Search Results

Search found 32464 results on 1299 pages for 'php cgi'.

Page 313/1299 | < Previous Page | 309 310 311 312 313 314 315 316 317 318 319 320  | Next Page >

  • PDF Viewer for my web - PHP

    - by hjaffer2001
    I am searching for pdf viewer for my web(Open Source). Searched for months and months. Is there any open source to view pdf in my web (without adobe). On the other hand, the documents should be secured. I have done a synopsis with the following urls;(but no use) http://embedit.in/ http://www.vuzit.com/ http://www.ajaxdocumentviewer.com/ http://flexpaper.devaldi.com http://www.icepdf.org/ https://docs.google.com/viewer http://www.snowbound.com/ http://www.mygazines.com http://www.issuu.com/business www.box.net http://viewer.zoho.com/ I want both download and print option for my pdf viewer.

    Read the article

  • String useless character strip - PHP

    - by Zoltan Repas
    Hi! I've got a huge problem. I made a special ID for the things in our webpage. Let's see an example: H0059 - this is the special ID called registration number. The last two chars are the things' id. I'd like to cut off the useless characters, to get the real ID, what means strip the first char, and all the 0s before any other numbers. (Example: L0745 = 745, V1754 = 1754, L0003 = 3, B0141 = 141, P0040 = 40, V8000 = 8000) Please help me in this. I've tried with strreplace and explode but failed :( Thanks for the help.

    Read the article

  • Please explain this php expression "!$variable"

    - by DogBot
    What does an exclamaton mark in front of a variable mean? And how is it being used in this piece of code? EDIT: From the answers so far I suspect that I also should mention that this code is in a function where one of the parameters is $mytype ....would this be a way of checking if $mytype was passed? - Thanks to all of the responders so far. $myclass = null; if ($mytype == null && ($PAGE->pagetype <> 'site-index' && $PAGE->pagetype <>'admin-index')) { return $myclass; } elseif ($mytype == null && ($PAGE->pagetype == 'site-index' || $PAGE->pagetype =='admin-index')) { $myclass = ' active_tree_node'; return $myclass; } elseif (!$mytype == null && ($PAGE->pagetype == 'site-index' || $PAGE->pagetype =='admin-index')) { return $myclass; }`

    Read the article

  • sort associative array PHP

    - by jim smith
    Here's my array, how do I sort it by saleref? Array ( [xml] => Array ( [sale] => Array ( [0] => Array ( [saleref] => 12345 [saleline] => 1 [product] => producta [date] => 19/ 3/10 [manifest] => 0 [qty] => 1 [nextday] => [order_status] => ) [1] => Array ( [saleref] => 12344 [saleline] => 1 [product] => productb [date] => 18/ 3/10 [manifest] => 11892 [qty] => 1 [nextday] => [order_status] => )

    Read the article

  • Partial PHP code refresh

    - by Tom
    Is it possible to refresh only the part of the page? How? the part: if (checkExpiry($member->expires)==true) { print timeLeft($leftts); } else { print "expired"; } I have table which is showing name, email, time until membership ends and I need to refresh 'time until membership ends' every second.

    Read the article

  • Codeigniter PHP - loading a view at an anchor point

    - by James Billings
    I have a form at the bottom of a long page, if a user fills out the form but it doesn't validate the page is reloaded in the typical codeigniter fashion: $this->load->view('template',$data); however because the form is way down at the bottom of the page I need the page to load down there like you do with HTML anchors. Does anyone know how to do this in codeigniter? I can't use the codeigniter redirect(); function because it loses the object and the validation errors are gone. Other frameworks I've used like Yii you can call the redirect function like: $this->redirect(); which solves the problem because you keep the object. I've tried using: $this->index() within the controller which works fine as a redirect but the validation errors are in another method which is where the current page is loaded from: $this->item($labs) but when I use this it get stuck in a loop Any ideas? I've seen this question a lot on the net but no clear answers. I'm researching using codeigniter "flash data" but think it's a bit overkill. cheers.

    Read the article

  • determine from where the function being called in php

    - by Avinash
    I have one function on my code. say its xyz(). This function is being called from different files of my project. Is there any way than I can get from where the function is being called. I want below infromation: File name from where its called. Line number of that file. if call is from inside the function then that function name. Class name Class method name. I know about use of magic constants like FILE and all that. but i don't want to pass all that in function call. like below: xyz('msg',__FILE__,__CLASS__); is there any way that i have to pass just my error related data only. and it will find the above details from where the function is called. let me know if anything is not clear.

    Read the article

  • PHP scope question

    - by Dan
    Hi, I'm trying to look through an array of records (staff members), in this loop, I call a function which returns another array of records (appointments for each staff member). foreach($staffmembers as $staffmember) { $staffmember['appointments'] = get_staffmember_appointments_for_day($staffmember); // print_r($staffmember['appointments'] works fine } This is working OK, however, later on in the script, I need to loop through the records again, this time making use of the appointment arrays, however they are unavailable. foreach ($staffmembers as $staffmember) { //do some other stuff //print_r($staffmember['appointments'] no longer does anything } Normally, I would perform the function from the first loop, within the second, however this loop is already nested within two others, which would cause the same sql query to be run 168 times. Can anyone suggest a workaround? Any advice would be greatly appreciated. Thanks

    Read the article

  • PHP Upload file enhance security

    - by mandril
    Hey.. my question is how to prevent someone upload a virus or some malicious code with the extension you pretend for example i have a pdf file uploader, anyone can upload a binary with pdf camouflage there are lots of programs to do that.

    Read the article

  • curl cookie problem in PHP

    - by safaali
    hi as my client needs, I developed a code to login via cURl. login to www.web1.com and store cookies in cookie.txt go to www.web2.com and browse a page using that cookie.txt no problem with www.web2.com so when i want to do this with www.web3.com, the problem appears. the www.web3.com uses session and cookies itself and I have to gather and use them. it means I should have tow series of cookies, first those from www.web1.com , and second those from www.web3.com , then request the www.web3.com/somepage how I can do that?

    Read the article

  • PHP Changing Class Variables Outside of Class

    - by Jamie Bicknell
    Apologies for the wording on this question, I'm having difficulties explaining what I'm after, but hopefully it makes sense. Let's say I have a class, and I wish to pass a variable through one of it's methods, then I have another method which outputs this variable. That's all fine, but what I'm after is that if I update the variable which was originally passed, and do this outside the class methods, it should be reflected in the class. I've created a very basic example: class Test { private $var = ''; function setVar($input) { $this->var = $input; } function getVar() { echo 'Var = ' . $this->var . '<br />'; } } If I run $test = new Test(); $string = 'Howdy'; $test->setVar($string); $test->getVar(); I get Var = Howdy However, this is the flow I would like: $test = new Test(); $test->setVar($string); $string = 'Hello'; $test->getVar(); $string = 'Goodbye'; $test->getVar(); Expected output to be Var = Hello Var = Goodbye I don't know what the correct naming of this would be, and I've tried using references to the original variable but no luck. I've come across this in the past, with the PDO prepared statements, see Example #2 $stmt = $dbh->prepare("INSERT INTO REGISTRY (name, value) VALUES (?, ?)"); $stmt->bindParam(1, $name); $stmt->bindParam(2, $value); // insert one row $name = 'one'; $value = 1; $stmt->execute(); // insert another row with different values $name = 'two'; $value = 2; $stmt->execute(); I know I can change the variable to public and do the following, but it isn't quite the same as how the PDO class handles it, and I'm really looking to mimic that behaviour. $test = new Test(); $test->setVar($string); $test->var = 'Hello'; $test->getVar(); $test->var = 'Goodbye'; $test->getVar(); Any help, ideas, pointers, or advice would be greatly appreciated, thanks.

    Read the article

  • Upload image using CURL + PHP via remote form

    - by user253530
    I have a few images that i need to upload using an online form. So far here's my code $info = array('test title','1234','virginia','@'.realpath('e:\wamp\www\1.jpg'),'@'.realpath('e:\wamp\www\2.jpg'),'@'.realpath('e:\wamp\www\3.jpg'),'@'.realpath('e:\wamp\www\4.jpg'),'test description'); $post->postAd($url, $info); The $info array is processed in the postAd method and it's being sent as an associative array using a method from a Curl class i have (it has been tested and worked nicely with everything i needed to do so far with curl). The problem is that the data is completed correctly on the form but the images are not uploaded. Can anyone help with advices/code/guidance?

    Read the article

  • Switch two items in associative array PHP

    - by user280381
    Example: $arr = array('apple'='sweet','grapefruit'='bitter','pear'='tasty','banana'='yellow'); I want to switch the positions of grapefruit and pear, so the array will become 'apple'='sweet','pear'='tasty','grapefruit'='bitter','banana'='yellow') I know the keys and values of the elements I want to switch, is there an easy way to do this? Or will it require a loop + creating a new array? Thanks

    Read the article

  • php foreach looping twice

    - by Jack
    Hi, I am trying to loop through some data from my database but it is outputting it twice. $fields = 'field1, field2, field3, field4'; $idFields = 'id_field1, id_field2, id_field3, id_field4'; $tables = 'table1, table2, table3, table4'; $table = explode(', ', $tables); $field = explode(', ', $fields); $id = explode(', ', $idFields); $str = 'Egg'; $i=1; while ($i<4) { $f = $field[$i]; $idd = $id[$i]; $sql = $writeConn->select()->from($table[$i], array($f, $idd))->where($f . " LIKE ?", '%' . $str . '%'); $string = '<a title="' . $str . '" href="' . $currentProductUrl . '">' . $str . '</a>'; $result = $writeConn->fetchAssoc($sql); foreach ($result as $row) { echo 'Success! Found ' . $str . ' in ' . $f . '. ID: ' . $row[$idd] . '.<br>'; } $i++; } Outputting: Success! Found Egg in field3. ID: 5. Success! Found Egg in field3. ID: 5. Could someone please explain why it is looping through both the indexed and associative values? UPDATE I did some more playing around and tried the following. $fields = 'field1, field2, field3, field4'; $idFields = 'id_field1, id_field2, id_field3, id_field4'; $tables = 'table1, table2, table3, table4'; $table = explode(', ', $tables); $field = explode(', ', $fields); $id = explode(', ', $idFields); $str = 'Egg'; $i=1; while ($i<4) { $f = $field[$i]; $idd = $id[$i]; $sql = $writeConn->select()->from($table[$i], array($f, $idd))->where($f . " LIKE ?", '%' . $str . '%'); $string = '<a title="' . $str . '" href="' . $currentProductUrl . '">' . $str . '</a>'; $sth = $writeConn->prepare($sql); $sth->execute(); $result = $sth->fetch(PDO::FETCH_ASSOC); foreach ($result as $row) { echo 'Success! Found ' . $str . ' in ' . $f . '. ID: ' . $row[$idd] . '.<br>'; } $i++; } The interesting thing is that this outputs the below: Success! Found Egg in field3. ID: E. Success! Found Egg in field3. ID: E. Success! Found Egg in field3. ID: 5. Success! Found Egg in field3. ID: 5. Success! Found Egg in field3. ID: E. Success! Found Egg in field3. ID: E. Success! Found Egg in field3. ID: 5. Success! Found Egg in field3. ID: 5. I have also tried adding $i to the output and this outputs 2 as expected. If I change fetch(PDO::FETCH_BOTH) to fetch(PDO::FETCH_ASSOC) the output is as follows: Success! Found Egg in field3. ID: E. Success! Found Egg in field3. ID: E. Success! Found Egg in field3. ID: 5. Success! Found Egg in field3. ID: 5. This has been bugging me for too long, so if anyone could help I would be very appreciative!

    Read the article

  • PHP Magento Screen Scraping

    - by Grant unwin
    I am trying to scrape a suppliers magento site in an effort to save some time because of there being around 2000 products I need to gather info for. I'm totally OK with writing a screen scraper for pretty much anything but i've encountered a major problem. Im using get_file_contentsto gather the html of the product page. The problem is: You need to be logged in, to view the product page. Its a standard magento login, so how can I get round this in my screen scraper? I don't require a full script, just advice on a method. Thanks

    Read the article

  • Escaping quotes twice in PHP

    - by Genadinik
    Hello, I have a complicated form where I first have to take some _GET parameters and obviously I have to do a mysql_real_escape_string() on them since I look stuff up in the database with them. Them problem for me is after the initial db lookup. When the user submits a form, I send them along as a _POST request and obviously have to do this mysql_real_escape_string call again just in case someone tries to hack my site with a faked form submission. Then the problem I have is the arguments are escaped twice and my queries begin to look strange like this: select field1 , field2 , from my_table where some_id = \'.$lookup_id.\' ... So the system seems to be adding \' and it is messing me up :) Also, in my other forms I have not seen such behavior. Any ideas on what may be causing this? One weird thing is that I tried to send unescaped parameters to the post, and the same problem happens. That is a clue, but not a sufficient one for me. :( Thanks, Alex

    Read the article

  • Prevent PHP sesison hijack, are these good ideas?

    - by matthew Rhodes
    I'm doing a simple shopping cart for a small site. I plan to store cart items as well as logged in user_id in session variables. to make things a little more secure, I thought I'd do this: sha1() the user_id before storing it in the session. Also sha1() and store the http_user_agent var with some salt, and check this along with the user_id. I know there is more one can do, but I thought this at least helps quite a bit right? and is easy for me to implement.

    Read the article

  • My IF statement is changing variables in PHP

    - by user1902509
    I am fairly new to the whole programming thing, so forgive me if this is a stupid question. It seems odd that I haven't run into it before. I am trying to make an order form for a cake. You fill out the form, submit it, and it will then display the order in a new window, where you then hit "submit," and upload it to the Database. I have a series of If Statements to check for errors in the form before submitting it. Here is a simplified version of the code. Writing means any writing you want on the cake, Name is your name, and cake is what type of cake you want (the default is "None"). try { $name = trim($params->name); $cake = trim($params->cake); $writing = trim($params->writing); if (strlen($name) < 3){ throw new Exception("Please enter Your name."); } if ($cake = "None") { throw new Exception("Please select a Cake" } if ($cake = "Caramel Apple Pie" or $cake = "Pumpkin Pie" or $cake = "Eggnog Pie" and strlen($writing) > 1) { throw new Exception("We are sorry, but you can't write on any of our specialty pies."); } } catch(Exception $x) { $error = $x->getmessage(); } So what is happening is that when I go and hit submit the first time, the correct cake type comes up, but when you submit it the second time, the error comes up saying that I have "None" selected. All the other values are there and remain the same. I think the problem is that the first "IF" statement (Where it says "If($cake = "None")) is automatically changing $cake to "None" because I have tried commenting just that statement out, and it will then change the cake to be "Caramel Apple Pie," which is in the top of the next IF statement. Anyone know why it is doing this? And how to fix it?

    Read the article

  • php mysql search

    - by mckenzie
    Hello, My code contain SELECT * FROM newchap WHERE company LIKE '%$company%' OR Category LIKE '%$cat%' It works perfectly however, when the field $company contain empty, it return all result in MYSQL. How to prevent it?

    Read the article

< Previous Page | 309 310 311 312 313 314 315 316 317 318 319 320  | Next Page >