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  • C# Finding 2 positions 1-dimArray

    - by Chris
    Hello, In a method i am calculating the longest row of elements. The 1-dim array is filled up with random values (0 or 1). The method looks up the longest row (being 0 or 1, whatever is the longest). Meaning in for example: 1110100 --> the longest row would be 3 (3 * 1) 0110000 --> the longest row would be 4 (4 * 0) My problem is i am trying to perform some type of linear search to show the position of the row in the array. The first example has the longest row of 3 elements (3 times 1). For 1110100 the position in the array would be 0 - 2 (index) For 0110000 the position in the array would be 3 - 6 (index) I have been trying with foreaches, for loops etc..but i cannot seem to get the proper indexes of both. Cannot seem to display both positions properly. For the first example the correct output wouldbe: The largest row of same elements of the array consists of 3 elements on the position 0 - 2. The longest row of elements gets of same elements get calculated as the following: public int BerekenDeelrij (int [] table) ( int count = 0; final int value = 0; int largest = 0; foreach (int value in table) ( if (value == last value) counter + +; else ( largest = Math.Max largest (largest, counter); final value = value count = 1; ) ) Math.Max return (largest, counter); ) Best Regards.

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  • Efficient Multiplication of Varying-Length #s [Conceptual]

    - by Milan Patel
    Write the pseudocode of an algorithm that takes in two arbitrary length numbers (provided as strings), and computes the product of these numbers. Use an efficient procedure for multiplication of large numbers of arbitrary length. Analyze the efficiency of your algorithm. I decided to take the (semi) easy way out and use the Russian Peasant Algorithm. It works like this: a * b = a/2 * 2b if a is even a * b = (a-1)/2 * 2b + a if a is odd My pseudocode is: rpa(x, y){ if x is 1 return y if x is even return rpa(x/2, 2y) if x is odd return rpa((x-1)/2, 2y) + y } I have 3 questions: Is this efficient for arbitrary length numbers? I implemented it in C and tried varying length numbers. The run-time in was near-instant in all cases so it's hard to tell empirically... Can I apply the Master's Theorem to understand the complexity...? a = # subproblems in recursion = 1 (max 1 recursive call across all states) n / b = size of each subproblem = n / 1 - b = 1 (problem doesn't change size...?) f(n^d) = work done outside recursive calls = 1 - d = 0 (the addition when a is odd) a = 1, b^d = 1, a = b^d - complexity is in n^d*log(n) = log(n) this makes sense logically since we are halving the problem at each step, right? What might my professor mean by providing arbitrary length numbers "as strings". Why do that? Many thanks in advance

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  • What is the purpose of this string argument in a JavaScript function?

    - by Adel
    In the following function, there is the line: var username=getCookie("username"); Here's the whole function: function checkCookie() { var username=getCookie("username"); if (username!=null && username!="") { alert("Welcome again " + username); } else { username=prompt("Please enter your name:",""); if (username!=null && username!="") { setCookie("username",username,365); } } What is the point of the "username" argument being passed above? function getCookie(c_name) { var i,x,y,ARRcookies=document.cookie.split(";"); for (i=0;i<ARRcookies.length;i++) { x=ARRcookies[i].substr(0,ARRcookies[i].indexOf("=")); y=ARRcookies[i].substr(ARRcookies[i].indexOf("=")+1); x=x.replace(/^\s+|\s+$/g,""); if (x==c_name) { return unescape(y); } } } The whole code is here Thanks!

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  • Hashmap method not accepting defined parameters

    - by Ocasta Eshu
    My assignment is to implement a contact list in a HashMap. All has gone well except for the problem in the code below. the HashMap method put(K key, V value) isnt accepting the defined parameters String, List. public ContactList(){ private HashMap<String, List<String>> map; public void update(String name, List<String> number){ this.map.put(name, number) The error is: The method put(String, List<String>) is undefined for the type ContactList How do I correct this?

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  • Lexical Analyzer(Scanner) for Language G by using C/C++

    - by udsha
    int a = 20; int b =30; float c; c = 20 + a; if(c) { a = c*b + a; } else { c = a - b + c; } use C++ / C to Implement a Lexer. 1. Create Unambiguous grammer for language G. 2. Create Lexical Analyzer for Language G. 3. It should identified tokens and lexemes for that language. 4. create a parse tree. 5. to use attribute grammer on a parse tree the values of the intrinsic attributes should be available on the symbol table.

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  • problem with join SQL Server 2000

    - by eyalb
    I have 3 tables - Items, Props, Items_To_Props i need to return all items that match all properties that i send example items 1 2 3 4 props T1 T2 T3 items_to_props 1 T1 1 T2 1 T3 2 T1 3 T1 when i send T1,T2 i need to get only item 1

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  • Calling arrays from other methods in a different class

    - by Jake H
    Hello, I need help dealing with an array in my java program. in my first class, "test", I set 4 variables and then send them to my other class (test2). arr[i] = new test2(id, fname, lname, case); at that point, variables are set and then I want to return those variables. So in the test2 class, I have a method that strictly returns one of those variables public int getId(){ return id; } I understand this is a little stupid, but professor gets what professor wants I guess. What I want to do now is in my main method in "test" I want to retrieve that variable and sort the array based on that int. Unfortunately, I have to create my own sort function, but I think this would work for what I want to do. for(j = 0; j < arr.length; j++){ int indexMin =j; for(i = j; i < arr.length;i++){ if(arr[i] < arr[indexMin]){ indexMin = i; } } int tmp = arr[j]; arr[j] = arr[indexMin]; arr[indexMin] = tmp; } I appreciate any help anyone could provide. Thank you

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  • Can't get Jacobi algorithm to work in Objective-C

    - by Chris Long
    Hi, For some reason, I can't get this program to work. I've had other CS majors look at it and they can't figure it out either. This program performs the Jacobi algorithm (you can see step-by-step instructions and a MATLAB implementation here). BTW, it's different from the Wikipedia article of the same name. Since NSArray is one-dimensional, I added a method that makes it act like a two-dimensional C array. After running the Jacobi algorithm many times, the diagonal entries in the NSArray (i[0][0], i[1][1], etc.) are supposed to get bigger and the others approach 0. For some reason though, they all increase exponentially. For instance, i[2][4] should equal 0.0000009, not 9999999, while i[2][2] should be big. Thanks in advance, Chris NSArray+Matrix.m @implementation NSArray (Matrix) @dynamic offValue, transposed; - (double)offValue { double sum = 0.0; for ( MatrixItem *item in self ) if ( item.nonDiagonal ) sum += pow( item.value, 2.0 ); return sum; } - (NSMutableArray *)transposed { NSMutableArray *transpose = [[[NSMutableArray alloc] init] autorelease]; int i, j; for ( i = 0; i < 5; i++ ) { for ( j = 0; j < 5; j++ ) { [transpose addObject:[self objectAtRow:j andColumn:i]]; } } return transpose; } - (id)objectAtRow:(NSUInteger)row andColumn:(NSUInteger)column { NSUInteger index = 5 * row + column; return [self objectAtIndex:index]; } - (NSMutableArray *)multiplyWithMatrix:(NSArray *)array { NSMutableArray *result = [[NSMutableArray alloc] init]; int i = 0, j = 0, k = 0; double value; for ( i = 0; i < 5; i++ ) { value = 0.0; for ( j = 0; j < 5; j++ ) { for ( k = 0; k < 5; k++ ) { MatrixItem *firstItem = [self objectAtRow:i andColumn:k]; MatrixItem *secondItem = [array objectAtRow:k andColumn:j]; value += firstItem.value * secondItem.value; } MatrixItem *item = [[MatrixItem alloc] initWithValue:value]; item.row = i; item.column = j; [result addObject:item]; } } return result; } @end Jacobi_AlgorithmAppDelegate.m // ... - (void)jacobiAlgorithmWithEntry:(MatrixItem *)entry { MatrixItem *b11 = [matrix objectAtRow:entry.row andColumn:entry.row]; MatrixItem *b22 = [matrix objectAtRow:entry.column andColumn:entry.column]; double muPlus = ( b22.value + b11.value ) / 2.0; muPlus += sqrt( pow((b22.value - b11.value), 2.0) + 4.0 * pow(entry.value, 2.0) ); Vector *u1 = [[[Vector alloc] initWithX:(-1.0 * entry.value) andY:(b11.value - muPlus)] autorelease]; [u1 normalize]; Vector *u2 = [[[Vector alloc] initWithX:-u1.y andY:u1.x] autorelease]; NSMutableArray *g = [[[NSMutableArray alloc] init] autorelease]; for ( int i = 0; i <= 24; i++ ) { MatrixItem *item = [[[MatrixItem alloc] init] autorelease]; if ( i == 6*entry.row ) item.value = u1.x; else if ( i == 6*entry.column ) item.value = u2.y; else if ( i == ( 5*entry.row + entry.column ) || i == ( 5*entry.column + entry.row ) ) item.value = u1.y; else if ( i % 6 == 0 ) item.value = 1.0; else item.value = 0.0; [g addObject:item]; } NSMutableArray *firstResult = [[g.transposed multiplyWithMatrix:matrix] autorelease]; matrix = [firstResult multiplyWithMatrix:g]; } // ...

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  • Codesample with bufferoverflow (gets method). Why does it not behave as expected?

    - by citronas
    This an extract from an c program that should demonstrate a bufferoverflow. void foo() { char arr[8]; printf(" enter bla bla bla"); gets(arr); printf(" you entered %s\n", arr); } The question was "How many input chars can a user maximal enter without a creating a buffer overflow" My initial answer was 8, because the char-array is 8 bytes long. Although I was pretty certain my answer was correct, I tried a higher amount of chars, and found that the limit of chars that I can enter, before I get a segmentation fault is 11. (Im running this on A VirtualBox Ubuntu) So my question is: Why is it possible to enter 11 chars into that 8 byte array?

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  • circular shift c

    - by simion
    I am doing some past papers and noticed a question where i have to shift the int one place to the right and return it i no in java i can just return n 1; is this possible in c? or is there a typically more compelx way of doing it :D. The method we were given is as follows // Return n after a right circular 1-bit shift unsigned int right_circular_shift_1(unsigned int n) {

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  • help implementing All Nearest Smaller Values algorithm

    - by davit-datuashvili
    http://en.wikipedia.org/wiki/All_nearest_smaller_values this is site of the problem and here is my code but i have some trouble to implement it import java.util.*; public class stack{ public static void main(String[]args){ int x[]=new int[]{ 0, 8, 4, 12, 2, 10, 6, 14, 1, 9, 5, 13, 3, 11, 7, 15 }; Stack<Integer> st=new Stack<Integer>(); for (int a:x){ while (!st.empty() && st.pop()>=a){ System.out.println( st.pop()); if (st.empty()){ break; } else{ st.push(a); } } } } } and here is pseudo code from site S = new empty stack data structure for x in the input sequence: while S is nonempty and the top element of S is greater than or equal to x: pop S if S is empty: x has no preceding smaller value else: the nearest smaller value to x is the top element of S push x onto S

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  • A two player game over the intranet..

    - by Santwana
    Hi everybody.. I am a student of 3rd year engineering and only a novice in my programming skills. I need some help with my project.. I wish to develop a two player game to be played over the network (Intranet). I want to develop a simple website with a few html pages for this.My ideas for the project run as follows: 1.People can log in from different systems and check who ever is online on the network currently. the page also shows who is playing with whom. 2.If a person is interested in playing with a player who is currently online, he sends a request of which the other player is somehow notified( using a message or an alert on his profile page..) 3.If the player accepts the request, a game is started. This is exactly where I am clueless.. How can I make them play the game? I need to develop a turn based game with two players, eg chessboard.. how can I do this? The game has to be played live.. and it is time tracked. i need your help with coding the above.. the other features i wish to include are: 4.The game could not be abruptly terminated by any one if the users.The request to terminate the game should be sent to the other player first and only if he accepts can the game be terminated. Whoever wins the game would get a plus 10 on their credit and if he terminated he gets a minus 10. The credits remains constant even if he loses but the success percentage is reduced. 6.The player with highest winning percentage is projected as the player of the week on the home page and he can post a challenge to all others.. I only have an intermediate knowledge of core java and know the basics of Swing and Awt. I am not at all familiar with networking in java right now. I have 5 to 6 weeks of time for developing the project but I hope to learn the things before I start my project. i would prefer to use a lan to illustrate the project and I know only java,jsp,oracle,html and bit of xml to develop my proj. Also I wish to know if I can code this within 6 weeks, would it be too difficult or complicated? Please spare some time to tell me. Please.. please.. I need your suggestions and help.. thank you so much..

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  • Append to the end of a Char array in C++

    - by Taylor Huston
    Is there a command that can append one array of char onto another? Something that would theoretically work like this: //array1 has already been set to "The dog jumps " //array2 has already been set to "over the log" append(array2,array1); cout << array1; //would output "The dog jumps over the log"; This is a pretty easy function to make I would think, I am just surprised there isn't a built in command for it. *Edit I should have been more clear, I didn't mean changing the size of the array. If array1 was set to 50 characters, but was only using 10 of them, you would still have 40 characters to work with. I was thinking an automatic command that would essentially do: //assuming array1 has 10 characters but was declared with 25 and array2 has 5 characters int i=10; int z=0; do{ array1[i] = array2[z]; ++i; ++z; }while(array[z] != '\0'); I am pretty sure that syntax would work, or something similar.

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  • Help in C with integers

    - by inferno2991
    You need to use division and remainder by 10. Consider this example: 163 divided by 10 is 16 remainder 3 16 divided by 10 is 1 remainder 6 1 divided by 10 is 0 remainder 1 You'll notice the remainder is always the last digit of the number that's being divided. Now figure out a way to do this in C... How do i do it in c Help :(

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  • Cart coding help

    - by user228390
    I've made a simple Javascript code for a shopping basket but now I have realised that I have made a error with making it and don't know how to fix it. What I have is Javascript file but I have also included the images source and the addtocart button as well, but What I am trying to do now is make 2 files one a .HTML file and another .JS file, but I can't get it to because when I make a button in the HTML file to call the function from the .JS file it won't work at all. <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd"> <HTML> <HEAD><TITLE>shopping</TITLE> <META http-equiv=Content-Type content="text/html; charset=UTF-8"> <STYLE type=text/CSS> fieldset{width:300px} legend{font-size:24px;font-family:comic sans ms;color:#004455} </STYLE> <META content="MSHTML 6.00.2900.2963" name=GENERATOR></HEAD> <BODY scroll="auto"> <div id="products"></div><hr> <div id="inCart"></div> <SCRIPT type="text/javascript"> var items=['Xbox~149.99','StuffedGizmo~19.98','GadgetyGoop~9.97']; var M='?'; var product=[]; var price=[]; var stuff=''; function wpf(product,price){var pf='<form><FIELDSET><LEGEND>'+product+'</LEGEND>'; pf+='<img src="../images/'+product+'.jpg" alt="'+product+'" ><p>price '+M+''+price+'</p> <b>Qty</b><SELECT>'; for(i=0;i<6;i++){pf+='<option value="'+i+'">'+i+'</option>'} pf+='</SELECT>'; pf+='<input type="button" value="Add to cart" onclick="cart()" /></FIELDSET></form>'; return pf } for(j=0;j<items.length;j++){ product[j]=items[j].substring(0,items[j].indexOf('~')); price[j]=items[j].substring(items[j].indexOf('~')+1,items[j].length); stuff+=''+wpf(product[j],price[j])+''; } document.getElementById('products').innerHTML=stuff; function cart(){ var order=[]; var tot=0 for(o=0,k=0;o<document.forms.length;o++){ if(document.forms[o].elements[1].value!=0){ qnty=document.forms[o].elements[1].value; order[k]=''+product[o]+'_'+qnty+'*'+price[o]+''; tot+=qnty*price[o];k++ } } document.getElementById('inCart').innerHTML=order.join('<br>')+'<h3>Total '+tot+'</h3>'; } </SCRIPT> <input type="button" value="Add to cart" onclick="cart()" /></FIELDSET></form> </BODY></HTML>

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  • Please help me in creating an update query

    - by Rajesh Rolen- DotNet Developer
    I have got a table which contains 5 column and query requirements: update row no 8 (or id=8) set its column 2, column 3's value from id 9th column 2, column 3 value. means all value of column 2, 3 should be shifted to column 2, 3 of upper row (start from row no 8) and value of last row's 2, 3 will be null For example, with just 3 rows, the first row is untouched, the second to N-1th rows are shifted once, and the Nth row has nulls. id math science sst hindi english 1 11 12 13 14 15 2 21 22 23 24 25 3 31 32 33 34 35 The result of query of id=2 should be: id math science sst hindi english 1 11 12 13 14 15 2 31 32 23 24 25 //value of 3rd row (col 2,3) shifted to row 2 3 null null 33 34 35 This process should run for all rows whose id 2 Please help me to create this update query I am using MS sqlserver 2005

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  • Spinning a circle in J2ME using a Canvas.

    - by JohnQPublic
    Hello all! I have a problem where I need to make a multi-colored wheel spin using a Canvas in J2ME. What I need to do is have the user increase the speed of the spin or slow the spin of the wheel. I have it mostly worked out (I think) but can't think of a way for the wheel to spin without causing my cellphone to crash. Here is what I have so far, it's close but not exactly what I need. class MyCanvas extends Canvas{ //wedgeOne/Two/Three define where this particular section of circle begins to be drawn from int wedgeOne; int wedgeTwo; int wedgeThree; int spinSpeed; MyCanvas(){ wedgeOne = 0; wedgeTwo = 120; wedgeThree = 240; spinSpeed = 0; } //Using the paint method to public void paint(Graphics g){ //Redraw the circle with the current wedge series. g.setColor(255,0,0); g.fillArc(getWidth()/2, getHeight()/2, 100, 100, wedgeOne, 120); g.setColor(0,255,0); g.fillArc(getWidth()/2, getHeight()/2, 100, 100, wedgeTwo, 120); g.setColor(0,0,255); g.fillArc(getWidth()/2, getHeight()/2, 100, 100, wedgeThree, 120); } protected void keyPressed(int keyCode){ switch (keyCode){ //When the 6 button is pressed, the wheel spins forward 5 degrees. case KEY_NUM6: wedgeOne += 5; wedgeTwo += 5; wedgeThree += 5; repaint(); break; //When the 4 button is pressed, the wheel spins backwards 5 degrees. case KEY_NUM4: wedgeOne -= 5; wedgeTwo -= 5; wedgeThree -= 5; repaint(); } } I have tried using a redraw() method that adds the spinSpeed to each of the wedge values while(spinSpeed0) and calls the repaint() method after the addition, but it causes a crash and lockup (I assume due to an infinite loop). Does anyone have any tips or ideas how I could automate the spin so you do not have the press the button every time you want it to spin? (P.S - I have been lurking for a while, but this is my first post. If it's too general or asking for too much info (sorry if it is) and I either remove it or fix it. Thank you!)

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  • question about missing element in array

    - by davit-datuashvili
    i have following problem from book introduction algorithm second edition by MIT university problem is following An array A[1 . . n] contains all the integers from 0 to n except one. It would be easy to determine the missing integer in O(n) time by using an auxiliary array B[0 . . n] to record which numbers appear in A. In this problem, however, we cannot access an entire integer in A with a single operation. The elements of A are represented in binary, and the only operation we can use to access them is “fetch the j th bit of A[i],” which takes constant time. Show that if we use only this operation, we can still determine the missing inte- ger in O(n) time please help

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