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  • Hosted SVN - RepositoryHosting.com

    - by SVN User
    I'm currently reviewing repositoryhosting.com for possibly hosting our company code, however, I'm weary about pushing forward for a few reasons. First, if the company goes under, I have no assurance that I will have access to grab backups of the code prior. Secondly, their terms state this: "User agrees that Repository Hosting shall not be liable for any direct, indirect, incidental, special, consequential or exemplary damages, including but not limited to, damages for loss of profits, goodwill, use, data or other intangible losses resulting from the use of or inability to use the Service." Basically, I want to ensure that our data is safe. I understand that they do offsite backups and such, however, if there were to be a catastrophic loss of data that was their fault, would we be left with just a "sorry"? What about your thoughts on hosted svn and is it better to just continue to do it yourself?

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  • Fluent many-to-many: Deleting one end does not remove the entry in the relation table

    - by Kristoffer
    I have two classes (Parent, Child) that have a many-to-many relationship that only one end (Parent) knows about. My problem is that when I delete a "relation unaware" object (Child), the record in the many-to-many table is left. I want the relationship to be removed regardless of which end of it is deleted. How can I do that with Fluent NHibernate mappings, without adding a Parent property on Child? The classes: public class Parent { public Guid Id { get; set; } public IList<Child> Children { get; set; } } public class Child { public Guid Id { get; set; } // Don't want the property below: // public Parent Parent { get; set; } }

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  • JOIN two tables to show already purchased items

    - by Norbert
    I have a table where I keep all my templates: templates template_id template_name template_price These templates can be purchased by a registered user and then are inserted in the payments table: payments payment_id template_id user_id Is there a way to join these two tables and get not just a list of templates that have been purchased by a certain user, but all the templates? And then figure out from there which ones have already been purchased? I used this SELECT, but only the ones that the user bought showed up. I would like to have all the rows from templates, but empty in case the user_id doesn't match. SELECT * FROM templates LEFT JOIN payments ON templates.template_id = payments.template_id WHERE user_id = 2 GROUP BY templates.template_id

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  • C: switch case with logical operator

    - by Er Avinash Singh
    While I am new to c and want help in this program my code is : #include<stdio.h> #include<conio.h> void main(){ int suite=2; switch(suite) { case 1||2: printf("hi"); case 3: printf("byee"); default: printf("hello"); } printf("I thought somebody"); getche(); } I am working in turbo c and it shows no error and the output is helloI thought somebody Please, let me know how is this working ??? note :- here break is not the case as I intentionally left them.

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  • Should old/legacy/unused code be deleted from source control repository?

    - by Checkers
    I've encountered this in multiple projects. As the code base evolves, some libraries, applications, and components get abandoned and/or deprecated. Most people prefer to keep them in. The usual argument is that the code does not really take any space, it can be left alone until needed again. So a repository slowly turns into a cesspool of legacy code, where it's hard to find anything. Some people delete old code, since it creates clutter, raises more questions for new people, and you can restore any old snapshot of the code base anyway. However you can't always find the old code if you don't know where to look, as none of the (common) VCS I know offer search over the entire repository including all historical revisions, and the only way to search the old files is to check out the revision where the deleted file exists. What would be a good approach to repository management?

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  • jQuery FadeIn, FadeOut Div - IE7 bug

    - by user1058223
    I have a div that will fade in and out on hover in FF, but in IE7 it just hides and shows with no animation. Here is my code: #nav-buttons { display:none; width:894px; position:relative; z-index:1000; } ---------- <div id="contents"> <div id="nav-buttons"> <a href="javascript:void(0)" id="left-button"></a> <a href="javascript:void(0)" id="right-button"></a> </div> other html.... </div> ---------- $(document).ready(function() { $("#contents").hover(function() { $("#nav-buttons").fadeToggle("slow"); }); });

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  • How to pass event to method?

    - by tomaszs
    I would like to create a method that takes as a argument an event an adds eventHandler to it to handle it properly. Like this: I have 2 events: public event EventHandler Click; public event EventHandler Click2; Now i would like to pass particular event to my method like this (pseudocode): public AttachToHandleEvent(EventHandler MyEvent) { MyEvent += Item_Click; } private void Item_Click(object sender, EventArgs e) { MessageBox.Show("lalala"); } ToolStripMenuItem tool = new ToolStripMenuItem(); AttachToHandleEvent(tool.Click); Is it possible or do I not understand it good? Edit: I've noticed with help of you that this code worked fine, and returned to my project and noticed that when I pass event declared in my class it works, but when I pass event from other class id still does not work. Updated above example to reflect this issue. What I get is this error: The event 'System.Windows.Forms.ToolStripItem.Click' can only appear on the left hand side of += or -=

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  • Rotating in OpenGL relative to the viewport

    - by Nick
    I'm trying to display an object in the view which can be rotated naturally by dragging the cursor/touchscreen. At the moment I've got X and Y rotation of an object like this glRotatef(rotateX, 0f, 1f, 0f); // Dragging along X, so spin around Y axis glRotatef(rotateY, 1f, 0f, 0f); I understand why this doesn't do what I want it to do (e.g. if you spin it right 180 degrees, up and down spinning gets reversed). I just can't figure out a way for both directions to stay left-right and up-down relative to the viewer. I can assume that the camera is fixed and looking along the Z axis. Any ideas?

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  • Grab triangles within a lower triangle

    - by Tyler Rinker
    I have the need to grab all the thee element triangles that make up the lower triangle of a symmetric matrix. I can not think of how to grab all these pieces in the order of far left column working down and then next column to the right and so on. I know that the numbe rof mini triangles inside of the lower triangle is: n = x(x - 1)/2 where: x = nrow(mats[[i]]) Here I've created three matrices with letters (it's easier for me to conceptualize this way) and the elements in the order I'm looking for: FUN <- function(n) { matrix(LETTERS[1:(n*n)], n) } mats <- lapply(3:5, FUN) So this is the output I'd like to get (I put it in code rather than output format) for each of the matrices created above: list(c("B", "C", "F")) list(c("B", "C", "G"), c("C", "D", "H"), c("G", "H", "L")) list(c("B", "C", "H"), c("C", "D", "I"), c("D", "E", "J"), c("H", "I", "N"), c("I", "J", "O"), c("N", "O", "T")) How can I do this task in the fastest manner possible while staying in base R? Not sure if this visual of what I'm after is helpful but it may be:

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  • PHP PDO fetch null

    - by Jacob
    How do you check if a columns value is null? Example code: $db = DBCxn::getCxn(); $sql = "SELECT exercise_id, author_id, submission, result, submission_time, total_rating_votes, total_rating_values FROM submissions LEFT OUTER JOIN submission_ratings ON submissions.exercise_id=submission_ratings.exercise_id WHERE id=:id"; $st = $db->prepare($sql); $st->bindParam(":id", $this->id, PDO::PARAM_INT); $st->execute(); $row = $st->fetch(); if($this->total_rating_votes == null) // this doesn't seem to work even though there is no record in submission_ratings???? { ... }

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  • What are good resources to learn Coldfusion for a job application...

    - by NoMoreZealots
    The job title is "ColdFusion Developer." I have bit's HTML and Javascripting experience, but mostly have worked in the "harder" languages such as C and C++ with occational flurries of assembly. I'm currently employeed, but in the current job climate I figure it can't hurt to be looking around and applying for other positions. Plus according to the friend who sent me the job posting, it is suppose to pay "very well." They left my office to work for this company themself so I figure it's a reasonable evaluation of the company. I don't know if there are any free tools that I could use to get my feet wet and bone up for an interview, or what sort of literature is decent for the ColdFusion. Plus any ideas on how to tune a resume for it would also be helpful.

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  • How do I trigger specific parts of a storyboard in WPF?

    - by George
    I have several grids in my window. I have created a storyboard that moves them left by x pixels when a button is clicked. I want to make it so that when the button is clicked again those grids move another x pixels, however I'm unable to find out how to do this as it's not a common task on tutorials. I have tried creating a second storyboard to do this, however that won't work as then the grids will be back at their starting positions. One solution might be to create a third set of keyframes after the first two sets, and somehow pause the animation when it gets there, and resumes it again when the button is clicked, however I'm not sure how to pause a storyboard when it reaches a keyframe. This would also make reversing the grids difficult (using this approach http://social.msdn.microsoft.com/forums/en-US/wpf/thread/ac54de71-f750-4940-91a2-231810308727/), as I'd like to make another button make the grids go the other way.

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  • Same Activity called twice... Issue with Multiple AsyncTasks?

    - by stormin986
    I have three simultaneous instances of an AsyncTask for download three files. When two particular ones finish, at the end of onPostExecute() I check a flag set by each, and if both are true, I call startActivity() for the next Activity. I am currently seeing the activity called twice, or something that resembles this type of behavior. Since the screen does that 'swipe left' kind of transition to the next activity, it sometimes does it twice (and when I hit back, it goes back to the same activity). It's obvious two versions of the activity that SHOULD only get called once are being put on the Activity stack. Could this be from both onPostExecute()s executing simultaneously and both checking the flags each other set at the exact same time? This seems extremely unlikely since two processes would have to be running line-by-line in parallel... *EDIT* A lot removed from this question since I was way off in what I thought was wrong. Nonetheless I found the answer here quite useful, so I have edited the question to reflect the useful parts.

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  • Connecting ipad to external monitor

    - by Josh P.
    I am trying to connect my ipad app to an external screen using the following (not checking the correct resolution for no - just want it up and running). - (BOOL)application:(UIApplication *)application didFinishLaunchingWithOptions:(NSDictionary *)launchOptions { [window addSubview:[navigationController view]]; if ([[UIScreen screens] count] > 1) { window.screen = [[UIScreen screens] objectAtIndex:1]; } [window makeKeyAndVisible]; return YES; } Is this supposed to redirect everything to the external monitor? How dows it work with touches/gestures? I see in the Apple apps, the controls etc are left on the ipad screen...

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  • How to create real-life robots?

    - by Click Upvote
    Even before I learnt programming I've been fascinated with how robots could work. Now I know how the underlying programming instructions would be written, but what I don't understand is how those intructions are followed by the robot. For example, if I wrote this code: object=Robot.ScanSurroundings(300,400); if (Objects.isEatable(object)) { Robot.moveLeftArm(300,400); Robot.pickObject(object); } How would this program be followed by the CPU in a way that would make the robot do the physical action of looking to the left, moving his arm, and such? Is it done primarily in binary language/ASM? Lastly, where would i go if I wanted to learn how to create a robot?

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  • Javascript height statement

    - by Sean
    This is not working and I can't figure out where I went wrong: <style> * { margin: 0px } div { height: 250px; width: 630px; overflow: hidden; vertical-align: top; position: relative; } iframe { position: absolute; left: -50px; top: -130px; } </style> <script> window.onload = function() { document.getElementsByTagName('body')[0].onkeyup = function(e) { var div = document.getElementById('capture'); if(e.keyCode == 70) { if(div.style.height == 250){ alert("Yes"); } else {alert("no");} } } }; </script>

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  • Problem getting value from "Checkbox group value prompt"

    - by Veer
    Hi, I've value prompt with ui:checkbox group parameter: p_IsLastMonth Name: Prompt_IsLastMonth ItemCount: 1; UseValue:Yes, DisplayValue: LastMonth? and two Date Prompts. Whenever the checkbox is checked, the UseValue 'Yes' is passed to the parameter 'p_IsLastMonth'. But whenever the checkbox is left as it is, it results in an error. Element 'selectOptions' is not valid for content model: 'All(style,defaultSelections,conditionalStyles,conditionalRender,XMLAttributes)' I also tried giving a default value. But the default value has to be in the collection. But i want only one checkbox to be displayed. I tried with html checkbox. But i'm not able to send the value 'either yes or no' to the parameter through javascript because however the finish button overrides the value. Any help?

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  • LINQ count query returns a 1 instead of a 0

    - by user335810
    I have the following view:- CREATE VIEW tbl_adjudicator_result_view AS SELECT a.adjudicator_id, sar.section_adjudicator_role_id, s.section_id, sdr.section_dance_role_id, d.dance_id, c.contact_id, ro.round_id, r.result_id, c.title, c.first_name, c.last_name, d.name, r.value, ro.type FROM tbl_adjudicator a INNER JOIN tbl_section_adjudicator_role sar on sar.section_adjudicator_role2adjudicator = a.adjudicator_id INNER JOIN tbl_section s on sar.section_adjudicator_role2section = s.section_id INNER JOIN tbl_section_dance_role sdr on sdr.section_dance_role2section = s.section_id INNER JOIN tbl_dance d on sdr.section_dance_role2dance = d.dance_id INNER JOIN tbl_contact c on a.adjudicator2contact = c.contact_id INNER JOIN tbl_round ro on ro.round2section = s.section_id LEFT OUTER JOIN tbl_result r on r.result2adjudicator = a.adjudicator_id AND r.result2dance = d.dance_id When I run the following query directly against the db I get 0 in the count column where there is no result select adjudicator_id, first_name, COUNT(result_id) from tbl_adjudicator_result_view arv where arv.round_id = 16 group by adjudicator_id, first_name However when I use LINQ query I always get 1 in the Count Column var query = from arv in db.AdjudicatorResultViews where arv.round_id == id group arv by new { arv.adjudicator_id, arv.first_name} into grp select new AdjudicatorResultViewGroupedByDance { AdjudicatorId = grp.Key.adjudicator_id, FirstName = grp.Key.first_name, Count = grp.Select(p => p.result_id).Distinct().Count() }; What do I need to change in the View / Linq query.

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  • Weird Jquery/CSS Menu Issue

    - by Kevin Z
    Hey All, I have a jquery drop down menu with jquery and css to style it. However, every time you hover over the menu options and go back and forth, it seems to leave pieces of the menu left over. Any ideas where this is coming from and how to get rid of it? Here is the code in a jsfiddle: http://jsfiddle.net/2msuP/2/ See the page and how it works here: http://f4design.com/clients/bigiochame/index.html I am noticing it in Safari. It may not be apparent in all browsers. However, the main user for this site will be Safari users. Any help is appreciated! Thanks! Kevin

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  • Poor Transparency on Images

    - by KyleStew
    I am having problems getting transparency to work well on an ImageView. The images at (http://img265.imageshack.us/img265/6233/whatn.png) were screen captured from a Droid (hdpi). The top image I made in Photoshop and left the background white. The bottom image is the same image with the background transparent and the layout's color (white) shows through. Whenever I have transparent backgrounds in images it dithers shadows like this. Also, it only happens on hdpi devices, on my G1 (mdpi) it looks just fine. What is going on? How can I make the bottom image look as good as the top one?

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  • Perl Tk closing windows

    - by guy ergas
    in my perl tk script i have opened 2 windows and after a spacific button click i want to close one of them. how can i do it? code example: main: $main = new MainWindow; $sidebar = $main-Frame(-relief = "raised", -borderwidth = 2) -pack (-side="left" , -anchor = "nw", -fill = "y"); $Button1 = $sidebar - Button (-text="Open\nNetlist", -command= \&GUI_OPEN_NETLIST) -pack(-fill="x"); MainLoop; sub GUI_OPEN_NETLIST { $component_dialog = new MainWindow; $Button = $component_dialog - Button (-text="Open\nNetlist", -command= close new window) -pack(-fill="x"); MainLoop; }

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  • Height of a binary tree

    - by Programmer
    Consider the following code: public int heightOfBinaryTree(Node node) { if (node == null) { return 0; } else { return 1 + Math.max(heightOfBinaryTree(node.left), heightOfBinaryTree(node.right)); } } I want to know the logical reasoning behind this code. How did people come up with it? Does some have an inductive proof? Moreover, I thought of just doing a BFS with the root of the binary tree as the argument to get the height of the binary tree. Is the previous approach better than mine?Why?

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  • Rectangle Rotation in Python/Pygame

    - by mramazingguy
    Hey I'm trying to rotate a rectangle around its center and when I try to rotate the rectangle, it moves up and to the left at the same time. Does anyone have any ideas on how to fix this? def rotatePoint(self, angle, point, origin): sinT = sin(radians(angle)) cosT = cos(radians(angle)) return (origin[0] + (cosT * (point[0] - origin[0]) - sinT * (point[1] - origin[1])), origin[1] + (sinT * (point[0] - origin[0]) + cosT * (point[1] - origin[1]))) def rotateRect(self, degrees): center = (self.collideRect.centerx, self.collideRect.centery) self.collideRect.topleft = self.rotatePoint(degrees, self.collideRect.topleft, center) self.collideRect.topright = self.rotatePoint(degrees, self.collideRect.topright, center) self.collideRect.bottomleft = self.rotatePoint(degrees, self.collideRect.bottomleft, center) self.collideRect.bottomright = self.rotatePoint(degrees, self.collideRect.bottomright, center)

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  • Online Advetisement/Banner Management System

    - by Sumesh Joshi
    I am developing site for online advertisements where sellers and buyers can come and sell/buy advertisements. Just need to develop detailed statistics like click counts, from which page clicks are coming (one advertisement can be placed on many pages), from which position (top, right, left ...) click are coming (one advertisement can be placed in different position on single page) etc. I seen that most of the advertisement on popular websites has following format: http://ads.stackoverflow.com/a.aspx?Task=Click&ZoneID=3&CampaignID=838&AdvertiserID=50&BannerID=1335&SiteID=1&RandomNumber=1463177307&Keywords=c%23%2c.net%2ccollections%2cdictionary%2chashtable It has many parameters like ZoneID, CampaignID, AdvertiserID, BannerID, SiteID, RandomNumber, adid, adcrid, obid, obtid and way. I can use one advertisement (adid) in multiple pages. But can't figure out the way to distinguish between from which pages clicks are coming. How can I use such parameters to generate statistics which tell me the page from which clicks are coming?

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  • How to vertically align images in <td>

    - by Ricky
    I got a <td> where two images () reside shown as follows. One is much higher than the other. How do I let the shorter one align to the top of <td />? <td style="padding-left: 0px; cursor: pointer; vertical-align: top;"> <img width="85px" src=".../xyz.png"/> <img src=".../icon_live.gif" /> // shorter one </td>

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