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  • again new query. i am trying to solve this from one hour. please help

    - by Dharmendra
    Query : List the film title and the leading actor for all of 'Julie Andrews' films. there are three tables : movie(id, title, yr, score, votes, director) actor(id, name) casting(movieid, actorid, ord) select movie.title,actor.name as cont from movie join casting on (movie.id=casting.movieid) join actor on (casting.actorid=actor.id) where actor.name='Julie andrews' actually i can' get how to find the leading actor.

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  • i demand you all men to help

    - by Hello you all men
    you all men i demand answer, you say not real question?? many page get big load for long time and now we are suspended and http://stackoverflow.com/questions/2890840/how-can-we-make-our-website-scalable and please you help men very sorry -bern

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  • How to display external database data in VBulletin 4 Forums Custom PHP Block?

    - by NJTechGuy
    Hi guys! I want to display data feed from an external database in a sidebar in the forums section. PHP Block Code : $host = 'db.123.net'; $dbUser = 'db49'; $dbPass = 'iReVbY'; $db = 'db6578h8'; mysql_connect("$host", "$dbUser", "$dbPass") or die(mysql_error()); mysql_select_db("$db") or die(mysql_error()); ob_start(); $result = mysql_query("SELECT id, title from abc") or die(mysql_error()); while($row = mysql_fetch_array( $result )) { print"<center>"; print "<a href=\"http://abc.com/?id=" . $row['id'] . "\"></a>"; print "</center>"; } $output .= ob_get_contents(); return $output; ob_end_clean(); How do I return an array to display in a PHP block in the sidebar (forums section)? Please help me out of this! Thank you..

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  • How can "set timestamp" be a slow query?

    - by Peder
    My slow query log is full of entries like the following # Query_time: 1.016361 Lock_time: 0.000000 Rows_sent: 0 Rows_examined: 0 SET timestamp=1273826821; COMMIT; I guess the set timestamp command is issued by replication but I don't understand how set timestamp can take over a second. Any ideas?

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  • Access 2007 file picker, replaces all rows with the same choice.

    - by SqlStruggle
    This code is from an Access 2007 project I've been struggling with. The actual mean part is the part where I should put something like "update only current form" DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Could someone please help me with this?` If I use it now, it updates all the tables with the same file picked. Heres the whole code. ' This requires a reference to the Microsoft Office 11.0 Object Library. Dim fDialog As Office.FileDialog Dim varFile As Variant Dim filePath As String ' Set up the File dialog box. Set fDialog = Application.FileDialog(msoFileDialogFilePicker) With fDialog ' Allow the user to make multiple selections in the dialog box. .AllowMultiSelect = False ' Set the title of the dialog box. .Title = "Valitse Tiedosto" ' Clear out the current filters, and then add your own. .Filters.Clear .Filters.Add "All Files", "*.*" ' user picked at least one file. If the .Show method returns ' False, the user clicked Cancel. If .Show = True Then ' Loop through each file that is selected and then add it to the list box. For Each varFile In .SelectedItems DoCmd.SetWarnings True DoCmd.RunSQL "Update Korut Set [PikkuKuva]=('" & varFile & "') ;" Next Else MsgBox "You clicked Cancel in the file dialog box." End If End With

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  • How to write stored procedures to separate files with mysqldump?

    - by Jader Dias
    The mysqldump option --tab=path writes the creation script of each table in a separate file. But I can't find the stored procedures, except in the screen dump. I need to have the stored procedures also in separate files. The current solution I am working on is to split the screen dump programatically. Is there a easier way? The code I am using so far is: mysqldump -p$PASSWORD --routines --skip-dump-date --no-create-info --no-data --skip-opt $DATABASE > $BACKUP_PATH/$DATABASE.sql mysqldump -p$PASSWORD --tab=$BACKUP_PATH --skip-dump-date --no-data --skip-opt $DATABASE

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  • SQL Count Query with Grouping by multiple Columns

    - by Christian
    I have a table with three filled columns named "Name", "City" and "Occupation". I want to create a new column in the same table that contains the number of people who have the same occupation. "Name" | "City" | "Occupation" ------------------------------ Amy | Berlin | Plumber Bob | Berlin | Plumber Carol | Berlin | Lawyer David | London | Plumber I want to have a table that contains: "Name" | "City" | "Occupation" | "Number" --------------------------------------- Amy | Berlin | Plumber | 2 Bob | Berlin | Plumber | 2 Carol | Berlin | Lawyer | 1 David | London | Plumber | 1 How does the SQL Query that creates the new columns have to look like? I want to actually create a new column in the database that I can access later.

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  • Error when trying to use PDO object

    - by Nate
    EDIT: I'm going to put my code in here due to comments below. So sit tight for a few minutes ;-) Thanks! I'm an inexperienced php programmer and only found out about PDO a few days ago. I'm now trying to port my website code over to using PDO, but I am getting an error when I try to use the PDO object that I create. I'm using a CMS on my website, and it makes building page output kind of complicated, but I've tried to draw the structure of what is being called below: index.php -class myClass defined --method myFunction defined (it gets called on pageload & returns the page output) ---include file1.php ----require_once('mysql_connect.php') (creates pdo object) ----*I can use the pdo object here successfully* ----require_once('file2.php') -----require_once('mysql_connect.php') -----function myFunction2 defined ------*trying to use the pdo object here results in the error* The error I'm getting is: Fatal error: Call to a member function prepare() on a non-object in /home/rgcpanel/public_html/account/account_functions.php on line 147 Any idea what's going on?

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  • How can I protect this code from SQL Injection? A bit confused.

    - by Craig Whitley
    I've read various sources but I'm unsure how to implement them into my code. I was wondering if somebody could give me a quick hand with it? Once I've been shown how to do it once in my code I'll be able to pick it up I think! This is from an AJAX autocomplete I found on the net, although I saw something to do with it being vulnerable to SQL Injection due to the '%$queryString%' or something? Any help really appreciated! if ( isset( $_POST['queryString'] ) ) { $queryString = $_POST['queryString']; if ( strlen( $queryString ) > 0 ) { $query = "SELECT game_title, game_id FROM games WHERE game_title LIKE '%$queryString%' || alt LIKE '%$queryString%' LIMIT 10"; $result = mysql_query( $query, $db ) or die( "There is an error in database please contact [email protected]" ); while ( $row = mysql_fetch_array( $result ) ) { $game_id = $row['game_id']; echo '<li onClick="fill(\'' . $row['game_title'] . '\',' . $game_id . ');">' . $row['game_title'] . '</li>'; } } }

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  • Why does my Doctrine DBAL query return no results when quoted?

    - by braveterry
    I'm using the Doctrine DataBase Abstraction Layer (DBAL) to perform some queries. For some reason, when I quote a parameter before passing it to the query, I get back no rows. When I pass it unquoted, it works fine. Here's the relevant snippet of code I'm using: public function get($game) { load::helper('doctrinehelper'); $conn = doctrinehelper::getconnection(); $statement = $conn->prepare('SELECT games.id as id, games.name as name, games.link_url, games.link_text, services.name as service_name, image_url FROM games, services WHERE games.name = ? AND services.key = games.service_key'); $quotedGame = $conn->quote($game); load::helper('loghelper'); $logger = loghelper::getLogger(); $logger->debug("Quoted Game: $quotedGame"); $logger->debug("Unquoted Game: $game"); $statement->execute(array($quotedGame)); $resultsArray = $statement->fetchAll(); $logger->debug("Number of rows returned: " . count($resultsArray)); return $resultsArray; } Here's what the log shows: 01/01/11 17:00:13,269 [2112] DEBUG root - Quoted Game: 'Diablo II Lord of Destruction' 01/01/11 17:00:13,269 [2112] DEBUG root - Unquoted Game: Diablo II Lord of Destruction 01/01/11 17:00:13,270 [2112] DEBUG root - Number of rows returned: 0 If I change this line: $statement->execute(array($quotedGame)); to this: $statement->execute(array($game)); I get this in the log: 01/01/11 16:51:42,934 [2112] DEBUG root - Quoted Game: 'Diablo II Lord of Destruction' 01/01/11 16:51:42,935 [2112] DEBUG root - Unquoted Game: Diablo II Lord of Destruction 01/01/11 16:51:42,936 [2112] DEBUG root - Number of rows returned: 1 Have I fat-fingered something?

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  • Cast integer to real

    - by Dave Jarvis
    Question How do you cast an INTEGER value as a REAL value? Attempts CAST( Y.YEAR AS REAL), but that failed (the documentation indicates you cannot CAST or CONVERT values to REALs. Y.YEAR + 0.0, but that failed, too. Error Message Using udf_slope fails due to: Can't initialize function 'slope'; slope() requires a real as parameter 2 Code SELECT D.AMOUNT, Y.YEAR, slope(D.AMOUNT, Y.YEAR + 0.0) as SLOPE, intercept(D.AMOUNT, Y.YEAR + 0.0) as INTERCEPT FROM YEAR_REF Y, DAILY D Here, D.AMOUNT is a FLOAT and Y.YEAR is an INTEGER. Thank you!

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  • Should I include user_id in multiple tables?

    - by Drarok
    I'm at the planning stages of a multi-user application where each user will only have access their own data. There'll be a few tables that relate to each other, so I could use JOINs to ensure they're accessing only their data, but should I include user_id in each table? Would this be faster? It would certainly make some of the queries easier in the long run. Thanks!

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  • SQL joining 3 tables when 1 table is emty

    - by AdRock
    I am trying to write a query that connects 3 tables. The first table is info about each festival The second table is the number of votes for each festival The third table is reviews for each festival I want to join all 3 tables so i get all the feilds from table1, join table1 with table2 on the festivalid but i also need to count the number of records in table 3 that applys to each festival. The first 2 tables give me a result becuase they both have data in them but table 3 is empty becuase there are no reviews yet so adding that to my query fives me no results SELECT f.*, v.total, v.votes, v.festivalid, r.reviewcount as count FROM festivals f INNER JOIN vote v ON f.festivalid = v.festivalid INNER JOIN (SELECT festivalid, count(*) as reviewcount FROM reviews) GROUP BY festivalid) as r on r.festivalid = v.festivalid

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  • Make A HTML/PHP Link

    - by Will Evans
    I have the code below: $result = mysql_query("SELECT link, notes FROM links WHERE username='will';"); $html .= "<ul>"; while ($row = mysql_fetch_array($result)) { //loop extract($row); $html .= "<li>{$link} - {$notes}</li>"; } I need the bit where it says {$link} to become a clickable link which opens a new window. How would I do this? When I put tags around it you get this error: The error is: Parse error: syntax error, unexpected '{' in /data/www/vhosts/themacsplash.com/httpdocs/ClipBoy/will.php on line 18 Line 18 is $html .= "{$link} - {$notes}";

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  • Search 2 Columns with 1 Input Field

    - by Norbert
    I have a db with two columns: first name and last name. The first name can have multiple words. Last name can contain hyphenated words. Is there a way to search both columns with only one input box? Database ID `First Name` `Last Name` 1 John Peter Doe 2 John Fubar 3 Michael Doe Search john peter returns id 1 john returns id 1,2 doe returns id 1,3 john doe returns id 1 peter john returns id 1 peter doe returns id 1 doe john returns id 1 I previously tried the following. Searching for John Doe: SELECT * FROM names WHERE ( `first` LIKE '%john%' OR `first` LIKE '%doe%' OR `last` LIKE '%john%' OR `last` LIKE '%doe%' ) which returns both 1 and 3

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  • Webmail system script

    - by panidarapu
    Hello, I am planning to launch a free webmail service at mail(dot)com(dot)es where users can signup and have their free webmail account (for example like www.email.gr). I am looking for a free or low cost webmail system script to install on my website. Do you know any free or low cost scripts which would be suitable for this? Thanks

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  • Minimizing SQL queries using join with one-to-many relationship

    - by Brian
    So let me preface this by saying that I'm not an SQL wizard by any means. What I want to do is simple as a concept, but has presented me with a small challenge when trying to minimize the amount of database queries I'm performing. Let's say I have a table of departments. Within each department is a list of employees. What is the most efficient way of listing all the departments and which employees are in each department. So for example if I have a department table with: id name 1 sales 2 marketing And a people table with: id department_id name 1 1 Tom 2 1 Bill 3 2 Jessica 4 1 Rachel 5 2 John What is the best way list all departments and all employees for each department like so: Sales Tom Bill Rachel Marketing Jessica John Pretend both tables are actually massive. (I want to avoid getting a list of departments, and then looping through the result and doing an individual query for each department). Think similarly of selecting the statuses/comments in a Facebook-like system, when statuses and comments are stored in separate tables.

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  • ZIP Numerous Blob Files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include 'config.php'; include 'connect.php'; $session= $_GET[session]; $query = " SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session= '$session'"; $result = mysql_query($query) or die('Error, query failed'); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { header("Content-length: $size"); header("Content-type: $type"); header("Content-Disposition: inline; filename=$username-$description.pdf"); echo $content; } $files = array('File 1 from database', 'File 2 from database'); $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); mysql_close($link); exit; ?>

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  • Rails Unit Testing with MyISAM Tables

    - by tadman
    I've got an application that requires the use of MyISAM on a few tables, but the rest are the traditional InnoDB type. The application itself is not concerned with transactions where it applies to these records, but performance is a concern. The Rails testing environment assumes the engine used is transactional, though, so when the test database is generated from the schema.rb it is imported with the same engine. Is it possible to over-ride this behaviour in a simple manner? I've resorted to an awful hack to ensure the tables are the correct type by appending this to test_helper.rb: (ActiveRecord::Base.connection.select_values("SHOW TABLES") - %w[ schema_info ]).each do |table_name| ActiveRecord::Base.connection.execute("ALTER TABLE `#{table_name}` ENGINE=InnoDB") end Is there a better way to make a MyISAM-backed model be testable?

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  • I need help with creating a data structure in PHP

    - by alex
    What I need to do is have a data structure that shows jobs organised into 14 day periods, but only when an id is the same. I've implemented all sorts of stuff, but they have failed miserably. Ideally, maybe a SQL expert could handle all of this in the query. Here is some of my code. You can assume all library stuff works as expected. $query = 'SELECT date, rig_id, comments FROM dor ORDER BY date DESC'; $dors = Db::query(Database::SELECT, $query)->execute()->as_array(); This will return all jobs, but I need to have them organised by 14 day period with the same rig_id value. $hitches = array(); foreach($dors as $dor) { $rigId = $dor['rig_id']; $date = strtotime($dor['date']); if (empty($hitches)) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } else { $found = false; foreach($hitches as $key => $hitch) { $hitchStartDate = $hitch['startDate']; $dateDifference = abs($hitchStartDate - $date); $isSameHitchTimeFrame = $dateDifference < (Date::DAY * 14); if ($rigId == $hitch['rigId'] AND $isSameHitchTimeFrame) { $found = true; $hitches[$key]['dors'][] = $dor; } } if ($found === false) { $hitches[] = array( 'rigId' => $rigId, 'startDate' => $date, 'dors' => array($dor) ); } } } This seems to work OK splitting up by rig_id, but not by date. I also think I'm doing it wrong because I need to check the earliest date. Is it possible at all to do any of this in the database query? To recap, here is my problem I have a list of jobs with all have a rig_id (many jobs can have the same) and a date. I need the data to be organised into hitches. That is, the rig_id must be the same per hitch, and they must span a 14 day period, in which the next 14 days with the same rig_id will be a new hitch. Can someone please point me on the right track? Cheers

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  • Help with query

    - by hdoe123
    Hi, I'm trying make a query that looks at a single table and looks to see if a student is a team called CMHT and in a medic team - if they are I don't want to see the result. I only want see if there only in CMHT or medic not both. Would the right direction be using sub query to filer it out? I've done a search on NOT IN but how could you get to see check if its in more then 2 teams are not? Student Team ref 1 CMHT 1 1 Medic 2 2 Medic 3 this would be in the result 3 CMHT 5 this would be in the result So far I've done the following code would I need use a sub query or do a self join and filter it that way? SELECT Table1.Student, Table1.Team, Table1.refnumber FROM Table1 WHERE (((Table1.Team) In ('Medics','CMHT'))

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  • [PHP] Associate different data

    - by Alex Cane
    I will try to be as clear as possible because I can't get anybody to help me around, I am trying to associate some data from a 'videos' table with their respective ID. Lets say, I have column ID, title, serie, season, episode. I am getting my data : <? $result = mysql_query("SELECT * FROM videos WHERE serie = '".$row['serie']."' AND season = '".$row['season']."'"); $total_rows = mysql_num_rows($result); ?> (that is in the page where you see the video itself) So now I can get the number of episodes from a serie and season. What I'm trying to do is have a link for the next episode, and aa link for the previous one. In the URL I am working with the id, so http://website.com/view/id/'video id here'/ So how can I get the ID of the following and previous episodes of the same season AND serie? Help will be much appreciated! The easiest thing I thought of is <?=$row['id'] + 1?> <?=$row['id'] - 1?> But the thing is that it's mixed videos, so it wont work 100%

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  • Select a random row from table, but with odds?

    - by Don
    I have a table that describes a variety of objects in my system (ie. umbrella, boots, satchel, whatever). Each one of these objects needs to have a distinct prevalence or incidence. For example, the umbrella is rarer than the boots. Based on those factors, I need to randomly select a single object (including a blank or 'no object found') based on that incidence value. Yikes. Make sense?

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