Search Results

Search found 45031 results on 1802 pages for 'same name'.

Page 354/1802 | < Previous Page | 350 351 352 353 354 355 356 357 358 359 360 361  | Next Page >

  • Pass data in np.dnarray to Highcharts

    - by F.N.B
    I'm working with python 2.7, jinja2, flask and Highcharts. I create two numpy array (x1 and x2, type = numpy.dnarray) and I pass to Highcharts. My problems is, Highcharts don't recognize the commas in the vector. This is my jinja2 code: <script> $(function () { $('#container').highcharts({ series: [{ name: 'Tokyo', data: {{ x1 }} }, { name: 'London', data: {{ x2 }} }] }); }); And this is the error that I look with network chrome dev tools: series: [{ name: 'Tokyo', data: [1 4 5 2 3] }, { name: 'London', data: [3 6 7 4 1] }] I need change the numpy array to python list to pass to Highcharts or there is a better way to do?? Thanks

    Read the article

  • Grails' GORM constraint question

    - by xain
    Hi, I have the following Domain Class: class Metric { String name float value static belongsTo = [Person,Corporation] static indexes = { name() } } How can I add a constraint so Person,Corporation and name are unique ? Thanks.

    Read the article

  • postgresql duplicate table names best practice

    - by veilig
    My company has a handful of apps that we deploy in the websites we build. Recently a very old app needed to be included along side a newer app and there was a conflict w/ a duplicate table name needed to be used by both apps. We are now in the process of updating an old app and there will be some DB updates. I'm curious what people consider best practice (or how do you do it) to help ensure these name collisions don't happen. I've looked at schema's but not sure if thats the right path we want to take. As the documentation prescribes, I don't want to "wire" a particular schema name into an application and if I add schema's to the user search path how would it know which table I was referring to if two schema's have the same table name. although, maybe I'm reading to much into this. Any insights or words of wisdom would be greatly appreciated!

    Read the article

  • Java Program Compiles and Runs, but doesn't work

    - by Richard Long
    When I run this program I enter information in a text box, push the search button, but nothing happens. The program just sits there until I press Cntrl C to break it. It looks like it should work, but I can't figure out what is hanging the program up. Here is the code: First class: import java.io.*; import java.awt.*; import javax.swing.*; import java.awt.event.*; import java.util.*; public class NameGameFrame extends JFrame { public static String name; static JTextField textfield = new JTextField(20); static JTextArea textarea = new JTextArea(30,30); public static String num; public static String [] fields; public static int [] yearRank; public static boolean match; public static int getInts, marker, year, max; public static void main( String[] args) { JFrame frame = new JFrame(); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.setTitle("Name Game"); frame.setLocation(500,400); frame.setSize(800,800); JPanel panel = new JPanel(new GridBagLayout()); GridBagConstraints c = new GridBagConstraints(); JLabel label = new JLabel("Enter the Name or Partial Name to search:"); c.gridx = 0; c.gridy = 0; c.insets = new Insets(2,2,2,2); panel.add(label,c); c.gridx = 0; c.gridy = 1; panel.add(textarea,c); JButton button = new JButton("Search"); c.gridx = 1; c.gridy = 1; panel.add(button,c); c.gridx = 1; c.gridy = 0; panel.add(textfield,c); frame.getContentPane().add(panel, BorderLayout.NORTH); frame.pack(); frame.setVisible(true); button.addActionListener(new ActionListener() { public void actionPerformed(ActionEvent ae) { name = textfield.getText(); java.io.File file = new java.io.File("namesdata.txt"); try { Scanner input = new Scanner(file); num = input.nextLine(); NameRecord nr = new NameRecord(name); while (input.hasNext()) { if(match = num.toLowerCase().contains(name.toLowerCase())) { nr.getRank(); nr.getBestYear(marker); } } } catch(FileNotFoundException e) { System.err.format("File does not exist\n"); } textarea.setText(fields[0]); } }); } } This is the second class: import java.io.*; import java.util.*; public class NameRecord { public NameRecord( String name) { } public static int getBestYear(int marker) { switch (marker) { case 1: year = 1900; break; case 2: year = 1910; break; case 3: year = 1920; break; case 4: year = 1930; break; case 5: year = 1940; break; case 6: year = 1950; break; case 7: year = 1960; break; case 8: year = 1970; break; case 9: year = 1980; break; case 10: year = 1990; break; case 11: year = 2000; break; } return year; } public static int getRank() { fields = num.split(" "); max = 0; for (int i = 1; i<12; i++) { getInts = Integer.parseInt(fields[i]); if(getInts>max) { max = getInts; marker = i; } } return max; } }

    Read the article

  • an asp.net routing issue

    - by Adam Right
    my route implementation on Global.asax protected void Application_Start(object sender, EventArgs e) { this.intRoutes(RouteTable.Routes); } void intRoutes(RouteCollection Rts) { Rts.MapPageRoute("search", "{language}/{page}", "~/search.aspx"); Rts.MapPageRoute("category", "{language}/{name}/{no}/{categoryname}", "~/category.aspx"); Rts.MapPageRoute("product", "{language}/{name}/{no}/{productname}", "~/product.aspx"); } the problem is; if i use product routing on a hyperlink, like as follows; <asp:HyperLink ID="hyProduct" NavigateUrl='<%#HttpUtility.UrlDecode(((Page)HttpContext.Current.Handler).GetRouteUrl("product", new{ language=getUIFromHelper(),name=getNameFromHelper(),no=Eval("code"),productname=getProductNameFromHelper(Eval("name"))})) %>' runat="server" Text="something" /> everything goes fine, the link is written as expected like /en/products/06.008.001.150.0510/davis-fish-seeker-green but when i click that link the category.aspx page runs insted of product.aspx. am i missing out something ?

    Read the article

  • Is there a way to keep track of the ordering of items in a dictionary?

    - by Corpsekicker
    I have a Dictionary<Guid, ElementViewModel>. (ElementViewModel is our own complex type.) I add items to the dictionary with a stock standard items.Add(Guid.NewGuid, new ElementViewModel() { /*setters go here*/ });, At a later stage I remove some or all of these items. A simplistic view of my ElementViewModel is this: class ElementViewModel { Guid Id { get; set; } string Name { get; set; } int SequenceNo { get; set; } } It may be significant to mention that the SequenceNos are compacted within the collection after adding, in case other operations like moving and copying took place. {1, 5, 6} - {1, 2, 3} A simplistic view of my remove operation is: public void RemoveElementViewModel(IEnumerable<ElementViewModel> elementsToDelete) { foreach (var elementViewModel in elementsToDelete) items.Remove(elementViewModel.Id); CompactSequenceNumbers(); } I will illustrate the problem with an example: I add 3 items to the dictionary: var newGuid = Guid.NewGuid(); items.Add(newGuid, new MineLayoutElementViewModel { Id = newGuid, SequenceNo = 1, Name = "Element 1" }); newGuid = Guid.NewGuid(); items.Add(newGuid, new MineLayoutElementViewModel { Id = newGuid, SequenceNo = 2, Name = "Element 2" }); newGuid = Guid.NewGuid(); items.Add(newGuid, new MineLayoutElementViewModel { Id = newGuid, SequenceNo = 3, Name = "Element 3" }); I remove 2 items RemoveElementViewModel(new List<ElementViewModel> { item2, item3 }); //imagine I had them cached somewhere. Now I want to add 2 other items: newGuid = Guid.NewGuid(); items.Add(newGuid, new MineLayoutElementViewModel { Id = newGuid, SequenceNo = 2, Name = "Element 2, Part 2" }); newGuid = Guid.NewGuid(); items.Add(newGuid, new MineLayoutElementViewModel { Id = newGuid, SequenceNo = 3, Name = "Element 3, Part 2" }); On evaluation of the dictionary at this point, I expected the order of items to be "Element 1", "Element 2, Part 2", "Element 3, Part 2" but it is actually in the following order: "Element 1", "Element 3, Part 2", "Element 2, Part 2" I rely on the order of these items to be a certain way. Why is it not as expected and what can I do about it?

    Read the article

  • Why do I get null objects in a many-to-many bag?

    - by Jim Geurts
    I have a bag defined for a many-to-many list: <class name="Author" table="Authors"> <id name="Id" column="AuthorId"> <generator class="identity" /> </id> <property name="Name" /> <bag name="Books" table="Author_Book_Map" where="IsDeleted=0" fetch="join"> <key column="AuthorId" /> <many-to-many class="Book" column="BookId" where="IsDeleted=0" /> </bag> </class> If I return all author objects using something like the following, I will get what initially appeared to be duplicate Author records: Session.Query<Author>().List<Author>() The extra author objects are created when an author is mapped to Book objects that have IsDeleted = 1 and IsDeleted = 0. Rather than creating one Author object with an enumerable that contains only the books with IsDeleted = 0, it will create two author objects. The first author object has a Books enumerable that contains books with IsDeleted = 0. The second author object will contain an enumerable of null book objects. Similarly, if an object only has one book map, and that map points to a book with IsDeleted = 1, then an author object is returned with a Books collection having one null object. I'm thinking part of the problem stems from the map table objects linking to rows that satisfy the where condition on the bag object but do not meet the many-to-many where condition. This is happening with NHibernate version 3.0.0.4980. Is this a configuration issue or something else?

    Read the article

  • Class Property in for each

    - by KoolKabin
    Hi guys, I am running from a problem while iterating over class properties. I have my first class: class Item private _UIN as integer = 0 private _Name as string = "" private _Category as ItemCategory = new ItemCategory() public Property UIN() as integer public property Name() as string public property Category() as ItemCategory end class Now when i iterate over the class properties from following code Dim AllProps As System.Reflection.PropertyInfo() Dim PropA As System.Reflection.PropertyInfo dim ObjA as object AllProps = new Item().getType().getProperties() for each propA in AllProps ObjA = PropA.GetValue(myObj, New Object() {}) debug.write ObjA.GetType().Name next I get UIN, Name, ItemCategory but i expected UIN, Name and Category. I am a bit unclear about this and dun know why this is happening? What should i do to correct it?

    Read the article

  • wifi disconnect event

    - by user986474
    when i get disconnect event by this code : public class WifiReceiver extends BroadcastReceiver { @Override public void onReceive(Context context, Intent intent) { String ssid="someSsidName"; ConnectivityManager conMan = (ConnectivityManager) context.getSystemService(Context.CONNECTIVITY_SERVICE); WifiManager wifiManager = (WifiManager) context.getSystemService(Context.WIFI_SERVICE); NetworkInfo netInfo = conMan.getActiveNetworkInfo(); WifiInfo wifiInfo = null; if (netInfo.getType() == ConnectivityManager.TYPE_WIFI) { //android connect to wifi } else{ //do somthing } } } i try to know what the ssid name when android disconnect. i mean when android disconnect from wifi i need to know it (this i can know by my code) but what i missing is the ssid name android just disconnect from. there is a way to do that? (i know i can save the name when android connect to wifi and use this name when disconnect but this not the way i want...) thanks in advance!

    Read the article

  • Entity Framework This property descriptor does not support the SetValue

    - by Gayan
    Hello guys, below are my entities which i have created using entity frame work. retailer id name childs(navigation) generated database schema [Id] [int] IDENTITY(1,1) NOT NULL, [Name] nvarchar NOT NULL childern id name RETAILER(navigation) generated database schema [Id] [int] IDENTITY(1,1) NOT NULL, [name] nvarchar NOT NULL [Retailer_Id] [int] NOT NULL, As you can see in the above model the relationship is 1 retailer can have 0 or 1 child. my problem is when i create a new child and set the retailer navigation property of it to a retailer entity it throws the following exception.how do i solve it Error while setting property 'retailer': 'This property descriptor does not support the SetValue method.'.

    Read the article

  • Classes and Objects in C++

    - by anurag18294
    class anurag { private: int rollno; char name[50]; int marks; float percen; void percentage(int num) { percen=(num/500)*100; } public: void getdata(void) { cout<<"\n\nEnter the name of the student:"; gets(name); cout<<"\n\nEnter the roll no: and the marks:"; cin>>rollno>>marks; percentage(marks); } void display(void) { cout<<"\n\nThe name of the student is:"; cout.write(name,50); cout<<"\n\nThe roll no: of the student is:"; cout<<rollno; cout<<"\n\n The marks obtained is:"<<marks; cout<<"\n\nThe percentage is:"<<percen; }}; void main() { clrscr(); anurag F; F.getdata(); F.display(); getch(); } why the following code is not giving the desired output?

    Read the article

  • Does my function right on python?

    - by Ali Ismayilov
    Write a function which takes a string argument, and creates and returns an Employee object containing details of the employee specified by the string. The string should be assumed to have the format 12345 25000 Consultant Bart Simpson The first three items in the line will be the payroll number, salary and job title and the rest of the line will be the name. There will be no spaces in the job title but there may be one or more spaces in the name. My function: def __str__(self): return format(self.payroll, "d") + format(self.salary, "d") + ' ' \ + self.jobtitle + self.name

    Read the article

  • help with generating models from database for many to many in doctrine

    - by ajsie
    im using doctrine and i have set up some test tables to be generated into models: I want a many-to-many relationship models (3 tables converted into 3 models) (things are simplified to make the point clear) mysql tables: user: id INT // primary key name VARCHAR group: id INT // primary key name VARCHAR user_group: user_id INT // primary and foreign key to user.id group_id INT // primary and foreign key to group.id i thought that it would generate these models (from the documentation): // User.php class User extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name); } public function setUp() { $this->hasMany('Group as Groups', array( 'refClass' => 'UserGroup', 'local' => 'user_id', 'foreign' => 'group_id' ) ); } } // Group.php class Group extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name); } public function setUp() { $this->hasMany('User as Users', array( 'refClass' => 'UserGroup', 'local' => 'group_id', 'foreign' => 'user_id' ) ); } } // UserGroup.php class UserGroup extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('user_id') ); $this->hasColumn('group_id') ); } } but it generated this: // User.php abstract class BaseUser extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name'); } public function setUp() { $this->hasMany('UserGroup', array( 'local' => 'id', 'foreign' => 'user_id')); } } // Group.php abstract class BaseGroup extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('id'); $this->hasColumn('name'); } public function setUp() { $this->hasMany('UserGroup', array( 'local' => 'id', 'foreign' => 'group_id')); } } // UserGroup.php abstract class BaseUserGroup extends Doctrine_Record { public function setTableDefinition() { $this->hasColumn('user_id'); $this->hasColumn('group_id'); } public function setUp() { $this->hasOne('User', array( 'local' => 'user_id', 'foreign' => 'id')); $this->hasOne('Group', array( 'local' => 'group_id', 'foreign' => 'id')); } } as you can see, there is no 'refClass' in the 'User' and 'Group' models pointing to the 'UserGroup'. the 'UserGroup' table in this case is just another table from Doctrine's perspective not a reference table. I've checked my table definitions in mysql. They are correct. user_group has 2 columns (primary keys and foreign keys), each one pointing to the primary key in either User or Group. But i want the standard many-to-many relationship models in Doctrine models. I'd appreciate some help. I have struggled to figure it out for a half day now. What is wrong? Thanks!

    Read the article

  • Javascript Regular Expression help

    - by user270399
    Hello! I have got the following regular expression working just fine in Rad Software Regular Expression designer. param\s+name\s*=\s*"movie"\s+value=\s*"(?<target>.*?)" And now i am wondering, how to get this to work in javascript. It keeps on complaininge about the "target" part. I am trying to validate and get the url from the youtube embed code. <object width="640" height="385"><param name="movie" value="http://www.youtube.com/v/ueZP6ifzqMY&hl=sv_SE&fs=1&rel=0"></param><param name="allowFullScreen" value="true"></param><param name="allowscriptaccess" value="always"></param><embed src="http://www.youtube.com/v/ueZP6ifzqMY&hl=sv_SE&fs=1&rel=0" type="application/x-shockwave-flash" allowscriptaccess="always" allowfullscreen="true" width="640" height="385"></embed></object> How the heck do i get this regex to work with my javascript? :)

    Read the article

  • ucommerce: how to change category template

    - by autonomatt
    Using uCommerce 2, umbraco 4.7. I have a category side nav showing the categories using: <a> <xsl:attribute name="href"> <xsl:value-of select="CommerceLibrary:GetNiceUrlForCategory($catalogueName, @id)"/> </xsl:attribute> <xsl:value-of select="@displayName"/> </a> First of all, when hovering over the links it still shows an old catalogue name, even though I've renamed the catalogue and also hardcoded the catalogue name into: <xsl:variable name="catalogueName" select="'MyCatalogue'"/> When I click on the link generated by GetNiceUrlForCategory I get the standard template that comes with uCommerce started site. I've tried deleting the whole started site, but I just can't get it to link to a template I did for the category. I still don't quite understand how ucommerce knows which template to use for a category link. Soren? :) Cheers, Matt

    Read the article

  • Why baseclass calls method of subclass?

    - by twlkyao
    I encounter some code like the following: BaseClass: public class BaseClass { String name = "Base"; public BaseClass() { printName(); } public void printName() { System.out.println(name + "——Base"); } } DrivedClass: public class SubClass extends BaseClass { String name = "Sub"; public SubClass() { printName(); } public void printName() { System.out.println(name + "——Sub"); } public static void main(String[] args) { new SubClass(); } } When run the code, the output is: null——Sub Sub——Sub while it should be: Base——Base Sub——Sub I wonder why the BaseClass constructor calls the SubClass method, can anybody explain this? Thanks in advance.

    Read the article

  • Quantity in amazon cart?

    - by user201140
    Hi I'd like to change the quantity in an AWS order. I've used the form below and that works fine for adding 1 item to the cart, but when I try to change it to a quantity of 2 it says there are no items in my cart. What am I doing wrong? Thanks. <form method="GET" action="http://www.amazon.com/gp/aws/cart/add.html" id="Quantity"> <input type="hidden" name="AWSAccessKeyId" value="Access Key ID" /> <input type="hidden" name="AssociateTag" value="Associate Tag" /> <?php echo "<input type='hidden' name='ASIN.1' value='".$itemid."'/>"; ?> <input type="hidden" name="Quantity.1" value="1"/><br/> <input type="image" src="buynow.gif" value="Submit" alt="Submit"> </form>

    Read the article

  • Windows 7 Mobile ListBox uncustomizable?

    - by Roy
    I've just recently started development using Visual Studio 2010 Express for Windows Phone and I put in a ListBox. I can't seem to manipulate the formatting. No matter what I do, the background is black/gray, the selected items have a blue border, and there is padding between the items in the listbox (i'm using images). Here is my code: Xaml: <Grid x:Name="ContentGrid" Grid.Row="1"> <Grid Name="gallery"> <Grid.RowDefinitions> <RowDefinition Height="370" /> <RowDefinition Height="150" /> </Grid.RowDefinitions> <Border BorderBrush="Red" Width="450" CornerRadius="4" BorderThickness="2" Background="Red" Margin="10,30,20,10" Padding="6,6,6,6"> <Image Grid.Row="0" Grid.Column="0" Height="360" x:Name="imgPreview"/> </Border> <ListBox x:Name="lbScrollGallery" Grid.Row="1" Grid.Column="0" Padding="0" VerticalAlignment="Top" Width="450" SelectionChanged="ScrollerSelectionChanged" d:LayoutOverrides="HorizontalAlignment" ScrollViewer.HorizontalScrollBarVisibility="Hidden"> <ListBox.ItemsPanel> <ItemsPanelTemplate> <StackPanel Orientation="Horizontal"/> </ItemsPanelTemplate> </ListBox.ItemsPanel> <ListBox.ItemTemplate> <DataTemplate> <Image Width="100" Height="100" Stretch="Fill" Name="imgSource" VerticalAlignment="Center" Source="{Binding Path=Url}" /> </DataTemplate> </ListBox.ItemTemplate> </ListBox> </Grid> </Grid> Is there some way I can customize the listbox? Like change the background to red or make the padding between different items 0?

    Read the article

  • cellForRowAtIndexPath not being called, but rowsInSections is and it's delegate is set

    - by Jhorra
    I searched around prior to posting this and made sure I hadn't missed anything obvious, though I have a feeling I am missing something basic. I'm using this as a sidebar navigation view. I tried making them static cells and pre-populating them, but they were blank that way as well. When I do it this way I can see everything gets called except that. I've tried deleting it and re-adding it. #import "acxSideBarController.h" @interface acxSideBarController () @end @implementation acxSideBarController @synthesize sidebarDelegate = _sidebarDelegate; - (id)initWithStyle:(UITableViewStyle)style { self = [super initWithStyle:style]; if (self) { // Custom initialization } return self; } - (void)viewDidLoad { [super viewDidLoad]; if ([self.sidebarDelegate respondsToSelector:@selector(lastSelectedIndexPathForSidebarViewController:)]) { NSIndexPath *indexPath = 0; [self.tableView selectRowAtIndexPath:indexPath animated:NO scrollPosition:UITableViewScrollPositionNone]; } self.tableView.backgroundColor = [UIColor underPageBackgroundColor]; self.tableView.dataSource = self; self.tableView.delegate = self; } - (void)viewDidUnload { [super viewDidUnload]; } - (void)viewWillAppear:(BOOL)animated { [super viewWillAppear:animated]; } - (BOOL)shouldAutorotateToInterfaceOrientation:(UIInterfaceOrientation)interfaceOrientation { return (interfaceOrientation == UIInterfaceOrientationPortrait); } #pragma mark - Table view data source - (NSInteger)numberOfSectionsInTableView:(UITableView *)tableView { return 3; } - (NSInteger)tableView:(UITableView *)tableView numberOfRowsInSection:(NSInteger)section { if(section == 0) return 2; else if(section == 1) return 1; else return 1; } - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { static NSString *CellIdentifier = @"linkCell"; UITableViewCell *cell = [tableView dequeueReusableCellWithIdentifier:CellIdentifier]; if (cell == nil) { cell = [[UITableViewCell alloc] initWithStyle:UITableViewCellStyleDefault reuseIdentifier:CellIdentifier]; } NSString *name = @""; if(indexPath.section == 1) name = @"Inbox"; else if(indexPath.section == 2) name = @"Logout"; else { if(indexPath.row == 0) name = @"Roster"; else if(indexPath.row == 1) name = @"Environmental Variables"; } cell.textLabel.text = name; cell.textLabel.textColor = [UIColor darkTextColor]; return cell; } - (NSString *)tableView:(UITableView *)tableView titleForHeaderInSection:(NSInteger)section { if(section == 0) return @"Students"; else if(section == 1) return @"Communication"; else return @" "; } #pragma mark - Table view delegate - (void)tableView:(UITableView *)tableView didSelectRowAtIndexPath:(NSIndexPath *)indexPath { if (self.sidebarDelegate) { [self.sidebarDelegate acxSideBarController:self atIndexPath:indexPath]; } } @end If it's helpful here's the header file #import <UIKit/UIKit.h> @protocol acxSideBarControllerDelegate; @interface acxSideBarController : UITableViewController @property (nonatomic, assign) id <acxSideBarControllerDelegate> sidebarDelegate; @end @protocol acxSideBarControllerDelegate <NSObject> - (void)acxSideBarController:(acxSideBarController *)acxSideBarController atIndexPath:(NSIndexPath *)indexPath; @optional - (NSIndexPath *)lastSelectedIndexPathForacxSideBarController:(acxSideBarController *)acxSideBarController; @end

    Read the article

  • SQL query showing element more than once.

    - by Sorin Cioban
    Hi guys, I have the following SQL query but it doesn't entirely work because it shows each element more than once. select c.name, c.director, c.title, count(c.title) as numfilms from casting c join casting c1 on c1.name = c.name Group by c.name, c.director, c.title Having count (c.title) > 1 order by numfilms So what it does it shows which actors have made more than 1 film. But unfortunately, this query shows each actor as many times as the number of movies he made. Using distinct doesn't work as actor may have been in different movie with same title and different director.

    Read the article

  • Hibernate NamingStrategy implementation that maintains state between calls

    - by Robert Petermeier
    Hi, I'm working on a project where we use Hibernate and JBoss 5.1. We need our entity classes to be mapped to Oracle tables that follow a certain naming convention. I'd like to avoid having to specify each table and column name in annotations. Therefore, I'm currently considering implementing a custom implementation of org.hibernate.cfg.NamingStrategy. The SQL naming conventions require the name of columns to have a suffix that is equivalent to a prefix of the table name. If there is a table "T100_RESOURCE", the ID column would have to be named "RES_ID_T100". In order to implement this in a NamingStrategy, the implementation would have to maintain state, i.e. the current class name it is creating the mappings for. It would rely on Hibernate to always call classToTableName() before propertyToColumnName() and to determine all column names by calling propertyToColumnName() before the next call to classToTableName() Is it safe to do that or are there situations where Hibernate will mix things up? I am not thinking of problems through multiple threads here (which can be solved by keeping the last class name in a ThreadLocal) but also of Hibernate deliberately calling this out of order in certain circumstances. For example Hibernate asking for mappings of three properties of class A, then one of class B, then again more attributes of class A.

    Read the article

  • PHP Object Access Syntax Question with the $

    - by ImperialLion
    I've been having trouble searching for this answer because I am not quite sure how to phrase it. I am new to PHP and still getting my feet on the ground. I was writing a page with a class in it that had the property name. When I originally wrote the page there was no class so I just had a variable called $name. When I went to encapsulate it in a class I accidental changed it to be $myClass->$name. It tool me a while to realize that the syntax I needed was $myClass->name. The reason it took so long was the error I kept getting was "Attempt to access a null property" or something along those lines. The error lead me to believe it was a data population error. My question is does $myClass->$name have a valid meaning? In other words is there a time you would use this and a reason why it doesn't create a syntax error? If so what is the semantic meaning of that code? When would I use it if it is valid? If its not valid, is there a reason that it doesn't create a syntax error?

    Read the article

  • I'm new to Java most basic question about arrays!

    - by ambidextorous
    Hey I have not been able to find a proper answer on any forums about this but how exactly do I pass an array to a class? public class TestArray { String name; String[] array; public TestArray(String name, String[] anArray){ this.name = name; int len = anArray.length; this.array = new String[len]; for (int i = 0; i < len; i++){ this.array[i] = new String(anArray[i]); } } } public static void main(String[] args){ String[] anArray = new String[2]; anArray[0] = new String("Test"); anArray[1] = new String("Test2"); TestArray work = new TestArray("Jordan", anArray?); } }

    Read the article

< Previous Page | 350 351 352 353 354 355 356 357 358 359 360 361  | Next Page >