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• PHP - Resize an image and fill gaps of proportions with a color

  - by Kerry

  I am uploading logos to my system, and they need to fix in a 60x60 pixel box. I have all the code to resize it proportionately, and that's not a problem. My 454x292px image becomes 60x38. The thing is, I need the picture to be 60x60, meaning I want to pad the top and bottom with white each (I can fill the rectangle with the color). The theory is I create a white rectangle, 60x60, then I copy the image and resize it to 60x38 and put it in my white rectangle, starting 11px from the top (which adds up to the 22px of total padding that I need. I would post my code but it's decently long, though I can if requested. Does anyone know how to do this or can you point me to code/tutorial that does this?

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• PHP Extension (memcache|memcached) not showing in phpinfo() but showing in php -m and php -i?

  - by Auston

  I am getting both modules listed as installed / configured when I use: php -m or if I use: php -i but when I use: $m = new Memcache; // or $m = new Memcache(); // or $m = new Memcached(); //or $m = new Memcached; I get the following error: Fatal error: Class 'Memcached' not found I am running on a Mac - OS X (10.5.7) with default install of apache & php. Additionally, I have memcached running as a daemon on 127.0.0.1:11211 and libmemcache as required by the php-memcached library. I have restarted apache tons of times and even done a machine restart. Does anyone know why the modules/extensions show up in the command line but not in my phpinfo()? I am literally stumped, after 3 hours of googling, I am just about ready to give up.

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• PHP curly string syntax question

  - by zildjohn01

  I'm running PHP 5.3.0. I've found that the curly string syntax only works when the first character of the expression is $. Is there a way to include other types of expressions (function calls, etc)? Trivial example: <?php $x = '05'; echo "{$x}"; // works as expected echo "{intval($x)}"; // hoped for "5", got "{intval(05)}"

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• innerJoin query show error

  - by Chithri Ajay

  just i print the two table data so i am using inner join SELECT sd.GameName FROM LottoryTickets AS sd JOIN group AS p ON sd.Group = p.groupname WHERE p.groupname = 11 now i get #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'group AS p ON sd.Group = p.groupname WHERE p.groupname = 11 LIMIT 0, 30' at line 3 this response please guide me thanks for advance.

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• Basic PHP question for Drupal Views theming

  - by oalo

  My PHP and programming knowledge is extremely basic, so this is probably a dumb question: I am theming a View in Drupal 6, and I want to add an id with a consecutive number to each item in the view (first item would have the id #item1, the second #item2, etc). I am customizing the style output (views-view-unformatted--MYVIEWNAME.tpl.php) and the row style output (views-view-fields--MYVIEWNAME.tpl.php), and I want to add a counter variable in the foreach loop in the style output tpl, and then use that variable in the row style output tpl, but the last one is not recognizing the variable. It does not give me any errors, but doesnt print the number. I understand this has probably something to do with variables visibility, how can I declare the counter variable in the style .tpl so I can the use it in the row style .tpl? Thank you

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• How to display configurable product in each color in Magento product listing?

  - by Thomas

  I have a configurable product which is available in many different colors and sizes. I want the configurable product to appear once for every color. My idea is to assign one simple product of the configurable product in every color to the category of the configurable product. Then I want to change the listing, so that the (colored) simple product links to it's master product (the configurable one). The other way would be, to just assign the configurable product to a category and then list it multiple times with different colors. But I think this would be to complicated.

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• Improve performance of website

  - by Vinodtiru

  Hi, I have designed a new web site. I have hosted it online. I want it to be of the best performance and load pages faster. This website is designed in php 5.0+ using codeigniter. This is using mysql as DB. I have images on it. I am using Nitobi grid for displaying set of records on page. The rest is everything normal page controls. As i am not so very experienced with website performance factors i would like to get suggestions and details on factors that can improve performance of website. Please let me know how i can improve my performance. Also please let me know if there are any ways to measure the performance of website and also any websites or tools to help test the performance. Any kind of help is appreciated. Thanks in advance. Thanks and Regards Vinod T.

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• php class scope when calling a non-method function not accessing all class members

  - by Aglystas

  So I'm using a stand alone function from within a class that that uses the class it's being called from. Here's the function function catalogProductLink($product_id,$product_name,$categories=true) { //This is the class that the function is called from global $STATE; if ($categories) { //The $STATE->category_id is the property I want to access, which I can't if (is_array($STATE->category_id)) { foreach($STATE->category_id as $cat_id) { if ($cat_id == 0) continue; $str .= "c$cat_id/"; } } } $str .= catalogUrlKeywords($product_name).'-p'.$product_id.'.html'; return $str; } And here's the function call, which is being made from within the $STATE class. $redirect = catalogProductLink($this->product_id, $tempProd->product_name, true, false); The object that I need access to is the $STATE object that has been declared global. Prior to this function call there are lots of public properties populated, but when I look at the $STATE object within the function scope it loses all the properties but one, product_id. The property that matters for this function is the category_id property, which is an array of category id's. I'm wondering why I don't have access to all the public properties of the $STATE object and how I can get access to them.

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• A PHP object server for business logic

  - by Matthieu

  I wonder if such a thing is possible or even exist : In the MVC pattern, I would like to have the Model part to be persistant in memory, instead of reloading my instances at each execution. So I want only the Controller and View part to be executed. Is there any solution of server that would provide PHP objects (just like a Mysql server provides data records), and that keeps these objects in memory ? A problem would be also : how to have a constructed query to get objects ? Maybe PHP Linq ?

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• Array filteration PHP

  - by Muhammad Sajid

  I have an array with values like: Array ( [0] => Array ( [parent] => Basic [parentId] => 1 [child] => Birthday [childId] => 2 ) [1] => Array ( [parent] => Basic [parentId] => 1 [child] => Gender [childId] => 3 ) [2] => Array ( [parent] => Geo [parentId] => 10 [child] => Current City [childId] => 11 ) [3] => Array ( [parent] => Known me [parentId] => 5 [child] => My personality [childId] => 7 ) [4] => Array ( [parent] => Known me [parentId] => 5 [child] => Best life moment [childId] => 8 ) ) And I want to filter this array such that their filtration based on parent index, and the final result would be like: Array ( [0] => Array ( [parent] => Basic [parentId] => 1 [child] => Array ( [0] => Birthday [1] => Gender ) ) [1] => Array ( [parent] => Geo [parentId] => 10 [child] => Array ( [0] => Current City ) ) [2] => Array ( [parent] => Known me [parentId] => 5 [child] => Array ( [0] => My personality [1] => Best life moment ) ) ) For that I coded : $filter = array(); $f = 0; for ($i=0; $i<count($menuArray); $i++) { $c = 0; for( $b = 0; $b < count($filter); $b++ ){ if( $filter[$b]['parent'] == $menuArray[$i]['parent'] ){ $c++; } } if ($c == 0) { $filter[$f]['parent'] = $menuArray[$i]['parent']; $filter[$f]['parentId'] = $menuArray[$i]['parentId']; $filter[$f]['child'][] = $menuArray[$i]['child']; $f++; } } But it results : Array ( [0] => Array ( [parent] => Basic [parentId] => 1 [child] => Array ( [0] => Birthday ) ) [1] => Array ( [parent] => Geo [parentId] => 10 [child] => Array ( [0] => Current City ) ) [2] => Array ( [parent] => Known me [parentId] => 5 [child] => Array ( [0] => My personality ) ) ) Could anyone point out my missing LOC?

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• PHPIniDir broken under windows 7?

  - by bobbyb

  I had a server running on a windows xp machine using apache2 with php and mysql. I've recently upgraded to windows 7 and have been having trouble getting it to work. Apache works fine and php works, but I can't seem to get it to work with a php.ini file. When I set PHPIniDir to a directory with a php.ini file, the Apache service does NOT start. When I set PHPIniDir to a directory with NO php.ini file, the Apache service does start. When I leave out PHPIniDir, the Apache service does not start. Has anyone found a fix for this problem? Thanks! EDIT: PHPIniDir "C:\Windows" #works (no php.ini file) PHPIniDir "C:\Program Files (x86)\php\" #does not work (contains php.ini file) i enable at most one at any given time.

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• Why am I returning empty records when querying in mysql with php?

  - by Brian Bolton

  I created the following script to query a table and return the first 30 results. The query returns 30 results, but they do not have any text or information. Why would this be? The table stores Vietnamese characters. The database is mysql4. Here's the page: http://saomaidanang.com/recentposts.php Here's the code: <?php header( 'Content-Type: text/html; charset=utf-8' ); //CONNECTION INFO $dbms = 'mysql'; $dbhost = 'xxxxx'; $dbname = 'xxxxxxx'; $dbuser = 'xxxxxxx'; $dbpasswd = 'xxxxxxxxxxxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpasswd ) or die('Error connecting to mysql'); mysql_select_db($dbname , $conn); //QUERY $result = mysql_query("SET NAMES utf8"); $cmd = 'SELECT * FROM `phpbb_posts_text` ORDER BY `phpbb_posts_text`.`post_subject` DESC LIMIT 0, 30 '; $result = mysql_query($cmd); ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html dir="ltr"> <head> <title>recent posts</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> </head> <body> <p> <?php //DISPLAY while ($myrow = mysql_fetch_row($result)) { echo 'post subject:'; echo(utf8_encode($myrow ['post_subject'])); echo 'post text:'; echo(utf8_encode($myrow ['post_text'])); } ?> </p> </body>

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• Php 5 and mysql connecting gives error ...code and error in there check out and plz..plz help....

  - by user309381

  **mysql_query() [function.mysql-query]: Access denied for user 'SYSTEM'@'localhost' (using password: NO) in C:\wamp\www\photo_gallery\includes\database.php on line 56 Warning: mysql_query() [function.mysql-query]: A link to the server could not be established in C:\wamp\www\photo_gallery\includes\database.php on line 56 The Query has problemAccess denied for user 'SYSTEM'@'localhost' (using password: NO) i have set the password for root and grant privilege all for root.Why it soes show like SYSTEM@localhost i dont have SYSTEM .** class MySQLDatabase { public $connection; function _construct() { $this-open_connection(); } public function open_connection() { /* $DB_SERVER = "localhost"; $DB_USER = "root"; $DB_PASS = ""; $DB_NAME = "photo_gallery";*/ $this-connection = mysql_connect($DBSERVER,$DBUSER,$DBPASS); if(!$this-connection) { die("Database Connection Failed" . mysql_error()); } else { $db_select = mysql_select_db($DBNAME,$this-connection); if(!$db_select) { die("Database Selection Failed" . mysql_error()); } } } function mysql_prep($value) { if (get_magic_quotes_gpc()) { $value = stripslashes($value); } // Quote if not a number if (!is_numeric($value)) { $value = "'" . mysql_real_escape_string($value) . "'"; } return $value; } public function close_connection() { if(isset($this->connection)) { mysql_close($this->connection); unset($this->connection); } } public function query($sql) { //$sql = "SELECT*FROM users where id = 1"; $result = mysql_query($sql); $this->confirm_query($result); //$found_user = mysql_fetch_assoc($result); //echo $found_user; return $found_user; } private function confirm_query($result) { if(!$result) { die("The Query has problem" . mysql_error()); } } } $database = new MySQLDatabase(); ?

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• DOM: how to import nodes and give them different namespace prefix

  - by thomasrutter

  I'm familiar with the DOMDocument::importNode method for importing a tree of nodes from some other document element. However, what I was wondering is if I can automatically change the namespace prefix on a tree of nodes as I import them, that is, specify a new prefix for all nodes of that namespace. Say the nodes, in their existing document, all have names like "name", "identity", and so on. When importing them into my new document they will be alongside other namespaces, so I'd like them to appear as "nicnames:name", "nicnames:identity" and so on. I'd like to be able to change this prefix programmatically so that in another context I may be able to import them as, for instance, "myprefix:name", "myprefix:identity" depending on the document they're imported into. Can anyone help me understand how to do this? Thanks

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• Get root node of XML doc using simplexml

  - by John Conde

  Using simplexml_load_string() how do I get "ForgotPassword" from the following XML? <?xml version="1.0" encoding="utf-8"?> <ForgotPassword> <version>1.0</version> <authentication> <login>username</login> <apikey>login</apikey> </authentication> <parameters> <emailAddress>[email protected]</emailAddress> </parameters> </ForgotPassword>

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• php and javascript?

  - by anitabehal

  how to call php variables or queries in javascript?

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• Can PHP Perform Magic Instantiation?

  - by Aiden Bell

  Despite PHP being a pretty poor language and ad-hoc set of libraries ... of which the mix of functions and objects, random argument orders and generally ill-thought out semantics mean constant WTF moments.... ... I will admit, it is quite fun to program in and is fairly ubiquitous. (waiting for Server-side JavaScript to flesh out though) question: Given a class class RandomName extends CommonAppBase {} is there any way to automatically create an instance of any class extending CommonAppBase without explicitly using new? As a rule there will only be one class definition per PHP file. And appending new RandomName() to the end of all files is something I would like to eliminate. The extending class has no constructor; only CommonAppBase's constructor is called. Strange question, but would be nice if anyone knows a solution. Thanks in advance, Aiden (btw, my PHP version is 5.3.2) Please state version restrictions with any answer.

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• How to process XML sernt via POST?

  - by John Conde

  I'm receiving XML sent via POST. Naturally I need to parse this XML to get at the goodies it holds for me. However, when I receive the XML is seems that PHP is parsing it like a query string. For example, this xml: <?xml version="1.0" encoding="utf-8"?> <ForgotPassword> <version>1.0</version> <authentication> <login>myresllerid</login> <apikey>1234567890abcdef</apikey> </authentication> <parameters> <emailAddress>[email protected]</emailAddress> </parameters> </ForgotPassword> Becomes this (from print_r($_REQUEST)): Array ( [ <?xml_version] => "1.0" encoding="utf-8"?> <IDCForgotPassword> <version>1.0</version> <authentication> <login>myresllerid</login> <apikey>1234567890abcdef</apikey> </authentication> <parameters> <emailAddress>[email protected]</emailAddress> </parameters> </IDCForgotPassword> ) You can see the XML is being broken up at the first equals sign (=) in the XML into a key/value pair. How do I avoid this?

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• php code execution time

  - by Bharanikumar

  Hi How to find my code execution time , Am using the below snippet, am not happy with that ? list ($msec, $sec) = explode(' ', microtime()); $microtime = (float)$msec + (float)$sec; Regards

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• a query is inserted from PHPMYAdmin but not from PHP

  - by iyad al aqel

  i'm writing a php code to insert form values in a forum values $dbServer = mysql_connect("localhost" , "root", "") ; if(!$dbServer) die ("Unable to connect"); mysql_select_db("kfumWonder"); $name= $_POST['name'] ; $password= md5($_POST['password']); $email= $_POST['email'] ; $major= $_POST['major'] ; $dateOfBirth=$_POST['dateOfBirth'] ; $webSite = $_POST['website']; $joinDate= date("Y m d") ; $query = "INSERT INTO user (name, password, email, major, dob, website, join_date) Values ('$name', '$password', '$email', '$major', '$dateOfBirth', '$webSite' , '$joinDate')" ; //echo $query ; $result = mysql_query($query) ; if (! $result ) echo " no results " ; this works perfectly fine when i took the printed query and run it in PHPMyAdmin but when i run this code nothing happens , any ideas !?

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• php syntax error

  - by Jacksta

  I have 3 files 1) show_createtable.html 2) do_showfielddef.php 3) do_showtble.php 1) First file is for creating a new table for a data base, it is a fom with 2 inputs, Table Name and Number of Fields. THIS WORKS FINE! <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <h1>Step 1: Name and Number</h1> <form method="post" action="do_showfielddef.php" /> <p><strong>Table Name:</strong><br /> <input type="text" name="table_name" size="30" /></p> <p><strong>Number of fields:</strong><br /> <input type="text" name="num_fields" size="30" /></p> <p><input type="submit" name="submit" value="go to step2" /></p> </form> </body> </html> 2) this script validates fields and createa another form to enter all the table rows. This for also WORKS FINE! <?php //validate important input if ((!$_POST[table_name]) || (!$_POST[num_fields])) { header( "location: show_createtable.html"); exit; } //begin creating form for display $form_block = " <form action=\"do_createtable.php\" method=\"post\"> <input name=\"table_name\" type=\"hidden\" value=\"$_POST[table_name]\"> <table cellspacing=\"5\" cellpadding=\"5\"> <tr> <th>Field Name</th><th>Field Type</th><th>Table Length</th> </tr>"; //count from 0 until you reach the number fo fields for ($i = 0; $i <$_POST[num_fields]; $i++) { $form_block .=" <tr> <td align=center><input type=\"texr\" name=\"field name[]\" size=\"30\"></td> <td align=center> <select name=\"field_type[]\"> <option value=\"char\">char</option> <option value=\"date\">date</option> <option value=\"float\">float</option> <option value=\"int\">int</option> <option value=\"text\">text</option> <option value=\"varchar\">varchar</option> </select> </td> <td align=center><input type=\"text\" name=\"field_length[]\" size=\"5\"> </td> </tr>"; } //finish up the form $form_block .= " <tr> <td align=center colspan=3><input type =\"submit\" value=\"create table\"> </td> </tr> </table> </form>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create a database table: Step 2</title> </head> <body> <h1>defnie fields for <? echo "$_POST[table_name]"; ?> </h1> <? echo "$form_block"; ?> </body> </html> Problem is here 3) this form creates the tables and enteres them into the database. I am getting an error on line 37 "Parse error: syntax error, unexpected $end in /home/admin/domains/domaina.com.au/public_html/do_createtable.php on line 37" <? $db_name = "testDB"; $connection = @mysql_connect("localhost", "admin_user", "pass") or die(mysql_error()); $db = @mysql_select_db($db_name, $connection) or die(mysql_error()); $sql = "CREATE TABLE $_POST[table_name]("; for ($i = 0; $i < count($_POST[field_name]); $i++) { $sql .= $_POST[field_name][$i]." ".$_POST[field_type][$i]; if ($_POST[field_length][$i] !="") { $sql .=" (".$_POST[field_length][$i]."),"; } else { $sql .=","; } $sql = substr($sql, 0, -1); $sql .= ")"; $result = mysql_query($sql, $connection) or die(mysql_error()); if ($result) { $msg = "<p>" .$_POST[table_name]." has been created!</p>"; ?> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Create A Database Table: Step 3</title> </head> <body> <h1>Adding table to <? echo "$db_name"; ?>...</h1> <? echo "$msg"; ?> </body> </html>

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• Cpu usage from top command

  - by kairyu

  How can i get the result like example following. Any command or scripts? Snapshot u1234 3971 1.9 0.0 0 0 ? Z 20:00 0:00 [php] u1234 4243 3.8 0.2 64128 43064 ? D 20:00 0:00 /usr/bin/php /home/u1234/public_html/index.php u1234 4289 5.3 0.2 64128 43064 ? R 20:00 0:00 /usr/bin/php /home/u1234/public_html/index.php u1234 4312 9.8 0.2 64348 43124 ? D 20:01 0:00 /usr/bin/php /home/u1234/public_html/index.php u1235 4368 0.0 0.0 30416 6604 ? R 20:01 0:00 /usr/bin/php /home/u1235/public_html/index.php u1236 4350 2.0 0.0 34884 13284 ? D 20:01 0:00 /usr/bin/php /home/u1236/public_html/index.php u1237 4353 13.3 0.1 51296 30496 ? S 20:01 0:00 /usr/bin/php /home/u1237/public_html/index.php u1238 4362 63.0 0.0 0 0 ? Z 20:01 0:00 [php] u1238 4366 0.0 0.1 51352 30532 ? R 20:01 0:00 /usr/bin/php /home/u1238/public_html/index.php u1239 4082 3.0 0.0 0 0 ? Z 20:00 0:01 [php] u1239 4361 26.0 0.1 49104 28408 ? R 20:01 0:00 /usr/bin/php /home/u1239/public_html/index.php u1240 1980 0.4 0.0 0 0 ? Z 19:58 0:00 [php] CPU TIME = 8459.71999999992 This result i got from hostgator support :) I was used "top -c" but they do not show "/home/u1239/public_html/index.php Thanks

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• PHP - Code Sample - Polymorphism Implementation - How to allow for expansion?

  - by darga33

  I've read numerous SO posts about Polymorphism, and also the other really good one at http://net.tutsplus.com/tutorials/php/understanding-and-applying-polymorphism-in-php/ Good stuff!!! I'm trying to figure out how a seasoned PHP developer that follows all the best practices would accomplish the following. Please be as specific and detailed as possible. I'm sure your answer is going to help a lot of people!!! :-) While learning Polymorphism, I came across a little stumbling block. Inside of the PDFFormatter class, I had to use (instanceof) in order to figure out if some code should be included in the returned data. I am trying to be able to pass in two different kinds of profiles to the formatter. (needs to be able to handle multiple kinds of formatters but display the data specific to the Profile class that is being passed to it). It doesn't look bad now, but imagine 10 more kinds of Profiles!! How would you do this? The best answer would also include the changes you would make. Thanks sooooooo much in advance!!!!! Please PHP only! Thx!!! File 1. FormatterInterface.php interface FormatterInterface { public function format(Profile $Profile); } File 2. PDFFormatter.php class PDFFormatter implements FormatterInterface { public function format(Profile $Profile) { $format = "PDF Format<br /><br />"; $format .= "This is a profile formatted as a PDF.<br />"; $format .= 'Name: ' . $Profile->name . '<br />'; if ($Profile instanceof StudentProfile) { $format .= "Graduation Date: " . $Profile->graduationDate . "<br />"; } $format .= "<br />End of PDF file"; return $format; } } File 3. Profile.php class Profile { public $name; public function __construct($name) { $this->name = $name; } public function format(FormatterInterface $Formatter) { return $Formatter->format($this); } } File 4. StudentProfile.php class StudentProfile extends Profile { public $graduationDate; public function __construct($name, $graduationDate) { $this->name = $name; $this->graduationDate = $graduationDate; } } File 5. index.php //Assuming all files are included...... $StudentProfile = new StudentProfile('Michael Conner', 55, 'Unknown, FL', 'Graduate', '1975', 'Business Management'); $Profile = new Profile('Brandy Smith', 44, 'Houston, TX'); $PDFFormatter = new PDFFormatter(); echo '<hr />'; echo $StudentProfile->format($PDFFormatter); echo '<hr />'; echo $Profile->format($PDFFormatter);

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• ACL implementation

  - by Kirzilla

  First question Please, could you explain me how simpliest ACL could be implemented in MVC. Here is the first approach of using Acl in Controller... <?php class MyController extends Controller { public function myMethod() { //It is just abstract code $acl = new Acl(); $acl->setController('MyController'); $acl->setMethod('myMethod'); $acl->getRole(); if (!$acl->allowed()) die("You're not allowed to do it!"); ... } } ?> It is very bad approach, and it's minus is that we have to add Acl piece of code into each controller's method, but we don't need any additional dependencies! Next approach is to make all controller's methods private and add ACL code into controller's __call method. <?php class MyController extends Controller { private function myMethod() { ... } public function __call($name, $params) { //It is just abstract code $acl = new Acl(); $acl->setController(__CLASS__); $acl->setMethod($name); $acl->getRole(); if (!$acl->allowed()) die("You're not allowed to do it!"); ... } } ?> It is better than previous code, but main minuses are... All controller's methods should be private We have to add ACL code into each controller's __call method. The next approach is to put Acl code into parent Controller, but we still need to keep all child controller's methods private. What is the solution? And what is the best practice? Where should I call Acl functions to decide allow or disallow method to be executed. Second question Second question is about getting role using Acl. Let's imagine that we have guests, users and user's friends. User have restricted access to viewing his profile that only friends can view it. All guests can't view this user's profile. So, here is the logic.. we have to ensure that method being called is profile we have to detect owner of this profile we have to detect is viewer is owner of this profile or no we have to read restriction rules about this profile we have to decide execute or not execute profile method The main question is about detecting owner of profile. We can detect who is owner of profile only executing model's method $model-getOwner(), but Acl do not have access to model. How can we implement this? I hope that my thoughts are clear. Sorry for my English. Thank you.

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• PHP: Prevent chained method from returning?

  - by Industrial

  Hi, I am having some headaches regarding method chaining for a quite simple PHP class that returns a value, which sometimes need to go through a decryption process: $dataset = new Datacontainer; $key = $dataset->get('key'); $key2 = $dataset->get('key')->decrypt(); The get method is where the return lives. So the call to the decrypt method on the second row isn't going to work in its current state. Can I do something to setup the get method to return only when nothing is chained to it, or what would be the best way to re-factor this code?

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