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  • Fetch multiple rows from SQL in PHP foreach item in array

    - by TrySpace
    I try to request an array of IDs, to return each row with that ID, and push each into an Array $finalArray But only the first result from the Query will output, and at the second foreach, it skips the while loop. I have this working in another script, so I don't understand where it's going wrong. The $arrayItems is an array containing: "home, info" $finalArray = array(); foreach ($arrayItems as $UID_get) { $Query = "SELECT * FROM items WHERE (uid = '" . cleanQuery($UID_get) . "' ) ORDER BY uid"; if($Result = $mysqli->query($Query)) { print_r($UID_get); echo "<BR><-><BR>"; while ($Row = $Result->fetch_assoc()) { array_push($finalArray , $Row); print_r($finalArray ); echo "<BR><><BR>"; } } else { echo '{ "returned" : "FAIL" }'; //. mysqli_connect_errno() . ' ' . mysqli_connect_error() . "<BR>"; } } (the cleanQuery is to escape and stripslashes) What I'm trying to get is an array of multiple rows (after i json_encoded it, like: {"finalArray" : { "home": {"id":"1","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"red\" }"} }, { "info": {"id":"2","created":"0000-00-00 00:00:00","css":"{ \"background-color\" : \"blue\" }"} } } But that's after I get both, or more results from the db. the print_r($UID_get); does print info, but then nothing.. So, why am I not getting the second row from info? I am essentially re-querying foreach $arrayItem right?

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  • PHP GD Incredibly Strange Problem

    - by ThinkingInBits
    if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { die("success"); } if ($img = imagecreatefromjpeg("/var/www/images/upload/1/1.jpg")) { $image_width = imagesx($img); $image_height = imagesy($img); $target_width = 150; $target_height = 150; if ($image_width > $image_height) { $percentage = ($target_width / $image_width); } else { $percentage = ($target_height / $image_height); } $new_image_width = round($image_width * $percentage); $new_image_height = round($image_height * $percentage); $imgResized = imagecreatetruecolor($new_image_width, $new_image_height); imagecopyresampled($imgResized, $img, 0, 0, 0, 0, $new_image_width, $new_image_height, $image_width, $image_height); imagejpeg($imgResized, $this->path, 100); imagedestroy($img); imagedestroy($imgResized); $this->storeThumbnailLocation(); } else { die ("image was not created or saved"); } The first if statement dies and echos success. If I take out the first if statement, the second one echos "image could not be created or saved" If honestly run out of ideas on this one, the code is identical

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  • PHP - BUG with filter_var and FILTER_VALIDATE_FLOAT

    - by Samuele
    I think there is a bug in this filter_var or maybe I'm doing something wrong: Try this: $options = array( 'options' => array( 'default' => 3, 'min_range' => 1000.0, 'max_range' => 5000.6, ) ); $VariableValue2 = 5698; $VariableValue4 = 5698.2; $chicco3 = filter_var($VariableValue2, FILTER_VALIDATE_INT, $options); $chicco4 = filter_var($VariableValue4, FILTER_VALIDATE_FLOAT, $options); It suppose to don't validate it... Infact the value: 5698 is greater than 5000.6!!!! But with FILTER_VALIDATE_INT it work FINE!! It return 3 that is the default value in case it don't validate it... PERFECT... Instead, with FILTER_VALIDATE_FLOAT it validate it... It return 5698.2!!! I'm doing something wrong??? Thank you to everybody... Samuele

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  • PHP or JS to connect with fingerprint scanner save to database

    - by narong
    I have a project to set profile user and save all data to database include fingerprint also. i don't what i should start, I have USB finger scanner already to test. What i think: i should have a input box to read data from USB finger scanner than i should create a function to upload it database. but with this thinking i meet problem: i don't know data that get from USB finger scanner is image or data? if image, how i can read it to input box to save to database ? Anyone have any idea, please share me to resolve it. I am looking to see your helping soon! thanks

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  • How to create PHP method linking?

    - by Kerry
    I've seen other objects that do this: $obj->method1()->method2(); How do I do that? Is each function just modifying the pointer of an object or returning a pointer? I don't know the proper term for this style -- if anyone could help me with that, it would be great.

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  • How to reformat date in PHP?

    - by Lisa
    I am pulling the dates of various posts from a database. The dates are in the following format: 2009-08-12 Numeric Year - Numeric Month - Numeric Day How can I reformat these dates to something more user friendly like: August 12, 2009 Numeric Month Numeric Date, Numeric Year Assuming that the date gotten from the mysql database is stored in a variable called: $date = $row['date_selected'];

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  • override __set in __construct() in php?

    - by user151841
    I have a class based on database values. I'm using __set to automatically sync database values with the class properties. Set checks an array of database fields that it is allowed to update in the database. The field 'id' isn't in the list, so __set will throw an exception if you try to do $objDbRow->id = 5;. However, there is one time when I do want to set the id property of the object, and that's on instantiation. So in __constuct, I have $this->id = $id (where $id is passed to __construct). However, __set seems to be intercepting the setting here, because an exception is being thrown on construction. What's the way to get around this? I suppose I also have a boolean flag, like $instantiated, that __set() would check before it does it's field whitelist checking. But that feels inelegant.

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  • Super fast getimagesize in php

    - by Sir Lojik
    Hi all, im trying to get image size(DIMENSIONS) of hundreds of remote images and getimagesize is way too slow. ive done some reading and found out the quickest way would be to use get_file_contents to read a certain aount of bytes from the images and examining the size within the binary data. Anyone attempted this before? How would i examine different formats. Seen any library for this? please let me know

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  • How to write ½ in php

    - by skarama
    Hi everyone, Quick question, how can I make this valid : if($this->datos->bathrooms == "1½"){$select1 = JText::_( 'selected="selected"' );} The ½ doesn't seem to be recognized. I tried to write it as &#189; but then it looks for &#189; literally, and not the ½ sign. Any ideas?

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  • PHP Session Array Value keeps showing as "Array"

    - by Nerathas
    Hello, When sending data from a form to a second page, the value of the session is always with the name "Array" insteed of the expected number. The data should get displayed in a table, but insteed of example 1, 2, 3 , 4 i get : Array, Array, Array. (A 2-Dimensional Table is used) Is the following code below a proper way to "call" upon the stored values on the 2nd page from the array ? $test1 = $_SESSION["table"][0]; $test2 = $_SESSION["table"][1]; $test3 = $_SESSION["table"][2]; $test4 = $_SESSION["table"][3]; $test5 = $_SESSION["table"][4]; What exactly is this, and how can i fix this? Is it some sort of override that needs to happen? Best Regards.

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  • PHP turn off errors - in one file only

    - by Industrial
    Hi! I am well aware about error_reporting(0); & ini_set('display_errors', "Off"); to make error messages go away. What would be an appropriate way to do this - for a specific file or part of code only? Surpressing errors with @'s seems like a bad idea since it apparently slows the code down... Thanks!

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  • php mysql , update query is not working

    - by Michael
    I'm trying to update some info into database but for some reasons it doesn't update. Also I'm not getting error in the server logs. mysql_query("UPDATE `view_item` SET `item_number` = $item_number, `title` = $title, `price` = $price, `shipping` = $shipping, `location` = $location, `start_time` = $start_time, `end_time` = $end_time, `seller_userName` = $seller_userName, `seller_UserNum` = $seller_UserNum, `number_of_bids` = $number_of_bids, `picture_link` = $picture_link WHERE `item_number` = $item_number");

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  • Simple PHP query question: LIKE

    - by pg
    When I replace $ordering = "apples, bananas, cranberries, grapes"; with $ordering = "apples, bananas, grapes"; I no longer want cranberries to be returned by my query, which I've written out like this: $query = "SELECT * from dbname where FruitName LIKE '$ordering'"; Of Course this doesn't work, because I used LIKE wrong. I've read through various manuals that describe how to use LIKE and it doesn't quite make sense to me. If I change the end of the db to "LIKE "apples"" that works for limiting it to just apples. Do I have to explode the ordering on the ", " or is there a way to do this in the query?

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  • PHP SimpleXML, how to set attributes ?

    - by Jahmaica
    Hi, if you've got something like, <hello id="1" name="myName1"> <anotherTag title="Hello"> </anotherTag> </hello> <hello id="2" name="myName2"> <anotherTag title="Hi"> </anotherTag> </hello> How to change the attributes of, for example, hello id 2, to name="William" ? Or the title hi to hello ? Thanks a lot for your atention, H'

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  • Php pi help... (Loops)

    - by James Rattray
    Is this iteration the best? (Pi^2)/12 = 1 - 1/4 + 1/9 - 1/16 + 1/25 etc. -For converging faster? If not please answer with the iteration -preferably in the form above (an example) -not a splat of algebra ... I'm doing this to find Pi to 1,000,000,000 places online.

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  • Need help with transferring data between MySQL db's using PHP

    - by JM4
    In one of the sites I manage, the client has decided to take on ACH/Bank Account administration where it was previously outsourced. As a result, the information submitted in our online form which used to simply store in a single database for processing now must sit in 'limbo' until the funds used for payment have been verified. My original plan is as follows: At the end of an enrollment, all form data is collected and stored in a single MySQL database. Our internal administrator will receive an email notification reminding him enrollments have taken place. He will process the ACH information collected and wait the 3-4 business days needed for payment to clear. Once the payment information has been returned as Good (haven't considered what I will do with the 'bad' yet), the administrator can log into a secure portal which allows him to click a button to 'process' the full information once compared and verified. the process is simplified as: Enrollment complete: data stored in DB 'A' Funds verified and link clicked: data from 'A' is copied to DB 'B' and 'A' is deleted. I have run similar processes with CSV output before and simply used //transfers old data to archive $transfer = mysql_query('INSERT INTO '.$archive.' SELECT * FROM '.$table) or die(mysql_error()); //empties existing table $query = mysql_query('TRUNCATE TABLE '.$table) or die(mysql_error()); but in those cases, ALL data returned was copied and deleted. I only want to copy and delete a single record. Any idea how to accomplish this?

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  • Speed up csv export when using php from mysql database query

    - by John
    Ok, so i've got a web system (built on codeigniter & running on mysql) that allows people to query a database of postal address data by making selections in a series of forms until they arrive at the selection that want, pretty standard stuff. They can then buy that information and download it via that system. The queries run very fast, but when it comes to applying that query to the database,and exporting it to csv, once the datasets get to around the 30,000 record mark (each row has around 40 columns of which about 20 are all populated with on average 20 chars of data per cell) it can take 5 or so minutes to export to csv. So, my question is, what is the main cause for the slowness? Is it that the resultset of data from the query is so large, that it is running into memory issues? Therefore should i allow much more memory to the process? Or, is there a much more efficient way of exporting to csv from a mysql query that i'm not doing? Should i save the contents of the query to a temp table and simply export the temp table to csv? Or am i going about this all wrong? Also, is the fact that i'm using Codeigniters Active Record for this prohibitive due to the way that it stores the resultset? Any advice is welcome! Thank you for reading!

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  • PHP Array - some further problems with displaying elements in the array

    - by Homer_J
    Hi again, Thanks in advance for the help. Here is my array based on $rowq: Array ( [0] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [1] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [2] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [3] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [4] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [5] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [6] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) [7] => Array ( [questions] => q8 [qnum] => 8 [qtext] => I know how what I do fits into my team's objectives [page] => 1 ) ) I would like to display elements of the array using (i think) the foreach statement but I can't get it working, ideally, I would like to echo something like this echo "<tr>".$rowq[qnum]." is the questions number and the question text is ".$rowq[qtext].". The page and q values are ".$rowq[page]." and ".$rowq[questions]." respectively."; And that link of text would appear how however many rows the array has in it. Any and all advice appreciated - I'm struggling like heck to get my head around multi-dimensional arrays :( Homer.

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  • PHP fails silently when function not defined?

    - by John Isaacks
    I am migrating from PHP4 to PHP5 I have this in my .htaccess: php_flag display_errors on php_value error_reporting 2039 Which used to show all errors. I am still getting some errors but I used to get an error when I called a function that was not defined, but now it stops where it is at and send the client everything up to the error and nothing after. With no error message. Here is what phpinfo is telling me: Directive Local Value Master Value display_errors On Off error_reporting 2039 6143 I would like to be able to see my error messages for trouble shooting purposes. Can someone tell me what I need to do? Thanks!!

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  • PHP IF statement not taking variable into account!

    - by Jess
    I have a tabled view in a while loop, where a user can view information on books. For example, book ISBN, book name, read status... Basically, when the user sets their 'readstatus' to 'complete' I want that specific table row to become grey! The logic is very straight forward, however I can't get my IF statement to recognise this: $readstatus = $_GET['readstatus']; if ($readstatus == 'complete') { echo '<tr class="completed">'; } else if ($readstatus != 'complete') { echo '<tr class="reading">'; } I'm obviously doing something wrong here, but all I need is the CSS class of the table row to change if the value of 'readstatus' = 'complete', if not, then output the default CSS table row color ('reading') Should I be putting $result as the variable or something? I have this coming just before my nested IF statement: $result = mysql_query($sql, $connection) or die ("Couldn't perform query $sql <br />".mysql_error()); while($row = mysql_fetch_array($result)) { ?>

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