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  • Printing out series of numbers in java

    - by Jay
    hi guys i am just doing some reading for myself to learn java and came across this problem and is currently stuck. i need to print out series of number based on the input given by the user. for example, if input = 5, the output should be as follows @1@22@333@4444@55555 import java.util.*; public class ex5{ public static void main(String[] args){ Scanner kb = new Scanner(System.in); System.out.println("Please type a #: "); int input = kb.nextInt(); for(int i=0;i<input;i++){ if(input==1){ System.out.print("@1"); } if(input==2){ System.out.print("@1@22"); } } } } this doesnt seem to be working because this is the output i get Please type a #: 2 @1@22@1@22 im not sure what to put inside the for loop right now and i dont think i am using the for loop here very well either... any help guys?

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  • Sending email using Java, connecting to a gmail host hangs

    - by Tot
    I would like to send emails via Java code. I added in my library the following .JARs: log4j.jar, smtp.jar, mailapi.jar,ctivation.jar. And my Java class looks like this: import java.util.Properties; import javax.mail.*; import javax.mail.internet.*; public class SendEmail { public static void main(String [] args) { String to = "[email protected]"; String from = "[email protected]"; String host = "smtp.gmail.com"; Properties properties = System.getProperties(); properties.setProperty("mail.smtp.host", host); properties.setProperty("mail.smtp.starttls.enable", "true"); properties.setProperty("mail.smtp.auth", "true"); SmtpAuthenticator authentication = new SmtpAuthenticator(); javax.mail.Message msg = new MimeMessage(Session .getInstance(properties, authentication)); try { msg.setFrom(new InternetAddress(from)); msg.setRecipient(Message.RecipientType.TO, new InternetAddress(to)); msg.setSubject("Subject"); msg.setText("Working fine..!"); System.out.println("fine1 !!"); Transport transport = Session.getDefaultInstance( properties , null).getTransport("smtp"); System.out.println("fine2 !!"); transport.connect("smtp.gmail.com" , 465 , "username", "password"); System.out.println("fine3 !!"); Transport.send(msg); System.out.println("fine!!"); } catch(Exception exc) { System.out.println(exc); } } } My SmtpAuthenticator class: import javax.mail.Authenticator; import javax.mail.PasswordAuthentication; public class SmtpAuthenticator extends Authenticator { public SmtpAuthenticator() { super(); } @Override public PasswordAuthentication getPasswordAuthentication() { String username = "user"; String password = "password"; if ((username != null) && (username.length() > 0) && (password != null) && (password.length() > 0)) { return new PasswordAuthentication(username, password); } return null; } } When i run my Java application class it prints: fine1 !! fine2 !! And it hangs. How can I get rid of this problem?

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  • how to do display text message from cellphone to textbox

    - by Jiggy Degamo
    I am just making a project automated polling system using sms but i just a beginner of serial communication i have seen a code on the net so i apply it as my guide just a simple text message and display it on the textbox it connects but the provlem is its didn't display on the textbox. here is the code below please help me why it didn't display and please give me a cite that have a tutorial of serial communication using vb.net Imports System.IO.Ports Public Class Form1 Dim inputData As String = "" Private WithEvents serialPort1 As New IO.Ports.SerialPort Public Event DataReceived As IO.Ports.SerialDataReceivedEventHandler Private Sub Form1_FormClosed(ByVal sender As Object, ByVal e As System.Windows.Forms.FormClosedEventArgs) Handles Me.FormClosed ' Close the Serial Port serialPort1.Close() End Sub Private Sub Form1_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load 'Set values for some properties serialPort1.PortName = "COM10" serialPort1.BaudRate = 2400 SerialPort1.Parity = IO.Ports.Parity.None SerialPort1.DataBits = 8 SerialPort1.StopBits = IO.Ports.StopBits.One SerialPort1.Handshake = IO.Ports.Handshake.None SerialPort1.RtsEnable = True ' Open the Serial Port SerialPort1.Open() 'Writes data to the Serial Port output buffer If SerialPort1.IsOpen = True Then SerialPort1.Write("MicroCommand") End If End Sub ' Receive data from the Serial Port 'Show received data on UI controls and do something Public Sub DoUpdate() TextBox1.Text = TextBox1.Text & inputData End Sub Private Sub serialPort1_DataReceived(ByVal sender As Object, ByVal e As System.IO.Ports.SerialDataReceivedEventArgs) Handles serialPort1.DataReceived inputData = serialPort1.ReadExisting 'or serialPort1.ReadLine Me.Invoke(New EventHandler(AddressOf DoUpdate)) End Sub End Class

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  • Releasing Excel after using Interop

    - by figus
    Hi everyone I've read many post looking for my answer, but all are similar to this: http://stackoverflow.com/questions/1610743/reading-excel-files-in-vb-net-leaves-excel-process-hanging My problem is that I don't quit the app... The idea is this: If a User has Excel Open, if he has the file I'm interested in open... get that Excel instance and do whatever I want to do... But I don't to close his File after I'm done... I want him to keep working on it, the problem is that when he closes Excel... The process keeps running... and running... and running after the user closes Excel with the X button... this is how I try to do it This piece is used to know if he has Excel open, and in the For I check for the file name I'm interested in. Try oApp = GetObject(, "Excel.Application") libroAbierto = True For Each libro As Microsoft.Office.Interop.Excel.Workbook In oApp.Workbooks If libro.Name = EquipoASeccionIdSeccion.Text & ".xlsm" Then Exit Try End If Next libroAbierto = False Catch ex As Exception oApp = New Microsoft.Office.Interop.Excel.Application End Try here would be my code... if he hasn't Excel open, I create a new instance, open the file and everything else. My code ends with this: If Not libroAbierto Then libroSeccion.Close(SaveChanges:=True) oApp.Quit() Else oApp.UserControl = True libroSeccion.Save() End If System.Runtime.InteropServices.Marshal.FinalReleaseComObject(libroOriginal) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(libroSeccion) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(origen) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(copiada) System.Runtime.InteropServices.Marshal.FinalReleaseComObject(oApp) libroOriginal = Nothing libroSeccion = Nothing oApp = Nothing origen = Nothing copiada = Nothing nuevosGuardados = True So you can see that, if I opened the file, I call oApp.Quit() and everything else and the Excel Process ends after a few seconds (maybe 5 aprox.) BUT if I mean the user to keep the file open (not calling Quit()), Excel process keeps running after the user closes Excel with the X button. Is there any way to do what I try to do?? Control a open instance of excel and releasing everything so when the user closes it with the X button, the Excel Process dies normally??? Thanks!!!

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  • Set Custom ASP.NET UserControl variables when its in a Repeater

    - by tnriverfish
    <%@ Register Src="~/Controls/PressFileDownload.ascx" TagName="pfd" TagPrefix="uc1" %> <asp:Repeater id="Repeater1" runat="Server" OnItemDataBound="RPTLayer_OnItemDataBound"> <ItemTemplate> <asp:Label ID="LBLHeader" Runat="server" Visible="false"></asp:Label> <asp:Image ID="IMGThumb" Runat="server" Visible="false"></asp:Image> <asp:Label ID="LBLBody" Runat="server" class="layerBody"></asp:Label> <uc1:pfd ID="pfd1" runat="server" ShowContainerName="false" ParentContentTypeId="55" /> <asp:Literal ID="litLayerLinks" runat="server"></asp:Literal> </ItemTemplate> </asp:Repeater> System.Web.UI.WebControls.Label lbl; System.Web.UI.WebControls.Literal lit; System.Web.UI.WebControls.Image img; System.Web.UI.WebControls.HyperLink hl; System.Web.UI.UserControl uc; I need to set the ParentItemID variable for the uc1:pdf listed inside the repeater. I thought I should be able to find uc by looking in the e.Item and then setting it somehow. I think this is the part where I'm missing something. uc = (UserControl)e.Item.FindControl("pfd1"); if (uc != null) { uc.Attributes["ParentItemID"] = i.ItemID.ToString(); } Any thoughts would be appreciated. Also tried this with similar results... when I debug inside my usercontrol (pfd1) the parameters I am trying to set have not been set. uc = (UserControl)e.Item.FindControl("pfd1"); if (uc != null) { uc.Attributes.Add("ContainerID", _cid.ToString()); uc.Attributes.Add("ParentItemId", i.ItemID.ToString()); }

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  • Dynamically class creating by using Java Reflection, java.lang.ClassNotFoundException

    - by rubby
    Hi all; i want to use reflection in java, i want to do that third class will read the name of the class as String from console. Upon reading the name of the class, it will automatically and dynamically (!) generate that class and call its writeout method. If that class is not read from input, it will not be initialized. I wrote that codes but i am always taking to "java.lang.Class.Not.Found.Exception", and i don't know how i can fix it. Can anyone help me? class class3 { public Object dynamicsinif(String className, String fieldName, String value) throws Exception { Class cls = Class.forName(className,true,null); Object obj = cls.newInstance(); Field fld = cls.getField(fieldName); fld.set(obj, value); return obj; } public void writeout3() { System.out.println("class3"); } } public class Main { public static void main(String[] args) throws Exception { System.out.println("enter the class name : "); BufferedReader reader= new BufferedReader(new InputStreamReader(System.in)); String line=reader.readLine(); String x="Text1"; try{ class3 trycls=new class3(); Object gelen=trycls.dynamicsinif(line, x, "rubby"); Class yeni=(Class)gelen; System.out.println(yeni); }catch(ClassNotFoundException ex){ System.out.print(ex.toString()); } } }

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  • how to convert bitmap to intptr in C#

    - by carl
    code as fellow: Bitmap bmp = new Bitmap(e.width, e.height, System.Drawing.Imaging.PixelFormat.Format24bppRgb); System.Drawing.Imaging.BitmapData data = bmp.LockBits(new Rectangle(0, 0, e.width, e.height), System.Drawing.Imaging.ImageLockMode.ReadWrite, System.Drawing.Imaging.PixelFormat.Format24bppRgb); int dataLength = e.width * e.height * 3; Win32.memcpy(data.Scan0, (IntPtr)e.data, (uint)dataLength); convertBitmapToIntptr(bmp);????? how to code in this function like convertBitmapToIntptr(bmp). who give me some idea. thank you very much.

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  • Not receiving all message via TCP in Java?

    - by javatcp
    I have a tcp socket sending three lines like this out2.println("message1\n"); out2.println("message2\n"); out2.println("message3\n"); and another tco socket receiving and displaying these messages like this System.out.println(in.readLine()); System.out.println(in.readLine()); System.out.println(in.readLine()); but only the first message is recieved and displayed, anything I send after that is not.

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  • How to allow for modular development while still running in same JVM?

    - by Marcus
    Our current app runs in a single JVM. We are now splitting up the app into separate logical services where each service runs in its own JVM. The split is being done to allow a single service to be modified and deployed without impacting the entire system. This reduces the need to QA the entire system - just need to QA the interaction with the service being changed. For interservice communication we use a combination of REST, an MQ system bus, and database views. What I don't like about this: REST means we have to marshal data to/from XML DB views couple the systems together which defeats the whole concept of separate services MQ / system bus is added complexity There is inevitably some code duplication between services You have set up n JBoss server configurations, we have to do n number of deployments, n number of set up scripts, etc, etc. Is there a better way to structure an internal application to allow modular development and deployment while allowing the app to run in a single JVM (and achieving the associated benefits)?

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  • Compute weighted averages for large numbers

    - by Travis
    I'm trying to get the weighted average of a few numbers. Basically I have: Price - 134.42 Quantity - 15236545 There can be as few as one or two or as many as fifty or sixty pairs of prices and quantities. I need to figure out the weighted average of the price. Basically, the weighted average should give very little weight to pairs like Price - 100000000.00 Quantity - 3 and more to the pair above. The formula I currently have is: ((price)(quantity) + (price)(quantity) + ...)/totalQuantity So far I have this done: double optimalPrice = 0; int totalQuantity = 0; double rolling = 0; System.out.println(rolling); Iterator it = orders.entrySet().iterator(); while(it.hasNext()) { System.out.println("inside"); Map.Entry order = (Map.Entry)it.next(); double price = (Double)order.getKey(); int quantity = (Integer)order.getValue(); System.out.println(price + " " + quantity); rolling += price * quantity; totalQuantity += quantity; System.out.println(rolling); } System.out.println(rolling); return totalQuantity / rolling; The problem is I very quickly max out the "rolling" variable. How can I actually get my weighted average? Thanks!

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  • Getting User input with Scanner

    - by Giannis
    I am trying to have a scanner take input in a loop. Once the user wants to finish he can exit this loop. I have tried many different ways to do it but there is always some problem. This is the code: Scanner sc = new Scanner(System.in); System.out.println("Continue?[Y/N]"); while (sc.hasNext()&& (sc.next().equals("Y"))) { System.out.println("Enter first name"); String name = sc.nextLine(); System.out.println("Enter surname"); String surname = sc.nextLine(); . . . System.out.println("Continue?[Y/N]"); } } The problem with the code above, which also happens on different methods I tried, is that when the user types Y, the scanner will skip the first input for first name,and jump to the surname. If the user types N the loop stops correctly. Someone can explain the reason this happens, and how to overcome using scanner class? p.s: Doing something like while(sc.nextLine().equals("Y")), will cause the loop to terminate before getting input from user after first run of the loop.

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  • Controller class not available in Add View ASP.NET MVC

    - by Tassadaque
    Hi I have created the following controller i want to add view that should have the data access class UserMagnament.Controller.menuitems but when i add view by right clicking on view folder,it is not showing "UserMagnament.Controller.menuitems" in add data class using System; using System.Collections.Generic; using System.Linq; using System.Web; using System.Web.Mvc; using UserManagement.Models; namespace UserManagement.Controllers { public class menuitems { EvoLetDataContext db1 = new EvoLetDataContext(); public menuitems() { } public IQueryable<UMUserType> menuitems() { return db1.UMUserTypes; //this.Packages = _SysPackage; //this.Modules = _SysModule; } public List<SysPackage> Packages { get; private set; } public List<SysModule> Modules { get; private set; } } public class Default1Controller : Controller { // // GET: /Default1/ public ActionResult Index() { return View(new menuitems()); } } }

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  • Can't draw to a pictureBox in a loop

    - by Jason94
    I have a List<Point> where Point contains X and Y. What i want is to loop a list like that and draw a line point to point, i do so by: foreach (List<Point> wps in map.waypoints) { System.Drawing.Pen myPen; myPen = new System.Drawing.Pen(System.Drawing.Color.Black); System.Drawing.Graphics formGraphics = this.pictureBox1.CreateGraphics(); Point startPos = new Point(wps[0].X, wps[0].Y); foreach (Point p in wps) { formGraphics.DrawLine(myPen, startPos.X, startPos.Y, p.X, p.Y); startPos = p; } myPen.Dispose(); formGraphics.Dispose(); } BUT nothing gets drawn! I did the same with the on_click event to the pictureBox but instead if a looping some Points ive just used mouse X and Y. I have verified the lists of points that they dont contain rubish :D

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  • Java: file write on finalize method

    - by sowrov
    In my understanding a singleton object will destroy only when the application is about to terminate. So in C++ I write a Singleton class to log my application and in that Singleton logger's destructor I log the time when my application was terminated. Things worked perfectly in C++. Now I want to have that same logger in Java, as in java there is no destructor so I implemented the finalize method for that singleton logger. But it seem that finalize method actually never get called. So, I add that System.runFinalizersOnExit(true); line, somewhere in my code (though I know it is deprecated) and that finalize method get called every time before termination of the app. But still there is a problem! If I try to write anything on file in that finalize method, It does not work, though System.out work without any problem! :( Can you guys help me on this problem? Here is a sample code of what I am try to do: Singleton Logger Class: public class MyLogger { FileWriter writer; private MyLogger() { try { this.writer = new FileWriter("log.txt"); } catch (IOException ex) { } } public static MyLogger getInstance() { return MyLoggerHolder.INSTANCE; } private static class MyLoggerHolder { private static final MyLogger INSTANCE = new MyLogger(); } @Override protected void finalize () { try { super.finalize(); System.out.println("Here"); //worked correctly. this.writer.write(new Date().toString()+System.getProperty("line.separator")); this.writer.write("End"); this.writer.flush(); //does not work! this.writer.close(); } catch (Throwable ex) { } } public synchronized void log(String str) { try { this.writer.write(new Date().toString()+System.getProperty("line.separator")); this.writer.write(str+"\n"); this.writer.flush(); } catch (IOException ex) { } } } Main: public class Main { public static void main(String[] args) { System.runFinalizersOnExit(true); MyLogger logger = MyLogger.getInstance(); logger.log("test"); } }

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  • Why my async call does not work?

    - by Petr
    Hi, I am trying to understand what is IAsyncresult good and therefore I wrote this code. The problem is it behaves as I called "MetodaAsync" normal way. While debugging, the program stops here until the method completed. Any help appreciated, thank you. using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Threading; namespace ConsoleApplication1 { class Program { delegate int Delegat(); static void Main(string[] args) { Program p=new Program(); Delegat d = new Delegat(p.MetodaAsync); IAsyncResult a = d.BeginInvoke(null, null); //I have removed callback int returned=d.EndInvoke(a); Console.WriteLine("AAA"); } private int MetodaAsync() { int AC=0; for (int I = 0; I < 600000; I++) { for (int A = 0; A < 6000000; A++) { } Console.Write("B"); } return AC; } } }

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  • ASP.net page gets error on import statement, but I do have the reference in place?

    - by Greg
    Hi, Any ideas why I am getting the below error in my MVC2 project, even through in the project itself I definitely have a reference to "system.Web.Entity"? Compiler Error Message: CS0234: The type or namespace name 'Entity' does not exist in the namespace 'System.Data' (are you missing an assembly reference?) Source Error: Line 1: <%@ Page Language="C#" Inherits="System.Web.Mvc.ViewPage<List<Node>>" %> Line 2: <%@ Import Namespace="TopologyDAL" %> Line 3: <%@ Import Namespace="System.Data.Entity" %> thanks

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  • Deserialization on client side in Domain Service

    - by ankit
    I have 2 classes: Person and Contact. Person class has a property named ContactNumber which returns the Contact type, and this property is marked as a DataMember for serialization. I have marked Contact type as a DataContract. On the client side I am able to get the values, but when I try to insert a value and then do submit, I get the following exception: Failed to deserialize change-set. Failed to convert value of type 'Dictionary`2' to type 'Contact' Stack Trace is: at System.Web.Ria.DataServiceSubmitRequest.GetChangeSet(DomainService domainService) at System.Web.Ria.DataServiceSubmitRequest.Invoke(DomainService domainService) at System.Web.Ria.DataService.System.Web.IHttpHandler.ProcessRequest(HttpContext context) Can anyone give me the solution ?

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  • Broken console in Maven project using Netbeans

    - by Maciek Sawicki
    Hi, I have strange problem with my Neatens+Maven installation. This is the shortest code to reproduce the problem: public class App { public static void main( String[] args ) { // Create a scanner to read from keyboard Scanner scanner = new Scanner (System.in); Scanner s= new Scanner(System.in); String param= s.next(); System.out.println(param); } } When I'm running it as Maven Project inside Netbeans console seems to be broken. It just ignores my input. It's look like infinitive loop in System.out.println(param);. However this project works fine when it's compiled as "Java Aplication" project. It also works O.K. if I build and run it from cmd. System info: Os: Vista IDE: Netbeans 6.8 Maven: apache-maven-2.2.1 //edit Built program (using mavean from Netbeans) works fine. I just can't test it using Net beans. And I think I forgot to ask the question ;). So of course my first question is: how can I fix this problem? And second is: Is it any workaround for this? For example configuring Netbeans to run external commend line app instead of using built in console.

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  • Is it OK to pass SQLCommand as a parameter?

    - by TooFat
    I have a Business Layer that passes a Conn string and a SQLCommand to a Data Layer like so public void PopulateLocalData() { System.Data.SqlClient.SqlCommand cmd = new System.Data.SqlClient.SqlCommand(); cmd.CommandType = System.Data.CommandType.StoredProcedure; cmd.CommandText = "usp_PopulateServiceSurveyLocal"; DataLayer.DataProvider.ExecSQL(ConnString, cmd); } The DataLayer then just executes the sql like so public static int ExecSQL(string sqlConnString, System.Data.SqlClient.SqlCommand cmd) { int rowsAffected; using (SqlConnection conn = new SqlConnection(sqlConnString)) { conn.Open(); cmd.Connection = conn; rowsAffected = cmd.ExecuteNonQuery(); cmd.Dispose(); } return rowsAffected; } Is it OK for me to pass the SQLCommand as a parameter like this or is there a better more accepted way of doing it. One of my concerns is if an error occurs when executing the query the cmd.dispose line will never execute. Does that mean it will continue to use up memory that will never be released?

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  • Matlab help: I am given a second order differential equation.I need to use matlab to find unit step response and impulse response?

    - by Cady Smith
    I have the second order differential equation d^2(y(t))/dt^2+ B1*d(y(t))/dt+ c1*y(t)=A1*x(t) t is in seconds and is greater than 0. A1, B1, C1 are constants that equal: A1= 3.8469x10^6 B1= 325.6907 C1= 3.8469x10^6 This system is linear, time-invariant, and casual. The system is called H1. I want to use Matlab to compute and plot the impulse response function h1(t) and the unit step response function g1(t) of this system.

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  • How to encrypt information in aspx page?

    - by Jimmyc
    Hi all, I know it's a silly question but , My client asked for encrypting some information form their payment system to prevent user stealing personal information. The system is web-base and written by ASP.NET We have tried some annoying solution such as JavaScript no right-click or css-no-print but apparently my client didn't like it. so are there any commercial solution to encrypt information in aspx produced html pages? or someone can tell me how to pursuit my client to stop these "prevent stealing" idea in a web-base system?

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  • Upgrading website from VS2005(2.0 Framework) to VS2008(2.0 Framework)

    - by Sravan
    We have a website that is created in VS2005 Recently we upgraded the website to VS2008 with 2.0 framework. While compiling the website Compilation errors are occuring i.e Licenses.licx file is not compiling, if it compile than it will reproduces an AppLicenses.dll. In the licensing.licx file containing one class and a namespace(i.e. OSADirectLicensing.OSADirectLicensedClass, OSADirectLicensing). The compilation error is as follows: Error 1 C:\Program Files\Sharp\Sharp Developer Tools\OSA SDK\Samples\DirectOSA\ExternalAuthority\licenses.licx: Could not transform licenses file into a binary resource. (1) : error LC0004 : Exception occurred creating type 'OSADirectLicensing.OSADirectLicensedClass, OSADirectLicensing, Version=1.0.4006.31768, Culture=neutral, PublicKeyToken=null System.ComponentModel.LicenseException: Invalid License at System.ComponentModel.LicenseManager.CreateWithContext(Type type, LicenseContext creationContext, Object[] args) at System.ComponentModel.LicenseManager.CreateWithContext(Type type, LicenseContext creationContext) at System.Tools.LicenseCompiler.GenerateLicenses(String fileContents, String targetPE, ITypeResolutionService resolver, DesigntimeLicenseContext ctx)' . Does VS2008 support licenses.licx or not? We should not remove this file from website. How can we solve this issue?

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  • 'Locale' configuration and its relationship with Windows API

    - by The Kaykay
    Can the locale configuration of a system OR the keyboard type configuration of that system in anyway affect which API is called at the Kernel level? To be specific, if a program is invoking 'CreateFile()' API then the windows API documentation says that the call gets delegated to either CreateFileA or CreateFileW. If that program is being run on a system present in China with a Chinese Keyboard then which of the two functions will be called?

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  • why Cannot invoke super constructor from enum constructor ?

    - by hilal
    public enum A { A(1); private A(int i){ } private A(){ super(); // compile - error // Cannot invoke super constructor from enum constructor A() } } and here is the hierarchy of enum A extends from abstract java.lang.Enum extends java.lang.Object Class c = Class.forName("/*path*/.A"); System.out.println(c.getSuperclass().getName()); System.out.println(Modifier.toString(c.getSuperclass().getModifiers()).contains("abstract")); System.out.println(c.getSuperclass().getSuperclass().getName());

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