Search Results

Search found 1071 results on 43 pages for 'jpeg'.

Page 35/43 | < Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >

  • PHP JQuery: Where to specify uploadify destination folder

    - by Eamonn
    I have an uploadify script running, basic setup. Works fine when I hard code the destination folder for the images into uploadify.php - now I want to make that folder dynamic. How do I do this? I have a PHP variable $uploadify_path which contains the path to the folder I want. I have switched out my hard coded $targetPath = path/to/directory for $targetPath = $uploadify_path in both uploadify.php and check_exists.php, but it does not work. The file upload animation runs, says it is complete, yet the directory remains empty. The file is not hiding out somewhere else either. I see there is an option in the Javascript to specify a folder. I tried this also, but to no avail. If anyone could educate me on how to pass this variable destination to uploadify, I'd be very grateful. I include my current code for checking (basically default): The Javascript <script type="text/javascript"> $(function() { $('#file_upload').uploadify({ 'swf' : 'uploadify/uploadify.swf', 'uploader' : 'uploadify/uploadify.php', // Put your options here }); }); </script> uploadify.php $targetPath = $_SERVER['DOCUMENT_ROOT'] . $uploadify_path; // Relative to the root if (!empty($_FILES)) { $tempFile = $_FILES['Filedata']['tmp_name']; $targetFile = $targetPath . $_FILES['Filedata']['name']; // Validate the file type $fileTypes = array('jpg','jpeg','gif','png'); // File extensions $fileParts = pathinfo($_FILES['Filedata']['name']); if (in_array($fileParts['extension'],$fileTypes)) { move_uploaded_file($tempFile,$targetFile); echo '1'; } else { echo 'Invalid file type.'; } }

    Read the article

  • How can I overlay images over one another in Java?

    - by Sam
    So I have been posting all over and have yet to get a solid answer: I have created an image resizing class, with a crop method. The cropping works great. The issue that I am having is the background color that I specify in the drawImage function of Graphics is not working correctly. It defaults to black as the background regardless of what I supply (in this case Color.WHITE). Also, the overlaying image or top most image (comes from a file) is being inverted (I think it is) or otherwise discolored. Just so you can conceptualize this a little bit better, I am taking a jpeg and overlaying it on top of a new BufferedImage, the new buffered image's background is not being set. Here is the code below that I am working with: public void Crop(int Height, int Width, int SourceX, int SourceY) throws Exception { //output height and width int OutputWidth = this.OutputImage.getWidth(); int OutputHeight = this.OutputImage.getHeight(); //create output streams ByteArrayOutputStream MyByteArrayOutputStream = new ByteArrayOutputStream(); MemoryCacheImageOutputStream MyMemoryCacheImageOutputStream = new MemoryCacheImageOutputStream(MyByteArrayOutputStream); //Create a new BufferedImage BufferedImage NewImage = new BufferedImage(Width, Height, BufferedImage.TYPE_INT_RGB); Graphics MyGraphics = NewImage.createGraphics(); MyGraphics.drawImage(this.OutputImage, -SourceX, -SourceY, OutputWidth, OutputHeight, Color.WHITE, null); // Get Writer and set compression Iterator MyIterator = ImageIO.getImageWritersByFormatName("png"); if (MyIterator.hasNext()) { //get image writer ImageWriter MyImageWriter = (ImageWriter)MyIterator.next(); //get params ImageWriteParam MyImageWriteParam = MyImageWriter.getDefaultWriteParam(); //set outputstream MyImageWriter.setOutput(MyMemoryCacheImageOutputStream); //create new ioimage IIOImage MyIIOImage = new IIOImage(NewImage, null, null); //write new image MyImageWriter.write(null, MyIIOImage, MyImageWriteParam); } //convert output stream back to inputstream ByteArrayInputStream MyByteArrayInputStream = new ByteArrayInputStream(MyByteArrayOutputStream.toByteArray()); MemoryCacheImageInputStream MyMemoryCacheImageInputStream = new MemoryCacheImageInputStream(MyByteArrayInputStream); //resassign as a buffered image this.OutputImage = ImageIO.read(MyMemoryCacheImageInputStream); }

    Read the article

  • how to release object from thid party dll?

    - by Mohamed
    hi all, i'm developing a program to convert RTF to html i'm using the DLLs found here http://www.codeproject.com/KB/recipes/RtfConverter.aspx?fid=1458864&df=90&mpp=25&noise=3&sort=Position&view=Quick&select=3427424&fr=1#xx0xx this dll saves a jpg file from html to a specific folder, when i run the program, it cinverts the rtf for the first time and saves the images to the folder perfectly but when i try to convert it again i hace this error "error a generic error occured in GDI+" i think this dll use SaveImage method and to avoid this you must release the Image object you created but i can't modify the DLL, is there is any way to release the object i've created from this dll? this is my code RtfVisualImageAdapter imageAdapter = new RtfVisualImageAdapter( @Application.StartupPath + "\\Program Data\\temp\\{0}{1}", System.Drawing.Imaging.ImageFormat.Jpeg); RtfImageConvertSettings imageConvertSettings = new RtfImageConvertSettings(imageAdapter); RtfImageConverter imageConverter = new RtfImageConverter(imageConvertSettings); try { IRtfDocument rtfDocument = RtfInterpreterTool.BuildDoc( ConversionText, imageConverter); RtfHtmlConverter htmlConverter = new RtfHtmlConverter(rtfDocument); htmlConverter.Settings.ConvertVisualHyperlinks = true; htmlConverter.Settings.UseNonBreakingSpaces = true; this.richTextBoxPrintCtrl2.Text = htmlConverter.Convert(); } catch (Exception exception) { MessageBox.Show(this, "Error " + exception.Message, this.Text, MessageBoxButtons.OK, MessageBoxIcon.Error); }

    Read the article

  • Jquery: how to call the function again?

    - by bakazero
    I'm making the script for easy upload many files. I've tried fyneworks plugin, but the file name does not appear in a form that uses tiny_mce. This is the code: $("document").ready(function () { var i = 0; //iteration for Inputted File var max = 5; //max file uploaded createStatus(); //generate status container $('.imageNow').change(function() { if($(this).val()) { var ext = $(this).val().split('.').pop().toLowerCase(); var allow = [ 'gif', 'png', 'jpg', 'jpeg' ]; if (jQuery.inArray(ext, allow) != -1) { //validation true addImgInput($(this).clone()); $(this).addClass('imgOK'); $(this).removeClass('imageNow'); addImgList($(this).val()); removeImgStatus(); i++; } else { addImgStatus(); $(this).remove(); addImgInput(); } } return false; }); }); This is another function that I use: function addImgInput(inputClone) { $(inputClone).prependTo( $('#upload_images') ); //div container for generated InputFileImg }; function addImgList(listingImg) { $('#list_image_file').append('<li>' + listingImg + '</li>' ); //list all images that have been inputted } function createStatus() { $('#upload_images').append('<small class="status"></small>'); //error display container } function addImgStatus() { $('.status').append('* Wrong File Extension'); //error display text } function removeImgStatus() { $('.status').empty(); } Mmm..yeah is't not finished yet, because when I try to generate another Inputfile with imageNow class, the $('.imageNow').change(function() is not going to work anymore. Does anyone can help me? Thanks

    Read the article

  • Image insert problem php sqlserver

    - by Termedi
    Hi I can not save image inside a sql server 2000 database. datatype is image here is the code: // Image Upload <?php include('config.php'); if(is_uploaded_file($_FILES['userfile']['tmp_name'])) { $fileName = $_FILES['userfile']['name']; $tmpName = $_FILES['userfile']['tmp_name']; $fileSize = $_FILES['userfile']['size']; $fileType = $_FILES['userfile']['type']; $size = filesize($tmpName); set_magic_quotes_runtime(0);//to desactive the default escape spacials caracters made by PHP in the externes files $img_binaire = base64_encode(fread(fopen(str_replace("'","''",$tmpName), "r"), $size)); $query = "INSERT INTO test_image (image_name, image_content, image_size) ". "VALUES ('{$fileName}','{$img_binaire}', '{$size}')"; odbc_exec($conn, $query) or die('Error, query failed'); echo "<br>File $fileName uploaded<br>"; echo "<br>File Size: $fileSize <br>"; } ?> // Image Show <?php include('config.php'); $sql = "select * from test_image where id =2"; $rsl = odbc_exec($conn, $sql); $image_info = odbc_fetch_array($rsl); //$count = sizeof($image_info['image_content']); //header('Accept-Ranges: bytes'); //header('Content-Length: '.$image_info['image_size']); //header("Content-length: 17397"); header('Content-Type: image/jpeg'); echo base64_decode($image_info['image_content']); //echo bindec($image_info['image_content']); ?> Error: Warning: odbc_exec() [function.odbc-exec]: SQL error: [Microsoft][ODBC SQL Server Driver][SQL Server]Operand type clash: text is incompatible with image, SQL state 22005 in SQLExecDirect in C:\xampp\htdocs\test\upload.php on line 25 Error, query failed

    Read the article

  • How to only fade content once it is ready in Jquery?

    - by Jared
    Hello, I've seen examples for load() and ready(), but they always seem to apply to the window or document body, or a div or img or something like that. I have a hover() function, and when you hover over it, it uses fadeIn() to reveal it. Problem is, the images inside the div aren't loaded yet, so it ends up just appearing anyway. I need code that will only allow the image to fade when it's contents are fully loaded. When I just plug in other selectors like the following, it doesn't work $(this).next(".menuPopup").ready(function () { //or load(), neither work fadeTo(300, 1); }); EDIT: Relevant code $( '.leftMenuProductButton' ).hover ( function () { $(this).next(".menuPopup").stop().css("opacity", 1).fadeIn('slow'); }, function () { $(this).next(".menuPopup").stop().hide(); }); HTML <div class="leftMenuProductButton"> Product 1</div> <div id="raceramps56" class="menuPopup"><IMG SRC="myimage.jpeg"> </div>

    Read the article

  • jQuery ajax post of jpg image to .net webservice. Image results corrupted

    - by sosergio
    I have a phonegap jquery app that opens the camera and take a picture. I then POST this picture to a .net webservice, wich I've coded. I can't use phonegap FileTransfer because such isn't supported by Bada os, wich is a requirement. I believe I've successfully loaded the image from phonegap FileSystem API, I've attached it into an .ajax type:post, I've even received it from .net side, but when .net save the image into the server, the image results corrupted. It seems to me that two sides of the communication have different data type. Has anyone experience in this? Any help will be appreciated. This is my code: //PHONEGAP CAMERA ACCESS (summed up) navigator.camera.getPicture(onGetPictureSuccess, onGetPictureFail, { quality: 50, destinationType:Camera.DestinationType.FILE_URI }); window.resolveLocalFileSystemURI(imageURI, onResolveFileSystemURISuccess, onResolveFileSystemURIError); fileEntry.file(gotFileSuccess, gotFileError); new FileReader().readAsDataURL(file); //UPLOAD FILE function onDataReadSuccess(evt) { var image_data = evt.target.result; var filename = unique_id(); var filext = "jpg"; $.ajax({ type : 'POST', url : SERVICE_BASE_URL+"/fotos/"+filename+"?ext="+filext, cache: false, timeout: 100000, processData: false, data: image_data, contentType: 'image/jpeg', success : function(data) { console.log("Data Uploaded with success. Message: "+ data); $.mobile.hidePageLoadingMsg(); $.mobile.changePage("ok.html"); } }); } On my .net Web Service this is the method that gets invoked: public string FotoSave(string filename, string extension, Stream fileContent) { string filePath = HttpContext.Current.Server.MapPath("~/foto_data/") + "\\" + filename; FileStream writeStream = new FileStream(filePath, FileMode.OpenOrCreate, FileAccess.Write); int Length = 256; Byte[] buffer = new Byte[Length]; int bytesRead = readStream.Read(buffer, 0, Length); // write the required bytes while (bytesRead > 0) { writeStream.Write(buffer, 0, bytesRead); bytesRead = readStream.Read(buffer, 0, Length); } readStream.Close(); writeStream.Close(); }

    Read the article

  • Rack, FastCGI, Lighttpd configuration

    - by zacsek
    Hi! I want to run a simple application using Rack, FastCGI and Lighttpd, but I cannot get it working. I get the following error: /usr/lib/ruby/1.8/rack/handler/fastcgi.rb:23:in `initialize': Address already in use - bind(2) (Errno::EADDRINUSE) from /usr/lib/ruby/1.8/rack/handler/fastcgi.rb:23:in `new' from /usr/lib/ruby/1.8/rack/handler/fastcgi.rb:23:in `run' from /www/test.rb:7 Here is the application: #!/usr/bin/ruby app = Proc.new do |env| [200, {'Content-Type' => 'text/plain'}, "Hello World!"] end require 'rack' Rack::Handler::FastCGI.run app, :Port => 4000 ... and the lighttpd.conf: server.modules += ( "mod_access", "mod_accesslog", "mod_fastcgi" ) server.port = 80 server.document-root = "/www" mimetype.assign = ( ".html" => "text/html", ".txt" => "text/plain", ".jpg" => "image/jpeg", ".png" => "image/png" ) index-file.names = ( "test.rb" ) fastcgi.debug = 1 fastcgi.server = ( ".rb" => (( "host" => "127.0.0.1", "port" => 4000, "bin-path" => "/www/test.rb", "check-local" => "disable", "max-procs" => 1 )) ) Can someone help me? What am I doing wrong?

    Read the article

  • curl post picture multipart/form-data, php cURL need help!

    - by user331071
    I'm trying to upload a picture to a specific website using php cURL but I don't really understand what parameters do I need to send because the data looks a bit weird . Here is what i got with the http analyzer Type : multipart/form-data; boundary=---------------------------182983931283 -----------------------------182983931283 Content-Disposition: form-data; name="file"; filename="Blue hills.jpg" Content-Type: image/jpeg Here appears the souce of the image itself like "ÿØÿàÿØÿàÿØÿàÿØÿàÿØÿàÿØÿà" -----------------------------182983931283 Content-Disposition: form-data; name="action" images -----------------------------182983931283 Content-Disposition: form-data; name="anonymous_email" Y -----------------------------182983931283 Content-Disposition: form-data; name="site_id" 1 -----------------------------182983931283 and so on other parameters. The issue that I have is that I don't understand what is the boundary, where do I get it from (because it doesn't appear in the html document that generates the POST and how should I make the post . If you would give me a simple example to post the above parameters to http://example.com I will definitely get the trick . Currently I'm using the following function to make the post : function processPicturesPage($title, $price, $numbedrooms, $description) { //Set the login parameters and initiate the Login process $fields = array( "changedImages" = "", "site_id" = "1", "posting_id" = "", "current_live_date" = "", "images_loaded" = "", "image_actions" = "", "title" = $title, ); foreach($fields as $key=$value) { $fields_string .= $key.'='.$value.'&'; } rtrim($fields_string,'&'); $URL = "http://www.example.com/cgi-bin/add_posting.pl"; return $this-processCurlrequest($URL, count($fields), $fields_string); } and in the processCurlrequest I have the curl options (cookies etc) and url .

    Read the article

  • MinGW-gcc PCH not speeding up wxWidget build times. Is my setup correct?

    - by Victor T.
    Hi all, I've been building wxMSW 2.8.11 with the latest stable release of mingw-gcc 4.5.1 and I'm trying to see if the build could be sped up using precompiled headers. My initial attempts at this doesn't seem to work. I basically followed the given instructions here. I created a wxprec.h precompiled header with the following: g++ -O2 -mthreads -DHAVE_W32API_H -D__WXMSW__ -DNDEBUG -D_UNICODE -I..\..\lib\gcc_dll\mswu -I..\..\include -W -Wall -DWXBUILDING -I..\.. \src\tiff -I..\..\src\jpeg -I..\..\src\png -I..\..\src\zlib -I..\..\src \regex -I..\..\src\expat\lib -DwxUSE_BASE=1 -DWXMAKINGDLL -Wno-ctor- dtor-privacy ../../include/wx/wxprec.h That does successfully create a wxprec.h.gch that's about ~1.6meg in size. Now I proceed to build wxmsw using the follow make command from cmd.exe shell: mingw32-make -f makefile.gcc While, the build does succeed I noticed no speedup whatsoever then if pch wasn't used. To make sure gcc was actually using the pch I added -H in the config.gcc and did another rebuild. Indeed, the outputted include list does show a '!' next to the wxprec.h so gcc is supposely using it. What's the reason for pch not working? Did I setup the precompiled headers correctly or am I missing a step? Just for reference comparison, here's the compile times I get when building wxmsw 2.8.11 with the other compilers(visual studio 2010 and C++ Builder 2007). The time savings is pretty significant. | | release, pch | release, nopch | debug, nopch ------------------------------------------------------- | gcc451 | 8min 33sec | 8min 17sec | 8min 49sec | msc_1600 | 2min 23sec | 13min 11sec | -- | bcc593 | 0min 59sec | 2min 29sec | -- Thanks

    Read the article

  • ASP.NET MVC: Can't figure out what VirtualPath is?

    - by Ryan_Pitts
    I have a View that displays a list of images and i am now trying to get it to display the images as thumbnails. Well, i'm pretty sure i got most of it right using VirtualPath's from a custom ActionResult although i can't seem to figure out what it is making the VirtualPath url?? BTW, i'm using XML to store the data from the images instead of SQL. Here is my code: Code from my custom ActionResult: public class ThumbnailResult : ActionResult { public ThumbnailResult(string virtualPath) { this.VirtualPath = virtualPath; } public string VirtualPath { get; set; } public override void ExecuteResult(ControllerContext context) { context.HttpContext.Response.ContentType = "image/bmp"; string fullFileName = context.HttpContext.Server.MapPath("~/Galleries/WhereConfusionMeetsConcrete/" + VirtualPath); using (System.Drawing.Image photoImg = System.Drawing.Image.FromFile(fullFileName)) { using (System.Drawing.Image thumbPhoto = photoImg.GetThumbnailImage(100, 100, null, new System.IntPtr())) { using (System.IO.MemoryStream ms = new System.IO.MemoryStream()) { thumbPhoto.Save(ms, System.Drawing.Imaging.ImageFormat.Jpeg); context.HttpContext.Response.BinaryWrite(ms.ToArray()); context.HttpContext.Response.End(); } } } } } Code for my Controller: public ActionResult Thumbnail(string id) { return new ThumbnailResult(id); } Code for my View: <% foreach (var image in ViewData.Model) { %> <a href="../Galleries/TestGallery1/<%= image.Path %>"><img src="../Galleries/TestGallery1/thumbnail/<%= image.Path %>" alt="<%= image.Caption %>" /></a> <br /><br /><%= image.Caption %><br /><br /><br /> <% } %> Any help would be greatly appreciated!! Let me know of any questions you have as well. :) Thanks!

    Read the article

  • What good open source programs exist for fuzzing popular image file types?

    - by JohnnySoftware
    I am looking for a free, open source, portable fuzzing tool for popular image file types that is written in either Java, Python, or Jython. Ideally, it would accept specifications for the fuzzable fields using some kind of declarative constraints. Non-procedural grammar for specifying constraints are greatly preferred. Otherwise, might as well write them all in Python or whatever. Just specifying ranges of valid values or expressions for them. Ideally, it would support some kind of generative programming to export the fuzzer into various programming languages to suit cases where more customization was required. If it supported a direct-manipulation GUI for controlling parameter values and ranges, that would be nice too. The file formats that should be supported are: GIF JPEG PNG So basically, it should be sort of a toolkit consisting of ready-to-run utility, a framework or library, and be capable of generating the fuzzed files directly as well as from programs it generates. It needs to be simple so that test images can be created quickly. It should have a batch capability for creating a series of images. Creating just one at a time would be too painful. I do not want a hacking tool, just a QA tool. Basically, I just want to address concerns that it is taking too long to get commonplace image rendering/parsing libraries stable and trustworthy.

    Read the article

  • Android: Resolution issue while saving image into gallery

    - by Luca D'Amico
    I've managed to programmatically take a photo from the camera, then display it on an imageview, and then after pressing a button, saving it on the Gallery. It works, but the problem is that the saved photo are low resolution.. WHY?! I took the photo with this code: Intent cameraIntent = new Intent(android.provider.MediaStore.ACTION_IMAGE_CAPTURE); startActivityForResult(cameraIntent, CAMERA_PIC_REQUEST); Then I save the photo on a var using : protected void onActivityResult(int requestCode, int resultCode, Intent data) { if (requestCode == CAMERA_PIC_REQUEST) { thumbnail = (Bitmap) data.getExtras().get("data"); } } and then after displaying it on an imageview, I save it on the gallery with this function: public void SavePicToGallery(Bitmap picToSave, File savePath){ String JPEG_FILE_PREFIX= "PIC"; String JPEG_FILE_SUFFIX= ".JPG"; String timeStamp = new SimpleDateFormat("yyyyMMdd_HHmmss").format(new Date()); String imageFileName = JPEG_FILE_PREFIX + timeStamp + "_"; File filePath = null; try { filePath = File.createTempFile(imageFileName, JPEG_FILE_SUFFIX, savePath); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } FileOutputStream out = null; try { out = new FileOutputStream(filePath); } catch (FileNotFoundException e) { // TODO Auto-generated catch block e.printStackTrace(); } picToSave.compress(CompressFormat.JPEG, 100, out); try { out.flush(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } try { out.close(); } catch (IOException e) { // TODO Auto-generated catch block e.printStackTrace(); } //Add the pic to Android Gallery String mCurrentPhotoPath = filePath.getAbsolutePath(); MediaScannerConnection.scanFile(this, new String[] { mCurrentPhotoPath }, null, new MediaScannerConnection.OnScanCompletedListener() { public void onScanCompleted(String path, Uri uri) { } }); } I really can't figure out why it lose so much quality while saved.. Any help please ? Thanks..

    Read the article

  • Resize an image and maintain quality?

    - by JasonS
    Hi, I have a problem with resizing images. What happens is that if you upload a file larger than the stated parameters, the image is cropped, then saved at 100% quality. So if I upload a large jpeg which is 272Kb. The image is cropped by 100 odd pixels. The file size then goes up to 1.2Mb. We are saving images at a 100% quality. I assume that this is what is causing the problem. The image is exported from Photoshop at 30% quality which reduces the file size. Resaving the image at 100% quality creates the same image but I assume with a lot of redundant file data. Has anyone encountered this before? Does anyone have a solution? This is what we are using. $source_im = imagecreatefromjpeg ($file); $dest_im = imagecreatetruecolor ($newsize_x, $newsize_y); imagecopyresampled ( $dest_im, $source_im, 0, 0, $offset_x, $offset_y, $newsize_x, $newsize_y, $sourceWidth, $sourceHeight ); imagedestroy ($source_im); if ($greyscale) { $dest_im = $this->imageconvertgreyscale ($dest_im); } imagejpeg($dest_im, $save_to_file, $quality); break;

    Read the article

  • Objective C code to handle large amount of data processing in iPhone

    - by user167662
    I had the following code that takes in 14 mb or more of image data encoded in base4 string and converts them to jpeg before writing to a file in iphone. It crashes my program giving the following error : Program received signal: “0”. warning: check_safe_call: could not restore current frame I tweak my program and it can process a few more images before the error appear again. My coding is as follows: // parameters is an array where the fourth element contains a list of images in base64 >encoded string NSMutableArray *imageStrList = (NSMutableArray*) [parameters objectAtIndex:5]; while (imageStrList.count != 0) { NSString *imgString = [imageStrList objectAtIndex:0]; // Create a file name using my own Utility class NSString *fileName = [Utility generateFileNName]; NSData *restoredImg = [NSData decodeWebSafeBase64ForString:imgString]; UIImage *img = [UIImage imageWithData: restoredImg]; NSData *imgJPEG = UIImageJPEGRepresentation(img, 0.4f); [imgJPEG writeToFile:fileName atomically:YES]; [imageStrList removeObjectAtIndex:0]; } I tried playing around with UIImageJPEGRepresentation and found out that the lower the value, the more image it can processed but this should not be the way. I am wondering if there is anyway to free up memory of the imageStrList immediately after processing each image so that it can be used by the next one in the line.

    Read the article

  • I need to sort php jquery gallery script alphabetically

    - by David Cahill
    know nothing about php, but I have this script that reads a folder and displays a thumbnail gallery, problem is it dosent display alphabetically. Have searched the net and seen that sort does this but have no idea where to start any help would be much appreciated. heres the script $sitename = $row_wigsites['id']; $directory = 'sites/'.$sitename.'/pans'; $allowed_types=array('jpg','jpeg','gif','png'); $file_parts=array(); $ext=''; $title=''; $i=0; $dir_handle = @opendir($directory) or die("There is an error with your image directory!"); while ($file = readdir($dir_handle)) { if($file=='.' || $file == '..') continue; $file_parts = explode('.',$file); $ext = strtolower(array_pop($file_parts)); $title = implode('.',$file_parts); $title = htmlspecialchars($title); $nomargin=''; if(in_array($ext,$allowed_types)) { if(($i+1)%4==0) $nomargin='nomargin'; echo ' <div class="pic '.$nomargin.'" style="background:url('.$directory.'/'.$file.') no-repeat 50% 50%;"> <a href="'.$directory.'/'.$file.'" title="Panoramic Stills taken at '.$title.'°" rel="pan1" target="_blank">'.$title.'</a> </div>'; $i++; } } closedir($dir_handle);

    Read the article

  • How to fix Java Image Fetcher error ?

    - by Frank
    My code looks like this : private static JFileChooser fc; if (fc==null) { fc=new JFileChooser(Image_Dir); fc.addChoosableFileFilter(new Image_Filter()); // Add a custom file filter and disable the default (Accept All) file filter. fc.setAcceptAllFileFilterUsed(false); fc.setAccessory(new Image_Preview(fc)); // Add the preview pane. } int returnVal=fc.showDialog(JFileChooser_For_Image.this,"Get Image"); // Show it. After I select an image from the panel, I got the following error message : Exception in thread "Image Fetcher 0" java.lang.UnsatisfiedLinkError: Native Library C:\Program Files (x86)\Java\jre6\bin\jpeg.dll already loaded in another classloader at java.lang.ClassLoader.loadLibrary0(Unknown Source) at java.lang.ClassLoader.loadLibrary(Unknown Source) at java.lang.Runtime.loadLibrary0(Unknown Source) at java.lang.System.loadLibrary(Unknown Source) at sun.security.action.LoadLibraryAction.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at sun.awt.image.JPEGImageDecoder.<clinit>(Unknown Source) at sun.awt.image.InputStreamImageSource.getDecoder(Unknown Source) at sun.awt.image.FileImageSource.getDecoder(Unknown Source) at sun.awt.image.InputStreamImageSource.doFetch(Unknown Source) at sun.awt.image.ImageFetcher.fetchloop(Unknown Source) at sun.awt.image.ImageFetcher.run(Unknown Source) When I run it from an executable Jar file, it works fine, but after I wrapped it into an exe file, I got the above error, why ? How to fix it ?

    Read the article

  • SQL query error while trying to put a file in the database

    - by DaGhostman Dimitrov
    Hey Guys I have a big problem that I have no Idea why.. I have few forms that upload files to the database, all of them work fine except one.. I use the same query in all(simple insert). I think that it has something to do with the files i am trying to upload but I am not sure. Here is the code: if ($_POST['action'] == 'hndlDocs') { $ref = $_POST['reference']; // Numeric value of $doc = file_get_contents($_FILES['doc']['tmp_name']); $link = mysqli_connect('localhost','XXXXX','XXXXX','documents'); mysqli_query($link,"SET autocommit = 0"); $query = "INSERT INTO documents ({$ref}, '{$doc}', '{$_FILES['doc']['type']}') ;"; mysqli_query($link,$query); if (mysqli_error($link)) { var_dump(mysqli_error($link)); mysqli_rollback($link); } else { print("<script> window.history.back(); </script>"); mysqli_commit($link); } } The database has only these fields: DATABASE documents ( reference INT(5) NOT NULL, //it is unsigned zerofill doc LONGBLOB NOT NULL, //this should contain the binary data mime_type TEXT NOT NULL // the mime type of the file php allows only application/pdf and image/jpeg ); And the error I get is : You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '00001, '????' at line 1 I will appreciate every help. Cheers!

    Read the article

  • PHP elseif statement not executed even though initial if statement is false

    - by DarwinIcesurfer
    I am writing a recursive function to print out the differences between 2 multildimensional php arrays. The purpose of this code is to see the difference between jpeg headers to deteremine how adobe bridge cs3 is saving rating information within the jpg file. When I am single-stepping through the code using my eclipse - zend debugger ide, it appears that even though the initial if statement is false (ie both values are arrays), the subsequent elseif statements are never executed. The function is attached below. function array_diff_multi($array1,$array2,$level){ $keys = array_keys($array1); foreach($keys as $key) { $value1 = $array1[$key]; if(array_key_exists($key,$array2) ){ $value2 = $array2[$key]; // Check if they are both arrays, if so recursion is needed if (is_array($value1) && is_array($value2)){ array_diff_multi($value1,$value2,$level . "[ " . $key . " ]"); } // the values aren't both arrays *** THE CODE IN THE ELSEIF BELOW IS NOT EXECUTED *** elseif(is_array($value1) != is_array($value2)){ print "" . $level . $key ."=" . $value1 . "as array, compared to ". $value2 .""; } // the values don't match elseif($value1 != $value2){ print "" . $level . $key ."=" . $value1 ." != " . $value2 .""; } else; } else{ print "" . $level. $key . "does not exist in array2"; } } }

    Read the article

  • How to test if a user has SELECTED a file to upload ?

    - by Tristan
    Hello, on a page, i have : if (!empty($_FILES['logo']['name'])) { $dossier = 'upload/'; $fichier = basename($_FILES['logo']['name']); $taille_maxi = 100000; $taille = filesize($_FILES['logo']['tmp_name']); $extensions = array('.png', '.jpg', '.jpeg'); $extension = strrchr($_FILES['logo']['name'], '.'); if(!in_array($extension, $extensions)) { $erreur = 'ERROR you must upload the right type'; } if($taille>$taille_maxi) { $erreur = 'too heavy'; } if(!empty($erreur)) { ....................... } The problem is, if the users wants to edit information WITHOUT uploading a LOGO, it raises an error : 'error you must upload the right type' So, if a user didn't put anything in the inputbox in order to upload it, i don't want to enter in these conditions test. i tested : if (!empty($_FILES['logo']['name']) and if (isset($_FILES['logo']['name']) but both doesn't seems to work. Any ideas? edit : maybe i wasn't so clear, i don't want to test if he uploaded a logo, i want to test IF he selected a file to upload, because right now, if he doesn't select a file to upload, php raises an error telling he must upload with the right format. thanks.

    Read the article

  • PHP Outputting File Attachments with Headers

    - by OneNerd
    After reading a few posts here I formulated this function which is sort of a mishmash of a bunch of others: function outputFile( $filePath, $fileName, $mimeType = '' ) { // Setup $mimeTypes = array( 'pdf' => 'application/pdf', 'txt' => 'text/plain', 'html' => 'text/html', 'exe' => 'application/octet-stream', 'zip' => 'application/zip', 'doc' => 'application/msword', 'xls' => 'application/vnd.ms-excel', 'ppt' => 'application/vnd.ms-powerpoint', 'gif' => 'image/gif', 'png' => 'image/png', 'jpeg' => 'image/jpg', 'jpg' => 'image/jpg', 'php' => 'text/plain' ); // Send Headers //-- next line fixed as per suggestion -- header('Content-Type: ' . $mimeTypes[$mimeType]); header('Content-Disposition: attachment; filename="' . $fileName . '"'); header('Content-Transfer-Encoding: binary'); header('Accept-Ranges: bytes'); header('Cache-Control: private'); header('Pragma: private'); header('Expires: Mon, 26 Jul 1997 05:00:00 GMT'); readfile($filePath); } I have a php page (file.php) which does something like this (lots of other code stripped out): // I run this thru a safe function not shown here $safe_filename = $_GET['filename']; outputFile ( "/the/file/path/{$safe_filename}", $safe_filename, substr($safe_filename, -3) ); Seems like it should work, and it almost does, but I am having the following issues: When its a text file, I am getting a strange symbol as the first letter in the text document When its a word doc, it is corrupt (presumably that same first bit or byte throwing things off). I presume all other file types will be corrupt - have not even tried them Any ideas on what I am doing wrong? Thanks - UPDATE: changed line of code as suggested - still same issue.

    Read the article

  • Save Bitmap image in a location in C#

    - by acadia
    Hello, I have this function to store the bmp image in a desired location as shown below My question is, how do I save the image in C:\temp folder by default, instead of opening the filedialog box? I want to specify sd.fileName=picname+".bmp" and store it in c:\temp by default. I tried to specify Thanks for your help in advance. I tried to public static bool SaveDIBAs( string picname, IntPtr bminfo, IntPtr pixdat ) { SaveFileDialog sd = new SaveFileDialog(); sd.FileName = picname; sd.Title = "Save bitmap as..."; sd.Filter = "Bitmap file (*.bmp)|*.bmp|TIFF file (*.tif)|*.tif|JPEG file (*.jpg)|*.jpg|PNG file (*.png)|*.png|GIF file (*.gif)|*.gif|All files (*.*)|*.*"; sd.FilterIndex = 1; if( sd.ShowDialog() != DialogResult.OK ) return false; Guid clsid; if( ! GetCodecClsid( sd.FileName, out clsid ) ) { MessageBox.Show( "Unknown picture format for extension " + Path.GetExtension( sd.FileName ), "Image Codec", MessageBoxButtons.OK, MessageBoxIcon.Information ); return false; } IntPtr img = IntPtr.Zero; int st = GdipCreateBitmapFromGdiDib( bminfo, pixdat, ref img ); if( (st != 0) || (img == IntPtr.Zero) ) return false; st = GdipSaveImageToFile( img, sd.FileName, ref clsid, IntPtr.Zero ); GdipDisposeImage( img ); return st == 0; }

    Read the article

  • uploading images with the help of arrays and fetch errors

    - by bonny
    i use a script to upload a couple of images to a directory. the code works great in case of just one picture will be uploaded. if i like to upload two images or more and have an extension that is not accepted, the script will upload the one with the extension that is allowed to upload and shows the errormessage for the one who is not accepted. but the upload takes place. that's my first problem. second problem will be: in case of an errormessage i would like to display a message in which it is said, which of the images will be not allowed. i do not know how to fetch this one that has an unaccepted ending into a variable that i can echo to the errormessage. here is the code i use: if(!empty($_FILES['image']['tmp_name'])){ $allowed_extension = array('jpg', 'jpeg', 'png', 'bmp', 'tiff', 'gif'); foreach($_FILES['image']['name'] as $key => $array_value){ $file_name = $_FILES['image']['name'][$key]; $file_size = $_FILES['image']['size'][$key]; $file_tmp = $_FILES['image']['tmp_name'][$key]; $file_extension = strtolower(end(explode('.', $file_name))); if (in_array($file_extension, $allowed_extension) === false){ $errors[] = 'its an unaccepted format in picture $variable_that_count'; continue; } if ($file_size > 2097152){ $errors[] = 'reached maxsize of 2MB per file in picture $variable_that_count'; } if (count($errors) == 0){ $path = "a/b/c/"; $uploadfile = $path."/".basename($_FILES['image']['name'][$key]); if (move_uploaded_file($_FILES['image']['tmp_name'][$key], $uploadfile)){ echo "success."; } } } } hope it will be clear what i like to approach. if there is someone who could help out i really would appreciate. thanks a lot.

    Read the article

  • java gui image problem : doesn't display in the background

    - by thegamer
    Hello, i have a query about why is my image not being displayed in my background of my program. I mean i did all the steps necessary and still it would'nt be displayed. The code runs perfectly but without having the image displayed. The directory is written in the good location of the image. I am using java with gui. If anyone could help me solve my problem, i would appreciate :) here is the code below: import java.awt.*; import java.awt.event.*; import javax.swing.*; public class hehe extends JPanel{ public hehe(){ setOpaque(false); setLayout(new FlowLayout()); } public static void main (String args[]){ JFrame win = new JFrame("yooooo"); // it is automaticcally hidden JPanel mainPanel = new JPanel(new BorderLayout()); win.add(mainPanel); JLabel titleLabel = new JLabel("title boss"); titleLabel.setFont(new Font("Arial",Font.BOLD,18)); titleLabel.setForeground(Color.blue); mainPanel.add(titleLabel,BorderLayout.NORTH); win.setSize(382,269); // the dimensions of the image win.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); win.setVisible(true); } public void paint(Graphics g) { Image a = Toolkit.getDefaultToolkit().getImage("C:\\Users\\andrea\\Desktop\\Gui\\car"); // car is the name of the image file and is in JPEG g.drawImage(a,0,0,getSize().width,getSize().height,this); super.paint(g); } }

    Read the article

  • Which is the best way to encode batch videos on server side?

    - by albanx
    Hello I am making a general question since I am a developer and I have no advance experience on video elaboration. I have to preparare a web application with the purpose to allow video files upload on our company server and then video elaboration by server, on user command. The purpose of the web application is to allow to the user to make some elaboration on video depending on user action launch from the web app: (server has to ) convert video in different format(mp4, flv...) extact keyframes from video and saves them in jpeg format possibility to extract audio from video automatic control of quality audio & video (black frames,silences detection) change scene detection and keyframe extraction ..... This what's my bosses wanted from the web based application (with the server support obviously), and I understand only the first 3 points of this list, the rest for me was arabic.... My question is: Which is the best and fastest server side application for this works, that can support multiple batch video conversions, from command line (comand line for php-soap-socket interaction or something else..)? Is suitable Adobe Media Server for batch video conversion? Which are adobe products that can be used for this purpose? Note: I have experience with Indesign Server scripting programing (sending xml with php and soap call...), and I am looking to something similiar for video elaboration. I will appreciate any answers. THANKS ALL

    Read the article

< Previous Page | 31 32 33 34 35 36 37 38 39 40 41 42  | Next Page >