 space between them and i have a tag table that looks like this Table name : bt_tags Table fileds : tid,tag now problem : when using while loop to fetch all fields in story table , the page uses 1 query to show every stories' detail but for showing tag's names , i should query another table to find names , we have ids stored in story table now i used for loop between while loop to show tag names but im sure there is a better way to decrease page queries $result = $db->sql_query("SELECT * FROM ".STORY_TABLE." "); while ($row = $db->sql_fetchrow($result)) { //fetching other $vars ---- $tags_id = explode(" ",$row['tags']); $c = count($tags_id); for($i=1;$i<$c-1;$i++){ list($tag_name,$slug) = $db->sql_fetchrow($db->sql_query( 'SELECT `tag`,`slug` FROM `bt_tags` WHERE `tid` = "'.tags_id[$i].'" LIMIT 1' )); $sow_tags = '$tag_name,'; } im not allowed to change anything in database table how can i improve this script and show tag's names without using *for loop ?*

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  • Should I Split Tables Relevant to X Module Into Different DB? Mysql

    - by Michael Robinson
    I've inherited a rather large and somewhat messy codebase, and have been tasked with making it faster, less noodly and generally better. Currently we use one big database to hold all data for all aspects of the site. As we need to plan for significant growth in the future, I'm considering splitting tables relevant to specific sections of the site into different databases, so if/when one gets too large for one server I can more easily migrate some user data to different mysql servers while retaining overall integrity. I would still need to use joins on some tables across the new databases. Is this a normal thing to do? Would I incur a performance hit because of this?

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  • Adding Information in SQLite

    - by Cam
    Hi All, I am having trouble with my Android App when adding information into SQLite. I am relatively new to Java/SQLite and though I have followed a lot of tutorials on SQLite and have been able to get the example code to run I am unable to get tables to be created and data to import when running my own app. I have included my code in two Java files Questions (Main Program) and QuestionData (helper class represents the database). Questions.java: public class Questions extends Activity { private QuestionData questions; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.quiztest); questions = new QuestionData(this); try { Cursor cursor = getQuestions(); showQuestions(cursor); } finally { questions.close(); } } private Cursor getQuestions() { //Select Query String loadQuestions = "SELECT * FROM questionlist"; SQLiteDatabase db = questions.getReadableDatabase(); Cursor cursor = db.rawQuery(loadQuestions, null); startManagingCursor(cursor); return cursor; } private void showQuestions(Cursor cursor) { // Collect String Values from Query and Display them this part of the code is wokring fine when there is data present. QuestionData.java public class QuestionData extends SQLiteOpenHelper { private static final String DATABASE_NAME = "TriviaQuiz.db" ; private static final int DATABASE_VERSION = 2; public QuestionData(Context ctx) { super(ctx, DATABASE_NAME, null, DATABASE_VERSION); } @Override public void onCreate(SQLiteDatabase db) { db.execSQL("CREATE TABLE questionlist (_id INTEGER PRIMARY KEY AUTOINCREMENT, QID TEXT, QQuestion TEXT, QAnswer TEXT, QOption1 TEXT, QOption2 TEXT, QOption3 TEXT, QCategoryTagLvl1 TEXT, QCategoryTagLvl2 TEXT, QOptionalTag1 TEXT, QOptionalTag2 TEXT, QOptionalTag3 TEXT, QOptionalTag4 TEXT, QOptionalTag5 TEXT, QTimePeriod TEXT, QDifficultyRating TEXT, QGenderBias TEXT, QAgeBias TEXT, QRegion TEXT, QWikiLink TEXT, QValidationLink1 TEXT, QValidationLink2 TEXT, QHint TEXT, QLastValidation TEXT, QNotes TEXT, QMultimediaType TEXT, QMultimediaLink TEXT, QLastAsked TEXT);"); db.execSQL("INSERT INTO questionlist (_id, QID, QQuestion, QAnswer, QOption1, QOption2, QOption3, QCategoryTagLvl1, QCategoryTagLvl2, QOptionalTag1, QOptionalTag2, QOptionalTag3, QOptionalTag4, QOptionalTag5, QTimePeriod, QDifficultyRating, QGenderBias, QAgeBias, QRegion, QWikiLink, QValidationLink1, QValidationLink2, QHint, QLastValidation, QNotes, QMultimediaType, QMultimediaLink, QLastAsked)"+ "VALUES (null,'Q00001','Example','Ans1','Q1','Q2','Q3','Q4','','','','','','','','','','','','','','','','','','','','')"); } @Override public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) { db.execSQL("DROP TABLE IF EXISTS " + TABLE_NAME); onCreate(db); } } Any suggestions at all would be great. I have tried debugging which suggests that the database does not exist. Thanks in advance for your assistance.

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  • How do I use a concatenation of 2 columns in a SQL DB in ASP.NET properly?

    - by user293357
    I'm using LinqToSql like this with a CheckBoxList in ASP.NET: var teachers = from x in dc.teachers select x; cbl.DataSource = teachers; cbl.DataTextField = "name"; cbl.DataValueField = "teacherID"; cbl.DataBind(); I want to display both "firstname" and "name" in the DataTextField however. I found this solution but I'm using LINQ: http://stackoverflow.com/questions/839223/concatenate-two-fields-in-a-dropdown How do I do this?

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  • Connect to a DB with an encrypted password with Django?

    - by Liam
    My place of employment requires that all passwords must be encrypted, including the ones used to connect to a database. What's the best way of handling this? I'm using the development version of Django with MySQL at the moment, but I will be eventually migrating to Oracle. Is this a job for Django, or the database? Edit: The encrypted password should be stored in the settings.py file, or somewhere else in the filesystem. This is the password that will be used to connect to the database.

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  • Displaying Longitude and Latitude values stored in a SQLite db as a Route on a MapView in Android (N

    - by LordSnoutimus
    I am currently in the process of creating an application that records current location of a mobile device in intervals, displaying the route as a coloured line on the device in real-time. At the same time the application is storing the longitude and latitude in a SQLite database as I want the user to be able to bring up that specific route again. The route has a primary key and each waypoint is linked to that route by a foreign key. What would be the easiest way to display the saved route on the map?.

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  • Passing user_id, site_id, and question_id to same table on create...

    - by bgadoci
    I can't seem to figure out how to do this. I am trying to pass four different variables to a single table. To be more specific I am trying to create a "like" in a likes table that also captures the site_id (like an answer), user_id, and the question_id. Here is the set up. class Like < ActiveRecord::Base belongs_to :site belongs_to :user belongs_to :question end I will spare you the reverse, has_many associations but they are there. Here is the likes controller where I think the problem is. class LikesController < ApplicationController def create @user = current_user @site = Site.find(params[:site_id]) @like = @site.likes.create!(params[:like]) @like.user = current_user @like.save respond_to do |format| format.html { redirect_to @site} format.js end end end This code successfully passes the like and site_id but after many different variations of trying I can't get it to pass the question id. Here is my form: /views/sites/_site.html.erb (though the partial is being displayed in the /views/questions/show.html.erb file). <% remote_form_for [site, Like.new] do |f| %> <%= f.hidden_field :site_name, :value => "#{site.name}" %> <%= f.hidden_field :ip_address, :value => "#{request.remote_ip}" %> <%= f.hidden_field :like, :value => "1" %> <%= submit_tag "^" , :class => 'voteup' %> <% end %>

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  • How to create a tabbar on clicking a row in table in iphone?

    - by Warrior
    My first view consist of table with 7 rows of data.When i click each row it should navigate to a view with tab bar with 4 tabitems .In this what is the proper approac of creating a tab bar. When should i create it.Should i create in didSelectRowAtIndexPath of the table in first view like this UITabBarController *tabbar=[[UITabBarController alloc] init]; Homepageview* vc1 = [[Homepageview alloc] initWithNibName:@"Homepageview" bundle:nil] ; vc1.tabBarItem.title=@"Home"; vc1.tabBarItem.image = [UIImage imageNamed:@"home.png"]; ShoppingView* vc2 = [[ShoppingView alloc] initWithNibName:@"ShoppingView" bundle:nil]; vc2.tabBarItem.title=@"Shopping"; vc2.tabBarItem.image = [UIImage imageNamed:@"shopping.png"]; Checkout* vc3 = [[Checkout alloc] initWithNibName:@"Checkout" bundle:nil] ; vc3.tabBarItem.title=@"Checkout"; vc3.tabBarItem.image = [UIImage imageNamed:@"checkout1.png"]; Settings *vc4=[[SlSettings alloc] initWithNibName:@"Settings" bundle:nil] ; vc4.tabBarItem.title=@"Settings"; vc4.tabBarItem.image = [UIImage imageNamed:@"setting1.png"]; tabbar.delegate = self; tabbar.viewControllers = [NSArray arrayWithObjects:vc1, vc2, vc3,vc4,nil]; //self.navigationItem.title=@"Snhopping list"; //[tabbar.selectedViewController viewDidAppear:YES]; [self.navigationController pushViewController:tabbar animated:YES]; [vc1 release]; [vc2 release]; [vc3 release]; [vc4 release]; [tabbar release]; Or is there any alternate to do it. If i do it by the above method , when i navigate from the home page view of tabbar to another view then i am not able to get tab bar.Please help me out.Thanks.

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  • object references an unsaved transient instance

    - by developer
    Hi, I have 2 tables, user and userprofile, both with almost identical fields. user table references userprofile table by primary key ID. My requirement is that on click of a button I need to dump user table record to userprofile table. Now for a particular user table, if there is a corresponding userprofile entry, I am successfully able to dump the data, but if there is no record in userprofile table then I need to create a new record by dumping all the data. My problem is that I am able to update the data when the record is present in userprofile table, but in the case wherein I have to create a new record I get the below error "object references an unsaved transient instance - save the transient instance before flushing". `<class name="User"> <id name="ID" type="Int32"> <generator class="native" /> </id> <many-to-one name="Pid" class="UserProfile" /> </class>` UserProfile is another table and Pid above references the Primary key ID of UserProfile table.

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  • Authlogic: passwords saved in the DB are not working as expected.

    - by user570459
    Hello everyone, Im having trouble with authlogic on my production server. Im able to update passwords in the database but when i try to validate a user using the new password, the validation fails. Please check the below console output. Notice how the salt and crypted_password fields get update before and after the new password is saved. The issue is only on my production server (running passenger). Everything works fine on my development machine. => #<User id: 3, login: "saravk", email: "[email protected]", crypted_password: "9bc86247105e940bb748ab680c0e77d9c44a82ea", salt: "WdVpQIdwl68k8lJWOU"> irb(main):003:0> u.password = "kettik123" => "kettik123" irb(main):004:0> u.password_confirmation = "kettik123" => "kettik123" irb(main):005:0> u.save! => true irb(main):006:0> u.valid_password?("kettik123") => true irb(main):007:0> u.reload => #<User id: 3, login: "saravk", email: "[email protected]", crypted_password: "f059007c56f498a12c63209c849c1e65bb151174", salt: "lVmmczhyGE0gxsbV421A"> irb(main):008:0> u.valid_password?("kettik123") => false The authlogic configuration in my User model.. class User < ActiveRecord::Base acts_as_authentic do |c| c.login_field :email c.validate_login_field false c.validate_email_field false c.perishable_token_valid_for = 1.day c.disable_perishable_token_maintenance = true end I use the email field as the main key for the user. Also the email field is allowed to be blank in some cases (eg a facebook user) Also i belive that my schema is proper (in terms of the length of the salt & crypted password fields) create_table "users", :force => true do |t| t.string "login" t.string "email" t.string "crypted_password", :limit => 128, :default => "" t.string "salt", Any help on this would be highly appreciated. Thanks.

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  • How to make sure no scripts except those under my own domain, can include the db connection file?

    - by Jack
    I would like to ensure that any scripts that are trying to "include" my database connection file are located under my own domain. I don't want a hacker to include the database connection file to their malicious script and gain access to my database that way. My connection file's name is pretty easy to guess, it's called "connect.php". So without renaming it and taking the security through obscurity route, how can I protect it by making sure all connection requests are made by scripts residing under my own domain name? How can this be checked using PHP?

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  • How can I pivot these key+values rows into a table of complete entries?

    - by CodexArcanum
    Maybe I demand too much from SQL but I feel like this should be possible. I start with a list of key-value pairs, like this: '0:First, 1:Second, 2:Third, 3:Fourth' etc. I can split this up pretty easily with a two-step parse that gets me a table like: EntryNumber PairNumber Item 0 0 0 1 0 First 2 1 1 3 1 Second etc. Now, in the simple case of splitting the pairs into a pair of columns, it's fairly easy. I'm interested in the more advanced case where I might have multiple values per entry, like: '0:First:Fishing, 1:Second:Camping, 2:Third:Hiking' and such. In that generic case, I'd like to find a way to take my 3-column result table and somehow pivot it to have one row per entry and one column per value-part. So I want to turn this: EntryNumber PairNumber Item 0 0 0 1 0 First 2 0 Fishing 3 1 1 4 1 Second 5 1 Camping Into this: Entry [1] [2] [3] 0 0 First Fishing 1 1 Second Camping Is that just too much for SQL to handle, or is there a way? Pivots (even tricky dynamic pivots) seem like an answer, but I can't figure how to get that to work.

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  • How to get a list of users for all instance's databases

    - by stee1rat
    I guess the procedure should be something like this: declare @db varchar(100) declare @user varchar(100) declare c cursor for select name from sys.sysdatabases open c fetch next from c into @db while @@fetch_status = 0 begin print @db exec ('use ' + @db) declare u cursor for select name from sys.sysusers where issqlrole <> 1 and hasdbaccess <> 0 and isntname <> 1 open u fetch next from u into @user while @@fetch_status = 0 begin print @user fetch next from u into @user end print '--------------------------------------------------' close u deallocate u fetch next from c into @db end close c deallocate c But the problem is that exec ('use ' + @db) doesn't work. And i always get user list of currently chosen database. How should i fix that? P.S.: I want this code to work on both 2000 and 2005 sql servers.

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  • How do I select column(s) by their "numeric" position in a table?

    - by DulcimerDude
    I am trying to select columns by their "x" position in the table. DBI my $example = $hookup->prepare(qq{SELECT This,That,Condition,"I also want COLUMN-10" FROM tbl LIMIT ? ?}); ###column_number=10 ordinal_position?? $example->execute('2','10') or die "Did not execute"; Is this possible or do I need to run another single select to just that column? One problem I encountered was with a col named "Condition". For some reason, when I tried to select Condition the execute would die. I never attempted but, What if the column name was SELECT? Another note is the table is 75 cols wide and I only need 50 of them. The Col names are pretty verbose so, I would like to just call them by their "position". This would also allow the col names to be changed in the future without having to change the select statement. I am quite the newbie so please explain any answers down to my level. Thanks for any assistance..

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  • how to store hour and minute in database table while using mktime() function?

    - by Learner Miz
    I am using a form to get the hour and minute using post method and then store it to mysql DB. Such as : $hour = $_POST['hour']; $minute = $_POST['minute']; ** There is no need of date, month and year. I just need to store the hour and minute in a column of a table (ex: exam_time) Column structure: exam_time time NOT NULL Now how to store these value into database using mktime() function. I tried but it stores 00:00:00, not the one which I am sending via form.

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  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

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