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  • Parsing Curl-ed XML with Perl

    - by syker
    How do I do the following in Perl in order: a) curl a page and save it to a variable b) parse the value of the variable (which is HTML content) for values I want (ex: the info is kept between tags like ... )

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  • Maven install-file won't generate pom.xml

    - by anotherCoder
    I've installed some third party jars to my repository using the following command: mvn install:install-file -Dfile=/home/anotherCoder/Downloads/nifty-1.0.jar -DgroupId=nifty-gui -DartifactId=nifty-gui -Dversion=1.0 -Dpackaging=jar However, once I do mvn compile, maven complains that there is no pom file in the repository and attempts to download it, but can't cause it is not published at any remote repository. Here is the exact message from maven: Downloading: http://repo1.maven.org/maven2/nifty-gui/nifty-gui/1.0/nifty-gui-1.0.pom [INFO] Unable to find resource 'nifty-gui:nifty-gui:pom:1.0' in repository central (http://repo1.maven.org/maven2) So how do I get maven to generate a pom file for that jar and put it in my local repository?

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  • How can I dynamically set the default namespace declaration of an XSLT transformation's output XML?

    - by Paralife
    I can do it, but not for the default namespace, using the <xsl:namespace>. If I try to do it for the default namespace: <xsl:namespace name="" select"myUri"/> it never works. It demands that I explicitly define the namespace of the element to be able to use the above null prefix declaration. The reason I want this is because I have a task to transform an input XML file to another output xml. The output XML has many elements and i dont want to have to explicitly set the namespace for every element. Thats why I want to set the default and never bother again. But the default must be computed from some data in the source XML. It does not change during the whole transformation, but it is dependent on input XML data. Any solution? EDIT 1: To sup up: I want to create a namespace dynamically and set it to be the default namespace of the output xml document. The uri of the namespace is derived from some data in the input XML. If I use <xsl:namespace> in my root output element, I cannot create a default namespace for it, only a prefixed one. And even with the prefixed one, it does not propagate to children.

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  • Environment variable expansion in persistence.xml (JPA)

    - by user342495
    I am developing a Eclipse RCP plugin which uses JPA. I tried to specify the database path via a variable give to the JVM on runtime. The property is set correctly but the database is created in a folder named after the variable name (here: ${DBHOME}). <property name="javax.persistence.jdbc.url" value="jdbc:derby:${DBHOME};create=true"/> Is there a possibility to fix this? Thx

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  • Ruby xml rpc error handling

    - by stel
    I have a model class Car @@RPCServer = XMLRPC::Client.new("localhost", "/", 8080) def self.count @@RPCServer.call("cars.count") end end If server is not running on localhost:8080 I've got a Errno::ECONNREFUSED error. I want to display an error message to user, how can a handle this error?

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  • Java RSA Encrypt using .NET XML Key File - need help

    - by badMonkey
    In .net I have generated the following public key file: <RSAKeyValue> <Modulus>xTSiS4+I/x9awUXcF66Ffw7tracsQfGCn6g6k/hGkLquHYMFTCYk4mOB5NwLwqczwvl8HkQfDShGcvrm47XHKUzA8iadWdA5n4toBECzRxiCWCHm1KEg59LUD3fxTG5ogGiNxDj9wSguCIzFdUxBYq5ot2J4iLgGu0qShml5vwk=</Modulus> <Exponent>AQAB</Exponent> .NET is happy to encrypt using it's normal methods. I am trying to use this key to encode a string in Java and am running into an Arithmetic problem (exception) when I attempt to encrypt the string. The following is the code I am using to encrypt: byte[] modulusBytes = Base64.decode(this.getString(R.string.public_key_modulus)); byte[] exponentBytes = Base64.decode(this.getString(R.string.public_key_exponent)); BigInteger modulus = new BigInteger( modulusBytes ); BigInteger exponent = new BigInteger( exponentBytes); RSAPublicKeySpec rsaPubKey = new RSAPublicKeySpec(modulus, exponent); KeyFactory fact = KeyFactory.getInstance("RSA"); PublicKey pubKey = fact.generatePublic(rsaPubKey); Cipher cipher = Cipher.getInstance("RSA"); cipher.init(Cipher.ENCRYPT_MODE, pubKey); byte[] cipherData = cipher.doFinal( new String("big kitty dancing").getBytes() ); It is the final line in the code block that fails. I have looked at numerous examples and this is the best I could come up with. If it is not obvious, the R.string.public_key_modulus is a copy/paste of the text in the Modulus element, same applies for exponent.

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  • iPhone RSS Reader -- parseXML won't Load some XML feeds

    - by JBMJBM
    I am using the SIMPLE RSS reading example found at http://theappleblog.com/2008/08/04/tutorial-build-a-simple-rss-reader-for-iphone/ It uses parseXML to load the RSS feeds. Here is the problem I am having. For the following RSS feed example, I am having trouble getting it to load the feed. Comes up with an error that it cannot connect. However on my Mac RSS Reader it works fine, so I know the link is good. Any ideas on why it cannot load this particular feed but it can load others fine? http://www.okstate.com/rss.dbml?db_oem_id=200&media=news Thanks.

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  • Ignoring namespace prefix while parsing xml

    - by Rachel
    If a xhtml file has namespace prefixes in the document and the namespace for the prefixes is not defined, is it possible to ignore the prefixes and still parse the file when using SAX parser. Is there a way to get rid of the error "The prefix for element is not bound." without defining the namespace for the prefixes while parsing?

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  • Is it the Correct way to create an XML like this:

    - by BDotA
    I want to create something like this at run-time: - <CWS> - <Case name="10-040-00022"> - <CaseDetailsSet> <CaseDetail title="Patient name" /> <CaseDetail title="Date of birth" /> </CaseDetailsSet> </Case> </CWS> so I wrote something like this ( I wish to use DOM in .NET .. not the XMLWriter,etc) XmlDocument doc = new XmlDocument(); XmlElement root = doc.CreateElement("CWS"); XmlElement singleCase = doc.CreateElement("Case"); root.AppendChild(singleCase); singleCase.SetAttribute("name", "10-040-00022"); XmlElement CaseDetailsSet = doc.CreateElement("CaseDetailsSet"); singleCase.AppendChild(CaseDetailsSet); XmlElement CaseDetail = doc.CreateElement("CaseDetail"); CaseDetailsSet.AppendChild(CaseDetail); CaseDetail.SetAttribute("title", "Patient Name"); please have a look at it and tell me if I am oing something wrong , regardign the code I worte to create that structure above. much appreciated.

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  • XML Serialization : Has property of type Class1 : Class1 has another property : How to write the property of Class1 into XML?

    - by Wonderlander
    I want to serialize a class. In this class there's a property, type of Class1, while there are other properties in Class1. public abstract class ComponentBase { [ToSerialize]//An attribute defined my me, indicating whether or not to serialize this property. public ComponentArgs Parameters { get; set; } } public class ComponentArgs { public string WorkingPath { get; set; } public IList<Language> Languages { get; set; } public string ComponentOutputPath { get; set; } } The information serialized must be put into a Dictionary, such as ComponentSettings[str_Name]=str_Value. The method used in reading this value is Reflection. pinfo: Property Info got via Type.GetProperties(); componentSettings.Add(pinfo.Name, pinfo.GetValue((object)this, null).ToString()); The information after serialization is: <Parameters>MS.STBIntl.Pippin.Framework.ComponentArgs</Parameters> instead of the value of ComponentArgs.WorkingPath. The solution I thought of is to append to the following line an if judgement: componentSettings.Add(pinfo.Name, pinfo.GetValue((object)this, null).ToString()); if(pinfo is ComponentArgs) componentSettings.Add(pinfo.Name, pinfo.GetValue( (ComponentArgs)this, null).WorkingPath+"\n"+ LanguageList+"\n"+ //Language list is a concatinated string of all elements in the list. (ComponentArgs)this, null).ComponentOutputPath+"\n"+ ); When deserializing, add a judgement of whether the value contains more than 2 "\n", if so, extract each value from the string. But this way seems clumsy and much more like an workaround. I wonder if there's any more professional way of doing it? My reviewer is very particular and he won't accept such a solution. If you know a way, could you please share it with me? Thanks a lot.

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  • Python templates for huge HTML/XML

    - by newtover
    Hello, Recently I needed to generate a huge HTML page containing a report with several thousand row table. And, obviously, I did not want to build the whole HTML (or the underlying tree) in memory. As result, I built the page with the old good string interpolation, but I do not like the solution. Thus, I wonder whether there are Python templating engines that can yield resulting page content by parts.

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  • Ruby xml rpc error handilng

    - by stel
    I have a model class Car @@RPCServer = XMLRPC::Client.new("localhost", "/", 8080) def self.count @@RPCServer.call("cars.count") end end If server is not running on localhost:8080 I've got a Errno::ECONNREFUSED error. I want to display an error message to user, how can a handle this error?

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  • Acessing elements of this xml

    - by csU
    <wsdl:definitions targetNamespace="http://www.webserviceX.NET/"> <wsdl:types> <s:schema elementFormDefault="qualified" targetNamespace="http://www.webserviceX.NET/"> <s:element name="ConversionRate"> <s:complexType> <s:sequence> <s:element minOccurs="1" maxOccurs="1" name="FromCurrency" type="tns:Currency"/> <s:element minOccurs="1" maxOccurs="1" name="ToCurrency" type="tns:Currency"/> </s:sequence> </s:complexType> </s:element> <s:simpleType name="Currency"> <s:restriction base="s:string"> <s:enumeration value="AFA"/> <s:enumeration value="ALL"/> <s:enumeration value="DZD"/> <s:enumeration value="ARS"/> i am trying to get at all of the elements in enumeration but cant seem to get it right. This is homework so please no full solutions, just guidance if possible. $feed = simplexml_load_file('http://www.webservicex.net/CurrencyConvertor.asmx?WSDL'); foreach($feed->simpleType as $val){ $ns s = $val->children('http://www.webserviceX.NET/'); echo $ns_s -> enumeration; } what am i doing wrong? thanks

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  • regex to match xml tags not containing other tags

    - by user1547254
    Let's say I want to look for <Address> <Street>Windsor</Street> </Address> and I do not want to return <Address> <Number>15</Number> <Street>Windsor</Street> </Address> i.e. I am looking for addresses where the Address node does not contain a number tag. I tried things like <Address>(?!Number)</Address> or <Address>.*?(?!Number).*?</Address> but can't quite figure it out :-( Any ideas? TIA eddiec :-)

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  • ReSharper 5.0s LINQ Refactoring Continues to be Amazing!

      In this post, well take a straight forward procedure based set of code and convert it to LINQ using a ReSharper from JetBrains suggestion.   The initial code is as follows: int... This site is a resource for asp.net web programming. It has examples by Peter Kellner of techniques for high performance programming...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.

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  • How to get distinct values from the List&lt;T&gt; with LINQ

    - by Vincent Maverick Durano
    Recently I was working with data from a generic List<T> and one of my objectives is to get the distinct values that is found in the List. Consider that we have this simple class that holds the following properties: public class Product { public string Make { get; set; } public string Model { get; set; } }   Now in the page code behind we will create a list of product by doing the following: private List<Product> GetProducts() { List<Product> products = new List<Product>(); Product p = new Product(); p.Make = "Samsung"; p.Model = "Galaxy S 1"; products.Add(p); p = new Product(); p.Make = "Samsung"; p.Model = "Galaxy S 2"; products.Add(p); p = new Product(); p.Make = "Samsung"; p.Model = "Galaxy Note"; products.Add(p); p = new Product(); p.Make = "Apple"; p.Model = "iPhone 4"; products.Add(p); p = new Product(); p.Make = "Apple"; p.Model = "iPhone 4s"; products.Add(p); p = new Product(); p.Make = "HTC"; p.Model = "Sensation"; products.Add(p); p = new Product(); p.Make = "HTC"; p.Model = "Desire"; products.Add(p); p = new Product(); p.Make = "Nokia"; p.Model = "Some Model"; products.Add(p); p = new Product(); p.Make = "Nokia"; p.Model = "Some Model"; products.Add(p); p = new Product(); p.Make = "Sony Ericsson"; p.Model = "800i"; products.Add(p); p = new Product(); p.Make = "Sony Ericsson"; p.Model = "800i"; products.Add(p); return products; }   And then let’s bind the products to the GridView. protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { Gridview1.DataSource = GetProducts(); Gridview1.DataBind(); } }   Running the code will display something like this in the page: Now what I want is to get the distinct row values from the list. So what I did is to use the LINQ Distinct operator and unfortunately it doesn't work. In order for it work is you must use the overload method of the Distinct operator for you to get the desired results. So I’ve added this IEqualityComparer<T> class to compare values: class ProductComparer : IEqualityComparer<Product> { public bool Equals(Product x, Product y) { if (Object.ReferenceEquals(x, y)) return true; if (Object.ReferenceEquals(x, null) || Object.ReferenceEquals(y, null)) return false; return x.Make == y.Make && x.Model == y.Model; } public int GetHashCode(Product product) { if (Object.ReferenceEquals(product, null)) return 0; int hashProductName = product.Make == null ? 0 : product.Make.GetHashCode(); int hashProductCode = product.Model.GetHashCode(); return hashProductName ^ hashProductCode; } }   After that you can then bind the GridView like this: protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { Gridview1.DataSource = GetProducts().Distinct(new ProductComparer()); Gridview1.DataBind(); } }   Running the page will give you the desired output below: As you notice, it now eliminates the duplicate rows in the GridView. Now what if we only want to get the distinct values for a certain field. For example I want to get the distinct “Make” values such as Samsung, Apple, HTC, Nokia and Sony Ericsson and populate them to a DropDownList control for filtering purposes. I was hoping the the Distinct operator has an overload that can compare values based on the property value like (GetProducts().Distinct(o => o.PropertyToCompare). But unfortunately it doesn’t provide that overload so what I did as a workaround is to use the GroupBy,Select and First LINQ query operators to achieve what I want. Here’s the code to get the distinct values of a certain field. protected void Page_Load(object sender, EventArgs e) { if (!IsPostBack) { DropDownList1.DataSource = GetProducts().GroupBy(o => o.Make).Select(o => o.First()); DropDownList1.DataTextField = "Make"; DropDownList1.DataValueField = "Model"; DropDownList1.DataBind(); } } Running the code will display the following output below:   That’s it! I hope someone find this post useful!

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  • Is there a Better Way to Retreive Raw XML from a URL than WebClient or HttpWebRequest? [.NET]

    - by DaMartyr
    I am working on a Geocoding app where I put the address in the URL and retreive the XML. I need the complete XML response for this project. Is there any other class for downloading the XML from a website that may be faster than using WebClient or HttpWebRequest? Can the XMLReader be used to get the full XML without string manipulation and would that be faster and/or more efficient?

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  • Creating Google sitemap.xml , is it okay for the images to be wrapped in url tags?

    - by AzizAG
    I'm using a tool to generate the sitemap.xml file for me, it started to crawl my website, got the pages and all images, but when exporting it, I review the xml(to make sure nothing is wrong) and I noticed that the images in my website are wrapped in url tags(I think it should be in image tags). See this: <url><loc>http://mywebsite.com/images/12.jpg</loc><lastmod>2012-05-23T13:39:02+00:00</lastmod><changefreq>weekly</changefreq><priority>0.50</priority></url> Shouldn't it be wrapped in image tag?(just like videos wrapped in video tag) Thanks.

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  • Oh that XML - did you ever try to read a raw file?

    - by GGBlogger
    If you've ever looked at a raw XML file - even a very simple one - you'll understand. XML files are nearly impossible to read in raw format. That's where various tools come in and there are a bunch of them including some very simple tools. If, however, you need some horsepower one of the best tools on the planet is LiquidXML! LiquidXML is a developer's tool. It's also an analyst's tool, a tester's tool and a designer's tool. Did I mention that it is compatible with Visual Studio? Once again I will be following up on this as time permits. But if this sounds like something you can use just visit http://www.liquid-technologies.com/. You will find a very complete description plus high quality training videos that will help you decide if this is a tool you can use.

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  • How do I customize desktop wallpaper slideshow via XML?

    - by Pithikos
    I spent some time and tried varioues things but nothing works. Here's what I have tried so far: Making a new folder /usr/share/backgrounds/mywallpapers and add my own background-1.xml in there. Copying a bunch of my own wallpaper files into /usr/share/backgrounds/ Copy /usr/share/backgrounds/Contest/background-1.xml to /usr/share/backgrounds/ I logged out and in and no changes in Appearance app. I have heard about Wallch but I don't want some app running in the background all the time. I'm not even sure Wallch will work with Gnome 3. I also tryied gnome-3-wp (Gnome 3 Wallpaper Slideshow app) but it just seems broken for Oneiric Ubuntu 11.10. Anyone has a solution?

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