Search Results

Search found 88004 results on 3521 pages for 'code for eternity'.

Page 343/3521 | < Previous Page | 339 340 341 342 343 344 345 346 347 348 349 350  | Next Page >

  • What is the best way to reduce code and loop through a hierarchial commission script?

    - by JM4
    I have a script which currently "works" but is nearly 3600 lines of code and makes well over 50 database calls within a single script. From my experience, there is no way to really "loop" the script and minimize it because each call to the database is a subquery of the ones before based on referral ids. Perhaps I can give a very simple example of what I am trying to accomplish and see if anybody has experience with something similar. In my example, there are three tables: Table 1 - Sellers ID | Comm_level | Parent ----------------------------------- 1 | 4 | NULL 2 | 3 | 1 3 | 2 | 1 4 | 2 | 2 5 | 2 | 2 6 | 1 | 3 Where ID is the id of one of our sales agents, comm_level will determine what his commission percentage is for each product he sells, parent indicates the ID for whom recruited that particular agent. In the example above, 1 is the top agent, he recruited two agents, 2 and 3. 2 recruited two agents, 4 and 5. 3 recruited one agent, 6. NOTE: An agent can NEVER recruit anybody equal to or higher than their own level. Table 2 - Commissions Level | Item 1 | Item 2 | Item 3 ----------------------------------------------------- 4 | .5 | .4 | .3 3 | .45 | .35 | .25 2 | .4 | .3 | .2 1 | .35 | .25 | .15 This table lays out the commission percentages for each agent based on their actual comm_level (if an agent is at a level 4, he will receive 50% on every item 1 sold, 40% on every item 2, 30% on every item 3 and so on. Table 3 - Items Sold ID | Item --------------------- 4 | item_1 4 | item_2 1 | item_1 2 | item_3 6 | item_2 1 | item_3 This table pairs the actual item sold with the seller who sold the item. When generating the commission report, calculating individual values is very simple. Calculating their commission based on their sub_sellers however is very difficult. In this example, Seller ID 1 gets a piece of every single item sold. The commission percentages indicate individual sales or the height of their commission. For example: When seller ID 6 sold one of item_2 above, the tree for commissions will look like the following: -ID 6 - 25% of cost(item_1) -ID 3 - 5% of cost(item_1) - (30% is his comm - 25% comm of seller id 6) -ID 1 - 10% of cost(item_1) - (40% is his comm - 30% of seller id 3) This must be calculated for every agent in the system from the top down (hence the DB calls within while loops throughout my enormous script). Anybody have a good suggestion or samples they may have used in the past?

    Read the article

  • What is the use of mysql_rollback() function in PHP?

    - by OM The Eternity
    What is the use of mysql_rollback() function in PHP? How is it used? please explain me with some example, PS: Please Do not give me link to the php.net or, mysql site, I dont need AUTHOR language to understand it, I need the Developer way to understand... I hope u understand... Thanks in advance. UPDATE if i have Updated something in a tanle can i Reset the previous value using this function?

    Read the article

  • How to sync two folders in PHP?

    - by OM The Eternity
    I am using windows, Mysql DB, PHP I am building the Joomla Component whose one of the functionality is to synchronize the folders I want to sync two folders of different name.. How can I do this? It has to be dne in the same machine, no two different servers are involved in it.. How to sync two folders in PHP?

    Read the article

  • Error in configuration file

    - by OM The Eternity
    I have copied my project folder from my live server to my local host and edited the config file as per localhost, but still i am displayed with the "Internal Server Error:500" The server encountered an internal error or misconfiguration and was unable to complete your request. Please contact the server administrator, admin@localhost and inform them of the time the error occurred, and anything you might have done that may have caused the error. More information about this error may be available in the server error log. I cannot understand what should be the problem here, please help me to track the issue here....

    Read the article

  • What is user gcc's purpose in requesting code possibly like this?

    - by James Morris
    In the question between syntax, are there any equal function the user gcc is requesting only what I can imagine to be the following code: #include <stdio.h> #include <string.h> /* estimated magic values */ #define MAXFUNCS 8 #define MAXFUNCLEN 3 int the_mainp_compare_func(char** mainp) { char mainp0[MAXFUNCS][MAXFUNCLEN] = { 0 }; char mainp1[MAXFUNCS][MAXFUNCLEN] = { 0 }; char* psrc, *pdst; int i = 0; int func = 0; psrc = mainp[0]; printf("scanning mainp[0] for functions...\n"); while(*psrc) { if (*psrc == '\0') break; else if (*psrc == ',') ++psrc; else { mainp0[func][0] = *psrc++; if (*psrc == ',') { mainp0[func][1] = '\0'; psrc++; } else if (*psrc !='\0') { mainp0[func][1] = *psrc++; mainp0[func][2] = '\0'; } printf("function: '%s'\n", mainp0[func]); } ++func; } printf("\nscanning mainp[1] for functions...\n"); psrc = mainp[1]; func = 0; while(*psrc) { if (*psrc == '\0') break; else if (*psrc == ',') ++psrc; else { mainp1[func][0] = *psrc++; if (*psrc == ',') { mainp1[func][1] = '\0'; psrc++; } else if (*psrc !='\0') { mainp1[func][1] = *psrc++; mainp1[func][2] = '\0'; } printf("function: '%s'\n", mainp1[func]); } ++func; } printf("\ncomparing functions in '%s' with those in '%s'\n", mainp[0], mainp[1] ); int func2; func = 0; while (*mainp0[func] != '\0') { func2 = 0; while(*mainp1[func2] != '\0') { printf("comparing %s with %s\n", mainp0[func], mainp1[func2]); if (strcmp(mainp0[func], mainp1[func2++]) == 0) return 1; /* not sure what to return here */ } ++func; } /* no matches == failure */ return -1; /* not sure what to return on failure */ } int main(int argc, char** argv) { char* mainp[] = { "P,-Q,Q,-R", "R,A,P,B,F" }; if (the_mainp_compare_func(mainp) == 1) printf("a match was found, but I don't know what to do with it!\n"); else printf("no match found, and I'm none the wiser!\n"); return 0; } My question is, what is it's purpose?

    Read the article

  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    How to make the use of hidden variables as array for consecutive submission of data so that they can be used to display the records list. I have a form with 4 text fields and a file upload field.. as i submit he form it should get appended to the list which needs to be displayed below the form, such that these values are NOT stored in the DB.. So in this case how can i use the post array to collect the data and display in the list below?

    Read the article

  • How to display records below form on submission in php without the use of database?

    - by OM The Eternity
    I have a form with multiple fields in it along with a image input field, just below the form i have a list to be displayed on every submit of this form... this has to be done without the use of DB.. I think this can be achieved by using session but its not working with me, as evrytime page gets refreshed and session gets recreated/reset.. Please help me in resolving this issue

    Read the article

  • is it correct to unset the session variable for a particular index as the vay whole session is made

    - by OM The Eternity
    is it correct to unset the session variable for a particular index as the vay whole session is made unset in PHP? I know this works: unset($_SESSION['bannersize']) But does this works ? : unset($_SESSION['bannersize'][3]) or is there any other way to unset any particular desired index of the session and then again rearrange the values inside it to remove the empty index..?

    Read the article

  • How do I defer execution of some Ruby code until later and run it on demand in this scenario?

    - by Kyle Kaitan
    I've got some code that looks like the following. First, there's a simple Parser class for parsing command-line arguments with options. class Parser def initialize(&b); ...; end # Create new parser. def parse(args = ARGV); ...; end # Consume command-line args. def opt(...); ...; end # Declare supported option. def die(...); ...; end # Validation handler. end Then I have my own Parsers module which holds some metadata about parsers that I want to track. module Parsers ParserMap = {} def self.make_parser(kind, desc, &b) b ||= lambda {} module_eval { ParserMap[kind] = {:desc => "", :validation => lambda {} } ParserMap[kind][:desc] = desc # Create new parser identified by `<Kind>Parser`. Making a Parser is very # expensive, so we defer its creation until it's actually needed later # by wrapping it in a lambda and calling it when we actually need it. const_set(name_for_parser(kind), lambda { Parser.new(&b) }) } end # ... end Now when you want to add a new parser, you can call make_parser like so: make_parser :db, "login to database" do # Options that this parser knows how to parse. opt :verbose, "be verbose with output messages" opt :uid, "user id" opt :pwd, "password" end Cool. But there's a problem. We want to optionally associate validation with each parser, so that we can write something like: validation = lambda { |parser, opts| parser.die unless opts[:uid] && opts[:pwd] # Must provide login. } The interface contract with Parser says that we can't do any validation until after Parser#parse has been called. So, we want to do the following: Associate an optional block with every Parser we make with make_parser. We also want to be able to run this block, ideally as a new method called Parser#validate. But any on-demand method is equally suitable. How do we do that?

    Read the article

  • I am getting error as "operation aboarded, Internet explorer can't open the page"

    - by OM The Eternity
    I have created a shopping cart site, and i have got two complains for the same issue, but i am not able to track the main problem... They whenever they complete the process and reach at the last page they get the error message as "operation aboarded, Internet explorer can't open the page" Could someone helo me out? what could be the reason behind this.. i tried to get the error in IE-6,7,8 but I didnt get any error... ?

    Read the article

  • Want to avoid the particular rows from select join query... See description

    - by OM The Eternity
    I have a Select Left Join Query whis displays me the rows for the latest changedone(its a time) column name ("field" should not be equal) column name ("trackid" should not be equal), and column name "Operation should be "UPDATE" ", below is the query I am talking about... SELECT j1. * FROM jos_audittrail j1 LEFT OUTER JOIN jos_audittrail j2 ON ( j1.trackid != j2.trackid AND j1.field != j2.field AND j1.changedone < j2.changedone ) WHERE j1.operation = 'UPDATE' AND j2.id IS NULL Now here I don't want a row to be displayed with a two particular column's value i.e. "field's value" the value is "LastvisitDate" and "hits" Now if if append the condition in the above query that " AND j1.field != 'lastvistDate' AND j1.field != 'hits' " theni do not get any result... The table structure is jos_audittrail: id trackid operation oldvalue newvalue table_name live changedone(its a time) I hope i have given the details properly If u still find something missing I will try to provide it more better way... Pls help me to avoid those two rows with those to mentioned value of "field"

    Read the article

< Previous Page | 339 340 341 342 343 344 345 346 347 348 349 350  | Next Page >