Search Results

Search found 28775 results on 1151 pages for 'line'.

Page 300/1151 | < Previous Page | 296 297 298 299 300 301 302 303 304 305 306 307  | Next Page >

• setlocale to fr-FR in PHP and number formatting

  - by bateman_ap

  Hi, I am trying to create a French version of one of my sites. I have set setlocale(LC_ALL, 'fr_FR'); at the top of my page, and using strftime I am displaying dates correctly in the French style. However I am having some problems with a number. Part of the page uses data I am getting from a Web Service. I am assigning a returned value to a var like this: $overallRating = $returnArray['Overall']; I am then using the following code later to format it to 1 decimal place number_format($overallRating,1) In the English version the overallRating value might be 7.5 and returns a value such as 7.5 (the reason for running it through the number_format is if it returns 7 I want it to display 7.0) However in the French version if I print out the raw $overallRating value I get 7,5 which looks like it has translated it into french. This would be fine but if I run it through number_format I get the error: Notice: A non well formed numeric value encountered in /sites/index.php on line 250 Line 250 is the number_format line I presume the translation to 7,5 is messing it up, but not sure how to solve this... Using PHP 5.3 in case there is anything new that helps me

  Read the article

• Treetop basic parsing and regular expression usage

  - by ucint

  I'm developing a script using the ruby Treetop library and having issues working with its syntax for regex's. First off, many regular expressions that work in other settings dont work the same in treetop. This is my grammar: (myline.treetop) grammar MyLine rule line string whitespace condition end rule string [\S]* end rule whitespace [\s]* end rule condition "new" / "old" / "used" end end This is my usage: (usage.rb) require 'rubygems' require 'treetop' require 'polyglot' require 'myline' parser = MyLineParser.new p parser.parse("randomstring new") This should find the word new for sure and it does! Now I wont to extend it so that it can find new if the input string becomes "randomstring anotherstring new yetanother andanother" and possibly have any number of strings followed by whitespace (tab included) before and after the regex for rule condition. In other words, if I pass it any sentence with the word "new" etc in it, it should be able to match it. So let's say I change my grammar to: rule line string whitespace condition whitespace string end Then, it should be able to find a match for: p parser.parse("randomstring new anotherstring") So, what do I have to do to allow the string whitespace to be repeated before and after condition? If I try to write this: rule line (string whitespace)* condition (whitespace string)* end , it goes in an infinite loop. If i replace the above () with [], it returns nil In general, regex's return a match when i use the above, but treetop regex's dont. Does anyone have any tips/points on how to go about this? Plus, since there isn't much documentation for treetop and the examples are either too trivial or too complex, is there anyone who knows a more thorough documentation/guide for treetop?

  Read the article

• asp.net mvc outputting json with backslashes ( escape) despite many attemps to filter

  - by minus4

  i have an asp.net controller that output Json as the results a section of it is here returnString += string.Format(@"{{""filename"":""{0}"",""line"":[", file.Filename); what i get returned is this: "{\"DPI\":\"66.8213457076566\",\"width\":\"563.341067\",\"editable\":\"True\",\"pricecat\":\"6\",\"numpages\":\"2\",\"height\":\"400\",\"page\":[{\"filename\":\"999_9_1.jpg\",\"line\":[]},{\"filename\":\"999_9_2.jpg\",\"line\":[]}]]" i have tried to return with the following methods: return Json(returnString); return Json(returnString.Replace("\\",""); return Json will serialize my string to a jSon string, this i know but it likes to escape for some reason, how can i get rid of it ???? for info this is how i call it with jQuery: $.ajax({ url:"/Products/LoadArtworkToJSon", type:"POST", dataType: "json", async: false, data:{prodid: prodid }, success: function(data){ sessvars.myData = data; measurements = sessvars.myData; $("#loading").remove(); //empty the canvas and create a new one with correct data, always start on page 0; $("#movements").remove(); $("#canvas").append("<div id=\"movements\" style=\"width:" + measurements.width + "px; height:" + Math.round(measurements.height) + "px; display:block; border:1px solid black; background:url(/Content/products/" + measurements.page[0].filename + ") no-repeat;\"></div>"); your help is much appreciated thanks

  Read the article

• Are licenses relevant for small code snippets?

  - by Martin

  When I'm about to write a short algorithm, I first check in the base class library I'm using whether the algorithm is implemented in it. If not, I often do a quick google search to see if someone has done it before (which is the case, 19 times out of 20). Most of the time, I find the exact code I need. Sometimes it's clear what license applies to the source code, sometimes not. It may be GPL, LGPL, BSD or whatever. Sometimes people have posted a code snippet on some random forum which solves my problem. It's clear to me that I can't reuse the code (copy/paste it into my code) without caring about the license if the code is in some way substantial. What is not clear to me is whether I can copy a code snippet containing 5 lines or so without doing a license violation. Can I copy/paste a 5-line code snippet without caring about the license? What about one-liner? What about 10 lines? Where do I draw the line (no pun intended)? My second problem is that if I have found a 10-line code snippet which does exactly what I need, but feel that I cannot copy it because it's GPL-licensed and my software isn't, I have already memorized how to implement it so when I go around implementing the same functionality, my code is almost identical to the GPL licensed code I saw a few minutes ago. (In other words, the code was copied to my brain and my brain after that copied it into my source code).

  Read the article

• how to do bar chart in c

  - by user292489

  i have written a program that prints out the integers in the same order as the input with 5 numbers per line. That is, the first 5 integers will be printed in the first line; the next 5 integers in the next line; and so on. and also i was trying to print out the numbers in a bar chart formatt:like 81-105 ( 1) x 56-80 ( 5) xxxxx 6-11(5) xxxxx -1-5 (3) xxx my program: cntr=0; while (fscanf(in, "%d", &a[i]) != EOF) {i++; fprintf(out, "%d-%d (%d) %s\n", A, B, k, x, cntr); fprintf(out, "%d\n", k, cntr); fprintf(out, "x", a[i]); i++; } fprintf(out, "1864-2336 (%d)%s\n", k, x); fprintf(out, "1391-1863 (%d)%s\n", k, x); fprintf(out, "918-1390 (%d)%s\n", k, x); fprintf(out, "445-917 (%d)%s\n", k, x); fprintf(out,"-28-444 (%d)%s\n", k, x); fclose(in); fclose(out); return 0; } enter code here

  Read the article

• Javascript error: Object required...tough time fixing this

  - by rtnav2301

  The situation is this: a friend of mine asked me to help her with a website she's working on called www.KeepsakePartyInvitations.com. Her original designer created this code but didn't finish the project. So here I am to help save the day. Now, once a photo has been added to the party template and the mouse is placed over the image, an alternate text message appears to the right. The message informs the visitor how to reposition and resize the image, if necessary. I'm testing the procedure in the invitation to reposition the image. I follow the directions about moving the picture, but the mouse does not let go of the photo. Where ever the mouse moves, so does the image. The same thing occurs if you want to resize the image, you follow the directions but the image does not resize. I check the error message in IE 8 and it states: Message: Object required Line: 873 Char: 3 Code: 0 URI: http://www.keepsakepartyinvitations.com/Includes/JCode.js When I checked the Javascript file, the Line 873 states: tempX = e.clientX + document.body.scrollLeft If you review the javascript file, the function where the line is located is called: function getMouseXY(e). Please help me, it has been a long while since I've worked with Javascript and I'm motivated to get this fixed. Thank you!

  Read the article

• How do I find, count, and display unique elements of an array using Perl?

  - by Luke

  I am a novice Perl programmer and would like some help. I have an array list that I am trying to split each element based on the pipe into two scalar elements. From there I would like to spike out only the lines that read ‘PJ RER Apts to Share’ as the first element. Then I want to print out the second element only once while counting each time the element appears. I wrote the piece of code below but can’t figure out where I am going wrong. It might be something small that I am just overlooking. Any help would be greatly appreciated. ## CODE ## my @data = ('PJ RER Apts to Share|PROVIDENCE', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Condo|WEST WARWICK', 'PJ RER Condo|WARWICK'); foreach my $line (@data) { $count = @data; chomp($line); @fields = split(/\|/,$line); if (($fields[0] =~ /PJ RER Apts to Share/g)){ @array2 = $fields[1]; my %seen; my @uniq = grep { ! $seen{$_}++ } @array2; my $count2 = scalar(@uniq); print "$array2[0] ($count2)","\n" } } print "$count","\n"; ## OUTPUT ## PROVIDENCE (1) JOHNSTON (1) JOHNSTON (1) JOHNSTON (1) 6

  Read the article

• HighCharts : Can I customize the colors of individual series?

  - by user1091114

  I am using HighCharts for a line graph and i am attemping to change the line color for each series. I did find this example here but the data is hard coded. My data is pulled from an Sql database and passed to the HTML page using some VB code. var chart; $(document).ready(function () { chart = new Highcharts.Chart({ chart: { renderTo: 'container', defaultSeriesType: 'column' }, title: { text: 'Chart Title' }, subtitle: { text: 'Chart subtitle' }, xAxis: { categories: [<%= GraphDate %>] , labels: { rotation: -45, align: 'right', style: { } } }, yAxis: { min: 160, title: { text: 'Temp' } }, legend: { layout: 'vertical', backgroundColor: '#FFFFFF', align: 'left', verticalAlign: 'top', x: 400, y: 0, floating: true, shadow: true }, tooltip: { formatter: function () { return '' + this.x + ': ' + this.y + ' ºC'; } }, plotOptions: { column: { pointPadding: 0.2, borderWidth: 0 } }, series: [<%= GraphSeries %>], }); I tried to style it using the other post however it failed to generate a chart. The main problem is though, the line graph has two series, so the below method would set the color for both series i assume? So, would i maybe need to format the series in my vb code somehow? series: [{ color: 'yellow', data: [ [<%= GraphSeries %>] ]},

  Read the article

• C# HTML tags inside GridView

  - by Geo Ego

  I have a SharePoint web part that I wrote in C# which is used to display SQL Server data based on user selections. I pull the data with a DataReader, fill a DataSet with it, and set that DataSet as the DataSource in a GridView and add that control to my page. The only problem I'm facing is that line breaks in the data fields are not being rendered at all. I'm simply getting a block of text that ignores the breaks that are present in the database when it's rendered to HTML. I tried a regex: Regex rgx = new Regex("\n"); string inputStr = Convert.ToString(dr[x]); string outputStr = rgx.Replace(inputStr, "<br />"); newRow[ds3.Tables["Bobst Specs 3"].Columns[x]] = outputStr; While that does detect and replace the newlines, I merely get the text "" with no line breaks. I also tried changing my SQL query to something along the lines of: SELECT REPLACE (fldCustomerName, '. ', '.' + @NewLineChar) This apparently renders more newlines. I can see that they are present, because if I also insert the regex they are affected, but do not create line breaks. I'm not sure how to replace these, and what with, to get the lines to actually break.

  Read the article

• Cocoa-Created PDF Not Rendering Correctly

  - by Matthew Roberts

  I've created a PDF on the iPad, but the problem is when you have a line of text greater than 1 line, the content just goes off the page. This is my code: void CreatePDFFile (CGRect pageRect, const char *filename) { CGContextRef pdfContext; CFStringRef path; CFURLRef url; CFMutableDictionaryRef myDictionary = NULL; path = CFStringCreateWithCString (NULL, filename, kCFStringEncodingUTF8); url = CFURLCreateWithFileSystemPath (NULL, path, kCFURLPOSIXPathStyle, 0); CFRelease (path); myDictionary = CFDictionaryCreateMutable(NULL, 0, &kCFTypeDictionaryKeyCallBacks, &kCFTypeDictionaryValueCallBacks); NSString *foos = @"Title"; const char *text = [foos UTF8String]; CFDictionarySetValue(myDictionary, kCGPDFContextTitle, CFSTR(text)); CFDictionarySetValue(myDictionary, kCGPDFContextCreator, CFSTR("Author")); pdfContext = CGPDFContextCreateWithURL (url, &pageRect, myDictionary); CFRelease(myDictionary); CFRelease(url); CGContextBeginPage (pdfContext, &pageRect); CGContextSelectFont (pdfContext, "Helvetica", 12, kCGEncodingMacRoman); CGContextSetTextDrawingMode (pdfContext, kCGTextFill); CGContextSetRGBFillColor (pdfContext, 0, 0, 0, 1); NSString *body = @"text goes here"; const char *text = [body UTF8String]; CGContextShowTextAtPoint (pdfContext, 30, 750, text, strlen(text)); CGContextEndPage (pdfContext); CGContextRelease (pdfContext);} Now the issue lies within me writing the text to the page, but the problem is that I can't seem to specify a multi-line "text view".

  Read the article

• Capture data read from file into string stream Java

  - by halluc1nati0n

  I'm coming from a C++ background, so be kind on my n00bish queries... I'd like to read data from an input file and store it in a stringstream. I can accomplish this in an easy way in C++ using stringstreams. I'm a bit lost trying to do the same in Java. Following is a crude code/way I've developed where I'm storing the data read line-by-line in a string array. I need to use a string stream to capture my data into (rather than use a string array).. Any help? char dataCharArray[] = new char[2]; int marker=0; String inputLine; String temp_to_write_data[] = new String[100]; // Now, read from output_x into stringstream FileInputStream fstream = new FileInputStream("output_" + dataCharArray[0]); // Convert our input stream to a BufferedReader BufferedReader in = new BufferedReader (new InputStreamReader(fstream)); // Continue to read lines while there are still some left to read while ((inputLine = in.readLine()) != null ) { // Print file line to screen // System.out.println (inputLine); temp_to_write_data[marker] = inputLine; marker++; }

  Read the article

• How do I tell gcc to relax its restrictions on typecasting when calling a C function from C++?

  - by Daryl Spitzer

  I'm trying to use Cmockery to mock C functions called from C++ code. Because the SUT is in C++, my tests need to be in C++. When I use the Cmockery expect_string() macro like this: expect_string(mock_function, url, "Foo"); I get: my_tests.cpp: In function ‘void test_some_stuff(void**)’: my_tests.cpp:72: error: invalid conversion from ‘void*’ to ‘const char*’ my_tests.cpp:72: error: initializing argument 5 of ‘void _expect_string(const char*, const char*, const char*, int, const char*, int)’ I see in cmockery.h that expect_string is defined: #define expect_string(function, parameter, string) \ expect_string_count(function, parameter, string, 1) #define expect_string_count(function, parameter, string, count) \ _expect_string(#function, #parameter, __FILE__, __LINE__, (void*)string, \ count) And here's the prototype for _expect_string (from cmockery.h): void _expect_string( const char* const function, const char* const parameter, const char* const file, const int line, const char* string, const int count); I believe the problem is that I'm compiling C code as C++, so the C++ compiler is objecting to (void*)string in the expect_string_count macro being passed as the const char* string parameter to the _expect_string() function. I've already used extern "C" around the cmockery.h include in my_tests.cpp like this: extern "C" { #include <cmockery.h> } ...in order to get around name-mangling problems. (See "How do I compile and link C++ code with compiled C code?") Is there a command-line option or some other means of telling g++ how to relax its restrictions on typecasting from my test's C++ code to the C function in cmockery.c? This is the command I'm currently using to build my_tests.cpp: g++ -m32 -I ../cmockery-0.1.2 -c my_tests.cpp -o $(obj_dir)/my_tests.o

  Read the article

• mysql to excel generation using php

  - by pmms

  <?php // DB Connection here mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $select = "SELECT * FROM jos_users "; $export = mysql_query ( $select ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; ?> The code above is used for generating an Excel spreadsheet from a MySQL database, but we are getting following error: The file you are trying to open, 'users.xls', is in a different format than specified by the file extension. Verify that the file is not corrupted and is from a trusted source before opening the file. Do you want to open the file now? What is the problem and how do we fix it?

  Read the article

• "Unable to open file", when the program tries to open file in /proc

  - by tristartom

  Hi, I try to read file /proc/'pid'/status, using c program. The code is as follows, and even I use sudo to run it, the prompt still keeps throwing "Unable to open file". Please let me know if you have any ideas on how to fix this. thanks Richard ... int main (int argc, char* argv[]) { string line; char* fileLoc; if(argc != 2) { cout << "a.out file_path" << endl; fileLoc = "/proc/net/dev"; } else { sprintf(fileLoc, "/proc/%d/status", atoi(argv[1])); } cout<< fileLoc << endl; ifstream myfile (fileLoc); if (myfile.is_open()) { while (! myfile.eof() ) { getline (myfile,line); cout << line << endl; } myfile.close(); } else cout << "Unable to open file"; return 0; }

  Read the article

• Java split giving opposite order of arabic characters

  - by MuhammadA

  I am splitting the following string using \\| in java (android) using the IntelliJ 12 IDE. Everything is fine except the last part, somehow the split picks them up in the opposite order : As you can see the real positioning 34,35,36 is correct and according to the string, but when it gets picked out into split part no 5 its in the wrong order, 36,35,34 ... Any way I can get them to be in the right order? My Code: public ArrayList<Book> getBooksFromDatFile(Context context, String fileName) { ArrayList<Book> books = new ArrayList<Book>(); try { // load csv from assets InputStream is = context.getAssets().open(fileName); try { BufferedReader reader = new BufferedReader(new InputStreamReader(is)); String line; while ((line = reader.readLine()) != null) { String[] RowData = line.split("\\|"); books.add(new Book(RowData[0], RowData[1], RowData[2], RowData[3], RowData[4], RowData[5])); } } catch (IOException ex) { Log.e(TAG, "Error parsing csv file!"); } finally { try { is.close(); } catch (IOException e) { Log.e(TAG, "Error closing input stream!"); } } } catch (IOException ex) { Log.e(TAG, "Error reading .dat file from assets!"); } return books; }

  Read the article

• Retrieving Json via HTML request from Jboss server

  - by Seth Solomon

  I am running into a java.net.SocketException: Unexpected end of file from server when I am trying to query some JSON from my JBoss server. I am hoping someone can spot where I am going wrong. Or does anyone have any suggestions of a better way to pull this JSON from my Jboss server? try{ URL u = new URL("http://localhost:9990/management/subsystem/datasources/data-source/MySQLDS/statistics?read-resource&include-runtime=true&recursive=true"); HttpURLConnection c = (HttpURLConnection) u.openConnection(); String encoded = Base64.encode(("username"+":"+"password").getBytes()); c.setRequestMethod("POST"); c.setRequestProperty("Authorization", "Basic "+encoded); c.setRequestProperty("Content-Type","application/json"); c.setUseCaches(false); c.setAllowUserInteraction(false); c.setConnectTimeout(5000); c.setReadTimeout(5000); c.connect(); int status = c.getResponseCode(); // throws the exception here switch (status) { case 200: case 201: BufferedReader br = new BufferedReader(new InputStreamReader(c.getInputStream())); StringBuilder sb = new StringBuilder(); String line; while ((line = br.readLine()) != null) { sb.append(line+"\n"); } br.close(); System.out.println(sb.toString()); break; default: System.out.println(status); break; } } catch (Exception e) { e.printStackTrace(); }

  Read the article

• PulpCore OGG music playback - can't loop as soon as I animate the musicVolume property

  - by Peter Perhác

  I have been experimenting with PulpCore for about a week or so and I am enjoying it very much but today I ran into a problem that I can't quite figure out. Sound bgMusic = Sound.load("music/music.ogg"); Playback musicPlayback; ... musicVolume = new Fixed(0.75); musicPlayback = bgMusic.loop(musicVolume); //TODO figure out why it's NOT looping when volume is animated // musicVolume.animate(0, musicVolume.get(), FADE_IN_TIME); This code, for as long as the last line is commented out, plays the music.ogg again and again in an endless loop (which I can stop by calling stop on the Playback object returned from loop(). However, I would like the music to fade in smoothly, so following the advice of the PulpCore API docs, I added the last line which will create the fade-in but the music will only play once and then stop. I wonder why is that? Here is a bit of the documentation: Playback pulpcore.sound.Sound.loop(Fixed level) Loops this sound clip with the specified volume level (0.0 to 1.0). The level may have a property animation attached. Parameters: level Returns: a Playback object for this unique sound playback (one Sound can have many simultaneous Playback objects) or null if the sound could not be played. So what could be the problem? I repeat, with the last line, the sound fades in but doesn't loop, without it it loops but starts with the specified 0.75 volume level.

  Read the article

• Include error in writing html file from php

  - by Grozav Alex Ioan

  I seem to have some problem with my code here. It creates a file from the php file, but I get an error on the include path. include('../include/config.php'); $name = ($_GET['createname']) ? $_GET['createname'] : $_POST['createname']; function buildhtml($strphpfile, $strhtmlfile) { ob_start(); include($strphpfile); $data = ob_get_contents(); $fp = fopen ($strhtmlfile, "w"); fwrite($fp, $data); fclose($fp); ob_end_clean(); } buildhtml('portfolio.php?name='.$name, "../gallery/".$name.".html"); The problem seems to be here: 'portfolio.php?name='.$name Any way I can replace this, and still send the variable over? Here's the error I get when I put ?name after the php extension: Warning: include(portfolio.php?name=hyundai) [function.include]: failed to open stream: No such file or directory in D:\Projects\Metro Web\Coding\admin\create.php on line 15 Warning: include(portfolio.php?name=hyundai) [function.include]: failed to open stream: No such file or directory in D:\Projects\Metro Web\Coding\admin\create.php on line 15 Warning: include() [function.include]: Failed opening 'portfolio.php?name=hyundai' for inclusion (include_path='.;C:\php\pear') in D:\Projects\Metro Web\Coding\admin\create.php on line 15

  Read the article

• Python access an object byref / Need tagging

  - by Aaron C. de Bruyn

  I need to suck data from stdin and create a object. The incoming data is between 5 and 10 lines long. Each line has a process number and either an IP address or a hash. For example: pid=123 ip=192.168.0.1 - some data pid=123 hash=ABCDEF0123 - more data hash=ABCDEF123 - More data ip=192.168.0.1 - even more data I need to put this data into a class like: class MyData(): pid = None hash = None ip = None lines = [] I need to be able to look up the object by IP, HASH, or PID. The tough part is that there are multiple streams of data intermixed coming from stdin. (There could be hundreds or thousands of processes writing data at the same time.) I have regular expressions pulling out the PID, IP, and HASH that I need, but how can I access the object by any of those values? My thought was to do something like this: myarray = {} for each line in sys.stdin.readlines(): if pid and ip: #If we can get a PID out of the line myarray[pid] = MyData().pid = pid #Create a new MyData object, assign the PID, and stick it in myarray accessible by PID. myarray[pid].ip = ip #Add the IP address to the new object myarray[pid].lines.append(data) #Append the data myarray[ip] = myarray[pid] #Take the object by PID and create a key from the IP. <snip>do something similar for pid and hash, hash and ip, etc...</snip> This gives my an array with two keys (a PID and an IP) and they both point to the same object. But on the next iteration of the loop, if I find (for example) an IP and HASH and do: myarray[hash] = myarray[ip] The following is False: myarray[hash] == myarray[ip] Hopefully that was clear. I hate to admit that waaay back in the VB days, I remember being able handle objects byref instead of byval. Is there something similar in Python? Or am I just approaching this wrong?

  Read the article

• Polymorphic Queue

  - by metdos

  Hello Everyone, I'm trying to implement a Polymorphic Queue. Here is my trial: QQueue <Request *> requests; while(...) { QString line = QString::fromUtf8(client->readLine()).trimmed(); if(...)){ Request *request=new Request(); request->tcpMessage=line.toUtf8(); request->decodeFromTcpMessage(); //this initialize variables in request using tcpMessage if(request->requestType==REQUEST_LOGIN){ LoginRequest loginRequest; request=&loginRequest; request->tcpMessage=line.toUtf8(); request->decodeFromTcpMessage(); requests.enqueue(request); } //Here pointers in "requests" do not point to objects I created above, and I noticed that their destructors are also called. LoginRequest *loginRequest2=dynamic_cast<LoginRequest *>(requests.dequeue()); loginRequest2->decodeFromTcpMessage(); } } Unfortunately, I could not manage to make work Polymorphic Queue with this code because of the reason I mentioned in second comment.I guess, I need to use smart-pointers, but how? I'm open to any improvement of my code or a new implementation of polymorphic queue. Thanks.

  Read the article

• how to read an arraylist from a txt file in java?

  - by lox

  how to read an arraylist from a txt file in java? my arraylist is the form of: public class Account { String username; String password; } i managed to put some "Accounts" in the a txt file, but now i don't know how to read them. this is how my arraylist look in the txt file: username1 password1 | username2 password2 | etc this is a part of the code i came up with, but it doesn't work. it looks logic to me though... :) . public static void RdAc(String args[]) { ArrayList<Account> peoplelist = new ArrayList<Account>(50); int i,i2,i3; String[] theword = null; try { FileReader fr = new FileReader("myfile.txt"); BufferedReader br = new BufferedReader(fr); String line = ""; while ((line = br.readLine()) != null) { String[] theline = line.split(" | "); for (i = 0; i < theline.length; i++) { theword = theline[i].split(" "); } for(i3=0;i3<theline.length;i3++) { Account people = new Account(); for (i2 = 0; i2 < theword.length; i2++) { people.username = theword[i2]; people.password = theword[i2+1]; peoplelist.add(people); } } } } catch (IOException ex) { System.out.println("Could not read from file"); } }

  Read the article

• zend framework - quickstart application

  - by m gahagan

  I have been attempting to install the 'quickstart' tutorial application on my system. After a considerable amount of frustration - a) because I dont know how it all works andb) mine's a windows (wamp) set-up, I have got as far as setting up the guestbook database successfully and reaching the Checkpoint: Now browse to http://localhost/guestbook. You should see the following in your browser: I get error: Warning: include(C:\wamp\www\quickstart\application/models//GuestbookMapper.php) [function.include]: failed to open stream: No such file or directory in C:\wamp\www\quickstart\library\Zend\Loader\Autoloader\Resource.php on line 176 Warning: include() [function.include]: Failed opening 'C:\wamp\www\quickstart\application/models//GuestbookMapper.php' for inclusion (include_path='C:\wamp\www\quickstart\library;.;C:\wamp\bin\php\php5.3.0\PEAR;C:\wamp\zend\library;C:\wamp\zend\extras\library') in C:\wamp\www\quickstart\library\Zend\Loader\Autoloader\Resource.php on line 176 Fatal error: Class 'Default_Model_GuestbookMapper' not found in C:\wamp\www\quickstart\application\models\Guestbook.php on line 102 Obviously failing to link relevant files is the main issue - First, that 'C:\wamp\www\quickstart\application/models//GuestbookMapper.php' looks wrong to me, but I cant figure out what's creating it. Second, I have a very tenuous grip on the whole file path system and cant tell whether things are wrongly configured. If I could get the guestbook app to function, then I might be able to get a grip on what's going on. As it is, I seem to fix one problem only to find another round the next corner.

  Read the article

• regex split and extract multiple parts from a string

  - by nLL

  I am trying to extract some parts of the "Video:" line from below text. Seems stream 0 codec frame rate differs from container frame rate: 30000.00 (300 00/1) -> 14.93 (1000/67) Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'C:\a.3gp': Metadata: major_brand : 3gp5 minor_version : 0 compatible_brands: 3gp5isom Duration: 00:00:45.82, start: 0.000000, bitrate: 357 kb/s Stream #0.0(und): Video: mpeg4, yuv420p, 352x276 [PAR 1:1 DAR 88:69], 344 kb /s, 14.93 fps, 14.93 tbr, 90k tbn, 30k tbc Stream #0.1(und): Audio: aac, 16000 Hz, mono, s16, 11 kb/s Stream #0.2(und): Data: mp4s / 0x7334706D, 0 kb/s Stream #0.3(und): Data: mp4s / 0x7334706D, 0 kb/s* This is an output from ffmpeg command line where i can get Video: part with private string ExtractVideoFormat(string rawInfo) { string v = string.Empty; Regex re = new Regex("[V|v]ideo:.*", RegexOptions.Compiled); Match m = re.Match(rawInfo); if (m.Success) { v = m.Value; } return v; } and result is mpeg4, yuv420p, 352x276 [PAR 1:1 DAR 88:69], 344 kb What i am trying to do is to somehow split that line and get mpeg4 yuv420p 352x276 [PAR 1:1 DAR 88:69] 344 kb assigned to different string objects instead of single

  Read the article

• Trouble with piping through sed

  - by Joel

  I am having trouble piping through sed. Once I have piped output to sed, I cannot pipe the output of sed elsewhere. wget -r -nv http://127.0.0.1:3000/test.html Outputs: 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/test.html [99/99] -> "127.0.0.1:3000/test.html" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/robots.txt [83/83] -> "127.0.0.1:3000/robots.txt" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/shop [22818/22818] -> "127.0.0.1:3000/shop.29" [1] I pipe the output through sed to get a clean list of URLs: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' Outputs: http://127.0.0.1:3000/test.html http://127.0.0.1:3000/robots.txt http://127.0.0.1:3000/shop I would like to then dump the output to file, so I do this: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' > /tmp/DUMP_FILE I interrupt the process after a few seconds and check the file, yet it is empty. Interesting, the following yields no output (same as above, but piping sed output through cat): wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' | cat Why can I not pipe the output of sed to another program like cat?

  Read the article

• Does Java 6 open a default port for JMX remote connections?

  - by Bob Cross

  My specific question has to do with JMX as used in JDK 1.6: if I am running a Java process using JRE 1.6 with com.sun.management.jmxremote in the command line, does Java pick a default port for remote JMX connections? Backstory: I am currently trying to develop a procedure to give to a customer that will enable them to connect to one of our processes via JMX from a remote machine. The goal is to facillitate their remote debugging of a situation occurring on a real-time display console. Because of their service level agreement, they are strongly motivated to capture as much data as possible and, if the situation looks too complicated to fix quickly, to restart the display console and allow it to reconnect to the server-side. I am aware the I could run jconsole on JDK 1.6 processes and jvisualvm on post-JDK 1.6.7 processes given physical access to the console. However, because of the operational requirements and people problems involved, we are strongly motivated to grab the data that we need remotely and get them up and running again. EDIT: I am aware of the command line port property com.sun.management.jmxremote.port=portNum The question that I am trying to answer is, if you do not set that property at the command line, does Java pick another port for remote monitoring? If so, how could you determine what it might be?

  Read the article

< Previous Page | 296 297 298 299 300 301 302 303 304 305 306 307  | Next Page >