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• Is there an HTML browser rendering engine for Ruby?

  - by Jose

  Given a URL, I would like to be able to render the returned HTML to know width and height for each div, fonts' size for each piece of text, color of each element, position of each element on screen, etc. A possible approach could be traversing the DOM tree with Hpricot and checking CSS style by parsing the associated stylesheet using css_parser gem. But this would not consider default styles, inheritance, floats, etc. In Java there's Cobra, a Java Web Renderer, which is able to render a web page and query attributes like width, font size, etc. for each fragment. I could use Cobra with JRuby or similar solutions, but prefer a Ruby native tool. Is there any library like this for Ruby?

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• Theme confusion in SpreadsheetML.

  - by dmaruca

  I've been fighting this all day. Inside my styles.xml file I have color information given like so: <fgColor theme="0" tint="-0.249977111117893" / ECMA 376 defines a theme color reference as: Index into the <clrScheme collection, referencing a particular <sysClr or <srgbClr value expressed in the Theme part. Ok, that sounds easy. Here is an excerpt from my clrScheme xml: <a:clrScheme name="Office" <a:dk1 <a:sysClr val="windowText" lastClr="000000" / </a:dk1 <a:lt1 <a:sysClr val="window" lastClr="FFFFFF" / </a:lt1 Index zero is black, and they are wanting to darken it? I can tell you that after the tint is applied, the color should be #F2F2F2. My confusion is what does theme="0" really mean? It can't possible mean to darken #000000. Checking MSDN only confuses me even more. From http://msdn.microsoft.com/en-us/library/dd560821.aspx note that the theme color integer begins counting from left to right in the palette starting with zero. Theme color 3 is the dark 2 text/background color. Actually, if you start counting at zero the third entry is Light 2. Dark 2 is the second one. Can anyone here shed some light on this subject for me? What does theme="0" really mean? Here is the VB6 code I have been working with to apply the tint. You can paste it into your vba editor and run the test sub. Public Type tRGB R As Byte G As Byte B As Byte End Type Public Type tHSL H As Double S As Double L As Double End Type Sub TestRgbTint() Dim c As tRGB RGB_Hex2Type "ffffff", c RGB_ApplyTint c, -0.249977111117893 Debug.Print Hex(c.R) & Hex(c.G) & Hex(c.B) End Sub Public Sub RGB_Hex2Type(ByVal HexString As String, RGB As tRGB) 'Remove the alpha channel if it exists If Len(HexString) = 8 Then HexString = mID(HexString, 3) End If RGB.R = CByte("&H" & Left(HexString, 2)) RGB.G = CByte("&H" & mID(HexString, 3, 2)) RGB.B = CByte("&H" & Right(HexString, 2)) End Sub Public Sub RGB_ApplyTint(RGB As tRGB, tint As Double) Const HLSMAX = 1# Dim HSL As tHSL If tint = 0 Then Exit Sub RGB2HSL RGB, HSL If tint < 0 Then HSL.L = HSL.L * (1# + tint) Else HSL.L = HSL.L * (1# - tint) + (HLSMAX - HLSMAX * (1# - tint)) End If HSL2RGB HSL, RGB End Sub Public Sub HSL2RGB(HSL As tHSL, RGB As tRGB) HSL2RGB_ByVal HSL.H, HSL.S, HSL.L, RGB End Sub Private Sub HSL2RGB_ByVal(ByVal H As Double, ByVal S As Double, ByVal L As Double, RGB As tRGB) Dim v As Double Dim R As Double, G As Double, B As Double 'Default color to gray R = L G = L B = L If L < 0.5 Then v = L * (1# + S) Else v = L + S - L * S End If If v > 0 Then Dim m As Double, sv As Double Dim sextant As Integer Dim fract As Double, vsf As Double, mid1 As Double, mid2 As Double m = L + L - v sv = (v - m) / v H = H * 6# sextant = Int(H) fract = H - sextant vsf = v * sv * fract mid1 = m + vsf mid2 = v - vsf Select Case sextant Case 0 R = v G = mid1 B = m Case 1 R = mid2 G = v B = m Case 2 R = m G = v B = mid1 Case 3 R = m G = mid2 B = v Case 4 R = mid1 G = m B = v Case 5 R = v G = m B = mid2 End Select End If RGB.R = R * 255# RGB.G = G * 255# RGB.B = B * 255# End Sub Public Sub RGB2HSL(RGB As tRGB, HSL As tHSL) Dim R As Double, G As Double, B As Double Dim v As Double, m As Double, vm As Double Dim r2 As Double, g2 As Double, b2 As Double R = RGB.R / 255# G = RGB.G / 255# B = RGB.B / 255# 'Default to black HSL.H = 0 HSL.S = 0 HSL.L = 0 v = IIf(R > G, R, G) v = IIf(v > B, v, B) m = IIf(R < G, R, G) m = IIf(m < B, m, B) HSL.L = (m + v) / 2# If HSL.L < 0 Then Exit Sub End If vm = v - m HSL.S = vm If HSL.S > 0 Then If HSL.L <= 0.5 Then HSL.S = HSL.S / (v + m) Else HSL.S = HSL.S / (2# - v - m) End If Else Exit Sub End If r2 = (v - R) / vm g2 = (v - G) / vm b2 = (v - B) / vm If R = v Then If G = m Then HSL.H = 5# + b2 Else HSL.H = 1# - g2 End If ElseIf G = v Then If B = m Then HSL.H = 1# + r2 Else HSL.H = 3# - b2 End If Else If R = m Then HSL.H = 3# + g2 Else HSL.H = 5# - r2 End If End If HSL.H = HSL.H / 6# End Sub

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• Turning an NSImage* into a CGImageRef?

  - by Brian Postow

  Is there an easy way to do this that works in 10.5? In 10.6 I can use nsImage CGImageForProposedRect: NULL context: NULL hints: NULL If I'm not using 1b black and white images (Like Group 4 TIFF), I can use bitmaps, but cgbitmaps seem to not like that setup... Is there a general way of doing this? I need to do this because I have an IKImageView that seems to only want to add CGImages, but all I've got are NSImages. Currently, I'm using a private setImage:(NSImage*) method that I'd REALLY REALLY rather not be using...

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• How can I have different colors for different tabs in SuperTabNavigator.

  - by Zeeshan Rang

  Hi Well the heading is basically what my question is: How can I have different colors for different tabs in SuperTabNavigator. Below is the code to my SuperTabNavigator with three tabs: <containers:SuperTabNavigator x="0" y="10" width="100%" height="100%" right="1" top="1" left="1" bottom="1" color="black" creationPolicy="all" id="tab_nav" popUpButtonPolicy="{SuperTabNavigator.POPUPPOLICY_OFF}"> <mx:Canvas label="My Friends" id="friends_container" width="100%" height="100%"/> <mx:Canvas label="My Groups" id="groups_container" width="100%" height="100%"/> <mx:Canvas label="Address Book" id="address_container" width="100%" height="100%"/> </containers:SuperTabNavigator> I want to have different color for every different tab. How should I do this. Thank you Zeeshan

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• security issue of Linux sudo command?

  - by George2

  Hello everyone, 1. I am using Red Hat Enterprise 5 Linux box. I find if a user is in /etc/sudoers file, then if the user run command with sudo, the user will run this command with root privilege (without knowing root password, the user runs sudo only need to input the user's own password in order to run a command with sudo). Is that correct understanding? 2. If yes, then is it a security hole? Since users other than root could run with root privilege? thanks in advance, George

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• [WPF] Format datagrid row foreground depends on data

  - by ktutnik

  Hi everyone, Im new in wpf, i though it was an easy task. i searched in the internet but not lucky to found any help regarding this problem. <Style TargetType="{x:Type DataGridRow}"> <Setter Property="Foreground" Value="{Binding Converter=conditionToColorConverter}"/> </Style> the problem is how to pass the row data to the value.. the converter will return RED or BLACK color when specified properties of the row data match some category. or maybe there is an easy way to do that? Thanks in advance Kin

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• Sparse O(1) array with indices being consecutive products

  - by Kos

  Hello, I'd like to pre-calculate an array of values of some unary function f. I know that I'll only need the values for f(x) where x is of the form of a*b, where both a and b are integers in range 0..N. The obvious time-optimized choice is just to make an array of size N*N and just pre-calculate just the elements which I'm going to read later. For f(a*b), I'd just check and set tab[a*b]. This is the fastest method possible - however, this is going to take a lot of space as there are lots of indices in this array (starting with N+1) which will never by touched. Another solution is to make a simple tree map... but this slows down the lookup itself very heavily by introducing lots of branches. No. I wonder - is there any solution to make such an array less sparse and smaller, but still quick branchless O(1) in lookup?

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• UISplitViewCOntroller + TabBarCOntroller + iPad

  - by tek3

  Hi all, I am developing a tab-based iPad application in which corresponding to each tab, I have to show an UISplitViewController . I have done this by adding two navigation controllers to my tabBarController and assigning a subclass of UISplitViewController as RootViewController of both navigationController. And also I have to show both viewControllers(Master and Detail) in both modes(Potrait and Landscape). For this I have constructed a subclass of UISplitViewController in which i am overriding willAnimateRotationToInterfaceOrientation method and setting the frame of both ViewControllers as demonstrated in this link. However i am not able to set both viewControllers correctly.If my app starts in Landscape mode everything displays fine but if i open it in Potrait mode then the orientation of both ViewControllers changes. Sometimes the MasterView occupies the entire screen or sometimes both ViewControllers appear leaving a black line between them and the navigationBar. I have been banging my head over this problem since two days without any success. kindly help..

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• how to round_corner a logo without leaving white background(transparent?) with it using pil?

  - by bdictator

  I got a square logo and I need to round_corner it, searched for a while and got the follow code "working": def round_corner_jpg(image, radius): """generate round corner for image""" mask = Image.new('RGB', image.size) #mask = Image.new('RGB', (image.size[0] - radius, image.size[1] - radius)) #mask = Image.new('L', image.size, 255) draw = aggdraw.Draw(mask) brush = aggdraw.Brush('black') width, height = mask.size draw.rectangle((0,0,width,height), aggdraw.Brush('')) #upper-left corner draw.pieslice((0,0,radius*2, radius*2), 90, 180, None, brush) #upper-right corner draw.pieslice((width - radius*2, 0, width, radius*2), 0, 90, None, brush) #bottom-left corner draw.pieslice((0, height - radius * 2, radius*2, height),180, 270, None, brush) #bottom-right corner draw.pieslice((width - radius * 2, height - radius * 2, width, height), 270, 360, None, brush) #center rectangle draw.rectangle((radius, radius, width - radius, height - radius), brush) #four edge rectangle draw.rectangle((radius, 0, width - radius, radius), brush) draw.rectangle((0, radius, radius, height-radius), brush) draw.rectangle((radius, height-radius, width-radius, height), brush) draw.rectangle((width-radius, radius, width, height-radius), brush) draw.flush() del draw return ImageChops.add(mask, image) then I saved the returned image object,however it has white background in it?how can i get rid of the white background? Thanks in advance~

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• How do you draw a line on a canvas in WPF that is 1 pixel thick.

  - by xarzu

  The method for drawing a line on a canvas in WPF that uses the line class actually draws a line that is two pixels thick: Line myLine = new Line(); myLine.Stroke = System.Windows.Media.Brushes.Black; myLine.X1 = 100; myLine.X2 = 140; // 150 too far myLine.Y1 = 200; myLine.Y2 = 200; myLine.StrokeThickness = 1; graphSurface.Children.Add(myLine); Microsoft might have decided to set a standard for line thickness and the minimum is 2 pixels thick when you set the strockThickness to 1, but when you already have rectangles drawn in XAML and even error fonts using WingDings, it is an obvious miss-match. How do you draw a line that is truly 1 pixel thick?

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• BitBlt code not working

  - by MusiGenesis

  I'm trying to use this code to draw a Bitmap directly onto a PictureBox: Bitmap bmp = (Bitmap)Bitmap.FromFile(@"C:\Users\Ken\Desktop\Load2.bmp"); Graphics grDest = Graphics.FromHwnd(pictureBox1.Handle); Graphics grSrc = Graphics.FromImage(bmp); IntPtr hdcDest = grDest.GetHdc(); IntPtr hdcSrc = grSrc.GetHdc(); BitBlt(hdcDest, 0, 0, pictureBox1.Width, pictureBox1.Height, hdcSrc, 0, 0, (uint)TernaryRasterOperations.SRCCOPY); // 0x00CC0020 grDest.ReleaseHdc(hdcDest); grSrc.ReleaseHdc(hdcSrc); but instead of rendering the Bitmap's contents it just draws a solid block of nearly-black. I'm pretty sure the problem is with the source hDC, because if I change SRCCOPY to WHITENESS in the above code, it draws a solid white block, as expected. Note: this next snippet works fine, so there's nothing wrong with the bitmap itself: Bitmap bmp = (Bitmap)Bitmap.FromFile(@"C:\Users\Ken\Desktop\Load2.bmp"); pictureBox1.Image = bmp;

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• Override colorscheme

  - by RymdPung

  I often find myself wanting to change just something little in a colorscheme, but i don't want to edit the original file. I tried putting my change in '~/.vim/after/colors/blah.vim', but that doesn't work for me. Example, I want to change the CursorLine highlight in BusyBee.vim.. ~/.vim/colors/BusyBee.vim I create the file '~/.vim/after/colors/BusyBee.vim' and add this: hi CursorLine guibg=#000000 ctermbg=Black cterm=none However, i don't see the change. Of course it works if i change the line in the originial BusyBee.vim, but like i said i'd prefer not to do that. Doing... :colo Busy<TAB> Shows me... BusyBee BusyBee

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• MVVM in a canvas with usercontrols

  - by Mauro Destro

  I have a MVVM WPF application that basically wants to be a single line diagram designer for an electrical distribution network. I have a canvas that must contains transformers, circuit breaker, lines and cables. My big problem is the design... How can i start? I think about a DesignerView, DesignerViewModel that contains an ObservableCollection of IDesignerItemViewModel that is my base class for all the element. But in this case I have to use ItemsControl to bind the content of the canvas to my collection but the pros is that I don't have to create usercontrol for each element but i'll solve most of the problems with DataTemplate (i suppose). Each element viewmodel mantain a link to a model persisted in a repository where i mantain my logical tree. Any hint about how to proceed, I have looked at many DiagramCanvas example but all of those use simple items most like simple rectangle...

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• How do I code a green button in UIActionSheet?

  - by Joshua

  I am using the code: { randomstatus=0; msg=[[NSString alloc]initWithFormat:@"Good job, do you want to continue?"]; UIActionSheet *actionSheet=[[UIActionSheet alloc]initWithTitle:msg delegate:self cancelButtonTitle:@"No" destructiveButtonTitle:@"Yes" otherButtonTitles:nil]; [actionSheet showInView:self.view]; [actionSheet release]; [msg release]; } I don't want to change the code, but I need the "destructiveButton" to be green instead of red. Is this possible, or do i need to use a different button?

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• Redirect to show ModelAndView from another Controller - (Spring 3 MVC, Hibernate 3)???

  - by Mimi

  How exactly can I trigger display of a model and view from another model and view’s controller? [B][COLOR="Blue"]HTTP Request View -- HttpRequestController POST - new HttpResponse POJO and a string of the POJO in XML as an Http Response msg to be sent back to the Requestor --[/COLOR][/B] [B][COLOR="Red"][/COLOR][/B] I have HttpRequestController() to handle a POST message with data from an input Form and populated an HttpRequest POJO with it. An HttpResponse POJO is composed and persisted along with the HttpRequest to a Db. I made this HttResponse POJO an XML string as the @Responsebody to be sent back by the HttpRequestController() (as an actual HTTP Response message with header and body) and I want to present this HttpResponse POJO in a View. I tried different things, none worked and I could not find a similar example anywhere.

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• Is url.openStream harmful?

  - by Casebash

  I was using the java.net.URL.openStream() method to retrieve content from the server. I recently ran into an issue where the HTTP Response code indicated an error, but instead of throwing an exception, the stream still was read anyway. This caused the error to appear much later in the execution and proved to be a red herring. As far as I can see, when you have opened a stream using this method, there is no way to check the HTTP response code. The only way I could find to handle this properly was to use code such as: HttpURLConnection conn=(HttpURLConnection) url.openConnection() if(conn.getResponseCode()!=HttpStatus.SC_OK) //Raise Exception; InputStream in=conn.getInputStream() So do you agree? Is it possible to use openStream safely, or is it a method that should be avoided at all costs. It is worth noting that Sun uses the method in their tutorial code for reading directly from a URL. Then again, the code throws Exception so it isn't exactly a bastion of good coding practices.

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• Using CSS Classes for indivdual effects - opinions?

  - by Cool Hand Luke UK

  Hey, Just trying to canvas some opinions here. I was wondering how people go about adding individual effects to html elements. Take this example: you have three types of h1 titles all the same size but some are black some are gold and some are white. Some have a text-shadow etc. Would you create separate CSS classes and add them do the h1 tag or would you create a new single class for each different h1 title type (with grouped CSS elements)? With singular class for each effect you can build up combos of classes in html class="gold shadow" but also how would you name them. For example its bad practice to give classes and id names associated to colours, because it doesn't define what it does well. However is this ok with textual CSS classes? Just wondering what others do, I know there are no hard and fast rules. Cheers.

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• HTML <select> selected option background-color CSS style

  - by arieltools

  Is there a style for a select option's "selected" color? For example: <HTML> <BODY> <FORM NAME="form1"> <SELECT NAME="mySelect" SIZE="7" style="background-color:red;"> <OPTION>Test 1 <OPTION>Test 2 <OPTION>Test 3 <OPTION>Test 4 <OPTION>Test 5 <OPTION>Test 6 <OPTION>Test 7 </SELECT> </FORM> </BODY> </HTML> When I select an option it turns blue, I want to override this and make it a different color. In the style I expected something like "selected-color", but it doesn't exist.

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• BlackBerry SDK 5.0 Issue

  - by Benoy Bose

  I developed a Hello World application using Black Berry Eclipse plug-in. When I rant it on any BlackBerry simulator of which platform version is greater than or equal to 5.0 then the Hello World application is not found listed in the default application list. However, I can run the application from Options Application : Search (Thridparty) and switch application. How can I make my application come to the default application list on any BlackBerry simulator with platform version is 5.0 or greater. My Hello World application is built for the JRE BlackBerry JRE 5.0.0 Can any one help.... Thanks, Benoy Bose

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• Problem with background color and Google Chrome

  - by Sergio del Amo

  Sometimes i get a broken background in Chrome. I do not get this error with any other browser. This is the simple CSS line responsible of the background color of body: body { background: black; color: white; font-family: Chaparral Pro, lucida grande, verdana, sans-serif; } This is exactly how i get this problem. I click a link included in an gmail's email and i get: I refresh the page and the background is colored complete. Does ayone knows about this problem?

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• ListBoxItem IsSelected style

  - by plotnick

  I still didn't get it. Could you please show me exactly how to override ListBox's default behavior. Everytime when ListBoxItem is selected the Border's background should be changed. Not the background of the whole row but only background of the border which's specified. <ListBox ItemsSource="{Binding Source={StaticResource AssetsViewSource}}"> <ListBox.ItemTemplate> <DataTemplate> <Border BorderThickness="2" BorderBrush="Black"> <StackPanel> <TextBlock Text="Name: " /> <TextBlock Text="{Binding Name}" /> </StackPanel> </Border> </DataTemplate> </ListBox.ItemTemplate> </ListBox>

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• VS2008: Add custom build rule to a Property Sheet (vsprops)?

  - by shoosh

  I'm using the CUDA .rules file which comes with the CUDA SDK for custom build steps in my project. To save on property duplication I'd like to define the properties of the CUDA rule in a .vsprops file. For some reason, the CUDA rule branch of the properties tree does not show under any of my property sheets, only under the main configurations sheets. I tried editing the .vsprops with a text edition and add the section by hand but there is no change it still does't show when in visual studio. Is there a way to do this?

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• Maximum bipartite graph (1,n) "matching"

  - by Imre Kelényi

  I have a bipartite graph. I am looking for a maximum (1,n) "matching", which means that each vertex from partitation A has n associated vertices from partition B. The following figure shows a maximum (1,3) matching in a graph. Edges selected for the matching are red and unselected edges are black. This differs from the standard bipartite matching problem where each vertex is associate with only one other vertex, which could be called (1,1) matching with this notation. If the matching cardinality (n) is not enforced but is an upper bound (vertices from A can have 0 < x <= n associated vertices from B), then the maximum matching can be found easily by transforming the graph to a flow network and finding the max flow. However, this does not guarantee that the maximum number of vertices from A will have n associated pairs from B.

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• Removing the image from an IKImageView

  - by Brian Postow

  I have an IKImageView that is coming up effectively un-initialized. This is happening effectively in an error-state (The user is unregistered) so I haven't had a chance to put an image in it yet. In 10.6, this comes up fine, with a black rectangle. In 10.5, however, it comes up with garbage. some rectangles of noise, some rectangles of copies of the desktop, etc. I've tried setting the ZoomFactor to 0.0, I've tried setting the image to nil, but it appears that the problem is beyond that. any ideas? (My next kludge is going to be to ship tiny blank image with the app, and try to get it to load that... but that's kind of silly)

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• Change color of text within a WinForms RichTextBox

  - by Addie

  I have a RichTextBox that I write a string to every time I click a Form button. The string ends with a newline so each time I add a string, it appends to the bottom of the RichTextBox. Each string begins with the string "Long" or "Short" and ends with Environment.NewLine. I'd like to color each line red if it beings with "Long" and blue if it begins with "Short". How can I do this? If you need further clarification of the question comment below.

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