Search Results

Search found 52589 results on 2104 pages for 'read table'.

Page 322/2104 | < Previous Page | 318 319 320 321 322 323 324 325 326 327 328 329  | Next Page >

  • Trying to packetize TCP with non-blocking IO is hard! Am I doing something wrong?

    - by Ricket
    Oh how I wish TCP was packet-based like UDP is! But alas, that's not the case, so I'm trying to implement my own packet layer. Here's the chain of events so far (ignoring writing packets) Oh, and my Packets are very simply structured: two unsigned bytes for length, and then byte[length] data. (I can't imagine if they were any more complex, I'd be up to my ears in if statements!) Server is in an infinite loop, accepting connections and adding them to a list of Connections. PacketGatherer (another thread) uses a Selector to figure out which Connection.SocketChannels are ready for reading. It loops over the results and tells each Connection to read(). Each Connection has a partial IncomingPacket and a list of Packets which have been fully read and are waiting to be processed. On read(): Tell the partial IncomingPacket to read more data. (IncomingPacket.readData below) If it's done reading (IncomingPacket.complete()), make a Packet from it and stick the Packet into the list waiting to be processed and then replace it with a new IncomingPacket. There are a couple problems with this. First, only one packet is being read at a time. If the IncomingPacket needs only one more byte, then only one byte is read this pass. This can of course be fixed with a loop but it starts to get sorta complicated and I wonder if there is a better overall way. Second, the logic in IncomingPacket is a little bit crazy, to be able to read the two bytes for the length and then read the actual data. Here is the code, boiled down for quick & easy reading: int readBytes; // number of total bytes read so far byte length1, length2; // each byte in an unsigned short int (see getLength()) public int getLength() { // will be inaccurate if readBytes < 2 return (int)(length1 << 8 | length2); } public void readData(SocketChannel c) { if (readBytes < 2) { // we don't yet know the length of the actual data ByteBuffer lengthBuffer = ByteBuffer.allocate(2 - readBytes); numBytesRead = c.read(lengthBuffer); if(readBytes == 0) { if(numBytesRead >= 1) length1 = lengthBuffer.get(); if(numBytesRead == 2) length2 = lengthBuffer.get(); } else if(readBytes == 1) { if(numBytesRead == 1) length2 = lengthBuffer.get(); } readBytes += numBytesRead; } if(readBytes >= 2) { // then we know we have the entire length variable // lazily-instantiate data buffers based on getLength() // read into data buffers, increment readBytes // (does not read more than the amount of this packet, so it does not // need to handle overflow into the next packet's data) } } public boolean complete() { return (readBytes > 2 && readBytes == getLength()+2); } Basically I need feedback on my code. Please suggest any improvements. Even overhauling my entire system would be okay, if you have suggestions for how better to implement the whole thing. Book recommendations are welcome too; I love books. I just get the feeling that something isn't quite right.

    Read the article

  • Missing Operating System after trying to upgrade to Ubuntu 11

    - by Mauricio
    there! After trying to upgrade from Ubuntu 10.04 to 11, the upgrading process stopped when running and then I got an "out of disk, grub rescue" message when booting. After running Boot Repair, I got this results. Now I get "Missing Operating System" whent trying to boot. Bellow I show some results from some commands I gather from help foruns, but I still reached no solution. Could you please help me? Any enlightment will be very helpful! Disk Utility says "Disk has a few bad sectors". When trying to run the Self-test I get "FAILED (Read)" Here we have what Gparted says about the /dev/sda1 partition (ext4): Flags: boot Status: not mounted Warning: e2label: Attempt to read block from filesystem resulted in short read while trying to open /dev/sda1Couldn`t find valid filesystem superblockUnable to read the contents of this filesystem! From sudo fdisk -lI got: Disk /dev/sda: 320.1 GB, 320072933376 bytes 255 heads, 63 sectors/track, 38913 cylinders, total 625142448 sectorsUnits = sectors of 1 * 512 = 512 bytesSector size (logical/physical): 512 bytes / 512 bytesI/O size (minimum/optimal): 512 bytes / 512 bytesDisk identifier: 0x000e0596 Device Boot Start End Blocks Id System/dev/sda1 * 2048 607428607 303713280 83 Linux/dev/sda2 607430654 625141759 8855553 5 Extended/dev/sda5 607430656 625141759 8855552 82 Linux swap / SolarisDisk /dev/sdb: 320.1 GB, 320072933376 bytes255 heads, 63 sectors/track, 38913 cylinders, total 625142448 sectorsUnits = sectors of 1 * 512 = 512 bytesSector size (logical/physical): 512 bytes / 512 bytesI/O size (minimum/optimal): 512 bytes / 512 bytes Disk identifier: 0x000c3c41 Device Boot Start End Blocks Id System /dev/sdb1 * 63 625137344 312568641 c W95 FAT32 (LBA) " and fromsudo fdisk /dev/sda1I got fdisk: unable to read /dev/sda1: Inappropriate ioctl for device` From sudo mount /dev/sda1 /mntI got: mount: wrong fs type, bad option, bad superblock on /dev/sda1, missing codepage or helper program, or other error In some cases useful info is found in syslog - try dmesg | tail or so From sudo update-grubI got: error: cannot read from `/dev/sda'. /usr/sbin/grub-probe: error: cannot find a device for / (is /dev mounted?).

    Read the article

  • Ubuntu 12.10 loud fan noise hp compaq 615

    - by Levente Nagy
    I am totally new to Linux, i installed it yesterday, since than i my fans are really loud, i did not have this problem on windows. I saw this post on this site How to control fan speed? But i am totally lost with it because im a new user to Ubuntu when i arrive to that page i see these lucid (utils): utilities to read temperature/voltage/fan sensors 1:3.1.2-2: all precise (utils): utilities to read temperature/voltage/fan sensors [universe] 1:3.3.1-2ubuntu1: all quantal (utils): utilities to read temperature/voltage/fan sensors [universe] 1:3.3.1-2ubuntu2: all raring (utils): utilities to read temperature/voltage/fan sensors [universe] 1:3.3.2-2ubuntu1: all saucy (utils): utilities to read temperature/voltage/fan sensors [universe] 1:3.3.3-1ubuntu1: all trusty (utils): utilities to read temperature/voltage/fan sensors [universe] 1:3.3.3-1ubuntu1: all So what is lucid? trusty? saucy? and other? i thought its some kind if a ubuntu type (sorry for beeing silly here) i checked my ubuntu version it just says Ubuntu 12.10 So which one i need to download? I saw there are terminal commands, im new to that too, will it cause some problem if i just copy and paste? PS: I saw my graphics card is undetected as well i have a ATI Mobility radeon HD 3200, could that cause the problem too?

    Read the article

  • C++ Numerical Recipes &ndash; A New Adventure!

    - by JoshReuben
    I am about to embark on a great journey – over the next 6 weeks I plan to read through C++ Numerical Recipes 3rd edition http://amzn.to/YtdpkS I'll be reading this with an eye to C++ AMP, thinking about implementing the suitable subset (non-recursive, additive, commutative) to run on the GPU. APIs supporting HPC, GPGPU or MapReduce are all useful – providing you have the ability to choose the correct algorithm to leverage on them. I really think this is the most fascinating area of programming – a lot more exciting than LOB CRUD !!! When you think about it , everything is a function – we categorize & we extrapolate. As abstractions get higher & less leaky, sooner or later information systems programming will become a non-programmer task – you will be using WYSIWYG designers to build: GUIs MVVM service mapping & virtualization workflows ORM Entity relations In the data source SharePoint / LightSwitch are not there yet, but every iteration gets closer. For information workers, managed code is a race to the bottom. As MS futures are a bit shaky right now, the provider agnostic nature & higher barriers of entry of both C++ & Numerical Analysis seem like a rational choice to me. Its also fascinating – stepping outside the box. This is not the first time I've delved into numerical analysis. 6 months ago I read Numerical methods with Applications, which can be found for free online: http://nm.mathforcollege.com/ 2 years ago I learned the .NET Extreme Optimization library www.extremeoptimization.com – not bad 2.5 years ago I read Schaums Numerical Analysis book http://amzn.to/V5yuLI - not an easy read, as topics jump back & forth across chapters: 3 years ago I read Practical Numerical Methods with C# http://amzn.to/V5yCL9 (which is a toy learning language for this kind of stuff) I also read through AI a Modern Approach 3rd edition END to END http://amzn.to/V5yQSp - this took me a few years but was the most rewarding experience. I'll post progress updates – see you on the other side !

    Read the article

  • Managing arbitrary user permissions under PureFTPd

    - by Sebastián Grignoli
    I need to provide an FTP service that needs to be web-managed in the simplest way possible. My customer wants to create folders and users, and give them read only or read/write access arbitrarily. For example: The folder 'Documents' should be read only for several users, writable for internal users, and invisible for the rest. The folder 'Pictures' should be read only for journalists, writable for associates, and invisible for the rest. The folder 'Media' should be read only, writable or invisible for arbitrary users specified on the admin. There could be a large number of users and folders. I can't find a good way to accomplish that. I thought that I could give each user a home folder and put symlinks for the folders he has read access to, and make the user part of the folder's group when he has write access too, but now I think that this wouldn't work, because with PureFTPd (or ProFTPd) I can only specify the virtual user's mapping to a system user, and only one GUID for each virtual user. My approach requires that I could specify several GUIDs for each user (one by each folder he has write access to). I need to start programming this admin and I still don't know wich approach would work, if any. ¿Any ideas?

    Read the article

  • failbit is being set and I can't figure out why

    - by felipedrl
    I'm writing a MIDI file loader. Everything is going fine until at some track I get a failbit exception while trying to read from file. I can't figure out why, I've checked the file size and it's ok too. Upon checking "errno" and it returns "0". Any ideas? Thanks. The snippet follows: file.read(reinterpret_cast<char*>(&mHeader.id), sizeof(MidiHeader)); mTracks = new MidiTrack[mHeader.nTracks]; for (uint i = 0; i < mHeader.nTracks; ++i) { // this read fails on 6th i. I've checked hexadecimal file and it's // ok so far. file.read(reinterpret_cast<char*>(&mTracks[i].id), sizeof(uint)); if (file.fail()) { std::cerr << errno << std::endl; massert(false); } massert(mTracks[i].id == 0x6B72544D); file.read(reinterpret_cast<char*>(&mTracks[i].size), sizeof(uint)); mTracks[i].size = swapBytes(mTracks[i].size); mTracks[i].data = new char[mTracks[i].size]; file.read(mTracks[i].data, mTracks[i].size * sizeof(char)); totalBytesRead += 8 + mTracks[i].size; massert(totalBytesRead <= fileSize); }

    Read the article

  • How to delete just one LINE of text (NOT a table-row!) with a single KEYBOARD shortcut in Microsoft Office Word 2010?

    - by Sk8erPeter
    Are there any shortcuts to delete just one row (which is NOT a table row, just a single row in a text) in Microsoft Office Word 2010? If not, how can I assign one to do it? In worst case, can I make a macro (in VB) which could do the same with a custom shortcut? To clarify my problem: I would like to avoid multiple clicks and/or pushing multiple buttons, even if I click in the middle of the line of text. :) For example, in Notepad++ I can delete the entire current line with Ctrl+L, in NetBeans, I can delete an entire line with Ctrl+E, in Eclipse, I can delete current line with Ctrl+D, etc., where it doesn't really matter where my mouse cursor is actually... so there are these simple solutions, which I look for in Word too. It really would simplify my work in huge documents.

    Read the article

  • eBooks on iPad vs. Kindle: More Debate than Smackdown

    - by andrewbrust
    When the iPad was presented at its San Francisco launch event on January 28th, Steve Jobs spent a significant amount of time explaining how well the device would serve as an eBook reader. He showed the iBooks reader application and iBookstore and laid down the gauntlet before Amazon and its beloved Kindle device. Almost immediately afterwards, criticism came rushing forth that the iPad could never beat the Kindle for book reading. The curious part of that criticism is that virtually no one offering it had actually used the iPad yet. A few weeks later, on April 3rd, the iPad was released for sale in the United States. I bought one on that day and in the few additional weeks that have elapsed, I’ve given quite a workout to most of its capabilities, including its eBook features. I’ve also spent some time with the Kindle, albeit a first-generation model, to see how it actually compares to the iPad. I had some expectations going in, but I came away with conclusions about each device that were more scenario-based than absolute. I present my findings to you here.   Vital Statistics Let’s start with an inventory of each device’s underlying technology. The iPad has a color, backlit LCD screen and an on-screen keyboard. It has a battery which, on a full charge, lasts anywhere from 6-10 hours. The Kindle offers a monochrome, reflective E Ink display, a physical keyboard and a battery that on my first gen loaner unit can go up to a week between charges (Amazon claims the battery on the Kindle 2 can last up to 2 weeks on a single charge). The Kindle connects to Amazon’s Kindle Store using a 3G modem (the technology and network vary depending on the model) that incurs no airtime service charges whatsoever. The iPad units that are on-sale today work over WiFi only. 3G-equipped models will be on sale shortly and will command a $130 premium over their WiFi-only counterparts. 3G service on the iPad, in the U.S. from AT&T, will be fee-based, with a 250MB plan at $14.99 per month and an unlimited plan at $29.99. No contract is required for 3G service. All these tech specs aside, I think a more useful observation is that the iPad is a multi-purpose Internet-connected entertainment device, while the Kindle is a dedicated reading device. The question is whether those differences in design and intended use create a clear-cut winner for reading electronic publications. Let’s take a look at each device, in isolation, now.   Kindle To me, what’s most innovative about the Kindle is its E Ink display. E Ink really looks like ink on a sheet of paper. It requires no backlight, it’s fully visible in direct sunlight and it causes almost none of the eyestrain that LCD-based computer display technology (like that used on the iPad) does. It’s really versatile in an all-around way. Forgive me if this sounds precious, but reading on it is really a joy. In fact, it’s a genuinely relaxing experience. Through the Kindle Store, Amazon allows users to download books (including audio books), magazines, newspapers and blog feeds. Books and magazines can be purchased either on a single-issue basis or as an annual subscription. Books, of course, are purchased singly. Oddly, blogs are not free, but instead carry a monthly subscription fee, typically $1.99. To me this is ludicrous, but I suppose the free 3G service is partially to blame. Books and magazine issues download quickly. Magazine and blog subscriptions cause new issues or posts to be pushed to your device on an automated basis. Available blogs include 9000-odd feeds that Amazon offers on the Kindle Store; unless I missed something, arbitrary RSS feeds are not supported (though there are third party workarounds to this limitation). The shopping experience is integrated well, has an huge selection, and offers certain graphical perks. For example, magazine and newspaper logos are displayed in menus, and book cover thumbnails appear as well. A simple search mechanism is provided and text entry through the physical keyboard is relatively painless. It’s very easy and straightforward to enter the store, find something you like and start reading it quickly. If you know what you’re looking for, it’s even faster. Given Kindle’s high portability, very reliable battery, instant-on capability and highly integrated content acquisition, it makes reading on whim, and in random spurts of downtime, very attractive. The Kindle’s home screen lists all of your publications, and easily lets you select one, then start reading it. Once opened, publications display in crisp, attractive text that is adjustable in size. “Turning” pages is achieved through buttons dedicated to the task. Notes can be recorded, bookmarks can be saved and pages can be saved as clippings. I am not an avid book reader, and yet I found the Kindle made it really fun, convenient and soothing to read. There’s something about the easy access to the material and the simplicity of the display that makes the Kindle seduce you into chilling out and reading page after page. On the other hand, the Kindle has an awkward navigation interface. While menus are displayed clearly on the screen, the method of selecting menu items is tricky: alongside the right-hand edge of the main display is a thin column that acts as a second display. It has a white background, and a scrollable silver cursor that is moved up or down through the use of the device’s scrollwheel. Picking a menu item on the main display involves scrolling the silver cursor to a position parallel to that menu item and pushing the scrollwheel in. This navigation technique creates a disconnect, literally. You don’t really click on a selection so much as you gesture toward it. I got used to this technique quickly, but I didn’t love it. It definitely created a kind of anxiety in me, making me feel the need to speed through menus and get to my destination document quickly. Once there, I could calm down and relax. Books are great on the Kindle. Magazines and newspapers much less so. I found the rendering of photographs, and even illustrations, to be unacceptably crude. For this reason, I expect that reading textbooks on the Kindle may leave students wanting. I found that the original flow and layout of any publication was sacrificed on the Kindle. In effect, browsing a magazine or newspaper was almost impossible. Reading the text of individual articles was enjoyable, but having to read this way made the whole experience much more “a la carte” than cohesive and thematic between articles. I imagine that for academic journals this is ideal, but for consumer publications it imposes a stripped-down, low-fidelity experience that evokes a sense of deprivation. In general, the Kindle is great for reading text. For just about anything else, especially activity that involves exploratory browsing, meandering and short-attention-span reading, it presents a real barrier to entry and adoption. Avid book readers will enjoy the Kindle (if they’re not already). It’s a great device for losing oneself in a book over long sittings. Multitaskers who are more interested in periodicals, be they online or off, will like it much less, as they will find compromise, and even sacrifice, to be palpable.   iPad The iPad is a very different device from the Kindle. While the Kindle is oriented to pages of text, the iPad orbits around applications and their interfaces. Be it the pinch and zoom experience in the browser, the rich media features that augment content on news and weather sites, or the ability to interact with social networking services like Twitter, the iPad is versatile. While it shares a slate-like form factor with the Kindle, it’s effectively an elegant personal computer. One of its many features is the iBook application and integration of the iBookstore. But it’s a multi-purpose device. That turns out to be good and bad, depending on what you’re reading. The iBookstore is great for browsing. It’s color, rich animation-laden user interface make it possible to shop for books, rather than merely search and acquire them. Unfortunately, its selection is rather sparse at the moment. If you’re looking for a New York Times bestseller, or other popular titles, you should be OK. If you want to read something more specialized, it’s much harder. Unlike the awkward navigation interface of the Kindle, the iPad offers a nearly flawless touch-screen interface that seduces the user into tinkering and kibitzing every bit as much as the Kindle lulls you into a deep, concentrated read. It’s a dynamic and interactive device, whereas the Kindle is static and passive. The iBook reader is slick and fun. Use the iPad in landscape mode and you can read the book in 2-up (left/right 2-page) display; use it in portrait mode and you can read one page at a time. Rather than clicking a hardware button to turn pages, you simply drag and wipe from right-to-left to flip the single or right-hand page. The page actually travels through an animated path as it would in a physical book. The intuitiveness of the interface is uncanny. The reader also accommodates saving of bookmarks, searching of the text, and the ability to highlight a word and look it up in a dictionary. Pages display brightly and clearly. They’re easy to read. But the backlight and the glare made me less comfortable than I was with the Kindle. The knowledge that completely different applications (including the Web and email and Twitter) were just a few taps away made me antsy and very tempted to task-switch. The knowledge that battery life is an issue created subtle discomfort. If the Kindle makes you feel like you’re in a library reading room, then the iPad makes you feel, at best, like you’re under fluorescent lights at a Barnes and Noble or Borders store. If you’re lucky, you’d be on a couch or at a reading table in the store, but you might also be standing up, in the aisles. Clearly, I didn’t find this conducive to focused and sustained reading. But that may have more to do with my own tendency to read periodicals far more than books, and my neurotic . And, truth be known, the book reading experience, when not explicitly compared to Kindle’s, was still pleasant. It is also important to point out that Kindle Store-sourced books can be read on the iPad through a Kindle reader application, from Amazon, specific to the device. This offered a less rich experience than the iBooks reader, but it was completely adequate. Despite the Kindle brand of the reader, however, it offered little in terms of simulating the reading experience on its namesake device. When it comes to periodicals, the iPad wins hands down. Magazines, even if merely scanned images of their print editions, read on the iPad in a way that felt similar to reading hard copy. The full color display, touch navigation and even the ability to render advertisements in their full glory makes the iPad a great way to read through any piece of work that is measured in pages, rather than chapters. There are many ways to get magazines and newspapers onto the iPad, including the Zinio reader, and publication-specific applications like the Wall Street Journal’s and Popular Science’s. The New York Times’ free Editors’ Choice application offers a Times Reader-like interface to a subset of the Gray Lady’s daily content. The completely Web-based but iPad-optimized Times Skimmer site (at www.nytimes.com/timesskimmer) works well too. Even conventional Web sites themselves can be read much like magazines, given the iPad’s ability to zoom in on the text and crop out advertisements on the margins. While the Kindle does have an experimental Web browser, it reminded me a lot of early mobile phone browsers, only in a larger size. For text-heavy sites with simple layout, it works fine. For just about anything else, it becomes more trouble than it’s worth. And given the way magazine articles make me think of things I want to look up online, I think that’s a real liability for the Kindle.   Summing Up What I came to realize is that the Kindle isn’t so much a computer or even an Internet device as it is a printer. While it doesn’t use physical paper, it still renders its content a page at a time, just like a laser printer does, and its output appears strikingly similar. You can read the rendered text, but you can’t interact with it in any way. That’s why the navigation requires a separate cursor display area. And because of the page-oriented rendering behavior, turning pages causes a flash on the display and requires a sometimes long pause before the next page is rendered. The good side of this is that once the page is generated, no battery power is required to display it. That makes for great battery life, optimal viewing under most lighting conditions (as long as there is some light) and low-eyestrain text-centric display of content. The Kindle is highly portable, has an excellent selection in its store and is refreshingly distraction-free. All of this is ideal for reading books. And iPad doesn’t offer any of it. What iPad does offer is versatility, variety, richness and luxury. It’s flush with accoutrements even if it’s low on focused, sustained text display. That makes it inferior to the Kindle for book reading. But that also makes it better than the Kindle for almost everything else. As such, and given that its book reading experience is still decent (even if not superior), I think the iPad will give Kindle a run for its money. True book lovers, and people on a budget, will want the Kindle. People with a robust amount of discretionary income may want both devices. Everyone else who is interested in a slate form factor e-reading device, especially if they also wish to have leisure-friendly Internet access, will likely choose the iPad exclusively. One thing is for sure: iPad has reduced Kindle’s market, and may have shifted its mass market potential to a mere niche play. If Amazon is smart, it will improve its iPad-based Kindle reader app significantly. It can then leverage the iPad channel as a significant market for the Kindle Store. After all, selling the eBooks themselves is what Amazon should care most about.

    Read the article

  • DB2 Integrity Checks and Exception Tables

    - by imthefirestartr
    I am working on planning a migration of a DB2 8.1 database from a horrible IBM encoding to UTF-8 to support further languages etc. I am encountering an issue that I am stuck on. A few notes on this migration: We are using db2move to export and load the data and db2look to get the details fo the database (tablespaces, tables, keys etc). We found the loading process worked nicely with db2move import, however, the data takes 7 hours to load and this was unacceptable downtime when we actually complete the conversion on the main database. We are now using db2move load, which is much faster as it seems to simply throw the data in without integrity checks. Which leads to my current issue. After completing the db2move load process, several tables are in a check pending state and require integrity checks. Integrity checks are done via the following: set integrity for . immediate checked This works for most tables, however, some tables give an error: DB21034E The command was processed as an SQL statement because it was not a valid Command Line Processor command. During SQL processing it returned: SQL3603N Check data processing through the SET INTEGRITY statement has found integrity violation involving a constraint with name "blah.SQL120124110232400". SQLSTATE=23514 The internets tell me that the solution to this issue is to create an exception table based on the actual table and tell the SET INTEGRITY command to send any exceptions to that table (as below): db2 create table blah_EXCEPTION like blah db2 SET INTEGRITY FOR blah IMMEDIATE CHECKED FOR EXCEPTION IN blah USE blah_EXCEPTION NOW, here is the specific issue I am having! The above forces all the rows with issues to the specified exception table. Well that's just super, buuuuuut I can not lose data in this conversion, its simply unacceptable. The internets and IBM has a vague description of sending the violations to the exception tables and then "dealing with the data" that is in the exception table. Unfortunately, I am not clear what this means and I was hoping that some wise individual knows and could help me out and let me know how I can retrieve this data from these tables and place the data in the original/proper table rather than these exception tables. Let me know if you have any questions. Thanks!

    Read the article

  • RUBY Nokogiri CSS HTML Parsing

    - by user296507
    I'm having some problems trying to get the code below to output the data in the format that I want. What I'm after is the following: CCC1-$5.00 CCC1-$10.00 CCC1-$15.00 CCC2-$7.00 where $7 belongs to CCC2 and the others to CCC1, but I can only manage to get the data in this format: CCC1-$5.00 CCC1-$10.00 CCC1-$15.00 CCC1-$7.00 CCC2-$5.00 CCC2-$10.00 CCC2-$15.00 CCC2-$7.00 Any help would be appreciated. require 'rubygems' require 'nokogiri' require 'open-uri' doc = Nokogiri::HTML.parse(<<-eohtml) <div class="AAA"> <table cellspacing="0" cellpadding="0" border="0" summary="sum"> <tbody> <tr> <td class="BBB"> <span class="CCC">CCC1</span> </td> <td class="DDD"> <table cellspacing="0" cellpadding="0" border="0"> <tbody> <tr><td class="FFF">$5.00</td></tr> <tr><td class="FFF">$10.00</td></tr> <tr><td class="FFF">$15.00</td></tr> </tbody> </table> </td> </tr> </tbody> </table> <table cellspacing="0" cellpadding="0" border="0" summary="sum"> <tbody> <tr> <td class="BBB"> <span class="CCC">CCC2</span> </td> <td class="DDD"> <table cellspacing="0" cellpadding="0" border="0"> <tbody> <tr><td class="FFF">$7.00</td></tr> </tbody> </table> </td> </tr> </tbody> </table> </div> eohtml doc.css('td.BBB > span.CCC').each do |something| doc.css('tr > td.EEE, tr > td.FFF').each do |something_more| puts something.content + '-'+ something_more.content end end

    Read the article

  • MSSQL: How to copy a file (pdf, doc, txt...) stored in a varbinary(max) field to a file in a CLR sto

    - by user193655
    I ask this question as a followup of this question. A solution that uses bcp and xp_cmdshell, that is not my desired solution, has been posted here: stackoverflow.com/questions/828749/ms-sql-server-2005-write-varbinary-to-file-system (sorry i cannot post a second hyperlink since my reputation is les than 10). I am new to c# (since I am a Delphi developer) anyway I was able to create a simple CLR stored procedures by following a tutorial. My task is to move a file from the client file system to the server file system (the server can be accessed using remote IP, so I cannot use a shared folder as destination, this is why I need a CLR stored procedure). So I plan to: 1) store from Delphi the file in a varbinary(max) column of a temporary table 2) call the CLR stored procedure to create a file at the desired path using the data contained in the varbinary(max) field Imagine I need to move C:\MyFile.pdf to Z:\MyFile.pdf, where C: is a harddrive on local system and Z: is an harddrive on the server. I provide the code below (not working) that someone can modify to make it work? Here I suppose to have a table called MyTable with two fields: ID (int) and DATA (varbinary(max)). Please note it doesn't make a difference if the table is a real temporary table or just a table where I temporarly store the data. I would appreciate if some exception handling code is there (so that I can manage an "impossible to save file" exception). I would like to be able to write a new file or overwrite the file if already existing. [Microsoft.SqlServer.Server.SqlProcedure] public static void VarbinaryToFile(int TableId) { using (SqlConnection connection = new SqlConnection("context connection=true")) { connection.Open(); SqlCommand command = new SqlCommand("select data from mytable where ID = @TableId", connection); command.Parameters.AddWithValue("@TableId", TableId); // This was the sample code I found to run a query //SqlContext.Pipe.ExecuteAndSend(command); // instead I need something like this (THIS IS META_SYNTAX!!!): SqlContext.Pipe.ResultAsStream.SaveToFile('z:\MyFile.pdf'); } } (one subquestion is: is this approach coorect or there is a way to directly pass the data to the CLR stored procedure so I don't need to use a temp table?) If the subquestion's answer is No, could you describe the approach of avoiding a temp table? So is there a better way then the one I describe above (=temp table + Stored procedure)? A way to directly pass the dataastream from the client application to the CLR stored procedure? (my files can be any size but also very big)

    Read the article

  • Reorder cells in a UITableView without displaying a "delete" button

    - by iter
    I want to be able to reorder cells in a table, but not to delete or insert them. I want a picture like this: This image appears in Apple's Table View Programming Guige, but the code samples there produce a table with red "delete" buttons when the table goes into editing mode. I can set editingStyleForRowAtIndexPath to UITableViewCellEditingStyleNone and that makes the delete buttons go away, but the rows are still indented as if to make room for these buttons.

    Read the article

  • What is wrong with my PHP/MySQL code?

    - by James
    I am building a navigation menu which lists all my categories and subcategories. The problem is it returns only one of these and not all. I have the categories echoed inside the while loop so I'm not sure why it's only showing one result and not all: <?php $query = mysql_query("SELECT * FROM categories_parent"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; $childStatus = $row['child_status']; // if has child categories if ($childStatus == "1") { echo "<li class='dir'><a href='category.php?slug=$slug'>$name</a>"; echo "<ul id='dropdown'>"; $query = mysql_query("SELECT * FROM categories_child WHERE parent=$id"); while ($row = mysql_fetch_assoc($query)) { $id = $row['id']; $name = $row['name']; $slug = $row['slug']; echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } echo "</ul>"; echo "</li>"; } // if singular parent else { echo "<li><a href='category.php?slug=$slug'>$name</a></li>"; } } ?> My database tables: -- -- Table structure for table `categories_child` -- CREATE TABLE IF NOT EXISTS `categories_child` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `parent` int(11) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_child` -- INSERT INTO `categories_child` (`id`, `name`, `slug`, `parent`) VALUES (138, 'Britney Spears', 'category/celiberties/britney-spears/', 137), (136, 'Tigers', 'category/animals/tigers/', 136), (137, 'Horses', 'category/animals/horses/', 136), (135, 'Lions', 'category/animals/lions/', 136); -- -- Table structure for table `categories_parent` -- CREATE TABLE IF NOT EXISTS `categories_parent` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(1000) NOT NULL, `slug` varchar(1000) NOT NULL, `child_status` int(1) NOT NULL DEFAULT '0', PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=139 ; -- -- Dumping data for table `categories_parent` -- INSERT INTO `categories_parent` (`id`, `name`, `slug`, `child_status`) VALUES (137, 'Celiberties', 'category/celiberties/', 1), (138, 'TV Shows', 'category/tv-shows/', 0), (136, 'Animals', 'category/animals/', 1);

    Read the article

  • Why does fprintf start printing out of order or not at all?

    - by Steve Melvin
    This code should take an integer, create pipes, spawn two children, wait until they are dead, and start all over again. However, around the third time around the loop I lose my prompt to enter a number and it no longer prints the number I've entered. Any ideas? #include <stdio.h> #include <stdlib.h> #include <unistd.h> #include <errno.h> #define WRITE 1 #define READ 0 int main (int argc, const char * argv[]) { //Pipe file-descriptor array unsigned int isChildA = 0; int pipeA[2]; int pipeB[2]; int num = 0; while(1){ fprintf(stderr,"Enter an integer: "); scanf("%i", &num); if(num == 0){ fprintf(stderr,"You entered zero, exiting...\n"); exit(0); } //Open Pipes if(pipe(pipeA) < 0){ fprintf(stderr,"Could not create pipe A.\n"); exit(1); } if(pipe(pipeB) < 0){ fprintf(stderr,"Could not create pipe B.\n"); exit(1); } fprintf(stderr,"Value read: %i \n", num); fprintf(stderr,"Parent PID: %i\n", getpid()); pid_t procID = fork(); switch (procID) { case -1: fprintf(stderr,"Fork error, quitting...\n"); exit(1); break; case 0: isChildA = 1; break; default: procID = fork(); if (procID<0) { fprintf(stderr,"Fork error, quitting...\n"); exit(1); } else if(procID == 0){ isChildA = 0; } else { write(pipeA[WRITE], &num, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); pid_t pid; while (pid = waitpid(-1, NULL, 0)) { if (errno == ECHILD) { break; } } } break; } if (procID == 0) { //We're a child, do kid-stuff. ssize_t bytesRead = 0; int response; while (1) { while (bytesRead == 0) { bytesRead = read((isChildA?pipeA[READ]:pipeB[READ]), &response, sizeof(int)); } if (response < 2) { //Kill other child and self fprintf(stderr, "Terminating PROCID: %i\n", getpid()); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); close(pipeA[WRITE]); close(pipeA[READ]); close(pipeB[WRITE]); close(pipeB[READ]); return 0; } else if(!(response%2)){ //Even response/=2; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } else { //Odd response*=3; response++; fprintf(stderr,"PROCID: %i, VALUE: %i\n", getpid(), response); write((isChildA?pipeB[WRITE]:pipeA[WRITE]), &response, sizeof(int)); bytesRead = 0; } } } } return 0; } This is the output I am getting... bash-3.00$ ./proj2 Enter an integer: 101 Value read: 101 Parent PID: 9379 PROCID: 9380, VALUE: 304 PROCID: 9381, VALUE: 152 PROCID: 9380, VALUE: 76 PROCID: 9381, VALUE: 38 PROCID: 9380, VALUE: 19 PROCID: 9381, VALUE: 58 PROCID: 9380, VALUE: 29 PROCID: 9381, VALUE: 88 PROCID: 9380, VALUE: 44 PROCID: 9381, VALUE: 22 PROCID: 9380, VALUE: 11 PROCID: 9381, VALUE: 34 PROCID: 9380, VALUE: 17 PROCID: 9381, VALUE: 52 PROCID: 9380, VALUE: 26 PROCID: 9381, VALUE: 13 PROCID: 9380, VALUE: 40 PROCID: 9381, VALUE: 20 PROCID: 9380, VALUE: 10 PROCID: 9381, VALUE: 5 PROCID: 9380, VALUE: 16 PROCID: 9381, VALUE: 8 PROCID: 9380, VALUE: 4 PROCID: 9381, VALUE: 2 PROCID: 9380, VALUE: 1 Terminating PROCID: 9381 Terminating PROCID: 9380 Enter an integer: 102 Value read: 102 Parent PID: 9379 PROCID: 9386, VALUE: 51 PROCID: 9387, VALUE: 154 PROCID: 9386, VALUE: 77 PROCID: 9387, VALUE: 232 PROCID: 9386, VALUE: 116 PROCID: 9387, VALUE: 58 PROCID: 9386, VALUE: 29 PROCID: 9387, VALUE: 88 PROCID: 9386, VALUE: 44 PROCID: 9387, VALUE: 22 PROCID: 9386, VALUE: 11 PROCID: 9387, VALUE: 34 PROCID: 9386, VALUE: 17 PROCID: 9387, VALUE: 52 PROCID: 9386, VALUE: 26 PROCID: 9387, VALUE: 13 PROCID: 9386, VALUE: 40 PROCID: 9387, VALUE: 20 PROCID: 9386, VALUE: 10 PROCID: 9387, VALUE: 5 PROCID: 9386, VALUE: 16 PROCID: 9387, VALUE: 8 PROCID: 9386, VALUE: 4 PROCID: 9387, VALUE: 2 PROCID: 9386, VALUE: 1 Terminating PROCID: 9387 Terminating PROCID: 9386 Enter an integer: 104 Value read: 104 Parent PID: 9379 Enter an integer: PROCID: 9388, VALUE: 52 PROCID: 9389, VALUE: 26 PROCID: 9388, VALUE: 13 PROCID: 9389, VALUE: 40 PROCID: 9388, VALUE: 20 PROCID: 9389, VALUE: 10 PROCID: 9388, VALUE: 5 PROCID: 9389, VALUE: 16 PROCID: 9388, VALUE: 8 PROCID: 9389, VALUE: 4 PROCID: 9388, VALUE: 2 PROCID: 9389, VALUE: 1 Terminating PROCID: 9388 Terminating PROCID: 9389 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9395, VALUE: 316 PROCID: 9396, VALUE: 158 PROCID: 9395, VALUE: 79 PROCID: 9396, VALUE: 238 PROCID: 9395, VALUE: 119 PROCID: 9396, VALUE: 358 PROCID: 9395, VALUE: 179 PROCID: 9396, VALUE: 538 PROCID: 9395, VALUE: 269 PROCID: 9396, VALUE: 808 PROCID: 9395, VALUE: 404 PROCID: 9396, VALUE: 202 PROCID: 9395, VALUE: 101 PROCID: 9396, VALUE: 304 PROCID: 9395, VALUE: 152 PROCID: 9396, VALUE: 76 PROCID: 9395, VALUE: 38 PROCID: 9396, VALUE: 19 PROCID: 9395, VALUE: 58 PROCID: 9396, VALUE: 29 PROCID: 9395, VALUE: 88 PROCID: 9396, VALUE: 44 PROCID: 9395, VALUE: 22 PROCID: 9396, VALUE: 11 PROCID: 9395, VALUE: 34 PROCID: 9396, VALUE: 17 PROCID: 9395, VALUE: 52 PROCID: 9396, VALUE: 26 PROCID: 9395, VALUE: 13 PROCID: 9396, VALUE: 40 PROCID: 9395, VALUE: 20 PROCID: 9396, VALUE: 10 PROCID: 9395, VALUE: 5 PROCID: 9396, VALUE: 16 PROCID: 9395, VALUE: 8 PROCID: 9396, VALUE: 4 PROCID: 9395, VALUE: 2 PROCID: 9396, VALUE: 1 Terminating PROCID: 9395 Terminating PROCID: 9396 105 Value read: 105 Parent PID: 9379 Enter an integer: PROCID: 9397, VALUE: 316 PROCID: 9398, VALUE: 158 PROCID: 9397, VALUE: 79 PROCID: 9398, VALUE: 238 PROCID: 9397, VALUE: 119 PROCID: 9398, VALUE: 358 PROCID: 9397, VALUE: 179 PROCID: 9398, VALUE: 538 PROCID: 9397, VALUE: 269 PROCID: 9398, VALUE: 808 PROCID: 9397, VALUE: 404 PROCID: 9398, VALUE: 202 PROCID: 9397, VALUE: 101 PROCID: 9398, VALUE: 304 PROCID: 9397, VALUE: 152 PROCID: 9398, VALUE: 76 PROCID: 9397, VALUE: 38 PROCID: 9398, VALUE: 19 PROCID: 9397, VALUE: 58 PROCID: 9398, VALUE: 29 PROCID: 9397, VALUE: 88 PROCID: 9398, VALUE: 44 PROCID: 9397, VALUE: 22 PROCID: 9398, VALUE: 11 PROCID: 9397, VALUE: 34 PROCID: 9398, VALUE: 17 PROCID: 9397, VALUE: 52 PROCID: 9398, VALUE: 26 PROCID: 9397, VALUE: 13 PROCID: 9398, VALUE: 40 PROCID: 9397, VALUE: 20 PROCID: 9398, VALUE: 10 PROCID: 9397, VALUE: 5 PROCID: 9398, VALUE: 16 PROCID: 9397, VALUE: 8 PROCID: 9398, VALUE: 4 PROCID: 9397, VALUE: 2 PROCID: 9398, VALUE: 1 Terminating PROCID: 9397 Terminating PROCID: 9398 106 Value read: 106 Parent PID: 9379 Enter an integer: PROCID: 9399, VALUE: 53 PROCID: 9400, VALUE: 160 PROCID: 9399, VALUE: 80 PROCID: 9400, VALUE: 40 PROCID: 9399, VALUE: 20 PROCID: 9400, VALUE: 10 PROCID: 9399, VALUE: 5 PROCID: 9400, VALUE: 16 PROCID: 9399, VALUE: 8 PROCID: 9400, VALUE: 4 PROCID: 9399, VALUE: 2 PROCID: 9400, VALUE: 1 Terminating PROCID: 9399 Terminating PROCID: 9400 ^C Another thing that's strange, when ran from within XCode it behaves normally. However, when ran from bash on Solaris or OSX it acts up.

    Read the article

  • Moving from Linear Probing to Quadratic Probing (hash collisons)

    - by Nazgulled
    Hi, My current implementation of an Hash Table is using Linear Probing and now I want to move to Quadratic Probing (and later to chaining and maybe double hashing too). I've read a few articles, tutorials, wikipedia, etc... But I still don't know exactly what I should do. Linear Probing, basically, has a step of 1 and that's easy to do. When searching, inserting or removing an element from the Hash Table, I need to calculate an hash and for that I do this: index = hash_function(key) % table_size; Then, while searching, inserting or removing I loop through the table until I find a free bucket, like this: do { if(/* CHECK IF IT'S THE ELEMENT WE WANT */) { // FOUND ELEMENT return; } else { index = (index + 1) % table_size; } while(/* LOOP UNTIL IT'S NECESSARY */); As for Quadratic Probing, I think what I need to do is change how the "index" step size is calculated but that's what I don't understand how I should do it. I've seen various pieces of code, and all of them are somewhat different. Also, I've seen some implementations of Quadratic Probing where the hash function is changed to accommodated that (but not all of them). Is that change really needed or can I avoid modifying the hash function and still use Quadratic Probing? EDIT: After reading everything pointed out by Eli Bendersky below I think I got the general idea. Here's part of the code at http://eternallyconfuzzled.com/tuts/datastructures/jsw_tut_hashtable.aspx: 15 for ( step = 1; table->table[h] != EMPTY; step++ ) { 16 if ( compare ( key, table->table[h] ) == 0 ) 17 return 1; 18 19 /* Move forward by quadratically, wrap if necessary */ 20 h = ( h + ( step * step - step ) / 2 ) % table->size; 21 } There's 2 things I don't get... They say that quadratic probing is usually done using c(i)=i^2. However, in the code above, it's doing something more like c(i)=(i^2-i)/2 I was ready to implement this on my code but I would simply do: index = (index + (index^index)) % table_size; ...and not: index = (index + (index^index - index)/2) % table_size; If anything, I would do: index = (index + (index^index)/2) % table_size; ...cause I've seen other code examples diving by two. Although I don't understand why... 1) Why is it subtracting the step? 2) Why is it diving it by 2?

    Read the article

  • Cucumber could not find table; but its there. What is going on?

    - by JZ
    I'm working with cucumber and I'm running into difficulties. When I run "cucumber features", I am met with errors, cucumber is unable to find my requests table. What obvious mistake am I making? Thank you in advance! Bash: justin-zollarss-mac-pro:conversion justinz$ cucumber features Using the default profile... /Users/justinz/.gem/ruby/1.8/gems/rails-2.3.5/lib/rails/gem_dependency.rb:119:Warning: Gem::Dependency#version_requirements is deprecated and will be removed on or after August 2010. Use #requirement F-- (::) failed steps (::) Could not find table 'requests' (ActiveRecord::StatementInvalid) ./features/article_steps.rb:3 ./features/article_steps.rb:2:in `each' ./features/article_steps.rb:2:in `/^I have requests named (.+)$/' features/manage_articles.feature:7:in `Given I have requests named Foo, Bar' Failing Scenarios: cucumber features/manage_articles.feature:6 # Scenario: Conversion 1 scenario (1 failed) 3 steps (1 failed, 2 skipped) 0m0.154s justin-zollarss-mac-pro:conversion justinz$ Manage_articles.feature: Feature: Manage Articles In order to make sales As a customer I want to make conversions Scenario: Conversion Given I have requests named Foo, Bar When I go to the list of customers Then I should see a new "customer" Article_steps.rb: Given /^I have requests named (.+)$/ do |firsts| firsts.split(', ').each do |first| Request.create!(:first => first) pending # express the regexp above with the code you wish you had end end Then /^I should see a new "([^"]*)"$/ do |arg1| pending # express the regexp above with the code you wish you had end DB schema: ActiveRecord::Schema.define(:version => 20100528011731) do create_table "requests", :force => true do |t| t.string "institution" t.string "website" t.string "type" t.string "users" t.string "first" t.string "last" t.string "jobtitle" t.string "phone" t.string "email" t.datetime "created_at" t.datetime "updated_at" end end

    Read the article

  • jquery performing calculation on dynamically generated elements

    - by user306472
    I have a table made up of a row of 3 input elements: Price, Quanity, and Total. Under that, I have two links I can click to dynamically generate another row in the table. All that is working well, but actually calculating a value for the total element is giving me trouble. I know how to calculate the value of the first total element but I'm having trouble extending this functionality when I add a new row to the table. Here's the html: <table id="table" border="0"> <thead> <th>Price</th><th>Quantity</th><th>Total</th> </thead> <tbody> <tr> <td><input id ="price" type = "text"></input></td> <td><input id ="quantity" type = "text"></input></td> <td><input id ="total" type = "text"></input></td> </tr> </tbody> </table> <a href="#" id="add">Add New</a> <a href="#" id="remove">Remove</a> Here's the jquery I'm using: $(function(){ $('a#add').click(function(){ $('#table > tbody').append('<tr><td><input id ="price" type = "text"></input></td><td><input id ="quantity" type = "text"></input></td><td><input id ="total" type = "text"></input></td></tr>'); }); $('a#remove').click(function(){ $('#table > tbody > tr:last').remove(); }); }); $(function(){ $('a#calc').click(function(){ var q = $('input#quantity').val(); var p = $('input#price').val(); var tot = (q*p); $('input#total').val(tot); }); }); I'm new to jquery so there's probably a simple method I don't know about that selects the relevant fields I want to calculate. Any guidance would be greatly appreciated.

    Read the article

  • How to create Query syntax for multiple DataTable for implementing IN operator of Sql Server

    - by Shantanu Gupta
    I have fetched 3-4 tables by executing my stored procedure. Now they resides on my dataset. I have to maintain this dataset for multiple forms and I am not doing any DML operation on this dataset. Now this dataset contains 4 tables out of which i have to fetch some records to display data. Data stored in tables are in form of one to many relationship. i.e. In case of transactions. N records per record. Then these N records are further mapped to M records of 3rd table. Table 1 MAP_ID GUEST_ID DEPARTMENT_ID PARENT_ID PREFERENCE_ID -------------------- -------------------- -------------------- -------------------- -------------------- 19 61 1 1 5 14 61 1 5 15 15 61 2 4 10 18 61 2 13 23 17 61 2 20 26 16 61 40 40 41 20 62 1 5 14 21 62 1 5 15 22 62 1 6 16 24 62 2 3 4 23 62 2 4 9 27 62 2 13 23 25 62 2 20 24 26 62 2 20 25 28 63 1 1 5 29 63 1 1 8 34 63 1 5 15 30 63 2 4 10 33 63 2 4 11 31 63 2 13 23 32 63 40 40 41 35 65 1 NULL 1 36 65 1 NULL 1 38 68 2 13 22 37 68 2 20 25 39 68 2 23 27 40 92 1 NULL 1 Table 2 Department_ID Department_Name Parent_Id Parent_Name -------------------- ----------------------- --------------- ---------------------------------------------------------------------------------- 1 Food 1, 5, 6 Food, North Indian, South Indian 2 Lodging 3, 4, 13, 20, 23 Room, Floor, Non Air Conditioned, With Balcony, Without Balcony 40 New 40 SubNew TABLE 3 Parent_Id Parent_Name Preference_ID Preference_Name -------------------- ----------------------------------------------- ----------------------- ------------------- NULL NULL NULL NULL 1 Food 5, 8 North Indian, Italian 3 Room 4 Floor 4 Floor 9, 10, 11 First, Second, Third 5 North Indian 14, 15 X, Y 6 South Indian 16 Dosa 13 Non Air Conditioned 22, 23 With Balcony, Without Balcony 20 With Balcony 24, 25, 26 Mountain View, Ocean View, Garden View 23 Without Balcony 27 Mountain View 40 New 41 SubNew I have these 3 tables that are related in some fashion like this. Table 1 will be the master for these 2 tables i.e. table 2 and table 3. I need to query on them as SELECT Department_Id, Department_Name, Parent_Name FROM Table2 WHERE Department_Id in ( SELECT Department_Id FROM Table1 WHERE guest_id=65 ) SELECT Parent_Id, Parent_Name, Preference_Name FROM Table3 WHERE PARENT_ID in ( SELECT parent_id FROM Table1 WHERE guest_id=65 ) Now I need to use these queries on DataTables. So I am using Query Syntax for this and reached up to this point. var dept_list= from dept in DtMapGuestDepartment.AsEnumerable() where dept.Field<long>("PK_GUEST_ID")==long.Parse(63) select dept; This should give me the list of all departments that has guest id =63 Now I want to select all departments_name and parent_name from Table 2 where guest_id=63 i.e. departments that i fetched above. This same case will be followed for Table3. Please suggest how to do this. Thanks for keeping up patience for reading my question.

    Read the article

  • Modify QueryString on PostBack to include an anchor bookmark without breaking subsequent events and

    - by roosteronacid
    Consider the following pseudo-code: // sorts the dataset used by the table void ClickEvent() { } foreach (column in table) { // create new LinkButton var lb = new LinkButton(); // hook sort event lb.Click += ClickEvent; // add LinkButton to table table.Controls.add(lb); } How can I modify the QueryString to include an anchor bookmark without breaking subsequent events and without using the dreaded PostBackUrl property on the LinkButtons?

    Read the article

  • A question about complex SQL statement

    - by william
    Table A has columns ID and AName, Table B has columns BName and ID. B.ID is foreign key of A.ID. Write a SQL statement to show data like: print column AName and C which describe whether Table B has ID in Table A, if exists 1 or else 0. So if A is: 1 aaa 2 bbb B is: something,2 output is: aaa,0 bbb,1

    Read the article

  • taking values from fields

    - by jagadeesh
    there is two table first table is pg_vendor_signup pg_vendor_signup id vendor_id name country_id secound table is pg_vendor_friends vid fid status pg_vendor_signup contain data is 1 3 ramu 381 2 4 raj 381 2 4 usha 381 3 4 krian 381 4 4 manu 381 4 9 aswin 381 pg_vendor_friends countain 1 9 4 0 1 9 3 0 i Want get all name where country id=381 and in pg_vendor_friends get status of table

    Read the article

  • DELETE from two tables with one OUTPUT clause?

    - by lance
    This deletes the document from the Document table and outputs information about the deleted document into the FinishedDocument table. DELETE FROM Document OUTPUT Deleted.DocumentId , Deleted.DocumentDescription INTO FinishedDocument WHERE DocumentId = @DocumentId I need to delete the document not just from the Document table, but also from the DocumentBackup table. Meanwhile, I need to maintain insertion into FinishedDocument. Is all of this possible with only one statement? If not, is a second DELETE (against DocumentBackup), with all of it wrapped in a transaction, the way to go?

    Read the article

  • Union and If Exists - not working together - Please help

    - by needshelp
    I need to get dummy values if they do no rows returned from table. The If exists works by itself, but gives error with a Union. Can someone please guide me with a solution or a workaround? create table test1 (col1 varchar(10)) create table test2 (col1 varchar(10)) create table test3 (col1 varchar(10)) insert test1 values ('test1-row1') insert test1 values ('test1-row2') insert test2 values ('test2-row1') insert test2 values ('test2-row2') select col1 from test1 union select col1 from test2 union if exists (select * from test3) select col1 from test3 else select 'dummy'

    Read the article

< Previous Page | 318 319 320 321 322 323 324 325 326 327 328 329  | Next Page >