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  • PHP Header redirection problem within page called by cURL

    - by Das123
    I have a site that uses cURL to access some pages, stores the returned results in variables, and then uses these variables within its own page. The script works well except where the target cURL page has a header('Location: ...') command inside it. It seems to just ignore this header command. The cURL command is as follows... //Load result page into variable so portions can be allocated to correct variables $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, $url); # URL to post to curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1 ); # return into a variable curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_POST, true); curl_setopt($ch, CURLOPT_POSTFIELDS, $postfields); $loaded_result = curl_exec( $ch ); # run! curl_close($ch); I've tried changing the CURLOPT_HEADER to 1 but it doesn't do anything. So how can I allow script redirection within the target urls using cURL to grab the results? By the way, the pages work fine if accessed other than via cURL but iFrames are not an option in this instance.

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  • Referral System PHP

    - by Liam
    I have a membership based website and im planning on implementing a referral system. My website is credit based, the idea is that if User X refers User Y, then User X gets 100 bonus credits. Has anybody built a referral system before and if so what obstacles should I bear in mind? I've had a snoop round SO tonight but couldn't find any suitable answers. My theory is to give each user a random string which is generated and stored in the DB when they sign up, The user will then be presented with a URL incl. that string which when they pass to somebody (User Z), User Z is then sent to a page, the page then uses the GET method to gather the Random string and update the DB Row they currently occupy, does this sound feasible or could it easily be breached? Thanks

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  • Fighing system in Php & MYSQL

    - by Gully
    I am working on a game like Mafia Wars and i am trying to get the fighting system working but i keep getting lose trying to work out who is going to win the fight and it still needs to know if the stats are close then there is a random chace of them winning. $strength = $my_strength; $otherplayerinfo = mysql_query("SELECT * FROM accounts WHERE id='$player_id'"); $playerinfo = mysql_fetch_array($otherplayerinfo); $players_strength = $playerinfo['stre']; $players_speed = $playerinfo['speed']; $players_def = $playerinfo['def']; if($players_strength > $strength){ $strength_point_player = 1; $strength_point_your = 0; }else{ $strength_point_your = 1; $strength_point_player = 0; } I was trying a point system but i still could not do it.

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  • PHP Count the lenght of each value in a array/string (tags)

    - by 2by
    Users writing an article have the option to write some tags, tags are written like this: tag1, tag2, tag3 So tags are stored like: $tags = "tag1, tag2, tag3"; I want to make sure, every tag has a minimum of 3 characters, so i need to validate the tags. I have tried this: $tagsstring = explode(",", $tags); $tagslength = array_map('strlen', $tagsstring); if (min($tagslength) < 3) { echo "Error... Each tag has to be at least 3 characters."; } It seems to work, sometimes... But of you write: tag1, df It wont give an error. Any suggestions?

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  • Help with PHP MySQL join

    - by kester martinez
    Please help me to understand proper join syntax. I have table named inventory which has: trans_id trans_items items -> item_id trans_user employees -> person_id trans_date trans_comment trans_inventory As you can see above, trans_items is a foreign key in items table, and trans_user is a foreign key in employees table. Now what I want to do is to display in HTML the inventory table, but instead of displaying the item id, I want the ITEM NAME to be displayed. Here is what I have done. Please note I'm using CodeIgniter. public function getData(array $inputs) { $this->db->select('trans_items, trans_user, trans_date, trans_inventory, trans_comment'); $this->db->from('inventory'); $this->db->order_by('trans_date desc'); return $this->db->get()->result_array(); }

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  • PHP / Windows - Opendir() fails opening subdirectories within symbolic linked directories

    - by John Himmelman
    Does anyone know a solution to this problem? I'm unable to open a subdirectory within a symboliclink'd directory. I've confirmed that the paths are correct (even copy & pasted the path into explorer, which parsed it fine). This is a strange, annoying, bug :|. Example: C:\folder\symbolic_link\dir1\dir2 - opening dir2 fails. C:\folder\symbolic_link\dir1 - works C:\folder\real_directory\dir1\dir2 - works C:\folder\real_directory\dir1 - works

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  • Error handling approach on PHP

    - by Industrial
    Hi everybody, We have a web server that we're about to launch a number of applications onto. They will all share database and memcached servers, but each application has it's own mySQL database and all memcached keys per application, is prefixed. Possible scenario: If a memcached server in our cluster goes boom, we want someone (operative system admin) to be automatically contacted by email/iphone push notification or in any other appropriate way. If we we're about to install 150 identical applications for our customers on our servers, and a memcached server dies - all 150 applications will individually find this out and contact our system admin, which most certainly is going to think about getting a new job where he or she isn't about to be woken up by getting 150 messages sent 4:15 in the morning. Possible solution: One idea is to set up an external server for error handling that gets a $_POST or cURL request sent, and handles storage of the error message depending on the seriousness of the actual error message. It would of course check upon receiving the error call, that if the same memcached server have already been reported as offline, there would be no need to spam the system admin with additional reminders... The questions: What's a good approach on how to handle errors? How does the big guys in the industry handle this? Thanks!

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  • Sum of a PHP Array

    - by user1879415
    The following code displays the ordered products individual weight: $weightsql = 'select op.products_name, op.products_quantity , p.products_weight from ' . TABLE_ORDERS_PRODUCTS . ' op left join ' . TABLE_PRODUCTS . ' p on op.products_id = p.products_id where op.products_id = '.$pro['products_id']; $weightq = tep_db_query( $weightsql ); while ($weight = tep_db_fetch_array( $weightq )){ if($category_parent_id != 0)$list_items[] = $weight['products_weight'].'&nbsp;&nbsp;&nbsp;'; } This shows the wieght for each of the products ordered. What I am stuck on is instead of showing seperate weights, I need to show a total weight. For example, if the product was ordered three times, and it weighs 7kg, the code at the moment is showing: Product 7.00 7.00 7.00 How would I make it show the total weight, 21kg?

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  • JSON Returning Null in PHP

    - by kira423
    Here is the two scripts I have Script 1: if(sha1($json+$secret) == $_POST['signature']) { $conversion_id = md5(($obj['amount'])); echo "OK"; echo $conversion_id; mysql_query("INSERT INTO completed (`id`,`uid`,`completedid`) VALUES ('','".$obj['uid']."','".$conversion_id."')"); } else { } ?> Script 2: <? $json = $_POST['payload']; $secret = "78f12668216b562a79d46b170dc59f695070e532"; $obj = json_decode($json); if(sha1($json+$secret) == $_POST['signature']) { print "OK"; } else { } ?> The problem here is that it is returning all NULL values. I am not an expert with JSON so I have no idea what is going on here. I really have no way of testing it because the information is coming from an outside website sending information such as this: { payload: { uid: "900af657a65e", amount: 50, adjusted_amount: 25 }, signature: "4dd0f5da77ecaf88628967bbd91d9506" } The site allows me to test the script, but because json_decode is providing NULL values it will not get through the signature block. Is there a way I can test it myself? Or is there a simple error in this script that I may have just looked over?

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  • In PHP + MySQL, How do I join many tables with conditions

    - by Moe
    Hi, I'm trying to get the users full activity throughout the website. I need to Join many tables throughout the database, with that condition that it is one user. What I currently have written is: SELECT * FROM comments AS c JOIN rphotos AS r ON c.userID = r.userID AND c.userID = '$defineUserID'; But What it is returning is everything about the user, but it repeats rows. For instance, for one user he has 6 photos and 5 comments So I expect the join to return 11 rows. Instead it returns 30 results like so: PhotoID = 1; CommentID = 1; PhotoID = 1; CommentID = 2; PhotoID = 1; CommentID = 3; and so on... What am i doing wrong?

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  • Converting a PHP array to class variables.

    - by animuson
    Simple question, how do I convert an associative array to variables in a class? I know there is casting to do an (object) $myarray or whatever it is, but that will create a new stdClass and doesn't help me much. Are there any easy one or two line methods to make each $key => $value pair in my array into a $key = $value variable for my class? I don't find it very logical to use a foreach loop for this, I'd be better off just converting it to a stdClass and storing that in a variable, wouldn't I? class MyClass { var $myvar; // I want variables like this, so they can be references as $this->myvar function __construct($myarray) { // a function to put my array into variables } }

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  • How to pass parameters dynamically in PHP?

    - by user198729
    I need to pass the $route to its inner function,but failed: function compilePath( $route ) { preg_replace( '$:([a-z]+)$i', 'pathOption' , $route['path'] ); function pathOption($matches) { global $route;//fail to get the $route } } I'm using php5.3,is there some feature that can help?

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  • How can use foreach to Loop Through PHP Array

    - by jtom
    How can use foreach loop to loop through the $Result? $Query = mysql_query("SELECT * FROM mytable"); $Result = array( ); while ($Row = mysql_fetch_array ( $Query) ) { $Result [ ] = $Row; } mysql_free_result($Query); print_r ($Result); ? I just have very vague idea: foreach ($Result ) { echo $row[fname] . ' ' . $row[lname] . ' ' $row[email]; } ? Could someone help please?

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  • PHP - Get a specific value in an array

    - by Charles Yeung
    Hi Suppose I have the code below: [taxonomy] => Array ( [118] => stdClass Object ( [tid] => 118 [vid] => 4 [name] => A [description] => [weight] => 4 ) [150] => stdClass Object ( [tid] => 150 [vid] => 5 [name] => B [description] => [weight] => 0 ) ) How can I only get the tid number and exclude others, could someone please give me a suggestion? Thanks you

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  • PHP: Find element with certain property value in array

    - by Svish
    I'm sure there is an easy way to do this, but I can't think of it right now. Is there an array function or something that lets me search through an array and find the item that has a certain property value? For example: $people = array( array( 'name' => 'Alice', 'age' => 25, ), array( 'name' => 'Waldo', 'age' => 89, ), array( 'name' => 'Bob', 'age' => 27, ), ); How can I find and get Waldo?

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  • == and === operators in php

    - by Lizard
    Lets say I have a variable that will always be a string. Now take the code below: if($myVar === "teststring") Note $myVar will always be a string, so my questions is Which is quicker/best, using === (Indentity) or the == (Equality)?

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  • Define 2D array with loops in php

    - by Michael
    I have an array $rows where each element is a row of 15 tab-delimited values. I want to explode $rows into a 2D array $rowData where each row is an array element and each tab-delimited value is assigned to a different array element. I've tried these two methods without success. I know the first one has a coding error but I do not know how to correct it. Any help would be amazing. for ($i=0; $i<count($rows); $i++){ for ($j=0; $j<15; $j++){ $rowData = array([$i] => array (explode(" ", $rows[$j]))); } } foreach ($rows as $value){ $rowData = array( array (explode(" ", $rows[$value]))); }

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  • Display PHP Query Array in the table

    - by Jerry
    Hi all I would like to display my Query from Mysql on the table. However, my data is like this: Array([0]=>data1, [1]=>data2, [2]=>data3,[3]=>data4,[4]=>pic1,[5]=>pic2,[6]=>pic3,[7]=>pic4); I want to display my table as |data1 | data2 |data3 |data4 |pic1 | pic2 |pic3 |pic4 I know how to display the data in the single ling like td or tr but not sure how to do tr and td on the same loop. Any helps? Thanks in advance! while($query=mysql_fetch_array($dataQuery)){ //not sure what to do here. }

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