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  • Echo autoincrement id doubt

    - by Marcelo
    Hi, can I print the id, even if it's autoincrement ? Because the way I'm doing I'm using an empty variable for id. $id= ""; mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die ("Não conectou com a base $database"); mysql_query("INSERT INTO table1(id,...) VALUES ('".$id."',....)") or die(mysql_error()); mysql_close(); echo "Your id is :"; echo "".$id; I'm trying to print the id, but it's coming blank. I checked the table and there's an id number there. How can I print it then at? Thanks for the attention

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  • SQL How to join multiplue columns with same name to one column

    - by Choi Shun Chi
    There is a super class account {User, TYPE} and subclasses saving{User, ID, balance,TYPE,interest,curency_TYPE} time{User,ID,balance,TYPE,interest,curency_TYPE,start_date,due_date,period} fore{User,ID,balance,interest,curency_TYPE} User and TYPE is the primary key of account and foreign key of three subclasses ID is primary key of three subclasses how to make a list of showing all IDs in one column?Also the same as balance and TYPE meet the problem I considered a.ID as saving, b.ID as time but it showing them separately

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  • how to get latest entry from a table for an item and do arithmatic operation on it?

    - by I Like PHP
    i have below tables tbl_rcv_items st_id | item_id |stock_opening_qnty |stock_received_qnty |stock_rcvd_date 14 1 0 70 2010-05-18 15 16 0 100 2010-05-06 16 10 0 59 2010-05-20 17 14 0 34 2010-05-20 20 1 70 5 2010-05-12 tbl_issu_items issue_id refer_issue_id item_id item_qntt item_updated 51 1 1 5 2010-05-18 19:34:29 52 1 16 6 2010-05-18 19:34:29 53 1 10 7 2010-05-18 19:34:29 54 1 14 8 2010-05-18 19:34:29 75 7 1 12 2010-05-18 19:40:52 76 7 16 1 2010-05-18 19:40:52 77 7 10 1 2010-05-18 19:40:52 78 7 14 1 2010-05-18 19:40:52 79 8 1 3 2010-05-19 11:28:50 80 8 16 5 2010-05-19 11:28:50 81 8 10 6 2010-05-19 11:28:50 82 8 14 7 2010-05-19 11:28:51 87 10 1 2 2010-05-19 12:51:03 88 10 16 0 2010-05-19 12:51:03 89 10 10 0 2010-05-19 12:51:03 90 10 14 0 2010-05-19 12:51:03 91 14 1 1 2010-05-19 18:43:58 92 14 14 3 2010-05-19 18:43:58 tbl_item_detail item_id item_name 1 shirt 2 belt 10 ball pen 14 vim powder 16 pant NOW if i want total available quantity for each item till today using both table total available quantity for an item =stock_opening_qnty+stock_received_qnty(LATEST ENTRY FROM (tbl_rcv_item) for that item id according to stock_rcvd_date) - SUM(item_qntt) for eg: if i want to know the available quantity for item_id=1 till today(25-05-2010) then it shoud be 70+5(latest entry for item_id till 25/5/2010)-23( issued till 25/5/2010)=52 i write below query , SELECT tri.item_id, tid.item_name, (tri.stock_opening_qnty + tri.stock_received_qnty) AS totalRcvQntt, SUM( tii.item_qntt ) AS totalIsudQntt FROM tbl_rcv_items tri JOIN tbl_issu_items tii ON tii.item_id = tri.item_id JOIN tbl_item_detail tid ON tid.item_id=tri.item_id WHERE tri.stock_rcvd_date <= CURDATE() GROUP BY (tri.item_id) which results Array ( [0] => Array ( [item_id] => 1 [item_name] => shirt [totalRcvQntt] => 70 [totalIsudQntt] => 46 ) [1] => Array ( [item_id] => 10 [item_name] => ball pen [totalRcvQntt] => 59 [totalIsudQntt] => 16 ) [2] => Array ( [item_id] => 14 [item_name] => vim powder [totalRcvQntt] => 34 [totalIsudQntt] => 20 ) [3] => Array ( [item_id] => 16 [item_name] => pant [totalRcvQntt] => 100 [totalIsudQntt] => 17 ) ) in above result total isuse quantity for shirt(item_id=1) shoube be 23 whereas results reflects 46 bcoz there are two row regrading item_id=1 in tbl_rcv_items, i only need the latest one(means which stock_rcvd_date is less than tommorow) please tell me where i doing mistake?? or rewrite the best query. thanks a lot!

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  • Fetch posts with attachments in a certain category?

    - by TiuTalk
    I need to retreive a list of posts that have (at least) one attachment that belongs to a category in WordPress. The relation between attachments and categories I made by myself using the WordPress default method. Here's the query that i'm running right now: SELECT p.* FROM `wp_posts` AS p # The post INNER JOIN `wp_posts` AS a # The attachment ON p.`ID` = a.`post_parent` AND a.`post_type` = 'attachment' INNER JOIN `wp_term_relationships` AS ra ON a.`ID` = ra.`object_id` AND ra.`term_taxonomy_id` IN (3) # The category ID list WHERE p.`post_type` = 'post' ORDER BY p.`post_date` DESC LIMIT 15 The problem here is that the query only use the first found attachment, and if it doesn't belongs to the category, the result isn't returned.

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  • How can I write this query in Django? (datetime)

    - by alex
    | time_before | datetime | YES | MUL | NULL | | | time_after | datetime | YES | MUL | NULL | | the_tag = Tag.objects.get(id=tag_id) Log.objects.filter(blah).extra(where=['last_updated >'+the_tag.time_before, 'last_updated' < the_tag.time_after]) Ok. Basically, I have an object that's called "the_tag". I want to select from Log where log.last_updated (which is a datetime field) is between the tag's time. But, I don't know how to write the last part of this Django query.

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  • Basic join query understanding

    - by OM The Eternity
    I know this very silly, but can anybody help me in understanding what does this join query is doing in elabortive description? SELECT j1.* FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON (j1.trackid = j2.trackid AND j1.field = j2.field AND j1.changedone < j2.changedone) WHERE j1.operation = 'UPDATE' AND j1.trackid=$t_ids[$n] AND j2.id IS NULL I know its very silly, but i need to go ahead with my further need... Pls do help me...

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  • Checking inherited attributes in an 'ancestry' based SQL table

    - by Brendon Muir
    I'm using the ancestry gem to help organise my app's tree structure in the database. It basically writes a childs ancestor information to a special column called 'ancestry'. The ancestry column for a particular child might look like '1/34/87' where the parent of this child is 87, and then 87's parent is 34 and 34's is 1. It seems possible that we could select rows from this table each with a subquery that checks all the ancestors to see if a certain attribute it set. E.g. in my app you can hide an item and its children just by setting the parent element's visibility column to 0. I want to be able to find all the items where none of their ancestors are hidden. I tried converting the slashes to comma's with the REPLACE command but IN required a set of comma separated integers rather than one string with comma separated string numbers. It's funny, because I can do this query in two steps, e.g. retrieve the row, then take its ancestry column, split out the id's and make another query that checks that the id is IN that set of id's and that visibility isn't ever 0 and whala! But joining these into one query seems to be quite a task. Much searching has shown a few answers but none really do what I want. SELECT * FROM t1 WHERE id = 99; 99's ancestry column reads '1/34/87' SELECT * FROM t1 WHERE visibility = 0 AND id IN (1,34,87); kind of backwards, but if this returns no rows then the item is visible. Has anyone come across this before and come up with a solution. I don't really want to go the stored procedure route. It's for a rails app.

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  • How to determine the difference among dates in the same column?

    - by Vera
    How to determine the difference among dates of birth? +----------+----------+------------+ | id | name | birth | +----------+----------+------------+ | 00001 | Claws | 2010-04-17 | | 00002 | Claws | 2010-01-31 | | 00003 | Claws | 2009-11-31 | | 00004 | Claws | 2009-09-31 | | 00005 | Claws | 2009-07-31 | | 00006 | Claws | 2008-10-31 | +----------+----------+------------+ I would like to obtain this: +----------+----------+------------+------------------------------------------+ | id | name | birth | diff | +----------+----------+------------+------------------------------------------+ | 00001 | Claws | 2010-04-17 | diff (id1-id2) = 2010-01-31 - 2010-04-17 | | 00002 | Claws | 2010-01-31 | diff (id2-id3) = 2010-01-31 - 2009-11-31 | | 00003 | Claws | 2009-11-31 | diff (id3-id4) = 2010-01-31 - 2009-09-31 | If possible, ORDER BY diff DESC Thank you for helping Vera

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  • Is using Natural Join or Implicit column names not a good practice when writing SQL in a programming

    - by Jian Lin
    When we use Natural Join, we are joining the tables when both table have the same column names. But what if we write it in PHP and then the DBA add some more fields to both tables, then the Natural Join can break? The same goes for Insert, if we do a insert into gifts values (NULL, "chocolate", "choco.jpg", now()); then it will break the code as well as contaminating the table when the DBA adds some fields to the table (example as column 2 or 3). So it is always best to spell out the column names when the SQL statements are written inside a programming language and stored in a file in a big project.

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  • atk4 advanced crud?

    - by thindery
    I have the following tables: -- ----------------------------------------------------- -- Table `product` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `product` ( `id` INT NOT NULL AUTO_INCREMENT , `productName` VARCHAR(255) NULL , `s7location` VARCHAR(255) NULL , PRIMARY KEY (`id`) ) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `pages` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `pages` ( `id` INT NOT NULL AUTO_INCREMENT , `productID` INT NULL , `pageName` VARCHAR(255) NOT NULL , `isBlank` TINYINT(1) NULL , `pageOrder` INT(11) NULL , `s7page` INT(11) NULL , PRIMARY KEY (`id`) , INDEX `productID` (`productID` ASC) , CONSTRAINT `productID` FOREIGN KEY (`productID` ) REFERENCES `product` (`id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; -- ----------------------------------------------------- -- Table `field` -- ----------------------------------------------------- CREATE TABLE IF NOT EXISTS `field` ( `id` INT NOT NULL AUTO_INCREMENT , `pagesID` INT NULL , `fieldName` VARCHAR(255) NOT NULL , `fieldType` VARCHAR(255) NOT NULL , `fieldDefaultValue` VARCHAR(255) NULL , PRIMARY KEY (`id`) , INDEX `id` (`pagesID` ASC) , CONSTRAINT `pagesID` FOREIGN KEY (`pagesID` ) REFERENCES `pages` (`id` ) ON DELETE NO ACTION ON UPDATE NO ACTION) ENGINE = InnoDB; I have gotten CRUD to work on the 'product' table. //addproduct.php class page_addproduct extends Page { function init(){ parent::init(); $crud=$this->add('CRUD')->setModel('Product'); } } This works. but I need to get it so that when a new product is created it basically allows me to add new rows into the pages and field tables. For example, the products in the tables are a print product(like a greeting card) that has multiple pages to render. Page 1 may have 2 text fields that can be customized, page 2 may have 3 text fields, a slider to define text size, and a drop down list to pick a color, and page 3 may have five text fields that can all be customized. All three pages (and all form elements, 12 in this example) are associated with 1 product. So when I create the product, could i add a button to create a page for that product, then within the page i can add a button to add a new form element field? I'm still somewhat new to this, so my db structure may not be ideal. i'd appreciate any suggestions and feedback! Could someone point me toward some information, tutorials, documentation, ideas, suggestions, on how I can implement this?

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  • LAMP stack on home computer as a public web server

    - by Scott
    So I'm using this website: http://www.howtoforge.com/ubuntu_debian_lamp_server to setup LAMP on my Ubuntu Virtual Machine. Here is my question though, This will enable me to program and test through localhost. How can I set this up so anyone on the web can access my .php pages from any Internet capable device, and they will still interact with my local database, etc?

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  • Debug irrelevant Wordpress search results

    - by konzepz
    On Wordpress, I keep getting irrelevant search results. Some search strings that do not exist on the DB yield All Posts as results. Some search strings that DO exist, works great. What could be the cause of that behavior? I've uninstalled all related plugins. Is there a way to debug the search? Thanks!

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  • Creating a Variable that is the Sum of Two Other Variables

    - by John
    Hello, For the code below, I would like to make a new variable called totalScore2 that equals days + totalScore. How can I do this? Thanks in advance, John $sqlStr = "SELECT l.loginid, l.username, l.created, DATEDIFF(NOW(), l.created) AS days, COALESCE(s.total, 0) AS countSubmissions, COALESCE(c.total, 0) AS countComments, COALESCE(s.total, 0) * 10 + COALESCE(c.total, 0) AS totalScore

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  • How to access stdClass variables stdClass Object([max(id)])=>64)

    - by Theopile
    I need the very last valid entry in a database table which would be the row with the greatest primary key. So using mysqli, my query is "SELECT MAX(id) FROM table LIMIT 1". This query returns the correct number(using print_r()) but I cannot figure out how to access it. Here is the main code. Note that the $this-link refers to class with a mysqli connection. $q="select max(id) from stones limit 1"; $qed=$this->link->query($q) or die(mysqli_error()); if($qed){ $row=$qed->fetch_object(); print_r($row); echo $lastid=$row;//here is the problem } The valid line print_r($row) echos out "stdClass Object ( [max(id)] = 68 )"

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  • SELECT a list of elements and 5 tags for each one

    - by Vittorio Vittori
    Hi, I'm trying to query a set of buldings listed on a table, these buildings are linked with tags. I'm able to do it, but my problem is how limit the number of tags to see: table buildings id building_name style 1 Pompidou bla 2 Alcatraz bla 3 etc. etc. table tags // they can be 50 or more per building id tag_name 1 minimal 2 gothic 3 classical 4 modern 5 etc. table buildings_tags id building_id tag_id I though to do something like this to retrieve the list, but this isn't compplete: SELECT DISTINCT(tag), bulding_name FROM buldings INNER JOIN buildings_tags ON buildings.id = buildings_tags.building_id INNER JOIN tags ON tags.id = buildings_tags.tag_id LIMIT 0, 20 // result building tag Pompidou great Pompidou france Pompidou paris Pompidou industrial Pompidou renzo piano <= How to stop at the 5th result? Pompidou hi-tech Pompidou famous place Pompidou wtf etc.. etc... this query loads the buildings, but this query loads all the tags linked for the building, and not only 5 of them?

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  • SQL select statement

    - by kwokwai
    Hi all, I got a Table which has two fields: Point, and Level, with some sample data as follows: ----------------------- Point | Level ----------------------- 10 | Level 1 20 | Level 2 30 | Level 3 40 | Level 4 Suppose that there is a user who has 25 points, to find the Level in which this user is in, the Select statement I used was: Select Level from Table where Point < 30 AND Point > 20; But the Select SQL ststament is a hard-copy one where you can see the ponts 30 and 20 are fixed. I want to alter the Select statement so that the new SQL Select statement can be applied to all users with different points, but I don't know how to do it.

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  • Sql query - selecting top 5 rows and further selecting rows only if User is present

    - by Gublooo
    Hello, I kind of stuck on how to implement this query - this is pretty similar to the query I posted earlier but I'm not able to crack it. I have a shopping table where everytime a user buys anything, a record is inserted. Some of the fields are * shopping_id (primary key) * store_id * user_id Now what I need is to pull only the list of those stores where he's among the top 5 visitors: When I break it down - this is what I want to accomplish: * Find all stores where this UserA has visited * For each of these stores - see who the top 5 visitors are. * Select the store only if UserA is among the top 5 visitors. The corresponding queries would be: select store_id from shopping where user_id = xxx select user_id,count(*) as 'visits' from shopping where store_id in (select store_id from shopping where user_id = xxx) group by user_id order by visits desc limit 5 Now I need to check in this resultset if UserA is present and select that store only if he's present. For example if he has visited a store 5 times - but if there are 5 or more people who have visited that store more than 5 times - then that store should not be selected. So I'm kind of lost here. Thanks for your help

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  • How to map to tables in database PHPMyAdmin

    - by thegrede
    I'm working now on a project which a user can save their own coupon codes on the websites, so I want to know what is the best to do that, Lets say, I have 1 table with the users, like this, userId | firstName | lastName | codeId and then I have a table of the coupon codes, like this, codeId | codeNumber So what I can do is to connect the codeId to userId so when someone saves the coupons goes the codeId from the coupon table into the codeId of the users table, But now what if when a user have multiple coupons what do I do it should be connected to the user? I have 2 options what to do, Option 1, Saving the codeId from coupons table into the codeId of users table like 1,2,3,4,5, Option 2 To make a new row into the coupons table and to connect the user to the code with adding another field in the coupon table userId and putting into it the user which has added the coupon his userId of the users table, So what of the two options is better to do? Thanks you guys.

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  • Creating search functionality with Laravel 4

    - by Mitch Glenn
    I am trying to create a way for users to search through all the products on a website. When they search for "burton snowboards", I only want the snowboards with the brand burton to appear in the results. But if they searched only "burton", then all products with the brand burton should appear. This is what I have attempted to write but isn't working for multiple reasons. Controller: public function search(){ $input = Input::all(); $v= Validator::make($input, Product::$rules); if($v->passes()) { $searchTerms = explode(' ', $input); $searchTermBits = array(); foreach ($searchTerms as $term) { $term = trim($term); if (!empty($term)){ $searchTermBits[] = "search LIKE '%$term%'"; } } $result = DB::table('products') ->select('*') ->whereRaw(". implode(' AND ', $searchTermBits) . ") ->get(); return View::make('layouts/search', compact('result')); } return Redirect::route('/'); } I am trying to recreate the first solution given for this stackoverflow.com problem The first problem I have identified is that i'm trying to explode the $input, but it's already an array. So i'm not sure how to go about fixing that. And the way I have written the ->whereRaw(". implode(' AND ', $searchTermBits) . "), i'm sure isn't correct. I'm not sure how to fix these problems though, any insights or solutions will be greatly appreciated.

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  • Update multiple rows with one query?

    - by kavoir.com
    I found something that works with updating one field at here: http://www.karlrixon.co.uk/articles/sql/update-multiple-rows-with-different-values-and-a-single-sql-query/ UPDATE person SET name = CASE id WHEN 1 THEN 'Jim' WHEN 2 THEN 'Mike' WHEN 3 THEN 'Precious' END WHERE id IN (1,2,3) My question is how to update more than one field? Such as: UPDATE person SET name = CASE, sex = CASE id WHEN 1 THEN 'Jim', 'female' WHEN 2 THEN 'Mike' 'male' WHEN 3 THEN 'Precious', 'male' END WHERE id IN (1,2,3) Which doesn't work of course. Tried a few other combination and failed. Any idea? Thanks!

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  • PHP replace string help...

    - by MILESMIBALERR
    i am designing a site with a comment system and i would like a twitter like reply system. The if the user puts @a_registered_username i would like it to become a link to the user's profile. i think preg_replace is the function needed for this. $ALL_USERS_ROW *['USERNAME'] is the database query array for all the users and ['USERNAME'] is the username row. $content is the comment containing the @username i think this should not be very hard to solve for someone who is good at php. Does anybody have any idea how to do it?

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  • Search & Replace SQL

    - by Shonna
    I am messing around with one of my databases.. is there away for me to search for a string in ALL the tables.. and replace it with another everywhere it occurs? I am looking for SQL

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