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  • PHP line break with file_put_contents()

    - by steve-o
    I can't seem to figure out why the following code doesn't produce a new line in my text file - neither does using \n etc either - any ideas what could be wrong? $data = $name . ' | ' . $_POST['comment'] . PHP_EOL; //write to file $f = file_put_contents('posts.txt', $data, FILE_APPEND);

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  • [PHP] Check Valid date type

    - by yukou
    may be this question had been asked, I've searched but still not confident about my problem.. my problem is checking valid date from string $a='23-June-11'; //valid $b='Normal String';//invalid I want to convert $a and $b using strtotime() before I do that, of course i want to validate whether $a or $b is a valid date format From $a i can get 23, 11 using explode function, but how about 'June'? using function above, 'June' is not numeric

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  • Add a + sign to a +ve number in PHP

    - by user318466
    I need to design a function to return -ve numbers unchanged but should add a + sign at the start of the number if its alreay no present. Example: Input Output ---------------- +1 +1 1 +1 -1 -1 It will get only numeric input. function formatNum($num) { # something here..perhaps a regex? } This function is going to be called several times in echo/print so the quicker the better.

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  • Mail php function does'nt send the email

    - by Mamadou
    Hello everybody, I have the following code wich work on some server and does not work in an other: $Name = "myname"; //senders name $email_sender = "[email protected]"; //senders e-mail adress $recipient = $email; //recipient $mail_body = "The text for the mail..."; //mail body $subject = "Subject for reviever"; //subject $header = "From: ". $Name . " <" . $email_sender . ">\r\n"; $status = mail($recipient, $subject, $mail_body, $header); print('ENVOI '. $status); the $status variable is true but i dont see any email.

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  • PHP & MySQL query value question.

    - by space
    How can I use the first query's id value $row['id'] again after I run a second query inside the while loop statement? To show you what I mean here is a sample code below of what I'm trying to do. I hope I explained it right. Here is the code. $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id = 4"); if (!$dbc) { // There was an error...do something about it here... print mysqli_error($mysqli); } while($row = mysqli_fetch_assoc($dbc)) { echo '<div>User: ' . $row['id'] . '</div>'; echo '<div>Link To User' . $row['id'] . '</div>'; $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc2 = mysqli_query($mysqli,"SELECT COUNT(cid) as num FROM comments WHERE comments_id = $row[id]"); if (!$dbc2) { // There was an error...do something about it here... print mysqli_error($mysqli); } else { while($row = mysqli_fetch_array($dbc2)){ $num = $row['num']; } } echo '<div>User ' . $row['id'] . ' Comments# ' . $num . '</div>'; }

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  • Empty files generated from running `mysqldump` using PHP

    - by alex
    I keep getting empty files generated from running $command = 'mysqldump --opt -h localhost -u username -p \'password\' dbname > \'backup 2009-04-15 09-57-13.sql\''; command($command); Anyone know what might be causing this? My password has strange characters in it, but works fine with connecting to the db. I've ran exec($command, $return) and outputted the $return array and it is finding the command. I've also ran it with mysqldump > file.sql and the file contains Usage: mysqldump [OPTIONS] database [tables] OR mysqldump [OPTIONS] --databases [OPTIONS] DB1 [DB2 DB3...] OR mysqldump [OPTIONS] --all-databases [OPTIONS] For more options, use mysqldump --help So it would seem like the command is working.

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  • Substr from end of string php?

    - by Gorostas
    I have this kind of array, i will make it very simple to understand $picture = ( 'artist2-1_thumb.jpg', 'artist2-2.jpg' , 'artist2-3_thumb.jpg', 'artist2-4.jpg', 'artist2-5_thumb.jpg'); Now i want use substr to get new array that only have thumb, to have new array like this $picturethumbs = ( 'artist2-1_thumb.jpg', 'artist2-3_thumb.jpg', 'artist2-5_thumb.jpg'); Can some substr but where to start?

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  • php adding value to session

    - by antikbd
    I am trying to implement a 'shopping cart' where, if the 'Add to Cart' has been clicked, the respective item is either added to the cart or incremented by one if already present. However, the following code isn't working and giving me a "Cannot use a scalar value as an array" error. Any help would be highly appreciated. if (isset($_POST['fan']) && ($_POST['fan']=="Add to Cart")) { if (($_SESSION['cart']['fan']==0) || (!isset($_SESSION['cart']['fan']))) { $_SESSION['cart']['fan']=1; } else { $_SESSION['cart']['fan']++; } }

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  • php associative array name?

    - by daniel Crabbe
    hello! Just trying to get the name of an assoc array; $test = array('selected' =>$selected, 'sectionList'=>$sectionList, 'categoryList'=>$categoryList); <? foreach($test as $list) { ?> <h3><?=$list?>, <?=$list[id]?>, <?=$list['name']?>, <?=$list['value']?></h3> <? } ?> but either get 'Array' or nothing?! I can see the name when i print_r($test); Do you think this is possible? Thanks in advance, D.

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  • find the total values get in a variable in php

    - by Hmwd
    hi, i am doing a shopping cart.i had a variable $total.when i add 1st product of price 200 i get $total=200 , when i add 2nd product of price 100 i get $total=200100 when i add 3rd product of price 400 i get $total=200100400 . i want to get $total=700. how to fix this problem? please help me........ thanks, Hmwd

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  • PHP - Search array in array

    - by Anonymous2011
    I have tried googling for the past one hour straight now and tried many ways to search for an array, in an array. My objective is, to find a keyword in the URL, and the keywords are in a txt file. This is what i have so far - but doesn't work. $file = "keywords.txt"; $open = fopen($file,'r'); $data = fread($open,filesize($file)); $data = explode(" ",$data); $url = (!empty($_SERVER['HTTPS'])) ? "https://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI'] : "http://".$_SERVER['SERVER_NAME'].$_SERVER['REQUEST_URI']; $url = parse_url($url); //parse the URL into an array foreach($data as $d) { if(strstr($d,$url)) { echo "yes"; } } This works WITHOUT the text file, or array - but that's not what i want. I'd appreciate it if anyone can assist me.

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  • PHP Forms checkbox calculation

    - by Sef
    Hello, I am trying to perform some calculations with a form but every time i try to work with checkboxes it goes wrong. The checkboxes are beign set on value 1 in the form itselff and are being checked if there checked or not. $verdieping = isset($_POST["verdieping"]) ? $_POST["verdieping"] : 0; $telefoon = isset($_POST["telefoon"]) ? $_POST["telefoon"] : 0; $netwerk = isset($_POST["netwerk"]) ? $_POST["netwerk"] : 0; When i try to do calculations every works expect for the options with the checkboxes. When both checkboxes (telefoon & netwerk) are selected the value should be 30. If only one is selected the value should be 20. But no mather what i have tried to write down it always give problem, and it always uses 20, never the value 30. How do i solve this problem? Or suppose i am writing the syntax all wrong to lay conditions to a calculation? Any input appreciated. $standnaam = $_SESSION["standnaam"]; $oppervlakte = $_SESSION["oppervlakte"]; $verdieping = $_SESSION["verdieping"]; $telefoon = $_SESSION["telefoon"]; $netwerk = $_SESSION["netwerk"]; if ($oppervlakte <= 10) $tarief = 100; if ($oppervlakte > 10 && $oppervlakte <= 20) $tarief = 90; if ($oppervlakte > 20) $tarief = 80; if($verdieping == 1) { $prijsVerdieping = $oppervlakte * 120; } else { $prijsVerdieping = 0; } if(($telefoon == 1) && ($netwerk == 1)) { $prijsCom = 30; // never get this value, it always uses 20 } if(($telefoon == 1) || ($netwerk == 1)) { $prijsCom = 20; } $prijsOpp = $tarief * $oppervlakte; // works $totalePrijs = $prijsOpp + $prijsVerdieping + $prijsCom; //prijsCom value is always wrong Regards.

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  • Testing if string is sha1 in PHP

    - by SGWebsNow
    I'm planning on storing the passwords as a sha1, so I need a way to validate that it is a sha1 at another point in my website. I was planning on using preg_match, but I do not know how to make regex patterns. Could someone help me out with one? Thanks

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  • unix timestamps and php

    - by sea_1987
    I have a list of unix timestamps in a database, and I wanting to select the ones that are from today. i.e If today is Tueday, I want to get all the timestamps that were made today? Is it possible? Is there such a things as strtotime("Today")? Any help would be great

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  • PHP: question about passing parameters in URL's

    - by user248959
    Hi, i have this two lines: var_dump($parametros_post_signin); $this->redirect('prueba/aux?email='.$parametros_post_signin['signin']); the first one prints this: array 'signin' => array 'email_address' => string '' (length=0) 'password' => string '' (length=0) the second one takes to another action where i have this code: var_dump($request->getParameter('email')); that prints this: string 'password' (length=8) I expected it to print something like this: string '' (length=0) What should i do to the get value of the 'email_address' field ? Regards Javi

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  • downloading security related problem in php

    - by pareek-rohit
    hi i have to upload a video.but i want to gives permission only authenticate user to download .but i have a problem in that.because if any body type the video detail in browser.(ex http://sitename/folder_name/videoname) then browser download that video.but i don't want this .please suggest me how can i resolve this problem.either i should generate the video name randomly or make a temporary folder in which video reside only for specific time,after this video will be delete. Or if any other ideas you have please let me know Thanks in advance

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  • generating images by user id php + mysql

    - by jay
    function user_image($id, $increment_views = false) { $id = mysql_real_escape_string($id); $q = mysql_query("SELECT * FROM `images` WHERE `id` = '$id'"); if (mysql_num_rows($q)) { $return = mysql_fetch_assoc($q); $q = mysql_query("SELECT * FROM `sources` WHERE `source_id` = $return[id] AND `source_flagged` = 0"); while ($r = mysql_fetch_assoc($q)) { $return['sources'][] = $r; } if ($increment_views) { $q = mysql_query("UPDATE `images` SET `views` = `views` + 1 WHERE `id` = $return[id]"); } return $return; } else { return false; } }

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