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  • How to split a string with negative numbers using ActionScript 3.0

    - by inzombiak
    I'm having trouble loading my level. I'm using Ogmo to create my level then I import it. I have no problem converting 0's and 1's into an Array, but I can't figure out how to do the same for -1's. It separates the "-" and the "1". Any help would be great. I've posted my code and the XML files below levelXML = new XML(e.target.data); playerX = int(levelXML.Entities.Player.@x); playerY = int(levelXML.Entities.Player.@y); levelGrid = levelXML.Grid; levelGrid = levelGrid.split("\n").join(""); levelTiles = levelXML.Tiles; levelTiles = levelTiles.split("\n").join(""); levelTiles = levelTiles.split(",").join(""); tileArray = levelTiles.split(""); gridArray = levelGrid.split(""); for(i = 0; i <= 34; i++) { levelArray[i] = new Array(); for(j = 0; j <= 34; j++) { if(tileArray[j*35 + i] == 0) { gridArray[j*35+i] = -1; } var currentSymbol = gridArray[j*35+i]; levelArray[i][j] = currentSymbol; if(gridArray[j*35 + i] == 1) { wall = new Wall; addChild(wall); wall.x = i*20 + 10; wall.y = j*20 + 10; } else if(gridArray[j*35 + i] == -1) { pellet = new Pellet; addChild(pellet); pellet.x = i*20 + 10; pellet.y = j*20 + 10; } } } I know the code is very dirty, but I needed a quick fix. Grid exportMode="Bitstring" 11111111111111111111111111111111111 10000000000000000011000000000000001 10000000000000000011000000000000001 10011111001111110011001111110011001 10011111001111110011001111110011001 10011111001111110011001111110011001 10000000000000000000000000000000001 10000000000000000000000000000000001 10011111001100111111100110011111001 10011111001100000100000110011111001 10000000001100000100000110000000001 10000000001111100100111110000000001 11111111001111100100111110011111111 00000001001111100100111110010000000 00000001001100000000000110010000000 11111111001100000000000110011111111 00000000000000111111100000000000000 00000000000000100000100000000000000 11111111001100100000100110011111111 00000001001100111111100110010000000 00000001001100000000000110010000000 11111111001100111111100110011111111 10000000000000000100000000000000001 10000000000000000100000000000000001 10011111001111100100111110011111001 10000011000000000000000000011000001 10000011000000000000000000011000001 11110011001100111111100110011001111 11110011001100111111100110011001111 10000000001100000100000110000000001 10000000001100000100000110000000001 10011111111111100100111111111111001 10000000000000000000000000000000001 10000000000000000000000000000000001 11111111111111111111111111111111111 Tiles tileset="Tiles" exportMode="CSV"-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1,-1,-1,-1,-1,-1,-1,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,0,0,0,0,0,0,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,0,-1 -1,-1,-1,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,0,-1 -1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1,-1

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  • How to make natural-looking paths with A* on a grid?

    - by user11177
    I've been reading this: http://theory.stanford.edu/~amitp/GameProgramming/Heuristics.html But there are some things I don't understand, for example the article says to use something like this for pathfinding with diagonal movement: function heuristic(node) = dx = abs(node.x - goal.x) dy = abs(node.y - goal.y) return D * max(dx, dy) I don't know how do set D to get a natural looking path like in the article, I set D to the lowest cost between adjacent squares like it said, and I don't know what they meant by the stuff about the heuristic should be 4*D, that does not seem to change any thing. This is my heuristic function and move function: def heuristic(self, node, goal): D = 10 dx = abs(node.x - goal.x) dy = abs(node.y - goal.y) return D * max(dx, dy) def move_cost(self, current, node): cross = abs(current.x - node.x) == 1 and abs(current.y - node.y) == 1 return 19 if cross else 10 Result: The smooth sailing path we want to happen: The rest of my code: http://pastebin.com/TL2cEkeX

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  • Rendering Texture Quad to Screen or FBO (OpenGL ES)

    - by Usman.3D
    I need to render the texture on the iOS device's screen or a render-to-texture frame buffer object. But it does not show any texture. It's all black. (I am loading texture with image myself for testing purpose) //Load texture data UIImage *image=[UIImage imageNamed:@"textureImage.png"]; GLuint width = FRAME_WIDTH; GLuint height = FRAME_HEIGHT; //Create context void *imageData = malloc(height * width * 4); CGColorSpaceRef colorSpace = CGColorSpaceCreateDeviceRGB(); CGContextRef context = CGBitmapContextCreate(imageData, width, height, 8, 4 * width, colorSpace, kCGImageAlphaPremultipliedLast | kCGBitmapByteOrder32Big); CGColorSpaceRelease(colorSpace); //Prepare image CGContextClearRect(context, CGRectMake(0, 0, width, height)); CGContextDrawImage(context, CGRectMake(0, 0, width, height), image.CGImage); glGenTextures(1, &texture); glBindTexture(GL_TEXTURE_2D, texture); glTexParameteri(GL_TEXTURE_2D, GL_TEXTURE_MIN_FILTER, GL_NEAREST); glTexImage2D(GL_TEXTURE_2D, 0, GL_RGBA, width, height, 0, GL_RGBA, GL_UNSIGNED_BYTE, imageData); glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_WRAP_S, GL_CLAMP_TO_EDGE); glTexParameterf(GL_TEXTURE_2D, GL_TEXTURE_WRAP_T, GL_CLAMP_TO_EDGE); Simple Texture Quad drawing code mentioned here //Bind Texture, Bind render-to-texture FBO and then draw the quad const float quadPositions[] = { 1.0, 1.0, 0.0, -1.0, 1.0, 0.0, -1.0, -1.0, 0.0, -1.0, -1.0, 0.0, 1.0, -1.0, 0.0, 1.0, 1.0, 0.0 }; const float quadTexcoords[] = { 1.0, 1.0, 0.0, 1.0, 0.0, 0.0, 0.0, 0.0, 1.0, 0.0, 1.0, 1.0 }; // stop using VBO glBindBuffer(GL_ARRAY_BUFFER, 0); // setup buffer offsets glVertexAttribPointer(ATTRIB_VERTEX, 3, GL_FLOAT, GL_FALSE, 3*sizeof(float), quadPositions); glVertexAttribPointer(ATTRIB_TEXCOORD0, 2, GL_FLOAT, GL_FALSE, 2*sizeof(float), quadTexcoords); // ensure the proper arrays are enabled glEnableVertexAttribArray(ATTRIB_VERTEX); glEnableVertexAttribArray(ATTRIB_TEXCOORD0); //Bind Texture and render-to-texture FBO. glBindTexture(GL_TEXTURE_2D, GLid); //Actually wanted to render it to render-to-texture FBO, but now testing directly on default FBO. //glBindFramebuffer(GL_FRAMEBUFFER, textureFBO[pixelBuffernum]); // draw glDrawArrays(GL_TRIANGLES, 0, 2*3); What am I doing wrong in this code? P.S. I'm not familiar with shaders yet, so it is difficult for me to make use of them right now.

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  • Problems when rendering code on Nvidia GPU

    - by 2am
    I am following OpenGL GLSL cookbook 4.0, I have rendered a tesselated quad, as you see in the screenshot below, and i am moving Y coordinate of every vertex using a time based sin function as given in the code in the book. This program, as you see on the text in the image, runs perfectly on built in Intel HD graphics of my processor, but i have Nvidia GT 555m graphics in my laptop, (which by the way has switchable graphics) when I run the program on the graphic card, the OpenGL shader compilation fails. It fails on following instruction.. pos.y = sin.waveAmp * sin(u); giving error Error C1105 : Cannot call a non-function I know this error is coming on the sin(u) function which you see in the instruction. I am not able to understand why? When i removed sin(u) from the code, the program ran fine on Nvidia card. Its running with sin(u) fine on Intel HD 3000 graphics. Also, if you notice the program is almost unusable with intel HD 3000 graphics, I am getting only 9FPS, which is not enough. Its too much load for intel HD 3000. So, sin(X) function is not defined in the OpenGL specification given by Nvidia drivers or something else??

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  • Android - Efficient way to draw tiles in OpenGL ES

    - by Maecky
    Hi, I am trying to write efficient code to render a tile based map in android. I load for each tile the corresponding bitmap (just one time) and then create the according tiles. I have designed a class to do this: public class VertexQuad { private float[] mCoordArr; private float[] mColArr; private float[] mTexCoordArr; private int mTextureName; private static short mCounter = 0; private short mIndex; As you can see, each tile has it's x,y location, a color array, texture coordinates and a texture name. Now, I want to render all my created tiles. To reduce the openGL api calls (I read somewhere that the state changes are costly and therefore I want to keep them to a minimum), I first want to hand ALL the coordinate-arrays, color-arrays and texture-coordinates over to OpenGL. After that I run two for loops. The first one iterates over the textures and binds the texture. The second for loop iterates over all Tiles and puts all tiles with the corresponding texture into an IndexBuffer. After the second for loop has finished, I call gl.gl_drawElements() whith the corresponding index buffer, to draw all tiles with the texture associated. For the next texture I do the same again. Now I run into some problems: Allocating and filling the FloatBuffers at the start of each rendering cycle costs very much time. I just run a test, where i wanted to put 400 coordinates into a FloatBuffer which took me about 200ms. My questions now are: Is there a better way, handling the coordinate and color structures? How is this correctly done, this is obviously not the optimal way? ;) thanks in advance, regards Markus

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  • HLSL Shader not working right?

    - by dvds414
    Okay so I have this shader for ambient occlusion. It loads to world correctly, but it just shows all the models as being white. I do not know why. I am just running the shader while the model is rendering, is that correct? or do I need to make a render target or something? if so then how? I'm using C++. Here is my shader. float sampleRadius; float distanceScale; float4x4 xProjection; float4x4 xView; float4x4 xWorld; float3 cornerFustrum; struct VS_OUTPUT { float4 pos : POSITION; float2 TexCoord : TEXCOORD0; float3 viewDirection : TEXCOORD1; }; VS_OUTPUT VertexShaderFunction( float4 Position : POSITION, float2 TexCoord : TEXCOORD0) { VS_OUTPUT Out = (VS_OUTPUT)0; float4 WorldPosition = mul(Position, xWorld); float4 ViewPosition = mul(WorldPosition, xView); Out.pos = mul(ViewPosition, xProjection); Position.xy = sign(Position.xy); Out.TexCoord = (float2(Position.x, -Position.y) + float2( 1.0f, 1.0f ) ) * 0.5f; float3 corner = float3(-cornerFustrum.x * Position.x, cornerFustrum.y * Position.y, cornerFustrum.z); Out.viewDirection = corner; return Out; } texture depthTexture; texture randomTexture; sampler2D depthSampler = sampler_state { Texture = <depthTexture>; ADDRESSU = CLAMP; ADDRESSV = CLAMP; MAGFILTER = LINEAR; MINFILTER = LINEAR; }; sampler2D RandNormal = sampler_state { Texture = <randomTexture>; ADDRESSU = WRAP; ADDRESSV = WRAP; MAGFILTER = LINEAR; MINFILTER = LINEAR; }; float4 PixelShaderFunction(VS_OUTPUT IN) : COLOR0 { float4 samples[16] = { float4(0.355512, -0.709318, -0.102371, 0.0 ), float4(0.534186, 0.71511, -0.115167, 0.0 ), float4(-0.87866, 0.157139, -0.115167, 0.0 ), float4(0.140679, -0.475516, -0.0639818, 0.0 ), float4(-0.0796121, 0.158842, -0.677075, 0.0 ), float4(-0.0759516, -0.101676, -0.483625, 0.0 ), float4(0.12493, -0.0223423, -0.483625, 0.0 ), float4(-0.0720074, 0.243395, -0.967251, 0.0 ), float4(-0.207641, 0.414286, 0.187755, 0.0 ), float4(-0.277332, -0.371262, 0.187755, 0.0 ), float4(0.63864, -0.114214, 0.262857, 0.0 ), float4(-0.184051, 0.622119, 0.262857, 0.0 ), float4(0.110007, -0.219486, 0.435574, 0.0 ), float4(0.235085, 0.314707, 0.696918, 0.0 ), float4(-0.290012, 0.0518654, 0.522688, 0.0 ), float4(0.0975089, -0.329594, 0.609803, 0.0 ) }; IN.TexCoord.x += 1.0/1600.0; IN.TexCoord.y += 1.0/1200.0; normalize (IN.viewDirection); float depth = tex2D(depthSampler, IN.TexCoord).a; float3 se = depth * IN.viewDirection; float3 randNormal = tex2D( RandNormal, IN.TexCoord * 200.0 ).rgb; float3 normal = tex2D(depthSampler, IN.TexCoord).rgb; float finalColor = 0.0f; for (int i = 0; i < 16; i++) { float3 ray = reflect(samples[i].xyz,randNormal) * sampleRadius; //if (dot(ray, normal) < 0) // ray += normal * sampleRadius; float4 sample = float4(se + ray, 1.0f); float4 ss = mul(sample, xProjection); float2 sampleTexCoord = 0.5f * ss.xy/ss.w + float2(0.5f, 0.5f); sampleTexCoord.x += 1.0/1600.0; sampleTexCoord.y += 1.0/1200.0; float sampleDepth = tex2D(depthSampler, sampleTexCoord).a; if (sampleDepth == 1.0) { finalColor ++; } else { float occlusion = distanceScale* max(sampleDepth - depth, 0.0f); finalColor += 1.0f / (1.0f + occlusion * occlusion * 0.1); } } return float4(finalColor/16, finalColor/16, finalColor/16, 1.0f); } technique SSAO { pass P0 { VertexShader = compile vs_3_0 VertexShaderFunction(); PixelShader = compile ps_3_0 PixelShaderFunction(); } }

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  • Need a good quality bitmap rotation algorithm for Android

    - by Lumis
    I am creating a kaleidoscopic effect on an android tablet. I am using the code below to rotate a slice of an image, but as you can see in the image when rotating a bitmap 60 degrees it distorts it quite a lot (red rectangles) – it is smudging the image! I have set dither and anti-alias flags but it does not help much. I think it is just not a very sophisticated bitmap rotation algorithm. canvas.save(); canvas.rotate(angle, screenW/2, screenH/2); canvas.drawBitmap(picSlice, screenW/2, screenH/2, pOutput); canvas.restore(); So I wonder if you can help me find a better way to rotate a bitmap. It does not have to be fast, because I intend to use a high quality rotation only when I want to save the screen to the SD card - I would redraw the screen in memory before saving. Do you know any comprehensible or replicable algorithm for bitmap rotation that I could programme or use as a library? Or any other suggestion? EDIT: The answers below made me think if Android OS had bilinear or bicubic interpolation option and after some search I found that it does have its own version of it called FilterBitmap. After applying it to my paint pOutput.setFilterBitmap(true); I get much better result

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  • Cocos2d: Adding a CCSequence to a CCArray

    - by Axort
    I have a problem with an action performed by a sprite. I have one CCSequence in a CCArray and I have an scheduled method (is called every 5 seconds) that make the sprite run the action. The action is performed correctly only the first time (the first 5 seconds), after that, the action do whatever it wants lol. Here is the code: In .h - @interface PowerUpLayer : CCLayer { PowerUp *powerUp; CCArray *trajectories; } @property (nonatomic, retain) CCArray *trajectories; In .mm - @implementation PowerUpLayer @synthesize trajectories; -(id)init { if((self = [super init])) { [self createTrajectories]; self.isTouchEnabled = YES; [self schedule:@selector(spawn:) interval:5]; } return self; } -(void)createTrajectories { self.trajectories = [CCArray arrayWithCapacity:1]; //Wave trajectory ccBezierConfig firstWave, secondWave; firstWave.controlPoint_1 = CGPointMake([[CCDirector sharedDirector] winSize].width + 30, [[CCDirector sharedDirector] winSize].height / 2);//powerUp.sprite.position.x, powerUp.sprite.position.y); firstWave.controlPoint_2 = CGPointMake([[CCDirector sharedDirector] winSize].width - ([[CCDirector sharedDirector] winSize].width / 4), 0); firstWave.endPosition = CGPointMake([[CCDirector sharedDirector] winSize].width / 2, [[CCDirector sharedDirector] winSize].height / 2); secondWave.controlPoint_1 = CGPointMake([[CCDirector sharedDirector] winSize].width / 2, [[CCDirector sharedDirector] winSize].height / 2); secondWave.controlPoint_2 = CGPointMake([[CCDirector sharedDirector] winSize].width / 4, [[CCDirector sharedDirector] winSize].height); secondWave.endPosition = CGPointMake(-30, [[CCDirector sharedDirector] winSize].height / 2); id bezierWave1 = [CCBezierTo actionWithDuration:1 bezier:firstWave]; id bezierWave2 = [CCBezierTo actionWithDuration:1 bezier:secondWave]; id waveTrajectory = [CCSequence actions:bezierWave1, bezierWave2, [CCCallFuncN actionWithTarget:self selector:@selector(setInvisible:)], nil]; [self.trajectories addObject:waveTrajectory]; //[powerUp.sprite runAction:bezierForward]; // [CCMoveBy actionWithDuration:3 position:CGPointMake(-[[CCDirector sharedDirector] winSize].width - powerUp.sprite.contentSize.width, 0)] //[powerUp.sprite runAction:[CCSequence actions:bezierWave1, bezierWave2, [CCCallFuncN actionWithTarget:self selector:@selector(setInvisible:)], nil]]; } -(void)setInvisible:(id)sender { if(powerUp != nil) { [self removeChild:sender cleanup:YES]; powerUp = nil; } } This is the scheduled method: -(void)spawn:(ccTime)dt { if(powerUp == nil) { powerUp = [[PowerUp alloc] initWithType:0]; powerUp.sprite.position = CGPointMake([[CCDirector sharedDirector] winSize].width + powerUp.sprite.contentSize.width, [[CCDirector sharedDirector] winSize].height / 2); [self addChild:powerUp.sprite z:-1]; [powerUp.sprite runAction:((CCSequence *)[self.trajectories objectAtIndex:0])]; } } I don't know what is happening; I never modify the content of the CCSequence after the first time. Thanks!

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  • Cutting out smaller rectangles from a larger rectangle

    - by Mauro Destro
    The world is initially a rectangle. The player can move on the world border and then "cut" the world via orthogonal paths (not oblique). When the player reaches the border again I have a list of path segments they just made. I'm trying to calculate and compare the two areas created by the path cut and select the smaller one to remove it from world. After the first iteration, the world is no longer a rectangle and player must move on border of this new shape. How can I do this? Is it possible to have a non rectangular path? How can I move the player character only on path? EDIT Here you see an example of what I'm trying to achieve: Initial screen layout. Character moves inside the world and than reaches the border again. Segment of the border present in the smaller area is deleted and last path becomes part of the world border. Character moves again inside the world. Segments of border present in the smaller area are deleted etc.

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  • Save Zone Implementation in Asteroids

    - by Moaz
    I would like to implement a safe zone for asteroids so that when the ship gets destroyed, it shouldn't be there unless it is safe from other asteroids. I tried to check the distance between each asteroid and the ship, and if it is above threshold, it sets a flag to the ship that's a safe zone, but sometimes it work and sometimes it doesn't for (list<Asteroid>::iterator itr_astroid = asteroids.begin(); itr_astroid!=asteroids.end(); ) { if(currentShip.m_state == Ship::Ship_Dead) { float distance = itr_astroid->getCenter().distance(Vec2f(getWindowWidth()/2,getWindowHeight()/2)); if( distance>200) { currentShip.m_saveField = true; break; } else { currentShip.m_saveField = false; itr_astroid++; } } else { itr_astroid++; } }

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  • Material usage, one per model or per object?

    - by WSkid
    Is it better (memory, time (of developer), space) to use single model that is unwrapped and uses a single material or to break a model down into appropriate bits, each with their own smaller texture/material? Or does it depend on the target platform as to what is acceptable - ie PC vs tablet? An example: Say you have a typical house with a tiled roof. Model it, make sure everything is attached, unwrap the walls/roof so in your UV template the walls and roof would be in one texture file, side-by-side in say a 512x512 file. Model the roof/walls as separate objects, unwrap them individually and have two UV templates. You could then have a 256x256 file for each one.

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  • Javascript - Canvas image never appears on first function run

    - by Matt
    I'm getting a bit of a weird issue, the image never shows the first time you run the game in your browser, after that you see it every time. If you close your browser and re open it and run the game again, the same issue occurs - you don't see the image the first time you run it. Here's the issue in action, just hit a wall and there's no image the first time on the end game screen. Any help would be appreciated. Regards, Matt function showGameOver() { ctx.clearRect(0, 0, canvas.width, canvas.height); ctx.fillStyle = "black"; ctx.font = "16px sans-serif"; ctx.fillText("Game Over!", ((canvas.width / 2) - (ctx.measureText("Game Over!").width / 2)), 50); ctx.font = "12px sans-serif"; ctx.fillText("Your Score Was: " + score, ((canvas.width / 2) - (ctx.measureText("Your Score Was: " + score).width / 2)), 70); myimage = new Image(); myimage.src = "xcLDp.gif"; var size = [119, 26], //set up size coord = [443, 200]; ctx.font = "12px sans-serif"; ctx.fillText("Restart", ((canvas.width / 2) - (ctx.measureText("Restart").width / 2)), 197); ctx.drawImage( //draw it on canvas myimage, coord[0], coord[1], size[0], size[1] ); $("canvas").click(function(e) { //when click.. if ( testIfOver(this, e, size, coord) ) { startGame(); //reload } }); $("canvas").mousemove(function(e) { //when mouse moving if ( testIfOver(this, e, size, coord) ) { $(this).css("cursor", "pointer"); //change the cursor } else { $(this).css("cursor", "default"); //change it back } }); function testIfOver(ele,ev,size,coord){ if ( ev.pageX > coord[0] + ele.offsetLeft && ev.pageX < coord[0] + size[0] + ele.offsetLeft && ev.pageY > coord[1] + ele.offsetTop && ev.pageY < coord[1] + size[1] + ele.offsetTop ) { return true; } return false; } }

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  • Where does the light come from, using Maya/Panda3D?

    - by Aerovistae
    Total noob to Maya. Total noob to Panda3D. Planning on becoming really good at both as soon as I have free time to do so, but right now I have an assignment due in a few hours which requires this: (The part which confuses me is bolded.) Model and texture a vehicle and two different obstacles Build a scene graph in Panda with a plane, the vehicle, several copies of each of the obstacles, and (at least) a direction light Program vehicle movement, constrained to a plane (no terrain) Working headlights Vehicle collides with obstacles How do I attach a light source to a model? I'm assuming this is done in Panda3D but I'm sufficiently new to this that I wouldn't be astonished to hear it's part of the model.

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  • Bubble shooter search alghoritm

    - by Fofole
    So I have a Matrix of NxM. At a given position (for ex. [2][5]) I have a value which represents a color. If there is nothing at that point the value is -1. What I need to do is after I add a new point, to check all his neighbours with the same color value and if there are more than 2, set them all to -1. If what I said doesn't make sense what I'm trying to do is an alghoritm which I use to destroy all the same color bubbles from my screen, where the bubbles are memorized in a matrix where -1 means no bubble and {0,1,2,...} represent that there is a bubble with a specific color. This is what I tried and failed: public class Testing { static private int[][] gameMatrix= {{3, 3, 4, 1, 1, 2, 2, 2, 0, 0}, {1, 4, 1, 4, 2, 2, 1, 3, 0, 0}, {2, 2, 4, 4, 3, 1, 2, 4, 0, 0}, {0, 1, 2, 3, 4, 1, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, {0, 0, 0, 0, 0, 0, 0, 0, 0, 0}, }; static int Rows=6; static int Cols=10; static int count; static boolean[][] visited=new boolean[15][15]; static int NOCOLOR = -1; static int color = 1; public static void dfs(int r, int c, int color, boolean set) { for(int dr = -1; dr <= 1; dr++) for(int dc = -1; dc <= 1; dc++) if(!(dr == 0 && dc == 0) && ok(r+dr, c+dc)) { int nr = r+dr; int nc = c+dc; // if it is the same color and we haven't visited this location before if(gameMatrix[nr][nc] == color && !visited[nr][nc]) { visited[nr][nc] = true; count++; dfs(nr, nc, color, set); if(set) { gameMatrix[nr][nc] = NOCOLOR; } } } } static boolean ok(int r, int c) { return r >= 0 && r < Rows && c >= 0 && c < Cols; } static void showMatrix(){ for(int i = 0; i < gameMatrix.length; i++) { System.out.print("["); for(int j = 0; j < gameMatrix[0].length; j++) { System.out.print(" " + gameMatrix[i][j]); } System.out.println(" ]"); } System.out.println(); } static void putValue(int value,int row,int col){ gameMatrix[row][col]=value; } public static void main(String[] args){ System.out.println("Initial Matrix:"); putValue(1, 4, 1); putValue(1, 5, 1); showMatrix(); for(int n = 0; n < 15; n++) for(int m = 0; m < 15; m++) visited[n][m] = false; //reset count count = 0; //dfs(bubbles.get(i).getRow(), bubbles.get(i).getCol(), color, false); // get the contiguous count dfs(5,1,color,false); //if there are more than 2 set the color to NOCOLOR for(int n = 0; n < 15; n++) for(int m = 0; m < 15; m++) visited[n][m] = false; if(count > 2) { //dfs(bubbles.get(i).getRow(), bubbles.get(i).getCol(), color, true); dfs(5,1,color,true); } System.out.println("Matrix after dfs:"); showMatrix(); } }

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  • Normal vector of a face loaded from an FBX model during collision?

    - by Corey Ogburn
    I'm loading a simple 6 sided cube from a UV-mapped FBX model and I'm using a BoundingBox to test for collisions. Once I determine there's a collision, I want to use the normal vector of the collided surface to correct the movement of whatever collided with the cube. I suppose this is a two-part question: 1) How can I determine which face of the cube was collided with in a collision? 2) How can I get the normal vector of that surface?

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  • How does this circle collision detection math work?

    - by Griffin
    I'm going through the wildbunny blog to learn about collision detection. I'm confused about how the vectors he's talking about come into play. Here's the part that confuses me: p = ||A-B|| – (r1+r2) The two spheres are penetrating by distance p. We would also like the penetration vector so that we can correct the penetration once we discover it. This is the vector that moves both circles to the point where they just touch, correcting the penetration. Importantly it is not only just a vector that does this, it is the only vector which corrects the penetration by moving the minimum amount. This is important because we only want to correct the error, not introduce more by moving too much when we correct, or too little. N = (A-B) / ||A-B|| P = N*p Here we have calculated the normalised vector N between the two centres and the penetration vector P by multiplying our unit direction by the penetration distance. I understand that p is the distance by which the circles penetrate, but I don't get what exactly N and P are. It seems to me N is just the coordinates of the 3rd point of the right trianlge formed by point A and B (A-B) then being divided by the hypotenuse of that triangle or distance between A and B (||A-B||). What's the significance of this? Also, what is the penetration vector used for? It seems to me like a movement that one of the circles would perform to get un-penetrated.

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  • How can I ease the work of getting pixel coordinates from a spritesheet?

    - by ThePlan
    When it comes to spritesheets they're usually easier to use, and they're very efficient memory-wise, but the problem that I'm always having is getting the actual position of a sprite from a sheet. Usually, I have to throw in some aproximated values and modify them several times until I get it right. My question: is there a tool which can basically show you the coordinates of the mouse relative to the image you have opened? Or is there a simpler method of getting the exact rectangle that the sprite is contained in?

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  • Uniform not being applied to proper mesh

    - by HaMMeReD
    Ok, I got some code, and you select blocks on a grid. The selection works. I can modify the blocks to be raised when selected and the correct one shows. I set a color which I use in the shader. However, I am trying to change the color before rendering the geometry, and the last rendered geometry (in the sequence) is rendered light. However, to debug logic I decided to move the block up and make it white, in which case one block moves up and another block becomes white. I checked all my logic and it knows the correct one is selected and it is showing in, in the correct place and rendering it correctly. When there is only 1 it works properly. Video Of the bug in action, note how the highlighted and elevated blocks are not the same block, however the code for color and My Renderer is here (For the items being drawn) public void render(Renderer renderer) { mGrid.render(renderer, mGameState); for (Entity e:mGameEntities) { UnitTypes ut = UnitTypes.valueOf((String)e.getObject(D.UNIT_TYPE.ordinal())); if (ut == UnitTypes.Soldier) { renderer.testShader.begin(); renderer.testShader.setUniformMatrix("u_mvpMatrix",mEntityMatrix); renderer.texture_soldier.bind(0); Vector2 pos = (Vector2) e.getObject(D.COORDS.ordinal()); mEntityMatrix.set(renderer.mCamera.combined); if (mSelectedEntities.contains(e)) { mEntityMatrix.translate(pos.x, 1f, pos.y); renderer.testShader.setUniformf("v_color", 0.5f,0.5f,0.5f,1f); } else { mEntityMatrix.translate(pos.x, 0f, pos.y); renderer.testShader.setUniformf("v_color", 1f,1f,1f,1f); } mEntityMatrix.scale(0.2f, 0.2f, 0.2f); renderer.model_soldier.render(renderer.testShader,GL20.GL_TRIANGLES); renderer.testShader.end(); } else if (ut == UnitTypes.Enemy_Infiltrator) { renderer.testShader.begin(); renderer.testShader.setUniformMatrix("u_mvpMatrix",mEntityMatrix); renderer.testShader.setUniformf("v_color", 1.0f,1,1,1.0f); renderer.texture_enemy_infiltrator.bind(0); Vector2 pos = (Vector2) e.getObject(D.COORDS.ordinal()); mEntityMatrix.set(renderer.mCamera.combined); mEntityMatrix.translate(pos.x, 0f, pos.y); mEntityMatrix.scale(0.2f, 0.2f, 0.2f); renderer.model_enemy_infiltrator.render(renderer.testShader,GL20.GL_TRIANGLES); renderer.testShader.end(); } } }

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  • rotating menu with Actors in libgdx

    - by joecks
    I am intending to build a circular menu, with menu items equally distributed around the circle. When clicking on a menu item the circle should rotate so that the selected item is facing the top. I am using libgdx and I am not very familiar with the Actors concept, so I intuitivly tried to implement an Actor, who is drawing a texture and then transforming it by using Actions, with no success: class CircleActor extends Actor { @Override public void draw(SpriteBatch batch, float parentAlpha) { batch.draw(texture1, 100, 100); } @Override public Actor hit(float x, float y) { return this; } } and the rotate action: CircleActor circleActor = new CircleActor(); circleActor.action(Forever.$(RotateBy.$(0.1f, 0.1f))); // stage.addActor(); stage.addActor(circleActor); The texture is rectangular, but it doe not work. 1. What is wrong? 2. Is it a good approach to solve the task? Thanks!

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  • HTML5 clicking objects in canvas

    - by Dave
    I have a function in my JS that gets the user's mouse click on the canvas. Now lets say I have a random shape on my canvas (really its a PNG image which is rectangular) but i don't want to include any alpha space. My issue lies with lets say i click some where and it involves a pixel of one of the images. The first issue is how do you work out the pixel location is an object on the map (and not the grass tiles behind). Secondly if i clicked said image, if each image contains its own unique information how do you process the click to load the correct data. Note I don't use libraries I personally prefer the raw method. Relying on libraries doesn't teach me much I find.

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  • How should I choose quadtree depth?

    - by Evpok
    I'm using a quadtree to prune collision detection pairs in a 2d world. How should I choose to what depth said quadtree is calculated? The world is made mostly of moving objects1, so the cost of dispatching the objects between the quadtree cells matters. What is the relationship between the gain from less collision checking and the loss from more dispatching? How can I strike a balance that performs optimally? 1 To be completely explicit, they are autonomous self-replicating cells competing for food sources. This is an attempt to show my pupils predator-prey dynamics and genetic evolution at work.

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  • Storing a Hex Grid

    - by Pedro Caetano
    I've been creating a small hex grid framework for Unity3D and have come to the following dilema. This is my coordinate system (taken from here) Link because I'm a new user It all works pretty nicely except for the fact I have no idea how to store it. I originally intended to store this in a 2D array and use images to generate my maps. One problem was that it had negative values (this was easily fixed by offsetting the coordinates a bit). However, due to this coordinate system, such an image or bitmap would have to be diamond shaped - and since these structures are square shaped, this would cause a lot of headaches even if I hack something together. Is there anything I'm missing that could fix this? I recall seeing a forum post regarding this in the unity forums but I can no longer find the link. Is writing a set of coordinate translators the best solution here? If you guys think it would be helpful, I can post code and images of my problem.

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  • Java enum pairs / "subenum" or what exactly?

    - by vemalsar
    I have an RPG-style Item class and I stored the type of the item in enum (itemType.sword). I want to store subtype too (itemSubtype.long), but I want to express the relation between two data type (sword can be long, short etc. but shield can't be long or short, only round, tower etc). I know this is wrong source code but similar what I want: enum type { sword; } //not valid code! enum swordSubtype extends type.sword { short, long } Question: How can I define this connection between two data type (or more exactly: two value of the data types), what is the most simple and standard way? Array-like data with all valid (itemType,itemSubtype) enum pairs or (itemType,itemSubtype[]) so more subtype for one type, it would be the best. OK but how can I construct this simplest way? Special enum with "subenum" set or second level enum or anything else if it does exists 2 dimensional "canBePairs" array, itemType and itemSubtype dimensions with all type and subtype and boolean elements, "true" means itemType (first dimension) and itemSubtype (second dimension) are okay, "false" means not okay Other better idea Thank you very much!

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  • OpenGL ES 2.0 gluUnProject

    - by secheung
    I've spent more time than I should trying to get my ray picking program working. I'm pretty convinced my math is solid with respect to line plane intersection, but I believe the problem lies with the changing of the mouse screen touch into 3D world space. Heres my code: public void passTouchEvents(MotionEvent e){ int[] viewport = {0,0,viewportWidth,viewportHeight}; float x = e.getX(), y = viewportHeight - e.getY(); float[] pos1 = new float[4]; float[] pos2 = new float[4]; GLU.gluUnProject( x, y, 0.0f, mViewMatrix, 0, mProjectionMatrix, 0, viewport, 0, pos1, 0); GLU.gluUnProject( x, y, 1.0f, mViewMatrix, 0, mProjectionMatrix, 0, viewport, 0, pos2, 0); } Just as a reference I've tried transforming the coordinates 0,0,0 and got an offset. It would be appreciated if you would answer using OpenGL ES 2.0 code.

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  • Player Movement DirectX

    - by SullY
    I'm reading on a Book that's about Gamedevelopment with C++ and DirectX 9. There is something that interrests me: It says that playermovements are increasing with the power of the CPU. Becouse a faster CPU will move the player with every frame ( better CPU = better FPS ) To bypass it, it says you have just to multiplicate time*movementfactor . I'd like to know is there an another way to bypass it ?

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