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  • What can I send back to the browser while I wait for PHP execution?

    - by Matt Malesky
    So....I have a PHP page that involves a lot of backend execution, namely 'exec' calls to run shell commands on the host server. This can take upwards of a few minutes depending on the calls involved. (If you look below, each recursion through the exec calls is mounting a LUN; I'd like to sometimes do upwards of 100 per execution.) I'm curious on what I can do to send content back to the browser (and prevent it from timing out). <!DOCTYPE html> <html> <head> <title>sfvmtk</title> </head> <body> <?php // TEMPORARY VARIABLES FOR TESTING $hba = 'vmhba38'; $svip = '10.10.20.100'; $targets = array ( 0 => array ( 'iqn' => 'iqn.2010-01.com.sf:t5np.esxtest.41', 'account' => 'esx', 'isecret' => 'isecret00000', 'tsecret' => 'tsecret00000' ), 1 => array ( 'iqn' => 'iqn.2010-01.com.sf:t5np.esxtest2.42', 'account' => 'esx2', 'isecret' => 'isecret00001', 'tsecret' => 'tsecret00001' ) ); $hostname = $_REQUEST['hostname']; $username = $_REQUEST['username']; $password = $_REQUEST['password']; foreach ($targets as $ctarget) { exec('esxcli -s '.$hostname.' -u '.$username.' -p '.$password.' iscsi adapter discovery statictarget add -A '.$hba.' -a '.$svip.' -n '.$ctarget['iqn'], $out); exec('esxcli -s '.$hostname.' -u '.$username.' -p '.$password.' iscsi adapter target portal auth chap set -A '.$hba.' -a '.$svip.' -N '.$ctarget['account'].' -d uni -l required -n '.$ctarget['iqn'].' -S '.$ctarget['isecret'], $out); exec('esxcli -s '.$hostname.' -u '.$username.' -p '.$password.' iscsi adapter target portal auth chap set -A '.$hba.' -a '.$svip.' -N '.$ctarget['account'].' -d mutual -l required -n '.$ctarget['iqn'].' -S '.$ctarget['tsecret'], $out); } exec('vicfg-rescan --server '.$hostname.' --username '.$username.' --password '.$password.' '.$hba, $out); ?> </body> </html>

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  • Getting a new session key after Facebook offline_access permission

    - by Richard
    I have a mobile application that I'm using with Facebook connect. I'm having trouble getting an offline_access session key after a user has granted extended permissions. Here's the user flow: User goes to my site for the first time I send them to m.facebook.com/tos.php? and pass my api key and secret The user logs in using Facebook connect Facebook returns them to a page in my site, mysite/login-success.php with an auth_token in the query string On mysite/login-success.php I instantiate the FB api client and check to see if I already have an offline_access session key for them: $facebook = new Facebook($appapikey, $appsecret); If they haven't already provided offline_access FB gives me a temporary session key I need to get offline_access permission from the user so I forward them on to www.facebook.com/connect/prompt_permissions.php? and pass offline_access in the querystring. The user authorizes offline_access and get forwarded to mysite/permissions-success.php The problem I'm having is that after instantiating the API client on permissions-success.php the session key I have is still the temporary session key, not a new offline_access session key. The only way I've found to get the offline_access key is to delete all cookies for the user and then have them login again using Facebook connect. A fairly poor user experience. Can anyone shed some light on how to use the Facebook api to generate a new session key even if one already exists (in my case a temporary session key)?

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  • Something is making my page perform an Ajax call multiple times... [read: I've never been more frust

    - by Jack Webb-Heller
    NOTE: This is a long question. I've explained all the 'basics' at the top and then there's some further (optional) information for if you need it. Hi folks Basically last night this started happening at about 9PM whilst I was trying to restructure my code to make it a bit nicer for the designer to add a few bits to. I tried to fix it until 2AM at which point I gave up. Came back to it this morning, still baffled. I'll be honest with you, I'm a pretty bad Javascript developer. Since starting this project Javascript has been completely new to me and I've just learn as I went along. So please forgive me if my code structure is really bad (perhaps give a couple of pointers on how to improve it?). So, to the problem: to reproduce it, visit http://furnace.howcode.com (it's far from complete). This problem is a little confusing but I'd really appreciate the help. So in the second column you'll see three tabs The 'Newest' tab is selected by default. Scroll to the bottom, and 3 further results should be dynamically fetched via Ajax. Now click on the 'Top Rated' tab. You'll see all the results, but ordered by rating Scroll to the bottom of 'Top Rated'. You'll see SIX results returned. This is where it goes wrong. Only a further three should be returned (there are 18 entries in total). If you're observant you'll notice two 'blocks' of 3 returned. The first 'block' is the second page of results from the 'Newest' tab. The second block is what I just want returned. Did that make any sense? Never mind! So basically I checked this out in Firebug. What happens is, from a 'Clean' page (first load, nothing done) it calls ONE POST request to http://furnace.howcode.com/code/loadmore . But every time you load a new one of the tabs, it makes an ADDITIONAL POST request each time where there should normally only be ONE. So, can you help me? I'd really appreciate it! At this point you could start independent investigation or read on for a little further (optional) information. Thanks! Jack Further Info (may be irrelevant but here for reference): It's almost like there's some Javascript code or something being left behind that duplicates it each time. I thought it might be this code that I use to detect when the browser is scrolled to the bottom: var col = $('#col2'); col.scroll(function(){ if (col.outerHeight() == (col.get(0).scrollHeight - col.scrollTop())) loadMore(1); }); So what I thought was that code was left behind, and so every time you scroll #col2 (which contains different data for each tab) it detected that and added it for #newest as well. So, I made each tab click give #col2 a dynamic class - either .newestcol, .featuredcol, or .topratedcol. And then I changed the var col=$('.newestcol');dynamically so it would only detect it individually for each tab (makin' any sense?!). But hey, that didn't do anything. Another useful tidbit: here's the PHP for http://furnace.howcode.com/code/loadmore: $kind = $this->input->post('kind'); if ($kind == 1){ // kind is 1 - newest $start = $this->input->post('currentpage'); $data['query'] = "SELECT code.id AS codeid, code.title AS codetitle, code.summary AS codesummary, code.author AS codeauthor, code.rating AS rating, code.date, code_tags.*, tags.*, users.firstname AS authorname, users.id AS authorid, GROUP_CONCAT(tags.tag SEPARATOR ', ') AS taggroup FROM code, code_tags, tags, users WHERE users.id = code.author AND code_tags.code_id = code.id AND tags.id = code_tags.tag_id GROUP BY code_id ORDER BY date DESC LIMIT $start, 15 "; $this->load->view('code/ajaxlist',$data); } elseif ($kind == 2) { // kind is 2 - featured So my jQuery code sends a variable 'kind'. If it's 1, it runs the query for Newest, etc. etc. The PHP code for furnace.howcode.com/code/ajaxlist is: <?php // Our query base // SELECT * FROM code ORDER BY date DESC $query = $this->db->query($query); foreach($query->result() as $row) { ?> <script type="text/javascript"> $('#title-<?php echo $row->codeid;?>').click(function() { var form_data = { id: <?php echo $row->codeid; ?> }; $('#col3').fadeOut('slow', function() { $.ajax({ url: "<?php echo site_url('code/viewajax');?>", type: 'POST', data: form_data, success: function(msg) { $('#col3').html(msg); $('#col3').fadeIn('fast'); } }); }); }); </script> <div class="result"> <div class="resulttext"> <div id="title-<?php echo $row->codeid; ?>" class="title"> <?php echo anchor('#',$row->codetitle); ?> </div> <div class="summary"> <?php echo $row->codesummary; ?> </div> <!-- Now insert the 5-star rating system --> <?php include($_SERVER['DOCUMENT_ROOT']."/fivestars/5star.php");?> <div class="bottom"> <div class="author"> Submitted by <?php echo anchor('auth/profile/'.$row->authorid,''.$row->authorname);?> </div> <?php // Now we need to take the GROUP_CONCATted tags and split them using the magic of PHP into seperate tags $tagarray = explode(", ", $row->taggroup); foreach ($tagarray as $tag) { ?> <div class="tagbutton" href="#"> <span><?php echo $tag; ?></span> </div> <?php } ?> </div> </div> </div> <?php } echo "&nbsp;";?> <script type="text/javascript"> var newpage = <?php echo $this->input->post('currentpage') + 15;?>; </script> So that's everything in PHP. The rest you should be able to view with Firebug or by viewing the Source code. I've put all the Tab/clicking/Ajaxloading bits in the tags at the very bottom. There's a comment before it all kicks off. Thanks so much for your help!

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  • Getting a users Facebook profile url

    - by Greg Pabst
    I am creating a registry site so similar people can find each other easily. I don't want to use Facebook Connect as the primary log in method or use Facebook to store their information. I'll be creating a database on my end to store that info. For security reasons I won't be displaying the users address, phone number or email address so I wanted to provide the next best way for people to connect with each other, this is where Facebook comes in. Normally I would just ask them to type their Facebook URL in a text box but I don't think most people know what their url is which is why I think I need to use Facebook Connect. So here is my idea..when the users signs up there is a check box that when checked signifies they are allowing people to find them on Facebook. I assume once they click the register button that a Facebook Connect popup will show up asking for permission to access their Facebook account. When they "allow" it, then I can get their profile url. All I need is their Facebook profile url, I don't want any other Facebook features or information. Is Facebook Connect the best thing to use for this scenario? Is there an easier way? Several months ago on the Facebook Connect site their used to be examples of doing this, but all the documentation has been rearranged and changed and I can't seem to find the information. Any help you can provide would be great!

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  • Facebook JS API: users_getInfo() inside ifUserConnected() deadlock.

    - by serg555
    I am trying to put Facebook connect button on the site and once connected display connected username. But for some reason following code goes into some infinite loop during first connection, and then works fine unless I delete this app from my facebook profile which causes freezing again. Here is a code on FB connect button click: FB.Connect.requireSession(); Here is code directly on the page: <script src="http://static.ak.connect.facebook.com/js/api_lib/v0.4/FeatureLoader.js.php/en_US" type="text/javascript"></script> <script type="text/javascript"> FB.init("123", "/xd_receiver.htm"); FB.ensureInit(function() { FB.Connect.ifUserConnected(function() { FB.Facebook.apiClient.users_getInfo(new Array(FB.Connect.get_loggedInUser()),new Array("name"), function(user, exec) { console.log("logged in:"+user[0].name); }); }, function(){ console.log("guest"); }); }); </script> If I remove FB.Facebook.apiClient.users_getInfo() it works fine, but I need to get username somehow. Any tips? Thanks.

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  • How can I make this script output each categories item per category [closed]

    - by Duice352
    Ok so here is the deal currently this script outputs all the products in a parent category as well as the products in the child categories. What i would like to do is seperate the output based on child categories. All the child categories are in the array $children and the string $childs. The parent category is the first array element of $children with the following ones being the actual children. The category names are stored in the database $result as " $cat_name ". I want to first Display the cat_name then the products that fall in that category and then display the next child cat_name and items, ect. Any suggestions of how to manipulate the while loop that cylcles through the rows? <?php $productsPerRow = 3; $productsPerPage = 15; //$productList = getProductList($catId); $children = array_merge(array($catId), getChildCategories(NULL, $catId)); $childs = ' (' . implode(', ', $children) . ')'; $sql = "SELECT pd_id, pd_name, pd_price, pd_thumbnail, pd_qty, c.cat_id, c.cat_name FROM tbl_product pd, tbl_category c WHERE pd.cat_id = c.cat_id AND pd.cat_id IN $childs ORDER BY pd_name"; $result = dbQuery(getPagingQuery($sql, $productsPerPage)); $pagingLink = getPagingLink($sql, $productsPerPage, "c=$catId"); $numProduct = dbNumRows($result); // the product images are arranged in a table. to make sure // each image gets equal space set the cell width here $columnWidth = (int)(100 / $productsPerRow); ?> <p><?php if(isset($_GET['m'])){echo "You must select a model first! After you select your model you can customize your dragster parts.";} ?> </p> <p align="center"><?php echo $pagingLink; ?></p> <table width="100%" border="0" cellspacing="0" cellpadding="20"> <?php if ($numProduct > 0 ) { $i = 0; while ($row = dbFetchAssoc($result)) { extract($row); if ($pd_thumbnail) { $pd_thumbnail = WEB_ROOT . 'images/product/' .$pd_thumbnail; } else { $pd_thumbnail = 'images/no-image-small.png'; } if ($i % $productsPerRow == 0) { echo '<tr>'; } // format how we display the price $pd_price = displayAmount($pd_price); echo "<td width=\"$columnWidth%\" align=\"center\"><a href=\"" . $_SERVER['PHP_SELF'] . "?c=$catId&p=$pd_id" . "\"><img src=\"$pd_thumbnail\" border=\"0\"><br>$pd_name</a><br>Price : $pd_price <br> $cat_id - $cat_name"; // if the product is no longer in stock, tell the customer if ($pd_qty <= 0) { echo "<br>Out Of Stock"; } echo "</td>\r\n"; if ($i % $productsPerRow == $productsPerRow - 1) { echo '</tr>'; } $i += 1; } if ($i % $productsPerRow > 0) { echo '<td colspan="' . ($productsPerRow - ($i % $productsPerRow)) . '">&nbsp;</td>'; }

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  • PHP Form: After getting results adding a new table row when entering new information.

    - by Chris
    Hello, Although probarly quite simple, i cannot seem to find the following. The form takes certain data, and then represents the data in a table. Next step i click the hyperlink that takes me back to the form. Now my question is how exactly do i make it possible when filling in the same form again so both results are displayed in the same table? Then filling in a other form with data adds another row and so on. Regards. The code below (pardon me that it is not english). <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoFormulier</title> <body> <?php if (!empty($_POST)) { $standnaam = $_POST["standnaam"]; $oppervlakte = $_POST["oppervlakte"]; //value in the form van checkboxes op 1 zetten! $verdieping = isset($_POST["verdieping"]) ? $_POST["verdieping"] : 0; //if checkbox checked value 1 anders 0 $telefoon = isset($_POST["telefoon"]) ? $_POST["telefoon"] : 0; $netwerk = isset($_POST["netwerk"]) ? $_POST["netwerk"] : 0; if (is_numeric($oppervlakte)) { $_SESSION["standnaam"]=$standnaam; $_SESSION["oppervlakte"]=$oppervlakte; $_SESSION["verdieping"]=$verdieping; $_SESSION["telefoon"]=$telefoon; $_SESSION["netwerk"]=$netwerk; header("Location:ExpoOverzicht.php"); //verzenden naar ExpoOverzicht.php dmv header } else { echo "<h1>Foute gegevens, Opnieuw invullen a.u.b</h1>"; } } ?> <form action="<?php echo $_SERVER["PHP_SELF"]; ?>" method="post" id="form1"> <h1>Vul de gegevens in</h1> <table> <tr> <td>Standnaam:</td> <td><input type="text" name="standnaam" size="18"/></td> </tr> <tr> <td>Oppervlakte (in m^2):</td> <td><input type="text" name="oppervlakte" size="6"/></td> </tr> <tr> <td>Verdieping:</td> <td><input type="checkbox" name="verdieping" value="1"/></td> <!--value op 1 zetten voor checkbox! indien checked is value 1 --> </tr> <tr> <td>Telefoon:</td> <td><input type="checkbox" name="telefoon" value="1"/></td> </tr> <tr> <td>Netwerk:</td> <td><input type="checkbox" name="netwerk" value="1"/></td> </tr> <tr> <td><input type="submit" name="verzenden" value="Verzenden"/></td> </tr> </table> </form> Second File: <?php session_start(); ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-Strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en" lang="en"> <head> <title>ExpoOverzicht</title> <meta http-equiv="content-type" content="text/html; charset=utf-8" /> <link href="StyleSheetExpo.css" rel="stylesheet" type="text/css" /> </head> <body> <h1>Overzicht van de ingegeven standen in deze sessie</h1> <?php $standnaam = $_SESSION["standnaam"]; $oppervlakte = $_SESSION["oppervlakte"]; $verdieping = $_SESSION["verdieping"]; $telefoon = $_SESSION["telefoon"]; $netwerk = $_SESSION["netwerk"]; $result1 = 0; //telkens declaren anders fout "undefined variable" $result2 = 0; $result3 = 0; $prijsCom = 0; $prijsVerdieping = 0; for ($i=1; $i <= $oppervlakte; $i++) { if($i <= 10) { $tarief1 = 1 * 100; $result1 += $tarief1; } if($i > 10 && $i <= 30) { $tarief2 = 1 * 90; $result2 += $tarief2; } if($i > 30) { $tarief3 = 1 * 80; $result3 += $tarief3; } } $prijsOpp = $result1 + $result2 + $result3; if($verdieping == 1) { $prijsVerdieping = $oppervlakte * 120; } if(($telefoon == 1) || ($netwerk == 1)) // eerst deze OR conditie of anders gebruikt de code alleen nog maar 20 { $prijsCom = 20; } if(($telefoon == 1) && ($netwerk == 1)) { $prijsCom = 30; } $totalePrijs = $prijsOpp + $prijsVerdieping + $prijsCom; echo "<table class=\"tableExpo\">"; echo "<th>Standnaam</th>"; echo "<th>Oppervlakte</th>"; echo "<th>Verdieping</th>"; echo "<th>Telefoon</th>"; echo "<th>Netwerk</th>"; echo "<th>Totale prijs</th>"; echo "<tr>"; echo "<td>".$standnaam."</td>"; echo "<td>".$oppervlakte."</td>"; echo "<td>".$verdieping."</td>"; echo "<td>".$telefoon."</td>"; echo "<td>".$netwerk."</td>"; echo "<td>".$totalePrijs."</td>"; echo "</tr>"; echo "</table>"; ?> <a href="ExpoFormulier.php">Terug naar het formulier</a> </body> </html> </body> </html>

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  • Export mysql database tables to php code to create same tables in other database?

    - by chefnelone
    How do I Export mysql database tables to php code so that it allows me to create and populate same tables in other database? I have a local database, I exported to sql syntax, then I get something like: CREATE TABLE `boletinSuscritos` ( `id` int(11) NOT NULL AUTO_INCREMENT, `name` varchar(120) NOT NULL, `email` varchar(120) NOT NULL, `date` timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY (`id`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 ; INSERT INTO `boletinSuscritos` VALUES(1, 'walter', '[email protected]', '2010-03-24 12:53:12'); INSERT INTO `boletinSuscritos` VALUES(2, 'Paco', '[email protected]', '2010-03-24 12:56:56'); but I need it to be: (Is there any way to export the tables in this way) $sql = "CREATE TABLE boletinSuscritos ( id int(11) NOT NULL AUTO_INCREMENT, name varchar(120) NOT NULL, email varchar(120) NOT NULL, date timestamp NOT NULL DEFAULT CURRENT_TIMESTAMP, PRIMARY KEY ( id ) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 AUTO_INCREMENT=3 )"; mysql_query($sql,$conexion); mysql_query("INSERT INTO boletinSuscritos VALUES(1, 'walter', '[email protected]', '2010-03-24 12:53:12')"); mysql_query("INSERT INTO boletinSuscritos VALUES(2, 'Paco', '[email protected]', '2010-03-24 12:56:56')");

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  • Able to connect by SSH, but not x2go

    - by Mike
    I am having trouble connecting to a remote server with X2GO using a DSA key. Connecting works fine over SSH, but when I try to connect with X2GO, it goes immediately to the username/password box and doesn't want to use the private key I specify in the options. If I select "Try auto login" it appears to try to connect and then I get the following error: No public key matched Access denied. Authentication that can continue: publickey It was working previously, but I reinstalled the client OS and since then I am unable to connect. I copied all of the SSH keys over from the previous installation. I also tried deleting my ~/.ssh/known_hosts file and adding the key to ssh-agent with no success, but the key is definitely added correctly: $ ssh-add -l 1024 b9:3d:e5:ef:48:ea:fc:c6:6e:45:89:b5:35:e7:58:39 server.com_dsa (DSA) Note, if I enable password authentication on the server, I can connect fine, however I would like to use publickey. Any ideas how I can connect with public key authentication?

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  • How to configure Apache2 to host Django and PHP on multiple domains simultaneously?

    - by Bert B.
    I have a VPS (Ubuntu 10.04) that hosts multiple domains, one of them being a CodeIgniter (PHP) web app. The others are just static websites, no fancy backend languages required. Well I am starting a new project and want to use Django. I have Django installed, mod_wsgi enabled in Apache2, but when I did the first steps on the documentation (https://docs.djangoproject.com/en/dev/howto/deployment/wsgi/modwsgi/) it seemingly overwrote my existing Apache2 configuration and served up the Django welcome page to all my domains. What should my httpd.conf file should look like so that it doesn't overtake all my domains.

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  • SharePoint 2010 Server Configuration Error -> "Cannot connect to database master"

    - by Chrish Riis
    I recieve the following error when I try to configure SharePoint 2010 Server: "Cannot connect to the database master at SQL server at [computer.domain]. The database might not exist, or the current user does not have permission to connect to it." I run the following setup: Windows Server 2008 R2 Standard with SP1 and all the updates SQL Server 2008 R2 with SP1 SharePoint Server 2010 with SP1 Everything is installed on the same server (it's a testserver) I have tried the following: Rebooting the server Checking the install account's DB rights (dbcreator, securityadmin - I even let it have sysadmin) Opened up the firewall on port 1433 and 1434 Uninstalled both SQL and SP, then reinstalled the both Enabled all client protocols in SQL Server Configuration Made sure I used the correct account for installing SharePoint (local admin) Useful links: TCP/IP settings – http:// blog.vanmeeuwen-online.nl/2010/10/cannot-connect-to-database-master-at.html http:// ybbest.wordpress.com/2011/04/22/cannot-connect-to-database-master-at-sql-server-at-sql2008r2/ Wrong slash - http:// yakimadev.com/2010/11/cannot-connect-to-database-master-at-sql-server-at-serverdbname-error-during-sharepoint-2010-products-configuration-wizard-and-installation/ Port error - http:// www.knowsharepoint.com/2011/08/error-connecting-to-database-server.html

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  • Microsoft FTP fails to connect after the client requests the list of features (FEAT)

    - by Max
    This is a really weird problem. The first few times I try to connect Filezilla just hangs on the line 211-Extended features supported: for a while before coming up and saying Error: Could not connect to server. The filezilla log below: Command: PASS *********** Response: 230 User logged in. Command: FEAT Response: 211-Extended features supported: Error: Could not connect to server The weird thing is if I keep trying to connect eventually it just works and connects fine. After Filezilla knows which features the server supports it stops asking for a while which enables you to connect first time until Filezilla decides it wants to double check the features list again. I'm at a loss on how to debug this. Has anyone experienced similar?

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  • Ideas for SVN/SQL/PHP/Linux Dev Enviroment Supporting Multiple Isolated Environments?

    - by jpganz18
    I am trying to create a "dev" for my users. In that environment they would access to their own account of PHPMyAdmin, SQL, Subversion and FTP which is not a big problem, but I would like to emulate like if each one would be in their own server. I mean so that they could change the PHP configuration (for example) and would be done only in its own environment. Any idea how to do this? Do I have to make something "special" at the installations of my server or something like that?

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  • apache2 and php slow first load on Ubuntu VPS - something like mysqltuner but for apache?

    - by talkingnews
    Ubuntu 10.10 64 bit VPS, 512Mb dedicated RAM. Mysql tuned so that sqltuner is completely happy. Used RAM never above 350Mb out of the 493 available. Load never exceeds 1.04 or so. httpd.conf tuned as per all the guides for vps of that memory - amount of preforks, spares etc. But for the FIRST load a site after having not visited for a while, it's taking ages. First load: Parse Time: 3.576 - Number of Queries: 50 - Query Time: 0.019723195953369 Reload Parse Time: 0.096 - Number of Queries: 39 - Query Time: 0.0066126374511719 Subsequent reloads will be at this speed. htop shows two items as soon as I load that page for the first time: php-cgi /usr/sbin/apache2 -k start I'm using suPHP but I've tried fast-cgi and cgi. Stuck now, a weekend of tweaking has brought me nothing. Advice appreciated.

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  • What are some good, free tools to run automated security audits for PHP code?

    - by James Simpson
    I've been looking for some time now and have come up short. The most promising I found was Spike PHP, which seems to no longer work. I'm looking to scan my code for potential risks of SQL Injection, XSS, etc. I've gone through most of my code manually, but with a few hundred thousand lines of code, I'm sure I missed things. If possible, are there any tools that can be downloaded and analyze code on my local machine rather than installing to the live server (this isn't a requirement if not)?

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  • When did Red Hat start shipping PHP 5.3 with 5.x?!?

    - by Jason
    Okay this is a PSA more than a question because I know the answer: January 13, 2011. See: https://rhn.redhat.com/errata/RHEA-2011-0069.html Colour me surprised though, didn't hear anything about in the blogosphere until I got a Security Errata notice today. I have been using the REMI repo for this in the past but will switch over to the Red Hat blessed PHP 5.3. Don't down-vote me bro! I'll select as the best answer the source that broke the news first (other than Red Hat of course). People have wanted this for so long I'm just amazed that it's finally happened!

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  • WiFi: Connect to a network with hidden SSID in Windows 7

    - by Dor
    I have Windows 7 with the following station: D-Link DWA-160 Xtreme N Dual Band USB Adapter(rev.A2) (driver version 3.5.0.21). I'm trying to connect to a wireless network that has an hidden SSID with the command: Netsh wlan connect name="myNetworkProfile" The profile is configured to connect even if the network is not broadcasting its name (SSID). Despite that, the command fails promptly every time with the message: The network specified by profile "myNetworkProfile" is not available to connect. Nonetheless, when trying to connect manually using the dialog box (see image below), it successfully connects to the network after about 10 or 15 seconds. Also, Please - no need to elaborate about how useless the hidden SSID feature is.

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  • How do I install hiphop-php in CentOS 6?

    - by Dai
    I've been trying to install hiphop-php on CentOS 6 with no luck. I found an .rpm for it but it fails dependency checks on boost which fails to install because it depends on curl which fails to install because it can't overwrite /etc/lib64/libcurl.so.4 I can't remove the current curl version because half the system seems to depend on it. Has anybody had any luck doing this? It's driving me mad. I tried compiling from source but that's even more hellish and I really have no idea what I'm doing anyway.

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  • Restore access to Cisco Connect after changing router settings

    - by StasM
    I have recently bought Cisco Valet Plus (M20) wireless router (which I recognize now was a mistake, but nevermind). It has two setup options - Cisco Connect software and web-based setup. Cisco Connect software allows changing very small set of settings, web-based setup allows access to almost all settings, except settings for guest network. The problem is that when I use web-based setup, Cisco Connect after some changes refuses to talk to the router, so I can't change guest settings anymore (since web interface doesn't allow to change them). It must be because of some config parameter not matching or some password set wrong - but I don't know where Cisco Connect stores them. So, does anybody have any idea how to make Cisco Connect talk to the router again once I changed the settings through the web interface?

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  • Is it possible to upgrade PHP to 5.3 on a Centos Kloxo installation?

    - by Malachi
    I have a VPS running Centos with Kloxo on and I was wondering how I would upgrade the PHP to 5.3 - It's currently running 5.2.6. When I try and do a yum update I get the following errors: Resolving Dependencies --> Running transaction check --> Processing Dependency: libpq.so.4 for package: lxphp ---> Package postgresql-libs.i386 0:8.3.7-umask.7 set to be updated --> Finished Dependency Resolution lxphp-5.2.1-400.i386 from installed has depsolving problems --> Missing Dependency: libpq.so.4 is needed by package lxphp-5.2.1-400.i386 (installed) Error: Missing Dependency: libpq.so.4 is needed by package lxphp-5.2.1-400.i386 (installed) You could try using --skip-broken to work around the problem You could try running: package-cleanup --problems package-cleanup --dupes rpm -Va --nofiles --nodigest The program package-cleanup is found in the yum-utils package. Any help would be greatly appreciated.

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  • How to connect with MySQL server if it won't connect via the socket?

    - by cwd
    I have an account on a shared server. I have jailshell access and also PhpMyAdmin. I want to run mysql commands via SSH but I'm getting an error: $ mysql -u mySqlUser -p mySqlPw Can't connect to local MySQL server through socket '/var/lib/mysql/mysql.sock' I can connect with PHP and phpMyAdmin, so would it be possible to call mysql from the shell and have it connect via an ip and port instead of the socket? The file /var/lib/mysql/mysql.sock does not exist - maybe that is intentional, and the only thing in /etc/my.cnf is [mysqld] skip-innodb More Info I don't have access to change system settings. I did a search in /var for mysql.sock but found nothing. However, phpMyAdmin might be connecting via a socket somehow: Really it would just be great if I could connect via IP. Also tried these two syntaxes: $ mysql -u mySqlUser -p mySqlPw -h localhost $ mysql -u mySqlUser -p mySqlPw -h localhost -P 3306 Both with the same result: ERROR 2002 (HY000): Can't connect to local MySQL server through socket '/var/lib/mysql/mysql.sock' (2)

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  • PHP fopen fails - does not have permission to open file in write mode.

    - by George
    Hello. I have an Apache 2.17 server running on a Fedora 13. I want to be able to create a file in a directory. I cannot do that. Whenever I try to open a file with php for writing fopen(,'w'), it tells me that I don't have permission to do that. So i checked the httpd.conf file in /etc/httpd/conf/. It says user apache, group apache. So I changed ownership (chown -R apache:apache .*) of my whole /www directory to apache:apache. I also run chmod -R 777 * Apart from knowing how terribly dangerous this is, it actually still gives me the same error, even though I even allow public write!

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  • Can you link to a good MySQL dumper PHP script?

    - by Ivan
    I need to migrate a website to another host. I have only FTP server access and MySQL name+pass (the MySQL server's IP I was provided is 127.0.0.1, and there's neither PhpMyAdmin nor SSHell to use). A web app run there can access the DB using credentials I know and localhost server. So I'd need a PHP script, that will correctly dump all the available databases of the MySQL server so that they can be imported on the new server. Can you recommend a good one?

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