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  • Weird ViewControllers - iPhone SDK

    - by Kevin
    Hello everyone, I have a Tab-Bar Application for this iPhone application I am making. I make a simple button on the 3rd view (3rd tab), and give it an IBAction to give an alert view. When I press build and go, everything works out fine. I go onto the 3rd tab, and I press my button. It simply crashes... Why is this happening? Everything I put in this 3rd tab crashes. I create a simple view controller, and write the class files to start over, but I keep getting the same errors.. Everything works fine on my first tab, where I originally got the first view controller.. P.S It also says Incomplete Implementation of Class 'ThirdViewController'. I don't know why its there.. If anyone can help me out here, i would greatly appreciate it. Kevin

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  • How do I write a spec to verify the rendering of partials?

    - by TheDeeno
    I'm using rr and rspec. Also, I'm using the collection short hand for partial rendering. My question: How do I correctly fill out the the following spec? before(:each) do assigns[:models] = Array.new(10, stub(Model)) end it "should render the 'listing' partial for each model" do # help me write something that actually verifies this end I've tried a few examples from the rspec book, rspec docs, and rr docs. Everything I try seems to leave me with runtime errors in the test - not failed assertions. Rather than show all the transformations I've tried, I figured all I'd need if someone showed me one that actually worked. I'd be good to go from there.

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  • ASP.NET MVC Newbie: why isn't my model available when creating a strongly-typed view?

    - by Rax Olgud
    I'm starting with ASP.NET MVC, and working with NerdDinner as reference. I did the following: Created a new project Added a couple of tables Created LINQ to SQL for them Created a new controller My Models directory now contains MyModel.dbml, under which I have MyModel.designer.cs, that contains classes for models relating to both of my tables (let's call them Categories and Products). Now, under my new controller, I would like to create a strongly typed view. So for example I have the following code in my controller (for my application I must work by name, and the "Name" field is unique): public ActionResult Details(string name) { MyModelDataContext db = new MyModelDataContext(); Product user = db.Products.Single(t => t.Name == name); return View(user); } I would like to create a strongly-typed view. So I right-click the line "return View(user)", and choose "Add View...". I click "Create a strongly-typed view". When I click the dropdown of "View data class", I don't see my models, but only: MyProject.Controllers.AccountMembershipService MyProject.Controllers.FormsAuthenticationService What am I missing?

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  • Problem bounding name to a class in Django

    - by martinthenext
    Hello! I've got a view function that has to decide which form to use depending on some conditions. The two forms look like that: class OpenExtraForm(forms.ModelForm): class Meta: model = Extra def __init__(self, *args, **kwargs): super(OpenExtraForm, self).__init__(*args, **kwargs) self.fields['opening_challenge'].label = "lame translation" def clean_opening_challenge(self): challenge = self.cleaned_data['opening_challenge'] if challenge is None: raise forms.ValidationError('??????? ???, ??????????? ?????? ???. ???????????') return challenge class HiddenExtraForm(forms.ModelForm): class Meta: model = Extra exclude = ('opening_challenge') def __init__(self, *args, **kwargs): super(HiddenExtraForm, self).__init__(*args, **kwargs) The view code goes like that: @login_required def manage_extra(request, extra_id=None, hidden=False): if not_admin(request.user): raise Http404 if extra_id is None: # Adding a new extra extra = Extra() if hidden: FormClass = HiddenExtraForm else: FormClass = OpenExtraForm else: # Editing an extra extra = get_object_or_404(Extra, pk=extra_id) if extra.is_hidden(): FromClass = HiddenExtraForm else: FormClass = OpenExtraForm if request.POST: form = FormClass(request.POST, instance=extra) if form.is_valid(): form.save() return HttpResponseRedirect(reverse(view_extra, args=[extra.id])) else: form = FormClass(instance=extra) return render_to_response('form.html', { 'form' : form, }, context_instance=RequestContext(request) ) The problem is somehow if extra.is_hidden() returns True, the statement FromClass = HiddenExtraForm doesn't work. I mean, in all other conditions that are used in the code it works fine: the correct Form classes are intantiated and it all works. But if extra.is_hidden(), the debugger shows that the condition is passed and it goes to the next line and does nothing! As a result I get a UnboundLocalVar error which says FormClass hasn't been asssigned at all. Any ideas on what's happening?

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  • Best way to create a preview functionality in rails

    - by slythic
    Hi all, I'm looking to implement a preview functionality in my posts scaffold. All I need to do is allow a user to enter information in the new view (/posts/new) and then replace the submit button with a preview button. Once the preview button is clicked, the user is routed to the preview page (probably /posts/new/preview). If the user wants to make a change they would click 'go back' or if they are happy with the post they can then submit the post. I found this article (http://eyedeal.team88.org/node/105) but it seems dated. Any ideas on what the best approach for this would be? Many thanks, Tony

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  • Online Sports betting website using Drupal

    - by Saurabh
    I wanted to know how suitable is Drupal for making a sports betting website similar to http://www.sportsinteraction.com/ . I am aware that there are modules like Bookmaker in Drupal which could help . However, I am puzzled about how to handle the user accounts can be extended to keep a track of the money in each individual account. Also I have with me betting scripts purchased from http://sportbettingscript.com/ . Can the same be integrated with Drupal? Wish to know your thoughts. Any help would be appreciated. Thanks.

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  • How do i create a view that can filter unique titles from a checkbox?

    - by buws
    I'm currently creating a view in Drupal that contains a number of fields. What I want to do is to create an exposed filter that is able to filter duplicate titles. The filter would be a checkbox. This is an example of the list NAME TIME RACE DISTANCE John Doe 2.07.54 Boston Marathon 42km Jane Boss 2.15.21 Boston Marathon 42km John Doe 2.02.22 Boston Marathon 42km Jane Boss 2.15.44 Boston Marathon 42km What I want to have is an exposed filter that only shows one unique NAME and sorts it by its best time. The resulting list would look as follows: NAME TIME RACE DISTANCE Jane Boss 2.15.21 Boston Marathon 42km John Doe 2.02.22 Boston Marathon 42km Any help is appreciated!

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  • Rails 3: How do I call a javascript function from a js.erb file

    - by user321775
    Now that I've upgraded to Rails 3, I'm trying to figure out the proper way to separate and reuse pieces of javascript. Here's the scenario I'm dealing with: I have a page with two areas: one with elements that should be draggable, the other with droppables. When the page loads I use jQuery to setup the draggables and droppables. Currently I have the script in the head portion of application.html.erb, which I'm sure is not the right solution but at least works. When I press a button on the page, an ajax call is made to my controller that replaces the draggables with a new set of elements that should also be draggable. I have a js.erb file that renders a partial in the correct location. After rendering I need to make the new elements draggable, so I'd like to reuse the code that currently lives in application.html.erb, but I haven't found the right way to do it. I can only make the new elements draggable by pasting the code directly into my js.erb file (yuck). What I'd like to have: - a javascript file that contains the functions prepdraggables() and prepdroppables() - a way to call either function from application.html.erb or from a js.erb file I've tried using :content_for to store and reuse the code, but can't seem to get it working correctly. What I currently have in the head section of application.html.erb <% content_for :drag_drop_prep do %> <script type="text/javascript" charset="utf-8"> $(document).ready(function () { // declare all DOM elements with class draggable to be draggable $( ".draggable" ).draggable( { revert : 'invalid' }); // declare all DOM elements with class legal to be droppable $(".legal").droppable({ hoverClass : 'legal_hover', drop : function(event, ui) { var c = new Object(); c['die'] = ui.draggable.attr("id"); c['cell'] = $(this).attr("id"); c['authenticity_token'] = encodeURIComponent(window._token); $.ajax({ type: "POST", url: "/placeDie", data: c, timeout: 5000 }); }}); }); </script> <% end %> undo.js.erb $("#board").html("<%= escape_javascript(render :partial => 'shared/board', :locals => { :playable => true, :restartable => !session[:challenge]}) %>") // This is where I want to prepare draggables. <%= javascript_include_tag "customdragdrop.js" %> // assuming this file had the draggables code from above in a prepdraggables() function prepdraggables();

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  • ASP.net MVC 2 SPARK - Create "Add New Item" link in spark page.

    - by KarlBear
    I have a web form in SPARK which allow the editing of a Facility class that contains Rooms. When editing the Facility all the Rooms are listed for editing too. The form works fine for editing, but I would like to include a button "Add Room" that adds a new blank room below the existing ones. Any idea how this is accomplished? Currently I am doing this in my SPARK page: [All the Facility editing stuff...] <p>Room</p> <div class="small">Enter the rooms associated with this facility.</div> <div class="add"> <div id="room"> <AddFacilityRoom each="var roomModel in Model.FacilityRooms" RoomModel="roomModel" Index="roomModelIndex" /> </div> <a id="addRoom" class="add" href="events/room/add.mvc">Add a room</a> </div> AddFacilityRoom contains the html elements for editing a room. I would like add.mvc to create a new empty Room class and inject a new identical (but empty) control below the existing ones. Currently, though it opens a new page when the "Add a Room" button is clicked.

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  • backbone model validation error

    - by koko
    I got a validation based on backbone fundamentals by addyosmani, but when i try it on my view i can't get the error that the model generated.TIA model.js validate: function(attrs) { var errors = this.errors = {}; if (!attrs.box) errors.box= 'box value is required'; //console.log(errors.box); if (!_.isEmpty(errors)) return errors; } view.js validate: function(model) { console.log("error text--" + model.errors[this.input] || ''); },

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  • CSS: Possible to define styles mid way through an html document?

    - by Dr. Zim
    In ASP.NET MVC, there are these snippets of html called view templates which appear when their matching data appears on the screen. For example, if you have a customer order and it has a vendor address, the vendor address view template shows up populated with data. Unfortunately, these don't have access to "MasterPages" nor are aware of their CSS surroundings. Instead of loading these up with style tags, is there any way to create partial CSS files that could work for that particular html snippet, a sort of in-line CSS style section? It would be really nice to plop this down just before we render the partial view: <style type="text/css"> input { margin: .2em .2em; overflow: hidden; width: 18.8em; height: 1.6em; border: 1px solid black;} </style> to have the 15 or so input fields in that particular Html snippet be formatted the same. These are swapped out, so the positions of the input fields change. This may also imply a CSS reset on each partial view.

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  • Locating file path from a <InMemoryUploadedFile> Djnago object

    - by PirosB3
    Hi all I have a Django app which, submitting a package, should return values that are inside it.. Submitted the form to a view called "insert": request.FILES['file'] returns the file objects, but it is of kind < InMemoryUploadedFile. What i need is a way to get the absolute path of the uploaded file, so that i can feed it to a method that will return the values needed Anyone know how i can accomplish this? Thanks

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  • MVC Partial View Postback - Jquery validation lost

    - by user415394
    I have a partial view which uses Jquery Valiation. This works OK when initially loaded, however after I do a ajax postback and return the partial view from the server with an error showing, the jquery validation seems to be lost. In that, if I delete a required field and hit save the partial view gets submitted, when I would expect it to show an error message and not get submitted. Does Jquery validation need to be initialised somehow for the form in the partial view?

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  • mysql select column from view problem

    - by haim evgi
    i create a view table like : CREATE VIEW ViewManager AS SELECT us.UserId AS 'Account Manager', ......... after that, when i run a query to select data from this view like : SELECT 'Account Manager' , .. from ViewManager then the data i get in this column is the text 'Account Manager' and not the value of the this columns. Is there a way to solve this ? Of course I can change the field name , but i want to know if there is another solution, thanks.

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  • make javascript repeat for each row in a view

    - by Kathy Chavez
    I have created a view in Drupal. I"m using javascript to modify css in each row. The script runs on the first row, but does not make the changes on the rest of rows from the view. This is the script: <script language="javascript" type="text/javascript"> window.onload = floatbr; function floatbr() { var f = document.getElementById('firstright') // Get div element var s = document.getElementById('secondright') // Get div element var w = document.getElementById('catwrapper') // Get div element var sh = s.offsetHeight // secondright div height var wh = w.offsetHeight // catwrapper div height f.style.height = wh - sh + 'px'; } </script> I'm using it from this page: http://agsone.100webcustomers.com/floatbottom.php having the script in the page once does not do the trick. having the script in the view footer and repeating the script does not work. THanks! link to fiddle with html, css & js: http://jsfiddle.net/Vvjku/

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  • How to return number of rows in the template

    - by xRobot
    In my view I return all posts of one blog: posts = Post.objects.filter(blog=blog) and pass it to context. But.. How can I get the number of posts in the template ? This is my template: <h1>Number of posts: {{ ??? }} </h1> {% for post in posts %} {{ post.title }} {{ post.body }} {% endfor %}

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  • How to handle model state errors in ajax-invoked controller action that returns a PartialView

    - by Robert Koritnik
    I have a POST controller action that returns a partial view. Everything seems really easy. but. I load it using $.ajax(), setting type as html. But when my model validation fails I thought I should just throw an error with model state errors. But my reply always returns 500 Server error. How can I report back model state errors without returning Json with whatever result. I would still like to return partial view that I can directly append to some HTML element. Edit I would also like to avoid returning error partial view. This would look like a success on the client. Having the client parse the result to see whether it's an actual success is prone to errors. Designers may change the partial view output and this alone would break the functionality. So I want to throw an exception, but with the correct error message returned to the ajax client.

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  • ASP.NET MVC - Combine Json result with ViewResult

    - by elado
    Can I return a Json result that contains also a rendered view? I need it to return the new ID of a submitted form along with its HTML and some other properties. Also that can be helpful when I need to return two (or more) view results from one action inside a Json object. Thanks!

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  • How do I attach a link (to a View) to an image in ASP.NET MVC?

    - by Ryan Pitts
    Ok, so here is my situation. I am creating a web application using ASP.NET MVC 2 using the C# language. I have programmed in HTML, CSS, and PHP for several years and I am very new to ASP.NET. The part that I am having trouble with is the image gallery. The setup: I have a link on the navigation bar that goes to a "Galleries" page. This page will show a list of galleries. Each gallery has a title, an image, and a description. All of this information is pulled from an XML file. I'm using the XML file like a database. I wanted to use this method so that i could easily update the list of galleries and have the updated XML file automatically be reflected by the website. Now, the galleries should link to an "Images" page. This page will display a list of images within the gallery based on what gallery was selected. This page will also pull from an XML file. The problem: I cannot seem to attach a dynamic link to the image? I am also stuck and not sure how to get the correct View to display. I know I need to do something with the controllers and models, right? I have some code if needed? I would greatly appreciate any help or direction for this! Thanks!

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  • Reading int from a hidden field in .aspx

    - by vikp
    Hi, I'm struggling to read an int from the hidden field on aspx page. <input type = "hidden" id = "myIntegerId" name = "integerId" value= "<%: Model.MyObjectId %>" runat = "server" /> The value is definately on the form, I can see it in the debugger and print it with <%: % When I read the form values in the controller, instead of an int I recieve a following string: <%: Model.MyObjectId % I have tried casting data in the hidden field to string and calling ToString() method on that field, neither has worked. The data is submitted using the post event. I have a feeling that I'm missing something very basic... Any help is greately appreciated. Thanks

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  • Partial view postback from a standard Html form with MVC

    - by fearofawhackplanet
    I have a file upload button on my MVC view. After the file is uploaded, my FileList partial view on the page should refresh. I tried to upload with Ajax.BeginForm(), but have discovered that Ajax will not submit file data. I've got the file upload working now by using the jQuery Form plugin, which lets you ajaxify the normal Html.BeginForm() submit method. Is is still possible to trigger the partial page update using this method?

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