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  • Taking over and Moving a PHP site

    - by KCavon
    I have a internal use PHP site at my new position. It only runs a few days a year off site so we keep it on laptops. The hardware it has been on, a 8 year IBM Thinkpad running Fedora, is dying. I have new Lenovo Thinkpad's running latest and greatest Ubuntu. I have copied the contents of var to a shared drive, renamed the old www folder in var on the new machine and copied over the old www folder. I can get to the login page and into the site, but when I look something up it returns Cannot Open. I know I cannot get to the MySQL in the new machine because users and passwords dont match. The version of the PHP from the old machine is before the setup script was included. I know very little about PHP. I am looking for input on the proper way to link the old PHP files to my mysql instance. Any help, much appreciated.

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  • PHP Runs Very Slow on IIS7. Need Help optimizing our config

    - by Kendor
    Am running a PHP based web app on our Windows 2008 cloud-based server. The app, which runs fine outside of our environment (e.g. a different IIS server), but is VERY slow in our environment. Based on googling this is a relatively common situation. I installed PHP and MySQL via the IIS web deployment method... Here's our setup: Windows 2008 Server Enterprise SP2 (32-bit) Microsoft-IIS/7.0 MySQL client version: mysqlnd 5.0.8-dev - 20102224 $Revision: 321634 $ PHP extension: mysqli Update for IIS 7.0 FastCGI Windows Cache Extension 1.1 for PHP 5.3 I had read elsewhere that ipv6 might be an issue, so I turned this off on the network adapter. The app is using: localhost as its connection Be easy on me, as I'm a bit green about some of these components... Also, rewriting the PHP app or modifying it is NOT an option. I'm reasonably SURE that our config is the issue.

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  • Force ID of user created by apt-get

    - by Bart van Heukelom
    Context: I'm automatically installing postgresql-9.1 on an Ubuntu server with apt-get. This creates the required postgres user. The Postgres data is on an external volume that survives reinstalls. This data is obviously owned by the postgres user. The problem I'm having is that the ownership is not recorded under the name postgres, but under the UID that postgres had at creation time. When the server is reinstalled, postgres sometimes gets a different UID, and no longer owns the data directory, and thus does not work. Question: Can I force the UID of the user postgres created by apt-get to something fixed? Or is there another way to solve my problem? (As you may have deduced, this is on Amazon EC2 with the data on an EBS volume)

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  • any security tips for my first server? (complete beginner)

    - by Haroldo
    I'm paying for a VPS and hoping to launch my first website on it in the next few days. I'm worried there might be some glaringly obvious security holes in the standard setup, so I'm keen to get some tips About the only thing i know is turn off error reporting in PHP and create users/privilages for MySQL... any more stuff along those lines? I'm using: cpanel and WHM centos 5 php mysql google apps as mail server (so maybe i should disable built in mailer server somehow?!!) This is my first post of Server Fault (i use stack overflow alot), I hope i'm posting this in the right place, with the right tags - please feel free to edit if i'm wrong. Thanks guys!

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  • Is it safe to use up all memory on linux server, not leaving anything for the cache?

    - by Temnovit
    I have a CentOS server fully dedicated to MySQL 5.5 (with innodb tables mostly). Server has 32 GB RAM, SSD disks, and avarage memory usage looks like this: So about 25GB is in use and about 6.5GB is cached. I am experiencing performance problems with WRITE queries, so I was thinking, is this the optimal cache size? I might increase innodb buffer size, so that linux cache would become smaller, or decrease it, so it would be bigger. What is the optimal used/cached memory balance for busy MySQL server on linux?

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  • Do all domains on the same shared hosting server have the same IP or ID

    - by silow
    Here's what I've got: siteA.com and siteB.com are hosted on hostgator. They're hosted on the same account of a shared hosting server (not VPS or dedicated). script.php is an external site that each of these 2 sites are accessing. I noticed that when siteA.com or siteB.com access the outside script.php, the script identifies them both as 1a.12.12ab.static.theplanet.com (apparently because hostgator uses theplanet.com servers). The fact that they're identified as the same value isn't surprising because after all they're hosted on the same account /home/user123/public_html. What I'm wondering about is how about other websites that are hosted on the same shared hosting server, but under other accounts. Basically other websites that are under another developer's control, but just happen to share the same hardware (hosting server). Do they also have the exact same identifier 1a.12.12ab.static.theplanet.com or that changes by account?

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  • mysqldump and wamp

    - by Adam
    I am running a wamp server and trying to use mysqldump to backup a mysql database I have. The following is the PHP code I am using to run mysqldump. exec("mysqldump backup -u$user -p$pass > $sql_file"); When I run the script the page just loads inifnately and the backup is not created. A blank file is being created so I know something is happening. Extra info: exec() is not disabled PHP is not running in safe mode Any ideas?? Win XP, WAMP, MYSQL 5.0.51b

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  • Server format & Reinstall while keeping Server & domain ID

    - by Chris
    Hi Everyone, I want to reinstall my 2008 R2 server from scratch, due to multiple Active Dir issues. I have only 1 server running AD and a spare machine to use if necessary. Is there a way to save just the user accounts and the domain SID, so that I can start with a clean server that uses the same name as before? I can reassign file security, but I do not want to have to rejoin all the users to a new domain. Also all users are mapped to folders on the server. What I hope to do is a clean install of the server without having to mess with the users machines. can someone please tell me the procedure to accomplish this? any help appreciated! Thanks guys, but I could be here all day telling you every error I am getting. can we please keep this to the question of how to do a reinstall and keep the same SID? I just want to start over without having to rejoin all the clients to a new domain. Is there such a tool that can backup the Server SID and the AD domain name so that I could restore them, without restoring any other data? I might not be using the correct terminology here, but hopefully you understand what I am asking. Thanks

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  • audiable caller id on windows mobile

    - by doug
    on my phone device which runs with windows mobile, I'll like to have an application which says the name of the caller, when i get a new call. I know that nokia has such an application. Do you know such an application for windows mobile?

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  • PHP and MySQL on IIS7: can't find php_mcrypt.dll in php.ini

    - by user46250
    I have installed PHP with Microsoft Web PI. Then I installed mysql. According to http://learn.iis.net/page.aspx/353/install-and-configure-mysql-for-php-applications-on-iis-7/ I have to Uncomment the following lines by removing the semicolon: extension=php_mysqli.dll extension=php_mbstring.dll extension=php_mcrypt.dll But there is no extension=php_mcrypt.dll in php.ini installed by web PI so should I add it by hand then where ? and where should I check that php_mcrypt.dll exists ? Seems nobody knows, should better ask on Microsoft forum ?

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  • Can't access phpMyAdmin because of host, username and password

    - by Engprof
    everyone. When I try to access phpMyAdmin on Uniform Server I get the following error messages: " #1045 - Access denied for user 'root'@'localhost' (using password: YES) " " phpMyAdmin tried to connect to the MySQL server, and the server rejected the connection. You should check the host, username and password in your configuration and make sure that they correspond to the information given by the administrator of the MySQL server. " The funny thing is my username and password are both set to "root" and I have changed the IP address in the httpd.conf file to my Unique IP adddress, so I still don't know what the problem is. Could somebody please help me out? Any help would be much appreciated.

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  • Should we regularly schedule mysqlcheck (or databsae optimization)

    - by scatteredbomb
    We run a forum with some 2 million posts and I've noticed that if left untouched the overhead in the mySQL (as listed in phpMyAdmin) can get quite large (hundreds of megabytes). I'm wondering if scheduling a normal mysqlcheck to optimize the tables is good practice? Any reason not to do it, say, once a week at an off-peak hour? There was a time over the summer where our site was constantly crashing because mysql was using up all resources. That's when I noticed the huge amount of overhead and optimized the database and haven't had any problems since then with stability. I figured if that was helping alleviate the issues, I should just setup a cron to automatically do this.

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  • How to copy a file to a remote server using the command line?

    - by cool_cs
    I am trying to copy a file from my desktop to my remote server using the sudo command. I am doing this from the remote machine since I know the password for this machine and I do not have a password for my local machine. sudo scp donj@localhost:/Desktop/my.cnf user@remotemachine:/app/MySQL/my.cnf This does not work however. I want to overwrite the my.cnf file in the MySQL directory. I tried the su command but I do not have the password to become a super user.

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  • Access denied for user 'root@localhost' (using password:NO)

    - by murgatroid99
    I am attempting to install a network management package called cacti onto Ubuntu running under Windows Virtual PC. I attempted to install MySQL as it is one of cacti's dependencies. I can install and start the MySQL server, but whenever I try to access it in any other way, such as to change the password, I get the error message Access denied for user 'root@localhost' (using password:NO). I would like to know what is causing this and how to fix it. Edit: (just in case my comments are not visible) The answers from HD and Devin Ceartas did not work for me.

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  • Upgrading Fedora to Current Version - Dependent Applications Concerns

    - by nicorellius
    Is it possible to upgrade to Fedora 11 and still keep the server functional (it's running Fedora Core release 6 now, with MySQL 5.0, PHP 5.1 and Apache 2.2)? I have a Customer Relationship Management system on there and it is required on a daily basis. I am trying to figure out if I should upgrade (and whether that will cause huge problems) or if I should start over with a new OS (like Ubuntu) and install the CRM fresh, with updated version of MySQL, PHP, Apache, etc. I ask because I am not really the sysadmin, but have but put in charge of this server.

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  • Access denied for user 'root@localhost' (using password:NO)

    - by murgatroid99
    I am attempting to install a network management package called cacti onto Ubuntu running under Windows Virtual PC. I attempted to install MySQL as it is one of cacti's dependencies. I can install and start the MySQL server, but whenever I try to access it in any other way, such as to change the password, I get the error message Access denied for user 'root@localhost' (using password:NO). I would like to know what is causing this and how to fix it. Edit: (just in case my comments are not visible) The answers from HD and Devin Ceartas did not work for me.

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  • ID Badge Access System for Building with Active Directory Integration [closed]

    - by Alex
    I hope this is the right place for this question. So, we're looking into setting up a building access that uses badges or cards of some kind. I wanted to ask the users on here if they've had to do such setups and/or if they have recommendations? Is there maybe a system that integrates with Active Directory? I know one of the things our managers want to do is to be able to run reports on when people are entering the buildings. I'd appreciate any suggestions and thanks in advance!

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  • Need help with Android TableLayout alignment

    - by Ben L.
    I'm trying to build a calculator layout using TableLayout, but the last two rows aren't aligning with the rest of the layout. Is there something wrong with my layout XML? What I'm trying to do would be easier to accomplish in HTML (<td> with colspan or rowspan), so should I try converting this into a WebView? Code is as follows: (Screenshot) <?xml version="1.0" encoding="utf-8"?> <LinearLayout xmlns:android="http://schemas.android.com/apk/res/android" android:orientation="vertical" android:layout_width="fill_parent" android:layout_height="fill_parent"> <EditText android:id="@+id/EditText01" android:layout_height="wrap_content" android:layout_width="fill_parent" /> <TableLayout android:layout_height="fill_parent" android:layout_width="fill_parent" android:stretchColumns="*"> <TableRow android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="1"> <Button android:id="@+id/Button08" android:textSize="16pt" android:text="^" android:layout_weight="1" android:layout_height="fill_parent" android:layout_width="wrap_content" /> <Button android:id="@+id/Button09" android:text="÷" android:textSize="16pt" android:layout_height="fill_parent" android:layout_weight="1" android:layout_width="wrap_content" /> <Button android:id="@+id/Button10" android:text="×" android:textSize="16pt" android:layout_height="fill_parent" android:layout_weight="1" android:layout_width="wrap_content" /> <Button android:id="@+id/Button11" android:textSize="16pt" android:text="-" android:layout_weight="1" android:layout_height="fill_parent" android:layout_width="wrap_content" /> </TableRow> <TableRow android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="2"> <LinearLayout android:layout_width="wrap_content" android:layout_height="fill_parent" android:orientation="vertical" android:layout_weight="1"> <Button android:id="@+id/Button01" android:text="7" android:textSize="16pt" android:layout_weight="1" android:layout_height="wrap_content" android:layout_width="fill_parent" /> <Button android:layout_height="wrap_content" android:textSize="16pt" android:text="4" android:id="@+id/Button05" android:layout_weight="1" android:layout_width="fill_parent" /> </LinearLayout> <LinearLayout android:layout_height="fill_parent" android:orientation="vertical" android:layout_weight="1" android:layout_width="fill_parent"> <Button android:id="@+id/Button02" android:layout_height="wrap_content" android:text="8" android:textSize="16pt" android:layout_weight="1" android:layout_width="fill_parent" /> <Button android:layout_height="wrap_content" android:textSize="16pt" android:text="5" android:id="@+id/Button06" android:layout_weight="1" android:layout_width="fill_parent" /> </LinearLayout> <LinearLayout android:layout_height="fill_parent" android:orientation="vertical" android:layout_weight="1" android:layout_width="fill_parent"> <Button android:id="@+id/Button03" android:text="9" android:textSize="16pt" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1" /> <Button android:textSize="16pt" android:text="6" android:id="@+id/Button07" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1" /> </LinearLayout> <Button android:id="@+id/Button04" android:text="+" android:textSize="16pt" android:layout_height="fill_parent" android:layout_width="fill_parent" android:layout_weight="1" /> </TableRow> <TableRow android:layout_width="fill_parent" android:layout_height="fill_parent" android:layout_weight="2"> <LinearLayout android:layout_width="wrap_content" android:layout_height="fill_parent" android:orientation="vertical" android:layout_weight="2"> <LinearLayout android:layout_weight="1" android:orientation="horizontal" android:layout_width="fill_parent" android:layout_height="wrap_content"> <Button android:id="@+id/Button02" android:textSize="16pt" android:layout_weight="1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="1" /> <Button android:textSize="16pt" android:id="@+id/Button06" android:layout_weight="1" android:layout_width="fill_parent" android:layout_height="fill_parent" android:text="2" /> </LinearLayout> <Button android:id="@+id/Button01" android:layout_height="wrap_content" android:textSize="16pt" android:layout_weight="1" android:layout_width="fill_parent" android:text="0" /> </LinearLayout> <LinearLayout android:layout_width="wrap_content" android:layout_height="fill_parent" android:orientation="vertical" android:layout_weight="1"> <Button android:id="@+id/Button03" android:textSize="16pt" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1" android:text="3" /> <Button android:textSize="16pt" android:id="@+id/Button07" android:layout_width="fill_parent" android:layout_height="wrap_content" android:layout_weight="1" android:text="." /> </LinearLayout> <Button android:id="@+id/Button04" android:textSize="16pt" android:layout_height="fill_parent" android:layout_width="fill_parent" android:layout_weight="1" android:text="=" /> </TableRow> </TableLayout> </LinearLayout>

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  • SQL Stored Queries - use result of query as boolean based on existence of records

    - by Christian Mann
    Just getting into SQL stored queries right now... anyway, here's my database schema (simplified for YOUR convenience): member ------ id INT PK board ------ id INT PK officer ------ id INT PK If you're into OOP, Officer Inherits Board Inherits Member. In other words, if someone is listed on the officer table, s/he is listed on the board table and the member table. I want to find out the highest privilege level someone has. So far my SP looks like this: DELIMITER // CREATE PROCEDURE GetAuthLevel(IN targetID MEDIUMINT) BEGIN IF SELECT `id` FROM `member` WHERE `id` = targetID; THEN IF SELECT `id` FROM `board` WHERE `id` = targetID; THEN IF SELECT `id` FROM `officer` WHERE `id` = targetID; THEN RETURN 3; /*officer*/ ELSE RETURN 2; /*board member*/ ELSE RETURN 1; /*general member*/ ELSE RETURN 0; /*not a member*/ END // DELIMITER ; The exact text of the error is #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'SELECT id FROM member WHERE id = targetID; THEN IF SEL' at line 4 I suspect the issue is in the arguments for the IF blocks. What I want to do is return true if the result-set is at least one -- i.e. the id was found in the table. Do any of you guys see anything to do here, or should I reconsider my database design into this:? person ------ id INT PK level SMALLINT

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  • Movies recommendation engine conceptual database design

    - by Supyxy
    I am working at an movie recommendations engine and i'm facing a DB design issue. My actual database looks like this: MOVIES [ID,TITLE] KEYWORDS_TABLE [ID,KEY_ID] - where ID is Foreign Key for MOVIES.id and KEY_ID is a key for a text keywords table This is not the entire DB, but i showed here what's important for my problem. I have about 50,000 movies and about 1,3 milion keywords correlations, and basically my algorithm consists in extracting all the who have the same keywords with a given movie, then ordering them by the number of keywords correlations. For example i looked for a movie similar to 'Cast away' and it returned 'Six days and six nights' because it had the most keywords correlations (4 keywords): Island Airplane crash Stranded Pilot The algorithm is based on more factors, but this one is the most important and the most difficult for the approach. Basically what i do now is getting all the movies that have at least one keyword similar to the given movie and then ordering them by other factors which are not important for a moment. There wouldn't be any problem if there weren't so many records, a query lasts in many cases up to 10-20 seconds and some of them return even over 5000 movies. Someone already helped me on here (thanks Mark Byers) with optimizing the query but that's not enough because it takes too longer SELECT DISTINCT M.title FROM keywords_table K1 JOIN keywords_table K2 ON K2.key_id = K1.key_id JOIN movies M ON K2.id = M.id WHERE K1.id = 4 So i thought it would be better if i pre-made those lists with movies recommendations for each movie, but i'm not sure how to design the tables.. whatever is it a good idea or how would you take this approach?

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  • Select * from 'many to many' SQL relationship

    - by Rampant Creative Group
    I'm still learning SQL and my brain is having a hard time with this one. Say I have 3 tables: teams players and teams_players as my link table All I want to do is run a query to get each team and the players on them. I tried this: SELECT * FROM teams INNER JOIN teams_players ON teams.id = teams_players.team_id INNER JOIN players ON teams_players.player_id = players.id But it returned a separate row for each player on each team. Is JOIN the right way to do it or should I be doing something else? ----------------------------------------- Edit Ok, so from what I'm hearing, this isn't necessarily a bad way to do it. I'll just have to group the data by team while I'm doing my loop. I have not yet tried the modified SQL statements provided, but I will today and get back to you. To answer the question about structure - I guess I wasn't thinking about the returned row structure which is part of what lead to my confusion. In this particular case, each team is limited to 4 players (or less) so I guess the structure that would be helpful to me is something like the following: teams.id, teams.name, players.id, players.name, players.id, players.name, players.id, players.name, players.id, players.name, 1 Team ABC 1 Jim 2 Bob 3 Ned 4 Roy 2 Team XYZ 2 Bob 3 Ned 5 Ralph 6 Tom

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  • Hibernate N+1 from select across multiple tables

    - by Marty Pitt
    Given the following hibernate query: String sql = "select distinct changeset " + "from Changeset changeset " + "join fetch changeset.changeEntries as changeEntry " + "join fetch changeEntry.repositoryEntity as repositoryEntity " + "join fetch repositoryEntity.project as project " + "join fetch changeset.author as changesetAuthor " + "where project.id = :projectID "; Why is this resulting in an N+1 problem? I expect this to generate the following single SQL statement (or something similar) select * from Changeset inner join changeEntry on changeset.id = changeEntry.changeset_id inner join repositoryEntity on changeEntry.repositoryentity_id = repositoryentity.id inner join project on repositoryentity.project_id = project.id where project.id = ? Instead, I see many many select statements firing. The data model here looks like this: I would like the full object graph returned from the Select statement in a single trip to the database, which is why I'm explicitly using "fetch" in the hibernate query. The Hibernate log statements are as follows: Hibernate: select distinct changeset0_.id as id2_0_, changeentr1_.id as id1_1_, repository2_.id as id9_2_, project3_.id as id6_3_, user4_.id as id7_4_, changeset0_.author_id as author5_2_0_, changeset0_.createDate as createDate2_0_, changeset0_.message as message2_0_, changeset0_.revision as revision2_0_, changeentr1_.changeType as changeType1_1_, changeentr1_.changeset_id as changeset4_1_1_, changeentr1_.diff as diff1_1_, changeentr1_.repositoryEntity_id as reposito5_1_1_, changeentr1_.repositoryEntityVersion_id as reposito6_1_1_, changeentr1_.sourceChangeEntry_id as sourceCh7_1_1_, changeentr1_.changeset_id as changeset4_0__, changeentr1_.id as id0__, repository2_.project_id as connecti6_9_2_, repository2_.name as name9_2_, repository2_.parent_id as parent7_9_2_, repository2_.path as path9_2_, repository2_.state as state9_2_, repository2_.type as type9_2_, project3_.projectName as connecti2_6_3_, project3_.driverName as driverName6_3_, project3_.isAnonymous as isAnonym4_6_3_, project3_.lastUpdatedRevision as lastUpda5_6_3_, project3_.password as password6_3_, project3_.url as url6_3_, project3_.username as username6_3_, user4_.username as username7_4_, user4_.email as email7_4_, user4_.name as name7_4_, user4_.password as password7_4_, user4_.principles as principles7_4_, user4_.userType as userType7_4_ from Changeset changeset0_ inner join ChangeEntry changeentr1_ on changeset0_.id=changeentr1_.changeset_id inner join RepositoryEntity repository2_ on changeentr1_.repositoryEntity_id=repository2_.id inner join project project3_ on repository2_.project_id=project3_.id inner join users user4_ on changeset0_.author_id=user4_.id where project3_.id=? order by changeset0_.revision desc Hibernate: select repository0_.id as id10_9_, repository0_.changeEntry_id as changeEn2_10_9_, repository0_.repositoryEntity_id as reposito3_10_9_, changeentr1_.id as id1_0_, changeentr1_.changeType as changeType1_0_, changeentr1_.changeset_id as changeset4_1_0_, changeentr1_.diff as diff1_0_, changeentr1_.repositoryEntity_id as reposito5_1_0_, changeentr1_.repositoryEntityVersion_id as reposito6_1_0_, changeentr1_.sourceChangeEntry_id as sourceCh7_1_0_, changeset2_.id as id2_1_, changeset2_.author_id as author5_2_1_, changeset2_.createDate as createDate2_1_, changeset2_.message as message2_1_, changeset2_.revision as revision2_1_, user3_.id as id7_2_, user3_.username as username7_2_, user3_.email as email7_2_, user3_.name as name7_2_, user3_.password as password7_2_, user3_.principles as principles7_2_, user3_.userType as userType7_2_, repository4_.id as id9_3_, repository4_.project_id as connecti6_9_3_, repository4_.name as name9_3_, repository4_.parent_id as parent7_9_3_, repository4_.path as path9_3_, repository4_.state as state9_3_, repository4_.type as type9_3_, project5_.id as id6_4_, project5_.projectName as connecti2_6_4_, project5_.driverName as driverName6_4_, project5_.isAnonymous as isAnonym4_6_4_, project5_.lastUpdatedRevision as lastUpda5_6_4_, project5_.password as password6_4_, project5_.url as url6_4_, project5_.username as username6_4_, repository6_.id as id9_5_, repository6_.project_id as connecti6_9_5_, repository6_.name as name9_5_, repository6_.parent_id as parent7_9_5_, repository6_.path as path9_5_, repository6_.state as state9_5_, repository6_.type as type9_5_, repository7_.id as id10_6_, repository7_.changeEntry_id as changeEn2_10_6_, repository7_.repositoryEntity_id as reposito3_10_6_, repository8_.id as id9_7_, repository8_.project_id as connecti6_9_7_, repository8_.name as name9_7_, repository8_.parent_id as parent7_9_7_, repository8_.path as path9_7_, repository8_.state as state9_7_, repository8_.type as type9_7_, changeentr9_.id as id1_8_, changeentr9_.changeType as changeType1_8_, changeentr9_.changeset_id as changeset4_1_8_, changeentr9_.diff as diff1_8_, changeentr9_.repositoryEntity_id as reposito5_1_8_, changeentr9_.repositoryEntityVersion_id as reposito6_1_8_, changeentr9_.sourceChangeEntry_id as sourceCh7_1_8_ from RepositoryEntityVersion repository0_ left outer join ChangeEntry changeentr1_ on repository0_.changeEntry_id=changeentr1_.id left outer join Changeset changeset2_ on changeentr1_.changeset_id=changeset2_.id left outer join users user3_ on changeset2_.author_id=user3_.id left outer join RepositoryEntity repository4_ on changeentr1_.repositoryEntity_id=repository4_.id left outer join project project5_ on repository4_.project_id=project5_.id left outer join RepositoryEntity repository6_ on repository4_.parent_id=repository6_.id left outer join RepositoryEntityVersion repository7_ on changeentr1_.repositoryEntityVersion_id=repository7_.id left outer join RepositoryEntity repository8_ on repository7_.repositoryEntity_id=repository8_.id left outer join ChangeEntry changeentr9_ on changeentr1_.sourceChangeEntry_id=changeentr9_.id where repository0_.id=? The 2nd one is repeated many times - for a result set of 17 objects, the 2nd statement executed 521 times. I suspect this is as a result of the parent/child relationship in the RepositoryEntity object. For the purposes of this select, I actually only require the parent object fetched. Any suggestions?

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  • INSERT INTO in MS Access 2010 SOMETIMES GETS ERROR: 3073 Operation must use an updateable query

    - by Gary
    I get the ERROR: 3073 Operation must use an updateable query SOMETIMES, while performing an INSERT statment. I have no problem on my windows 7 PC, but the person I am writing this for sometimes gets the error. She also has MS Access 2010 on Windows 7. As I said I have never got it on my PC, and she only gets it sometimes. The code will insert a number of rows and then through the error, and other times not through the erro at all. The error occurs if I have the code and data in one .mdb file or seperate files. Here a snippet of code: OrderHdrInsertStmnt = " INSERT INTO ORDER_HDR " _ & "(ORDER_ID, SOURCE_CODE, ORDER_DATE, SHIP_FNAME, SHIP_LNAME, SHIP_EMAIL, SHIP_COMP, SHIP_PHONE, SHIP_ADDR, SHIP_CITY, SHIP_STATE, SHIP_ZIP, SHIP_CNTRY, " _ & " BILL_FNAME, BILL_LNAME, BILL_EMAIL, BILL_COMP, BILL_PHONE, BILL_ADDR, BILL_CITY, BILL_STATE, BILL_ZIP, BILL_CNTRY, " _ & " TAX, SHIPPING, TOTAL, MOD_DATE, INSERT_DATE) " _ & " VALUES (" _ & "'" & OrderId & "','" & SourceCode & "','" & Orderdate & "','" & ShipFName & "','" & ShipLName & "','" & ShipEmail & "','" & ShipComp & "','" & ShipPhone & "','" & ShipAddr & "','" & ShipCity & "','" & ShipState & "','" & ShipZip & "','" & ShipCntry _ & "','" & BillFName & "','" & BillLName & "','" & BillEmail & "','" & BillComp & "','" & BillPhone & "','" & BillAddr & "','" & BillCity & "','" & BillState & "','" & BillZip & "','" & BillCntry _ & "','" & OrderTax & "','" & OrderShipping & "','" & OrderTotal & "','" & ImportDate & "','" & ImportDate & "');" then I use dbsCurrent.Execute OrderHdrInsertStmnt, dbFailOnError Any assistance would be great!

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  • Excessive use of Inner Join for more than 3 tables

    - by Archangel08
    Good Day, I have 4 tables on my DB (not the actual name but almost similar) which are the ff: employee,education,employment_history,referrence employee_id is the name of the foreign key from employee table. Here's the example (not actual) data: **Employee** ID Name Birthday Gender Email 1 John Smith 08-15-2014 Male [email protected] 2 Jane Doe 00-00-0000 Female [email protected] 3 John Doe 00-00-0000 Male [email protected] **Education** Employee_ID Primary Secondary Vocation 1 Westside School Westshore H.S SouthernBay College 2 Eastside School Eastshore H.S NorthernBay College 3 Northern School SouthernShore H.S WesternBay College **Employment_History** Employee_ID WorkOne StartDate Enddate 1 StarBean Cafe 12-31-2012 01-01-2013 2 Coffebucks Cafe 11-01-2012 11-02-2012 3 Latte Cafe 01-02-2013 04-05-2013 Referrence Employee_ID ReferrenceOne Address Contact 1 Abraham Lincoln Lincoln Memorial 0000000000 2 Frankie N. Stein Thunder St. 0000000000 3 Peter D. Pan Neverland Ave. 0000000000 NOTE: I've only included few columns though the rest are part of the query. And below are the codes I've been working on for 3 consecutive days: $sql=mysql_query("SELECT emp.id,emp.name,emp.birthday,emp.pob,emp.gender,emp.civil,emp.email,emp.contact,emp.address,emp.paddress,emp.citizenship,educ.employee_id,educ.elementary,educ.egrad,educ.highschool,educ.hgrad,educ.vocational,educ.vgrad,ems.employee_id,ems.workOne,ems.estartDate,ems.eendDate,ems.workTwo,ems.wstartDate,ems.wendDate,ems.workThree,ems.hstartDate,ems.hendDate FROM employee AS emp INNER JOIN education AS educ ON educ.employee_id='emp.id' INNER JOIN employment_history AS ems ON ems.employee_id='emp.id' INNER JOIN referrence AS ref ON ref.employee_id='emp.id' WHERE emp.id='$id'"); Is it okay to use INNER JOIN this way? Or should I modify my query to get the results that I wanted? I've also tried to use LEFT JOIN but still it doesn't return anything .I didn't know where did I go wrong. You see, as I have thought, I've been using the INNER JOIN in correct manner, (since it was placed before the WHILE CLAUSE). So I couldn't think of what could've possible went wrong. Do you guys have a suggestion? Thanks in advance.

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