XSLT: replace an integer by a string
- by binogure
I have a little problem.
A node in my XML may contains and integer, and i have to replace this integer by a string.
Each number match with a string.
For example i have:
Integer - String
1 - TODO
2 - IN PROGRESS
3 - DONE
4 - ERROR
5 - ABORTED
Original XML:
<root>
<status>1</status>
</root>
Converted XML:
<root>
<status>TODO</status>
</root>
So i want replace 1 by "TODO", 2 by "IN PROGRESS" ...
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/root/status">
<root>
<status>
<xsl:variable name="text" select="." />
<xsl:choose>
<xsl:when test="contains($text, '1')">
<xsl:value-of select="'TODO'"/>
</xsl:when>
<xsl:otherwise>
<xsl:value-of select="$text"/>
</xsl:otherwise>
</xsl:choose>
</status></root>
</xsl:template>
</xsl:stylesheet>
I'am asking if there is another way to do that.
