Search Results

Search found 10101 results on 405 pages for 'temporary tables'.

Page 317/405 | < Previous Page | 313 314 315 316 317 318 319 320 321 322 323 324  | Next Page >

  • many-to-many relationship in CI (not using ORM)

    - by Ross
    I'm implementing a categories system in my CI app and trying to work out the best way of working with many to many relationships. I'm not using an ORM at this stage, but could use say Doctrine if necessary. Each entry may have multiple categories. I have three tables (simplified) Entries: entryID, entryName Categories: categoryID, categoryname Entry_Category: entryID, categoryID my CI code returns a record set like this: entryID, entryName, categoryID, categoryName but, as expected with Many-to-Many relationships, each "entry" is repeated for each "category". What would the best way to "group" the categories so that when I output the results, I am left with something like: Entry Name Appears in Category: Foo, Bar rather than: Entry Name Appears in Category: Foo Entry Name Appears in Category: Bar I believe the option is to track if the post ID matches a previous entry, and if so, store the respective category, and output it as one, rather than several, but am unsure of how to do this in CI. thanks for any pointers (I appreciate this is may be a vague/complex question without a better knowledge of the system).

    Read the article

  • error defining foreign key PhpMyAdmin

    - by Ngounou lassale
    I am new to PhpMyAdmin. I will like to create a foreign key for my tables. In fact i have create tableI with this structures(A as int(11) autoincrement, B as varchar) TableII ( A_2 as int(11) auto increment, B_2 as varchar, A as int(11). I have declared A as an index in tableII, now when i go to relationship view to precise A as a foreign key i always have this error Erreur lors de la création de la clé étrangère sur ID_Ville (vérifiez le type des colonnes) Erreur ALTER TABLE tb_quartier ADD FOREIGN KEY ( ID_Ville ) REFERENCES ingenieris2.tb_ville ( ID_Ville ) ON DELETE RESTRICT ; Please Help thanks!

    Read the article

  • Please help me out in fetching the desired result from below given DB table structure of MySQL..

    - by OM The Eternity
    Hi All below are the table structures according to which I have to develop the desired output(given at the end) tbl_docatr docatr_id doc_id docatrtype_id docatr_float docatr_int docatr_date docatr_varchar docatr_blob 1 12 1 NULL NULL NULL testing [BLOB - NULL] 2 12 2 NULL NULL NULL Tesitng [BLOB - NULL] tbl_docatrtype docatrtype_id docatrtypegroup_id docatrtypetype_id docatrtype_name 1 1 4 Name 2 1 4 Company Name tbl_docatrtypetype docatrtypetype_id docatrtypetype_name 1 Float 2 Int 3 Date 4 String line Above are three tables from which I have to display the desired output as Name : testing Company Name : Tesitng such that at first step I have doc_id then I get docatrtype_id and then docatrtypetype_id acording to these values i have to fetch the result. Also the query must see the doactrtypetype_id from table tbl_docatrtypetype and fetch the result from tbl_docatr from respective column docatr_float, docatr_int, docatr_date, docatr_varchar, docatr_blob Please help!!!

    Read the article

  • Where to store users visited pages?

    - by kofto4ka
    Hi there. I have a project, where I have posts for example. The task is next: I must show to user his last posts visit. This is my solution: every time user visits new (for him) topic, I create a new record in table visits. Table visits has next structure: id, user_id, post_id, last_visit. Now my tables visits has ~14,000,000 records and its still growing every day.. May be my solution isnt optimal and exists another way how to store users visits? Its important to save every visit as standalone record, because I also have feature to select and use users visits. And I cant purge this table, because data could be needed later month, year. How I could optimize this situation?

    Read the article

  • My table cells don't highlight immediately when touched

    - by Steve Denenberg
    Hi, In my app, I have a table view that has about eight cells. There is a navigation bar at the top. When a user touches a cell, nothing happens for about 1/2 second. Then the touched cell highlights blue and immediately the new view slides into position. The problem is that there is no feedback to the user about which cell he touched until just before the new view slides into position. For example, when I explore the tables in the iPhone's Settings application, when you touch a cell, the cell immediately turns blue, and then there is a 1/2 second delay, and then you see the new view. How do I get my table's feedback of highlighting the cells to happen immediately? I am using tableView didSelectRowAtIndexPath:, and each cell has an accessory button. Thanks for any insight.

    Read the article

  • How do i use SQL Server 2008? With Visual Studios?

    - by acidzombie24
    Its a two part question. How do i use SQL Server 2008? With Visual Studios? I started up a dummy project and with server explorer i tried with create new sql server database and add connection using my computer name (it came from a dropdown) as the server location. When i tried to create the database 'TestDB1' i got an error. I dont understand why. Its a fresh install and i have restarted the comp a few times since then. I havent messed with visual studios or the servers or even the control options to disable anything that would have been automatic. So whats with this? -edit- My goals are 1) create a database. 2) Be able to see all the database that exist on the server 3) execute sql queries in the ide 4) be able to browse tables. I dont need all of these but as many possible would be nice.

    Read the article

  • Traversing ORM relationships returns duplicate results

    - by NKing253
    I have 4 tables -- store, catalog_galleries, catalog_images, and catalog_financials. When I traverse the relationship from store --> catalog_galleries --> catalog_images in other words: store.getCatalogGallery().getCatalogImages() I get duplicate records. Does anyone know what could be the cause of this? Any suggestions on where to look? The store table has a OneToOne relationship with catalog_galleries which in turn has a OneToMany relationship with catalog_images and an eager fetch type. The store table also has a OneToMany relationship with catalog_financials.

    Read the article

  • Questions regarding databases MS Access [on hold]

    - by user2977751
    Good day! I am using MS Access 2007. I was wondering, how can I link a specific item on a table to another item in another table? For example, if I search for a particular product, all the suppliers of that product will be displayed. I want to connect my supply field to different suppliers field in different tables so that when I search for a particular supply, all the suppliers for that supply will be shown. And if it is also possible to link the records into a pre-set template in excel. THANKS!

    Read the article

  • Expanded securityadmin

    - by user80652
    I'm aware that sysadmin is documented as the server role necessary for creating logins (SQL/Windows-integrated); nevertheless, I'm tasked to find out if there's any other server role (built-in or otherwise) that can be used. To be specific, I'm looking to setup one or two logins with access to create logins, create [database] users, assign users to [database] roles. Potentially reset passwords, but most of the logins are Windows-integrated and it's not necessary. Cannot have access to data at all, nor can these logins have rights to update tables nor create/update roles. Seems my only options so far are to set these 2 logins with securityadmin server role and for the specific databases, configure with db_securityadmin and db_accessadmin... but this configuration doesn't allow for creating logins.

    Read the article

  • Any Way to Use a Join in a Lambda Where() on a Table<>?

    - by lush
    I'm in my first couple of days using Linq in C#, and I'm curious to know if there is a more concise way of writing the following. MyEntities db = new MyEntities(ConnString); var q = from a in db.TableA join b in db.TableB on a.SomeFieldID equals b.SomeFieldID where (a.UserID == CurrentUser && b.MyField == Convert.ToInt32(MyDropDownList.SelectedValue)) select new { a, b }; if(q.Any()) { //snip } I know that if I were to want to check the existence of a value in the field of a single table, I could just use the following: if(db.TableA.Where(u => u.UserID == CurrentUser).Any()) { //snip } But I'm curious to know if there is a way to do the lambda technique, but where it would satisfy the first technique's conditions across those two tables. Sorry for any mistakes or clarity, I'll edit as necessary. Thanks in advance.

    Read the article

  • fastest way to perform string search in general and in python

    - by Rkz
    My task is to search for a string or a pattern in a list of documents that are very short (say 200 characters long). However, say there are 1 million documents of such time. What is the most efficient way to perform this search?. I was thinking of tokenizing each document and putting the words in hashtable with words as key and document number as value, there by creating a bag of words. Then perform the word search and retrieve the list of documents that contained this word. From what I can see is this operation will take O(n) operations. Is there any other way? may be without using hash-tables?. Also, is there a python library or third party package that can perform efficient searches?

    Read the article

  • Count, inner join

    - by Urosh
    I have two tables: DRIVER (Driver_Id,First name,Last name,...) PARTICIPANT IN CAR ACCIDENT (Participant_Id,Driver_Id-foreign key,responsibility-yes or no,...) Now, I need to find out which driver participated in accident where responsibility is 'YES', and how many times. I did this: Select Driver_ID, COUNT (Participant.Driver_ID)as 'Number of accidents' from Participant in car accident where responsibility='YES' group by Driver_ID order by COUNT (Participant.Driver_ID) desc But, I need to add drivers first and last name from the first table(using inner join, I suppose). I don't know how, because it is not contained in either an aggregate function or the GROUP BY clause. Please help :)

    Read the article

  • Normalization two types of customers into one table

    - by JDewzy
    I am trying to model a sales situation where you can sell to a person or to a business with a contact person. I cannot figure out the proper way to do this. It seems like 2 tables would be incorrect. But how do I model a Customer table that can be a business or a person? Would I just have a boolean for "business" and an additional "business_name" field that would default to Null. But then I have to do an if/then on the columns and that seems like poor design. Any advice, direction, or links is appreciated.

    Read the article

  • Fill data gaps without UNION

    - by Dave Jarvis
    Problem There are data gaps that need to be filled, possibly using PARTITION BY. Query Statement The select statement reads as follows: SELECT count( r.incident_id ) AS incident_tally, r.severity_cd, r.incident_typ_cd FROM report_vw r GROUP BY r.severity_cd, r.incident_typ_cd ORDER BY r.severity_cd, r.incident_typ_cd Code Tables The severity codes and incident type codes are from: severity_vw incident_type_vw Actual Result Data 36 0 ENVIRONMENT 1 1 DISASTER 27 1 ENVIRONMENT 4 2 SAFETY 1 3 SAFETY Required Result Data 36 0 ENVIRONMENT 0 0 DISASTER 0 0 SAFETY 27 1 ENVIRONMENT 0 1 DISASTER 0 1 SAFETY 0 2 ENVIRONMENT 0 2 DISASTER 4 2 SAFETY 0 3 ENVIRONMENT 0 3 DISASTER 1 3 SAFETY Any ideas how to use PARTITION BY (or JOINs) to fill in the zero counts?

    Read the article

  • PHP Booking timeslot

    - by boyee007
    Im developing a php booking system based on timeslot for daily basis. Ive set up 4 database tables! Bookslot (which store all the ids - id_bookslot, id_user, id_timeslot) Timeslot (store all the times on 15 minutes gap ex: 09:00, 09:15, 09:30, etc) Therapist (store all therapist details) User (store all the members detail) ID_BOOKSLOT ID_USER ID_THERAPIST ID_TIMESLOT 1 10 1 1 (09:00) 2 11 2 1 (09:00) 3 12 3 2 (09:15) 4 15 3 1 (09:00) Now, my issue is, it keep showing repeation for timeslot when i want echoing the data for example: thera a thera b thera c ------------------------------------------------- 09:00 BOOKED available available 09:00 available BOOKED available 09:00 available available BOOKED 09:15 available BOOKED available as you can see, 09:00 showing three times, and i want something like below thera a thera b thera c ------------------------------------------------- 09:00 BOOKED BOOKED BOOKED 09:15 available BOOKED available There might be something wrong with joining the table or else. The code to join the table $mysqli->query("SELECT * FROM bookslot RIGHT JOIN timeslot ON bookslot.id_timeslot = timeslot.id_timeslot LEFT JOIN therapist ON bookslot.id_therapist = therapist.id_therapist" if anyone have the solution for this system, please help me out and i appriciate it much!

    Read the article

  • MySQL query to find the most popular value in a column joined by another value in a second table

    - by Budove
    I have two tables: users: user_id, user_zip settings: user_id, pref_ex_loc I need to find the single most popular 'pref_ex_loc' from the settings table based on a particular user_zip, which will be specified as the variable $userzip. Here is the query that I have now and obviously it doesn't work. $popularexloc = "SELECT pref_ex_loc, user_id COUNT(pref_ex_loc) AS countloc FROM settings FULL OUTER JOIN users ON settings.user_id = users.user_id WHERE users.user_zip='$userzip' GROUP BY settings.pref_ex_loc ORDER BY countloc LIMIT 1"; $popexloc = mysql_query($popularexloc) or die('SQL Error :: '.mysql_error()); $exlocrow = mysql_fetch_array($popexloc); $mostpopexloc=$exlocrow[0]; echo '<option value="'.$mostpopexloc.'">'.$mostpopexloc.'</option>'; What am I doing wrong here? I'm not getting any kind of error from this either.

    Read the article

  • Delete rows out of table that is innerjoined and unioned with 2 others

    - by jonathan
    We have 3 tables (table1, table2, table3), and I need to delete all the rows from table1 that have the same ID in table2 OR table3. To see a list of all of these rows I have this code: ( select table2.ID, table2.name_first, table2.name_last, table2.Collected from table2 inner join table1 on table1.ID = table2.ID where table2.Collected = 'Y' ) union ( select table3.ID, table3.name_first, table3.name_last, table3.Collected from table3 inner join table1 on table1.ID = table3.ID where table3.Collected = 'Y' ) I get back about 200 rows. How do I delete them from table1? I don't have a way to test if my query will work, so I'm nervous about modifying something I found online and potentially deleting data (we do have backups, but I'd rather not test out their integrity). TIA!

    Read the article

  • MySQL: Select remaining rows

    - by Bjork24
    I've searched everywhere for this, but I can't seem to find a solution. Perhaps I'm using the wrong terms. Either way, I'm turning to good ol' trusty S.O. to help my find the answer. I have two tables, we'll call them 'tools' and 'installs' tools = id, name, version installs = id, tool_id, user_id The 'tools' table records available tools, which are then installed by a user and recorded in the 'installs' table. Selecting the installed tools are simple enough: SELECT tools.name FROM tools LEFT JOIN installs ON tools.id = installs.tool_id WHERE user_id = 99 ; How do I select the remaining tools -- the ones that have yet to be installed by user #99? I'm sorry if this is painfully obvious, but I just can't seem to figure it out! Thanks for the help!

    Read the article

  • How to return result set based on other rows

    - by understack
    I've 2 tables - packages and items. Items table contains all items belonging to the packages along with location information. Like this: Packages table id, name, type(enum{general,special}) 1, name1, general 2, name2, special Items table id, package_id, location 1, 1, America 2, 1, Africa 3, 1, Europe 4, 2, Europe Question: I want to find all 'special' packages belonging to a location and if no special package is found then it should return 'general' packages belonging to same location. So, for 'Europe' : package 2 should be returned since it is special package (Though package 1 also belongs to Europe but not required since its a general package) for 'America' : package 1 should be returned since there are no special packages

    Read the article

  • Concurrency handling

    - by Lijo
    Hi, Suppose, I am about to start a project using ASP.NET and SQL Server 2005. I have to design the concurrency requirement for this application. I am planning to add a TimeStamp column in each table. While updating the tables I will check that the TimeStamp column is same, as it was selected. Will this approach be suffice? Or is there any shortcomings for this approach under any circumstances? Please advice. Thanks Lijo

    Read the article

  • how to join on varchar(32) and binary(16) columns in sybase?

    - by Paul Sanwald
    I want to join two tables on a UUID. table A's UUID is represented as varchar(32). table B's UUID is represented as binary(16). what's the best way to join a varchar to a binary column? I've tried using some sybase functions for this, but I'm getting different results and unsure of why: select hextobigint('0x000036ca4c4c11d88b8dcd1344cdb512') 3948051912944290701 select convert(bigint,0x000036ca4c4c11d88b8dcd1344cdb512) -2877434794219274240 what am I missing about convert and hextobigint? I must be misundstanding at least one of these functions. thanks for your help!

    Read the article

  • PHP "You have () new comments on your clip", how?

    - by user292516
    Hello. I want to do a function to my users, so on index.php there is e.g: You have 2 new comments on your clip How should i do this? I mean i want ideas to do this the easiest way. Table for the videos is member_videos, and tables for the comment is member_videocomments, a comment inside the table is connected by their "videoID", which is the id of the column in member_videos. Should i do the classic, making a field, which all is 0, until it has been seen by the user its 1 or what should i do.

    Read the article

  • Reading input from a text file, omits the first and adds a nonsense value to the end?

    - by Greenhouse Gases
    Hi there When I input locations from a txt file I am getting a peculiar error where it seems to miss off the first entry, yet add a garbage entry to the end of the link list (it is designed to take the name, latitude and longitude for each location you will notice). I imagine this to be an issue with where it starts collecting the inputs and where it stops but I cant find the error!! It reads the first line correctly but then skips to the next before adding it because during testing for the bug it had no record of the first location Lisbon though whilst stepping into the method call it was reading it. Very bizarre but hopefully someone knows the issue. Here is firstly my header file: #include <string> struct locationNode { char nodeCityName [35]; double nodeLati; double nodeLongi; locationNode* Next; void CorrectCase() // Correct upper and lower case letters of input { int MAX_SIZE = 35; int firstLetVal = this->nodeCityName[0], letVal; int n = 1; // variable for name index from second letter onwards if((this->nodeCityName[0] >90) && (this->nodeCityName[0] < 123)) // First letter is lower case { firstLetVal = firstLetVal - 32; // Capitalise first letter this->nodeCityName[0] = firstLetVal; } while(n <= MAX_SIZE - 1) { if((this->nodeCityName[n] >= 65) && (this->nodeCityName[n] <= 90)) { letVal = this->nodeCityName[n] + 32; this->nodeCityName[n] = letVal; } n++; } //cityNameInput = this->nodeCityName; } }; class Locations { private: int size; public: Locations(){ }; // constructor for the class locationNode* Head; //int Add(locationNode* Item); }; And here is the file containing main: // U08221.cpp : main project file. #include "stdafx.h" #include "Locations.h" #include <iostream> #include <string> #include <fstream> using namespace std; int n = 0,x, locationCount = 0, MAX_SIZE = 35; string cityNameInput; char targetCity[35]; bool acceptedInput = false, userInputReq = true, match = false, nodeExists = false;// note: addLocation(), set to true to enable user input as opposed to txt file locationNode *start_ptr = NULL; // pointer to first entry in the list locationNode *temp, *temp2; // Part is a pointer to a new locationNode we can assign changing value followed by a call to Add locationNode *seek, *bridge; void setElementsNull(char cityParam[]) { int y=0, count =0; while(cityParam[y] != NULL) { y++; } while(y < MAX_SIZE) { cityParam[y] = NULL; y++; } } void addLocation() { temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it if(!userInputReq) // bool that determines whether user input is required in adding the node to the list { cout << endl << "Enter the name of the location: "; cin >> temp->nodeCityName; temp->CorrectCase(); setElementsNull(temp->nodeCityName); cout << endl << "Please enter the latitude value for this location: "; cin >> temp->nodeLati; cout << endl << "Please enter the longitude value for this location: "; cin >> temp->nodeLongi; cout << endl; } temp->Next = NULL; //set to NULL as when one is added it is currently the last in the list and so can not point to the next if(start_ptr == NULL){ // if list is currently empty, start_ptr will point to this node start_ptr = temp; } else { temp2 = start_ptr; // We know this is not NULL - list not empty! while (temp2->Next != NULL) { temp2 = temp2->Next; // Move to next link in chain until reach end of list } temp2->Next = temp; } ++locationCount; // increment counter for number of records in list if(!userInputReq){ cout << "Location sucessfully added to the database! There are " << locationCount << " location(s) stored" << endl; } } void populateList(){ ifstream inputFile; inputFile.open ("locations.txt", ios::in); userInputReq = true; temp = new locationNode; // declare the space for a pointer item and assign a temporary pointer to it do { inputFile.get(temp->nodeCityName, 35, ' '); setElementsNull(temp->nodeCityName); inputFile >> temp->nodeLati; inputFile >> temp->nodeLongi; setElementsNull(temp->nodeCityName); if(temp->nodeCityName[0] == 10) //remove linefeed from input { for(int i = 0; temp->nodeCityName[i] != NULL; i++) { temp->nodeCityName[i] = temp->nodeCityName[i + 1]; } } addLocation(); } while(!inputFile.eof()); userInputReq = false; cout << "Successful!" << endl << "List contains: " << locationCount << " entries" << endl; cout << endl; inputFile.close(); } bool nodeExistTest(char targetCity[]) // see if entry is present in the database { match = false; seek = start_ptr; int letters = 0, letters2 = 0, x = 0, y = 0; while(targetCity[y] != NULL) { letters2++; y++; } while(x <= locationCount) // locationCount is number of entries currently in list { y=0, letters = 0; while(seek->nodeCityName[y] != NULL) // count letters in the current name { letters++; y++; } if(letters == letters2) // same amount of letters in the name { y = 0; while(y <= letters) // compare each letter against one another { if(targetCity[y] == seek->nodeCityName[y]) { match = true; y++; } else { match = false; y = letters + 1; // no match, terminate comparison } } } if(match) { x = locationCount + 1; //found match so terminate loop } else{ if(seek->Next != NULL) { bridge = seek; seek = seek->Next; x++; } else { x = locationCount + 1; // end of list so terminate loop } } } return match; } void deleteRecord() // complete this { int junction = 0; locationNode *place; cout << "Enter the name of the city you wish to remove" << endl; cin >> targetCity; setElementsNull(targetCity); if(nodeExistTest(targetCity)) //if this node does exist { if(seek == start_ptr) // if it is the first in the list { junction = 1; } if(seek != start_ptr && seek->Next == NULL) // if it is last in the list { junction = 2; } switch(junction) // will alter list accordingly dependant on where the searched for link is { case 1: start_ptr = start_ptr->Next; delete seek; --locationCount; break; case 2: place = seek; seek = bridge; delete place; --locationCount; break; default: bridge->Next = seek->Next; delete seek; --locationCount; break; } } else { cout << targetCity << "That entry does not currently exist" << endl << endl << endl; } } void searchDatabase() { char choice; cout << "Enter search term..." << endl; cin >> targetCity; if(nodeExistTest(targetCity)) { cout << "Entry: " << endl << endl; } else { cout << "Sorry, that city is not currently present in the list." << endl << "Would you like to add this city now Y/N?" << endl; cin >> choice; /*while(choice != ('Y' || 'N')) { cout << "Please enter a valid choice..." << endl; cin >> choice; }*/ switch(choice) { case 'Y': addLocation(); break; case 'N': break; default : cout << "Invalid choice" << endl; break; } } } void printDatabase() { temp = start_ptr; // set temp to the start of the list do { if (temp == NULL) { cout << "You have reached the end of the database" << endl; } else { // Display details for what temp points to at that stage cout << "Location : " << temp->nodeCityName << endl; cout << "Latitude : " << temp->nodeLati << endl; cout << "Longitude : " << temp->nodeLongi << endl; cout << endl; // Move on to next locationNode if one exists temp = temp->Next; } } while (temp != NULL); } void nameValidation(string name) { n = 0; // start from first letter x = name.size(); while(!acceptedInput) { if((name[n] >= 65) && (name[n] <= 122)) // is in the range of letters { while(n <= x - 1) { while((name[n] >=91) && (name[n] <=97)) // ERROR!! { cout << "Please enter a valid city name" << endl; cin >> name; } n++; } } else { cout << "Please enter a valid city name" << endl; cin >> name; } if(n <= x - 1) { acceptedInput = true; } } cityNameInput = name; } int main(array<System::String ^> ^args) { //main contains test calls to functions at present cout << "Populating list..."; populateList(); printDatabase(); deleteRecord(); printDatabase(); cin >> cityNameInput; } The text file contains this (ignore the names, they are just for testing!!): Lisbon 45 47 Fattah 45 47 Darius 42 49 Peter 45 27 Sarah 85 97 Michelle 45 47 John 25 67 Colin 35 87 Shiron 40 57 George 34 45 Sean 22 33 The output omits Lisbon, but adds on a garbage entry with nonsense values. Any ideas why? Thank you in advance.

    Read the article

  • Merge Join component sorted outputs [SSIS]

    - by jamiet
    One question that I have been asked a few times of late in regard to performance tuning SSIS data flows is this: Why isn’t the Merge Join output sorted (i.e.IsSorted=True)? This is a fair question. After all both of the Merge Join inputs are sorted, hence why wouldn’t the output be sorted as well? Well here’s a little secret, the Merge Join output IS sorted! There’s a caveat though – it is only under certain circumstances and SSIS itself doesn’t do a good job of informing you of it. Let’s take a look at an example. Here we have a dataflow that consumes data from the [AdventureWorks2008].[Sales].[SalesOrderHeader] & [AdventureWorks2008].[Sales].[SalesOrderDetail] tables then joins them using a Merge Join component: Let’s take a look inside the editor of the Merge Join: We are joining on the [SalesOrderId] field (which is what the two inputs just happen to be sorted upon). We are also putting [SalesOrderHeader].[SalesOrderId] into the output. Believe it or not the output from this Merge Join component is sorted (i.e. has IsSorted=True) but unfortunately the Merge Join component does not have an Advanced Editor hence it is hidden away from us. There are a couple of ways to prove to you that is the case; I could open up the package XML inside the .dtsx file and show you the metadata but there is an easier way than that – I can attach a Sort component to the output. Take a look: Notice that the Sort component is attempting to sort on the [SalesOrderId] column. This gives us the following warning: Validation warning. DFT Get raw data: {992B7C9A-35AD-47B9-A0B0-637F7DDF93EB}: The data is already sorted as specified so the transform can be removed. The warning proves that the output from the Merge Join is sorted! It must be noted that the Merge Join output will only have IsSorted=True if at least one of the join columns is included in the output. So there you go, the Merge Join component can indeed produce a sorted output and that’s very useful in order to avoid unnecessary expensive Sort operations downstream. Hope this is useful to someone out there! @Jamiet  P.S. Thank you to Bob Bojanic on the SSIS product team who pointed this out to me!

    Read the article

< Previous Page | 313 314 315 316 317 318 319 320 321 322 323 324  | Next Page >