Search Results

Search found 1181 results on 48 pages for 'letters'.

Page 36/48 | < Previous Page | 32 33 34 35 36 37 38 39 40 41 42 43  | Next Page >

  • Regular Expression; Find whether a line contains any word with more than X characters.

    - by Simpsoid
    Hi, I am trying to use a Validator on a ASP.NET site and need to find whether the Street Address textbox contains a valid entry. Entries with words that are longer than X characters (in this case 25, with no punctuation or spaces) will cause the HTML on a printed A4 page to not wrap properly and therefore not to confrom to certain sizes correctly pushing the margins off. For a street address I want to match that something like "201 Long Road" is valid but "235 ReallyLongAndNarrowWindingRoadBesideTheRiver Street" is invalid. Using a Microsoft .Net Regular Expression Validator I need to know what the RegEx pattern might be. I think if it does find a match the Validator will fire correctly however if there is no match the Validator won't fire and the Update button (in this case) won't fire. Since Street addresses can contain Capital Letters and numbers etc. it will need to accomodate for that and also Spaces, Commas, Semi-Colons and Colons and Hyphens are valid characters too. Any help would be greatly appreciated as I am really stuck with this problem. Thanks, David

    Read the article

  • character matching in grayscale image

    - by maximus
    I made patterns: images with the "A" letter of different sizes (from 12 to 72: 12, 14, .., 72) And I tested the method of pattern matching and it gave a good results. One way to select text regions from image is to run that algorithm for all small and big letters and digits of different sizes. And fonts! I don't like it. Instead of it I want to make something like a universal pattern or better to say: scanning image with different window sizes and select those regions where some function (probability of that there is a character at that window) is more than some fixed value. Do you know any methods or ideas to make that function? It must work with original image (grayscale).

    Read the article

  • How do you increase Internet Explorer 7's "Select as you type" timeout for comboboxes?

    - by Iain Fraser
    In Internet Explorer 7, you can select options from comboboxes by typing the first few letters of the value you're looking for. However, some people in our organisation are a bit slow and can't type their selection quick enough, with the result that the timeout is triggered and the "select as you type" process starts all over again. Example: If I type A-R-M-A (looking for Armadale) then wait half a second and type D, I'll get selections beginning with the letter D. What I want to do is increase this timeout to allow for slow typers. (We're in a corporate environment so rolling out these changes to all machines won't be a problem).

    Read the article

  • Need help with formulating LINQ query

    - by eponymous23
    I'm building a word anagram program that uses a database which contains one simple table: Words --------------------- varchar(15) alphagram varchar(15) anagram (other fields omitted for brevity) An alphagram is the letters of a word arranged in alphabetical order. For example, the alphagram for OVERFLOW would be EFLOORVW. Every Alphagram in my database has one or more Anagrams. Here's a sample data dump of my table: Alphagram Anagram EINORST NORITES EINORST OESTRIN EINORST ORIENTS EINORST STONIER ADEINRT ANTIRED ADEINRT DETRAIN ADEINRT TRAINED I'm trying to build a LINQ query that would return a list of Alphagrams along with their associated Anagrams. Is this possible?

    Read the article

  • AJAX Autocomplete appears at a random vertical position, not touching the textbox

    - by Tim
    Hi, I am using the AJAX Autocomplete extender for ASP.NET 2. Everything works fine...I am calling a webservice which gets me the values to fill the drop down with after 3 letters are typed into certain es. I have set the maxheight attribute and am using a scrollbar in case there are more entries than would fit that height. However, I notice that in some cases, the drop down appears at a random position on the screen, i.e. rather than connected to the relevant textbox, sometimes it appears with its entries above the textbox, not touching it at all. Sometimes it would have just one entry and it would appear in the middle of the screen vertically above the textbox it is associated to. Is there a reason why this is happening?

    Read the article

  • Remove line breaks and add BR tags in PHP

    - by user201140
    I have the following text for which I would like to add a <br> tag between every paragraph. And also remove all the line breaks. How would I do this in PHP? Thanks. So this - This is some text for which I would like to remove the line breaks. And I would also like to place a b> tag after every paragraph. Here is one more paragraph. Would become this - This is some text for which I would like to remove the line breaks.<br/> And I would also like to place a br tag after every paragraph. <br> Here is one more paragraph. NOTE: Ignore the highlighting of any letters.

    Read the article

  • python: creating a list inside a dictionary

    - by user1871081
    I just started using python and I'm trying to create a program that will read a file that looks like this: AAA x 111 AAB x 111 AAA x 112 AAC x 123 ... the file is 50 lines long and I'm trying to make the letters into keys in a dictionary and the numbers lists that correspond with the keys. I want the output to look like this: {AAA: ['111', '112'], AAB: ['111'], AAC: [123], ...} This is what I've tried file = open("filename.txt", "r") readline = file.readline().rstrip() while readline!= "": list = [] list = readline.split(" ") j = list.index("x") k = list[0:j] v = list[p + 1:] d = {} if k in d == False d[k] = [] d[k].append(v) else d[k].append(v) readline = file.readline().rstrip() I keep getting syntax errors on my if statement and I can't figure out what I've done wrong.

    Read the article

  • How can I use edit_in_place on three different models from a View for a model those three belong_to?

    - by Angela
    I have a model called Campaign. In the controller, I do the following to list, in order, the three Models that belong_to a Campaign: <% @campaign_events = campaign_events %> <% @campaign_events.each do |campaign_event| %> <% model_name = campaign_event.class.name.tableize.singularize %> <p> <%= link_to campaign_event.title, send("#{model_name}_path", campaign_event) %> <span class='model_name'>(<%= model_name.capitalize %>)</span> <%= campaign_event.days %> Days </p> <% end %> campaign_event is a campaign_helper defined as: module CampaignsHelper def campaign_events return (@campaign.calls + @campaign.emails + @campaign.letters).sort{|a,b| a.days <=> b.days} end end I want to be able to click on the numerical value for Days when looking at the view/campaign/show and edit the value for :days (in this case, displayed as campaign_event.days

    Read the article

  • Match two mysql cols on alpha chars (ignoring numbers in same field)

    - by Steve
    I was wondering if you know of a way I could filter a mysql query to only show the ‘alpha’ characters from a specific field So something like SELECT col1, col2, **alpha_chars_only(col3)** FROM table I am not looking to update only select. I have been looking at some regex but without much luck most of what turned up was searching for fields that only contain ‘alpha’ chars. In a much watered down context... I have col1 which contains abc and col two contains abc123 and I want to match them on alpha chars only. There can be any number of letters or numbers. Any help very much wel come

    Read the article

  • Loop crashing program having to do with 2D arrays

    - by user450062
    I am creating an encoding program and when I instruct the program to create a 5X5 grid based on the alphabet while skipping over letters that match up to certain pre-defined variables(which are given values by user input during runtime). I have a loop that instructs the loop to keep running until the values that access the array are out of bounds, the loop seems to cause the problem. This code is standardized so there shouldn't be much trouble compiling it in another compiler. Also would it be better to seperate my program into functions? here is the code: #include<iostream> #include<fstream> #include<cstdlib> #include<string> #include<limits> using namespace std; int main(){ while (!cin.fail()) { char type[81]; char filename[20]; char key [5]; char f[2] = "q"; char g[2] = "q"; char h[2] = "q"; char i[2] = "q"; char j[2] = "q"; char k[2] = "q"; char l[2] = "q"; int a = 1; int b = 1; int c = 1; int d = 1; int e = 1; string cipherarraytemplate[5][5]= { {"a","b","c","d","e"}, {"f","g","h","i","j"}, {"k","l","m","n","o"}, {"p","r","s","t","u"}, {"v","w","x","y","z"} }; string cipherarray[5][5]= { {"a","b","c","d","e"}, {"f","g","h","i","j"}, {"k","l","m","n","o"}, {"p","r","s","t","u"}, {"v","w","x","y","z"} }; cout<<"Enter the name of a file you want to create.\n"; cin>>filename; ofstream outFile; outFile.open(filename); outFile<<fixed; outFile.precision(2); outFile.setf(ios_base::showpoint); cin.ignore(std::numeric_limits<int>::max(),'\n'); cout<<"enter your codeword(codeword can have no repeating letters)\n"; cin>>key; while (key[a] != '\0' ){ while(b < 6){ cipherarray[b][c] = key[a]; if ( f == "q" ) { cipherarray[b][c] = f; } if ( f != "q" && g == "q" ) { cipherarray[b][c] = g; } if ( g != "q" && h == "q" ) { cipherarray[b][c] = h; } if ( h != "q" && i == "q" ) { cipherarray[b][c] = i; } if ( i != "q" && j == "q" ) { cipherarray[b][c] = j; } if ( j != "q" && k == "q" ) { cipherarray[b][c] = k; } if ( k != "q" && l == "q" ) { cipherarray[b][c] = l; } a++; b++; } c++; b = 1; } while (c < 6 || b < 6){ if (cipherarraytemplate[d][e] == f || cipherarraytemplate[d][e] == g || cipherarraytemplate[d][e] == h || cipherarraytemplate[d][e] == i || cipherarraytemplate[d][e] == j || cipherarraytemplate[d][e] == k || cipherarraytemplate[d][e] == l){ d++; } else { cipherarray[b][c] = cipherarraytemplate[d][e]; d++; b++; } if (d == 6){ d = 1; e++; } if (b == 6){ c++; b = 1; } } cout<<"now enter some text."<<endl<<"To end this program press Crtl-Z\n"; while(!cin.fail()){ cin.getline(type,81); outFile<<type<<endl; } outFile.close(); } } I know there is going to be some mid-forties guy out there who is going to stumble on to this post, he's have been programming for 20-some years and he's going to look at my code and say: "what is this guy doing".

    Read the article

  • Loop through non-integer rows using SQL

    - by Jesse
    I know how to accomplish my task with .NET, but I wanted to do this just in SQL. I need to loop through all of the rows where the primary key is somewhat arbitrary. It can be a number or a series of letters, and probably any number of unusual things. I know I could do something like this... DECLARE @numRows INT SET @numRows = (SELECT COUNT(pkField) FROM myTable) DECLARE @I INT SET @I = 1 WHILE (@I <= @numRows) BEGIN --Do what I need to here SET @I = @I + 1 END ...if my rows were indexed in a contiguous fashion, but I don't know enough about SQL to do that if they're not. I keep coming across the use of "cursors," but I come across just as much reading about avoiding cursors. I found this SO solution but I'm not sure if that's what I'm needing? I appreciate any ideas.

    Read the article

  • Tag suggestion (not tag autocomplete)

    - by takeshin
    AJAX autocomplete is fairly simple to implement. However, I wonder how to handle smart tag suggestion like this on SO. To clarify the difference between autocomplete and suggestion: autocomplete: foo [foobar, foobaz] suggestion: foo [barfoo, foobar, foobaz], or even better, with 'did you mean' feature: [barfoo, foobar, foobaz, fobar, fobaz] I suppose I need some full text search in tags (all letters indexed, not just words). There would be no problem to do it witch regex or other patterns for limited number of tags (even client side). But how to implement this feature for big number of tags? Is there any particular reason (besides URL) the tags on SO are dash separated? What about Unicode characters in tags? I store the tags in the table with the following columns: id, tagname. My SQL query returns objects with following fields: id, tagname, count

    Read the article

  • Exception for java Swing application?

    - by Rich Fluckiger
    For some reason this is locking up the java application. Did I handle the exception correctly? private void submitButtonActionPerformed(java.awt.event.ActionEvent evt) { double amount, interest,rateCalc, a, b, c, payment; int years, months; while (true){ try{ amount = Double.valueOf(loanAmount.getText()); interest = Double.valueOf(interestRate.getText()); years = Integer.valueOf(loanYears.getText()); rateCalc = (interest/12); months = (years*12); a = Math.pow((1+rateCalc),months); b = (a*rateCalc); c = (a-1); payment = (amount *(b/c)); monthlyPayment.setText("Mortgage Payment $ = " + payment); } catch (NumberFormatException nfe){ javax.swing.JOptionPane.showMessageDialog(null, "Please enter numbers and not letters"); return; } } } monthlyPayment returns to the java app.

    Read the article

  • 2 Questions 1.How to find differences in lists in prolog and 2. Determine if the lists are the same

    - by Alexander
    1.If i have two lists say A and B made upp of different letters. [b,a,c] in list A and [b,d,c,e] in list B how can i get prolog to give me C,which is a list of elements that A has which are not included in list B Ex. So if i type difference([b,a,c],[b,d,c,e],C). I want the answer to read: C=[a] If i have two lists where list A is made up off [a,b,c] and list B is [c,a,b] i want the result to be Yes if i type: same([a,b,c],[c,a,b]). since they contain the same elements the fact that they are in a different order does not matter. Also it should only answer yes if all of the elements are the same not if 3/4 are right.

    Read the article

  • Form validation in JAvascript with Regexp

    - by Nikita Barsukov
    I have a webpage with an input field where only digits are allowed. The input field has an onkeyup event that starts this validating function: function validate() { var uah_amount = document.getElementById("UAH").value; var allowed = /^\d+$/; document.getElementById("error").innerHTML = document.getElementById("UAH").value; if (!allowed.test(uah_amount)) { document.getElementById("error").style.backgroundColor = "red"; } } Everything works as I expect until I hit Backspace button to remove some characters. In this case function always behaves as if I entered letters. How to correct this?

    Read the article

  • Perl regular expression question

    - by user368311
    Suppose I have variables $x1 = 'XX a b XX c d XX'; $x2 = 'XX a b XX c d XX e f XX'; I want a regular expression that will find each instance of letters between XX. I'm looking for a general solution, because I don't know how many XX's there are. I tried using /XX(.*?)XX/g but this only matches "a b" for x1 and "a b", "e f" for x2 because once the first match is found, the engine has already read the second "XX". Thanks for any help.

    Read the article

  • regular expression "(?<!^)(?=[A-Z])"

    - by imad
    I spent like three hours trying to understant how does "(?<!^)(?=[A-Z])" works to split at tring according to capital letters i.e. string[] s = Regex.Split("TheWorldWithoutStrangers", "(?<!^)(?=[A-Z])"); How does it work !! I do understand what is the meaning of each char in the above expression, but I do not get how does it work together. why "(? < !^)([A-Z])" doesnot work ? it means that whenever you find a captial letter that is not after a new line, then split, am I right ?

    Read the article

  • trying to sort a simple string in c++

    - by every_answer_gets_a_point
    #include "stdio.h" #include "conio.h" #include <iostream> using namespace std; int main (void) { char my_char[] = "happy birthday"; int i; bool j=false; char my_char_temp[1]; do { for (i=0;i<sizeof(my_char)-2;i++) { j=false; if (my_char[i+1] < my_char[i]) { my_char_temp[0]=my_char[i+1]; my_char[i+1] = my_char[i]; my_char[i] = my_char_temp[0]; j=true; } } }while (j); cout << my_char; } what am i doing wrong? im just trying to sort the letters within the char the output i get is completely wrong

    Read the article

  • In B-trees which element gets promoted when the node splits

    - by Phenom
    Let's say there is a B-tree of order 8. This means it can have 8 pointers and 7 elements. Say the letters A through G are stored in this B-tree. So this B-tree is just a single node containing 7 elements. Then you try to insert J into the tree. There's no room, so you have to split the node and create a new root node. Which element gets promoted up into the root node?

    Read the article

  • C# matching two text files, case sensitive issue

    - by Mike
    What i have is two files, sourcecolumns.txt and destcolumns.txt. What i need to do is compare source to dest and if the text doesnt match write out to a new file. The code below works except i have case sensitive issues like this: CPI Cpi These say they dont match because of captial letters, any help is always thanked! string[] sourcelinestotal = File.ReadAllLines(@"C:\testdirectory\" + "sourcecolumns.txt"); string[] destlinestotal = File.ReadAllLines(@"C:\testdirectory\" + "destcolumns.txt"); foreach (string sline in sourcelinestotal) { if(destlinestotal.Contains(sline)) { } else { File.AppendAllText(@"C:\testdirectory\" + "missingcolumns.txt", sline); } }

    Read the article

  • Java spliting strings

    - by N0b
    Hi I've got a Java problem. I'm trying split a string when ever a " " occurs, for example the sentence test abc. Then move the first letter in each word from first to last. I got the moving the letter to work on the original string using String text = JOptionPane.showInputDialog(null,"Skriv in en normal text:"); char firstLetter = text.charAt(0); normal = text.substring(1,text.length()+0) + firstLetter; So my question is how would I split the string then start moving the letters around in each part of the cut string? Thanks in advance

    Read the article

  • How to create a NSPredicate to find entries with leading numerical value?

    - by Toastor
    Hello, I'm using NSPredicates to fetch entities based on a name attribute. Creating a predicate for names beginning with letters was easy (@"name BEGINSWITH %@", searchLetter), however now I'd like to fetch all entities with a name that begins with a numerical value, or rather a non-alphabetical number. What would be the appropriate predicate expression here? Right now I don't want to get too deep into predicate programming, as this is all I need right now and time flies. So, please, don't point me to the Predicate Programming Guide, I just need that expression.. :) Thanks alot guys!

    Read the article

  • How to determine if two strings are sufficiently close?

    - by A.06
    We say that we can "hop" from the word w1 to the word w2 if they are "sufficiently close". We define w2 to be sufficiently close to w1 if one of the following holds: w2 is obtained from w1 by deleting one letter. w2 is obtained from w1 by replacing one of the letters in w1 by some letter that appears to its right in w1 and which is also to its right in alphabetical order. I have no idea how to check if 2. is fulfilled. To check if 1. is possible this is my function: bool check1(string w1, string w2){ if(w2.length - w1.length != 1){ return false; } for(int i = 0,int j = 0;i < w2.length;i++;j++){ if(w2[i] == w1[j]){//do nothing } else if(i == j){ j++; } else{ return false; } } return true; } Given two words w1 and w2, how do we check if we can 'hop' from w1 to w2?

    Read the article

  • BI Publisher at Collaborate 2010

    - by mike.donohue
    Noelle and I are heading to Collaborate 2010 next week. There are over two dozen sessions on BI Publisher including a Hands On Lab (see below). Very excited to see what our customers and partners will be presenting and how they are using BI Publisher to get better reports and reduce costs. My only regret is that many sessions are scheduled at the same time so I won't get to see all of them. Noelle and I will be presenting the following: Monday, April 19 2:30 pm - 3:30 pm Introduction to Oracle Business Intelligence Publisher Session: 227 Location: Reef F By: Mike 2:30 pm - 3:30 pm The Reporting Platform for Applications: Oracle Business Intelligence Publisher Session: 73170 Location: South Seas Ballroom J By: Noelle 3:45 pm - 4:45 pm Oracle Business Intelligence Publisher Hands On Lab (1) Session: 217 Location: Palm D By: Noelle and Mike Tuesday, April 20 8:00 am - 9:00 am Oracle Business Intelligence Publisher Best Practices Session: 218 Location: Palm D By: Noelle and Mike We will also be at the BI Technology demo pod in the exhibt hall so please stop by and say hello. All BI Publisher related Sessions Sunday, April 18 2:00 pm - 2:50 pm Customizing your Invoices in a Flash! 3:00 pm - 3:50 pm BI Publisher SIG Meeting - Part 1 4:00 pm - 4:50 pm BI Publisher SIG Meeting - Part 2 Monday, April 19 8:00 am - 9:00 am XML Publisher and FSG for Beginners 2:30 pm - 3:30 pm Introduction to Oracle Business Intelligence Publisher 2:30 pm - 3:30 pm The Reporting Platform for Applications: Oracle Business Intelligence Publisher 2:30 pm - 3:30 pm Bay Ballroom A What it Takes to Make Your Business Intelligence Implementation a Success 2:30 pm - 3:30 pm XML Publisher-More Than Just Form Letters 3:45 pm - 4:45 pm JD Edwards EnterpriseOne Reporting and Batch Discussions presented by Technology SIG 3:45 pm - 4:45 pm Hands On Lab: Oracle Business Intelligence Publisher (1) Tuesday, April 20 8:00 am - 9:00 am Oracle Business Intelligence Publisher Best Practices 8:00 am - 9:00 am Creating XML Publisher Documents with PeopleCode 10:30 am - 11:30 am Moving to BI Publisher, Now What? Automated Fax and Email from Oracle EBS 2:00 pm - 3:00 pm Smart Reporting in Oracle Financials Release 12.1 2:00 pm - 3:00 pm Custom Check Printing Framework using XML Publisher 2:00 pm - 3:00 pm BI Publisher and Oracle BI for JD Edwards Wednesday, April 21 8:00 am - 9:00 am XML Publisher Tips for PeopleTools 10:30 am - 11:30 am JD Edwards World - Technical Upgrade Considerations 10:30 am - 11:30 am Data Visualization Best Practices: Know how to design and improve your BI & EPM reports, dashboards, and queries 10:30 am - 11:30 am Oracle BIEE End-to-End 1:00 pm - 2:00 pm Empower JD Edwards Users with Oracle BI Publisher for Ad Hoc Reporting 1:00 pm - 2:00 pm BIP and JD Edwards World - Good Stuff! 2:15 pm - 3:15 pm Proven Strategies for Increasing ROI with PeopleSoft HCM 4:00 pm - 5:00 pm Using Oracle BI Delivers to Send Reports to JD Edwards Users Thursday, April 22 9:45 am - 10:45 am PeopleSoft Recruiting Enhancements You Can Use 9:45 am - 10:45 am Reducing Cost with Oracle's BI Publisher Note (1) the Hands On Lab was not showing in the joint scheduler as of this posting but, it is definitely ON.

    Read the article

  • What is causing my spacebar to randomly stop working?

    - by Chris Billington
    A couple of times a day, I'll be typing something and realise I can't type spaces. Usually the cursor will flicker instead when I press the spacebar, and I can type all other letters as far as I can tell. If I'm in a terminal the cursor turns from a solid square to an empty square until I release the spacebar. For some reason, restarting compiz with alt-F2 compiz fixes it, until it next occurs. I can still copy and paste spaces from sources that already have them, and I can still insert spaces with ctrl-shift-u, 20, enter. This has been happening for a while, since before I upgraded to maverick, but it feels like its beceoming more frequent. There really doesn't seem to be any kind of a pattern to it. I'm using 64 bit ubuntu 10.10 on a system76 panp7 laptop. Any ideas how I might troubleshoot? EDIT: using xev, normally a spacebar registers as: KeyPress event, serial 36, synthetic NO, window 0x5600001, root 0x101, subw 0x0, time 26488647, (88,403), root:(748,458), state 0x10, keycode 65 (keysym 0x20, space), same_screen YES, XLookupString gives 1 bytes: (20) " " XmbLookupString gives 1 bytes: (20) " " XFilterEvent returns: False KeyRelease event, serial 36, synthetic NO, window 0x5600001, root 0x101, subw 0x0, time 26488729, (88,403), root:(748,458), state 0x10, keycode 65 (keysym 0x20, space), same_screen YES, XLookupString gives 1 bytes: (20) " " XFilterEvent returns: False But when it's stopped behaving a press of the spacebar instead gives the three events: FocusOut event, serial 36, synthetic NO, window 0x5600001, mode NotifyGrab, detail NotifyAncestor FocusIn event, serial 36, synthetic NO, window 0x5600001, mode NotifyUngrab, detail NotifyAncestor KeymapNotify event, serial 36, synthetic NO, window 0x0, keys: 2 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 FURTHER EDIT: Ok, so I think I've solved the problem, and by that I mean I now know which package to file a bug against. I have a hot corner which initiates a window picker, and I've customised the window picking so that left click goes to a window, right click closes one and spacebar zooms in on one. When I go to this hot corner, compiz must take control of my spacebar, and clearly isn't giving it back when I leave the window picker. So I'll be filing a bug against compiz. reported:here

    Read the article

< Previous Page | 32 33 34 35 36 37 38 39 40 41 42 43  | Next Page >