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  • How do I set default group ownership for files in a directory?

    - by tnichols
    I am running a cakephp webapp on Linode LAMP. I am finding that my temp files are created with root:root ownership. But the webapp is running with Apache's permissions (www-data). This causes warnings any time there is a new file created because it is not writable for user www-data. How do I change the default ownership to www-data on any new files created in the temp folder? Thanks for your help!

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  • Can I set Windows default second-monitor behaviour to "Extend these displays"?

    - by MT_Head
    I travel to multiple offices (and multiple desks in those offices), and whenever possible I plug an external monitor into my laptop. Whenever I plug in a monitor I haven't used before, Windows defaults to "Duplicate these displays" - which messes up the arrangement of icons on my desktop if the external monitor is a different shape from my laptop's monitor. I then select "Extend these displays", and my laptop screen returns to its original shape - but my icons don't go back to their original arrangement. Grrrrr. Fast-forward a few days or weeks; I've got my icons arranged so I can find stuff again - then I go to a new office and it starts all over again. I'm tired of this. Is it possible to make "Extend these displays" the default behavior? I'm using Windows 8 x64 Home Premium, but I had the same complaint under Windows 7 x64 Ultimate. (Prior to that, I hadn't discovered the joy of dual displays. Ah, the time I wasted...)

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  • Using a Dell PowerConnect to set up load balancing/redundancy, 1 switch 2 routres 2 private wan link

    - by MarianoC
    Hi, We have different locations connected by two different WAN providers. Each site has a dell powerConnect 6224 and two cisco routers with the WAN connections (we don’t have access to router admin). The 6224 connects to each cisco LAN port and to our LAN backbone. We would like the 6224 provide the ip gateway address and load balance and support redundancy, if one of the routes fail. Is this possible?. We can't find any samples on doing this and we have tried with no success. Any help or link to documentation regarding this, will be greatly appreciated. Thanks, MarianoC

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  • Set property with reflection after Fluent Nhibernates automapping has occured?

    - by Marcus
    I have an abstract baseclass with a collection of details IList that is automapped with fnh. After it has been populated with the correct values i would like to set some properties with reflection on the my class that inherits the abstract baseclass. I have tried to accomplish this in the constructor of my abstract baseclass but obviously my Details collection is empty when the occurs so my question is, what is the recommended way of doing this?

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  • Android Set up Question - Which API Level do I Install?

    - by Greg
    Hi all, I'm trying to set up the Android SDK on Ubuntu. Someday I want to make apps that can reach most of the market. I've heard I need to make the apps compatible with Android 1.6 for this. Does that mean everything I install should be for Android 1.6 (API level 4?). Will I have any trouble running the apps on my phone with is Android 2.1?

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  • Rails 3: How to validate that A < B where A and B are both model attributes ?

    - by Misha Moroshko
    I would like to validate that customer_price >= my_price. I tried the following: class Product < ActiveRecord::Base attr_accessor :my_price validates_numericality_of :customer_price, :greater_than_or_equal_to => my_price ... end (customer_price is a column in the Products table in the database, while my_price isn't.) Here is the result: NameError in ProductsController#index undefined local variable or method `my_price' for #<Class:0x313b648> What is the right way to do this in Rails 3 ?

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  • How to insert a SQLite record with a datetime set to 'now' in Android application?

    - by droidguy
    Say, we have a table created as: create table notes (_id integer primary key autoincrement, created_date date) To insert a record, I'd use ContentValues initialValues = new ContentValues(); initialValues.put("date_created", ""); long rowId = mDb.insert(DATABASE_TABLE, null, initialValues); But how to set the date_created column to "now"? To make it clear, the initialValues.put("date_created", "datetime('now')"); Is not the right solution. It just sets the column to "datetime('now')" text.

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  • How to set Outlook 2010 to use signatures outside of the default signature folder?

    - by Gregory MOUSSAT
    With Outlook before the 2010 version, it was possible to specify any path for the signatures. With Outlook 2010, the only way is to use those stored into C:\Documents and Setting\UserName\Local Settings\Application Datas\Microsoft\Signature\ I'd like to point the signatures to a network share. Allowing us to modify the signatures into the share, instead of login on every computers each time we are asked to modify them (and this is quite often because the signatures contain logos about current events). We currently use a script to copy the signatures from the share to the local disk when users login.

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  • sql "Group By" and "Having"

    - by Hans Rudel
    im trying to work through some questions and im not sure how to do the following Q:Find the hard drive sizes that are equal among two or more PCs. its q15 on this site http://www.sql-ex.ru/learn_exercises.php#answer_ref The database scheme consists of four tables: Product(maker, model, type) PC(code, model, speed, ram, hd, cd, price) Laptop(code, model, speed, ram, hd, screen, price) Printer(code, model, color, type, price) any pointers would be appreciated.

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  • Correct model for a database with a table for each user.

    - by BAH
    Kinda stuck here... I have an application with lets say 5000 rows of data per user and was wondering if it was right or wrong to do it this way: On user account creation a new table is created (UserData_[UserID]) or should I just have 1 table for userdata and have everything in there with a column for userid? The reason I am stuck at the moment is that it seems NHibernate isn't able to be mapped to dynamic table names without creating another ISessionFactory which has alot of overhead AFAIK. Any help would be greatly appreciated. Thanks.

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  • Is it possible to set up rule in Outlook 2010 based on message class?

    - by BFDatabaseAdmin
    I recieve all the undeliverable reports for mailings sent from my company. Moving and cataloguing them can take a while, and it would be handy if I could create a rule that did that for me. The most robust way of doing this would seem to be to run a rule based on the Undeliverable message class. However, I can't see message class as an option anywhere in the advanced rules wizard, and Googling it is no help. EDIT: I already have a rule that searches for "Undeliverable" in the subject header of emails received and moves them, but this only affects traditional emails (i.e. those with a message class of "Message") and ignores actual undeliverable reports. Am I missing something obvious, or can this not be done?

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  • Django: get count of ForeignKey item in template?

    - by AP257
    Straightforward question - apologies if it is a duplicate, but I can't find the answer if so. I have a User model and a Submission model, like this: class Submission(models.Model): uploaded_by = models.ForeignKey('User') class User(models.Model): name = models.CharField(max_length=250 ) How can I show the number of Submissions made by each user in the template? I've tried {{ user.submission.count }}, like this: for user in users: {{ user.name }} ({{ user.submission.count }} submissions) but no luck...

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  • can I add properties to a typo3 extbase domain model object?

    - by The Newbie Qs
    I want to store a username in a coupon object, each coupon object already has the uid of the user who created it. I can loop over the coupon objects and read the associated usernames from fe_users but how then will I save those usernames into the coupons so when they are passed to the template the usernames can be read like so coupon.username, or in some other easy way so each username will appear on the page with the right coupon as they are all printed out in a table? If I was doing basic php instead of typo3 i would just define a query but what is the typo3 v4.5 way? My code so far - which dies on the line where I try to assign the new property --creatorname -- to the $coup object. public function listAction() { $coupons = $this->couponRepository->findAll(); // @var Tx_Extbase_Domain_Repository_FrontendUserRepository $userRepository */ $userRepository = $this->objectManager->get("Tx_Extbase_Domain_Repository_FrontendUserRepository"); foreach ($coupons as $coup) { echo '<br />test '.$coup->getCreator(); echo '<br />count = '.$userRepository->countAll().'<br />'; $newObject = $userRepository->findByUid( intval($coup->getCreator())); //var_dump($newObject); var_dump($coup); echo '<br />getUsername '.$newObject->getUsername() ; $coup['creatorname'] = $newObject->getUsername(); echo '<br />creatorname '.$coup['creatorname'] ; } $this->view->assign('coupons', $coupons); }

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  • How do you programmatically set a Style on a View?

    - by Greg
    I would like to do something like this: <Button android:id="@+id/button" android:layout_width="wrap_content" android:layout_height="wrap_cotent" style="@style/SubmitButtonType" /> But in code The xml approach works fine provided that SubmitButtonType is defined. Now what I assume happens is that the appt parser runs through this xml, generates an AttributeSet. That AttributeSet when passed to context/theme#obtainStyledAttributes() will have the style ref mask anything that is not written inline in this tag. Great that's fine! Now how do we do this programmatically. Button, as well as other View types, has a constructor that has the form: <Widget>(Context context, AttributeSet set, int defStyle). So I thought this would work. Button button = new Button(context, null, R.style.SubmitButtonType); However, I am finding that defStyle is badly documented as it really should be written to be a resourceId to an attribute (from R.attrs) that will be passed to obtainStyledAttributes() as the attribute resource, and not the style resource. After looking at the code, all the view implementations seem to pass 0 as the styleRef. I don't see the harm in having it passed as both the attr and the style resource (more flexible and negligible overhead) However I might be approaching this all wrong. How do you do this in code then other than by setting each individual element of the style to the specific widget you want to style (only possible by looking a the code to see what param maps to which method or set of methods). The only way I have found to do this is: <declare-styleable> <attr name="totallyAdhoc_attribute_just_for_this_case" format="reference"> </declare-styleable> <style name="MyAlreadyExistantTheme" > ... ... <item name="totallyAdhoc_attribute_just_for_this_case">@style/SubmitButtonType</item> </style> And instead of passing R.style.SubmitButtonType as defStyle, I pass the new R.attr.totallyAdhoc_attribute_just_for_this_case. Button button = new Button(context, null, R.attr.totallyAdhoc_attribute_just_for_this_case); This works but sounds way too complicated.

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  • Does setting an A record for a root domain set it (automatically) for subdomains?

    - by Edan Maor
    I bought a domain from Dreamhost, but my servers are actually running on Amazon's AWS. I have an Elastic IP, say 1.1.1.1. In the Dreamhost panel, I've added an A record for my domain name, pointing it to 1.1.1.1. My question is, are all subdomains (e.g. www.mydomain.com, a.mydomain.com, etc.) automatically mapped to 1.1.1.1 as well, because the root is? Or do I have to add separate rules for each subdomain?

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  • How to page multiple data sets in ASP.NET MVC

    - by REA_ANDREW
    On a single view I will have three sets of paged data. Which means for each model I will have The Objects The Page Index The Page Size My initial thought was for example: public class PagedModel<T> where T:class { public IList<T> Objects { get; set; } public int ModelPageIndex { get; set; } public int ModelPageSize { get; set; } } Then having a model which is to be supplied to the action as for example: public class TypesViewModel { public PagedModel<ObjectA> Types1 { get; set; } public PagedModel<ObjectB> Typed2 { get; set; } public PagedModel<ObjectC> Types3 { get; set; } } So if I then for example have the Index view inherit from the type: System.Web.Mvc.ViewPage<uk.co.andrewrea.forum.Web.Models.TypesViewModel> Now my initial aciton method for the index is simply: public ActionResult Index() { var forDisplayPurposes = new TypesViewModel(); return View(forDisplayPurposes); } If I then want to page, it is here where I am struggling to decide which action to take. Lets say that I select the next page of the Types2 PageModel. What should the action look like for this in order to return the new view showing the second page of the Types2 PageModel I was thinking possibly to duplicate the action but use it with POST [AcceptVerbs(HttpVerbs.Post)] public ActionResult Index(TypesViewModel model) { return View(model); } Is this a good way to approach it. I understand there is always Session, but I was just wondering how such a thing is achieved currently out there. If any best methods have been mutually accepted and things. So simply, one page with multiple paged models. How to persist the data for each using a wrapper model. Which way should you pass in the model and which way should you page the data, i.e. Form Post Lastly, I have seen the routes take this into account i.e. {controller}/{action}/{id}/{pageindex}/{pagesize} but this only accounts for one model and I do not really wwant to repeat the pagesize and pageindex values for the number of models I have inside the wrapper model. Thanks for your time!! Andrew

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  • Can I set up a different method of authentication on Nagios?

    - by cwd
    Nagios is a wonderful too for monitoring servers. Their web interface is not bad, either. However I am not crazy about using the HTTP Authentication that comes standard. Is there a way to use another method of authentication? (and I don't mean restricting access by IP address in the .htaccess file) Something with a form-based login would be wonderful, but perhaps there is no such thing. I'm hoping you guys have found something I haven't.

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