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  • how to do bar chart in c

    - by user292489
    i have written a program that prints out the integers in the same order as the input with 5 numbers per line. That is, the first 5 integers will be printed in the first line; the next 5 integers in the next line; and so on. and also i was trying to print out the numbers in a bar chart formatt:like 81-105 ( 1) x 56-80 ( 5) xxxxx 6-11(5) xxxxx -1-5 (3) xxx my program: cntr=0; while (fscanf(in, "%d", &a[i]) != EOF) {i++; fprintf(out, "%d-%d (%d) %s\n", A, B, k, x, cntr); fprintf(out, "%d\n", k, cntr); fprintf(out, "x", a[i]); i++; } fprintf(out, "1864-2336 (%d)%s\n", k, x); fprintf(out, "1391-1863 (%d)%s\n", k, x); fprintf(out, "918-1390 (%d)%s\n", k, x); fprintf(out, "445-917 (%d)%s\n", k, x); fprintf(out,"-28-444 (%d)%s\n", k, x); fclose(in); fclose(out); return 0; } enter code here

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  • Include error in writing html file from php

    - by Grozav Alex Ioan
    I seem to have some problem with my code here. It creates a file from the php file, but I get an error on the include path. include('../include/config.php'); $name = ($_GET['createname']) ? $_GET['createname'] : $_POST['createname']; function buildhtml($strphpfile, $strhtmlfile) { ob_start(); include($strphpfile); $data = ob_get_contents(); $fp = fopen ($strhtmlfile, "w"); fwrite($fp, $data); fclose($fp); ob_end_clean(); } buildhtml('portfolio.php?name='.$name, "../gallery/".$name.".html"); The problem seems to be here: 'portfolio.php?name='.$name Any way I can replace this, and still send the variable over? Here's the error I get when I put ?name after the php extension: Warning: include(portfolio.php?name=hyundai) [function.include]: failed to open stream: No such file or directory in D:\Projects\Metro Web\Coding\admin\create.php on line 15 Warning: include(portfolio.php?name=hyundai) [function.include]: failed to open stream: No such file or directory in D:\Projects\Metro Web\Coding\admin\create.php on line 15 Warning: include() [function.include]: Failed opening 'portfolio.php?name=hyundai' for inclusion (include_path='.;C:\php\pear') in D:\Projects\Metro Web\Coding\admin\create.php on line 15

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  • Are licenses relevant for small code snippets?

    - by Martin
    When I'm about to write a short algorithm, I first check in the base class library I'm using whether the algorithm is implemented in it. If not, I often do a quick google search to see if someone has done it before (which is the case, 19 times out of 20). Most of the time, I find the exact code I need. Sometimes it's clear what license applies to the source code, sometimes not. It may be GPL, LGPL, BSD or whatever. Sometimes people have posted a code snippet on some random forum which solves my problem. It's clear to me that I can't reuse the code (copy/paste it into my code) without caring about the license if the code is in some way substantial. What is not clear to me is whether I can copy a code snippet containing 5 lines or so without doing a license violation. Can I copy/paste a 5-line code snippet without caring about the license? What about one-liner? What about 10 lines? Where do I draw the line (no pun intended)? My second problem is that if I have found a 10-line code snippet which does exactly what I need, but feel that I cannot copy it because it's GPL-licensed and my software isn't, I have already memorized how to implement it so when I go around implementing the same functionality, my code is almost identical to the GPL licensed code I saw a few minutes ago. (In other words, the code was copied to my brain and my brain after that copied it into my source code).

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  • Retrieving Json via HTML request from Jboss server

    - by Seth Solomon
    I am running into a java.net.SocketException: Unexpected end of file from server when I am trying to query some JSON from my JBoss server. I am hoping someone can spot where I am going wrong. Or does anyone have any suggestions of a better way to pull this JSON from my Jboss server? try{ URL u = new URL("http://localhost:9990/management/subsystem/datasources/data-source/MySQLDS/statistics?read-resource&include-runtime=true&recursive=true"); HttpURLConnection c = (HttpURLConnection) u.openConnection(); String encoded = Base64.encode(("username"+":"+"password").getBytes()); c.setRequestMethod("POST"); c.setRequestProperty("Authorization", "Basic "+encoded); c.setRequestProperty("Content-Type","application/json"); c.setUseCaches(false); c.setAllowUserInteraction(false); c.setConnectTimeout(5000); c.setReadTimeout(5000); c.connect(); int status = c.getResponseCode(); // throws the exception here switch (status) { case 200: case 201: BufferedReader br = new BufferedReader(new InputStreamReader(c.getInputStream())); StringBuilder sb = new StringBuilder(); String line; while ((line = br.readLine()) != null) { sb.append(line+"\n"); } br.close(); System.out.println(sb.toString()); break; default: System.out.println(status); break; } } catch (Exception e) { e.printStackTrace(); }

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  • Can you help with this assembly language code?

    - by Mugen
    Hi, I've been looking through a piece of code of a pc game that I'm trying to "improve". (ok so maybe I suck at the game but I still want to play it). Could you please look into the following code: fld dword ptr[ebp+00007B1C] fsub dword ptr[esp+64] fst dword ptr[ebp+00007B1C] call 004A2E48 This code is called every second for the level countdown timer. I need to stay on a particular level for a few minutes. If I can modify the above code so that the value pushed into the address [ebp+00007B1C] is 0 then the game level will always time out and it will save me playing those crazy "survival" minigames. I'll explain what I understand from this code. Dont worry, you dont have to go deep into this. In the first line we get the timer value. For example if 97 seconds are remaining then it is here that this value is loaded. In the second line a value (1 second) is subtracted from 97. In the third line 96 is again moved to memory. And finally we have the function call that will do other processing based on the time remaining. Now all I need to do is patch this piece of code somehow so that the value that is pushed is 0 (in the third step). Can you please help me out with this?

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  • asp.net mvc outputting json with backslashes ( escape) despite many attemps to filter

    - by minus4
    i have an asp.net controller that output Json as the results a section of it is here returnString += string.Format(@"{{""filename"":""{0}"",""line"":[", file.Filename); what i get returned is this: "{\"DPI\":\"66.8213457076566\",\"width\":\"563.341067\",\"editable\":\"True\",\"pricecat\":\"6\",\"numpages\":\"2\",\"height\":\"400\",\"page\":[{\"filename\":\"999_9_1.jpg\",\"line\":[]},{\"filename\":\"999_9_2.jpg\",\"line\":[]}]]" i have tried to return with the following methods: return Json(returnString); return Json(returnString.Replace("\\",""); return Json will serialize my string to a jSon string, this i know but it likes to escape for some reason, how can i get rid of it ???? for info this is how i call it with jQuery: $.ajax({ url:"/Products/LoadArtworkToJSon", type:"POST", dataType: "json", async: false, data:{prodid: prodid }, success: function(data){ sessvars.myData = data; measurements = sessvars.myData; $("#loading").remove(); //empty the canvas and create a new one with correct data, always start on page 0; $("#movements").remove(); $("#canvas").append("<div id=\"movements\" style=\"width:" + measurements.width + "px; height:" + Math.round(measurements.height) + "px; display:block; border:1px solid black; background:url(/Content/products/" + measurements.page[0].filename + ") no-repeat;\"></div>"); your help is much appreciated thanks

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  • Devise routes to only use custom sign in page

    - by eblume
    I am trying to learn Devise and seem to have hit a problem that is nearly the same as many, many questions here on SO but just slightly different enough that I am not getting much traction following those questions' threads. I have a very simple application. Users can sign in and sign out (and also the devise 'forgot password' stuff is enabled - I am not concerned about it at this time) and that is it. They can't register, they can't edit their profile other than to change their password, they can't do anything except sign in and sign out. (Account creation will, for now, be handled manually at the command line.) I would vastly prefer that the only page that users can log in from was "/" (root_path). I already have it working where you can log in from "/", and that is great. The problem I am having is that if you type in your user/password combination incorrectly from the root_path login page, it automatically sends you to the Devise sign-in page to continue trying to sign in. How can I make Devise redirect to root_path on sign-in failure? Here are my routes - they are probably not optimal or correctly configured and I would appreciate pointers on fixing them: root to: "core_pages#splash" devise_for :users, skip: [:sessions] as :user do # get 'signin' => 'devise/sessions#new', as: :new_user_session post 'signin' => 'devise/sessions#create', as: :user_session delete 'signout' => 'devise/sessions#destroy', as: :destroy_user_session, via: Devise.mappings[:user].sign_out_via end match '/home' => 'core_pages#home' Note the commented-out 'get signin' line. The system works without this line but, surprisingly (to me), "GET /signin" results in a HTTP 400 (OK) response and renders the Devise login template. I would prefer it return some sort of 'invalid request' or just silently redirect the user to root_path. Running rake routes on these routes gives: root / core_pages#splash user_password POST /users/password(.:format) devise/passwords#create new_user_password GET /users/password/new(.:format) devise/passwords#new edit_user_password GET /users/password/edit(.:format) devise/passwords#edit PUT /users/password(.:format) devise/passwords#update user_session POST /signin(.:format) devise/sessions#create destroy_user_session DELETE /signout(.:format) devise/sessions#destroy home /home(.:format) core_pages#home Thanks!

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  • How do I tell gcc to relax its restrictions on typecasting when calling a C function from C++?

    - by Daryl Spitzer
    I'm trying to use Cmockery to mock C functions called from C++ code. Because the SUT is in C++, my tests need to be in C++. When I use the Cmockery expect_string() macro like this: expect_string(mock_function, url, "Foo"); I get: my_tests.cpp: In function ‘void test_some_stuff(void**)’: my_tests.cpp:72: error: invalid conversion from ‘void*’ to ‘const char*’ my_tests.cpp:72: error: initializing argument 5 of ‘void _expect_string(const char*, const char*, const char*, int, const char*, int)’ I see in cmockery.h that expect_string is defined: #define expect_string(function, parameter, string) \ expect_string_count(function, parameter, string, 1) #define expect_string_count(function, parameter, string, count) \ _expect_string(#function, #parameter, __FILE__, __LINE__, (void*)string, \ count) And here's the prototype for _expect_string (from cmockery.h): void _expect_string( const char* const function, const char* const parameter, const char* const file, const int line, const char* string, const int count); I believe the problem is that I'm compiling C code as C++, so the C++ compiler is objecting to (void*)string in the expect_string_count macro being passed as the const char* string parameter to the _expect_string() function. I've already used extern "C" around the cmockery.h include in my_tests.cpp like this: extern "C" { #include <cmockery.h> } ...in order to get around name-mangling problems. (See "How do I compile and link C++ code with compiled C code?") Is there a command-line option or some other means of telling g++ how to relax its restrictions on typecasting from my test's C++ code to the C function in cmockery.c? This is the command I'm currently using to build my_tests.cpp: g++ -m32 -I ../cmockery-0.1.2 -c my_tests.cpp -o $(obj_dir)/my_tests.o

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  • Javascript error: Object required...tough time fixing this

    - by rtnav2301
    The situation is this: a friend of mine asked me to help her with a website she's working on called www.KeepsakePartyInvitations.com. Her original designer created this code but didn't finish the project. So here I am to help save the day. Now, once a photo has been added to the party template and the mouse is placed over the image, an alternate text message appears to the right. The message informs the visitor how to reposition and resize the image, if necessary. I'm testing the procedure in the invitation to reposition the image. I follow the directions about moving the picture, but the mouse does not let go of the photo. Where ever the mouse moves, so does the image. The same thing occurs if you want to resize the image, you follow the directions but the image does not resize. I check the error message in IE 8 and it states: Message: Object required Line: 873 Char: 3 Code: 0 URI: http://www.keepsakepartyinvitations.com/Includes/JCode.js When I checked the Javascript file, the Line 873 states: tempX = e.clientX + document.body.scrollLeft If you review the javascript file, the function where the line is located is called: function getMouseXY(e). Please help me, it has been a long while since I've worked with Javascript and I'm motivated to get this fixed. Thank you!

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  • How can I optimize this or is there a better way to do it?(HTML Syntax Highlighter)

    - by Tanner
    Hello every one, I have made a HTML syntax highlighter in C# and it works great, but there's one problem. First off It runs pretty fast because it syntax highlights line by line, but when I paste more than one line of code or open a file I have to highlight the whole file which can take up to a minute for a file with only 150 lines of code. I tried just highlighting visible lines in the richtextbox but then when I try to scroll I can't it to highlight the new visible text. Here is my code:(note: I need to use regex so I can get the stuff in between < & characters) Highlight Whole File: public void AllMarkup() { int selectionstart = richTextBox1.SelectionStart; Regex rex = new Regex("<html>|</html>|<head.*?>|</head>|<body.*?>|</body>|<div.*?>|</div>|<span.*?>|</span>|<title.*?>|</title>|<style.*?>|</style>|<script.*?>|</script>|<link.*?/>|<meta.*?/>|<base.*?/>|<center.*?>|</center>|<a.*?>|</a>"); foreach (Match m in rex.Matches(richTextBox1.Text)) { richTextBox1.Select(m.Index, m.Value.Length); richTextBox1.SelectionColor = Color.Blue; richTextBox1.Select(selectionstart, -1); richTextBox1.SelectionColor = Color.Black; } richTextBox1.SelectionStart = selectionstart; } private void pasteToolStripMenuItem_Click(object sender, EventArgs e) { try { LockWindowUpdate(richTextBox1.Handle);//Stops text from flashing flashing richTextBox1.Paste(); AllMarkup(); }finally { LockWindowUpdate(IntPtr.Zero); } } I want to know if there's a better way to highlight this and make it faster or if someone can help me make it highlight only the visible text. Please help. :) Thanks, Tanner.

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  • Java split giving opposite order of arabic characters

    - by MuhammadA
    I am splitting the following string using \\| in java (android) using the IntelliJ 12 IDE. Everything is fine except the last part, somehow the split picks them up in the opposite order : As you can see the real positioning 34,35,36 is correct and according to the string, but when it gets picked out into split part no 5 its in the wrong order, 36,35,34 ... Any way I can get them to be in the right order? My Code: public ArrayList<Book> getBooksFromDatFile(Context context, String fileName) { ArrayList<Book> books = new ArrayList<Book>(); try { // load csv from assets InputStream is = context.getAssets().open(fileName); try { BufferedReader reader = new BufferedReader(new InputStreamReader(is)); String line; while ((line = reader.readLine()) != null) { String[] RowData = line.split("\\|"); books.add(new Book(RowData[0], RowData[1], RowData[2], RowData[3], RowData[4], RowData[5])); } } catch (IOException ex) { Log.e(TAG, "Error parsing csv file!"); } finally { try { is.close(); } catch (IOException e) { Log.e(TAG, "Error closing input stream!"); } } } catch (IOException ex) { Log.e(TAG, "Error reading .dat file from assets!"); } return books; }

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  • PHP Error handling in WordPress plugin

    - by AaronM
    I am a newbie to both PHP and Wordpress (but do ok in C#), and am struggling to understand the error handling in a custom plugin I am attempting to write. The basics of the plugin is to query an exsiting MSSQL database (note its not the standard MYSQL db...) and return the rows back to the screen. This was working well, but the hosting provider has taken my database offline, which led me to the error handling problem (which I thought was ok). The following code is failing to connect to the database (as expected), but puts an error onto the screen and stops the page processing. It does not even output the 'or die' error text. QUESTION: How can I just output a simple "Cant load data" message, and continue on normally? function generateData() { global $post; if ("$post->post_title" == "Home") { try { $myServer = "<servername>"; $myUser = "<username>"; $myPass = "<password>"; $myDB = "<dbName>"; //connection to the database $dbhandle = mssql_connect($myServer, $myUser, $myPass) or die("Couldn't open database $myDB"); //... query processing here... } catch (Exception $e) { echo "Cannot load data<br />"; } } return $content; } Error being generated: (line 31 is $dbhandle = mssql_connect...) Warning: mssql_connect() [function.mssql-connect]: Unable to connect to server: <servername> in <file path> on line 31 Fatal error: Maximum execution time of 30 seconds exceeded in <file path> on line 31

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  • Capture data read from file into string stream Java

    - by halluc1nati0n
    I'm coming from a C++ background, so be kind on my n00bish queries... I'd like to read data from an input file and store it in a stringstream. I can accomplish this in an easy way in C++ using stringstreams. I'm a bit lost trying to do the same in Java. Following is a crude code/way I've developed where I'm storing the data read line-by-line in a string array. I need to use a string stream to capture my data into (rather than use a string array).. Any help? char dataCharArray[] = new char[2]; int marker=0; String inputLine; String temp_to_write_data[] = new String[100]; // Now, read from output_x into stringstream FileInputStream fstream = new FileInputStream("output_" + dataCharArray[0]); // Convert our input stream to a BufferedReader BufferedReader in = new BufferedReader (new InputStreamReader(fstream)); // Continue to read lines while there are still some left to read while ((inputLine = in.readLine()) != null ) { // Print file line to screen // System.out.println (inputLine); temp_to_write_data[marker] = inputLine; marker++; }

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  • Python access an object byref / Need tagging

    - by Aaron C. de Bruyn
    I need to suck data from stdin and create a object. The incoming data is between 5 and 10 lines long. Each line has a process number and either an IP address or a hash. For example: pid=123 ip=192.168.0.1 - some data pid=123 hash=ABCDEF0123 - more data hash=ABCDEF123 - More data ip=192.168.0.1 - even more data I need to put this data into a class like: class MyData(): pid = None hash = None ip = None lines = [] I need to be able to look up the object by IP, HASH, or PID. The tough part is that there are multiple streams of data intermixed coming from stdin. (There could be hundreds or thousands of processes writing data at the same time.) I have regular expressions pulling out the PID, IP, and HASH that I need, but how can I access the object by any of those values? My thought was to do something like this: myarray = {} for each line in sys.stdin.readlines(): if pid and ip: #If we can get a PID out of the line myarray[pid] = MyData().pid = pid #Create a new MyData object, assign the PID, and stick it in myarray accessible by PID. myarray[pid].ip = ip #Add the IP address to the new object myarray[pid].lines.append(data) #Append the data myarray[ip] = myarray[pid] #Take the object by PID and create a key from the IP. <snip>do something similar for pid and hash, hash and ip, etc...</snip> This gives my an array with two keys (a PID and an IP) and they both point to the same object. But on the next iteration of the loop, if I find (for example) an IP and HASH and do: myarray[hash] = myarray[ip] The following is False: myarray[hash] == myarray[ip] Hopefully that was clear. I hate to admit that waaay back in the VB days, I remember being able handle objects byref instead of byval. Is there something similar in Python? Or am I just approaching this wrong?

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  • mysql to excel generation using php

    - by pmms
    <?php // DB Connection here mysql_connect("localhost","root",""); mysql_select_db("hitnrunf_db"); $select = "SELECT * FROM jos_users "; $export = mysql_query ( $select ) or die ( "Sql error : " . mysql_error( ) ); $fields = mysql_num_fields ( $export ); for ( $i = 0; $i < $fields; $i++ ) { $header .= mysql_field_name( $export , $i ) . "\t"; } while( $row = mysql_fetch_row( $export ) ) { $line = ''; foreach( $row as $value ) { if ( ( !isset( $value ) ) || ( $value == "" ) ) { $value = "\t"; } else { $value = str_replace( '"' , '""' , $value ); $value = '"' . $value . '"' . "\t"; } $line .= $value; } $data .= trim( $line ) . "\n"; } $data = str_replace( "\r" , "" , $data ); if ( $data == "" ) { $data = "\n(0) Records Found!\n"; } header("Content-type: application/octet-stream"); header("Content-Disposition: attachment; filename=your_desired_name.xls"); header("Pragma: no-cache"); header("Expires: 0"); print "$header\n$data"; ?> The code above is used for generating an Excel spreadsheet from a MySQL database, but we are getting following error: The file you are trying to open, 'users.xls', is in a different format than specified by the file extension. Verify that the file is not corrupted and is from a trusted source before opening the file. Do you want to open the file now? What is the problem and how do we fix it?

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  • C# HTML tags inside GridView

    - by Geo Ego
    I have a SharePoint web part that I wrote in C# which is used to display SQL Server data based on user selections. I pull the data with a DataReader, fill a DataSet with it, and set that DataSet as the DataSource in a GridView and add that control to my page. The only problem I'm facing is that line breaks in the data fields are not being rendered at all. I'm simply getting a block of text that ignores the breaks that are present in the database when it's rendered to HTML. I tried a regex: Regex rgx = new Regex("\n"); string inputStr = Convert.ToString(dr[x]); string outputStr = rgx.Replace(inputStr, "<br />"); newRow[ds3.Tables["Bobst Specs 3"].Columns[x]] = outputStr; While that does detect and replace the newlines, I merely get the text "" with no line breaks. I also tried changing my SQL query to something along the lines of: SELECT REPLACE (fldCustomerName, '. ', '.' + @NewLineChar) This apparently renders more newlines. I can see that they are present, because if I also insert the regex they are affected, but do not create line breaks. I'm not sure how to replace these, and what with, to get the lines to actually break.

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  • How do I find, count, and display unique elements of an array using Perl?

    - by Luke
    I am a novice Perl programmer and would like some help. I have an array list that I am trying to split each element based on the pipe into two scalar elements. From there I would like to spike out only the lines that read ‘PJ RER Apts to Share’ as the first element. Then I want to print out the second element only once while counting each time the element appears. I wrote the piece of code below but can’t figure out where I am going wrong. It might be something small that I am just overlooking. Any help would be greatly appreciated. ## CODE ## my @data = ('PJ RER Apts to Share|PROVIDENCE', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Apts to Share|JOHNSTON', 'PJ RER Condo|WEST WARWICK', 'PJ RER Condo|WARWICK'); foreach my $line (@data) { $count = @data; chomp($line); @fields = split(/\|/,$line); if (($fields[0] =~ /PJ RER Apts to Share/g)){ @array2 = $fields[1]; my %seen; my @uniq = grep { ! $seen{$_}++ } @array2; my $count2 = scalar(@uniq); print "$array2[0] ($count2)","\n" } } print "$count","\n"; ## OUTPUT ## PROVIDENCE (1) JOHNSTON (1) JOHNSTON (1) JOHNSTON (1) 6

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  • how to read an arraylist from a txt file in java?

    - by lox
    how to read an arraylist from a txt file in java? my arraylist is the form of: public class Account { String username; String password; } i managed to put some "Accounts" in the a txt file, but now i don't know how to read them. this is how my arraylist look in the txt file: username1 password1 | username2 password2 | etc this is a part of the code i came up with, but it doesn't work. it looks logic to me though... :) . public static void RdAc(String args[]) { ArrayList<Account> peoplelist = new ArrayList<Account>(50); int i,i2,i3; String[] theword = null; try { FileReader fr = new FileReader("myfile.txt"); BufferedReader br = new BufferedReader(fr); String line = ""; while ((line = br.readLine()) != null) { String[] theline = line.split(" | "); for (i = 0; i < theline.length; i++) { theword = theline[i].split(" "); } for(i3=0;i3<theline.length;i3++) { Account people = new Account(); for (i2 = 0; i2 < theword.length; i2++) { people.username = theword[i2]; people.password = theword[i2+1]; peoplelist.add(people); } } } } catch (IOException ex) { System.out.println("Could not read from file"); } }

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  • regex split and extract multiple parts from a string

    - by nLL
    I am trying to extract some parts of the "Video:" line from below text. Seems stream 0 codec frame rate differs from container frame rate: 30000.00 (300 00/1) -> 14.93 (1000/67) Input #0, mov,mp4,m4a,3gp,3g2,mj2, from 'C:\a.3gp': Metadata: major_brand : 3gp5 minor_version : 0 compatible_brands: 3gp5isom Duration: 00:00:45.82, start: 0.000000, bitrate: 357 kb/s Stream #0.0(und): Video: mpeg4, yuv420p, 352x276 [PAR 1:1 DAR 88:69], 344 kb /s, 14.93 fps, 14.93 tbr, 90k tbn, 30k tbc Stream #0.1(und): Audio: aac, 16000 Hz, mono, s16, 11 kb/s Stream #0.2(und): Data: mp4s / 0x7334706D, 0 kb/s Stream #0.3(und): Data: mp4s / 0x7334706D, 0 kb/s* This is an output from ffmpeg command line where i can get Video: part with private string ExtractVideoFormat(string rawInfo) { string v = string.Empty; Regex re = new Regex("[V|v]ideo:.*", RegexOptions.Compiled); Match m = re.Match(rawInfo); if (m.Success) { v = m.Value; } return v; } and result is mpeg4, yuv420p, 352x276 [PAR 1:1 DAR 88:69], 344 kb What i am trying to do is to somehow split that line and get mpeg4 yuv420p 352x276 [PAR 1:1 DAR 88:69] 344 kb assigned to different string objects instead of single

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  • Cocoa-Created PDF Not Rendering Correctly

    - by Matthew Roberts
    I've created a PDF on the iPad, but the problem is when you have a line of text greater than 1 line, the content just goes off the page. This is my code: void CreatePDFFile (CGRect pageRect, const char *filename) { CGContextRef pdfContext; CFStringRef path; CFURLRef url; CFMutableDictionaryRef myDictionary = NULL; path = CFStringCreateWithCString (NULL, filename, kCFStringEncodingUTF8); url = CFURLCreateWithFileSystemPath (NULL, path, kCFURLPOSIXPathStyle, 0); CFRelease (path); myDictionary = CFDictionaryCreateMutable(NULL, 0, &kCFTypeDictionaryKeyCallBacks, &kCFTypeDictionaryValueCallBacks); NSString *foos = @"Title"; const char *text = [foos UTF8String]; CFDictionarySetValue(myDictionary, kCGPDFContextTitle, CFSTR(text)); CFDictionarySetValue(myDictionary, kCGPDFContextCreator, CFSTR("Author")); pdfContext = CGPDFContextCreateWithURL (url, &pageRect, myDictionary); CFRelease(myDictionary); CFRelease(url); CGContextBeginPage (pdfContext, &pageRect); CGContextSelectFont (pdfContext, "Helvetica", 12, kCGEncodingMacRoman); CGContextSetTextDrawingMode (pdfContext, kCGTextFill); CGContextSetRGBFillColor (pdfContext, 0, 0, 0, 1); NSString *body = @"text goes here"; const char *text = [body UTF8String]; CGContextShowTextAtPoint (pdfContext, 30, 750, text, strlen(text)); CGContextEndPage (pdfContext); CGContextRelease (pdfContext);} Now the issue lies within me writing the text to the page, but the problem is that I can't seem to specify a multi-line "text view".

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  • "Unable to open file", when the program tries to open file in /proc

    - by tristartom
    Hi, I try to read file /proc/'pid'/status, using c program. The code is as follows, and even I use sudo to run it, the prompt still keeps throwing "Unable to open file". Please let me know if you have any ideas on how to fix this. thanks Richard ... int main (int argc, char* argv[]) { string line; char* fileLoc; if(argc != 2) { cout << "a.out file_path" << endl; fileLoc = "/proc/net/dev"; } else { sprintf(fileLoc, "/proc/%d/status", atoi(argv[1])); } cout<< fileLoc << endl; ifstream myfile (fileLoc); if (myfile.is_open()) { while (! myfile.eof() ) { getline (myfile,line); cout << line << endl; } myfile.close(); } else cout << "Unable to open file"; return 0; }

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  • zend framework - quickstart application

    - by m gahagan
    I have been attempting to install the 'quickstart' tutorial application on my system. After a considerable amount of frustration - a) because I dont know how it all works andb) mine's a windows (wamp) set-up, I have got as far as setting up the guestbook database successfully and reaching the Checkpoint: Now browse to http://localhost/guestbook. You should see the following in your browser: I get error: Warning: include(C:\wamp\www\quickstart\application/models//GuestbookMapper.php) [function.include]: failed to open stream: No such file or directory in C:\wamp\www\quickstart\library\Zend\Loader\Autoloader\Resource.php on line 176 Warning: include() [function.include]: Failed opening 'C:\wamp\www\quickstart\application/models//GuestbookMapper.php' for inclusion (include_path='C:\wamp\www\quickstart\library;.;C:\wamp\bin\php\php5.3.0\PEAR;C:\wamp\zend\library;C:\wamp\zend\extras\library') in C:\wamp\www\quickstart\library\Zend\Loader\Autoloader\Resource.php on line 176 Fatal error: Class 'Default_Model_GuestbookMapper' not found in C:\wamp\www\quickstart\application\models\Guestbook.php on line 102 Obviously failing to link relevant files is the main issue - First, that 'C:\wamp\www\quickstart\application/models//GuestbookMapper.php' looks wrong to me, but I cant figure out what's creating it. Second, I have a very tenuous grip on the whole file path system and cant tell whether things are wrongly configured. If I could get the guestbook app to function, then I might be able to get a grip on what's going on. As it is, I seem to fix one problem only to find another round the next corner.

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  • Does Java 6 open a default port for JMX remote connections?

    - by Bob Cross
    My specific question has to do with JMX as used in JDK 1.6: if I am running a Java process using JRE 1.6 with com.sun.management.jmxremote in the command line, does Java pick a default port for remote JMX connections? Backstory: I am currently trying to develop a procedure to give to a customer that will enable them to connect to one of our processes via JMX from a remote machine. The goal is to facillitate their remote debugging of a situation occurring on a real-time display console. Because of their service level agreement, they are strongly motivated to capture as much data as possible and, if the situation looks too complicated to fix quickly, to restart the display console and allow it to reconnect to the server-side. I am aware the I could run jconsole on JDK 1.6 processes and jvisualvm on post-JDK 1.6.7 processes given physical access to the console. However, because of the operational requirements and people problems involved, we are strongly motivated to grab the data that we need remotely and get them up and running again. EDIT: I am aware of the command line port property com.sun.management.jmxremote.port=portNum The question that I am trying to answer is, if you do not set that property at the command line, does Java pick another port for remote monitoring? If so, how could you determine what it might be?

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  • Trouble with piping through sed

    - by Joel
    I am having trouble piping through sed. Once I have piped output to sed, I cannot pipe the output of sed elsewhere. wget -r -nv http://127.0.0.1:3000/test.html Outputs: 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/test.html [99/99] -> "127.0.0.1:3000/test.html" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/robots.txt [83/83] -> "127.0.0.1:3000/robots.txt" [1] 2010-03-12 04:41:48 URL:http://127.0.0.1:3000/shop [22818/22818] -> "127.0.0.1:3000/shop.29" [1] I pipe the output through sed to get a clean list of URLs: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' Outputs: http://127.0.0.1:3000/test.html http://127.0.0.1:3000/robots.txt http://127.0.0.1:3000/shop I would like to then dump the output to file, so I do this: wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' > /tmp/DUMP_FILE I interrupt the process after a few seconds and check the file, yet it is empty. Interesting, the following yields no output (same as above, but piping sed output through cat): wget -r -nv http://127.0.0.1:3000/test.html 2>&1 | grep --line-buffered -v ERROR | sed 's/^.*URL:\([^ ]*\).*/\1/g' | cat Why can I not pipe the output of sed to another program like cat?

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  • PulpCore OGG music playback - can't loop as soon as I animate the musicVolume property

    - by Peter Perhác
    I have been experimenting with PulpCore for about a week or so and I am enjoying it very much but today I ran into a problem that I can't quite figure out. Sound bgMusic = Sound.load("music/music.ogg"); Playback musicPlayback; ... musicVolume = new Fixed(0.75); musicPlayback = bgMusic.loop(musicVolume); //TODO figure out why it's NOT looping when volume is animated // musicVolume.animate(0, musicVolume.get(), FADE_IN_TIME); This code, for as long as the last line is commented out, plays the music.ogg again and again in an endless loop (which I can stop by calling stop on the Playback object returned from loop(). However, I would like the music to fade in smoothly, so following the advice of the PulpCore API docs, I added the last line which will create the fade-in but the music will only play once and then stop. I wonder why is that? Here is a bit of the documentation: Playback pulpcore.sound.Sound.loop(Fixed level) Loops this sound clip with the specified volume level (0.0 to 1.0). The level may have a property animation attached. Parameters: level Returns: a Playback object for this unique sound playback (one Sound can have many simultaneous Playback objects) or null if the sound could not be played. So what could be the problem? I repeat, with the last line, the sound fades in but doesn't loop, without it it loops but starts with the specified 0.75 volume level.

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